Imprimatur; …

Imprimatur;

Guil. Iane R. P. D. Hen. Episc. Lond. à Sacris Dom.

COSMOGRAPHIA, OR A VIEW OF THE Terrestrial and Coelestial GLOBES, IN A Brief Explanation OF THE PRINCIPLES Of plain and solid GEOMETRY, Applied to Surveying and Gauging of CASK.

The Doctrine of the Primum Mobile.

With an Account of the Juilan & Gregorian Calendars, and the Computation of the Places of of the Sun, Moon, and Fixed Stars, from such De­cimal Tables of their Middle Motion, as supposeth the whole Circle to be divided into an hundred Degrees or Parts.

To which is added an Introduction unto GEOGRAPHY.

By John Newton, D. D.

London, Printed for Thomas Passinger, at the Three Bibles on London-Bridge 1679.

TO THE Most Honourable HENRY SOMERSET, Lord Herbert, Baron of Chepstow, Raglan, and Gower, Earl and Marquess of Worcester, Lord President and Lord Lieutenant of Wales and the Marches, Lord Lieutenant of Gloucester, Here­ford and Monmouth, and of the City and County of Bristol, Knight of the Most Noble Order of the Garter, and one of His Majestie's Most Honourable Privy Council.

HE that adventures upon any thing contrary to the General received practice, what ever his own courage and resolutions are, had need to be supported, not only by the most Wise and Honourable, but also [Page] the most Powerful Persons that are in a Nation or Kingdom; For let the Propo­sals be never so advantagious to the Pub­lick, they shall not only be decried and neglected, but it is well, if the Promoter be not both abused and ruined: Yet I, not­withstanding all these discouragements, have not been silent, but in order to Child­rens better Education, have long since pub­lished my thoughts, and have and do declare, that the multitude of Schools for the learning of the Latine and Greek Tongues, are destru­ctive both to our youth and the Commonwealth; and if the Opinion of Sir Francis Bacon in his Advice to King Iames concerning Sut­ton's Hospital, be not sufficient to warrant my Assertion, I could heartily wish that no such Evidence could have been produ­ced, as the late unhappy Wars, in the Bowels of this Kingdom hath afforded us; for what he saith there by way of Advice, we by woful Experience have found too true; that by reason of the multitude of Grammar Schools, more Scholars are dayly brought up, than all the Preferments in this Nation can provide for, and so they become uncapable of other Professions, and unprofitable in their own, and at last become, materia rerum novarum; whether this be an essential or an accidental Effect, [Page] I will not here dispute; the truth of it, I am sure, cannot be denied: but that is not all; by this means it comes to pass, that four of the seven Liberal Arts, are almost wholly neglected, as well in both Univer­sities, as in all Inferiour Schools; and set­ting aside the City of London, there are but few Places in this Nation, where a man can put his Son, to be well instructed in A­rithmetick, Geometry, Musick and Astronomy; and even that Famous City was without a Publick School for Mathematical Learn­ing, till His present Majesty was pleased to lay the Foundation; nay so averse are men in the general to these Arts (which are the support of all Trade) that without a high hand, it will be almost impossible, to make this People wise for their own good: I come therefore to your Honour, humbly to beg your Countenance and Assistance, that the Stream of Learning may be a lit­tle diverted, in those Schools that are al­ready erected, and to be instrumental for the erecting more, when they shall be wanting; that we may not be permitted still to begin at the wrong end; but that according to the practice of the Ancient Philosophers, Children may be instructed in Arithmetick, Geometry, Musick and A­stronomy; before the Latine and Greek [Page] Grammars are thought on, these Arts in themselves, are much more easie to be learned, tend more to a general good, and will in a great measure facilitate the Learn­ing of the Tongues, to as many as shall af­ter this Foundation laid, be continued at School, and provided for in either Univer­sities. Your Honour was instrumental to enlarge the Maintenance for God's Mini­ster in the Place where I live, and perhaps it may please God to make you so, not on­ly in making this Place in particular, but many other Places in this Land happy, by procuring Schools for these Sciences, and not only so, but by your Loyal and Prudent managing the several Trusts committed to you, you may do much for God's Glory, your Countries Good, and the continuance of your own Honour to all Future Genera­tions, which is, and shall be the Prayer of,

Your Honour's Obliged and Devoted Servant, JOHN NEWTON.

TO THE READER.

MY Design in publishing these In­troductions to Geometry and A­stronomy, is so well known by all the Epistles, to my other Treati­ses of Grammar, Arithmetick, Rhetorick, and Logick, that I think it needless to tell thee here, that it is my Opinion, that all the Arts should be taught our Children in the English Tongue, before they begin to learn the Greek or Latin Grammar, by which means many thousands of Children would be fitted for all Trades, enabled to earn their own Li­vings, and made useful in the Commonwealth; and that before they attain to twelve years of age; and by consequence the swarming of Bees would be prevented, who being compelled to leave their Hives, for want of room, do spread themselves abroad, and instead of ga­thering of Honey, do [...] sting all that come in their way. We should not have such innu­merable company of Gown-men to the loss and prejudice of themselves and the Common­wealth; and those we had would probably be more learned, and better regarded.

[Page] His Majesty being pleased to begin this Work, by His Bounty towards a Mathemati­cal School in Christ's Church London; I am not now without hopes, to see the same effected in many other Places in this Kingdom; and to this purpose I have to my Introductions to the other Arts, added these also to Geome­try and Astronomy; which I call by the name of Cosmographia; and this I have divided into four Parts; in the first I have briefly laid down the first Principles belonging to the three kinds of Magnitude or continued Quantity, Lines, Planes and Solids; which ought in some measure to be known, before we enter upon Astronomy, and this part I call an Introduction unto Geometry:

The second and third Parts treat of Astro­nomy; the first of which sheweth the Do­ctrine of the Primum Mobile, that is, the Declination, Right Ascension, and Oblique Ascensions of the Sun and Stars, and such other Problems, as do depend upon the Do­ctrine of Spherical Triangles.

The second Part of Astronomy, treateth of the motion of the Sun, Moon and Fixed Stars; in order whereunto, I have first giv­en thee a brief account of the Civil Year, with the cause of the difference between our Julian and Gregorian Calendar, and of both from the true; for it must be acknowledged [Page] that both are erroneous, though ours be the worse of the two; yet not so bad, but that our Dissenting Brethren have I hope some better Arguments to justifie their Non-conformity▪ than what I see published in a little Book without any name to it, concerning two Easters in one Year; by the General Table, saith this learned man, who owneth the Feast of Easter was to be observed Anno 1674. upon the 19 day of April, so the Almanacks for that Year, as well as the General Table set before the Book of Common Prayer; but by the Rule in the said Book of Common Prayer given, the Feast of Easter should have been upon the twelfth of April, for Easter-Day must al­ways be the first Sunday after the first Full Moon, which happeneth next after the one and twentieth day of March, and if the Full Moon happen upon a Sunday, Easter-Day is the Sunday after; Now in the Year 1674. the 19 of April being Friday was Full Moon, therefore by this Rule, Easter-Day should be the twelfth, and by the Table and the Common Almanacks April the tenth; but this learned man must know, that the mistake is in himself, and not in the Rule or Table set down in the Book of Common Prayer; for if he please to look into the Calendar, he will find that the Golden Number Three, (which was the Golden Number for that Year) is [Page] placed against the last day of March, and therefore according to the supposed motion of the Moon, that Day was New Moon; and then the Full Moon will fall upon the fourteenth day of April, and not upon the tenth, and so by consequence the Sunday following the first Full Moon after the 21 day of March was the nineteenth of April and not the twelfth. And thus the Rule and the Table in the Book of Common Prayer for finding the Feast of Easter are reconciled; and when Authori­ty shall think sit, the Calendar may be cor­rected and all the moveable Feasts be observed upon the days and times at first appointed; but till that be, a greater difference than one Week will be found in the Feast of Easter be­tween the Observation thereof according to the Moons true motion, and that upon which the Tables are grounded; for by the Fathers of the Nicene Council it was appointed, that the Feast of Easter should be observed upon the Sunday following the first Full Moon after the Vernal Equinox, which then indeed was the 21 of March; but now the tenth, and in the Year 1674. Wednesday the 11 of March was Full Moon, and therefore by this Rule, Easter-Day should have been upon March the fifteenth, whereas according to the Rules we go by, it was not till April the nineteenth.

[Page] The Tables of the Sun and Moons middle motions are neither made according to the u­sual Sexagenary Forms, nor according to the usual Degrees of a Circle and Decimal Parts, but according to a Circle divided into 100 Degrees and Parts, and this I thought good to do, to give the World a taste of the excel­lency of Decimal Numbers, which if a Canon of Sines and Tangents were fitted to it, would be found much better, as to the com­puting the Places of the Planets; but as to the Primum Mobile, by reason of the gene­ral dividing a Circle into 360 Degrees, I should think such a Canon with the Decimal Parts most convenient, and in some cases the common Sexagenary Canon may be very useful, and indeed should wish and shall en­deavour to have all printed together, one Table of Logarithms will serve them all, and two such Canons, one for the Study and an­other for the Pocket, would be sufficient for all Mathematical Books in that kind; and then men may use them all or either of them as they shall have occasion, or as every one is perswaded in his own mind.

What I have done in this particular, as it was for mine own satisfaction, so I am apt to believe, that it will be pleasing to many others; and although I shall leave every one to abound in his own sense, yet I cannot think [Page] that Custom should be such a Tyrant, as to force us always to use the Sexagenary form, if so, I wonder that men did not always use the natural Canon; if no alteration may be admit­ted, what reason can be given for the use of Lo­garithms; and if that be found more ready than the natural, in things of this kind, where none but particular Students are concerned, I should think it reasonable, to reduce all things hereafter, into that form, which shall be found most ready and exact; now the Part Proportional in the Artificial Sines and Tan­gents in the three first Degrees cannot be well taken by the common difference, and the way of finding them otherwise will not be so easie in the Sexagenary Canon, as in either of the other, and this me thinks, should render that Canon which divides each Degree into 100 Parts more acceptable; but thus to retain the use of Sines, Degrees, and Decimal Parts, doth not to me seem convenient, and to rec­kon up, a Planets middle motion, by whole Circles will sometimes cause a Division of Degrees by 60, which hath some trouble in it also, but if a Circle be divided into 100 De­grees, this inconvenience is avoided, and were there no other reason to be given, this me thinks should make such a Canon to be desi­rable; but till I can find an opportunity of publishing such an one, I shall forbear to [Page] shew any further uses of it, and for what is wanting here in this subject, I therefore re­fer thee to Mr. Street's Astronomia Caroli­na, and the several Books written in English by Mr. Wing.

The fourth Part of this Treatise is an In­troduction unto Geography, in which I have given general Directions, for the understand­ing how the habitable part of the World is divided in respect of Longitude and Latitude in respect of Climes and Parallels with such other Particulars as will be found useful unto such as shall be willing to understand History; in which three things are required; The time when, and this depends upon Astrono­my; the place where, and this depends upon Geography; and the Person by whom any memorable Act was done, and this must be had from the Historical narration thereof; and he that reads History without some know­ledge in Astronomy and Geography will find himself at a loss, and be able to give but a lame account of what he reads; but after the learning of these Arts of Grammar, (I mean so much thereof, as tends to the un­derstanding of every ones Native Language) Arithmetick, Geometry and Astronomy; a Child may proceed profitably to Rhetorick and Logick, the reading of History, and the learning of the Tongues; and sure there is [Page] no studious and ingenious man, but will stand in need of some Recreation, and therefore if Musick in the Worship and Service of God be not Argument enough to allow that a place among the Arts, let that poor end of De­light and Pleasure be her Advocate; and al­though that all men have not Voyces, yet I can hardly believe, that he expects any Melodious Harmony in Heaven, that will not allow In­strumental Musick a place on Earth; and as for those that have Voyces, surely the time of learning Vocal Musick, must be in Youth, and I am perswaded that the Arts and Sci­ences to some good degree may be learned by Children before they be full twelve years old, and would our Grammer Masters leave off their horrible severity, and apply themselves to such ways of teaching Youth, as the World is not now unacquainted with, I am perswaded that it is no difficult matter, in four years time more to fit Children in some good measure for the University.

The great Obstruction in this Work, is the general Ignorance of Teachers, who be­ing unacquainted with this Learning, cannot teach others what they know not themselves. I could propound a remedy for this, Sed Cynthius aurem vellit; Therefore I will forbear and leave what I have written, to be perused and censured as thou shall think fit.

John Newton.

Practical Geometry; OR, THE ART of SURVEYING.

CHAP. I.

Of the Definition and Division of Geometry.

GEometry is a Science explaining the kinds and properties of continued quantity or magnitude.

2. There are three Kinds or Spe­cies of Magnitude or continued Quantity, Lines, Superficies and Solids.

3. A Line is a Magnitude consisting only of length without either breadth or thickness.

4. In a Line two things are to be considered, the Terms or Limits, and the several Kinds.

5. The term or limit of a Line is a Point.

6. A Point is an indivisible Sign in Magni­tude which cannot be comprehended by sense, but must be conceived by the Mind.

7. The kinds of Lines are two, Right and Ob­lique.

[Page 2] 8. A Right Line is that which lieth between his Points, without any going up or going down on either side. As the Line AB lieth streight and equally between the Points A and B. Fig. 1.

9. An Oblique Line is that which doth not lie equally between its Points, but goeth up and down sometimes on the one side and sometimes on the other. And this is either simple or various.

10. A simple Oblique Line, is that which is ex­actly Oblique, as the Arch of a Circle; of Various Oblique Lines there is but little use in Geometry.

11. Thus are Lines to be considered in them­selves, they may be also considered as compared to one another, and that either in respect of their distances, or in respect of their meetings.

12. In respect of their distances, they may be either equally distant, or unequally.

13. Lines equally distant are two or more, which by an equal space are distant from one ano­ther, and these are called Parallels; and these though infinitely extended will never concur.

14. Lines unequally distant, are such as do more or less incline to one another, and these be­ing extended will at last concur.

15. Concurring Lines are either perpendicu­lar or not perpendicular.

16. A Perpendicular Line, is a Right Line falling directly upon another Right Line, not de­clining or inclining to one side more than ano­ther; as the Line AB in Fig. 1.

17. A Perpendicular Line is twofold, to wit, ei­ther falling exactly in the middle of another Line, or upon some other Point which is not the middle.

18. A line exactly Perpendicular, may be drawn in the same manner, as any Right Line [Page 3] may be divided into two equal Parts; the which may thus be done. If from the two Terms or Points of the Right Line given, there shall be described two Arches crossing one another above and below, a Line drawn through the Intersecti­ons of those Arches, shall be exactly Perpendicu­lar, and also divide the Right Line given into her equal Parts. Fig. 1.

For Example; Let CD be the Right Line given, and let it be required, to bisect this Line, and to erect a Perpendicular in the middle thereof. 1. Then set­ting one of your Compasses in the Points C, draw the Arches E and F. 2. Setting one Foot of your Com­passes in D, draw the Arches G and H, and from the Intersections of these Arches draw the Right Line KL, so shall the Right Line KL be Perpendicular to the Right-Line CD, and the Right Line CD also di­vided into two equal Parts, in the Point A.

19. A Line Perpendicular to any other Point than the middle is twofold: for it is either drawn from some Point given in the Line; or from some Point given without the Line.

20. From a Point given in the Line, at Per­pendicular may thus be drawn. In Fig. 2. Let the given Line be CD, and let it be required to draw a Perpendicular Line to the Point C, your Compasses being opened to any reasonable distance, set one Foot in the Point C, and the other in any place on either side the Line CD, suppose at A, then describe the Arch ECF, this done draw the Line EA, and where that Line being extended shall cut the Arch ECF, a Right Line drawn from C to that Intersection shall be Perpendi­cular to the Point C in the Line CD, as was required.

21. From a Point given without the Line, a Perpendicular may be drawn in this manner. [Page 4] In Fig. 2. Let the given Line be CD, and let it be re­quired to draw another Line Perpendicular thereunto, from the Point F without the Line. From the Point F draw a streight Line to some part of the Line CD at pleasure, as FE, which being bisected, the Point of Bi­section will be A, if therefore at the distance of AF, you draw the Arch ECF, the Right Line CF shall be Perpendicular to the Line CD, as was required.

22. Hitherto concerning a Perpendicular Line. A Right Line not Perpendicular, is a Right Line falling indirectly upon another Right Line, in­clining thereto on the one side more, and on the other less.

23. Lines unequally distant, and at last con­curring, do by their meeting make an Angle.

24. An Angle therefore is nothing else, then the place, where two Lines do meet or touch one another, and the two Lines which constitute the Angle, are in Geometry called the sides of the Angle.

25. Every Angle is either Heterogeneous, or Ho­mogeneous: that is called an Hetorogeneous Angle, which is made by the meeting of one Right Line, and another that is Oblique and Crooked; and that is called an Homogeneous Angle, which is made by the meeting of two Lines of the same kind, that is, of two Right Lines, or of two curved or Circular Lines.

26. An Homogeneous Angle made of two curved or Circular Lines, is to be considered in Geome­try as in Spherical Triangles, but the other which is made of Right Lines, is in all the Parts of Geometry of more frequent use.

27. Right lined Angles are either Right or Oblique.

[Page 5] 28. A Right Angle is that whose legs or sides are Perpendicular to one another, making the comprehended space on both sides equal. Thus in Fig. 1. the Line AK is Perpendicular to the Line CD, and the Angles KAC and KAD, are right and equal to one another.

29. An Oblique Angle is that, whose sides are not Perpendicular to one another.

30. An Oblique Angle is either acute or ob­tuse.

31. An Acute Angle is that which is less than a Right.

32. An Obtuse Angle, is that which is greater than a Right. Thus in Fig. 1. The Angle BAC is an Acute Angle because less than the Right Angle CAK. And the Angle BAD is an Obtuse Angle being greater than the Right Angle DAK.

The Geometrical Propositions concerning Lines and Angles are very many, but these follow­ing we think sufficient for our present purpose.

Proposition I.

To divide a Right Line given into any Number of equal Parts.

Let it be required to divide the Right Line AB into five equal Parts. From the extream Points of the given Line A and B, let there be drawn two Parallel Lines, then from the Point A at any di­stance of the Compasses, set off as many equal Parts wanting one, as the given Line is to be di­vided into, which in our Example is four, and are noted thus, 1. 2. 3. 4. and from the Point B set off the like Parts in the Line BC, and let them be [Page 6] noted likewise thus, 1. 2. 3. 4. then shall the Pa­rallel Lines, 14. 23. 32, and 41. divide the Right Line AB into 5 equal Parts, as was required.

Proposition II.

Two Right Lines being given, to find a Mean pro­pertional between them.

Let the two Right Lines given be DB and CB, which let be made into one Line as CD, which being besected the Point of bisection is A, from which as from a Centre describe the Arch CED, and from the Point B erect the Perpendi­cular BE, so shall BE, be the Mean proportional required; for, BC. BE∷BE. BD.

Proposition III.

Three Right Lines being given, to find a fourth proportional.

Let the three given Lines be AB. BC. and AD. Fig. 5. to which a fourth proportional is required: draw AE at any Acute Angle, to the Line AD in the Point A; and make DE paral­lel to BC, so shall AE be the fourth proportio­nal required; for, AB. BC∷AD. AE.

Proposition IV.

Vpon a Right Line given, to make a right-lined. Angle, equal to an Angle given.

Let it be required upon the Line CD in Fig. 6. [Page 7] to make an Angle, equal to the Angle DAE in Fig. 5. From the Point A as a Center, at any ex­tent of the Compasses describe the Arch BG, between the sides of the Angle given, and with the same extent describe the Arch HL from the Point D, and then make HL equal to BG, then draw the Line DL, so shall the Angle CDL be equal to the Angle DAE given, as was re­quired.

CHAP. II.

Of Figures in the general, more particularly of a Circle and the affections thereof.

HItherto we have spoken of the first kind of Magnitude, that is, of Lines, as they are considered of themselves, or amongst them­selves.

2. The second kind of Magnitude is that which is made of Lines, that is, a Figure con­sisting of breadth as well as length, and this is otherwise called a Superficies.

3. And in a Superficies there are three things to be considered. 1. The Term or Limit. 2. The middle of the Term. 3. The Thing or Figure made by the Term or Limit.

4. The Term or Limit is that which compre­hendeth and boundeth the Figure, it is common­ly called the Perimeter or Circumference.

5. The Term of a Figure is either Simple or various.

6. A Simple Term is that which doth consist of a Simple Line, and is properly called a Cir­cumference [Page 8] or Periphery: A Periphery therefore is the Term of a Circle or most Simple Figure.

7. A various Term is that which hath bending or crooked Lines, making Angles, and may there­fore be called Angular.

8. The middle of Term is that which is the Center of the Figure; for every Figure, whe­ther Triangular, Quadrangular, or Multangular, hath a Center as well as the Circular, differing in in this, that the Lines in a Circle drawn from the Center to the Circumference are all equal, but in other Figures they are not equal.

9. The Thing or Figure made by the Term or Limit, is all that Area or space which is inclu­ded by the Term or Terms. And here it is to be observed, that the Term of a Figure is one thing, and the Figure it self another; for Example, A Periphe­ry is the Term of a Circle, but the Circle it self is not properly the Periphery, but all that Area or space which is included by the Periphery, for a Periphery is nothing but a Line, but the Circle is that which is in­cluded by that Line.

10. As the Term of a Figure is either Simple or Various; so the Figure it self is either Simple and Round, or Various and Angular.

11. A Simple Figure is that which is contained by a Simple or Round Line, and is either a Circle or an Ellipsis.

12. A Circle therefore is such a Figure which is made by a Line so drawn into it self, as that it is every where equally distant from the middle or Center.

13. An Ellipsis is an oblong Circle.

14. In a Circle we are to consider the affecti­ons which are as it were the Parts or Sections [Page 9] thereof, as they are made by the various applica­tions of Right Lines.

15. And Right Lines may be applied unto a Circle, either by drawing them within, or with­out the Circle.

16. Right Lines inscribed within a Circle, are either such as do cut the Circle into two equal or unequal Parts, as the Diameter and lesser Chords, or such as do cut the Diameter and lesser Chords into two equal or unequal Parts, as the Right and versed Sines.

17. A Diameter is a Right Line drawn through the Center from one side of the Cir­cumference to the other, and divideth the Circle into two equal Parts, As in Fig. 7. The Right Line GD drawn through the Center B is the Diameter of the Circle GEDL dividing the same into the two e­qual Parts GED, and GLD: and this is also called the greatest Chord or Subtense.

18. A Chord or Subtense is a Right Line in­scribed in a Circle, dividing the same into two equal or unequal Parts; if it divide the Circle into two equal Parts, it is the same with the Diameter, but if it divide the Circle into two unequal Parts it is less than the Diameter, and is the Chord or Sub­tense of an Arch less than a Semi-circle, and also of an Arch greater than a Semi-circle. As in the former Figure, the Right Line CAK divideth the Circle into two unequal Parts, and is the Chord or Subtense of the Arch CDK, less than a Semi-circle, and of the Arch CGK greater than a Semi-circle: and these are the Lines which divide the Circle into two equal or unequal Parts. And as they divide the Circle into two equal Parts, so do they also divide one another; The lesser Chords when they are divided by [Page 10] the Diameter into two equal Parts, those Parts are called Right Sines, and the two Parts of the Diame­ter made by the intersection of the Chords are called versed Sines.

19. Sines are right or versed.

20. Right Sines are made by being besected, by the Diameter, and are twofold, Sinus totus, the whole Sine or Radius, and this is the one half of the Diameter, as the Lines BE or BD, and all Lines drawn from the Center to the Circumference.

21. Sinus simpliter, or the lesser Sines, are the one half of any Chord less than the Diameter, as in the former Figure CA or AK, which are the equal Parts of the Chord CAK, are the Sines of the Arch­es CD. and DK less than a Quadrant, and also the Sines of CEG and KLG greater than a Quadrant.

22. Versed Sines are the Segments of the Dia­meter, made by the Chords intersecting it, at Right Angles, as AD is the versed Sine of CD or DG and the other Segment AG is the versed Sine of the Arch CEG or KLG.

23. The Right Lines drawn without the Cir­cle are two, the one touching the Circle, and is called a Tangent, and the other cutting the Cir­cle, and is called a Secant.

24. A Tangent is a Right Line touching the Circle, and drawn perpendicular to the Diame­ter, and extended to the Secant.

25. A Secant is a Right Line drawn from the Center through the Circumference, and extended to the Tangent. As in the former Figure, the Right Line DF is the Tangent of the Arch CD, and the Right Line BF is the Secant of the same Arch CD.

Proposition I.

The Arch of a Circle being given to describe the whole Periphery.

Let ABC be an Arch given, and let the Cir­cumference of that Circle be required. Let there be three Points taken in the given Arch at plea­sure, as A, B, C; open your Compasses to more than half the distance of A, B, and setting one Foot in A describe the Arch of a Circle, and the Compasses remaining at the same distance, set­ting one Foot in B, describe another Arch so as it may cut the former in two Points, suppose G, and H, and draw the Line HG towards that Part on which you suppose the Center of the Center of the Circle will fall.

In like manner, opening your Compasses to more than half your distance of B, C, describe two other Arches from the Points E and C, cut­ting each other in E and F, then draw the Line EF till it intersect the former Line HG, so shall the Point of Intersection be the Center of the Circumference or Circle required, as in Fig. may be seen.

Proposition II.

The Conjugate Diameters of an Ellipsis being given, to draw the Ellipsis.

Let the given Diameter in Fig. 24. be LB and ED, the greatest Diameter. LB being bisected in the Point of Bisection, erect the Perpendicular [Page 12] AD. which let be half of the lesser Diameter ED, then open your Compasses to the extent of AB, and setting one Foot in D, with the other make a mark at M and N in the Diameter BL, then cutting a thred to the length of BL, fasten the thred with your Compasses in the Points NM, and with your Pen in the inside of the thred de­scribe the Arch BFKL, so shall you describe the one half of the Ellipsis required, and turning the Thred on the other side of the Compasses, you may with your Pen in the like manner describe the other half of the Ellipsis GBHL.

CHAP. III.

Of Triangles.

HItherto we have spoken of the most Simple Figure, a Circle. Come we now to those Figures that are Various or Angular.

2. And an Angular Figure is that which doth consist of three or more Angles.

3. An angular Figure consisting of three Angles, otherwise called a Triangle, is a Super­ficies or Figure comprehended by three Right Lines including three Angles.

4. A Triangle may be considered either in re­spect of its Sides, or of its Angles.

5. A Triangle in respect of its Sides, is either Isopleuron, Isosceles, or Scalenum.

6. An Isopleuron Triangle, is that which hath three equal sides. An Isoscecles hath two equal Sides. And a Scalenum hath all the three Sides unequal.

7. A Triangle in respect of its Angles is Right or Oblique.

[Page 13] 8. A Right angled Triangle is that which hath one Right Angle and two Acute.

9. An Oblique angled Triangle, is either Acute or Obtuse.

10. An Oblique acute angled Triangle, is that which hath all the three Angles Acute.

11. An Oblique obtuse angled Triangle, is that which hath one Angle Obtuse, and the other two Acute.

Proposition I.

Vpon a Right Line given to make an Isopleuron or an Equilateral Triangle.

In Fig. 8. let it be required to make an Equila­teral Triangle upon the Right Line AB. Open your Compasses to the extent of the Line given, and setting one Foot of your Compasses in A, make an Arch of a Circle above or beneath the Line given, then setting one Foot of your Com­passes in B, they being full opened to the same extent, with the other foot draw another Arch of a Circle crossing the former, and from the In­tersection of those Arches draw the Lines AC and AB, so shall the Triangle ACB be Equilate­ral as was desired.

Proposition II.

Vpon a Right Line given to make an Isosceles Tri­angle, or a Triangle having two Sides equal.

In Fig. 8. let AB be the Right Line given, from the Points A and B as from two Centers, but at a lesser extent of the Compasses than AB; [Page 14] if you would have AB the greatest Side, at a greater extent; if you would have it to be the least Side, describe two Arches cutting one ano­ther, as at F, and from the Intersection draw the Lines AF, and FB, so shall the Triangle AFB have two equal Sides, as was required.

Proposition 3.

To make a Scalenum Triangle, or a Triangle, whose three Sides are unequal.

In Fig. 9. let the three unequal Sides be EFG make AB equal to one of the given Lines, sup­pose G, and from A as a Center, at the extent of E describe the Arch of a Circle; in like manner from B at the extent of F describe another Arch intersecting the former, then shall the Right Lines AC. CB and BA comprehend a Triangle, whose three sides shall be unequal, as was required.

CHAP. IV.

Of Quadrangular and Multangular Figures.

WE have spoken of Triangles or Figures con­sisting of three Angles, come we now to those that have more Angles than three, as the Quadrangle, Quinquangle, Sexangle, &c.

2. A Quadrangle is a Figure or Superficies, which is bounded with four Right Lines.

3. A Quadrangle is either a Parallelogram or a Trapezium.

4. A Parallelogram is a Quadrangle whose oppo­site [Page 15] Sides are parallel having equal distances from one another in all Places.

5. A Parallelogram is either Right angled or Oblique.

6. A Right angled Parallelogram, is a Quadran­gle whose four Angles are all Right, and is either Square or Oblong.

7. A Square Parallelogram doth consist of four equal Lines. The Parts of a Square are, the Sides of which the Square is made, and the Dia­gonal or Line drawn from one opposite Angle to another through the middle of the Square.

8. An Oblong is a Right angled Parallelogram, having two longer and two shorter Sides.

9. An Oblique angled Parallelogram, is that whose Angles are all Oblique, and is either a Rhombus or a Rhomboides.

10. A Rhombus is an Oblique angled and equi­lateral Parallelogram.

11. A Rhomboides is an Oblique angled and inequilateral Parallelogram.

12. A Trapezium is a Quadrangular Figure whose Sides are not all parallel; it is either Right angled or Oblique.

13. A Right angled Trapezium hath two op­posite Sides parallel, but unequal, and the Side between them perpendicular.

14. An Oblique angled Trapezium is a Qua­drangle, but not a Parallelogram, having at least two Angles Oblique, and none of the Sides pa­rallel.

15. Thus much concerning Quadrangles or four sided Figures. Figures consisting of more than four Angles are almost infinite, but are re­ducible unto two sorts, Ordinate and Regular, or Inordinate and Irregular.

[Page 16] 16. Ordinate and Regular Polygons are such, as are contained by equal Sides and Angles, as the Pentagon, Hexagon, and such like.

17. Inordinate or irregular Polygons, are such as are contained by unequal Sides and Angles. The construction of these Quadrangular and Multangular Figures is explained in the Proposi­tions following.

Proposition. I.

Vpon a Right Line given to describe a Right an­gled Parallelogram, whether Square or Oblong.

In Fig. 10. let the given Line be AB, upon the Point A erect the Perpendic [...]lar AD equal to AB if you intend to make a Square, but long­er or shorter, if you intend an oblong, and upon the Points D and B at the distance of AB and AD describe two Arches intersecting one ano­ther, and from the Intersection draw the Lines ED and EB, so shall the Right angled Figure AE be a Square, if AB and AD be equal, o­therwise an Oblong, as was desired.

Proposition II.

To describe a Rhombus or Rhomboides.

In Fig. 11. To the Right Line AB draw the Line AD at any Acute Angle at pleasure, equal to AB if you intend a Rhombus, longer or short­er if you intend a Rhomboides, then upon your Compasses to the extent of AD and upon B as a Center describe an Arch; in like manner, at the extent of AB upon D as a Center describe an­other [Page 17] Arch intersecting the former, then draw the Lines ED and EB, so shall AE be the Rhom­bus or Rhomboides, as was required.

Proposition III.

Vpon a Right Line given to make a Regular Pen­tagon, or five sided Figure.

In Fig. 12. Let the given Line be AB, upon A and B as two Centers describe the Circles EBGH and CAGK, then open your Compasses to the extent of BC, and making G the Cen­ter, describe the Arch HAFK, then draw the Lines KFE and HFC: so shall AE and BC be two sides of the Pentagon desired, and opening your Compasses to the extent of AB, upon E and C as two Centers describe two Arches inter­secting one another, and from the Point of Inter­section draw the Lines ED and DC, so shall the Figure AB and DE be the Pentagon required.

Proposition IV.

To make a Regular Pentagon and Decagon in a given Circle.

In Fig. 13. upon the Diameter CAB describe the Circle CDBL, from the Center AErect the Perpendicular AD, and let the Semidiameter AC be bisected, the Point of Bisection is E, set the distance ED from E to G, and draw the Line GD, which is the side of a Pentagon, and AG the side of a Decagon inscribed in the same Circle.

Proposition V.

In a Circle given to describe a Regular Hexagon.

The side of a Hexagon is equal to the Radius of a Circle, the Radius of a Circle therefore being six times applied to the Circumference, will give you six Points, to which Lines being drawn from Point to Point, will constitute a Regular Hexagon, as was desired.

Proposition VI.

In a Circle given to describe a Regular Hepta­gon or Figure consisting of seven equal sides.

The side of a Heptagon is equal to half the side of a Triangle inscribed in a Circle, having therefore drawn an Hexagon in a Circle, the Chord Line subtending two sides of the Hexagon lying together, is the side of a Triangle inscrib­ed in that Circle, and half that Chord applied seven times to the Circumference, will give se­ven Points, to which Lines being drawn from that Point, will constitute a Regular Heptagon, as in Fig. 14. is plainly shewed.

CHAP. V.

Of Solid Bodies.

HAving spoken of the two first kinds of Magnitude, Lines and Superficies, come we now to the third, a Body or Solid.

2. A Body or Solid is a Magnitude consisting of length, breadth and thickness.

3. A Solid is either regular or irregular.

4. That is called a regular Solid, whose Bases, Sides and Angles are equal and like.

5. And this either Simple or Compound.

6. A simple regular Solid, is that whith doth consist of one only kind of Superficies.

7. And this is either a Sphere or Globe, or a plain Body.

8. A Globe is a Solid included by one round and convex Superficies, in the middle whereof there is a Point, from whence all Lines drawn to the Circumference are equal.

9. A simple plain Solid, is that which doth consist of plain Superficies.

10. A plain Solid is either a Pyramid, a Prism, or a mixt Solid.

11. A Pyramid is a Solid, Figure or Body, contained by several Plains set upon one right lin'd Base, and meeting in one Point.

12. Of all the several sorts of Pyramids, there is but one that is Regular, to wit a Tetrahe­dron, or a Pyramid consisting of four regular or equilateral Triangles; the form whereof (as it may be cut in Pastboard) may be conceived by Figure 15.

[Page 20] 13. A Prism is a Solid contained by several Plains, of which those two which are opposite, are equal, like and parallel, and all others are Paralellogram.

14. A Prism is either a Pentahedron, a Hexahe­dron, or a Polyhedron.

15. A Pentahedron Prism, is a Solid compre­hended of five Sides, and the Base a Triangle, as Fig. 16.

16. An Hexahedron Prism, is a Solid com­prehended of six Sides, and the Base a Quadran­gle, as Fig. 17.

17. An Hexahedron Prism, is distinguished into a Parallelipipedon and a Trapezium.

18. An Hexahedron Prism called a Trapezium is a Solid, whose opposites Plains or Sides, are neither opposite nor equal.

19. A Parallelipipedon is either right angled or oblique.

20. A right angled Parallelipipedon is an Hexa­hedron Prism, comprehended of right angled Plains or Sides; and it is either a Cube or an Ob­long.

21. A Cube is a right angled Parallelipipedon comprehended of six equal Plains or Sides.

22. An Oblong Parallelipipedon, is an Hexahe­dron Prism, comprehended by unequal Plains or Sides.

23. An Oblique angled Parallelipipedon, is an Hexahedron Prism, comprehended of Oblique Sides.

24. A Polyhedron Prism, is a Solid compre­hended by more than six Sides, and hath a mul­tangled Base, as a Quincangle, Sexangle, &c.

25. A regular compound or mixt Solid, is such [Page 21] a Solid as hath its Vertex in the Center, and the several Sides exposed to view, and of this sort there are only three; the Octohedron, the Icosahe­dron, of both which the Base is a Triangle; and the Dodecahedron, whose Base is a Quincangle.

26. An Octohedron is a Solid Figure which is contained by eight equal and equilateral Trian­gles, as in Fig. 18.

27. An Icosahedron is a Solid, which is con­tained by twenty equal and equilateral Trian­gles, as Fig. 19.

28. A Dodecahedron is a Solid, which is con­tained by twelve equal Pentagons, equilateral and equiangled, as in Fig. 20.

29. A regular compound Solid, is such a So­lid as is Comprehended both by plain and circu­lar Superficies, and this is either a Cone or a Cylinder.

30. A Cone is a Pyramidical Body, whose Base is a Circle, or it may be called a round Py­ramis, as Fig. 21.

31. A Cylinder is a round Column every where comprehended by equal Circles, as Fig. 22.

32. Irregular Solids are such, which come not within these defined varieties, as Ovals, Fru­stums of Cones, Pyramids, and such like.

And thus much concerning the description of the several sorts of continued Quantity, Lines, Plains and Solids; we will in the next place consider the wayes and means by which the Di­mentions of them may be taken and determined, and first we will shew the measuring of Lines.

CHAP. VI.

Of the Measuring of Lines both Right and Circular.

EVery Magnitude must be measured by some known kind of Measure; as Lines by Lines, Superficies by Superficies, and Solids by Solids, as if I were to measure the breadth of a River, or height of a Turret, this must be done by a Right Line, which being applied to the breadth or height desired to be measured, shall shew the Perches, Feet or Inches, or by some other known measure the breadth or height desired: but if the quantity of some Field or Meadow, or any other Plain be desired, the number of square Perches must be enquired; and lastly, in measuring of Solids, we must use the Cube of the measure used, that we discover the number of those Cubes that are contained in the Body or Solid to be measured. First, therefore we will speak of the several kinds of measure, and the making of such Instruments, by which the quantity of any Magni­tude may be known.

2. Now for the measuring of Lines and Su­perficies, the Measures in use with us, are Inches, Feet, Yards, Ells and Perches.

3. An Inch is three Barley Corns in length, and is either divided into halves and quarters, which is amongst Artificers most usual, or into ten equal Parts, which is in measuring the most useful way of Division.

4. A Foot containeth twelve Inches in length, and is commonly so divided; but as for such things as are to be measured by the Foot, it is far [Page 23] better for use, when divided into ten equal Parts, and each tenth into ten more.

5. A Yard containeth three Foot, and is com­monly divided into halves and quarters, the which for the measuring of such things as are usually sold in Shops doth well enough, but in the mea­suring of any Superficies, it were much better to be divided into 10 or 100 equal Parts.

6. An Ell containeth three Foot nine Inches, aud is usually divided into halves and quarters, and needs not be otherwise divided, because we have no use for this Measure, but in Shop Com­modities.

7. A Pole or Perch cotaineth five Yards and an half, and hath been commonly divided into Feet and half Feet. Forty Poles in length do make one Furlong, and eight Furlongs in length do make an English Mile, and for these kinds of of lengths, a Chain containing four Pole, divided by Links of a Foot long, or a Chain of fifty Foot, or what other length you please, is well enough, but in the measuring of Land, in which the number of square Perches is required; the Chain called Mr. Gunters, being four Pole in length divided into 100 Links, is not without just reason reputed the most useful.

8. The making of these several Measures is not difficult, a Foot may be made, by repeating an Inch upon a Ruler twelve times, a Yard is eight Foot, and so of the rest; the Subdivision of a Foot or Inch into halves and quarters, may be performed by the seventeenth of the first, and into ten or any other Parts by the first Proposition of the first Chapter, and all Scales of equal Parts, of what scantling you do desire. And this I [Page 24] think is as much as needs to be said concerning the dividing of such Instruments as are useful in the measuring Right Lines.

9. The next thing to be considered is the mea­suring of Circular Lines, or Perfect Circles.

10. And every Circle is supposed to be divi­ded into 360 Parts called Degrees, every Degree into 60 Minutes, every Minute into 60 Seconds, and so forward this division of the Circle into 360 Parts is generally retained, but the Sub­division of those Parts, some would have be thus and 100, but as to our present purpose either may be used, most Instruments not exceeding the fourth part of a Degree.

11. Now then a Circle may be divided into 360 Parts in this manner, Having drawn a Dia­meter through the Center of the Circle dividing the Circle into two equal Parts, cross that Dia­meter with another at Right Angles through the Center of the Circle also, so shall the Circle be divided into four equal Parts or Quadrants, each Quadrant containing 90 Degrees, as in Fig. 7. GE. ED. DL and LG, are each of them 90 Degrees; and the Radius of a Circle being equal to the Chord of the sixth Part thereof, that is to the Chord of 60 Degrees, as in Fig. 14. if you set the Radius GB from L towards G, and also from G towards L, the Quadrant GL will be sub­divided into three equal Parts, each Part con­taining 30 Degrees, GM. 30. MH 30 and HL 30, the like may be done in the other Quadrants also; so will the whole Circle be divided into twelve Parts, each Part containing 30 Degrees.

And because the side of a Pentagon inscribed in a Circle is equal to the Chord of 72 Degrees, or [Page 25] the first Part of 360, as in Fig. 13. therefore if you set the Chord of the first Part of the Circle given from G to L or L to G, in Fig. 7. you will have the Chord of 72 Degrees, and the difference between GP 72 and GH 60 is HP 12, which be­ing bisected, will give the Arch of 6 Degrees, and the half of six will give three, and so the Circle will be divided into 120 Parts, each Part con­taining three Degrees, to which the Chord Line being divided into three Parts, the Arch by those equal Divisions may be also divided, and so the whole Circle will be divided into 360, as was de­sired.

12. A Circle being thus divided into 360 Parts, the Lines of Chords, Sines, Tangents and Secants, are so easily made (if what hath been said of them in the Second Chapter be but considered) that I think it needless to say any more concerning their Construction, but shall rather proceed unto their Use.

13. And the use of these Lines and other Lines of equal Parts we will now shew in circular and right lined Figures; and first in the measuring of a Circle and Circular Figures.

CHAP. VII.

Of the Measuring of a Circle.

THe squaring of a Circle, or the finding of a Square exactly equal to a Circle given, is that which many have endeavoured, but none as yet have attained: Yet Archimedes that Famous Mathe­matician hath sufficiently proved, That the Area of a Circle is equal to a Rectangle made of the Ro­dius and half the Circumference: Or thus, The Area of a Circle is equal to a Rectangle made of the Diameter and the fourth part of the Circum­ference. For Example, let the Diameter of a Circle be 14 and the Circumference 44; if you multiply half the Circumference 22 by 7 half the Diameter, the Product is 154; or if you multiply 11 the fourth part of the Circumference, by 14 the whole Diameter, the Product will still be 154. And hence the Superficies of any Circle may be found though not exactly, yet near enough for any use.

2. But Ludolphus Van Culen finds the Circum­ference of a Circle whose Diameter is 1.00 to be 3.14159 the half whereof 1.57095 being mul­tiplied by half the Diameter 50, &c. the Product is 7.85395 which is the Area of that Circle, and from these given Numbers, the Area, Circumfe­rence and Diameter of any other Circle may be found by the Proportions in the Propositions fol­lowing.

Proposition I.

The Diameter of a Circle being given to find the Circumference.

As 1. to 3.14159: so is the Diameter to the Circumference. Example. In Fig. 13. Let the Diameter IB be 13. 25. I say as 1. to 3. 14159. so IB. 13.25 to 41.626 the Circumference of that Circle.

Proposition II.

The Diameter of a Circle being given to find the Superficial Content.

As 1. to 78539; so is the Square of the Dia­meter given, to the Superficial Content required. Example, Let the Diameter given be as before IB 13.25 the Square thereof is 175.5625 therefore.

As 1. to 78539: so 175.5625 to 137.88 the Superficial Content of that Circle.

Proposition III.

The Circumference of a Circle being given, to find the Diameter.

This is but the Converse of the first Propositi­on: Therefore as 3.14159 is to 1: so is the Circumference to the Diameter; and making the Circumference an Unite, it is. 3. 14159. 1∷ 1. 318308, and so an Unite may be brought into the first place. Example, Let the given Cir­cumference [Page 28] be 41. 626. I say,

As 1. to 318308: so 41.626 to 13. 25. the Diameter required.

Proposition IV.

The Circumference of a Circle being given to find the Superficial Content.

As the Square of the Circumference of a Cir­cle given is to the Superficial Content of that Circle: so is the Square of the Circumference of another Circle given to the Superficial Con­tent required. Example, As the Square of 3.14159 is to 7853938: so is 1. the Square of another Circle to 079578 the Superficial Content required, and so an Unite for the most easie work­ing may be brought into the first place: Thus the given Circumference being 41. 626. I say,

As 1. to 0.79578: so is the Square of 41.626 to 137.88 the Superficial Content required.

Proposition V.

The Superficial Content of a Circle being given, to find the Diameter.

This is the Converse of the second Propositi­on, therefore as 78539 is to 1. so is the Superfici­al Content given, to the Square of the Diameter required. And to bring an Unite in the first place: I say.

As 7853978. 1∷1. 1. 27324, and there­fore if the Superficial Content given be 137.88, to find the Diameter: I say,

[Page 29] As 1. to 1.27324: so 137.88 to 175.5625 whose Square Root is 13.25, the Diameter sought.

Proposition VI.

The Superficial Content of a Circle being given, to find the Circumference.

This is the Converse of the Fourth Propositi­on, and therefore as 079578 is to 1 : so is the Su­perficial Content given, to the Square of the Cir­cumference required, and to bring an Unite in the first place: I say,

As 079578. 1 :: 1. 12.5664, and therefore if the Superficial Content given be 137.88, to find that Circumference: I say,

As 1. to 12.5664: so is the 137.88 to 1732.7 whose Square Root is 626 the Circumference.

Proposition VII.

The Diameter of a Circle being given to find the Side of the Square, which may be inscribed within the same Circle.

The Chord or Subtense of the Fourth Part of a Circle, whose Diameter is an Unite, is 7071067, and therefore, as 1. to 7071067: so is the Dia­meter of another Circle, to the Side required. Example, let the Diameter given be 13.25 to find the side of a Square which may be inscribed in that Circle: I say,

As 1. to 7071067: so is 13.25 to 9.3691 the side required.

Proposition VIII.

The Circumference of a Circle being given, to find the Side of the Square which may be inscribed in the same Circle.

As the Circumference of a Circle whose Dia­meter is an Unite, is to the side inscribed in that Circle; so is the Circumference of any other Circle, to the side of the Square that may be in­scribed therein. Therefore an Unite being made the Circumference of a Circle.

As 3.14159 to 7071067: so 1. to 225078.

And therefore the Circumference of a Circle being as before 41.626, to find the side of the Square that may be inscribed: I say,

As 1. to 225078. so is 41.626 to 9.3691 the side inquired.

Proposition IX.

The Axis of a Sphere or Globe being given, to find the Superficial Content.

As the Square of the Diameter of a Circle, which is Unity, is to 3.14159 the Superficial Content, so is the Square of any other Axis given, to the Superficial Content required. Ex­ample, Let 13.25 be the Diameter given, to find the Content of such a Globe: I say,

As 1. to 3.14159: so is the Square of 13.25 to 551.54 the Superficial Content required.

Proposition X.

To find the Area of an Ellipsis.

As the Square of the Diameter of a Circle, is to the Superficial Content of that Circle; so is the Rectangle made of the Conjugate Diame­ters in an Ellipsis, to the Area of that Ellipsis; And the Diameter of a Circle being one, the Area is 7853975, therefore in Fig. 26. the Diameters AC8 and BD5 being given, the Area of the Ellipsis ABCD may thus be found.

As 1. to 7853975: so is the Rectangle AC in BD40 to 3.1415900, the Area of the Ellipsis required.

CHAP. VIII.

Of the Measuring of Plain Triangles.

HAving shewed the measuring of a Circle, and Ellipsis, we come now to Right lined Figures, as the Triangle, Quadrangle, and Mul­tangled Figures, and first of the measuring of the plain Triangles.

2. And the measuring of Plain Triangles is either in the measuring of the Sides and Angles, or of their Area and Superficial Content.

3. Plain Triangles in respect of their Sides and Angles are to be measured by two sorts of Lines, the one is a Line of equal Parts, and by that the Sides must be measured, the other is a Line of Chords, the Construction whereof hath [Page 32] been shewed in the sixth Chapter, and by that the Angles must be measured, the Angles may in­deed be measured by the Lines of Sines, Tan­gents or Secants, but the Line of Chords being not only sufficient, but most ready, it shall suffice to shew how any Angle may be protracted by a Line of Chords, or the Quantity of any Angle found, which is protracted.

4. And first to protract or lay down an Angle to the Quantity or Number of Degrees propo­sed, do thus, draw a Line at pleasure as AD in Figure 5, then open your Compasses to the Num­ber of 60 Degrees in the Line of Chords, and setting one Foot in A, with the other describe the Arch BG, and from the Point A let it be requi­red to make an Angle of 36 Degrees: open your Compasses to that extent in the Line of Chords, and setting one Foot in B, with the other make a mark at G, and draw the Line AG, so shall the Angle BAG contain 36 Degrees, as was re­quired.

5. If the Quantity of an Angle were re­quired, as suppose the Angle BAG, open your Compasses in the Line of Chords to the extent of 60 Degrees, and setting one Foot in A, with the other draw the Arch BG, then take in your Com­passes the distance of BG, and apply that extent to the Line of Chords, and it will shew the Num­ber of Degrees contained in that Angle, which in our Example is 36 Degrees.

6. In every Plain Triangle, the three Angles are equal to two right or 180 Degrees, there­fore one Angle being given, the sum of the other two is also given, and two Angles being given, the third is given also.

[Page 33] 7. Plain Triangles are either Right Angled or Oblique.

8. In a Right Angled Plain Triangle, one of the Acute Angles is the Complement of the other to a Quadrant or 90 Degrees.

9. In Right Angled Plain Triangles, the Side subtending the Right Angle we call the Hypotenuse, and the other two Sides the Legs, thus in Fig. 5▪ AE is the Hypotenuse, and AD and ED are the Legs; these things premised, the several cases in Right Angled and Oblique Angled Plain Tri­angles may be resolved, by the Propositions fol­lowing.

Proposition I.

In a Right Angled Plain Triangle, the Angles of one Leg being given, to find the Hypotenuse and the other Leg.

In the Right Angled Plain Triangle ADE in Fig. 5. Let the given Angles be DAE 36, and DEA 54, and let the given Leg be AD 476; to find the Hypotenuse AE, and the other Leg ED.

Draw a Line at pleasure, as AD, and by your Scale of equal Parts set from A to D 476 the Quantity of the Leg given, then erect a Perpen­dicular upon the Point D, and upon the Point A lay down your given Angle DAE 36 by the fourth hereof, and draw the Line AE till it cut the Perpendicular DE, then measure the Lines AE and DE upon your Scale of Equal Parts, so shall AE 588.3 be the Hypotenuse, and DE 345.8 the other Leg.

Proposition II.

The Hypotenuse and Oblique Angles given, to find the Legs.

Let the given Hypotenuse be 588, and one of the Angles 36 degrees, the other will then be 54 degrees, Draw a Line at pleasure, as AD, and upon the Point A by the fourth▪ hereof lay down one of the given Angles suppose the less, and draw the Line AC, and from your Scale of equal Parts, set off your Hypotenuse 588 from A to E, and from the Point E to the Line AD let fall the Perpendicular ED, then shall AD be­ing measured upon the Scale be 476 for one Leg, and ED 345.8 the other.

Proposition III.

The Hypotenuse and one Leg given to find the An­gles and the other Leg.

Let the given Hypotenuse be 588. and the given Leg 476. Draw a Line at pleasure as AD, upon which set the given Leg from A to D. 476, and upon the Point D, erect the Perpendicular DE, then open your Compasses in the Scale of Equal Parts to the Extent of your given Hypotenuse 588, and setting one Foot of that Extent in A, move the other till it touch the Perpendicular DE, then and there draw AE, so shall ED be 345.8 the Leg inquired, and the Angle DAE, will be found by the Line of Chords to be 36▪ whose Comple­ment is the Angle DEA. 54.

Proposition IV.

The Legs given to find the Hypotenuse, and the Oblique Angles.

Let one of the given Legs be 476, and the o­ther 345.8, Draw the Line AD to the extent of 476, and upon the Point D, erect the Perpendi­cular DE to the extent of 345.8, and draw the Line AE, so shall AE be the Hypotenuse 588, and the Angle DAE will by the Line of Chords be found to be 36 Degrees, and the Angle DEA 54, as before.

Hitherto we have spoken of Right angled plain Triangles: the Propositions following concern such as are Oblique.

Proposition V.

Two Angles in an Oblique angled plain Triangle, being given, with any one of the three Sides, to find the other two Sides.

In any Oblique angled plain Triangle, let one of the given Angles be 26.50 and the other 38. and let the given Side be 632, the Sum of the two given Angles being deducted from a Semi-circle, leaveth for the third Angle 115.50 De­grees, then draw the Line BC 632. and upon the Points B and C protract the given Angles, and draw the Lines BD and CD, which being mea­sured upon your Scale of equal Parts BD will be fou [...]d to be 312.43, and BD 431.09,

Proposition VI.

Two Sides in an Oblique Angled Triangle being given, with an Angle opposite to one of them, to find the other Angles and the third Side, if it be known whe­ther the Angle Opposite to the other Side given be Acute or Obtuse.

In an Oblique Angled Plain Triangle, let the given Angle be 38 Degrees, and let the Side ad­jacent to that Angle be 632, and the Side oppo­site 431. 1. upon the Line BC in Fig. 25. protract the given Angle 38 Degrees upon the Point C, and draw the Line DC, then open your Compasses to the Extent of the other Side given 431. 1. and setting one Foot in B, turn the other about till it touch the Line DC, which will be in two pla­ces, in the Points D and E; if therefore the Angle at B be Acute the third Side of the Triangle will he CE, according therefore to the Species of that Angle you must draw the Line BD or BE to compleat the Triangle, and then you may measure the other Angles, and the third Side as hath been shewed.

Proposition VII.

Two Sides of an Oblique Angled Plain Triangle be­ing given, with the Angle comprehended by them to find the other Angles and the third Side.

Let one of the given Sides be 632, and the o­ther 431.1, and let the Angle comprehended by them be Deg. 26.50, draw a Line at pleasure, [Page 37] as BC, and by help of your Scale of Equal Parts, set off one of your given Sides from B to C 632. then upon the Point B protract the given Angle 26. 50. and draw the Line BD, and from B to D, set off your other given Side 431. 1. and draw the Line DC, so have you constituted the Triangle BDC, in which you may measure the Angles and the third Side, as hath been shewed.

Proposition VIII.

The three Sides of an Oblique Angled Triangle being given, to find the Angles.

Let the length of one of the given Sides be 632, the length of another 431.1, and the length of the third 312.4, and Draw a Line at pleasure, as BC in Fig. 25, and by help of your Scale of E­qual Parts, set off the greatest Side given 632 from B to C. then open your Compasses in the same Scale to the extent of either of the other Sides, and setting one Foot of your Compasses in B, with the other describe an occult Arch, then extend your Compasses in the same Scale to the length of the third Side, and setting one Foot in C with the other describe another Arch cutting the former, and from the Point of Intersection draw the Lines BD and DC. to constitute the Triangle BDC, whose Angles may be measured, as hath heen shewed.

And thus may all the Cases of Plain Triangles be resolved by Scale and Compass, he that desires to resolve them Arithmetically, by my Trigome­tria Britannica, or my little Geometrical, Trigo­nometry; only one Case of Right Angled Plain [Page 38] Triangles which I shall have occasion to use, in the finding of the Area of the Segment of a Cir­cle I will here shew how, to resolve by Numbers.

Proposition IX.

In a Right Angled Plain Angle the Hypote­nuse and one Leg being given to find the other Leg.

Take the Sums and difference of the Hypotenuse and Leg given, then multiply the Sum by the Dif­ference, and of the Product extract the Square Root, which Square Root shall be the Leg inqui­red.

Example. In Fig. 5. Let the given Hypotenuse be AE 588.3, and the given Leg AD 476, and let DE be the Leg inquired. The Sum of AE and AD is 1064.3, and their Difference is 112.3, now then if you multiply 1064.3 by 112.3, the Product will be 119520.89, whose Square Root is the Leg DE. 345. 8.

Proposition X.

The Legs of a Right Angled Plain Triangle being gived, to find the Area or Superficial Content thereof.

Multiply one Leg by the other, half the Product shall be the Content. Example, In the Right angled plain Triangle ADE, let the given Legs be AD 476, and DE 345, and let the Area of that Triangle be required, if you multiply 476 by 345 the Product will be 164220, and the half thereof 82110 is the Area or Superficial Con­tent required.

Proposition XI.

The Sides of an Oblique angled plain Triangle be­ing given to find the Area or Superficial Content there­of.

Add the three Sides together, and from the half Sum subtract each Side, and note their Dif­ference; then multiply the half Sum by the said Differences continually, the Square Root of the last Product, shall be the Content required.

Example. In Fig. 9. Let the Sides of the Tri­angle ABC be AB 20. AC 13, and BC 11 the Sum of these three Sides is 44, the half Sum is 22, from whence subtracting AB 20, the Dif­ference is 2, from whence also if you substract AC 13, the Difference is 9, and lastly, if you subtract BC 11 from the half Sum 22, the Diffe­rence will be 11. And the half Sum 22 being multiplied by the first Difference 2, the Product is 44, and 44 being multiplied by the Second Dif­ference 9, the Product is 396, and 396 being mul­tiplied by the third Difference 11, the Product is 4356, whose Square Root 66, is the Content re­quired.

Or thus, from the Angle C let fall the Perpen­dicular DC, so is the Oblique angled Triangle ABC, turned into two right, now then if you measure DC upon your Scale of Equal Parts, the length thereof will be found to be 6.6, by which if you multiply the Base AB 20, the Product will be 132.0, whose half 66, is the Area of the Tri­angle, as before.

Proposition XII.

The Sides of any Oblique angled Quadrangle be­ing given, to find the Area or Superficial Content thereof.

Let the Sides of the Oblique angled Quadran­gle ABED in Fig. 11. be given, draw the Diago­nal AE, and also the Perpendiculars DC and BF, then measuring AE upon the same Scale by which the Quadrangular Figure was protracted, suppose you find the length to be 632, the length of DC 112, and the length of BF 136, if you multiply AE 632 by the Half of DC 56, the Product will be 35392 the Area of ACED. In like manner if you multiply AE 632, by the half of BF 68, the Product will be 42976 the Area of ACEB, and the Sum of these two Products is the Area of ABED as was required.

Or thus, take the Sum of DC 112, and BF 136; the which is 248, and multiply AE 632 by half that Sum, that is by 124, the Product will be 78368 the Area of the Quadrangular Figure ABED, as before.

Proposition XIII.

The Sides of a plain irregular multangled Figure being given, to find the Content.

In Fig. 26. Let the Sides of the multangled Fi­gure. A. B. C. D. E. F. G. H. be given, and let the Area thereof be required, by Diagonals drawn from the opposite Angles reduce the Figure given, [Page 41] into Oblique angled plain Triangles, and those Oblique angled Triangles, into right by letting fall of Perpendiculars, then measure the Diagonals and Perpendiculars by the same Scale, by which the Figure it self was protracted, the Content of those Triangles being computed, as hath been shewed, shall be AF the Content required: thus by the Diagonals AG. BE and EC the mul­tangled Figure propounded is converted into three Oblique angled quadrangular Figures, AFGH. AFEB and BEDC, and each of these are divided into four Right angled Triangles, whose several Contents may be thus computed. Let GA 94 be multiplied by half HL 27 more Half of KF 29, that is by 23, the Product will be 21, be the Area of AHGF. Secondly, OB is 11, and FN 13, their half Sum 12, by which if you multiply AE 132, the Product will be 1584 the Area of AFEB. Thirdly, let Bp be 18 m D 32, the half Sum is 25, by which if you multiply AEC 125 the Product will be 3125 the Area of BEDC, and the Sum of these Products is 6871 the Area of the whole irregu­lar Figure. ABCDEFGH, as was required.

Proposition XIV.

The Number of Degrees in the Sector of a Circle being given, to find the Area thereof.

In Fig. 27. ADEG is the Sector of a Circle, in which the Arch DEG, is Degrees. 23.50, and by 1. Prop. of Archimed. de Dimensione Circuli, the length of half the Arch is equal to the Area of the Sector of the double Arch, there the length [Page 42] of DE or EG is equal to the Area of the Sector ADEG: and the length or circumference of the whole Circle whose Diameter is 1 according to Van Culen, is 3.14159265358979, therefore the length of one Centesme of a Degree, is. 0. 01745329259. Now then to find the length of any Number of Degrees and Decimal Parts, you must multiply the aforesaid length of one Cen­tesme by the Degrees and Parts given, and the Product shall be the length of those Degrees and Parts required, and the Area of a Sector containing twice those Degrees and Parts. Example, the half of DEG 23.50 is DE or EG 11.75, by which if you multiply 0.01745329259, the Pro­duct will be 2050761879325, the length of the Arch DE, and the Area of the Sector ADEG.

Proposition XV.

The Number of Degrees in the Segment of a Circle being given, to find the Area of the Segment.

In Fig. 27. Let the Area of the Segment DEGK be required, in which let the Arch DEG be Degrees 23.50, then is the Area of the Sector ADEG 2050761879325 by the last a­foregoing, from which if you deduct the Area of the Triangle ADG, the remainer will be the Area of the Segment DEGK. And the Area of the Tri­angle ADG may thus be found. DK is the Sine of DE 11.75, which being sought in Gellibrand's De­cimal Canon is. 2036417511, and AK is the Sine of DH 78.25, or the Cosine of DE. 9790454724, which being multiplied by the Sine of DE, the Pro­duct will be 1993745344, or if you multiply AG [Page]

[figure]

[Page] [Page 43] the Radius by half DF the Sine of the double Arch DEG, the Product will be 19937453445 as be­fore, and this Product being deducted from the Area of the Sector ADEG 2050761879325, the remainer will be 57016434875 the Area of the Segment DEGL, as was desired.

Proposition XVI.

The Diameter of a Circle being cut into any Num­ber of Equal Parts, to find the Area of any Segment made by the Chord Line drawn at Right Angles through any of those equal Parts of the Diameter.

In Fig. 28. The Radius AD is cut into five E­qual Parts, and the Segment EDFL is made by the Chord Line ELF at Right Angles to AD in the fourth Equal Part, or at eight tenths there­of: now then to find the Area of this Segment we have given AE Radius, and AL 8, and there­fore by the ninth hereof EL will be found to be 606000, the Sine of ED 36.87, by which if you multiply 0.0174532, the Product is the Area of the Sector AEDF 64350286, and the Area of the Triangle AEF is 48, which being deducted from the Area of the Sector, the Remainer 16350286 is the Area of the Sector EDFL, as was required. And in this manner was that Ta­ble of Segments made by the Chord Lines cutting the Radius into 100 Equal Parts.

Another way.

In Fig. 28. Let the Radius AD be cut into 10.100 or 1000 Equal Parts, and let the Area of [Page 44] the Segments made by the Chord Lines drawn at Right Angles through all those Parts be required: first find the Ordinates GK and M. PN. EL, the double of each Ordinate, will be the Chords of the several Arches, and the Sum of these Chords beginning with the least Ordinate, will orderly give you the Area of the several Segments made by those Chord Lines, but the Diameter must be be divided into 100000 Equal Parts, because of the unequal differences at the beginning of the Diameter: but taking the Area of the Circle to be 3. 1415926535, &c. as before, the Area of the Semicircle will be 1.57079632, from which if you deduct the Chord GH1999999, the Chord answering to 999 Parts of the Radius, the remainer is. 1.56879632 the Area of the Seg­ment GDH. And in this manner by a conti­nual deduction of the Chord Lines from the Area of the Segment of the Circle given, was made that Table shewing the Area of the Segments of a Circle to the thousandth part of the Radius.

And because a Table shewing the Area of the Segments of a Circle to the thousandth part of the Radius, whose whole Area is Unity, is yet more useful in Common Practice, therefore from this Table, was that Table also made by this Pro­portion.

As the Area of the Circle whose Diameter is. Unity, to wit 3.14149 is to the Area of any part of that Diameter, so is Unity the supposed Area of another Circle, to the like part of that Diameter. Example, the Area answering to 665 parts of the Radius of a Circlewhose Area is 3.14159 is 0.91354794 therefore,

As 3.14159265 is to 0.91354794: So is [...]. [Page]

[figure]

[Page]

[figure]

[Page 45] to 290791, the Area required; and the Table being thus computed to the 1000 parts of the Radius, we have enlarged it by the difference to the 5000 parts of the Radius, and consequently to the ten thousandth part of the Diameter: The use of which Table shall be shewed when we come to the measuring of Solid Bodies.

CHAP. IX.

Of the Measuring of Heights and Distances.

HAving shewed in the former Chapter, how all plain Triangles may be measured, not only in respect of their Sides and Angles, but in respect of their Area, and the finding of the A­rea of all other plain Figures also, that which is next to be considered, is the practical use of those Instructions, in the measuring of Board, Glass, Wainscot, Pavement, and such like, as also the measuring or surveying of Land; and first we will shew the measuring of Heights and Distances.

2. And in the measuring of Heights and Di­stances, besides a Chain of 50 or 100 Links, each Link being a Foot, it is necessary to have a Qua­drant of four or five Inches Radius, and the larger the Quadrant is, the more exactly may the Angles: be taken, though for ordinary Practice, four or five Inches Radius will be sufficient.

Let such a Quadrant therefore be divided in the Limb into 90 Equal Parts or Degrees, and numbred from the left hand to the right, at every tenth Degree, in this manner 10. 20. 30. 40. 50. 60. 70. 80. 90. and within the Limb of the Qua­drant [Page 46] draw another Arch, which being divided by help of the Limb into two Equal Parts, in the Point of Interfection set the Figure 1. represent­ing the Radius or Tangent of 45 Degrees, and from thence both ways the Tangents of 63.44 Deg. 71.57 Deg. 75.97 Deg.78.70 Deg. 80.54 Deg. that is, 2. 3. 4. 5 and 6 being set also, your Quadrant will be fitted for the taking of Heights several ways, as shall be explained in the Propositions following.

Proposition I.

To find the Height of a Tower, Tree, or other Object at one Station.

At any convenient distance from the Foot of the Object to be measured, as suppose at C in Fig. 30. and there looking through the Sights of your Quadrant till you espie the top of the Object at A, observe what Degrees in the Limb are cut by the Thread, those Degrees from the left Side or Edge of the Quadrant to the Right, is the Quan­tity of the Angle ACB, which suppose 35 De­grees; then is the Angle BAC 55 Degrees, be­ing the Complement of the former to 90 Degrees. This done with your Chain or otherwise mea­sure the distance from B the Foot of the Object, to your Station at C, which suppose to be 125 Foot. Then as hath been shewed in the 1. Prop. Chap. 8. draw a Line at pleasure as BC, and by your Scale of Equal Parts, set off the distance measured from B to C 125 Foot, and upon the Point C lay down your Angle taken by observa­tion 35 Degrees, then erect a Perpendicular upon [Page 47] the Point B, and let it be extended till it cut the Hypothenusal Line AC, so shall AB measured on your Scale of Equal Parts, be 87.5 Foot for the Height of the Object above the Eye; to which the Height of the Eye from the Ground being added, their Sum is the Height required.

Another way.

Let AB represent a Tower whose Altitude you would take, go so far back from it, that looking through the Sights of your Quadrant, to the top of the Tower at A the Thread may cut just 45 Degrees in the Limb, then shall the distance from the Foot of the Tower, to your Station, be the Height of the Tower above the Eye.

Or if you remove your Station nearer and near­er to the Object, till your Thread hang over the Figures 2. 3. 4 or 5 in the Quadrant, the Height of the Tower at 2. will be twice as much as the distance from the Tower to the Station, at 3. it will be thrice as much, &c. As if removing my Station from C to D, the Thread should hang o­ver 2 in the Quadrant, and the distance BD 62 Foot, then will 124 Foot be the Height of the Tower, above the Eye.

In like manner if you remove your Station backward till your Thread fall upon one of those Figures in the Quadrant; between 45 and 90 De­grees, the distance between the Foot of the Tower, and your Station will at 2. be twice as much as the Height, at 3. thrice as much, at 4. four times so much, and so of the rest.

[Page 48] A Third way by a Station at Random.

Take any Station at pleasure suppose at C, and looking through the Sights of your Quadrant, observe what Parts of the Quadrant the Thread falls upon, and then measure the distance be­tween the Station, and the Foot of the Object, that distance being multiplied by the parts cut in the Quadrant, cutting off two Figures from the Product shall be the Height of the Object above the Eye?

Example, Suppose I standing at C, that the Thread hangs upon 36 Degrees, as also upon 72 in the Quadrant which is the Tangent of the said Arch, and let the measured distance be CB 125 Foot, which being multiplied by 72, the Product is 9000, from which cutting off his Figures be­cause the Radius is supposed to be 100, the Height inquired will be 90 Foot, he that desires to per­form this work with more exactness, must make use of the Table of Sines and Tangents Natural or Artificial, this we think sufficient for our pre­sent purpose.

Proposition II.

To find an inaccessible Height at two Stations.

Take any Station at pleasure as at D, and there looking through the Sights of your Quadrant to the top of the Object, observe what Degrees are cut by the Thread in the Limb, which admit to be 68 Degrees, then remove backward, till the An­gle taken by the Quadrant, be but half so much [Page 49] as the former, that is 34 Degrees, then is the di­stance between your two Stations equal to the Hypothenusal Line at your first Station, viz. AD. if the distance between your two Stations were 326 foot, then draw a Line at pleasure as BD, upon the Point D protract, the Angle ADB 68 Degrees, according to your first Observation, and from your Line of equal parts set off the Hy­pothenusal 326 Foot from D to A, and from the Point A let fall the Perpendicular AB which be­ing measured in your Scale of Equal Parts, shall be the Altitude of the Object inquired.

Or working by the Table of Sines and Tan­gents, the Proportion is.

As the Radius, is to the measured distance or Hypothenusal Line AD; so is the Sine of the Angle ADE, to the height AB inquired.

Another more General way, by any two Stations taken at pleasure.

Admit the first Station to be as before at D, and the Angle by observation to be 68 Degrees, and from thence at pleasure I remove to C, where observing aim I find the Angle at C to be 32 De­grees, and the distance between the Stations 150 Foot. Draw a Line at pleasure as BC, and upon Clay down your last observed Angle 32 Degrees, and by help of your Scale of Equal Parrs, set off your measured distance from C to D 150 Foot, then upon D lay down your Angle of 68 De­grees, according to your first Observation, and where the Lines AD and AC meet, let fall the Perpendicular AB, which being measured in your Scale of Equal Parts, shall be the height of the Object as before.

[Page 50] Or working by the Tables of Sines and Tan­gents, the Proportions.

1. As the Sine of DAC to the Distance DC. So the Sine of ACD, to the Side AD.

2. As the Radius, to the Side AD; so the Sine ADB, to the Perpendicular height AB inquired.

The taking of Distances is much after the same manner, but because there is required either some alteration in the sights of your Quadrant or some other kind of Instrument for the taking of Angles, we will particularly shew, how that may be also done several ways, in the next Chapter.

CHAP. X.

Of the taking of Distances.

FOr the taking of Distances some make use of a Semicircle, others of a whole Circle, with Ruler and Sights rather than a Quadrant, and al­though the matter is not much by which of these Instruments the Angles be taken, yet in all Cases the whole Circle is somewhat more ready, than either a Semicircle or Quadrant, the which with its Furniture is called the Theodolite.

2. A piece of Board or Brass then about twelve or fourteen Inches Diameter, being made Circular like a round Trencher, must be divided into four Quadrants, and each Quadrant divided into 90 Degrees, or the whole Circle into 360, and each Degree into as many other Equal Parts, as the largeness of the Degrees will well permit: let your Circle be numbred both ways to 360, that is from the right hand to the left, and from the left to the right.

[Page 51] 3. Upon the backside of the Circle there must be a Socket made fast, that it may be set upon a three legged Staff, to bear it up in the Field.

4. You must also have a Ruler with Sights fixed at each end, for making of Observation, either fixed upon the Center of your Circle, or loose, as you shall think best; your Instrument being thus made, any distance whether accessible or inacces­sible may thus be taken.

5. When you are in the Field, and see any Church, Tower, or other Object, whose Distance from you, you desire to know, choose out some other Station in the same Field, from whence you may also see the Object, and measure the distance between your Stations; then setting your Ruler upon the Diameter of your Circle, set your In­strument so, as that by the Sights on your Ruler, you may look to the other Station, this done turn your Ruler to that Object whose distance you de­sire to know, and observe how many Degrees of the Circle are cut by the Ruler, as suppose 36 De­grees, as the Angle ACD in Fig. 30. Then re­moving your Instrument to D, lay the Ruler on the Diameter thereof, and then turn the whole In­strument about till through your Sights you can espy the mark set up at your first Station at C, and there fix your Instrument, and then upon the Cen­tre of your Circle turn your Ruler till through the Sights you can espy the Object whose distance is inquired, suppose at A; and observe the De­grees in the Circle cut by the Ruler, which let be 112, which is the Angle ADC, and let the di­stance between your two Stations be DC 326 Foot; so have you two Angles and the side be­tween them, in a plain Triangle given, by which [Page 52] to find the other sides, the which by protraction may be done as hath been shewed, in the fifth Pro­position of Chapter 8. but by the Table of Sines and Tangents, the Proportion is.

As the Sine of DAC, is to DC; so is the Sine of ACD to the Side AD.

Or, as the Sine of DAC, is to the given Side DC.

So is the Sine of ADC to the Side AC.

6. There is another Instrument called the plain Table, which is nothing else, but a piece of Board, in the fashion and bigness of an ordinary sheet of paper, with a little frame, to fasten a sheet of pa­per upon it, which being also set upon a Staff, you may by help of your Ruler, take a distance there­with in this manner.

Having measured the distance between your two Stations at D and C, draw upon your paper a Line, on which having set off your distance place your Instrument at your first Station C, and laying your Ruler upon the Line so drawn there­on, turn your Instrument till through the Sights you can espy the Station at D, then laying your Ruler upon the Point C, turn the same about till through the Sights you can espy the Object at A, and there draw a Line by the side of your Ruler, and remove your Instrument to D, and laying your Ruler upon the Line DC, turn the Instru­ment about, till through the Sight you can espy the Mark at C, and then laying your Ruler upon the Point D, turn the same, till through the Sights you can espy the Object at A, and by the side of your Ruler draw a Line, which must be extended till it meet with the Line AC, so shall the Line AD being measured upon your Scale of Equal [Page 53] Parts, be the distance of the Object from D, and the Line AC shall be the distance thereof from C.

7. And in this manner may the distance of two, three or more Objects be taken, from any two Stations from whence the several Objects may be seen, and that either by the plain Table, or The­odolite.

CHAP. XI.

How to take the Plot of a Field at one Station, from whence the several Angles may be seen.

ALthough there are several Instruments by which the Plat of a Field may be taken, yet do I think it sufficient to shew the use of these two, the plain Table and Theodolite.

2. In the use of either of which the same chain which is used in taking of heights and distances, is not so proper. I rather commend that which is known by the Name of Gunter's Chain, which is four Pole divided into 100 Links; being as I con­ceive much better for the casting up the Content of a Piece of Ground, than any other Chain that I have yet heard of, whose easie use shall be explain­ed in its proper place.

3. When you are therefore entered the Field with your Instrument, whether plain Table, or Theodolite, having chosen out your Station, let visible Marks be set up in all the Corners thereof, and then if you use the plain Table, make a mark upon your paper, representing your Stati­on, and laying your Ruler to this Point, direct [Page 54] your Sights to the several Corners of the Field, where you have caused Marks to be set up, and draw Lines by the side of the Ruler upon the paper to the point representing your station, then measure the distance of every of these Marks from your Instrument, and by your Scale set those distances upon the Lines drawn upon the paper, making small marks at the end of every such distance, Lines drawn from Point to Point, shall give you upon your paper, the Plot of the Field, by which Plot so taken the content of the Field may easily be computed.

Example. Let Fig. 31. represent a Field whose Plot is required; your Table being placed with a sheet of paper thereupon, make a Mark about the middle of your Table, as at A. apply your Ruler from this Mark to B and draw the Line AB, then with your Chain measure the distance there­of which suppose to be 11 Chains 36 Links, then take 11 Chains 36 Links from your Scale, and set that distance from A to B, and at B make a mark.

Then directing the Sights to C, draw a Line by the side of your Ruler as before, and measure the distance AC, which suppose to be 7 Chains and 44 Links, this distance must be taken from your Scale, and set from A to C upon your paper.

And in this manner you must direct your Sights from Mark to Mark, until you have drawn the Lines and set down the distances, between all the Angles in the Field and your station, which being done, you must draw the Lines from one Point to another, till you conclude where you first began, so will those Lines BC. CD. DE. FG. and GB, give you the exact Figure of the Field.

4. To do this by the Theodolite, in stead of [Page 55] drawing Lines upon your paper in the Field, you must have a little Book, in which the Pages must be divided into five Columns, in the first Column whereof you must set several Letters to signifie the several Angles in the Field, from which Lines are to be drawn to your place of standing, in the second and third Columns the degrees and parts taken by your Instrument, and the fourth and fifth, to set down your distances Chains and Links, this being in readiness, and have placed your Instrument direct your Sights to the first mark at B, and observe how many De­grees are comprehended between the Diameter of your Instrument, and the Ruler, and set them in the second and third Columns of your Book against the Letter B, which stands for your first Mark, then measure the distance AB as before, and set that down, in the fourth and fifth Co­lumns, and so proceed from Mark to Mark, until you have taken all the Angles and Distances in the Field, which suppose to be, as they are ex­pressed in the following Table.

 Degr.PartChainsLinks
B39751156
C4075744
D9600748
E4325892
F8000608
G5925973

5. Having thus taken the Angles and Distances in the Field, to protract the same on Paper or [Page 56] Parchment, cannot be difficult; for if you draw a Line at pleasure as EB representing the Dia­meter of your Instrument about the middle there­of, as at A, mark a Mark, and opening your Com­passes to 60 Degrees in your Line of Chords, up­on A as a Center describe a Circle, then lay your Field book before you seeing that your first Ob­servattion cut no Degrees, there are no Degrees to be marked out in the Circle, but the Degrees at C are 40.75 which being taken from your Line of Chords, you must set them from H to I, and draw the Line AI. the Degrees at D are 96 which must in like manner be set from I to K, and so the rest in order.

This done observe by your Field-book the length of every Line, as the Line AB at your first Observation was 11 Chains and 36 Links, which being by your Scale set from A will give the Point B in the Paper, the second distance be­ing set upon AI will give the Point C, and so proceeding with the rest, you will have the Points BCDEF and G, by which draw the Lines BC. CD. DE; EF. FG and GB, and so at last you have the Figure of the Field upon your Paper, as was required.

And what is here done at one station, may be done at two or more, by measuring one or two distances from your first station, taking at every station, the Degrees and distances to as many An­gles, as are visible at each station.

And as for taking the the Plot of a-Field by In­tersection of Lines, he that doth but consider how the distances of several Objects may be taken at two stations, will be able to do the other also, and therefore I think it needless, to make any il­lustration by example.

CHAP. XII.

How to take the Plot of a Wood, Park or other Cham­pion Plain, by going round the same, and making Observation at every Angle.

BY these Directions which have been already given, may the Plot of any Field or Fields be taken, when the Angles may be seen alone or more stations within the Field, which though it is the case of some Grounds, it is not the case of all; now where observation of the Angles cannot be observed within, they must be observed without, and although this may be done by the plain Ta­ble, yet as I judge it may be more conveniently done by the Theodolite, in these cases thereof I chiefly commend that Instrument, I know some use a Mariners Compass, but the working with a Needle is not only troublesom, but many times uncertain, yet if a Needle be joyned with the Theodolite the joynt Observations of the Angles may serve to confirm one another.

2. Suppose the Fig. 32. to be a large Wood whose Plot you desire to take; Having placed your Instrument at the Angle A, lay your Ruler on the Diameter thereof, turning the whole Instru­ment till through the Sights you espy the Angle at K, then fasten it there, and turn your Ruler up­on the Center, till through the Sights you espy your second Mark at B, the Degrees cut by the Ruler do give the quantity of that Angle BAK, suppose 125 Degrees, and the Line AB 6 Chains, 45 Links, which you must note in your Field-book, as was shewed before.

[Page 58] 3. Then remove your Instrument to B, and laying your Ruler upon the Diameter thereof, turn it about, till through the Sights you can espy your third mark at C, and there fasten your In­strument, then turn the Ruler backward till through the Sights you see the Angle at A, the Degrees cut by the Ruler being 106.25 the quan­tity of the Angle ABC, and the Line BC contain­ing 8 Chains and 30 Links, which note in your Field-book, as before.

4. Remove your Instrument unto C, and laying the Ruler on the Diameter thereof, turn the In­strument about till through the Sights you see the Angle at D, and fixing of it there, turn the Ruler upon the Center till you see your last station at B, and observe the Degrees cut thereby, which sup­pose to be 134 Degrees, and the Line CD 6 Chains 65 Links, which must be entered into your Field-book also, and because the Angle BCD is an in­ward Angle, note it with the Mark [...] for your better remembrance.

5. Remove your Instrument unto D, and Iaying the Ruler on the Diameter, turn the Instrument a­bout, till through the Sights, you see the Angle at E, and there fixing your Instrument, turn your Ruler backward till you espy the Mark at C, where the Degrees cut are, suppose 68.0 and the Line DE 8 Chains and 23 Links.

6. Remove your Instrument unto E, and laying the Ruler on the Diameter, turn the Instrument about, till through the Sights you see the Angle at F, and there fix it, then turn the Ruler back­ward till you see the Angle at D, where the De­grees cut by the Ruler suppose to be 125 and the Line EF 7 Chains and 45 Links.

[Page 59] 7. Remove your Instrument unto F, and laying your Ruler upon the Diameter, turn the Instru­ment about, till through the Sights, you see the Angle at G, where fix the same, and turn the Ruler backward till you see the Angle at E, where the Degrees cut by the Ruler are 70, and the Line FG 4 Chains 15 Links, which must be set down with this [...] or the like Mark at the Angle.

8. Remove your Instrument unto G, and lay­ing your Ruler upon the Diameter, turn the In­strument about, till through the Sights you see the Angle at H, where fix the same, and turn the Ru­ler backward till you see the Angle at F, where the Degrees cut by the Ruler are 65.25, and the Line GH 5 Chains 50 Links.

9. Remove your Instrument in like manner to H and K, and take thereby the Angles and Di­stances as before, and having thus made observa­tion at every Angle in the Field, set them down in your Field-book, as was before directed, the which in our present Example will be as follow­eth.

A151.006.45
B106.258.30
C [...]134.006.65
D68.008.23
E125.007.45
F [...]70.254.15
G65.255.50
H130.006.50
K140.0011.00

The taking of the inward Angles BCD and EFG was more for Conformity sake than any [Page 60] necessity, you might have removed your Instru­ment from B to D, from E to G, the Length of the Lines BC. CD. EF and G, would have given by protraction the Plot of the Field without taking these Angles by observation; many other com­pendious ways of working there are, which I shall leave to the discretion of the Ingenious Pra­ctitioner.

10. The Angles and Sides of the Field being thus taken, to lay down the same upon Paper, Parchment, another Instrument called a Protractor is convenient, the which is so well known to In­strument-makers, that I shall not need here to describe it, the chief use is to lay down Angles, and is much more ready for that purpose than a Line of Chords, though in effect it be the same.

11. Having then this Instrument in a readiness draw upon your Paper or Parchment upon which you mean to lay down the Plot of that Field, a Line at pleasure as AB. Then place the Center of your Protractor upon the Point A, and be­cause the Angle of your first observation at A was 115 Degrees 00 Parts, turn your Protractor a­bout till the Line AK lie directly under the 115 Degree; and then at the beginning of your Pro­tractor make a Mark, ând draw the Line AB, set­ting off 6 Chains 45 Links from A to B.

12. Then lay the Center of your Protractor upon the Point B, and here turn your Protractor about, till the line AB lie under 106 Degrees 25 Parts, and draw the Line BC, setting off the Distance 8 Chains, 30 Links from B to C.

13. Then lay the Center of your Protractor upon the Point C, and turn the same about till the Line BC lie under 134 Degrees, but remember [Page 61] to make it an inward Angle, as it is marked in your Field-Book, and there make a Mark, and draw the Line CD, setting off 6 Chains, 65 Links from C to D.

And thus must you do with the rest of the Sides and Angles, till you come to protract your last Angle at H, which being laid down accord­ing to the former Directions the Line HK will cut the Line AK making AK 11 Chains and HK 6 Chains, 50 Links. This work may be also per­formed by protracting your last observation first; for having drawn the Line AK, you may lay the Center of your Protractor upon the Point K, and the Diameter upon the Line AK; and because your Angle at K by observation was 140 Degrees, you must make a Mark by the Side of your Protractor at 140 Degrees; and draw the Line KH, setting off 6 Chains, 50 Links from K to H. And thus proceeding with the rest of the Lines and Angles, you shall find the Plot of your Field at last to close at A, as before it did at K.

CHAP. XIII.

The Plot of the Field being taken by any Instrument, how to compute the Content thereof in Acres, Roods, and Perches.

THe measuring of many sided plain Figures hath been already shewed in the 13 Propositi­on of the 8 Chapter, which being but well conside­red, to compute the Content of a Field cannot be difficult; It must be remembred indeed that 40 square Pearches do make an Acre.

[Page 62] 2. Now then if the Plot be taken by a four Pole Chain divided into 100 Links, as 16 square Poles are the tenth part of an Acre; so 10.000 square Links of such a Chain are equal to 16 square Pole, or Perches; and by consequence 100.000 square Links are equal to an Acre, or the square Pearches.

3. Having then converted your Plot into Tri­angles, you must cast up the Content of each Triangle as hath been shewed, and then add the several Contents into one Sum, and from the aggre­gate cut off five Figures towards the right hand; the remainer of the Figures towards the left hand are Acres, and the five Figures so cut off towards the right hand are parts of an Acre, which being multiplied by four, if you cut off five Figures from the Product, the Figures remaining towards the left hand are Roods, and the five Figures cut off are the parts of a Rood, which being multi­plied by forty, if you cut off five Figures from the Product, the Figures remaining towards the left hand are Perches, and the Figures cut off are the Parts of a Pearch.

Example. Let 258.94726 be the Sum of seve­ral Triangles, or the Content of a Field ready cast up, the three Figures towards the left hand 258 are the Acres, and the other Figures towards the right hand 94726 are the Decimal Parts of an Acre, which being multiplied by 4, the Pro­duct is 3.78904, that is three Roods and 78904 Decimal Parts of a Rood, which being multiplied by 40, the product is 31.56160, that is 31 Perch­es and 56160 Decimal Parts of a Perch; and therefore in such a Field there are Acres 258, Roods 3, Pearches 31, and 56160 Decimal Parts of a Perch.

CHAP. XIV.

How to take the Plot of Mountainous and uneven Grounds, and how to find the Content.

VVHen you are to take the Plot of any Mountainous or uneven piece of Ground, such as is that in Figure 33, you must first place your Instrument at A, and direct your Sights to B, measuring the Line AB, observing the Angle GAB, as was shewed before, and so proceed from B to C, and because there is an as­cent from C to D, you must measure the true length thereof with your Chain, and set that down in your Book, but your Plot must he drawn according to the length of the Horizontal Line, which must be taken by computing the Base of a right angled Plain Triangle, as hath been shewed before, and so proceed from Angle to Angle until you have gone round the Field, and having drawn the Figure thereof upon your Paper, reduce into Triangles and Trapezias, as ABC. CDE. ACEF and AFG. then from the Angles B. C. D. F and G; let fall the Perpendiculars, BK. CN. DL. FM. and GH. This done you must measure the Field again from Angle to Angle, setting down the Distance taken in a straight Line over Hill and Dale, and so likewise the several Perpendiculars, which will be much longer than the streight Lines measured on your Scale, and by these Lines thus measured with your Chain cast up the Content; which will be much more than the Horizontal Content of that Field according to the Plot, but if it should be otherwise plotted than by the Ho­rizontal [Page 64] Lines, the Figure thereof could not be contained within its proper limits, but being laid down among other Grounds, would force some of them out of their places, and therefore such Fields as these must be shadowed off with Hills, if it be but to shew that the Content thereof is computed according to the true length of the Lines from Corner to Corner, and not according to their Distance measured by Scale in the Plot.

CHAP. XV.

How to reduce Statute Measure into Customary, and the contrary.

VVHereas an Acre of Ground by Statute Measure is to contain 160 square Perches, measured by the Pole or Perch of sixteen foot and a half: In many places of this Nation, the Pole or Perch doth by custom contain 18 foot, in some 20. 24. 28 Foot; it will be therefore re­quired to give the Content of a Field according to such several quantities of the Pole or Perch.

2. To do this you must consider how many square Feet there is in a Pole according to these several Quantities.

  • In 16.5 to the Pole, there are 272.25 sq. feet.
  • In 18 to the Pole there are 324 square feet.
  • In 20 to the Pole there are 400 square feet.
  • In 24 to the Pole there are 576 square feet.
  • In 28 to the Pole there are 784 square feet.

Now then if it were desired to reduce 7 Acres, 3 Roods, 27 Perches, according to Statute Measure, into Perches of 18 Foot to the Perch; first re­duce [Page 65] your given quantity, 7 Acres. 3 Rods, 27 Poles into Perches, and they make 1267 Perches.

Then say, as 324. to 272. 25. so is 1267 to 1065. 6. that is 1065 Perches, and 6 tenths of a Perch. But to reduce customary Measure into sta­tute measure, say as 272. 25. is to 324 so is 1267 Perches in customary measure, to 1507. 8 that is 1507 Perches and 8 tenths of a Perch in statute measure, the like may be done, with the custo­mary measures of 20.24 and 28 or any other mea­sure that shall be propounded.

CHAP. XVI.

Of the Measuring of solid Bodies.

HAving shewed how the content of all plains may be computed, we are now come to the measuring of solid Bodies, as Prisms, Pyramids and Spheres, the which shall be explained in the Propositions following.

Proposition. I.

The base of a Prism or Cylinder being given, to find the solid content.

The base of a Prism is either Triangular, as the Pentahedron; Quadrangular, as the Hexahedron, or Multangular, or the Polyhedron Prism, all which must be computed as hath been shewed, which done if you multiply the base given by the altitude, the product shall be the solid content required.

Example. In an Hexahedron Prism, whose base [Page 66] is quadrangular, one side of the Base being 65 foot and the other 43, the Superficies or Base will be 27. 95. Which being multiplyed by the Alti­tude, suppose 12. 5. the product. 359. 375. is the so­lid content required.

In like manner the Base of a Cylinder being 45. 6. and the altitude 15. 4. the content will be 702. 24.

And in this manner may Timber be measured whether round or squared, be the sides of the squa­red Timber equal or unequal.

Example. Let the Diameter of a round piece of Timber be 2. 75 foot. Then, As 1 it to 785397. so is the square of the Diameter 2. 75. to 5.9395 the Superficial content of that Circle.

Or if the circumference had been given 8. 64. then, As 1 is to 079578, so is the square of 8. 64. to 5.9404 the superficial content.

Now then if you multiply this Base 5. 94. by the length, suppose 21 foot, the content will be 124. 74.

If the side of a piece of Timber perfectly square be 1.15 this side being multiplyed by it self, the product will be 1.3225 the superficial content, or content of the Base, which being multiplyed by 21 the length, the content will be 27. 7745.

Or if a piece of Timber were in breadth 1. 15. in depth 1.5 the content of the Base would be 1.725 which being multiplied by 21 the length, the content will be. 36. 225.

Proposition. II.

The Base and Altitude of a Pyramid or Cone being given, to find the solid content.

[Page 67] Multiply the Altitude by a third part of the Base, or the whole Base by a third part of the Al­titude, the Product shall be the solid content re­quired.

Example. In a Pyramid having a Quadrangu­lar Base as in Fig. 22. The side CF 17. CD 9. 5. the Product is the Base CDEF. 161. 5, which being multiplyed by 10.5 the third of the Alti­tude AB 31.5 the Product is 1695.75 the con­tent. Or the third of the Base. viz. 53. & 3 being multiplied by the whole Altitude AB 31.5 the Product will be the content as before.

2. Example. In Fig. 21. Let there be given the Diameter of the Cone AB 3. 5. The Base will be 96. 25. whose Altitude let be CD 16.92 the third part thereof is 5.64 & 96.25 being multipli­ed by 5.64, the Product 542.85 is the solid con­tent required.

Proposition. III.

The Axis of a Sphere being given, to find the so­lid content.

If you multiply the Cube of the Axis given by 523598 the solid content of a Sphere whose Ax­is is an unite, the Product shall be the solid content required.

Example. Let the Axis given be [...], the Cube thereof is 27, by which if you multiply. 523598, the Product 14.137166 is the solid content re­quired.

Proposition. IV.

The Basis and Altitude of the Frustum of a Pyra­mid or Cone being given, to find the content.

If the aggregate of both the Bases of the Frust­an and the mean proportional betwe [...]n them, shall be multiplied by the third part of the Altitude, the Product shall be the solid content of the Frustum.

Example. In Fig. 22. Let CDEF represent the greater Base of a Pyramid, whose superfici­al content let be 1. 92, and let the lesser Base be HGLKO. 85 the mean proportional between them is. 1. 2775 and the aggregate of these three numbers is. 4. 0475. Let the given Altitude be 15. the third part thereof is. 5 by which if you mul­tiply 4.0475 the Product 20. 2375 is the content of the Frustum Pyramid.

And to find the content of the Frustum Cone. I say.

As. 1. ro 78539. so 20.23 to 15. 884397, the content of the Cone required.

But if the Bases of the Frustum Pyramid shall be square, you may find the content in this man­ner.

Multiply each Diameter by it self and by one another, and the aggregate of these Products, by the third part of the altitude, the last Product shall be the content of the Frustum Pyramid.

Example. Let the Diameter of the greater Base be 144, the Diameter of the lesser Base 108, and the altitude 60.

The Square of 144 is
20736
The Square of 108 is
11664
The Product of 1444108 is
15552
The Sum of these 3 Products is
47952

Which being multiplyed by 20 the third part of the Altitude, the Product 959040 is the con­tent of the Frustum Pyramid.

And this content being multiplied by .785 39 the content of the Frustum Cone will be .753 .228.

Another way.

Find the content of the whole Pyramid of the greater and lesser Diameter, the lesser content de­ducted from the greater, the remain shall be the content of the Frustum. To find the content of the whole Pyramid, you must first find their se­veral Altitudes in this manner.

As the difference between the Diameters,

Is to the lesser Diameter.

So is the Altitude given, to the Altitude cut off.

Example. The difference between the former Diameter. 144. and 108 is 36, the Altitude 60. now then As 36. 108∷60. 108. the altitude cut off.

Now then if you mnltiply the lesser Base 1 1664 by 60 the third part of 180 the Product 699840 is the content of that Pyramid.

And adding 60 to 180 the Altitude of the great­er Pyramid is 240, the third part whereof is 80, by which if you multiply the greater Base before found, 70736, the Product is the content of the [Page 70] greater Pyramid. 1658880, from which if you deduct the lesser 699840 the remainer 959040 is the content of the Frustum Pyramid as before.

And upon these grounds may the content of Taper Timber, whether round or square, and of Brewers Tuns, whether Circular or Elliptical, be computed, as by the following Propositions shall be explained.

Proposition. V.

The breadth and depth of a Taper piece of Squared Timber, both ends being given together with the length, to find the content.

Let the given Dimensions.
  • At the Bottom be A. 5.75 and B 2.34
  • At the Top. C. 2.16 and D. 1.83.
  • And let the given length be 24 Foot.

According to the last Proposition, find the A­rea or Superficial content of the Tree at both ends thus.

Multiply the breadth3.750.574031
By the depth2.340.369215
The Product8.77500.943246
2. Multiply the breadth2.160.334453
By the depth1.820.262451
The Product is3.95280.596904
[Page 71] 3. Multiply the 1. Content.877500.943246
by the second content.3.95280.596904
And find the square root5.89861.540150
  0.770075

The Sum of these 18.6264 being multiplyed by 8 one third of the length, the content will be found to be 149. 0112. Thus by the Table of Logarithms the mean proportional between the two Bases is easily found, and without extracting the square Root, may by natural Arithmetick be found thus.

A 4 2/2 CX A half C multiplyed by B: And C more half A multiplyed by D being added toge­ther and multiplyed by 30, the length shall give the content. Example.

A. 3.75C 2.16
1/2 C. 1.081/2 A 1.875
Sum 4.83Sum. 4.035
B- 2.34D. 1.83
193212105
144932280
9664035
11.30227.38405
 11.30220
The sum of the Products18.68625

Being multiplyed by 8 the third of the length, the content will be. 149. 49000. The like may be done for any other.

Proposition VI.

The Diameters of a piece of Timber being given at the Top and and Bottom, together with the length, to find the content.

The Proposition may be resolved either by the Squares of the Diameters, or by the Areas of the Circles answering to the Diameters given, for which purpose I have here annexed not only a Ta­ble of the Squares of all numbers under a thou­sand, but a Table sharing the third part of the Areas of Circles in full measure, to any Diame­ter given under 3 foot.

And therefore putting S = The Sum of the Tabular numbers answering to the Diameters at each end.

X = The difference between these Diameters.

L = the length of the Timber, C = The content.

Then 1 ½ S = ½ - XX. + L. = C.

If you work by the Table of the squares of Numbers. you must multiply the less side of the Equation, by 0.26179 the third part of 0.78539 the Product being multiplyed by the length, will give the content.

But if you work by the Table of the third parts of the Areas of Circles in full measure, the ta­bular Numbers being multiplyed by the length will give the content. Only instead of the square of the difference of the Diameter, you must take half the Tabular number answering to that Dif­ference, and you shall have the content as be­fore. Example.

[Page 73]

Let the greatest Diameter by 2.75, and the less 1. 93.
Their difference is 0.83
The square of 2.75 is
7.5625
The square of 1.93 is
3.7249.
The Sum of the Squares
11.2874
The half Sum
5.6437
The Sum of them is
16.9311
Half the square of 0.82 deduct.
0.3362
The Difference is
16.5949
Which being multiplyed by
26179
 
1493541
 
1161643
 
165949
 
995694
 
331898
The Product will be.
4.344378871

Or by the Table of Areas.
The Area of 2.75 is
1.979857
The Area of 1.93 is
0.975176
The Sum
2.955033
The half Sum
1.477516
The Sum of them
4.432549
Half the Area of 0.82 deduct
0.088016
The former Product
4.344533
Which being multiplyed by
24
 
17378132
 
8689066
The content is
104268792

But because that in measuring of round Tim­ber the circumference is usually given and not the Diameter, I have added another Table by which the circumference being given, the Diame­ter may be found.

Example. Let the circumference of a piece of Timber be 8325220 looking this Number in the second column of that Table, I find the next less to be 8.168140 and thence proceeding in a streight Line, I find that in the seventh Column the Num­ber given, and the Diameter answering thereun­to to be 2. 65. and thus may any other Diameter be found not exceeding the three foot. The Proportion by which the Table was made, is thus. As 1. to 3.14159 so is the Diameter given, to the circumference required.

[Page] [Page]

[figure]

[Page 75] Or the Circumference being given, to find the Diameter, say: As. 1. to 0.3183, so is the Circum­ference given to the Diameter required.

And although by these two Tables all round Timber may be easily measured, yet it being more usual to take the Circumference of a Tree, then the Diameter, I have here added a third Table, shewing the third part of the Areas of Circles answering to any circumference under 10 foot, and that in Natural and Artificial numbers, the use of which Table shall be explained in the Proposition following.

Proposition. VII.

The Circumference of a piece of round Timber at both ends, with the length being given, to find the con­tent.

The Circumference of a Circle being given, the Area thereof may be found as hath been shewed, in the 7 Chapter, Proposition 4. and by the first Pro­position of this; and to find the third part of the Area, which is more convenient for our purpose I took a third part of the number given by which to find the whole, that is a third part of 07957747 that is 0.02652582 and having by the multiplying this number by the square of the Circumference computed three or four of the first numbers, the rest were found by the first and second differences.

The Artificial numbers were computed by ad­ding the Logarithms of the Squares of the cir­cumference, to 8.42966891 the Logarithm of 0. 02652582.

And by these Natural and Artificial numbers [Page 76] the content of round Timber may be found two ways

By the Natural numbers in the same manner as the content was computed, the Diameters being given, and by the Natural and Artificial numbers both, by finding a mean proportional between the two Areas at the top and bottom of the Tree, as by Example shall be explained.

Let the given Diamensions, or Circumferences be At the Bottom 9.95 Their difference is 6.20 At the Top 3.75

The tabular Numbers.
 NaturalArtificial.
Answering to 9.952.6261620.418931
And to 3.750.3730199.571731
The Sum of the Logarith.
9.990662
The half Sum or Logarith. 989300
9.995331
The Sum of the Number is
3.988481
The Sum of the Natural Numbers is
2.9 [...]9181
The half Sum
[...].499190
The Sum of them
4.498771
Half the number answer. to. 6. 20 is
0.509826
The remainer is
3.988945

Which being multiplyed by the length 24, the content will be 95. 73468.

Mr. Darling in his Carpenters Rule made easie, doth propound a shorter way, but not so exact, which is by the Circumference given in the middle of the piece to find the side of the Square, name­ly [Page 77] by multiplying the Circumference given by 28209, or 2821. which side of the Square being computed in Inches, and lookt in his Table of Timber measure, doth give the content of the Tree not exceeding 31 foot in length, the which way of measuring may be as easily performed by this Table. Example.

The circumference at the top and bottom of the Tree being given 9.95 and 3.75 the Sum is 13.70 The half thereof is the mean circumfer. 6.85 Which sought in the Table, the Numbers are.

The Natural number is 1.244657, which being multiplyed by 3 the Product is 3.733971, which multiplyed by the length 24, the content is 89. 615304.

The Artificial number is
0.095049
The Logarithm of 24 is
1.380211
The Absolute Number 29.871
1.475260
Which multiplyed by 3, the Product is
89613

Proposition. VIII.

The Diameters of a Brewers Tun at top and bottom being given with the height thereof, to find the con­tent.

In Fig. 29. Let the given Diameter.

At the top be AC 136 BD 128

At the bottom. KG 152 HF 144 Altit. 51 Inches.

The which by the 5 Proposition of this Chap. may thus be computed. AC 139 + ½ KG 76 = 212 × BD 128 the Product is 27136.

[Page 78] And KG 1524 ½ AC 68 = 220 × HF 144 the Product is 31680. the Sum of these 2 Products is 58816 which being multiplyed by onethird of 51, that is by 17, and that Product multiplyed by 26179 the third of 78539 will give the content.

The Logarithm of 58816. is
54.76949
The Logarithm of 17 is
1.230449
The Product
1.999944
The Logarithm of. 26179
9.417968
The content is. 261765
5.417912

Thus the content of a Tun may be found in In­ches, which being divided 282 the number of In­ches in an Ale Gallon, the quotient will be the con­tent in Gallons.

Or thus; divide the former. 26179 by 282 the quotient will be 00092836. by which the content may be found in Ale Gallons in this manner.

The former Product
5.999944
The Logarithm of 0.00092836
6.967719
The content in Gallons 928.24
2.967663

Proposition. IX.

The Diameters of a close Cask, at head and bung with the length given, to find the content.

In the resolving of this Proposition, we are to consider the several forms of Casks, as will as the kind of the Liquor, with which it is filled, for one and the same Rule will not find the con­tent in all Cask.

[Page 79] And a Coopers Cask is commonly taken, ei­ther for the middle Frustum of a Spheroid, the middle Frustum of a Parabolical Spindle, the mid­dle Frustum of two Parabolick Conoids, or for the middle Frustum of two Cones abutting upon one common Base.

And the content of these several Casks may be found either by equating the Diameters, or by e­quating the Circles. for the one, a Table of Squares is necessary, and a Table shewing the third part of the Areas of a Circle to all Diameters. The making of the Table of Squares, every one knows, to be nothing else but the Product of a Number multiplyed, by it self, thus the Square of 3 is 9. the Square of 8 is 64 and so of the rest.

And the Area of a Circle to any given Diame­ter may be found, as hath been shewed, in Chap. 7 Proposition 2. But here the Area of a Circle in In­ches, will not suffice, it will be more fit for use, if the third part of the Area be found in Ale and Wine Gallons both, the which may indeed be done by dividing the whole Area in Inches by 3 and the quotient by 282 to make the Table for Ale-measure, and by 231 to make the Table for Wine-measure; but yet these Tables (as I think) may be more readily made in this manner.

The Square of any Diameter in Inches, being divided by 3.81972 will give the Area of the Cir­cle in Inches: And this Division being multiply­ed by 282 will give you 1077.161 for a common Division, by which to find the Area in Ale-Gal­lons, or being multiplyed by 231 the Product, 882.355 will be a commou Division by which to find the Area in Wine-Gallons.

But because it is easier to multiply then divide: [Page 80] If you multiply the several Squares by 26178 the third part of 78539 the Product will give the Area in Inches, or if you divide. 26179 by 282 the quotient will be. 00092886 for a common Mul­tiplicator, by which to find the Area in Ale-Gal­lons, or being divided by 231 the quotient will be 0011333 a common Multiplicator, by which to find the content in Wine-Gallons. An Exam­ple or two will be sufficient for illustration. Let the Diameter given be 32 Inches, the Square thereof 1024 being divided by 3.81970 the quo­tient is 268.083, and the same Square 1024 be­ing multiplyed by 261799, the Product will be 268. 082.

Again if you divide 1024 by 1077.161 the quotient will be 9508, or being multiplied by 00092836, the Product will be 9508.

Lastly if you divide 1024 by 882.755, the quo­tient will be 1.1605, or being multiplied by 00113333 the Product is 1.1605,

And in this manner may the Tables be made for Wine and Beer-measure, but the second differen­ces in these Numbers being equal, three or four Numbers in each Table being thus computed, the rest may be found by Addition only.

Thus the Squares of 1. 2. 3. and 4 Inches are. 1. 4. 9 and 16 by which if you multiply 00113333, the several Products will be third part of the Area, of the Circles answering to those Diameters in Wine-Gallons. Or 00092836 being multiplied by those Squares, the several Products, will be the third part of the Areas of the Circles answering to those Diameters in Ale-Gallons; the which with their first and second differences are as fol­loweth.

[Page 81]

The Products or Areas in Wine-Gallons:
1.00113333  
2.0045333233999226666
3.01019997566665226666
4.01813328796331 
The Products in Ale-Gallons.
1.00092836  
2.00371344278508185672
3.00835524464180185672
4.01485376649852 

And by the continual addition of the second differences to the first, and the first differences to the products before found, the Table may be con­tinued as far as you please.

The construction of the Tables being thus shewed: We will now shew their use in finding the content of any Cask.

Let S = the Sum of the Tabular Numbers an­swering to the Diameters at the Head and Bung. D = their difference X = the difference of the Diameters themselves. L = the length of the Vessel, and C = the content thereof.

1. If a Cask be taken for the middle Frustum of a Spheroid, intercepted between two Planes parallel, cutting the Axis at right Angles: Then 1 ½ S + ½ D × L = C.

2. If a Cask be taken for the middle Frustum of a parabolical Spindle, intercepted between two planes parallel cutting the Axis at right Angles. Then 1 ½ S + ½ D × L = C.

[Page 82] 3. If a Cask be taken for the middle Frustum of two Parabolick Conoids, abutting upon one common Base, intercepted between two Planes parallel, cutting the Axis at right Angle: Then 1 ½ S: × L = C.

4. If a Cask be taken for the middle Frustum of two Cones, abutting upon one common bafe, intercepted between two Planes parallel cutting the Axis at Right Angles. Then 1 ½ S—⅓ XX. × L = C.

In all these four Equations, if you work by the Table of Squares of numbers, you must multi­ply the less side of the Equation by 262, if you would have the content in Cubical Inches; by 001133 if you would have the content in Wine-Gallons; and by 000928, if you would have the content in Ale-Gallons.

But if you work by the Tables of the third parts of the Areas Circle, the Tabular Numbers being multiplyed by the length only will give the content required, only in the fourth Equation instead of half the Square of the Difference of the Diameters, take half the Tabular Number answering to that difference, and you shall have the content required; as by the following Exam­ples will better appear, then by many words.

Examples in Wine-measure by the Table of the Squares of Numbers.

The Diameter of a Vessel

At the Bung being 32 Inches.

At the Head 22 Inches.

The difference of the Diameters 10 Inches.

And the length of the Vessel 44 Inches.

[Page 83]

Spheroid.Parabolick Spindle.
10241024
484484
15081508
754754
270540
253223160
253223160
759669480
759669480
759669480
28695156262472280
4444
114780624104988912
114780624104988912
126.2586864115.4878032

[Page 84]

Parabolick ConoidCone.
10241024
484484
15081508
754754
 50
22622212
22622212
67866636
67866636
67866636
2563524625068596
4444
102540984200274384
102540984100274384
112.79508241110.30182224

[Page 85] This which hath been done by the Table of Squares may be more easily performed, by the Table of the third part of the Areas of Circles, ready reduced to Wine-Gallons.

SpheroidParabolick Spindle.
1.160531.16053
0.548530.54853
1.709061.70906
8545385453
3060061200
2.869592.624790
4444
11478361049916
114783610499160
126.26196115.490760

[Page 86]

Parabolick ConoidCone.
1.160531.16053
0.548530.54853
1.709061.70906
8545385453
 56666
2.563592.506924
4444
102543610027696
102543610027696
112.79796110.304656

[Page 87] Examples in Ale-measure by the Table of the Squares of Numbers.

Spheroid.Parabolick Spindle.
10241024
484484
15081508
754754
270540
25322316.0
0009283600092836
2275820844
50644632
2025618528
75966948
15192138960
2356607522.150081760
4444
948623008860032704
940643008860032704
103.2267308894.60359744

[Page 88]

Parabolick ConoidCone.
10241024
484484
15081508
754754
 50
22622212
2035819909
45244424
1809617696
67866636
1352713272
2.099950322.05423232
4444
8.39980128821692928
839980128821692928
92.3978140890.38622208

[Page 89]

By the Areas of Circles.
Spheroid.Parabolick Spindle.
0.950520.95052
0.449300.44930
1.399821.39982
.6999169991
.25061050122
2.350342.149852
3444
9401368599408
9401368599408
103.4149694.593488

[Page 90]

Parabolick Conoid.Cone.
0.950520.95052
0.449300.44930
1.399821.39982
69991.69991
 46425
2099732.053305
4444
8398928213220
8398928213220
90.34542090.345420

And here for the Singularity of the Example, I will set the Dimensions of a Cask lately made in Herefordshire, for that excellent Liquor of Red streak Cyder, the like whereof either for the largeness of the Cask, or incomparable goodness of that kind of Drink, is not to be found in all England, nay and perhaps not in the World.

The length of the Cask is 104 Inches.

The Diameter at the Bung 92 Inches.

And the Diameter at the Head 74 Inches.

[Page 91] The Numbers in the Table of Ale-Gallons an­swering to these Dimensions are.

SpheroidParabolick Spindle.
Bung. 92 7.8596397.859639
Head. 74 5.0836995.083699
12.94133812.941338
6.4706696.470669
1.386770.277394
20.79877719.689401
104104
8319510878.757604
2079877719689401
Con. 2163.0728082047.697704

[Page 92]

Parabolick Conoid.Cone.
7.8576397.857639
5.0836995.083699
12.94133812.941338
6.4706696.470669
 0.150394
19.41200719.261613
104104
7764802877046452
1941200719261613
201. 8. 8487282003.207752

And thus you have the content of this Cask by four several Ways of Gauging, but that which doth best agree with the true content, found by these that filled the same is the second way or that which takes a Cask to be the middle Frustum of a Parabolick Spindle, according to which the content is 2047 Gallons. That is allowing 64 Gallons to the Hogshead. 32 Hogsheads very near.

Proposition. X.

If a Cask be not full, to find the quantity of Li­quor contained in it, the Axis being posited parallel to the Horizon.

To resolve this Proposition, there must be gi­ven the whole content of the Cask, the Diame­ter at the Bung, and the wet Portion thereof, then by help of the Table of Segments, whose Area is unity, and the Diameter divided into 10.000 equal parts, the content may thus be found.

As the whole Diameter, is to its wet Por­tion.

So is the Diameter in the Table. 10.000 to its like Portion, which being sought in the Table of Segments, gives you a Segment, by which if you multiply the whole content of the Cask, the Product is the content of the Liquor remaining in the Cask.

But in the Table of Segments in this Book, you have the Area, to the equal parts of one half of the Diameter only, when the Cask therefore is more then half full, you must make use of the dry part of the Diameter instead of the wet, so shall you find what quantity of Liquor is wanting to fill up the Cask, which being deducted from the whole content of the Cask; the remainer is the quantity of Liquor yet remaining, an Exam­ple in each will be sufficient, to explane the use of this Table.

1. Example, In a Wine Cask not half full, let the great Diameter be as before 32 Inches, the [Page 94] content 126.25 Gallons, and let the wet part of the Diameter be 12 Inches, First I say.

As the whole Diameter 32. is to the wet part 12. so is 10.000 to 3750, which being sought in the Table, I find, the Area of that Segment to be. 342518 which being multiplyed by the whole content of the Cask 126.25, the Product is 43.24289750 and therefore there is remaining in the Cask 43 & 1/4 ferè.

2. Example. In the same Cask let the wet part of the Diameter be 18 Inches. I say.

As 32.18 :: 10000.5625 whose Complement to 10000 is 4375 which being sought in the Ta­ble, I find the Area answering thereto to be 420630; now then I say.

As the whole Area of the Circle 1000000 is to the whole content of the Cask 126. 25.

So is the Area of the Segment sought. 420630, to the content 53.1044375 which is in this case the content of the Liquor that is wanting, this therefore being deducted from the content of the whole Cask, 136. 25. the part remaining in the Vessel is. 73. 1455625.

Thus may Casks be gauged in whole or in part, in which a Table of Squares is sometimes necessary, as being the Foundation, from whom the other Tables are deduced; such a Table therefore is here exhibited, for all Numbers un­der 1000, by help whereof the Square of any Number under 10.000 may easily be found in this manner.

The Rectangle made of the Sum and Difference of any two Numbers, is equal to the Difference of the Squares of these Numbers.

Example, Let the given Numbers be 36 and 85 [Page 95] their Sum is 121, their difference 49, by which if you multiply 121, the Product will be 5929. The Square of 36 is 1296, and the Square of 85 is 7225, the difference between which Squares is 5929 as before.

And hence the Square of any Number under 10.000 may thus be found, the Squares of all Numbers under 1000 being given.

Example. Let the Square of 5715 be required. The Square of 571 by the Table is 326041, there­fore the Square of 5710 is 32604100: the Sum of 5710 and 5715 is 11425, and the difference 5, by which if you multiple 11425, the Product is 52125 which being added unto 32604100 the Sum 32656325 is the Square of 5715. The like may be done for any other.

TABLES FOR THE Measu …

TABLES FOR THE Measuring OF TIMBER, AND THE GAUGING OF CASKS AND Brevvers Tuns.

LONDON, Printed for Thomas Passinger at the three Bibles on London-Bridge. 1679.

[Page 99]

A Table of Squares.
113
24 
3095
4167
5259
63611
74913
86415
98117
1010019
1112121
1214423
1316025
1419627
1522529
1625631
1728733
1832435
1936137
2040039
2144141
2248443
2352945
2457647
2562549
2667651
2772953
2878455
2984157
3090059
3196161
32102463
33108965
34115667
34115669
35122571
36120673
37136975
38144477
39152179
40160081
41168183
42176485
43184187
44193689
45202591
46211693
47220995
48230497
49240199
502500101
512601103
522704105
532809107
542916109
553025111
563136113
573249115
583364117
593481119
603600121
613721123
623844125
633969127
644096129
654225131
664356133
674489135
674489135
684624137
604761139
704900141
715041143
725184145
735329147
745476149
755625151
765776153
775929155
786084157
796241159
806400161
816561163
826724165
836889167
847056169
057225171
067396173
877559175
887744177
897921179
908100181
918281183
928464185
938649187
948836189
959025191
969216193
979409195
989604197
999801199
10010000201
[Page 100] 10110201203
10210404205
10310609207
10410816209
10511025211
10611236213
10711449215
10811664217
10911881219
11012100221
11112321223
11212544225
11312769227
11412996229
11513225231
11613456233
11713689235
11813924237
11914161239
12014400241
12114641243
12214884245
12315129247
12415376249
12515625251
12615876253
12716129255
12816384257
12916641259
13016900261
13117161263
13217424265
13317689267
13417956269
13417956269
13518225271
13618496273
13718769275
13819044277
13919321279
14019600281
14119881283
14220164285
14320449287
14420736289
14521025291
14621316293
14721609295
14821904297
14922201299
15022500301
15122801303
15223104305
15323409307
15423716309
15524025311
15624336313
15724649315
15824964317
15925281319
16025600321
16125921323
16226244325
16326569327
16426896329
16527225331
16627556333
16727889335
[Page 101] 16727889335
16828224337
16928561339
17028900341
17129241343
17229584345
17329929347
17430276349
17530625351
17630976353
17731329355
17831684357
17932041359
18032400361
18132761363
18233124365
18333489367
18433856369
18534225371
18634596373
18734969375
18835344377
18935721379
19036100381
19136481383
19236864385
19337249387
19437636389
19538025391
19638416393
19738809395
19839204397
19939601399
20040000401
20140401403
20240804405
20341209407
20441616409
20542025411
20642436413
20742849415
20843264417
20943681419
21044100421
21144521423
21244944425
21345369427
21445796429
21546255431
21646656433
21747089435
21847524437
21947961439
22048400441
22148841443
22249284445
22349729447
22450176449
22550625451
22651076453
22751529455
22851984457
22952441459
23052900461
23153361463
23253824465
23354289467
23454756469
[Page 102] 23454756469
23555225471
23655696473
23756169475
23856644477
23957121479
24057600481
24158081483
24258564485
14359049487
24459536489
24560025491
24660516493
24761009495
24861504497
24962001499
25062500501
25163001503
25263504505
25364009507
25464516509
25565025511
25665536513
25766049515
25866564517
25967071519
26067600621
26168121523
26268644525
26369169527
26469696529
26570225531
26670756533
27771289535
26771289535
26871824537
26972361539
27072900541
27173441543
27273984545
27374529547
27475076549
27575625551
27676176553
27776729555
27877284557
27977841559
28078400561
28178961563
28279524565
28380089567
28480616569
28581225571
28681796573
28782369575
28882944577
28983521579
29084100581
29184681583
29285264585
29385849587
29486436589
29587025591
29687616593
29788200595
29888804597
29989401599
30090000601
[Page 103] 301090601603
302091204605
303091809607
304092416609
305093025611
306093636613
307094249615
308094864617
309095481619
310096109621
311096721623
31297344625
31397969627
31498596629
31599325631
31699856633
317100487645
318101124637
319101761639
320102400641
321103041643
322103684645
323104329647
324104976649
325105625651
326106276653
327106929655
328107584657
329108241659
330108900661
331109561663
332110224665
333110889667
334111556669
334111556669
335112225671
336112896673
337113569675
338114244677
339114921679
340115600681
341116281683
342116964685
343117649687
344118336689
345119025691
346119716693
347120409695
348121104697
349121801699
350122500701
351123201703
352123904705
353124609707
354125316709
355126025711
356126736713
357127449715
358128164717
359128881719
360129600721
361138321723
362131044725
363131769727
364132496729
365133225731
366133956733
367134689735
[Page 104] 367134689735
368135424737
369136161739
370136900741
371137641743
372138384745
373139129747
374139876749
375140625751
376141376753
377142129755
378142884757
379143641759
380144400761
381145161763
382145924765
383146689767
384147456769
385148225771
386148996773
387149769775
388150544777
389151321779
390152100781
391152881783
392153664785
393154449787
394155236789
395156025791
396156816793
397157609795
398158404797
399159201799
400160000801
401160801803
402161604805
403162409807
404163216809
405164025811
406164836813
407165649815
408166464817
409167281819
410168100821
411168921823
412169744825
413170569827
414171396829
415172225831
416173056833
417173889835
418174724837
419175561839
420176400841
421177241843
422178084845
423178929847
424179776849
425180625851
426181476853
427182329855
428183184857
429184041859
430184900861
431185761863
432186624865
433187489867
434188356869
[Page 105] 434188356869
435189225871
436190096873
437190969875
438191844877
439192721879
440193600881
441194481883
442195364885
443196249887
444197136889
445198025891
446198916893
447199809895
448200704897
449201601899
450202500901
451203401903
452204304905
453205209907
454206116909
455207025911
456207936913
457208849915
458209764917
459210681919
460211600921
461212521923
462213444925
463214369927
464215296929
465216225931
466217156933
467218089935
467218089935
468219024937
469219961939
470220900941
471221841943
472222784945
473223729947
474224676949
475225625951
476226576953
477227529955
478228484957
479229441959
480230400961
481231361963
482232324965
483233289967
484234256969
485235225971
486236196973
487237169975
488238144977
489239121979
490240100981
491241081983
492242064985
493243049987
494244036989
495245025991
496246016993
497247009995
498248004997
499249001999
5002500001001
[Page 106] 5012510011003
5022520041005
5032530091007
5042540161009
5052550251011
5062560361013
5072570491015
5082580641017
5092590811019
5102601001021
5112611211023
5122621441025
5132631691027
5142641961029
5152652251031
5162662561033
5172672891035
5182683241037
5192693611039
5202704001041
5212714411043
5222724841045
5232735291047
5242745761049
5252756251051
5262766761053
5272777291055
5282787841057
5292798411050
5302889001061
5312819611063
5322830241065
5332840891067
5342851561069
5342851561069
5352862251071
5362872961073
5372883691075
5382894441077
5392905211079
5402916001081
5412926811083
5422937641085
5432948491087
5442959361089
5452970251091
5462981161093
5472992091095
5483003241097
5493014011099
5503025001101
5513036011103
5523047041105
5533058091107
5543069161109
5553080251111
5563091361113
5573102491115
5583113641117
5593124811119
5603136001121
5613147211123
5623158441125
5633169691127
5643180961129
5653192251131
5663203561133
5673214891135
[Page 107] 5673214891135
5683226241137
5693237611139
5703249001141
5713260411143
5723271841145
5733283291147
5743294761149
5753306251151
5763317761153
5773329291155
5783340841157
5793352411159
5803364001161
5813375611163
5823387241165
5833398891167
5843410561169
5853422251171
5863433961173
5873445691175
5883457441177
5893469211179
5903481001181
5913492811183
5923504641185
5933516491187
5943528361189
5953540251191
5963552161193
5973564091195
5983576041197
5993588011199
6003690001201
6013612011203
6023624041205
6039636091207
6043648161209
6053660251211
6063672361213
6073684491215
6083696641217
6093708811219
6103721001221
6113733211223
6123745441225
6133757691227
6143769961229
6153782251231
6163794561233
6173806891235
6183819241237
6193831611239
6203844001241
6213856411243
6223868341245
6233881291247
6243893761249
6253906251251
6263918761253
6273931291255
6283943851257
6293956411259
6303969001261
6313981611263
6323994241265
6334006891267
6344019561269
[Page 108] 6344019561269
6354032251271
6364044961273
6374057691275
6384070441277
6394083211279
6404096001281
6414108811283
6424121641285
6434134491287
6444147361289
6454160251291
6464173161293
6474186091295
6484199041297
6494212011299
6504225001301
6514238011303
6524251041305
6534264091307
6544277161309
6554290251311
6564303361313
6574316491315
6584329641317
6594342811319
6604356001321
6614369211323
6624382441325
6634395691327
6644408961329
6654422251331
6664435561333
6674448891335
6674448891335
6684462241337
6694475611339
6704489001341
6714502411343
6724515841345
6734529291347
6744542761349
6754556251351
6764569761353
6774583291355
6784596841357
6794610411359
6804624001361
6814637611363
6824651241365
6834664891367
6844678561369
6854692251371
6864705961373
6874719691375
6884733441377
6894747211379
6904761001381
6914774811383
6924788641385
6934802491387
6944816361389
6954830251391
6964844161393
6974858091395
6984872041397
6994886011399
7004900001401
[Page 109] 7014914011403
7024928041405
7034942091407
7044956161409
7054970251411
7064984361413
7074998491415
7085012641417
7095026811419
7105041001421
7115055211423
7125069441425
7135083691427
7145097961429
7155112251431
7165126561433
7175140891435
7185155241437
7195169611439
7205184001441
7215198411443
7225212841445
7235227291447
7245241761449
7255256251451
7265270761453
7275285291455
7285299841457
7295314411459
7305329001461
7315343611463
7325358241465
7335372891467
7345387561469
7345387561469
7355402251471
7365416961473
7375431691475
7385446441477
7395461211479
7405476001481
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8.862.0822660.318536
8.872.0869690.319516
8.882.0916770.320494
8.892.0963910.321472
8.902.1011100.322448
8.912.1058340.323424
8.922.1105640.324498
8.932.1152990.325371
8.942.1200390.326343
8.952.1247840.327314
8.962.1295350.328284
8.972.1342910.329253
8.982.1390530.330221
8.992.1438190.331178
9.002.1485910.332153
9.012.1533682.333118
9.022.1581510.334081
9.032.1629390.335044
9.042.1677320.336005
9.052.1725310.337966
9.062.1773350.338925
9.072.1821440.338883
9.082.1869580.339840
9.092.1917780.340796
9.102.1966030.341751
[Page 149] 9.112.2014330.342705
9.122.2062690.343658
9.132.2111100.344610
9.142.2159560.345561
9.152.2208080.346511
9.162.2256650.347459
9.172.2305279.348407
9.182.2353940.349354
9.192.2402670.350299
9.202.2451450.351244
9.212.2500290.352881
9.222.2549170.353130
9.232.2598110.354072
9.242.2647110.355012
9.252.2696150.355872
9.262.2745250.356890
9.272.2794400.357828
9.282.2843610.358764
9.292.2892870.359700
9.302.2942180.360634
9.312.2991540.361568
9.322.3040960.362500
9.332.3090430.363432
9.342.3139960.364362
9.352.3189530.365292
9.362.3239160.366220
9.372.3288850.367148
9.382.3338580.368074
9.392.3388470.369000
9.402.3438210.369924
9.412.3481440.370848
9.422.3538060.371770
9.432.3588060.372692
9.442.3634780.373612
9.452.3684890.374532
9.462.3738380.375451
9.482.3788930.376368
9.482.3838860.377285
9.492.3889180.378201
9.502.3939550.37911 [...]
9.512.3989980.380029
9.522.4040450.380942
9.532.4090990.381854
9.542.4141570.382765
9.552.4192210.383675
9.562.4242900.384584
9.572.4293640.385492
9.582.4344440.386399
9.592.4395290.387306
9.602.4446290.388211
9.612.4497150.389115
9.622.4548160.390019
9.632.4599220.390921
9.642.4650340.391822
9.652.4701500.392723
9.662.4752730.393623
9.672.4804000.394521
9.682.4855330.395419
9.692.4906710.396316
9.702.4958140.397212
9.712.5009630.39810 [...]
9.722.5061170.399001
9.732.5112430.399894
9.742.5164410.400786
9.752.5216110.4 [...]1678
9.762.5267860.402568
9.772.5319660.403458
9.782.5371520.404346
9.792.5423430.405234
9.802.5475400.406121
[Page 150] 9.812.5527450.407006
9.822.5579480.407891
9.832.5631640.408775
9.842.5683780.409659
9.852.5736010.410541
9.862.5788290.411422
9.872.5840630.412303
9.882.5893020.413182
9.892.5945460.414061
9.902.5997950.414939
9.912.6050500.415816
9.922.6103100.416692
9.932.6155730.417567
9.942.6208460.418441
9.952.6261220.419315
9.962.6314040.420187
9.972.6366900.421059
9.982.6419820.421929
9.992.6472790.422789
10.002.6525820.423668

[Page 151] A Table for the speedy find­ing of the Length or Cir­cumference answering to a­ny Arch in Degrees and Decimal Parts.

[Page 152] A Table for the speedy find­ing of the Length or Circumfe­rence answering to any Arch, in Degrees and Decimal Parts.

10.017453292519
20.034906585038
30.052359877557
40.069813170076
50.087266462595
60.104719755114
70.122173047633
80.139626340152
90.157079632671
100.174532925190
110.191986217709
120.209439510228
130.226892802747
140.244346095266
150.261799387785
160.279252680304
170.296705972823
180.314159265342
190.331612557861
200.349065850380
210.366519142899
220.383972455418
230.401425727937
240.418879020456
250.436332312975
260.453785605495
270.471238898013
280.488682190532
290.506145483051
300.523548775570
310.541052068089
320.558505360608
330.575958653127
340.593411945646
350.610865238165
360.628318530684
370.645771283203
380.663225115722
390.680678408241
400.698131700760
410.715584993279
420.733038285798
430.750491578317
440.767944870836
450.785398163355
460.802831455874
470.820304748393
480.837758040912
490.855211333431
500.872664624950
[Page 153] 510.890117918469
520.907571210988
530.925024503507
540.942477796026
550.959931088545
560.977384381064
570.994837673583
581.012290966102
591.029744258621
601.047197551140
611.064650843659
621.082104136178
631.099557428697
641.117010721216
651.134464013735
661.151917306254
671.169370598773
681.186823891292
691.204277183811
701.221730476330
711.239183768849
721.256637061368
731.274090353887
741.291543646406
751.308996938925
761.326450231444
771.343903523963
781.361356816482
791.378810109001
801.396263401520
811.413716694039
821.431169986558
831.448623279057
841.466076571596
851.483529864115
861.500983156634
872.518436449153
881.535889741572
891.553343034191
901.570796326710
911.588249619229
921.605702911748
931.623156204267
941.640609496786
951.658062789305
961.675516081824
971.692969374343
981.710422666862
991.727875959381
1001.745329251900

[Page 154] A Common Divisor for the speedy converting of the Table, shewing the Area of the Segments of a Circle whose Diameter is 2.0000 &c. into a Table shewing the Area of the Segment of any Circle whose Area is given.

1003141592653
2006283185306
3009424777959
4012566370612
5015707963265
6018849555918
7021991148571
8025132741224
9028274333877
10031415926530
11034557519183
12037699111836
13040840704489
14043982297142
15047123889795
16050265482448
17053407075101
18056548667754
19059690260407
20062831853060
21065973445713
22069115038366
23072256631019
24075398223672
25078539816325
26081681408978
27084823001631
28088964594284
29091106186937
30094247779590
21097389372243
32100530964896
33103672557549
34106814150202
35109955742855
36113097335508
37116238928161
38119380520814
39122522113467
40125663706120
41128805298773
42131946891426
43135088484079
44138230076732
45141371669385
46144513262038
47147654854691
48150796447344
49153938039997
50157079632650
[Page 155] 51160221225303
52163362817956
53166504410609
54169646003262
55172787595915
56175929186568
57179070781221
58182212373874
59185353966527
60188495559180
61191637151833
62194778744486
63197920337139
64201061929792
65204203522445
66207345115098
67210486707751
68213628300404
69216769893057
70219911485710
71223053078363
72226194671016
53229336263669
74232477856322
75235619448975
76238761041628
77241902634281
78245044226934
79248185819587
80251327412240
81254469004893
82257610597546
83260752190199
84263893782852
85267035375505
86270176968158
87273318560811
88276460153464
89279601746117
90282743338770
91285884931423
92289026524076
93292168116729
94295309709382
95298451302035
96301592894688
97304734487341
98307876079994
99311017672647
100314159265300

[Page 156] A Table shewing the Ordi­nates, Arches and Areas of the Segments of a Circle, whose Diameter is 2000, &c. to every Hundredth Part of the Radius.

[Page 157]

 OrdinatesDeg. & Dec. p.Areas
1001000000000090.000000001.57079632
99999949997189.427041961.55079682
98999799979988.854007991.53079890
97999549898788.289871101.51080538
969991996797487.707561241.49081774
95998749217787.134020201.47083808
94998198377086.560187491.45086837
93997546991385.986015811.43091081
92996794863585.411435291.41096718
91995941765384.836395131.39103966
90994987437184.260830181.37113017
89993931587183.684686411.35124084
88992773891683.107898601.35137360
87991513993882.530407931.31153053
86990151503581.952154791.29171372
85988685996681.373074681.27192518
84987117013880.793104741.25216697
83985444062380.212181801.23244118
82983666610179.630240301.21274989
81981784090379.047216721.19309522
80979795897178.463041881.17347924
79977701385977.877621121.15390361
78975499871877.290967351.13437189
77973190628876.702929031.11488481
76970772887976.112436811.09544458
75968245836575.522488451.07605462
74965608616374.929960141.05671627
73962860322174.335733921.03743102
72960000000073.739794561.01820220
71957026645473.142024740.99903143
70953939201472.542397370.97992192
69950 [...]36556571.940769690.96087497
68947417542571.337075640.94189323
67943980931970.731224760.92297905
[Page 158] 67943980931970.731224760.92297905
66940425435670.123126620.90413479
65936749699769.512685220.88536283
64932952303168.899804010.86666560
63929031754068.284383260.84804557
62924986486467.666317840.82950517
61920814856467.045501170.81104695
60916515138966.421823240.79267345
59912085522265.795165670.77438721
58907524104365.165412980.75619089
57902828887464.532440200.73808713
56897997772863.896120580.72007866
55893028554963.256316450.70216884
54887918915262.612897540.68435845
53882666414961.965703870.66665234
52877268487961.314598380.64905275
51871722475560.659411810.63156249
50866025403760.000000000.61418485
49860174400959.336170610.59692260
48854166260158.667748750.57977892
47847997641557.994545530.56275702
46841665016557.316361470.54586011
45835164654456.633070650.52909299
44828492607055.944202560.51245467
43821644692655.249774330.49595300
42814626474154.549457420.47959008
41807403244953.842992050.46336957
40800000000053.130102370.44725221
39792401413452.410497080.43137885
38784601809851.683865970.41560051
37776595132550.949877480.39998818
36768374908450.208106570.38453683
35759934207649.458310120.36925312
34751265598848.700127210.35414227
[Page 159] 34751265598848.700127210.35414227
33742361098147.932935390.33920561
32733212111147.156357170.32444946
31723809367146.369891130.30987884
30714142842845.572996180.29549884
29704201675644.765084890.28131493
28693974062948.945519770.26733268
27683447144943.113606130.25355796
26672606868842.268584520.23999689
25661437827741.409625950.22665594
24649923072340.535802280.21354168
23638043885639.646111320.20066138
22625779513838.739424000.18802248
21613106842237.814488670.17563291
20600000000036.869897650.16350111
19586429876435.904068730.15163601
18572363520834.915206400.14004722
17557763390633.901255150.12874491
16542586398632.859880590.11774053
15526782687631.788330690.10704574
14510294032830.683417220.09667379
13493051721429.541361210.08663902
12474973683428.357736660.07695728
11455960524627.126753210.06764629
10435889894325.841932820.05872590
09414608248824.494648570.05021866
08391918358823.073918150.04215095
07367559518921.565185470.03455313
06341174442119.948443630.02746204
05312249899918.194872440.02092302
04280000000016.260204 [...]10.01499411
03243104915614.069861840.00975364
02198997487411.478340970.00551730
0114106735978.109614460.00188278
[Page 160] 01014106735978.109614460.00188278
00913386186917.692812470.00160779
00812623787077.252246800.00134761
00711811435136.783288920.00110317
00610938007136.279 [...]80640.00087554
00509987492175.731967970.00066616
00408935323165.126400100.00047674
00307740155034.439222280.00030969
00206321392253.624307500.00016860
00104471017782.562558740.00005961

[Page 161]

 1.57079632
999199999
 1.56879632
998199999
 1.56679632
 199999
9971.56479633
 199998
9961.56279634
 199997
9951.56079636
 199996
9941.55879639
 199995
9931.55679644
 199994
9921.55479649
 199992
9911.55299657
 199991
9901.55079666
 199988
9891.54879677
 199986
9881.54679690
 199984
9871.54479706
 199981
9861.54279724
 199978
9851.54079745
 199976
9841.53879769
 199972
9831.53679796
9831.53679796
 199969
9821.53479827
 199965
9811.53279862
 199962
9801.53079899
 199957
9791.52879941
 199953
9781.52679988
 199949
9771.52480039
 199944
9761.52280095
 199939
9751.52080156
 199934
9741.51880222
 199929
9731.51680293
 199924
9721.51480369
 199918
9711.51280451
 199912
9701.51080539
 199906
9691.50880633
 199909
9681.50680733
 199894
9671.50480839
 199887
9661.50280952
[Page 162] 9661.50280952
 199880
9651.50081072
 199873
9641.49881199
 199866
9631.49681333
 199859
9621.49481474
 199851
9611.49281623
 199843
9601.49081774
 199835
9591.48881938
 199827
9581.48682110
 199819
9571.48482291
 199810
9561.48282480
 199801
9551.48082678
 199792
9541.47882885
 199783
9531.47683102
 199774
9521.47483328
 199764
9511.47283563
 199754
9501.47083808
 199744
9491.46884063
9491.46884063
 199734
9481.46684328
 199724
9471.46484604
 199713
9461.46284890
 199702
9451.46085187
 199691
9441.45885496
 199680
9431.45685815
 199669
9421.45486146
 199657
9411.45286489
 199645
9401.45086837
 199633
9391.44887204
 199621
9381.44687583
 199608
9371.44487975
 199596
9361.44288379
 199585
9351.44088794
 199570
9341.43889224
 199557
9331.43689667
 199543
9321.43490124
[Page 163] 9321.43490124
 199530
9311.43290594
 199516
9301.43091078
 199502
9291.42891578
 199488
9281.42692090
 199473
9271.42492617
 199459
9261.42293158
 199444
9251.42093714
 199429
9241.41894305
 199413
9231.41694892
 199398
9221.41495494
 199382
9211.41296112
 199366
9201.41096746
 199350
9191.40897396
 199334
9181.40698062
 199318
9171.40498744
 199301
9161.40299443
 199284
9151.40100159
9151.40100159
 199267
9141.39900892
 199250
9131.39701642
 199232
9121.39502410
 199215
9111.39303195
 199197
9101.39103998
 199178
9091.38904820
 199160
9081.38705660
 199142
9071.38506518
 199123
9061.38307395
 199104
9051.38108291
 199085
9041.37909206
 199066
9031.37710140
 199047
9021.37511093
 199027
9011.37312066
 199007
9001.37113059
[Page 164] 9001.37113017
 198987
8991.36914030
 198967
8981.36715063
 198946
8971.36516117
 198925
8961.36317192
 198904
8951.36118288
 198883
8941.35919405
 198861
8931.35720544
 198839
8921.35521705
 198818
8911.35322887
 198797
8901.35124090
 198775
8891.34925315
 198752
8881.34726563
 198729
8871.34527834
 198707
8861.34329127
 198684
8851.34130443
 198661
8841.33931782
 198638
88 [...]1.33733144
8831.33733144
 198619
8821.33534525
 198590
8811.33335935
 198566
8801.33137360
 198541
8791.32938819
 198517
8781.32740302
 198499
8771.32541803
 198480
8761.32343323
 198449
8751.32144874
 198418
8741.31946456
 198393
8731.31748063
 198367
8721.31549696
 198341
8711.31351355
 198315
8701.31153053
 198289
8691.30954764
 198262
8681.30756502
 198235
8671.30558267
 198209
[Page 165]198209
8661.30360058
 198182
8651.30161876
 198154
8641.29963722
 198127
8631.29765595
 198100
8621.29567495
 198072
8611.29369423
 198044
8601.29171379
 198015
8591.28973357
 197986
8581.28775371
 197958
8571.2857741 [...]
 197929
8561.28379484
 197900
8551.28181584
 197871
8541.27983713
 197841
8531.27785872
 197811
8521.27588061
 197781
8511.27390280
 197751
8501.27192529
8501.27192518
 197721
8491.26994797
 197691
8481.26797106
 197660
8471.26599446
 197629
8461.26401817
 197598
8451.26204219
 197561
8441.26006658
 197534
8431.25809124
 197489
8421.25611635
 197457
8411.25414178
 197427
8401.25216751
 197395
8391.25019356
 197374
8381.24821982
 197341
8371.24624641
 197308
8361.24427333
 197275
8351.24230058
 197241
8341.24032817
 197212
[Page 166]197272
8331.23835605
 197173
8321.23638432
 197139
8311.23441293
 197105
8301.23244118
 197072
8291.23047046
 197036
8281.22850010
 197001
8271.22653009
 196966
8261.22456043
 196930
8251.22259113
 196895
8241.22062218
 196861
8231.21865357
 196825
8221.21668532
 196787
8211.21471745
 196750
8201.21274989
 196714
8191.21078275
 196677
8181.20881598
 196640
8171.20684958
8171.20684954
 1966 [...]3
8161.20488355
 196565
8151.20291790
 196527
8141.20 [...]95263
 196479
8131.19898774
 196451
8121.19702323
 196413
8111.19505910
 196375
8101.19309525
 196347
8091.19113254
 196298
8081.18916956
 196258
8071.18720698
 196219
8061.18524479
 196188
8051.18328291
 196148
8041.18132143
 196100
8031.17936043
 196060
8021.17739983
 196019
8011.17543964
 195978
8001.17347986
[Page 167] 8001.17347924
 195938
7991.17151986
 195897
7981.16956089
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 127488
2290.19938650
 127245
2280.19811405
 127002
2270.19684403
 126758
2260.19557645
 126514
2250.19431131
 126269
2240.19304862
 126023
2230.19178839
 125776
2220.19053063
 125528
2210.18927535
 125279
2200.18802248
 125027
2190.18677221
 124777
2180.18552444
 124529
2170.18427915
 124278
 124278
2160.18303637
 124025
2150.18179612
 123771
2140.18055841
 123517
2130.17932324
 123262
2120.17809062
 123006
2110.17686056
 122749
2100.17563291
 122490
2090.17440801
 122232
2080.17318569
 122974
2070.17196595
 121713
2060.17074882
 121451
2050.16953431
 121189
2040.16832242
 120926
2030.16711316
 120663
2020.16590653
 120399
2010.16470254
 120133
2000.16350121
[Page 185] 2000.16350111
 119866
1990.16230245
 119598
1980.16110647
 119329
1970.15991318
 119959
1960.15872259
 118789
1950.15753470
 118518
1940.15634952
 118246
1930.15516706
 117972
1920.15398733
 117698
1910.15281035
 117422
1900.15163596
 117146
1890.15046450
 116869
1880.14929581
 116591
1870.14812990
 116312
1860.14696678
 116032
1850.14580646
 115751
1840.14464895
 115468
1830.14349427
 115084
1820.14234243
 114900
1810.14119343
 114615
1800.14004728
 114328
1790.13890400
 114040
1780.13776354
 113752
1770.13612602
 163462
1760.13549140
 113164
1750.13435926
 112873
1740.13323103
 112587
1730.13210516
 112292
1720.13098224
 111996
1710.12986228
 111700
1700.12874498
 111403
1690.21763088
 111105
1680.12651983
 110805
1670.12541178
 110503
[Page 186]110503
1660.12430675
 110200
1650.12320475
 109896
1640.12210579
 109592
1630.12100987
 109287
1620.11991700
 108980
1610.11882720
 108671
1600.11774053
 108361
1590.11665692
 108047
1580.11557645
 107735
1570.11449910
 107425
1560.11342485
 107110
1550.11235375
 106794
1540.11128581
 106478
1530.11022103
 106159
1520.10915944
 105838
1510.10810106
 105517
1500.10704589
1500.10704589
 105194
1490.10599395
 104870
1480.10494525
 104545
1470.10389980
 104218
1460.10285762
 105889
1450.10181873
 103560
1440.10078313
 103229
1430.09975084
 102895
1420.09872199
 102561
1410.09769638
 102213
1400.09667379
 101876
1390.09565503
 101550
1380.09463953
 101210
1370.09362743
 100869
1360.09261874
 100526
1350.09161348
 100181
1340.09061167
 99834
[Page 187] 1330.08961333
 99461
1320.08861872
 99112
1310.08762760
 98786
1300.08663902
 98433
1290.08565469
 98078
1280.08467391
 97722
1270.08369669
 97364
1260.08272305
 97004
1250.08175301
 96643
1240.08078658
 96280
1230.07982378
 95915
1220.07886463
 95548
1210.07790915
 95179
1200.07695736
 94811
1190.07600925
 94438
1180.07506487
 94061
1170.07412426
 93685
 93685
1160.07318741
 93307
1150.07225434
 92901
1140.07132533
 92524
1130.07040009
 92161
1120.06947848
 91774
1110.06856074
 91386
1100.06764629
 90944
1090.06673685
 90551
1080.06583134
 90208
1070.06492926
 89811
1060.06403115
 89412
1050.06313703
 89011
1040.06224692
 88608
1030.06136084
 88202
1020.06047882
 87793
1010.05960089
 87382
1000.05872707
[Page 188] 1000.05872590
 86969
990.05785621
 86554
980.05699067
 86137
970.05612930
 85717
960.05527213
 85293
950.05441920
 84867
940.05357053
 84440
930.05272613
 84010
920.05188603
 83666
910.05104937
 83229
900.05121866
 82700
890.04939166
 82259
880.04856907
 81814
870.04775093
 81366
860.04693727
 80916
850.04612811
 89462
840.04532349
 80005
830.04452344
 79545
820.04372799
 79083
810.04293716
 78617
800.04215095
 78147
790.04136948
 77674
780.04058274
 77197
770.03982077
 76707
760.03905370
 76224
750.03829146
 75748
740.03753398
 75250
730.03678140
 74764
720.03603376
 34265
710.03529111
 73752
700.3455313
 73246
690.03382067
 72746
680.03309321
 72232
670.03237089
 71716
[Page 189]71716
660.03165373
 71193
650.03094180
 70664
640.03023516
 70132
630.02953384
 69995
620.02883789
 69054
610.02814735
 68508
600.02746204
 67961
590.02928243
 67405
580.02610838
 66840
570.02543998
 66273
560.02477725
 65701
550.02412024
 65123
540.02346901
 64539
530.02282362
 63950
520.02218412
 63353
510.02155059
 62750
500.02092309
500.02092302
 62143
490.02030159
 61528
480.01968631
 60906
470.01907725
 60277
460.01847448
 59640
450.01787808
 58996
440.01728812
 58344
430.01670468
 57683
420.01612784
 57016
410.01555768
 56340
400.01499411
 55655
390.01443756
 54960
380.01388796
 54256
370.01334540
 53540
360.01281000
 52815
350.01228185
 52079
340.01176106
 51331
[Page 190] 330.01124776
 50572
320.01074204
 49801
310.01024403
 49016
300.00975364
 48217
290.00927147
 47405
280.00879742
 46578
270.00833164
 45734
260.00787430
 44874
250.00742556
 43997
240.00698559
 43102
230.00655457
 42185
220.00613272
 41244
210.00572028
 40273
200.00531730
 39291
190.00492439
 38297
180.00454142
 37248
170.00416894
 36176
 36176
160.00380718
 35071
150.00345647
 33929
140.00311718
 32746
130.00278972
 31517
120.00247455
 30236
110.00217219
 28897
100.00188278
 27442
90.00160836
 25959
80.00134877
 24434
70.00110443
 22749
60.00087694
 20925
50.00066769
 18922
40.00047847
 16675
30.00031172
 14061
20.00017111
 10792
10.00006319
 6319
00.00000000
A TABLE SHEWING THE …

A TABLE SHEWING THE AREA OF THE SEGMENTS OF A CIRCLE WHOSE Whole Area is Unity, to the ten Thousandth part of the Diameter.

 0123456789 
0000000000004000007000011000014000018000025000032000039000046 
1000053000062000071000080000089000098000108000119000130000140 
2000151000163000175000187000200000212000225000238000251000265 
3000278000292000307000322000336000351000366000382000397000413 
4000428000444000461000478000494000511000529000546000564000581 
500059900061700063600065400067300069100071000072900074800076819
600078700080700082700084700086700088700090800092800094900097020
700099100101200103400105600107700109900112100114400116600118821
800121100123400125700128000130400132700135000137400139800142123
900144500146900149400151800154200156700159200161700164200166725
1000169200171700174300176900179400182000184600187300189900192526
1100195200197900200500203200205900208600211300214100216800219527
1200222300225100227900230700233500236300239200242000244900247728
1300250600253500256400259300262300265200268100271100274100277029
1400270000283000286000289000292100295100298200301300304300307430
1500310500313600316700319800322900326000329100332300335500338731
1600341900345100348300351500354800358000361200364500367800371032
170037430037760038090038420038 [...]600390900394200397600400900404333
1800407700411100414500417900421300424700428100431600435100438534
1900442000445500449000452500456000459500463000466500470000473535
2000477000480600484300487900491500495200498800502400506100509736
2100513300517000520600524300528000531700535400539100542800546537
22005502005539005 [...]7700561500565200569000572800576600580400584238
2300588000591800595700599500602300607200611100615000618800622739
240062660063 [...]500634400638300642300646200650100654100658100662039
2500666000670000673900677900681900685900689900694000698000702140
2600706100710200714200718300722300726400730500734600738700742941
2700747000751100755300759400763500767700771900776100780200784442
2800788600792800797000801200805500809700814000818200822500826742
2900831000835300839600843900848200852500856800861100865400869843
3000847100878500882800887200891600895900920300904700909100913544
3100917900922300926700931200935600940000944500949000953500957945
3200962400966900971400975900980400984900989400993900998501003045
3301007501012101016701021201025801030301034901039501044101048746
[Page 194-195] 3301007501012101016701021201025801030301034901039501044101048746
3401053301058001062601067201071901076501081201085801090501095247
3501099901104501109301113901118601123301128101132801137501142247
3601146901151701156501161201166001170701175501180301185101189947
3701194701199501204301209201214001218801223701228501233401238248
3801243101247901252801257701262601267501272401277301282301287249
390129210129700130 [...]001306901311801316801321801326701331701336750
4001341701346701351701356701361701366701371701376701381801386850
4101391901396901402001407101412101417201422301427401432501437551
4201442601447801452901458001463201468301473401478601483701488951
4301494101499201504401509601514801519901525201530401535601540852
4401546001551201556501561701566901572101577401582701587901593252
450159850160380160910161440161970162490163030163560164 [...]901646253
4601651501656901662201667601672901678301683701689101694401699854
4701705201790601716001721401726801732201737601743101748501753954
4801759301764801770301775701781201786601792101797601803101808655
4901814101819601825101830601836101841601847101852701858201863855
5001869301874901880401886001891601897101902701908301913901919556
5101925101930701936301941901947501953101958801964401970101975756
5201981301987001992701998402004002009702015402021102026802032557
5302038102043902049602055302061002066702072502078202084002089757
5402095402101202107002112802118502124302130102135902141602147457
5502153202159002164902170702176502182302188202194002199902205758
5602211502217402223302229202235002240902246802252702258602264559
5702270302276302282202288102294902299902305802311802317702323759
5802329602335602341502347502353402359402365402371402377402383460
5902389402395402401402407402413402419402425402431502437502443660
6002449602455702461702467802473802479902486002492102498102504260
6102510302516402522502528602534702540802547002553102569202565461
6202571502577602583802589902596102602202608402614602620802627062
6302633102639302645502651702657902664102670302676602682802689062
6402695202701502707702714002720202726402732702739002745302751563
6502757802764102770402776702783002789202795602801902808202814563
6602820802827102833502839802846102852402858802865202871502877963
[Page 196-197] 6702884202890602897002903402909702916102922502928902935 [...]02941764
6802948102954502961002967402973802980202986702993102999603006065
6903018403018903025303031803038303044703051203057703064203070765
7003077203083703090203096703103203109703116303122803129303135965
7103142403148903155503162003168603175103181703188303194903201466
7203208003214603221203227803234403240903247603254203260803267466
7303274103280703287303293903300603307203313903320503327203333866
7403340503347203353803360503367203373803387503387903393903400667
7503407303414003420803427503434203440903447703454403461203467967
7603474603481403488103494903501603508403515203521903528703535568
7703542303549103555903562703569503576303583103589903596803603668
7803610403617203624903630903637803644603651503658303665103672069
7903678903685803692703699503706403713303720203727103733903740869
8003747703754603761503768403775203782203789103796103803003809969
8103816903823903830803837803844703851703858703865703872703879770
8203886703893703900703907703914703921703928703935703942803949870
8303956803963803970903977903984903991903999004006104013104020271
8404027204034304041404048504055504063604070704077804084904092071
8504098104105204112304119404126504133604140704147904155004162171
8604169204176404183504190704197804205004212204219304226504233672
8704240804248004255204262404269604276804284004291204298404305672
8804312804320004327204334504341704348904356204363404370604377973
8904385204392404369704406904414204421404428704436004443304450573
9004457804465104472404479704487004494304501604508904516304523673
9104530904538204545604552904560304567604574904582304589604596974
9204604304611704619004626404633804641104648504655904663304670774
93046781046855046929047003047077047151047 [...]2504729904737404744874
9404752204759604767104774504781904789404796904804304811804819275
9504826704834204841704849104856604864104871604879104886604894175
9604901504909104916604924104931604939104946604954204961704969275
9704976704984304991804999405006905014405022605029605037105044775
9805052205059805067405075005082605090105097705105305112905120576
9905128105135805143405151005158605166205173805181505189105196876
10005204405212005219705227305235005242605250305257905265605273376
[Page 198-199]0123456789D
100052044052120052197052273052350052426052503052579052656052733076
101052810052886052963053040053117053193053271053348053425053502077
102053579053656053733053810053887053964054041054119054196054273077
103054351054428054506054583054661054738054816054893054973055049078
104055127055204055282055360055438055516055594055672055750055828078
105055906055984056062056140056218056296056374056453006531056610078
106056688056766056845056923057002057080057159057237057316057395079
107057474057552057631057710057789057868057946058025058104058183079
108058262058341058420058499058578058658058737058816058895058975079
109059054059133059213059292059372059451059531059610059690059769079
110059849059929060009060088060168060248060328060408060488060560080
111060648060728060808060888060968061048061128061208061289061369080
112061449061529061610061690061771061851061932062012062093062173080
113062254062334062415062496062576062657062738062819062900062981081
114063062063143063224063305063386063467063548063629063710063791081
115063873063954064035064116064198064279064360064442064523064605081
116064686064768064849064931065013065095065176065258065340065421082
117065503065585065667065749065831065913065995066077066159066241082
118066323066405066488066570066652066735066817066899066981067064082
119067146067229067311067393067476067559067642067724067807067889083
120067972068055068138068221068304068387068469068552068635068718083
121068801068884068967069051069134069217069300069384069467069550083
122069633069717069800069884069967070051070134070218070301070385083
123070468070552070635070719070803070887070970071054071138071222084
124071306071390071474071558071642071726071810071895071979072063084
125072148072232072316072400072484072569072653072733072822072906084
126072991073075073160073244073329073414073498073583073668073752084
127073837073922074007074092074177074262074347074432074517074602085
128074687074772074857074942075027075112075197075283075368075453085
129075539075624075709075795075880075966076051076137076222076908085
130076394076479076565076651076736076822076908076994077079077165086
131077251077337077423077509077595077681077767077853077939078025086
132078112078198078184078370078457078543078629078716078802078889086
133078975079062079148079235079321079408079494079581079668079754086
[Page 200-201] 133078975079062079148079235079321079408079494079581079668079754086
134079841079928080015080101080188080275080362080449080536080623087
13508071008079708088508g972081059081147081234081321081408081495087
136081582081669081756081841081931032018082106082193082281082368087
137082456082543082631082718082806082894082981083069083157083245087
138083333083420083508083596083684083772083860083948084036084124088
139084212084300084388084477084565084653084741084830084918085006088
140085095085183085271085359085448085536085625085714085802085891088
141085979086068086157086246086334086423086512086601086689086778089
142086867086956087045087134087223087312087401087490087579087668089
143087757087846087935088025088114088203088292088383088471088561089
144088650088740088829088920089009089099089188089278089366089456090
145089545089635089725089814089904089994090084090174090264090354090
14609044409053309062309071309080309089309098309107309116309125390
14709134409143409152409161409170409179509188509197509206609215690
14809224709233709242709251809260809269909279009288009297109306190
1490931520932430933330934240 [...]351509360609369609378709387809396991
15009406009415109424209433309442409451509460609469709478809487991
15109497109506209515309524409533509542709551809560909570109579291
15209588409597509606709615809624909634109643309652409661609670792
15309679909689109698209707409716609725809734909744109753309762592
15409771709780909790109799309808509817709826909836109845309854592
15509863709872909882209891409900609909809919109928309937509946892
15609956909965309974509983809983010002310011510020810030010039393
15710048610057810067110076310085610094910104210113510122710132093
15810141310150610159910169210178510187810197110206410215710125093
15910234310243610252910262210271510280910290210299510308810318293
16010327510336810346210355510364910374210383610392910402310411693
16110421010430410439710449110458410467810477210486610495910505394
16210514710524110533510542910552310561710571110580510589910599194
19310608710618110627510636910646310655710665110674510684010693494
16410702810712210721710731110740610750010759410768910778310787894
16510797210806710816110825610835010844510854010863410872710882495
16610891910901310910810920310929810939310948810958310967810977395
[Page 202-203] 16610891910901310910810920310929810939210948710968310967710977395
16710986710996311005811015311024811034311043811053311062811072395
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FINIS.
COSMOGRAPHIA, THE Se …

COSMOGRAPHIA, THE Second Part. OR, THE DOCTRINE OF THE PRIMUM MOBILE.

AN INTRODUCTION TO Astronomy.
The First Part.

Of the Primum Mobile.

CHAP. I.

Of the General Subject of Astronomy.

AStronomy, is a Science concerning the Measure and Motion of the Spheres and Stars.

2. Astronomy hath two parts, the first is Absolute, and the other Comparative.

3. The Absolute part of Astronomy is that which treateth of the Measure and Motion of the Orbs and Stars absolutely without respect to any distinction of Time.

[Page 226] 4. The Comparative part of Astronomy is that, which treateth [...] the Motion of the Stars, in reference to some certain distinction of Time.

5. The Absolute part of Astronomy treateth of the Primum Mobile, or Diurnal Motion of all the Celestial Orbs or Spheres.

6. The Primum Mobile, or Diurnal Motion of the Heavens, is that Motion, by which the se­veral Spheres are moved round the World in a Day [...] from East towards West, and [...]o forward [...] from West towards East, and so continually returning to the same point from whence they began their Mo­tion.

7. This first and common Motion of the Hea­vens, will be best understood, by help of an In­strument called a Globe, which is an Artificial re­presentation of the Heavens, or the Earth and Wa­ters under that Form and Figure of Roundness which they are supposed to have.

8. This Representation or Description of the Visible World is by Circles, great and small, some of which are expressed upon, and others are fra­med without the Globe.

9. The Circles without the Globe are chiefly two; the Meridian and the Horizon, the one of Brass, and the other of Wood▪ And these two Circles are variable or mutable; for although there is but one Horizon and one Meridian in re­spect of the whole World, or in respect of the whole Heaven and Earth, yet in respect of the particular parts of Heaven, or rather in respect of the diverse Provinces, Countries and Cities on the Earth, there are diverse both Horizons and Meridians.

[Page 227] 10. The Meridian then is a great Circle with­out the Globe, dividing the Globe, and conse­quently the Day and Night into two equal parts, from the North and South ends whereof a strong Wyre of Brass or Iron is drawn or supposed to be drawn through the Center of the Globe repre­senting the Axis of the Earth, by means whereof the whole Globe turneth round within the said Circle, so that any part may be brought directly under this Brass Meridian at pleasure.

11. This Brass Meridian is divided into 4 e­qual parts or Quadrants, and each of them are subdivided into 90 Degrees, that is 360 for the whole Circle. The reason why this Circle is not divided in 360 Degrees throughout, but still stop­ing at 90, beginneth again with 10. 20. 30 &c. is, for that the use of this Meridian, in reference to its Division in Degrees, requireth no more than that Number.

12. The Horizon is a great Circle without the Globe, which divides the upper part of Heaven from the lower, so that the one half is always above that Circle, and the other under it.

13. The Poles of this Circle are two, the one directly over our Heads, and is called the Zenith; the other is under feet, and is called the Na­dir.

14. The Horizon is either Rational or Sensi­ble.

15. The Rational Horizon is that, which divi­deth the Heavens and the Earth into two equal parts, which though it cannot be perceived and distinguished by the eye, yet may be conceived i [...] our minds, in which respect all the Stars may be conceived to rise and set as in our view.

[Page 228] 16. The Visible Horizon is that Circle which the eye doth make at its farthest extent of sight, when the body in any particular place doth turn it self round. Of these two Circles there need­eth no more to be said at present, only we may ob­serve, that it was ingeniously devised by those, who first thought upon it, to set one Meridian and one Horizon without the Globe, to avoid the confusion, if not the impossibility, of drawing a several Meridian and a several Horizon for eve­ry place, which must have been done if this or the like device had not been thought upon.

17. Besides these two great Circles without the Globe, there are 4 other great Circles drawn up­on the Globe it self besides the Meridian. 1. The AEquator or Equinoctial Circle. 2. The Zodiack. 3. The AEquinoctial Colure. 4. Sol­stitial Colure. And these four Circles are imm [...] ­table, that is, in whatsoever part of the World you are, these Circles have no variation, as the o­ther two have.

18. The AEquator is a great Circle drawn upon the Globe, in the middle between the two Poles▪ and plainly dividing the Globe into two equal parts.

19. The AEquator is the measure of the Moti­on of the Primum Mobile, for 15 Degrees of this Circle do always arise in an hours time; the which doth clearly shew, that the whole Heavens are turned round by equal intervals in the space of one day or 24 hours.

20. In this Circle the Declinations of the Stars are computed from the mid-Heaven towards the North or South.

[Page 229] 21. This Circle gives denomination to the AEquinox, for the Sun doth twice in a Year and no more cross this Circle, to wit, when he enters the first points of Aries, and Libra, and then he maketh the Days and the Nights equal: His en­trance into Aries is in March, and is called the Vernal Equinox; and his entrance into Libra, is in September, and is called the Autumnal Equi­nox.

22. And from one certain point in this Circle, the Longitude of Places upon the Earth are reckoned; and the Latitude of Places are reckoned from this Circle towards the North, or the South Poles.

23. The Zodiack is a great Circle drawn up­on the Globe, cutting the AEquinoctial Points at Oblique Angles: for although it divides the whole World into two equal parts, in reference to its own Poles; yet in reference to the Poles of the World, it hath an Oblique Motion.

24. The Poles of this Circle are as far distant from the Poles of the World, as the greatest Obliquity thereof is from the Equinoctial, that is 23 Degrees, and 31 Minutes or therea­bouts.

25. This Circle doth differ from all other Cir­cles upon the Globe in this: other Circles (to speak properly) have Longitude assigned them, but no Latitude; but this hath both. Whereas other Cir­cles are in reference to their Longitude or Rotun­dity only divided into 360 Degrees, this Circle in respect of its Latitude is supposed to be divided into 16 Degrees in Latitude.

26. The Zodiack then in respect of Longi­tude is commonly divided into 360 Degrees as o­ther [Page 230] Circles are: but more peculiarly in respect of its self it is divided into 12 Parts called Signs, and each Sign into 30 Degrees, and 12 times 30 do make 360.

27. The 12 Signs into which the Zodiack is divided, have these Names and Characters. Aries ♈. Taurus ♉. Gemini ♊. Cancer ♋. Leo ♌. Virgo ♍. Libra ♎. Scorpio ♏. Sagittarius ♐. Capricor­nus ♑. Aquarius ♒. and Pisces ♓.

28. These two Circles of the Equator and Zo­diack are crossed by two other great Circles, which are called Colures: They are drawn through the Poles of the World, and cut one another as well as the Equator at Right Angles. One of them passeth through the Intersections of the Equi­noctial points, and is called the Equinoctial Co­lure. The other passeth through the points of the greatest distance of the Zodiack, from the Equator, and is called the Solstitial Co­lure.

29. The other great Circles described upon the Globe are the Meridians: Where we must not think much to hear of the Meridians again. That of Brass without the Globe is to serve all turns, and the Globe is framed to apply it self thereto. The Meridians upon the Globe, will easily be perceived to be of a new and another use.

30. The Meridians upon the Globe are either the great or the less: Not that the great are any greater than the less, for they have all one and the same center, and equally pass through the Poles of the Earth; But those which are called less, are of less use than that, which is called the great.

[Page 231] 31. The great is otherwise called the fixt and first Meridian, to which the less are second, and respectively moveable. The great Meridian is as it were the Landmark of the whole Sphere, from whence the Longitude of the Earth, or any part thereof is accounted. And it is the only Circle which passing through the Poles is graduated or divided into Degrees, not the whole Circle but the half, because the Longitude is to be reckoned round about the Earth.

32. The lesser Meridians are those black lines; which you see to pass through the Poles and suc­ceeding the great at 10 and 10 Degrees, as in most Globes; or at 15 and 15 Degrees difference, as in some. Every place never so little more East or West than another, hath properly a several Me­ridian, yet because of the huge distance of the Earth from the Heavens, there is no sensible dif­ference between the Meridians of places that are less than one Degree of Longitude asunder, and therefore the Geographers as well as the Astrono­mers allow a new Meridian to every Degree of the Equator; which would be 180 in all: but ex­cept the Globes were made of an extream and an unusual Diameter, so many would stand too thick for the Description. Therefore most common­ly they put down but 18, that is, at 10 Degrees di­stance from one another; the special use of the les­ser Meridians being to make a quicker dispatch, in the account of the Longitudes. Others set down but 12, at 15 Degrees difference; aiming at this, That the Meridians might be distant from one another a full part of time, or an hour: for see­ing that the Sun is carried 15 Degrees of the E­quinoctial every hour, the Meridians set at that [Page 232] distance must make an hours difference in the ri­sing or setting of the Sun in those places which differ 15 Degrees in Longitude.

And to this purpose also upon the North end of the Globe, without the Brass Meridian, there is a small Circle of Brass set, and divided into two equal parts, and each of them into twelve, that is, twenty four all; to shew the hour of the Day and Night, in any place where the Day and Night exceed not 24 hours; for which purpose it hath a little Brass Pin turning about upon the Pole, and pointing to the several hours, which is therefore the Index Horarius, or Hour Index.

33. Having described the great Circles fra­med without and drawn upon the Globe, we will now describe the lesser Circles also; And these lesser Circles are called Parallels, that is, such as are in all places equally distant from the Equator; and these Circles how little soever, are supposed to be divided into 360 Degrees: but these De­grees are not so large as in the great Circles, but do proportionably decrease according to the Ra­dius by which they are drawn.

34. These lesser Circles are either the Tro­picks or the Polar Circles.

35. The Tropicks are two small Circles drawn upon the Globe, one beyond the Equator towards the North Pole, and the other towards the South, Shewing the way which the Sun makes in his Di­urnal Motion, when he is at his greatest distance from the Equator either North or South. These Circles are called Tropicks [...], that is, from the Suns returning: for the Sun coming to these Circles, he is at his greatest distance from the Equator, and in the same Moment of time [Page 233] sloping as it were his course, he returns nearer and nearer to the Equator again.

36. These Tropical Circles do shew the point of Heaven in which the Sun doth make either the longest Day, or the Shortest Day in the Year, ac­cording as he is in the Northern or the Southern Tropick: And are drawn at 23 Degrees and a half distant from the Equator.

37. The Polar Circles are two lesser Circles drawn upon the Globe at the Radius of 23 De­grees and a half distant from the Poles of the World, shewing thereby the Poles of the Zodi­ack, which is so many Degrees distant from the Equator on both sides thereof.

38. These Polar Circles are 66 Degrees and a half distant from the Equator, and 43 Degrees distant from his nearest Tropick. They are called the Arctick and Antarctick Circles.

39. The Arctick Circle is that which is descri­bed about the Arctick Pole, and passeth almost through the middle of the Head of the greater Bear. It is called the Arctick Circle [...] from the two conspicuous Stars towards the North; called the greater and the lesser Bear.

40. The Antarctick Circle is that which is de­scribed about the Antarctick or South Pole. It is so called [...] that is, from being oppo­site to the greater and lesser Bear.

Having thus described the Globe or Astronomi­cal Instrument by which the Frame of the World is represented to our view, I will proceed to shew the use for which it is intended.

CHAP. II.

Of the Distinctions and Affections of Sphe­rical Lines or Arches.

THE uses of the Globe as to practice, are ei­ther such as concern the Heavens or the Earth, in either of which, if we should descend unto particulars, the uses would be more in num­ber, than a short Treatise will contain: Seeing therefore that all Problems which concern the Globe, may be best and most accurately resol­ved by the Doctrine of Spherical Triangles, we will contract these uses of the Globe (which other­wise might prove infinite) to such Problems as come within the compass of the 28 Cases of Right and Oblique angled Spherical Triangles.

2. And that the nature of Spherical Trian­gles may be the better understood, and by which of the 28 Cases the particular Problems may be best resolved, I will set down some General De­finitions and Affections, which do belong to such Lines or Arches of which the Triangle must be framed, with the Parts and Affections of those Triangles, and how the things given and requi­red in them, may be represented and resolved upon and by the Globe, as also how they may be represented and resolved by the Projection of the Sphere, and by the Canon of Triangles.

3. A Spherical Triangle then is a Figure con­sisting of three Arches of the greatest Circles upon the Superficies of a Sphere or Globe, eve­ry one being less than a semicircle.

[Page 235] 4. A great Circle is that which divideth the Sphere or Globe into two equal parts, and thus the Horizon, Equator, Zodiack and Meridians before described are all of them great Circles: And of these Circles or any other, there must be three Arches to make a Triangle, and every one of these Arches severally must be less than a se­micircle: To make this plain.

In Fig. 1. The streight Line HAR doth repre­sent the Horizon, PR the height of the Pole a­bove the Horizon, PMS a Meridian, and these three Arches by their intersecting one another do visibly constitute four Spherical Triangles. 1. PMR. 2. PMH. 3. SHM. 4. SMR. And every Arch is less than a semicircle, as in the Triangle PMR, the Arch PR is less than the Se­micircle PRS, the Arch MR is less than the Se­micircle AMR, and the Arch PM is less than the Semicircle PMS, the like may be shewed in the other Triangles.

5. Spherical or circular Lines are Parallel or Angular.

6. Parallel Arches or Circles, are such as are drawn upon the same Center within, without, or equal to another Arch or Circle. Thus in Fig. 1. The Arches ♋ M ♋ and ♑ O ♑ are though lesser Circles, parallel to the Equinoctial AE A Q and do in that Scheme represent the Tropicks of Cancer and Capricorn. The manner of describing them or any other Parallel Circle is thus, set off their distance from the great Circle, to which you are to draw a parallel with your Compasses, by help of your Line of Chords, which in this Example is 23 Degrees and a half from AE to ♋, then draw the Line A ♋, and upon the point ♋ erect a Per­pendicular, [Page 236] where that Perpendicular shall cut the Axis PAS extended, is the Center of that Pa­rallel.

7. A Spherical Angle, is that which is con­teined by two Arches of the greatest Circles up­on the Superficies of the Globe intersecting one another: Angles made by the Intersection of two little Circles, or of a little Circle with a great, we take no notice of in the Doctrine of Spheri­cal Triangles.

8. A Spherical Angle is either Right or Ob­lique.

9. A Spherical Right Angle is that which is conteined, by two Arches of the greatest Circles in the Superficies of the Sphere cutting one ano­ther at Right Angles, that is, the one being right or perpendicular to the other: thus the Brass Meridian cutteth the Horizon at right An­gles; and thus the Meridians drawn upon the Globe, as well as the Brass Meridian, do all of them cut the Equator at Right Angles.

10. An Oblique Spherical Angle, is that which is conteined by two Arches of the greatest Circles in the Superficies of the Sphere, not be­ing right or perpendicular to one another.

11. An Oblique Spherical Angle is Obtuse, or Acute.

12. An Obtuse Spherical Angle, is that which is greater than a Right Angle. An Acute is that which is less than a Right Angle.

13. If two of the greatest Circles of the Sphere shall pass through one anothers Poles, those two great Circles shall cut one another at Right An­gles: Thus the Brazen Meridian doth intersect the Equinoctial and Horizon.

[Page 237] 14. If two of the greatest Circles of the Sphere shall intersect one another, and pass through each others Poles, they shall intersect one another at unequal or Oblique Angles, the Angle upon the one side of the intersection being Obtuse, or more than a Right, and the Angle upon the other side of the intersection being Acute or less than a Right. Thus in Fig. 1. The Arch PM doth intersect the Meridian and Horizon, but not in the Poles of either, therefore the Angle HPM upon one side of the intersection of that Arch with the Meridian, is more than a Right Angle; And the Angle MPR upon the other side of the Inter­section is less. And so likewise the Angle PMH upon the one side of the intersection of the Arch PM with the Horizon HR, is greater than a right Angle; and the Angle RMP upon the o­ther side of the Intersection is less than a Right.

15. A Spherical Angle is measured by the Arch of a great Circle described from the Angular point between the sides of the Angle, those sides being continued unto Quadrants. Thus the Arch of the Equator TQ in Fig. 1. is the measure of the Angle MPR, or TPQ, the sides PT and PQ being Quadrants.

And the measure thereof in the Projection may thus be found: lay a Ruler from P to T, and it will cut the Primitive Circle in V; and the Arch VQ being taken in your Compasses and applyed to your Line of Chords, will give the Quantity of the Angle propounded.

16. The Complement of a Spherical Arch or Angle, is so much as it wanteth of a Quadrant, if the Arch or Angle given be less than a Qua­drant; or so much as it wanteth of a Semicir­cle, [Page 238] if it be more than a Quadrant.

17. An Arch of a great Circle cutting the Arch of another great Circle, shall intersect one another at Right Angles, or make two Angles; which being taken together, shall be equal unto two Right. Thus in Fig. 1. The Axis PAS or Equinoctial Colure doth cut the Equator AE A Q at Right Angles; but the Meridian PMS doth cut the Horizon HMR at Oblique Angles, ma­king the Angle PMR less than a Right, and the Angle SMR more than a Right, and both to­gether equal to a Semicircle.

18. From these general Definitions proper to Spherical Lines or Arches, the general Affecti­ons of these Arches may easily be discerned; I mean the various Positions of the Globe of the Earth, in respect of all and singular the Inhabi­tants thereof.

19. And the whole Body of the Sphere or Globe, in respect of the Horizon, is looked upon by the Earths Inhabitants, either in a Parallel, a Right, or an Oblique Sphere.

20. A Parallel Sphere is, when one of the Poles of the World is elevated above the Horizon to the Zenith, the other depressed as low as the Na­dir, and the Equinoctial Line joyned with the Ho­rizon. They which there inhabite (if any such be) see not the Sun or other Star rising or setting, or higher or lower in their diurnal revolution. And seeing that the Sun traverseth the whole Zo­diack in a Year, and that half the Zodiack, is a­bove the Horizon and half under it, it cometh to pass, that the Sun setteth not with them, for the space of six Months, nor giveth them any Light for the space of other six Months, and so [Page 239] maketh but one Day and Night of the whole Year.

21. A Right Sphear is, when both the Poles of the World do lie in the Horizon, and the E­quinoctial Circle is at his greatest distance from it, passing through the Zenith of the place. And in this position of the Sphere, all the Coelestiall Bodies, Sun, Moon, and other Planets, and fix­ed Stars, by the daily turning about of the Hea­ven, do directly ascend above, and also directly descend below the Horizon, because the Moti­ons which they make in their Daily motion do cut the Horizon Perpendicularly, and as it were at Right Angles. In this Position of the Sphere, all the Stars may be observed to rise and set in an e­qual space of time, and to continue as long above the Horizon, as they do under it, the Day and Night to those Inhabitants, being always of an equal length.

22. An Oblique Sphere is, when the Axis of the World (being neither Direct nor Parallel to the Horizon) is inclined obliquely towards both sides of the Horizon, as in Fig. 1. Whence it co­meth to pass; that so much as one of the Poles is elevated above the Horizon, upon the one side; so much is the other depressed under the Hori­zon, upon the other side.

And in this Position of Sphere, the Days are some­times longer than the Nights, sometimes shorter, and sometimes of equal length. When the Sun is in either of the Equinoctial Points, the Days and Nights are equal; but when he declineth from the Equator towards the elevated Pole, the Days are observed to encrease; and when he declineth from the Equator towards the opposite Pole, or the Pole [Page 240] depressed, the Days do decrease▪ as is manifest in Fig. 1. For when the Sun riseth at M, the Line M ♋ above the Horizon is the Semidiurnal Arch of the longest day. When he riseth at C, the Arch C ♑ above the Horizon, is the Semidiurnal Arch of the shortest Day: And when he riseth at A, the Days and Nights are of equal Length, the Semi­diurnal Arch AAE, being equal to the Semino­cturnal Arch AQ.

CHAP. III.

Of the kind and parts of Spherical Trian­gles; and how to project the same upon the Plane of the Meridian.

HAving shewed what a Spherical Triangle is, and of what Circles it is composed, with the general Affections of such Lines: I will now shew how many several sorts of Triangles there are, of what Circular parts they do consist, and such Affections proper to them as will render the so [...]ition of them more clear and certain.

2. Spherical Triangles are either Right or Ob­lique.

3. A Right Angled Spherical Triangle, is that which hath one or more Right Angles.

4. A Spherical Triangle which hath three Right Angles, hath always his three sides Qua­drants. As in Fig. 1. The Spherical Triangle AZR, the Angles ZRA, RAZ and AZR are right Angles, and the three sides AZ, ZR and AR are Quadrants also.

[Page 241] 5. A Triangle that hath two right Angles, hath the sides opposite to those Angles Quadrants, and the third side is the measure of the third Angle. As in Fig. 1. The sides of the Spherical Trian­gle TPQ, namely TP and PQ are Quadrants, and the Angles opposite to these sides, to wit, PTQ and TQP are Quadrants also, and the third Angle TQ is the measure of the third Angle TPQ. But the Right Angled Triangle which hath one Right and two Acute Angles, is that which cometh most commonly to be resol­ved.

6. The Legs of a right Angled Spherical Triangle are of the same Affection with their op­posite Angles; as in the Triangle ZAR Fig. 1. The side ZA is a Quadrant, and the Angle at A is right, because Z is the Pole of the Arch AR and ZA is perpendicular thereunto. And in the Tri­angle RAAE the side RZAE being more then a Quadrant the Angle RAAE is more then a Quadrant also, being more then the Right An­gle RAZ. And in the right Angled Spherical Triangle APR the side PR being less then a Quadrant, the Angle PAR is less then a Quadrant also, being less then the right Angle RAZ.

7. An Oblique angled Spherical Triangle is either acute or obtuse.

8. An Acute angled Spherical Triangle hath all his Angles Acute, and each Side less then a Quadrant; As in the Triangles, ZFP. Fig. 2. The Angles at Z and P are acute, as appeareth by inspection; and the Angle at F is acute also be­cause the Measure thereof CD = EM is less then a Quadrant.

[Page 242] 9. An Oblique Angled Spherical Triangle hath all his Angles either acute or obtuse: viz. Acute and mixt.

10. The Sides of a Spherical Triangle may be turned into Angles, and the Angles into Sides; The Complement of the greatest Side or greatest Angle to a Semicircle being taken in each conver­sion. For Example. If it were required to turn the Angles of the Oblique Angled Spheri­cal Triangle ZFP into sides in Fig. 3. EAE is the measure of the Angle at P, and AD in the Triangle ADC equal thereunto, AC is the Complement of FZP to a Semicircle, and KM the the Measure of the Angle at F is equal to DC, and so the Sides of the Spherical Triangle ADC are equal to the Angles of the Spherical Triangle FZP, making the side AC equal to the Comple­ment of the Angle Z to a Semicircle.

11. In Right Angled Spherical Triangles the Sides intending the Right Angle we call the Legs; The Side subtending it the Hypotenuse.

12. In every Spherical Triangle besides the Area or space contained, there are six parts. viz. Three Sides and three Angles and of these six there must be always three given to find the rest, but in right Angled Spherical Triangles there are but five of the six parts parts which come into questi­on, because one of the Angles being right is allways known, and so any two of the other five being gi­ven, the three remaining parts whether Sides or Angles, may be found. But before I come to the solution of these Triangles whether right or ob­lique, I will first shew how they may be represented upon the Globe, and projected upon the plane of of the Meridian.

[Page 243] 13. A right Angled Spherical Triangle may be represented upon the Globe in this manner: Elevate one of the Poles of the Globe above the Horizon, to the quantity of one of the given Legs, so shall the distance between the AEquinox and the Zenith be equal thereunto, and at the Zenith fast­en the Quadrant of altitude, so shall there be de­lineated upon the Globe the right Angled Spheri­cal Triangle AEZB as may be seen in Fig. 1. In which the outward Circle HZR doth represent the Brass Meridian, AEAQ the Equator, and ZC the Quadrant of altitude.

14. An Oblique Angled Spherical Triangle may be represented upon the Globe in this man­ner. Number one of the given sides from one of the Poles to the Zenith; and there fasten the Quadrant of Altitude, upon which number ano­ther side, the third upon the great Meridian, from the Pole towards the Equinoctial, then turn the Globe till the Side numbred upon the Quadrant of Altitude, and the Side numbred upon the great Meridian shall intersect one another; so shall there be delineated upon the Globe the Oblique An­gled Spherical Triangle ZFP in Fig. 3. In which ZP is numbred upon the Brass Meridian from S the Pole of the World to Z the Zenith, ZF the Azimuth Circle represents the Quadrant of Alti­tude, and PF the great Meridian upon the Globe intersecting the Quadrant of Altitude at F.

15. A Right or Oblique Angled Spherical Triangle being thus delineated upon the Globe, there needs no further instructions, as to the mea­sure of the sides, all that is wanting, is the laying down the Angles comprehended by those sides, and the finding out the measure of these Angles [Page 244] being so laid down. And that this may be the better understood, I will first shew; how the se­veral Circles upon the Globe before described, may be projected upon the Plane of the Meridian, and the several useful Triangles that are described by such Projection with such Astronomical Propo­sitions as are conteined and resolvable by these Triangles.

16. The Circles in the first Figure are the Me­ridian, AEquator, Horizon, AEquinoctial Colure, and the Tropicks. The Brass Meridian without the Globe, is a perfect Circle described by taking 60 Degrees from your Line of Chords, as the Cir­cle HZRN in Fig. 1. Within which all the other are projected. The Horizon, AEquator, AEqui­noctial Colure, East and West Azimuths are all streight Lines. Thus the Diameter HAR re­presents the Horizon, AEAQ the Equator, PAS the Equinoctial Colure and ZAN the East and West Azimuths, in the drawing of these there is no difficulty, PMS is a Meridian, and ZCN an Azimuth Circle, for the drawing of which there are three points given and the Centers of the Meridians do always fall in the Equinoctial ex­tended if need be, the Centers of the Azimuth Circles do fall in the Horizon extended if need be, and for the drawing of these Circles there needs no further direction, supposing the middle point given to be in the AEquator or Horizon, but yet the Centers of these Circles may be readily found, by the Lines of Tangents or Secants, for the Tangent of the Complement of AT set from A to D, or the Secant of the Complement set from A to D will give the Center of the Meridi­an PTS. The other two Circles in the 1. Fig. [Page 245] are the Tropicks whose Centers are thus found; each Tropick is Deg. 23 ½ from the Equinoctial, which distance being set upon the Meridian from AE to ♋ and AE to ♑, if you draw a Line from A to ♋ and another perpendicular thereunto from ♋ it will cut the Axis SAP extended in the Cen­ter of that Tropick, by which extent of the com­passes the other Tropick may be drawn also. Or thus the Co-tangent of AE ♋ set from ♋ to the Axis extended will give the Center as before, and thus may all other Parallels be described.

17. In the second and third figures, the two extream points given in the Meridians are not e­qnidistant from the third, for the drawing of which Circles, if the common way of bringing three points into a Circle be not liked; you may do thus, from the given point at F and the Cen­ter A draw the Diameter TAS, and cross the same at Right Angles with the Diameter BAG, a Ruler laid from G to F will cut the primitive Cir­cle in L, make EL = BL a Ruler laid from G to E will cut the Diameter SAT in V the Center of the Circle BDG. Which Circle doth cut the Diameter HAR in the Pole of ZF, and the Di­ameter AEAQ in D in the Pole of PFX, and a Ruler laid from Z to C will cut the Primitive Circle in Y, and making Y O equal to Y a Ruler laid from Z to O will cut the Diameter HAR, extended in the Center of the Circle ZF.

18. Having drawn the Circle ZFI, in Fig. 13. The Circle PEX, or any other passing through the point F, may easily be described. Draw AEQ at right Angles to PX, a Ruler laid from G unto (e) will cut the Primitive Circle in (m) make mn = Bn, a Ruler laid from G to n [Page 246] shall cut the Diameter TFS in p make Fq = Fp so shall FQ be the Radius, and the Center of the Circle PFX as was desired.

19. The preceeding directions are sufficient for the projecting of several Circles of the Globe before described upon the Plane of the Meridian, and the parts of those Circles so described may thus be measured. In Fig. 1. HZ = CZ = AZ 90 Degrees. Whence it followeth, that the Quadrant CZ is divided into Degrees from its Pole M, by the Degrees of the Quadrant HZ, that is a Ruler laid from M to any part of the Quadrant HZ will cut as many Degrees in CZ as it doth in the Quadrant HZ, and thus the Arch CF = HK the Arch CB = HL, and the Arch BF = LK.

20. That which is next to be considered is the projecting or laying down the Angles of a Trian­gle, and the measuring of them being projected, and the Angles of a Triangle are either such as are conteined between two right Lines as the An­gle A in the Triangle PAR; or such as are con­teined by a streight and a Circular Line, as the Angle PMR. Fig. 1. Or such as are conteined by two circular Lines, as the Angles FZP or ZFP in Fig. 3. The projecting or measuring the first sort of these Angles, needs no direction.

21. To project an Angle conteined by a streight and a circular line as the Angle AEBZ in Fig. 1. Do thus, lay a Ruler from N to C, and it will cut the Primitive Circle in K make ZX = HK, a Ru­ler laid from N to X will cut the Diameter HAR in the point M the Pole of the Circle ZCN, a Ruler laid from M to B the Angular point pro­pounded, will cut the primitive Circle in I, make [Page 247] NY = HL a Ruler laid from N to Y will cut the Circle ZCN in W, a Ruler laid from B to W will cut the Primitive Circle in A, make AQ equal to the Angle propounded, and draw the Diame­ter BAQ, then is the Angle AEBZ or NBQ = NQ as was required.

22. If the Angle had been projected and the measure required, a Ruler laid from M to B would give L and making NY = HL a Ruler laid from M to Y would give W, from B to W would give A, and AQ would be the measure of the Angle propounded.

23. To project an Angle conteined by two circular lines, one of them being an Arch of the Primitive Circle, as the Angle AEZB, Fig. 1. Do thus, set off the quantity of the Angle given from H to G, a Ruler laid from Z to G will cut the Diameter HAR in the point C, so may you draw the Circle ZCN and the Angle HZC will be e­qual to the Arch HG = HC as was required.

24. If the Angle had been projected and the measure required, a Ruler laid from Z to C would cut the Primitive Circle in G and HG would be the measure of the Angle propounded.

25. To project an Angle conteined by two ob­lique Arches of a Circle, as the Angle ZFP in Fig. 3. You must first find the Pole of one of the two Circles conteining the Angle propounded, suppose ZBI, a Ruler laid from C the Pole there­of to F, the Angular point propounded, will cut the Primitive Circle in a make ab equal to the Angle propounded, a Ruler laid from F to b will cut the Diameter AEAQ in D the Pole of the Circle PEX, a Ruler laid from G to e will cut the Primitive Circle in m, make mn = Bm [Page 248] ler laid from G to n will cut the Diameter TAS in p, make Aq = Ap so shall Fp be the Radi­us and the Center of the Circle PFX and the An­gle ZFP = ab, as was propounded.

26. If the Angle had been projected and the measure required; through the point F draw the Diameter TFS and the Diameter BAG at right Angles thereunto, a Ruler laid from G to F will cut the Primitive Circle in K, and making KE = BK a Line drawn from G to E will cut the Dia­meter TAS in the Center of the Circle GDB cutting the Diameter HAR in C the Pole of the Circle ZBI, and the Diameter AEAQ in D, the Pole of the Circle PEX and a Ruler laid from F to C and D will cut the Primitive Circle in a and b the measure of the Angle required.

Or a Ruler laid from F to K and M will cut the Primitive Circle in Deg. the measure of the Angle propounded as before.

Or thus a Ruler laid from C and D to F will cut the Primitive Circle in ae and h set 90 Degrees from e and h to f and l a Ruler laid from C to f will cut ZBI in M and a Ruler laid from D to l will cut PEX in K. This done a Ruler laid from F to K and M will cut the Primitive Circle in g and d the measure of the Angle as before.

And in Fig. 2. The quantity of the Angle ZEP may thus be found. A Ruler laid from C the Pole of the Circle ZFI to F the angular point will cut the Primitive Circle in a, set off a Quadrant from a to b, a Ruler laid from C to b will cut the Circle ZFI in the point M. In like manner a Ruler laid from D the Pole of the Circle PEX, will cut the Primitive Circle in D, set off a Qua­drant from A to h, a Ruler laid from D to P will [Page 249] cut the Circle PFX in K: Lastly a Ruler laid from F to K, and M will cut the Primitive Circle in NS the measure of the Angle KFM or ZFP, as was propounded.

27. Having shewed how a right or oblique An­gled Spherical Triangle may be projected up­on the Plane of the Meridian, as well as delinea­ted upon the Globe, we will now consider the se­veral Triangles usually represented upon the Globe, with the several Astronomical and Geo­graphical Problems conteined in them, and re­solved by them.

28. The Spherical Triangles usually represent­ed upon the Globe are eight, whereof there are five Right angled Triangles, have their De­nomination from their Hypotenusas.

The first is called the Ecliptical Triangle, whose Hypotenusa is an Arch of the Ecliptick, the Legs thereof are Arches of the AEquator and Meridi­an, this is represented upon the Globe, by the Triangle ADF, in Fig. 1. In which the five Cir­cular parts, besides the Right Angle are;

1. The Hypotenuse or Arch of the Ecliptick AF.

2. The Leg or Arch of the AEquator, AD.

3. The Leg or Arch of the Meridian DF.

4. The Oblique Angle of the Equator with the Ecliptick and the Suns greatest Declination DAF.

5. The Oblique Angle of the Ecliptick and Meridian, or the Angle of the Suns position AFD.

The two next I call Meridional, because the Hypotenusas in them both, are Arches of a Meri­dian. One of these is noted with the Letters [Page 250] MPR in Fig. 1. In which the five Circular parts are;

1. The Hypotenusa or Arch of a Meridian PM.

2. The Leg or Arch of the Horizon MR, the Suns Azimuth North.

3. The Leg or Arch of the Brass Meridian, representing the height of the Pole PR.

4. The Oblique Angle of the Meridian upon the Globe; with the Brass Meridian, or Angle of the Hour from Midnight. P.

5. The Oblique Angle of the Suns Meridian with the Horizon, or the Complement of the Suns Angle of Position PMR.

The other Right Angled Meridional Triangle is noted with the Letters AEG in Fig. 1. In which the 5 Circular parts are.

1. The Hypotenusa or present Declination of the Sun, AE.

2. The Leg or Suns Amplitude at the hour of six, AG.

3. The other Leg or Suns height at the same time EG.

4. The Angle of the Meridian with the Ho­rizon, or Angle of the Poles elevation, EAG.

5. The Angle of the Meridian with the Azi­muth, or the Angle of the Suns position, AEG.

The fourth Right Angled Spherical Triangle, I call an Azimuth Triangle, because the Hypote­nusa doth cut the Horizon in the East and West Azimuths, as is represented by the Triangle ADV. in Fig. 1. In which the 5 Circular parts are,

[Page 251] 1. The Hypotenusa, or Arch of the Sun or Stars Altitude AV.

2. The Leg or Declination of the Sun or Star, DV.

3. The other Leg, or Right Ascension of the Sun or Star, AD.

4. The Oblique Angle or Angle of the Poles elevation, DAV.

5. The other Oblique Angle or Angle of the Sun or Stars Position, DVA.

The fifth and last Right Angled Spherical Tri­angle, that I shall mention, I call an Horizontal Triangle, because the Hypotenusa thereof is an Arch of the Horizon, and is represented by the Triangle AMT in Fig. 1. In which the 5 Circular parts are;

1. The Hypotenusa and Arch of the Horizon, or Amplitude of the Sun at his rising or setting, AM.

2. The Leg conteining the Sun or Stars Decli­nation TM.

3. The other Leg or Ascensional difference AT, that is, the difference between DT the Right Ascension and DA the Oblique Angle.

4. The Oblique Angle of the Horizon and E­quator, or height of the Equator TAM.

5. The other Oblique Angle, or Angle of the Horizon and Meridian AMT.

The Oblique Angled Spherical Triangles u­sually represented upon the Globe are three. The first I call the Complemental Triangle, be­cause the sides thereof are all Complements, and this is represented by the Triangle FZP in Fig. 1. Whose Circular parts are;

1. The Complement of the Poles elevation ZP.

[Page 252] 2. The Complement of the Suns Declination, FP.

3. The Complement of the Suns Altitude or Almicantar FZ.

4. The Suns Azimuth or Distance from the North FZP.

5. The hour of the day or distance of the Sun from Noon ZPF.

6. The Angle of the Suns Position ZFP.

The second Oblique Angled Spherical Trian­gle, I call a Geographical or Nautical Triangle, because it serveth to resolve those Problems, which concern Geographie and Navigation, and this is also represented by the Triangle FZP in Fig. 1. Whose parts are.

1. The Complement of Latitude as before ZP.

2. The distance between the two places at Z and F or side FZ.

3. The Complement of the Latitude of the place at F or side FP.

4. The difference of Longitude between the two places at Z and F or the Angle FBZ.

5. The point of the compass leading from Z to F or Angle FZP.

6. The point of the Compass leading from F to Z, or Angle ZFP.

The third Oblique Angled Spherical Trian­gle is called a Polar Triangle, because one side thereof is the distance between the Poles of the World, and the Poles of the Zodiack. This Triangle is represented upon the Coelestial Globe, by the Triangle FSP in Fig. 4. In which the Cir­cular parts are;

1. The distance between the Pole of the [Page 253] World, and the Pole of the Ecliptick, or the Arch SP.

2. The Complement of the Stars Declination, FP.

3. The Complement of the Stars North La­titude, from the Ecliptick or the Arch FS.

4. The Angle of the Stars Right Ascension FPS.

5. The Complement of the Stars Longitude FSP.

6. The Angle of the Stars Position SFP.

29. And thus at length I have performed, what was proposed in the 15 of this Chapter, that is, I have shewed how the several Circles of the Globe, may be projected upon the Plane of the Meridian, the several useful Triangles that are described by such projection, with such Astrono­mical Propositions as are contained and resolvea­ble by those Triangles; And although the most accurate way of resolution is by the Doctrine of Trigonometry and the Canon of Lines and Tangents, yet it is not impertinent to do the same upon the Globe it self, which as to the sides is easie, but to measure or lay down the Angles is sometimes a little labourious.

In the Right Angled Spherical Triangle AEBZ in Fig. 1. The measure of the Angle AEZB is reckoned in the Horizon from H to C but to lay down or measure the Angle AEBZ the readiest way is to describe the Triangle again, making AEZ = AEB and AEB = AEZ, so will the Angle AEBZ stand where the Angle AEZB is, and may be measured in the Horizon as the other was.

[Page 254] And so in the Oblique Angled Spherical Trian­gle FZP in Fig. 1. The Angles at Z and P are easily measured or laid down upon the Globe, but to perform the same with the Angle ZFP, you may represent it at the Pole or Zenith and find the measure in the Equator or Horizon.

30. And now having, as I hope, sufficiently pre­pared the young Student for the first part of A­stronomy, the Doctrine of the Primum Mobile, by shewing how the Heavens and the Earth are repre­sented upon the Globe, or may be projected in Plane, I will now proceed to such Astronomi­cal Propositions as are generally useful, and may be sufficient for an Introduction to this noble Sci­ence: to go through the several Triangles before propounded, will be very tedious, I will there­fore shew the several Problems in one Right An­gled and one Oblique Angled Spherical Triangle and the Canons by which they are to be resolved, and leave the rest for the Practice of my Reader. To this purpose I will next acquaint you with my Lord Nepiers Catholick Proposition for the solu­tion of all Right and Oblique Angled Spherical Triangles.

CHAP. IV.

Of the solution of Spherical Triangles.

IN Spherical Triangles there are 28 Varieties or Cases, 16 in Rectangular, and 12 in Oblique, whereof all the Rectangular and ten of the Obli­que may be resolved by the two Axioms follow­ing.

1. Axiom. In all Right Angled Spherical Tri­angles having the same Acute Angle at the Base, the Sines of the Hypotenusas are proportional to the Sines of their Perpendicular.

2. Axiom. In all right Angled Spherical Tri­angles, the Sines of the Bases and the Tangents of the Perpendicular are proportional.

That all the Cases of a Right Angled Spherical Triangle may be resolved by these two Axioms, the several parts of the Spherical Triangle propo­sed, that so the Angles may be turned into sides, the Hypotenusa, into Bases and Perpendiculars and the contrary. By which means the proportions as to the parts of the Triangle given, are sometimes changed into Co-sines instead of Sines, and into Co­tangents instead of Tangents. Which the Lord Nepier observing; those parts of the Right An­gled Spherical Triangle, which in conversion do change their proportion, he noteth by their Com­plements. viz. The Hypotenuse and the two A­cute Angles: But the sides or Legs are not so no­ted, [Page 256] as in the Right Angled Spherical Triangle MPR in Fig. 1. And these five he calleth the Cir­cular parts of the Triangle, amongst which the Right Angle is not reckoned.

2. Now if you reckon five Circulat parts in a Triangle, one of them must needs be in the mid­dle, and of the other four, two are adjacent to that middle part, the other two are disjunct, and which soever of the five you call the middle part, for every one of them may by supposition be made so; those two Circular parts which are on each side of the middle are called extreams adjunct, and the other two remaining parts, are called ex­tream disjunct, as in the Triangle MPR if you make the Leg PR the middle part, then the o­ther Leg MR and the Angle Comp. P. Are the extreams conjunct, the Hyp. Comp. MP and Comp. M, are the extreams disjunct, and so of the rest, as in the following Table.

[Page 257]

Mid. PartExctr. conj.Extr. disj [...]
 Leg. MRComp. M
Leg PR  
 Comp. PComp. MP
 Leg. PRComp. MP
Leg MR  
 Comp. MComp. P
 Leg. MRComp. P
Comp. M  
 Comp. MPLeg. PR
 Comp. MLeg. PR
Comp. MP  
 Comp. P.Leg. MR
 Comp. MPLeg. MR
Comp. P  
 Leg. PRComp. M

3. These things premised, the Ld. Nepier as a consectory from the two preceeding Axioms hath composed this Catholick and Universal Pro­position.

The Rectangle made of the Sine of the middle part and Radius is equal to the Rectangle made of the Tan­gents of the Extremes conjunct or the cosines of the Extremes disjunct.

Therefore if the middle part be sought, the Radius must be in the first place; if either of the extremes, the other extreme must be in the first place.

Only note that if the middle part, or either of the extremes propounded be noted with its [Page 258] Comp. in the circular parts of the Triangle, in­stead of the Sine or Tangent you must use the Cosine or Cotangent of such circular part or parts.

That these directions may be the better con­ceived, we have in the Table following set down the circular parts of a Triangle under their respective Titles, whether they be taken for the middle part, or for the extremes, conjunct or disjunct, and unto these parts, we have pre­fixed the Sine or Cosine, the Tangent or Co­tangent, as it ought to be by the former Rule.

Mid. Par.Extr. Conj.Ext. Disj.
 Tang. MRSine M
Sine PR  
 Tang. P.Sine MP
 Tang. PRSine MP
Sine MR  
 Cotang. M.Sine P
 Tang. MRSine P
Cosine M  
 Cot. MPCos. PR
 Cotang. M.Cos. PR
Cos. MP  
 Cotang. PCos. MR
 Cot. MPCos. MR
Cosine P  
 Tang. PRSine M
Now then according to this Table and the former Rules.
  • [Page 259]1. Sine PR x Rad.= t MR x ct P.
  • 2. Sine PR x Rad.= s M x s MP.
  • 3. Sine MR x Rad.= t PR x ct M.
  • 4. Sine MR x Rad.= s MP x s P.
  • 5. Cos. M x Rad.= t MR x ct MP.
  • 6. Cos. M x Rad.= s P x cs PR.
  • 7 Cos. MP x Rad.= ct M x ct P.
  • 8. Cos. MP x Rad.= cos. PR x cs MR.
  • 9. Cos. P x Rad.= ct MP x t PR.
  • 10. Cos. P x Rad.= cos. MR x s M.

By these 10 Rectangles may the 16 Cases of a Right angled Spherical Triangle be resolved, and some of them twice over; for although there are but 16 varieties in all Right angled Spherical Triangles, yet 30 Astronomical Problems may be resolved by one Triangle, as by the following Examples shall more clearly appear.

Of Right angled Spherical Triangles.

CASE 1.

The Legs given, to find the Angles.

IN the Right angled Spherical Triangle MPR. The given Legs are MR and RP. The Angles at M and P are required.

By the first of the 10 equal Rectangles s PR x Rad.=t MR x ct P. in which P is fought, therefore putting MR in the first place. The proportion is. t MR. x Rad.∷s PR. ct P.

And by the third equal Rectangle. t PR. Rad.∷s MR. ct M.

CASE 2.

The Legs given, to find the Hypotenuse.

In the Right angled Spherical Triangle MPR. The given Legs are MR and PR. The Hypo­tenuse MP is required.

By the eighth of the 10 Rectangles cos. MP x Rad.=cos. PR x cos. MR in which MP the middle part is sought, therefore Radius must be put in the first place, and then the proportion is.

Rad: cos. PR∷ cos. M. R. cos. MP.

CASE 3.

A Leg with an Angle opposite thereunto being given, to find the other Leg.

In the Right angled Spherical Triangle MPR, let there be given. The Leg MR. The Angle P. The Leg PR inquired.

By the first of the 10 Rectangles. Rad. tMR ∷cot. P. Sine PR. or The Leg PR and the Angle M given, to [...]ind MR.

By the 3 of the 10 Rectangles. Rad. tPR∷ct M. Sine MR.

CASE 4.

A Leg with an Angle conterminate therewith being given, to find the other Leg.

In the Right angled Spherical Triangle, MPR, The given Leg is MR, with the Angle M. The Leg PR is required.

By the 3 Rectangle. cot. M. Rad∷Sine MR. tPR.

The given Leg RP, and Angle P. The Leg MR is required.

By the 1. Rectangle. ctP. Rad∷sine RP. tang. MR.

CASE 5.

A Leg and an Angle conterminate therewith being given, to find the Hypotenuse.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Leg
    • MR and the Angle M
    • PR and the Angle P
  • to find MP.

By the 5. Rectangle, t MR. Rad∷cos. M. ct MP.

By the 9. Rectangle. t PR. Rad.∷cos. P. ct MP.

CASE 6.

The Hypotenuse and a Leg given, to find the con­tained Angle.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Hypote­nuse MP,
  • and Leg
  • MR. PR.
  • To find
  • M.

By the 5. Rectangle, Rad. ct MP∷t MR. cos. M.

By the 9. Rectangle, Rad. ct MR∷t PR. cos. P.

CASE 7.

The Hypotenuse and one Angle given, to find the other Angle.

In the Right angled Spherical Triangle MPR, let there be given,

  • [Page 263]The Hypote­nuse MP
  • & Angle
  • M P.
  • To find the Angle
  • P. M.

By the 7. Rectangle, cot. M. Rad∷cos. MP. cot. P.

By the 7. Rectangle cot. P. Rad∷cos. MP. cot. M.

CASE 8.

The Oblique A [...]gles given, to find the Hypotenuse.

In the Right angled Spherical Triangle MPR, let there be given The Angles at P and M, To find the Hypotenuse PM.

By the 7. Rectangle. Rad. ct P∷cot. M. cos. MP.

CASE 9.

The Hypotenuse and an Angle given, to find the Leg conterminate with the given Angle.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Hypote­nuse PM
  • Angle
  • P. M.
  • To find
  • PR. MR.

By the 9. Rectangle, ct PM. Rad∷cos. P. t PR.

By the 5. Rectangle, ct PM. Rad∷cos. M. tMR.

CASE 10.

The Hypotenuse and an Angle given, to find the Leg opposite to the given Angle.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Hypote­nuse PM
  • and the Angle
  • M. P.
  • To find
  • PR. MR.

By the 2. Rectangle, Rad. s MP∷s M. Sine PR.

By the 4. Rectangle, Rad. s MP∷s P. Sine MR▪

CASE 11.

A Leg and an Angle opposite thereunto being given, to find the Hypotenuse.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Leg
  • PR. MR.
  • and the Angle
  • M P
  • to find the Hy­potenuse PM.

By the 2. Rectangle, s M. Rad∷s PR. s MP.

By the 4. Rectangle, s P. Rad∷s MR. s PM.

CASE 12.

The Hypotenuse and a Leg given, to find the Angle opposite to the given Leg.

In the Right angled Spherical Triangle PMR, [Page 265] the Hypotenuse MP and the Leg MR are given, the Angle at P is required.

By the fourth Rectangle Sine MP to, Rad∷s MR. s P.

The Hypotenuse MP and Leg PR given, the Angle M is required.

By the second Rectangle. sMP. Rad∷s PR. s M.

CASE 13.

The Angle and Leg conterminate with it being given, to find the other Angle.

In the Right angled Spherical Triangle PMR, let there be given,

  • The An­gle
  • M P
  • and the Leg
  • MR PR
  • to find the Angle
  • P. M.

By the tenth Rectangle, Rad. cs MR∷s M. cs P.

By the sixth Rectangle, Rad. s P∷cs PR. cs M.

CASE 14.

An Angle and a Leg opposite thereunto being given, to find the other Angle.

In the Right angled Spherical Triangle MPR, let there be given,

  • The An­gle
  • P M
  • and the Leg
  • MR PR
  • to find the Angle
  • M. P.

By the 10. Rectangle, cs MR. Rad∷cs P. csM.

By the 6. Rectangle, cs PR. Rad∷cs M. sP.

CASE 15.

The Oblique Angles given, to find a Leg.

In the Right angled Spherical Triangle MPR, let there be given, the Angles at M and P, to find the Legs MR and PR.

By the 10. Rectangle, sM. Rad∷cs P. cs MR.

By the 6. Rectangle, s P. Rad∷cs M. cs PR.

CASE 16.

The Hypotenuse and one Leg given, to find the other Leg.

In the Right angled Spherical Triangle MPR, let there be given,

  • The Hypotenuse MP and the Leg
  • PR MR
  • to find the Leg
  • MR. PR.
  • By the 8. Re­ctangle,
  • csPR. Rad∷csMP. csMR.
  • csMR. Rad∷csMP. csPR.

Thus I have given you the Proportions by which the 16 Cases of a Right angled Spherical Triangle may be resolved, In which there are contained 30 Astronomical Problems. Two in every Case except the Second and the Eighth. In both which Cases there are but two Problems. And thus I have done with Right angled Spheri­cal Triangles.

4. In Oblique angled Spherical Triangles [Page]

[figure]

[Page] [Page]

[figure]

[Page] [Page 267] there are twelve Cases, ten whereof may be re­solved by the Catholick Proposition; If the Spherical Triangle propounded be first convert­ed into two right, by letting fall of a Perpendi­cular, sometimes within, sometimes without the Triangle.

5. If the Angles at the Base be both acute or both obtuse, the Perpendicular shall fall with­in the Triangle; but if one of the Angles of the Base be acute and the other obtuse, the Perpendicular shall fall without the Triangle.

6. However the Perpendicular falleth, it must be always opposite to a known Angle, for your better direction, take this General Rule. From the end of a Side given, being adjacent to an Angle given, let fall the Perpendicular.

As in the Triangle FPS in Fig. 4. If there were given the Side F S and the Angle at S, the Perpendicular by this Rule must fall from P upon the Side S P extended, if need require.

But if there were given the Side P S and the Angle at S, the Perpendicular must fall from F upon the Side F S.

7. To divide an Oblique angled Spherical Triangle into two Right, by letting fall a Per­pendicular upon the Globe it self, is not necessa­ry, because all the Cases may be resolved with­out it, but in projection it is convenient to in­form the fancy: and seeing the reason by which it is done in projection doth depend upon the na­ture of the Globe, I will here shew it both ways, first upon the Globe, and then by pro­jection.

[Page 268] An Oblique angled Spherical Triangle may be divided into two Right, by letting fall a Per­pendicular upon the Globe it self, in this manner. In the Oblique angled Spherical Tri­angle FPS in Fig. 4. let it be required to let fall a Perpendicular from P upon the Side FS. Sup­pose the Point P to stand in the Zenith, where the Arch FS shall cut the Zodiack, which in this Figure is at K, make a mark, and from this Point of Intersection of the Circle upon which the Perpendicular is to fall with the Zodiack, reckon 90 Degrees, which suppose to be at P; a thin Plate of Brass with a Nut at one end thereof, whereby to fasten it to the Meridian, as you do the Quadrant of Altitude, being graduated as that is, but of a larger extent (for that a Qua­drant in this case will not suffice) being fastned at P and turned about till it cut the Point L in the Zodiack, will describe upon the Globe the Arch of a great Circle PEL, intersecting the Side F S at Right Angles in the Point E, because the Point L in the Zodiack is the Pole of the Circle SFK, now all great Circles which passing through the Point L, shall intersect the Circle SKG, shall intersect it at Right Angles; by the 13. of the 2. Chapter.

9. And hence to divide an Oblique angled Spherical Triangle into two Right by projecti­on is easie, as in the Triangle FPS, the Pole of the Circle SFK is L, therefore the Circle BLP shall cut the Arch FS at Right Angles in the Point E. And because the Point M is the Pole of the Circle BFP, therefore the Circle GMS shall cut the Circle BFP at Right An­gles in the Point D, the Side F P being extend­ed. [Page 269] Come we now to the several Cases which af­ter this preparation may be resolved, by the Ca­tholick Proposition.

CASE 1.

Two Sides with an Angle opposite to one of them be­ing given, to find the Angle opposite to the other.

In the Oblique angled Spherical Triangle F P S, in Fig. 4. the Sides and Angles given and required will admit of six Varieties; all which may be resolved by the Catholick Proposition, at two operations, but those two may be re­duced to one, as by the following Analogies to every Variety will plainly appear.

GivenRequired 
FP Rad. s PS∷s PSF. s PE
1. PSPFSs. PF. Rad∷s PE. s PFS
PSF s PF. s PS∷s PSF. s PFS
FP Rad. s FP∷s F. s PE
2. PSPSFs PS. Rad∷s PE. s PSF
PFS s. PS. s FP∷s PFS. s PSF
PS Rad. s SF∷s F. sDS
3. FSFPSs PS. Rad∷s DS. s SPD
PFS s. PS. s SF∷s PFS. s PSF
PS Rad. s PS∷s SPD. s DS
4. FSPFSs FS. Rad∷s DS. s SF
FPS s FS. s PS∷s SPF. s SF
FS Rad. s FS∷s S. s FC
5. FPFPSs. FP. Rad∷s FC. s FPC
FSP s. FP. s FS∷s PSF. s FPS
[Page 270] FS Rad. s FP∷s FPC. s FC
6. FPFSPs FS. Rad∷s FC. s S
FPS s. FS. s FP∷FPS. s PSF.
CASE 2.

Two Sides with an Angle appo [...]ite to one of them being given, to find the contained Angle.

In this Case there are six Varieties, all which may be resolved by the Catholick Proposition, according to the Table following.

GivenRequired 
FP 1: cot PSF. Rad∷cs PS. ct EPS
1. PSFPS2. ct PS. Rad∷cs EPS. t EP
PSF 3. Rad. t EP∷ct FP. cs FPE
EPS+EPF=FPS ct PS. cs EPS∷ct FP. ct FPE
FP 1. cot PFS. Rad∷cs PF .ct EPF
2. PSFPS2. ct PF. Rad∷cs EPF. t EP
PFS 3. Rad. t EP∷cot PS. cs EPS
EPS+EPF=FPS cot PF. cs EPF∷ct PS ct EPS
PS 1. cot PFS. Rad∷cs FS. ct FSD
3. FSPSF2. ct FS. cs FSD∷ Rad. t DS
PFS 3. Rad. t DS∷ ct PS. cs PSD
FSD-PSD=PSF ct FS. cs FSD∷ct PS. cs PSD
PS 1. cot FPS. Rad∷cs PS. ct PSD
4. FSPSF2. ct PS. cs PSD∷Rad. t DS
FPS 3. Rad. t DS∷ct FS. cs FSD
FSD-PSD=PSF ct PS. cs PSD∷ct FS. cs FSD
FS 1. cot FSP. Rad∷cs FS. ct SFC
5. FPPFS2. ct FS. cs SFC∷Rad. t FC
FSP 3. Rad. t FC∷ct FP. cs PFC
SFC-PFC=PFS ct FS. cs SFC∷ct FP. cs PFC
[Page 271] FS 1. cot FPS. Rad∷cs PF. ct PFC
6. FFPFS2. cot FP. cs PFC∷Rad. t FC
FPS 3. Rad. t FC∷ct FS. cs SFC
SFC-PFC=PFS ct FP. cs PFC∷ct FS. cs SFC.
CASE 3.

Two Sides and an Angle opposite to one of them being given, to find the third side.

The Varieties in this Case, with their resolu­tion by the Catholick Proposition, are as follow­eth.

GivenRequired 
FP 1. ct PS∷cs PSF. t ES
1. PSFS2. cs ES. cs PS∷Rad. cs EP
PSF 3. Rad. cs EP∷cs FP. cs FE
ES+FE=FS cs ES. cs PS∷cs FP. cs FE
FP 1. cot FP. Rad∷cos PFS. t FE
2. PSFS2. cos FE. cos FP∷Rad. cos EP
PFS 3. Rad. cos EP∷cos PS. cos SE
SE+FE=FS cos FE. cos FP∷cos PS. cos SE
PS 1. cot FS. Rad∷cos PFS. t FD
3. FSFP2. cos FD. cos FS∷Rad. cs SD
PFS 3. Rad. cos SD∷cos PS. cs PD
FD-PD=FP cos FD. cos FS∷cs PS. cs PD
PS 1. cot PS. Rad∷cos FPS. t PD
4. FSFP2. cos PD. cos PS∷Rad. cos SD
FPS 3. Rad. cos SD∷cos FS. cs FD
FD-PD=FP cos PD. cos PS∷cos FS. cs FD
[Page 272] FS 1. cot FS. Rad∷cos FSP. t SC
5. FPPS2. cos SC. cos FS∷Rad. cos FC
FSP 3. Rad. cos FC∷cos FP. cos PC
SP-PC=PS cos SC. cos FS. cos FP. cos PC
FS 1. cot FP. Rod∷cos FPS. t PC
6. FPPS2. cos PC. cos FP∷Rad. cos FC
FPS 3. Rad. cos FC∷cos FS. cos SC
SC-PC=PS cos PC. cos FP∷cos FS. cos SC
CASE 4.

Two Angles with a Side opposite to one of them being given, to find the Side opposite unto the other.

The Varieties in this Case, with their Resolu­tion by the Catholick Proposition, are as follow­eth.

GivenRequired 
PFS Rad. s. PS∷s DPS. s SD
1. FPSFSS. FP. Rad∷s SD. s FS
PS  
  s. PFS. s PS∷s FPS. s FS
PFS Rad. s FS∷s PFS. s. SD
2. FPSPSs. FPS. Rad∷s SD. s PS
FS  
  s. FPS. s FS∷s PFS. s PS
FPS Rad. s FP∷s FPS. s FC
3. PSFFSs. PSF. Rad∷s FC. s FS
FP  
  s. PSF. s FP∷s FPS. s FS
[Page 273] FPS Rad. s FS∷s PSF. s FC
4. PSFFPs. FPS. Rad∷s FC. s FP
FS s. FPS s FS∷s PSF. s FP
PSF Rad. s PS∷s PSF. s PE
5. SFPFPs. SFP. Rad∷s PE. s FP
PS s. SFP. s PS∷s PSF. s FP
PSF Rad. s FP∷s PFS. s PE
6. SFPPSs. PSF. Rad∷s PE. s PS
FP s. PSF. s FP∷s PFS. s PS
CASE 5.

Two Angles and a side opposite to one of them being given, to find the Side between them.

The Varieties and Proportions, are as follow­eth.

GivenRequired 
PFS 1. ct PS. Rad∷cs DPS. PD
1. FPSFP2. ct DPS. s PD∷Rad. t DS
PS 3. Rad. t DS∷ct PFS. s FD
FD-PD=FP ct DPS. s PD∷ct PFS. s FD
PFS 1. ct DFS. Rad∷cs PFS. t FD
2. FPSFP2. cot PFS. s FD∷Rad. t DS
FS 3. Rad. t DS∷ct FPS. s PD
FD-PD=FP  
FPS 1. cot FP. Rad∷cs FPC. t PC
3. PSFPS2. cot FPC. s PC∷Rad. t FC
FP 3. Rad. t FC∷ct PSF. s SC
SC-PC=PS cot FPC. s PC∷ct PSF. CS
[Page 274] FPS 1. cot FS. Rad∷cs PSF. t SC
4. PSFPS2. cot PSF. s SC∷Rad. t FC
FS 3. Rad. t FC∷cot FPS. s PC
SC-PC=PS cot PSF. s SC∷cot FPS. s PC
PSF 1. cot PS. Rad∷cs PSF. t SE
5. SFPFS2. cot PSF. s SE∷Rad. t PE
PS 3. Rad. t PE∷cot SFP. s FE
FE+SE=FS cot PSF. s SE∷cot SFP. s FE
PSF 1. cot FP. Rad∷cs SFP. t FE
6. SFPFS2. cot SFP. s FE∷Rad. t PE
FP 3. Rad. t PE∷cos PSF. s SE
FE+SE=FS cot. SFP. s FE∷cs PSF. s SE
CASE 6.

Two Angles and a Side opposite to one of them being given, to find the third Angle.

The Varieties and Proportions are as follow­eth.

GivenRequired 
PFS 1. ct DPS. Rad∷cs PS. ct PSD
1. FPSPSF2. s PSD. cs DPS∷Rad. cs DS
PS 3. cs DS. Rad∷cs DFS. s FSD
FSD-PSD=PSF cs DPS. s PSD∷cs DFS. s FSD
PFS 1. ct PFS. Rad∷cs FS. ct FSD
2. FPSPSF2. s FSD. cs PFS∷Rad. cs DS
FS 3. cs PDS. Rad∷cs DPS. cs PSD
FSD-PSD=PSF cs PFS. s FSD∷cs DPS. cs PSD
[Page 275] FPS 1. ct FPC. Rad∷cs FP. ct PFC
3. PSFPFS2. s PFC. cs FPG∷Rad. cs FC
FP 3. cs FC. Rad∷cs PSF. s FC
SFC-PFC=PFS cs FPC. s PFC∷cs PSF. s SFC
FPS 1. cot PSF. Rad∷cos FS. ct SFC
4. PSFPFS2. s SFC. cs PSF∷Rad. cs FC
FS 3. cs FC. Rad∷cs CPF. s PFC
SFC-PFC=PFS cs PSF. s SFC∷cs CPF. s PFC
PSF 1. cot PSF. Rad∷cs PS. ct SPE
5. SFPFPS2. s SPE. cs PSF∷Rad. cs PE
PS 3. cs PE. Rad∷cs SFP. s FPE
FPE+SPE=FPS cs PSF. s SPE∷cs SFP. s FPE
PSF 1. cot SFP. Rad∷cs FP. ct FPE
6. SFPFPS2. s FPE. cs SFP∷Rad. cs PE
FP 3. cos PE Rad∷cs PSF. s SPE
FPE+SPE=FPS cs SFP. s FPE∷cs PSF. s SPE
CASE 7.

Two Sides and their contained Angle being given, to find either of the other Angles.

The Varieties and Proportions are as follow­eth.

GivenRequired 
FS 1. ct FP. Rad∷cs PFS. t FE
1. FPFSP2. ct PFS. s FE∷Rad. t PE
PFS 3. t PE. Rad.∷s ES. ct PSF
FS-FE=ES s EF. ct PFS∷s ES. ct PSF
[Page 276] FS 1. cot FS. Rad::cs PFS. t DF
2. FPFPS2. cot PFS. s DF::Rad. t DS
PFS 3. t DS. Rad::s PD. ct SPD
FD - FP=PD s DF. ct PFS::s PD. ct SPD
FP 1. cot FP. Rad::cos FPC. t PC
3. PSPSF2. cot FPC. s PC::Rad. t FC
FPS 3. t FC. Rad::s CS. cot FSP
PS+PC=CSs PC. ct FPC::s CS. ct FSP
FP 1. cot PS. Rad::cos SPD. t PD
4. PSSFP2. cot SPD. s PD::Rad. t DS
FPS 3. t DS Rad::s FD. cot SFP
FP+PD=FD s PD. ct SPD::s FD. cot SFP
PS 1. cot PS. Rad:: cs PSF. t SE
5. FSSFP2. cot PSF. s SE::Rad. t PE
PSF 3. t PE. Rad::s FE. cot SFP
FS-SE=FE s SE. ct PSF::s FE. ct SFP
PS 1. cot FS. Rad::cs PSF. t SC
6. FSFPS2. cot PSF. s SC::Rad. t FC
PSF 3. t FC. Rad::s PC. cot FPC
SC-PS=PC s SC. cot PSF::s PC. ct FPC
CASE 8.

Two Sides and their contained Angle being given, to find the third Side.

The Varieties and Proportions are as follow­eth.

GivenRequired 
FS 1. ct FP. Rad::cs PFS. t FE
1. FPPS2. cs FE. cs FP::Rad. cos PE
PFS 3. Rad. cs PE :: cs ES. cs PS
FS-FE=ES cs FE. cs FP::cs ES. cs PS
FP 1. ct PS. Rad::cs SPD. t PD
2. SPFS2. cs PD. cs PS::Rad. cos DS
FPS 3. Rad. cos DS::cs FD. cs FS
FP+PD=FD cs PD. cs PS::cs FD. cs FS
PS 1. ct PS. Rad::cs PSF. t. ES
3. FSFP2. cs ES. cs PS::Rad. cos PE
PSF 3. Rad. cos PE::cos FE. cos FP
FS-ES=FE cs ES. cs PS::cos FE. cs FP
CASE 9.

Two Angles and their contained Side being given, to find one of the other Sides.

GivenRequired 
PFS 1. ct PFS. Rad::cs FP ct FPE
1. FPSPS2. ct FP. cs FPE::Rad. t PE
FP 3. t PE. Rad::cs EPS. ct PS
FPS-FPE=EPS cs FPE. ct FP::cs EPS. ct PS
PFS 1. cot FPC. Rad::cs FP. t PFC
2. FPSFS2. cot FP. cs PFC::Rad. t FC
FP 3. t FC. Rad::cs SFC. ct SF
SFP+PFC=SFC ct FP. cs PFC::cs SFC. ct SF
[Page 278] FPS 1. ct SPD. Rad::cs PS. ct PSD
3. PSFSF2. ct PS. cos PSD::Rad. t DS
PS 3. t DS. Rad::cs FSD. ct SF
PSF+PSD=FSD cs PSD. ct PS::cs FSD. ct SF
FPS 1. ct PSF. Rad::cs PS. ct SPE
4. PSFFP2. ct PS. cs SPE::Rad. t PE
PS 3. t PE. Rad::cs PPE. ct FP
FPS-EPS=FPE cs SPE. ct PS::cs FPE. ct FP
PSF 1. ct PSF. Rad::cs SF. ct SFC
5. SFPFP2. ct SF. cs SFC::Rad. t FC
SF 3. t FC. Rad::cs CFP. ct FP
SFC-SFP=CFP cs SFC. ct SF::cs CFP. ct FP
PSF 1. ct SFP. Rad::cs FS. ct FSD
6. SFPPS2. ct FS. cs FSD::Rad. t SD
SF 3. t SD. Rad::cos PSD. ct PS
FSD-FSP=PSD cs FSD. ct FS::cs PSD. ct PS
CASE 10.

Two Angles and the Side between them being given, to find the third Angle.

The Varieties and Proportions are as follow­eth.

GivenRequired 
SFP 1. ct SFP. Rad::cs FP. ct FPE
1. FPSPSF2. s FPE. cs F::Rad. cs PE
FP 3. Rad. cs PE::s EPS. cs PST
FPS-FPE=EPS s FPE. cs PFS::s SPE. cs PSF
[Page 279] FPS 1. ct SPD. Rad::cs PS. ct PSD
2. PSFSFP2. s PSD. cs SPD::Rad. cs DS
PS 3. Rad. cs DS::s FSD. cs SFP
PSF+PSD=FSD s PSD. cs SPD::s FSD. cs SFP
PSF 1. ct PSF. Rad::cs SF. ct SFC
3. SFPFPS2. s SFC. cs PSF::Rad. cs FC
SF 3. Rad. cs FC::s PFC. cs FPS
SFC-SFP=PFC s SFC. cs PSF::s PFC. cs FPS
CASE 11.

The three Sides being given, to find an Angle.

This Case may be resolved by the Catholick Proposition also, according to the direction of the Lord Nepier, as I have shewed at large in the Second Book of my Trigonometria Britannica, Chap. 2. but may as I conceive be more conveniently solved, by this Proposition following.

As the Rectangle of the Square of the Sides containing the Angle inquired;

Is to the Square of Radius: So is the Rectan­gle of the Square of the difference of each con­taining Side, and the half sum of the three Sides given.

To the Square of the Sine of half the Angle inquired.

In this Case there are three Varieties, as in the Triangle FZP. Fig. 3.

[Page 280]

GivenRequired 
ZP s ZP x s PF. Rad. q.
1. PFZPFs ½ Z-ZP x s ½ Z-PF. Q
FZ s ½ ZPF
ZP s PF x s PZ. Rad. q.
2. PFPFZs ½ Z-PF x s ½ Z-FZ. Q
FZ s ½ PFZ
ZP s ZP x s FZ Rad. q.
3. PFFZPs. ½ Z-ZP x ½ Z-ZF. Q
FZ s ½ FZP
CASE 12.

The three Angles given, to find a Side.

This is the Converse of the last, and to be re­solved after the same manner, if so be we convert the Angles into Sides, by the tenth of the third Chapter: for so the Sides of the Triangle ACD will be equal to the Angles of the Triangle FZP n Fig. 3.

That is
  • AD=AEE the measure of the An­gle ZPF.
  • DC=KM the measure of the An­gle ZFP.
  • AC=HB the Complement of FZP to a Semicircle.
The Angle
  • [Page 281]DAC = QR = ZP.
  • ACD = rM = Hf = Zoe = ZF.
  • ADM = sK = AEl = Ph = PF.

And thus the Sides of the Triangle ZPF are equal to the Angles of the Triangle ACD. The Complement of the greatest Side PF to a Semicircle being taken for the greatest Angle ADC.

And in this Case therefore, as in the preceding, there are three Varieties which make up sixty Pro­blems in every Oblique angled Spherical Trian­gle; which actually to resolve in so many Tri­angles, as have been mentioned, would be both tedious, and to little purpose; I will therefore select some few, that are of most general use in the Doctrine of the Sphere, and leave the rest to thine own practice.

CHAP. V.

Of such Spherical Problems as are of most General Use in the Doctrine of the Pri­mum Mobile or Diurnal Motion of the Sun and Stars.

PROBLEM 1.

The greatest Declination of the Sun being given, to find the Declination of any Point of the Ecliptick.

THe Declination of the Sun or other Star, is his or their distance from the Equator, and as they decline from thence either Northward or Southward; so is their Declination reckoned North or South.

2. The Sun's greatest Declination, which in this and many other Problems is supposed to be given, with the Distance of the Tropicks, Ele­vation of the Equator, and Latitude of the Place, may thus be found.

Take with a Quadrant, the Sun's greatest and least Meridian Altitudes, on the longest and shortest days of the year, which suppose at London to be as followeth. [Page 283]

[figure]
  • [Page 283]The Sun's
    greatestMeridianH♋. 61.9916
    leastAltitudeH♑. 14.9416
  • Their difference is the distance of the Tropicks ♋. ♑. 47. 050
  • Half that Difference, is the Sun's greatest Declination AE ♋. 23. 525
  • Which deduct from the Sun's greatest Altitude, the remainer is the height of the Equator HAE. 38. 467
  • The Complement is the height of the Pole AEZ or PR. 51. 533

Now then in the Right angled Spherical Tri­angle ADF in Fig. 1. there being given.

1. The Angle of the Sun's greatest Declina­tion DAF. 23. 525.

2. The Sun's supposed distance from ♈ to ♎ AF. 60 deg.

The Sun's present Declination DF may be found, by the 10 Case of Right angled Spherical Triangles.

As the Radius

Is to the Sine of DAF. 23. 525.
9.60113517
So is the Sine of AF 60.
9.93753063
To the Sine of DF. 20. 22.
9.53866580

PROBLEM 2.

The Sun's groatest Declination, with his Distance from the next AEquinoctial Point being given, to find his Right Ascension.

In the Right angled Spherical Triangle ADF in Fig. 1. Having the Angle of the Sun's great­est Declination DAF. 23. 525. And his sup­posed distance from ♈ or ♎, the Hypotenusa AF. 60. The Right Ascension of the Sun, or Arch of the AEquator, AD may be found, by the ninth Case of Right angled Spherical Triangles,

As the Cotang. of the Hypot. AF. 60.
9.76143937
Is to the Radius
10.00000000
So is the Cosine of DAF. 23. 525.
9▪96231533
To the Tang. of AD. 57. 80.
10.20087596

PROBLEM 3.

To find the Declination of a Planet or Fixed Star with Latitude.

In the Oblique angled Spherical Triangle FPS in Fig. 4. we have given, 1. PS = AE ♋ the greatest Declination of the Ecliptick, 2. The Side FS the Complement of the Stars Latitude from the Ecliptick at K. 3. The Angle PSF the Complement of the Stars Longitude. To find PF the Complement of Declination. By the eighth Case of Oblique angled Spherical Triangles, the Proportions are.

As the Cot. of PS. 23. 525.
10.3611802
Is to the Radius.
10.0000000
So is the Cos. of PSF. 20 deg.
9.9729858
To the Tang. of SE. 22. 25.
9.6118056
FS. 86 deg. - ES. 22. 25. = FE.
63. 75.
As the Cos. of ES. 22. 25. Comp. Arith.
0.0336046
To the Cosine of PS. 23. 525.
9.9623154
So the Cos. FE. 63. 75.
9.6457058
To the Cos. PF. 64. 01.
9.6416258

Whose Complement, is FT. 25. 99. the De­clination sought.

PROBLEM 4.

To find the Right Ascension of a Planet, or other Star with Latitude.

The Declination being found by the last Pro­blem, we have in the Oblique angled Spherical Triangle PFS in Fig. 4. All the Sides with the Angle FSP 20 deg. or the Complement of the Stars Longitude. Hence to find FPS by the first Case of Oblique angled Spherical Triangles, I say

As the Sine of PF. 64. 01. Comp. Arith.
0.0463059
Is to the Sine of FSP. 20.
9.5340516
So is the Sine of FS. 86.
9.9984407
To the Sine of FPS. 22. 28.
9.5787982

Whose Complement 67. 72. is the Right Asc. of a Star II. 10. North Lat. 4.

PROBLEM 5.

The Poles Elevation, Sun's greatest Declination and Meridian Altitude being given, to find his true place in the Zodiack.

If the Meridian Altitude of the Sun be less than the height of the AEquator, deduct the Me­ridian Altitude from the height of the AEqua­tor, the Remainer is the Sun's Declination to­wards the South Pole: but if the Meridian Al­titude of the Sun be more than the height of the AEquator, deduct the height of the AEquator from the Meridian Altitude, what remaineth, is the Sun's Declination towards the North Pole, in these Northern Parts of the World: the con­trary is to be observed in the Southern Parts.

Then in the Right angled Spherical Triangle ADF in Fig. 1. we have given the Angle FAD the Sun's greatest Declination.

The Leg DF the Sun's present Declination, To find AF the Sun's distance from the next E­quinoctial Point.

Therefore by the Case of Right angled Spherical Triangles.

As the Sine of FAD. 23. 525. Comp. Ar.
0.3988648
Is to the Sine of DF. 23. 5.
9.5945468
So is the Radius.
10.0009000
To the Sine of AF. 80. 04.
9.9934116

PROBLEM 6.

The Poles Elevation and Sun's Declination being given, to find his Amplitude.

The Amplitude of the Sun's rising or setting is an Arch of the Horizon intercepted betwixt the AEquator and the place of the Sun's rising or setting; and it is either Northward or South­ward, the Northward Amplitude is when he riseth or setteth on this Side of the AEquator to­wards the North Pole; and the Southern when he riseth or setteth on that Side of the AEquator which is towards the South Pole: That we may then find the Sun's Amplitude or Distance from the East or West Point, at the time of his rising or setting. In the Right angled Spherical Tri­angle ATM, in Fig. 2. let there be given the Angle TAM. 38. 47. the Complement of the Poles Elevation; and TM. 23. 15. the Sun's present Declination: To find AM the Sun's Amplitude.

By the eleventh Case of Right angled Spheri­cal Triangles.

As the Sine of MAT. 38. 47. Comp. Ar.
0.2061365
Is to the Radim.
10.0000000
So is the Sine of MT. 23. 15.
9.5945468
To the Sine of AM. 39. 19.
9.8006833

PROBLEM 7.

To find the Ascensional Difference.

The Ascensional Difference is nothing else, but the Difference between the Ascension of any Point of the Ecliptick in a Right Sphere, and the Ascension of the same Point in an Oblique Sphere; As in Fig. 1. AT is the Ascensional dif­ference between DA the Sun's Ascension in a Right Sphere, and DT the Sun's Ascension in an Oblique Sphere. Now then in the Right angled Spherical Triangle AMT, we have given. The Angle MAT. 38. 47. the Complement of the Poles Elevation. And MT. 23. 15. To find AT the Ascensional difference.

As Rad.
 
To the Cot. of MAT. 38. 47. Com. Ar.
10.0999136
So is Tang. MT. 23. 55.
9.6310051
To the Sine of AT. 32. 56.
9.7309187

PROBLEM 8.

Having the Right Ascension and Ascensional Diffe­rence, to find the Oblique Ascension and Descension.

In Fig. 1. DT represents the Right Ascension, AT the Ascensional Difference. DA the Oblique Ascension which is found by deducting the Ascen­sional Difference AT. from the Right Ascension DT. according to the Direction following.

  • [Page 289]If the Declination be
    • N.
    • North
      • Subt.
      • Add
        • The Ascentional Difference from the Right, and it giveth the Oblique A­scension.
        • The Ascensional Difference to the Right, and it giveth the Oblique Descension.
    • South
      • Add
      • Subt.
        • The Ascensional Difference to the Right, and it giveth the Oblique Ascension.
        • The Ascensional Difference from the Right, and it giveth the Oblique De­scension.
Right Ascension of ♊. 0 deg.
57.80
Ascensional Difference
27.62
Oblique Ascension ♊. 0 deg.
30.18
Oblique Descension ♊. 0 deg.
85.42

PROBLEM 9.

To find the time of the Sun's rising and setting, with the length of the Day and Night.

The Ascensional Difference of the Sun being added to the Semidiurnal Arch in a Right Sphere, that is, to 90 Degrees in the Northern Signs, or substracted from it in the Southern, their Sum or Difference will be the Semidiurnal Arch, which [Page 290] doubled is the Right Arch, which bisected is the time of the Sun rising, and the Day Arch bisected is the time of his setting.

As when the Sun is in 0 deg. ♊. his Ascensio­nal Difference is 27. 62. which being added to 90 degrees, because the Declination is North, the Sum will be 117.62 the Semidiurnal Arch.

The double whereof is 235.22 the Diurnal Arch, which being converted into time makes 15 hours 41 minutes: for the length of the Day, whose Complement to 24; is 8 hours 19 minutes the length of the Night; the half whereof is 4 hours 9 minutes 30 Seconds the time of the Sun's rising.

PROBLEM 10.

The Poles Elevation and the Sun's Declination being given, to find his Altitude at any time assigned.

In this Problem there are three Varieties. 1. When the Sun is in the AEquator., that is, in the beginning of ♈ and ♎ in which case suppo­sing the Sun to be at B, 60 degrees or four hours distant from the Meridian, then in the Right angled Spherical Triangle BZ AE, in Fig. 1. we have given, AE Z, 51. 53. the Poles Elevation, and B AE 60 degrees, to find BZ.

Therefore by the 2 Case of Right angled Sphe­rical Triangles.

As the Radius
 
To the Cosine of AE Z. 51. 53.
9.7938635
So is the Cosine of B. AE. 60.
9.6989700
To the Cosine of B Z. 71. 88.
9.4928335

Whose Complement BC. 18. 12. is the ☉ Al­titude required.

The second Variety is when the Sun is in the Northern Signs, that is, in ♈. ♉. ♊. ♋. ♌. ♍. in which Case supposing the Sun to be at F in Fig. II Then in the Oblique angled Spherical Triangle FZP, we have given. 1. PZ 38. 47 the Com­plement of the Poles Elevation. 2. FP. 67. 97 the Complement of Declination. 3. ZPF. 45 the Distance of the ☉ from the Meridian, To find FZ.

Therefore by the eighth Case of Oblique angled Spherical Triangles.

As the Cotang. of ZP. 38. 47.
10.0997059
Is to the Radius.
10.0000000
So is the Cosine of ZPF. 45.
9.8494850
To the Tang. of SP. 29. 33.
9.7497791
Then from FP.
67.97
Deduct SP.
29.33
There rests FS.
38.64
As the Cosine of SP. 29. 33. Comp. Ar.
0.0595768
To the Cosine of PZ. 38. 47.
9.8937251
So is the Cosine of FS. 38. 64.
9.8926982
To the Cosine of FZ. 45. 45.
9.8460001

Whose Complement FC. 44. 55 is the ☉ Alti­tude required.

The third Variety is when the Sun is in the Southern Signs as in ♎. ♏. ♐. ♑. ♒. ♓. And in this Case supposing the ☉ to be ♐ 10 degrees, and his Declination South Db 22. 03. and his Di­stance from the Meridian 45 as before, then in the Oblique angled Spherical Triangle Z bP in Fig. 1. we have given Z P. 38. 47. The Side bP 112. 03. and the Angle ZPb 45. To find Zb.

Therefore by the 8 Case of Oblique angled Spherical Triangles.

As the Cotang. of ZP. 38. 47.
10.0997059
Is to the Radius.
10.0000000
So is the Cosine of ZPb. 45.
9.8494850
To the Tang. of SP. 29. 33.
9.7497791
Then from bP.
112.03
Deduct SP.
29.33
There rests bS.
82.70
As the Cosine of P S. 29. 33. Comp. Ar.
0.0595768
To the Cosine of ZP. 38. 47.
9.8937251
So the Cosine of bS. 82. 70
9.1040246
To the Cosine of Zb. 83. 45.
9.0573265

Whose Complement 6.55 is the ☉ Altitude required.

PROBLEM 11.

Having the Altitude of the Sun, his Distance from the Meridian, and Declination, to find his Azimuth.

The Azimuth of the Sun is an Arch of the Horizon intercepted between the Meridian and the Vertical Line passing by the Sun, being un­derstood by the Angle HZC in Fig. 1. or Arch HC. And in all the Varieties of the last Pro­blem, may be found, by the first Case of Oblique angled Spherical Triangles.

Thus in the Triangle ZBP.

As the Sine of BZ. 71. 88. Comp. Ar.
0.022090 [...]
Is to the Sine of BPZ. 60.
9.9375306
So is the Sine of BP. 90.
10.0000000
To the Sine of BZP. 65. 67.
9.9596209

In the Triangle ZFP. I say.

s. ZF. s. ZPF▪ :: s. FP. s. FZP.

In the Triangle ZbP. I say.

Sine Zb. Sine ZPb :: Sine bP. Sine bZP.

PROBLEM 12.

The Poles Elevation, with the Sun's Altitude and Declination given, to find his Azimuth.

In the Oblique angled Spherical Triangle FZP in Fig. 1. let there be given.

1. FP. 67. 97 the Complement of the ☉ De­clination.

2. ZP. 38. 47 the Complement of the Poles Elevation.

3. FZ. 45. 46 the Complement of the ☉ Al­titude.

And let the Angle FZP the ☉ Azimuth be required.

By the 11 Case of Oblique Angled Spherical Triangles.

As the Sine ZP x Sine FZ, Is to the Square of Radius.

So is the Sine 1/2 Z of the Sides ZP x 1/2 Z cr—ZF.

To the Square of the Sine of half the Angle FZP.

The Sum of the three Sides is 151.89

The half Sum is 75.945 from which deduct PZ 38. 47. The difference is 37.475 And the Difference between 75.945 and FZ is 30. 495.

Sine of PZ. 38. 47. Comp. Ar.
0.2061365
Sine of FZ. 45. 45. Comp. Ar.
0.1471308
s. 1/2 Z cr—PZ. 37. 475.
9.7842000
s. 1/2 Z cr—FZ. 30. 495.
9.7054045
Square of the Sine of 1/2 FZP.
19.8428618
Sine of 57. 94.
9.9214309

The double whereof is 115.88 the ☉ Azimuth from the North. And the Complement 64.12, is the ☉ Azimuth from the South.

PROBLEM 13.

To find the Point of the Ecliptick Culminating, and its Altitude.

Before we can know what Sign and Degree of the Ecliptick is in the Medium Coeli; we must find the Right Ascension thereof, to do which, we must add the Sun's Right Ascension to the time afternoon, being reduced into Degrees and Minutes of the AEquator, the Sum is the Right Ascension of the Medium Coeli.

Example. Let the time given, be March the 20. 1674. at one of the Clock in the After­noon.

At which time the Sun's place is in ♈. 10 deg. 23 Centesms.

To find the Right Ascension thereof, in the Right angled Spherical T [...]iangle ADF in Fig. 1. we have given; The Angle of the Sun's great­est Declination DAF 23. 525 and the Sun's di­stance from the next Equinoctial Point AF 10. 23.

Therefore by the ninth Case of Right angled Spherical Triangles.

As the ct. AF. 10. 23.
10.7435974
Is to Radius.
10.0000000
So is cs DAF 22. 525.
19.9623154
To t AD 9. 39.
9.2187180

To which adding the Equinoctial Degrees an­swering to one hour, viz. 15. the Sum is 24.39 the Right Ascension of the Mid Heaven. Hence to find the Point culminating; in the Right angled Spherical Triangle ADF in Fig. 1. we have given AD 24. 39 and DAF 23. 525 to find AF.

Therefore by the fifth Case of Right Angled Spherical Triangles.

As t AD 24. 39.
10.6564908
Is to Radius.
10.0000000
So is cs DAF 23. 525.
9.9623154
To ct. AF 26. 31.
10.3058246

Therefore the Point culminating is ♈ 26. 31.

To find the Altitude thereof above the Hori­zon we have given in the same Triangle DAF 23. 525. and AF 26. 31. to find DF.

Therefore by the tenth Case of Right angled Spherical Triangles.

As Radius.
10.0000000
Is to s AF—26, 31.
9.6466268
So is s DAF 23. 525.
9.6011352
To the s DF 10. 19.
9.2477628

[Page 297] Which is the North Declination of the Point of the Ecliptick culminating, and being added to the height of the AEquator at London 38. 47 the Sum is 48.66 the Altitude of the Mid Heaven as was required.

PROBLEM 14.

Having the greatest obliquity of the Ecliptick together with the Distance of the Point given from the Equinoctial, to find the Meridian Angle, or Intersection of the Meridian with the Ecliptick.

Having drawn the Primitive Circle HZRN in Fig. 5. representing the Meridian, and the two Diameters HAR, and ZAN, set off the height of the Pole from R to P. 51. 53, and from N to S, and draw the Diameters PAS for the Axis of the World, and AE AQ for the AEquator; this done, the Right Ascension of the Mid Heaven being given, as in the last Problem 24.39 with the Point culminating. ♈. 26.31, and the Declination thereof 10.19, if you set 10 deg. 19 Centesmes from AE to F and e to X, you may draw the Dia­meters FAX and cAd at Right Angles thereun­to, and because the Imum Coeli is directly opposite to the Point culminating, that is, in ♎ 26.31, if you set 26.31 from X to b, a Ruler laid from c to b will cut the Diameter FX in G, and then making Xh Z Xb you have the three Points b G h, by which to draw that Circle, which will cut the AE­quator AE AQ in ♎, and so you have the three Points XF by which to describe the Arch of the Ecliptick ♈ F ♎ X.

[Page 298] And in the Right angled Spherical Triangle ♈ AEF we have given. The Angle AEF. 23.525 the Sun's greatest Declination, and ♈ F. 26. 31. the Point culminating, to find the Angle ♈ F AE.

Therefore by the seventh Case of Right ang­led Spherical Triangles.

As the ct AE ♈ F. 23. 525.
10.3611802
Is to the Radius.
10.0000000
So is the csF. 26. 31.
9.9525062
To the cot.FAE. 68. 60.
9.5913260

Which is the Angle of the Ecliptick with the Meridian.

PROBLEM 15.

To find the Angle Orient, or Altitude of the Nona­gesime Degree of the Ecliptick.

In Fig. 5. the Pole of the Ecliptick ♈ FX is at m, and so you have the three Points Z m N to draw the Vertical Circle Z k N cutting the Ecliptick at Right Angles in the Point a: And then in the Right angled Spherical Triangle F a Z, we have given; FZ 41. 34 the Comple­ment of FH the Altitude of the Mid Heaven; And the Angle a FZ 68. 68 the Angle of the Ecliptick with the Meridian. To find Z a.

Therefore by the tenth Case of Right angled Spherical Triangles.

[Page 299] As the Radius.

To the Sine of FZ. 41. 34.
9.819889 [...]
So is the Sine of Z F a. 68. 68.
9.9691128
To the Sine of Z a. 37. 97.
9.7891027

Whose Complement is ak the Measure of the Angle agk 52. 03 the Angle of the Ecliptick with the Horizon, or Altitude of the Nonagesime Degree.

PROBLEM 16.

To find the place of Nonagosime Degree of the Ecliptick.

In Fig. 5. F represents the Point of the Eclip­tick in the Mid Heaven, which according to Pro­blem 14 is ♈. 26.31 which being known, in the Triangle FZa, we have also given, FZ 41. 34 and the Angle ZFa. 68. 68. To find Fa.

Therefore by the ninth Case of Right angled Spherical Triangles.

As the cot. of FZ. 41. 34.
10.0556361
Is to the Radius.
10.0000000
So is the cos. of ZFa. 6. 8. 6. 8.
9.5605957
To the tang. of Fa. 17. 73.
9.5049596

Which being added to ♈ F 26. 31 the sum is ♈ a. 44. 04 the place of the Nonagesime Degree of the Ecliptick at a.

PROBLEM 17.

The Mid Heaven being given, to find the Points of the Ecliptick Ascending and Descending.

Having found by the last Problem, the place of Nonagesime Degree of the Ecliptick at a to be in ♉. 14.04, if you add 90 Degrees or three Signs thereto, the Ascendant at g will be in ♌ 14. 04, and the Point descending by adding of six Signs will be in ♒ 14. 02. But these with the Cusps of the other Houses of Heaven may be otherwise found in this manner.

To the Right Ascension of the Medium Coeli or the tenth House, add 30, it giveth the Ascen­sion of the eleventh House, to which adding 90 Degrees more, it giveth the Ascension of the twelfth House, &c. According to which dire­ction, the Ascensions of the six Houses towards the Orient, are here set down in the following Table.

10.24.39
11.54.39
12.84.39
1.114.39
2.144.39
3.174.39

Now because the Circles of Position must according to these Directions cut the AEquator at 30 and 30 Degrees above the Horizon, if in Fig. 5. you set 30 Degrees from AE to n, and n to r. A Ruler laid from P to n and r, shall cut the AEquator at B and K, and then you may describe the Circles of Position HBR and HKR, make AT = AK and AV= AB, and so you may describe the Circles HTR and HVR, and where these Circles do cut the [Page 301] Arch of the Ecliptick ♈ F ♎ there are the Cusps of the Coelestial Houses.

Thus a Ruler laid from m. the Pole of the E­cliptick to the Intersections ct s. t. g. [...]. will cut the Primitive Circle in [...]. and the Ar­ches [...] = Fs. [...] = Ft. [...] = Fg. [...] = [...]. and [...] = [...] being added to [...] B will give you the Cusps of the 11. 12. 1. 2 and 3 Houses, the o­ther six are the same Degrees and Parts in the Opposite Signs.

Thus a Figure in Heaven may be erected by Projection, the Arithmetical Computation now followeth; In which the height of the Pole above each Circle of Position is required, the which in the Projection is easily found; as the Pole of the Circle of Position HBR is at the Point D. and so you have the three Points S, D, P, to describe that Circle by, which will cut the Circle HBR at Right Angles in the Point C. and the Arch PC is the height of the Pole above that Circle of Po­sition, and may be measured by the Directions given in the nineteenth of the third Chapter.

In like manner the height of the Pole above the Circle of Position HKR, will be the Arch PE.

To compute the same Arithmetically in the Right angled Spherical Triangle HAEB in Fig. 5. we have given AEH. 38. 47 the height of the Equator. AEB 30. the difference of Ascension be­tween the 10 and 11 Houses, to find HBAE the Angle of that Equator with the Circle of Posi­tion.

Therefore by the first Case of Right angled Spherical Triangles.

As the Tang. of H AE, 38. 47.
9.90000652
Is to the Radius.
10.00000000
So is the Sine of AE B. 30
9.69897000
To the Cotang. of AE B H. 57. 81626.
9.79888348

Whose Measure in the Scheme is EC, and the Complement thereof is CP. 32. 18374 the height of the Pole required.

Therefore the height of the Pole above the Circle of Position HKR. In the Triangle HAEK, we have given, H AE as before, and AE K. 60 to find HKAE. Therefore.

As the Tang. of H AE 38. 47.
9.90008652
Is to the Radius.
10.00000000
So is the Sine of AE K 60.
9.93753063
To the Cotang. of HK AE 42. 53308.
10.03744411

Whose Measure in the Scheme is GL, and the Complement thereof is PL 47. 46692. the height of the Pole required.

The height of the Pole above HDR is the same with HBR, and the height of the Pole a­bove HTR is the same with HKR.

Having found the Ascensions of the several Houses together with the Elevation of the Pole above their Circles of Position, in the Oblique angled Spherical Triangle ♈ BS, we have given.

1. The Angle ♈ BS the Complement of HBAE.

2. The Angle B ♈ S. 23. The Sun's greatest Declination.

3. Their included Side ♈ B. 54. 39 the As­cension of the eleventh House. To find ♈ S the [Page 303] Point of the Ecliptick, which is resolvable by the ninth Case of Right angled Spherical Triangles.

But in my Trigonometria Britannica, Problem. 5. for the resolving of Oblique angled Spherical Triangles, I have shewed how this Case as to our present purpose may be resolved, by these Pro­portions following.

  • 1. s 1/2 Z Ang. s 1/2 X Ang :: t 1/2 ♈ B. t 1/2 X Cru.
  • 2. cs 1/2 Z Ang. cs 1/2 X Ang :: t 1/2 ♈ B. t 1/2 Z Cru.
  • 1/2 Z Cru + 1/2 X Cru=♈ S the Arch of the E­cliptick desired.
For the Cusp of the Eleventh House.
  • T B Arch ♈ B. 4439 the half whereof is 27. 195.
  • ♈ B S. 122. 18374.
  • B ♈ S. 23. 525.
  • Z 145.70874—1/2 Z 72. 85437.
  • X. 198.65874—1/2 X. 49. 32937.
s 1/2 Z. 72. 85437. Comp. Arith.
0.01977589
s 1/2 X. 49. 32937.
9.88000800
t 1/2 ♈ B. 27. 195.
9.71081089
t 1/2 X Cru. 22. 192.
9.61059478
2. Operation.
cs. 1/2 Z. 72. 85437. Comp. Arith.
0.53012277
ss 1/2 X. 49. 32937.
9.81395860
t 1/2 ♈ B. 27. 195.
9.71081089
t 1/2 Z Cru. 48. 611.
10.05489226

1. Arch. 22. 192. Their Sum is 70.803 the Point of the Ecliptick.

cs. ½ Z. 82. 51916. Comp. Arish.
0.88517901
cs ½ X. 59. 00416.
9.71164750
t. ½ ♈ A. 57. 195.
10.19072348
t▪ ½ Z Cru: 78. 397.
10.68754999

1. Arch—53. 296. Their Sum 121.693 is the Point of the Ecliptick for the Ascendant.

For the Cusp of the Second House.

In the Oblique angled Spherical Triangle ♈ T [...]. we have given,

1. ♈ T. 144. 39.
The half whereof is 72. 195.
2. ♈ T [...]. 122. 18374
To find [...]. The An­gles are the same with those of the Twelfth House. Therefore.
3. T [...] y. 23. 525
 
s. ½ Z. 80. 49596. Comp. Arith.
0.00601663
s ½ X. 56. 97096.
9.92351651
Their Sum
9.92953314
t ½ ♈ T. 72. 195.
10.49327695
t ½ X Cru. 69. 306.
10.42281009
2. Operation.
cs ½ Z 80. 49596. Comp. Arith.
0.78170174
cs ½ X 56. 97096.
9.73628614
Their Sum
10.51798788
t ½ ♈ T. 72. 195.
10.49327695
t ½ Z Cru. 84. 34.
11.01126483

1. Arch. 69. 306. Their Sum is 53.740 is the Point of the Ecliptick for the Second House.

For the Cusp of the Third House.

In the Oblique angled Spherical Triangle ♈ [...], we have,

1. ♈ [...]. 174. 39. The half whereof is 87. 195. The Angls ♈ [...] and [...] [...] are the same with those of the Eleventh House.

s ½ Z. 72. 85437. Comp. Arith.
0.01977580
s ½ [...] 49. 32937.
6.88000800
Their Sum
9.89978389
t ½ [...]. 87. 195.
11.30984054

For the Eleventh House.

For the Cusp of the Twelfth House.

In the Oblique angled Spherical Triangle ♈ KF, we have given.

1. [...] K. 84. 39.
The half whereof is. 42. 195.
2. ♈ Kt. 137.46692
 
3. K ♈ t. 23.525
To find ♈ t.
Z. 160.99192
½ Z. 80.49596
X. 113.94192
½ X. 56.97096
s ½ Z. 80. 49596. Comp. Arith.
0.00601663
s ½ X. 56. 97096.
9.92351651
t ½ ♈ K. 42. 195.
9.95740882
t ½ X Cru. 37. 625.
9.88694196
2. Operation.
cs. ½ Z. 80. 49596. Comp. Arith.
0.78170174
cs ½ X. 56. 97096.
9.73628614
t ½ ♈ K. 42. 195.
9.95740882
t ½ Z Cru. 71. 496.
10.47539670

1. Arch. 37. 625. Their Sum 113.6691 is the Point of the Ecliptick for the Twelfth House.

For the Cusp of the Ascendant.

In the Oblique angled Spherical Triangle ♈ AG we have,

1. ♈ A. 114. 39.
The half whereof is 57. 195.
2. ♈ AZ. 141. 5333.
The Complement of HAAE 38. 46667.
3. A [...] y. 23. 525.
 
Z. 165.05833
½ Z. 82.51916
X. 118.00833
½ X. 59.00416
s. ½ Z. 82. 51916. Comp. Arith.
0.0037162 [...]
s. ½ X. 59. 00416.
9.93313477
t ½ ♈ A. 57. 195.
10.19072348
t ½ X. 53. 296.
10.12757454
2. Operation.
t ½ X Cru. 86. 468.
11.20962043
2. Operation.
cs ½ Z. 72. 85437. Comp. Arith.
0.53012277
cs ½ X. 49. 32937.
9.81395860
Their Sum
10.34408137
t ½ ♈ [...]. 87. 195.
11.39984054
t ½ X Cru. 88. 729.
11.65392191

1. Arch. 86. 468. Their Sum 175.197 is the Point of the Ecliptick for the Third House.

And thus we have not only erected a Figure for the Time given, but composed a Table for the general erecting of a Figure in that Eatitude; for by adding together the first and second Num­bers in each Proportion for the first, second and third Houses there is composed two Numbers for each House, to each of which the Artificial Tan­gent of half the Ascension of each House being added, their Aggregates are the Tangents of two Arches, which being added together, do give the distance of the Cusp of the House, from the first Point of Aries, as in the preceding Ope­rations hath been shewed.

Only note, That if the Ascension of any House be more than a Semicircle, you must take the Tangent of half the Complement to a whole Circle. And to find the Cusp of the House, you must also take the Complement of the Sum of the Arches added together.

The Numbers according to the former Ope­rations which do constitute a Table of Houses for the Latitude of London. 51. 53 are as follow­eth.

[Page 308]

 11 and 3 HousesAscendant12 and 2 Houses
1. Oper.9.899783899.936851069.92953314
2. Oper.10.3440813710.5968265110.51798788

The Six Oriental Houses, by the preceding Operations.

The opposite Hou­ses are in the op­posite Signs and Degrees.
  • 10 House ♈ 26.311
  • 11 House ♊ 10.803
  • 12 House ♋ 23.691
  • Ascendant ♌ 11.693
  • 2 House ♏ 3.740
  • 3 House ♏ 25.197
  • 4 House ♎ 26.311
  • 5 House ♐ 10.803
  • 9 House ♑ 23.691
  • 7 House ♒ 11.693
  • 8 House ♓ 3.740
  • 9 House ♓ 25.197

A Figure of the Twelve Coelestial Houses.

[Page]

[figure]

[Page] [Page]

[figure]
ASTRONOMY. THE Secon …

ASTRONOMY. THE Second Part: OR, AN ACCOUNT OF THE Civil Year, With the Reason of the Difference Between the JULIAN & GREGORIAN Calendars, And the manner of Compu­ting the Places of the SVN and MOON.

LONDON, Printed for Thomas Passinger, at the Three Bibles on London-Bridge. 1679.

AN INTRODUCTION TO Astronomy.
The Second Book.

CHAP. I.

Of the Year Civil and Astronomical.

HAving shewed the Motion of the Pri­mum Mobile, or Doctrine of the Sphere, which I call the Absolute Part of Astronomy; I come now un­to the Comparative, that is, to shew the Motion of the Stars in reference to some cer­tain Distinction of Time.

2. And the Distinction of Time is to be con­sidered either according to Nature, or according to Institution.

[Page 312] 3. The Distinction of Time according to Na­ture, is that space of Time, in which the Planets do finish their Periodical Revolutions from one certain Point in the Zodiack, to the same again, and this in reference to the Sun is called a Year, in reference to the Moon a Month.

4. The Sun doth pass through the Zodiack in 365 Days, 5 Hours, and 49 Minutes. And the Moon doth finish her course in the Zodiack, and return into Conjunction with the Sun, in 29 Days, 12 hours, 44 Minutes, and 4 Seconds. And from the Motion of these two Planets, the Civil Year in every Nation doth receive its Institu­tion.

5. Twelve Moons or Moneths is the measure of the Common Year, in Turkey in every Moneth they have 29 or 30 Days, in the whole Year 354 Days, and in every third Year 355 Days.

6. The Persians and Egyptians do also account 12 Moneths to their Year; but their moneths are proportioned to the Time of the Suns con­tinuance in every of the Twelve Signs; in their Year therefore which is Solar, there are always 365 Days, that is eleven Days more than the Lu­nar Year.

7. And the Iulian Year which is the Account of all Christendom, doth differ from the other in this; that by reason of the Sun's Excess in Moti­on above 365 Days, which is 5 Hours, 49 Minutes, it hath a Day intercalated once in 4 Years, and by this intercalation, it is more agreeable to the Motion of the Sun, than the former, and yet there is a considerable difference between them, which hath occasioned the Church of Rome to make some further amendment of the Solar [Page 313] Year, but hath not brought it to that exactness, which might be wished.

8. This intercalation of one Day once in 4 Years, doth occasion the Sunday Letter still to al­ter till 28 Years be gone about; The Days of the Week which use to be signed by the seven first Letters in the Alphabet, do not fall alike in eve­ry Common Year, but because the Year consisteth of 52 Weeks and one Day, Sunday this Year will fall out upon the next Year's Monday, and so for­ward for seven years, but every fourth year con­sisting of 52 weeks and two days, doth occasion the Sunday Letter to alter, till four times seven years, that is till 28 years be gone about. This Revolution is called the Cycle of the Sun, taking its name from the Sunday Letter, of which it sheweth all the Changes that it can have by rea­son of the Bissextile or Leap-year. To find which of the 28 the present is, add nine to the year of our Lord, (because this Circle was so far gone about, at the time of Christs Birth) and di­vide the whole by 28, what remaineth is the present year, if nothing remain the Cycle is out, and that you must call the last year of the Cycle, or 28.

9. This Intercalation of one day in four years, doth occasion the Letter F to be twice repeated in February, in which Moneth the day is added, that is, the Letter F is set to the 24 and 25 days of that Moneth, and in such a year S. Matthias day is to be observed upon the 25 day, and the next Sunday doth change or alter his Letter, from which leaping or changing, such a year is called Leap-year, aud the number of days in each Moneth is well expressed by these old Verses.

[Page 314] Thirty days hath September, April, June and No­vember.

February hath 28 alone, All the rest have thirty and one.

But when of Leap-year cometh the Time,
Then days hath February twenty and nine.

That this year is somewhat too long, is ac­knowledged by the most skilful Astronomers, as for the number of days in a year the Emperours Mathematicians were in the right, for it is cer­tain, that no year can consist of more than 365 days, but for the odd hours it is as certain that they cannot be fewer than five, nor yet so many as six; so then the doubt is upon the minutes, 60 whereof do make an hour, a small matter one would think, but how great in the consequence we shall see. The Emperours year being more than 10 minutes greater than the Suns, will in 134 years rise to one whole day, and by this means the Vernal or Spring Equinox, which in Iulius Caesar's time was upon the 24 of March, is now in our time upon the 10 of March, 13 days backward, and somewhat more, and so if it be let alone will go back to the first of March, and first of February, and by degrees more and more backward still.

10. To reform this difference, some of the late Roman Bishops have earnestly endeavoured. And the thing was brought to that perfection it now standeth, by Gregory the Thirteenth, in the year 1582. His Mathematicians, whereof Lili­us was the Chief, advised him thus: That con­sidering there had been an Agitation in the [Page 315] Council of Nice somewhat concerned in this matter upon the motion of that Question, about the Celebration of Easter. And that the Fa­thers of the Assembly, after due deliberation with the Astronomers of that time, had fixed the Vernal Equinox at the 21 of March, and con­sidering also that since that time a difference of ten whole days had past over in the Calendar, that is, that the Vernal Equinox, which began upon the 21 of March, had prevented so much, as to begin in Gregorie's days at the 10 of the same, they advised, that 10 days should be cut off from the Calendar, which was done, and the 10 days taken out of October in the year 1582. as being the moneth of that year in which that Pope was born; so that when they came to the fifth of the moneth they reckoned the 15, and so the Equinox was come up to its place a­gain, and happened upon the 21 of March, as at the Council of Nice.

But that Lilius should bring back the begin­ning of the year to the time of the Nicene Council and no further, is to be marvelled at, he should have brought it back to the Emperours own time, where the mistake was first entered, and instead of 10, cut off 13 days; however this is the reason why these two Calendars differ the space of 10 days from one another. And thus I have given you an account of the year as it now stands with us in England, and with the rest of the Christian World in respect of the Sun, some o­ther particulars there are between us and them which do depend upon the motion of the Moon, as well as of the Sun, and for the better under­derstanding of them, I will also give you a brief [Page 316] account of her revolution. But first I will shew you, how the day of the moneth in any year pro­pounded in one Couutry, may be reduced to its correspondent time in another.

11. Taking therefore the length of the year, to be in several Nations as hath been before de­clared, if we would find what day of the moneth in one Conntry is correspondent to the day of that moneth given in another, there must be some beginning to every one of these Accounts, and that beginning must be referred to some one, as to the common measure of the rest.

12. The most natural beginning of All Ac­counts, is the time of the Worlds Creation, but they who could not attain to the Worlds Begin­ning, have reckoned from their own, as the Ro­mans from the building of Rome, the Greeks from their Olympicks, the Assyrians from Nabonassar, and all Christians from the Birth of Christ: the beginning of which and all other the most nota­ble Epochaes, we have ascertained to their corre­spondent times in the Julian Period, which Sca­liger contrived by the continual Multiplication of those Circles, all in former time of good use, and two of them do yet remain; the Circles yet in use are those of the Sun and Moon, the one, to wit, the Sun, is a Circle of 28 years, and the Cir­cle of the Moon is 19, as shall be shewed here­after. The third Circle which now serves for no other use than the constituting of the Julian Period, is the Roman Indiction, or a Circle of 15 years; if you multiply 28 the Circle of the Sun, by 19 the Circle of the Moon, the Product is 532, which being multiplied by 15, the Circle of the Roman Indiction, the Product is 7980, the [Page 317] Number of years in the Julian Period: whose admirable condition is to distinguish every year within the whole Circle by a several certain Cha­racter, the year of the Sun, Moon, and Indiction being never the same again until the revolution of 7980 years be gone about, the beginning of this Period was 764 Julian years before the most reputed time of the Worlds Creation; which being premised, we will now by Example shew you how to reduce the years of Forreigners to our Julian years, and the contrary.

1. Example.

I desire to know at what time in the Turkish Account, the fifth of Iune in the year of our Lord 1640. doth fall.

The Julian years complete are 1648, and are thus turned into days, by the Table of days in Julian years.

1000 Julian years give days
365250
600 Julian years give days▪
219150
40 Julian years give days
14610
8 Years give days
2922
May complete
151
Days
5
The Sum is
602088

Now because the Turkish Account began Iuly 16. Anno Christi. 622. you must convert these years into days also.

600 Julian years give days
219150
20 Years give days
7305
1 Year giveth days
365
Iune complete
181
Days
15
The Sum is
227016
Which being substracted from
602088
There resteth days
375072
900 Turkish years give days
318930
There resteth
56142
150 Turkish years give days
53155
There resteth
02987
8 Turkish years give days
2835
There resteth
152
Giumadi. 4.
148
There resteth
4

Therefore the fifth of Iune 1649. in our En­glish Account doth fall in the year 1058. of Ma­homet, or the Turkish Hegira, the fourth day of the moneth Giumadi. 11

2. Example.

I desire to know upon what day of our Julian year the 17 day of the moneth in the 1069 year complete of the Persian Account from Ieshagile doth fall.

The beginning of this Epocha is from the Epo­cha of Christ in complete days
230639
1000 Persian years give
365000
60 Years give
21900
9 Years give
3285
Chortal complete
90
Days complete
16
The Sum
620930
1000 Julian years Substracted
365250
There rests
255680
700 Julian years
255675
There rests
5

Therefore it falls out in the Julian year from Christ 1700. the fifth day of Ianuary.

He that understands this may by the like me­thod convert the years of other Epochas, into our Julian years and the contrary.

The Anticipation of the Gregorian Calendar is more easily obtained, for if you enter the Ta­ble with the years of Christ complete, you have the days to be added to the time in the Julian Account, to make it answer to the Gregorian, which will be but ten days difference till the year 1700. and then the difference will be a day more, until the year 1800. and so forward three days difference more in every 400 years to come, un­less our year shall be reformed as well as theirs.

CHAP. II.

Of the Cycle of the Moon, what it is, how placed in the Calendar, and to what pur­pose.

THat the Civil Year in use with us and all Christians, doth consist of 365 days, and every fourth year of 366, hath been already shew­ed, with the return of the Sunday Letter in 28 years. In which time the Moon doth finish her course in the Zodiack no less than twelve times, which twelve Moons, or 354 days, do fall short of the Sun's year, eleven days in every common year, and twelve in the Bissextile or Leap-year.

And by Observation of Meton an Athenian, it was found out about 432 years before Christ, that the Moon in nineteen years did return to be in Conjunction with the Sun on the self same day, and this Circle of nineteen years is called the Cy­cle of the Moon, which being written in the Ca­lendar against the day in every Moneth, in which the Moon did change, in Letters of Gold, was also called the Golden Number, or from the excellent use thereof, which was at first, only to find the New Moons in every Moneth for ever, but a­mongst Christians it serveth for another purpose also, even the finding of the time when the Feast of Easter is to be observed. The New Moons by this Number are thus found. In the first year of the Circle, or when the Golden Number is 1, where the Number 1 was set in the Ca­lendar in any Moneth, that day is New Moon, in [Page 319] the second Year where you find the golden Num­ber 2, in the third Year where you find the gol­den Number 3, and so forward till the whole Circle be expired; then you must begin with one again, and run through the whole Circle as be­fore.

2. And the reason why the Calendar begins with the golden Number 3, not 1, is this. The Christians in Alexandria had used this Circle of the Moon two Years before the Nicene Council. And in the first of these Years the new Moon next to the Vernal Equinox was upon the 27th Day of the Egyptian month Phamenoth answering to the 23d of our March, against that Day therefore they placed the golden Number 1. And because there are 29 Days and a half from one new Moon to another, they made the distance be­tween the new Moons to be interchangeably 29 and 30 Days, and so they placed the same gol­den Number against the 26 Day of Phurmuthi the Month following, and against the 26 Day of the Month Pachon and so forward, and upon this ground by the like progression was the golden Number set in the Roman Calendar; and so the golden Number 1 by their example was set a­gainst March 23. April 21. Iune 19. Iuly 19. August 17. September 16. October 15. Novem­ber 14. December. 13. But then because in the following Year the golden Number was 2. reckon­ing 30 Days from the 13th of December, the golden Number 2 was set to Innuary 12. Febru­ary 10. March 12. April 10. May 10. Iune 8. Iuly 8. August 6. September 5. October 4. November 3. December. 2. From whence reckon­ing 13 Days as before, the golden Number 3 [Page 320] comes in course for the third Year to be set against the first of Ianuary.

But that you may know how the golden Num­ber comes to be distributed in the Calendar ac­cording to the form in which it now is, you must consider that in 19 Solar Years there are not only 228 Lunar Months or 12 times 19 Lunar Months but 235 for the 11 Days which the com­mon Solar Year doth exceed the Lunar, do in 19 Years arise to 209 Days, out of which there may be appointed 7 Months, 6 whereof will con­tain 30 Days apiece, and one Month 29 days; and these 7 Months are called Embolismical Months, because by a kind of injection or interposition they are reckoned in some of the 19 Years. And those Years in which they are reckoned are called Embolismical Years, to distinguish them from the common Years which always contain 354 Days, whereas 6 of these Embolismical Years do each of them contain 384 Days, and the seventh Embo­lismical Year in which the Month of 29 Days is reckoned, doth contain 383 Days.

3. The Embolismical Years in the Cycle of the Moon are properly these Seven. 3, 6, 9, 11, 14, 17, 19. because in the third Year 11 Days being thrice reckoned do amount to 33 Days, that is one Month of 30 Days and 3 Days over. A­gain in the sixth Year the 11 Days which the So­lar exceed the Lunar, being thrice numbred, do amount to 33 Days. which with the 3 Days for­merly reserved do make 36 Days, that is one Month of 30 Days and 6 Days over. Again in the Ninth Year there are also 33 Days, to which the 6 Days reserved being added, there will a­rise one Month more and 9 Days over. But in [Page 321] the Eleventh Year twice 11 Days being added to the 9 Days reserved, do make 31 Days, that is, one Month of 30 days and one day over, which be­ing added to the supernumerary days in the four­teenth Year do make another Month of 30 Days and 4 Days over, and these being added to the supernumerary Days in the sevententh Year do make another Month of 30 and 7 Days over, and these 7 Days being added to the 22 supernu­merary Days in the Ninteenth Year of the Moons Cycle do make another Month of 29 Days.

4. But because there are 6939 Days and 18 Hours in 19 Solar Years, that is, 4 Days 18 Hours more then in the common and Embolismical Lu­nar Years, in which the excess between the Lu­nar and the Solar Year is supposed to be no more then 11 Days in each Year, whereas in every fourth Year the excess is one Day more, that is, 12 Days, that is, in 16 Years 4 Days, and in the remaining 3 Years three fourths of a day more. And that the new Moons after 19 Lunar Years or 235 Lunations do not return to the same days again, but want almost 5 days, it is evident that the civil Lunations do not agree with the Astro­nomical and that there must be yet some kind of intercalation used.

5. Now therefore in distributing the golden Number throughout the Calendar. If the new Moons should interchangeably consist of 30 and 29 days, and so but 228 Lunations in 19 Years; we might proceed in the same order in which we have begun, and by which as hath been shewed the third Year of the Golden Number falls upon the Calends of Ianuary. But for as much as there are first six Lunations of 30 days apiece and [Page 322] one of 29 days to be interposed, therefore there must be 6 times 2 Lunations together consisting of 30 days and once three Lunations of 29 days. And that respect may be also had to the Bissextile days, although they are not exprest in the Calen­dar, that Lunation which doth contain the Bis­sertile day, if it should have been 29 days, it must be 30, if it should have consisted of 30 days it must consist of 31.

6. And because it was thought convenient, as hath been shewed, to begin with the third Year of the Cycle of the Moon, because the Golden Num­ber 3 is set to the Calends of Ianuary, therefore in this Cycle the Embolismical Years are, 2, 5, 8, 11, 13, 16, 19. But yet that it may ap­pear, that these Years are in effect the same, as if we had begun with the first Year of the Gol­den Number, save only that the eighth Year in­stead of the ninth is to be accounted Embolismi­cal, I have added the Table follwing, in which it is apparent that the former Embolismical years do agree with these last mentioned.

7. But as I said before, it was thought more convenient to begin the account from the num­ber 3 set to the Calends of Ianuary, because by so reckoning 30 and 29 days to each Lunation interchangeably, the same Number 3 falls upon Ianuary 31. March 1, and 31. April 29. May 29. Iune 27. Iuly 27. August 25. September 14. October 23. November 22. December 21. As if the Lunar years were compleated upon the 20 of December there remain just 11 Days, which the Solar years doth exceed the Lunar.

8. And by ranking on and accounting 4 for the Golden Number of the next year, you will [Page 323] find it set on Ianuary 20, February 18, March 20, April 18, May 18, Iune 16, Iuly 16, August 14, September 13, Octob. 12, No­vemb. 11, Decemb. 10.

Cycle of the Moon.Cycle of the Moon.Embolismical Years.Number of Days.
13 354
24 354
35Embol.384
46 354
57 354
68Embol.384
79 354
810 354
911Embol.384
1012 354
    
1113Embol.384
1214 354
1315 354
1416Embol.384
1517 354
1618 354
1719Embol.384
181 354
192Embol.384

9. But in going on, and taking 5 for the Golden Number in the third year, we must remember that that is an Embolis­mical Year, and therefore that some­where there must be 2 Months together of 30 days. And for this reason the Gol­den Number 5, is set to Ianuary 9, Febru­ary 7, March 9, April 7, May 7, Iune 5, Iuly 5, August 3, Se­ptember 2, as also up­on the second day of October, and not up­on the first, that so there may be 2 Luna­tions together of 30, and the same Num­ber 5 is also set to the thirty first of October, to make the Lunation to consist of 29 days, and to the thirtieth of November in­stead of the twenty ninth, that so a Lunation of [Page 324] 30 may again succeed as it ought.

10. In like manner in the sixth Year, having gone through the fourth and fifth as common years, you may see the Golden Number 8 set to the fifth of April, which should have been upon the fourth, and in the ninth Year the Golden Number 11 is set to the second of February which should have been upon the first.

And there is a particular reason, for which these numbers are otherwise placed from the eighth of March to the fifth of April, namely, that all the paschal Lunations may consist of 29 days: For thus from the eighth of March to the sixth of April, to both which days the Golden Number is 16, there are but 29 days. And from the ninth of March to the seventh of April, to both which days the Golden Number is 5, there are also 29 days, and so of the rest till you come to the fifth of April, which is the last Paschal Lunation, as the eighth of March is the first, but at any other time of the Year, the length of the Month in the Embolismical Year, may be fixed as you please.

12. And in this manner in the 17 years, in which the lunations of the whole Circle are fi­nished, and in which the Golden Number is 19, the Month of Iuly is taken at pleasure, to the thir­tieth day whereof is set the Golden Number 19, which should have been upon the thirty first, and the same Number being notwithstanding placed upon the twenty eighth of August, that by the two Lunations of 29 days together, it might be understood, that the seventh Embolismical Month consisting of 29 days is there inserted, instead of a Month of 30 days. In which place the Em­bolismical or leaping Year of the Moon may [Page 325] plainly be observed for that year is one day less than the rest, which the Moon doth as it were pass over. The which one day is again added to the 29 days of the last Month, that we may by that means come, as in other Years, to the Gol­den Number, which sheweth the New Moon in Ianuary following. And for this reason the E­pact then doth not consist of 11 but of 12 days. And thus you see the reason, for which the Gol­den Numbers are thus set in the Calendar as here you see. In which we may also observe, that every following Number is made by adding 8 to the Number preceding, and every preceding Num­ber is also made by adding 11 to the Number next following, and casting away 19 when the addition shall exceed it.

For Example, if you add 8 to the Golden Number 3 set against the first of Ianuary, it ma­keth 11, to which add 8 more and it maketh 19, to which adding 8 it maketh 27, from which substracting 19 the remainer is 8, to which again adding 8, the sum is 19, to which adding 8 the sum is 24, from which deducting 19 the remainer is 5, and so of the rest. In like manner receding backward, to the 5 add 11 they make 16, to the 16 add 11 they make 27, from which deducting 19 the remainer is 8, to which 11 being added the same is 19, to which 11 being added the sum is 30, from which deducting 19 the remainer is 11, to which 11 being added the sum is 22, from which deducting 19 the remainer is 3. And by this we may see that every following number will be in use 8 years after the preceding, and every prece­ding Number will be in use 11 years after the fol­lowing, that is, the same will return to be in use after [Page 326] 8 Years and 11, and the other after 11 Years and 8, or once in 19 years.

CHAP. III.

Of the Vse of the Golden Number in finding the Feast of Easter.

THe Cycle of the Moon or Golden Number is a circle of 19 years, as hath been said al­ready, which being distributed in the Calendar as hath been shewn in the last Chapter, doth shew the day of the New Moon for ever; though not exactly: But the use for which it was chiefly in­tended, was to find the Paschal New Moons, that is, those new Moons on which the Feast of Easter and other moveable Feasts depend. To this purpose we must remember,

1. That the vernal Equinox is supposed to be fixed to the twenty first day of March.

2. That the fourteenth day of the Moon on which the Feast of Easter doth depend, can ne­ver happen before the Equinox; though it may fall upon it or upon the day following.

3. That the Feast of Easter is never observed upon the fourteenth day of the Moon, but upon the Sunday following; so that if the fourteenth day of the Moon be Sunday, the Sunday follow­ing is Easter day.

4. That the Feast of Easter may fall upon the fifteenth day of the Moon, or upon any other day unto the twenty first, inclusively.

5. That the Paschal Sunday is discovered by [Page 327] the proper and Dominical Letter for every Year The which may be found as hath been already de­clared, or by the proper Table for that purpose. Hence it followeth,

1. That the New Moon immediately prece­ding the Feast of Easter, cannot be before the eighth day of March, for if you suppose it to be upon March 6, the Moon will be 14 days old March 19, which is before the Equinox, contra­ry to the second Rule before given, and upon the seventh day of March there is no Golden Number fixed; and therefore the Golden Number 16, which standeth against March 8, is the first by which the Paschal New Moon may be disco­vered.

2. It followeth hence, That the last Paschal New Moon cannot happen beyond the fifth day of April, because all the 19 Golden Numbers are expressed from the eighth of March to that day. And if a New Moon should happen upon the sixth of April, there would be two Paschal New Moons that year, one upon the eighth of March and a­nother upon the sixth of April, the same Golden Number 16 being proper to them both, but this is absurd because Easter cannot be observed twice in one year.

3. It followeth hence, That the Feast of Easter can never happen before the twenty second day of March, nor after the twenty fifth day of April: For if the first New Moon be upon the eighth of March, and that the Feast of Easter must be upon the Sunday following the fourteenth day of the Moon; it is plain that the fourteenth day of the Moon must be March 21 at the soonest: So that supposing the next day to be Sunday, Easter can­not [Page 228] not be before March the twenty second. And because the fourteenth day of the last Moon fal­leth upon the eighteenth day of April, if that day be Saturday, and the Dominical Letter D, Easter shall be upon the nineteenth day, but if it be Sun­day, Easter cannot be till the twenty fifth.

4. It followeth hence, That although there are but 19 days, on which the fourteenth day of the Moon can happen, as there are but 19 Golden Numbers, yet there are 35 days from the twenty second of March to the twenty fifth of April, on which the Feast of Easter may happen, because there is no day within those Limits, but may be the Sunday following the fourteenth day of the Moon. And although the Feast of Easter can ne­ver happen upon March 22, but when the four­teenth day of the Moon is upon the twenty first, and the Sunday Letter D, nor upon the twenty fifth of April, but when the fourteenth day of the Moon is upon April 18, and the Dominical Letter C. Yet Easter may fall upon March 23, not only when the fourteenth day of the Moon is upon the twenty second day which is Saturday, but also if it fall upon the twenty first which is Friday. In like manner Easter may fall upon April 24, not only when the fourteenth day of the Moon is upon the eighteenth day which is Monday, but also if it happen upon the seventeenth being Sunday. And for the same reason it may fall oftner upon other days that are further distant from the said twenty second of March and twenty fifth of April.

5. It followeth hence, That the Feast of Easter may be easily found in any Year propounded: For the Golden Number in any Year being given, if [Page 329] you look the same between the eighth of March and fifth of April both inclusively, and reckon 14 days from that day, which answereth to the Golden Number given, where your account doth end is the fourteenth day of the Moon: Then consider which is the Dominical Letter for that Year, and that which followeth next after the four­teenth day of the Moon is Easter day. Example, In the year 1674 the Golden Number is 3, and the Sunday Letter D, which being sought in the Calendar between the aforesaid limits, the four­teenth day of the Moon is upon April the thir­teenth, and the D next following is April 19. And therefore Easter day that Year is April 19. Otherwise thus.

In March after the first C,
Look the Prime wherever it be,
The third Sunday after Easter day shall be.
And if the Prime on Sunday be,
Reckon that for one of the Three.

6. Thus the Feast of Easter may be found in the Calendar, and from thence a brief Table shew­ing the same, may be extracted in this manner. Write in one Column the several Golden Num­bers in the Calendar from the eighth of March to the fifth of April, in the same order observing the same distance. In the second Column set the Dominical Letters in number 35 so disposed, as that no Dominical Letter may stand against the Golden Number 16, but setting the Letter D against the Golden Number 5, write the rest in [Page 330] this order. E, F, G, A, B, &c. and when you come to the Golden Number 8, set the Letter C, and there continue the Letters till you come to C again, because when the Golden Number is 16, which in the Calendar is set to the eighth day of March, is new Moon, and the fourteenth day of that Moon doth fall upon the twenty first, to which the Dominical Letter is C, upon which the Feast of Easter cannot happen; and therefore in the third Column containing the day in which the Feast of Easter is to be observed, is also void. But in the next place immediately following, to wit, against the letter D is set March 22, because if the fourteenth day of the Moon shall fall upon the twenty first of March being Saturday, the next day being Sunday, shall be the Feast of Easter.

To the Letters following, E, F, G, A, B, &c. are set 23, 24, 25, and so orderly to the last of March, and so forward till you come to the twen­ty fifth of April, by which Table thus made, the Feast of Easter may be found until the Calendar shall be reformed.

For having found the Golden Number in the first Column, the Dominical Letter for the Year next after it, doth shew the Feast of Easter, as in the former Example, the Golden Number is 3 and the Dominicall Letter D, therefore Easter day is upon April 19. The other moveable Feasts are thus found.

Advent Sunday is always the nearest Sunday to St. Andrews, whether before or after.

[Page 331] Septuagesima Sunday is Nine Weeks before Easter.

Sexagesima Sunday is Eight Weeks before Easter.

Qainquagesima Sunday is Seven Weeks be­fore Easter.

Quadragesima Sunday is Six Weeks before Easter.

Rogation Sunday is five Weeks after Easter.

Ascension day is Forty Days after Easter.

Whitsunday is Seven Weeks after Easter.

Trinity Sunday is Eight Weeks after Easter.

G. N.D. L.Easter.
XVI  
VD22 March
 E23
XIIIF24
IIG25
 A26
XB27
 C28
XVIIID29
VIIE30
 F31
XVG1 April
IVA2
 B3
XIIC4
ID5
 E6
IXF7
 G8
XVIIA9
VIB10
 C11
XIVD12
IIIE13
 F14
XIG15
 A16
XIXB17
VIIIC18
 D19
 E20
 F21
 G22
 A23
 B24
 C25

CHAP. IV.

Of the Reformation of the Calendar by Pope Gregory the Thirteenth; and substituting a Cycle of Epacts in the room of the Golden Number.

HItherto we have spoken of the Calendar which is in use with us, we will now shew you for what reasons it is alter'd in the Church of Rome, and how the Feast of Easter is by them observed.

The Year by the appointment of Iulius Caesar consisting of 365 days 6 hours, whereas the Sun doth finish his course in the Zodiack, in 365 days 5 hours 49 minutes or thereabouts, it cometh to pass that in 134 Years or less, there is a whole day in the Calendar more than there ought; in 268 years 2 days more; in 4002 years 3 days: and so since Iulius Caesar's time the vernal Equinox hath gone backward 13 or 14 days, namely from the 24 of March to the tenth. Now because the Equi­nox was at the time of the Nicene Council upon the twenty first of March, when the time for the ob­serving of Easter was first universally established, they thought it sufficient to bring the Equinox back to that time, by cutting off 10 days in the Calendar as hath been declared, and to prevent any anticipation for the time to come, have ap­pointed, that the Leap-year shall be thrice omit­ted in every 400 Years to come, and for memory sake, appointed the first omission to be account­ed from the Year 1600, not from 1582, in which the reformation was made, because it was not only near the time, in which the emendation was begun, but also because the Equinox has not fully made an anticipation of 10 days from the [Page 333] place thereof, at the time of the Nicene Council, which was March 21.

The Years then 1700, 1800, 1900, which should have been Bissextile Years, are to he ac­counted common years, but the Year 2000 must be a Bissextile: In like manner the Years 2100, 2200, 2300, shall be common years, and the Year 2400 Bissextile, and so forward.

2. Again, because it was supposed that the Cycle of the Moon, or Golden Number was so fixed, that the new and full Moons would in eve­ry 19 years return to the same days again; where­as their not returning the same hours, but making an anticipation of one hour 27 minutes or there­abouts, it must needs be that in 17 Cycles or lit­tle more than 300 Years, there would be an anti­cipation of a whole day. And hence it is evi­dent that in 1300 Years since the Nicene Council, the New and Full Moons do happen more than 4 days sooner than the Cycle of the Moon or Gol­den Number doth demonstrate: Whence also it comes to pass, that the fourteenth day of the Moon by the Cycle is in truth the eighteenth day, and so the Feast of Easter should be observed not from the fifteenth day of the Moon to the twenty first, but from the nineteenth to the twenty fifth.

3. That the Moon therefore being once brought into order, might not make any antici­pation for the time to come, it is appointed that a Cycle of 30 Epacts should be placed in the Ca­lendar instead of the Golden Number, answering to every day in the Year; to shew the New Moons in these days, not only for 300 Years or there­abouts, but that there might be new Epacts with­out [Page 334] altering the Calendar, to perform the same thing upon other days as need shall require.

4. For the better understanding whereof, to the Calendar in use with us, we have annexed the Gregorian Calendar also: In the first Column whereof you have 30 numbers from 1 to 30, save only that in the place of 30 you have this Asterisk *, But they begin with the Calends of Ianuary, and we continued and repeated af­ter a Retrograde order in this manner, *29, 28, 27, &c. and that for this cause especially, that the number being given which sheweth the New Moons in every Month for one Year, you might by numbring 11 upwards exclusively find the number which will shew the New Moons the Year following, to wit, the Number which fal­leth in the eleventh place.

5. And these Numbers are called Epacts, be­cause they do in order shew those 11 days, which are yearly to be added to the Lunar Year consist­ing of 354 days, that it may be in conformity with the Solar Year consisting of 365 days. To this purpose, as hath been said concerning the Golden Number, these Epacts being repeated 12 times, and ending upon the twentieth day of De­cember, the same Numbers must be added to the 11 remaining days, which were added to the first 11 days in the Month of Ianuary.

6. And because 12 times 30 do make 360, whereas from the first of Ianuary to the twentieth of December inclusively, there are but 354 days, you must know that to gain the other six days, the numbers 25 and 24 are in every other Month both placed against one day, namely, to February 5, April 5, Iune 3, August 1, September 29, and [Page 335] November 27. But why these two Numbers are chosen rather then any other, and why in these 6 Months the number 25 is sometimes writ to XVI, sometimes to XXV in a common character, and why the number 19 is set to the last day of De­cember in a common Character, shall be declared hereafter.

7. Here only note that this Asterisk * is set in­stead of the Epact 30, because the Epact shew­ing the Number of days which do remain after the Lunation in the Month of December, it may some­times fall out that 2 Lunations may so end, that the one may require 30 for the Epact, and the other 0, which would, if both were written, cause some inconveniences, and therefore this * Aste­risk is there set, that it might indifferently serve to both. And the Epact 29 is therefore set to the second day of Ianuary, because after the com­pleat Lunation in the second of December there are 29 days, and for the like reason the Epact 28 is set against the third of Ianuary, because after the compleat Lunation in the third of December there are then 28 days over, and so the rest in order till you come to the thirtieth of Ianuary, where you find the Epact 1. because after the compleat Lunation on the thirtieth day there is only one day over.

8. And besides the shewing of the New Moons in every Month, which is and may be done by the Golden Number, the Epacts have this advan­tage, that they may be perpetual and keep the same place in the Calendar in all future ages, which can hardly be effected with the Golden Number, for in little more then 700 years, the New Moons do make an anticipation of one day, and then it [Page 336] will be necessary to set the Golden Number one degree backward, and so the Golden Number which at the time of the Nicene Council was set to the first of Ianuary, should in 300 years be set to the last of December, and so of the rest, but the Epacts being once fixed shall not need any such retraction or commutation. For as often as the New Moons do change their day either by Anticipation or by Suppression of the Bissextile year, you shall not need to do any more than to take another rank of 19 Epacts, insteed of those which were before in use. For instance, the Epacts which are and have been in use in the Church of Rome since the year of reformation 1582, and will continue till the year 1700, are these 10 fol­lowing 1. 12. 23. 4. 15. 26. 7. 18. 29. 10. 21. 2. 13. 24. 5. 16. 27. 8. 19. And from the year 1700 the Epacts which will be in use are these. * 11. 22. 3. 14. 25. 6. 17. 28. 9. 20. 1. 12. 23. 4. 15. 26. 7. 18. and shall con­tinue not only to the year 1800, but from thence until the year 1900 also; and although in the year 1800 the Bissextile is to be suppressed, yet is there a compensation for that Suppression, by the Moons Anticipation. To make this a little more plain, the motion of the Moon, which doth occasion the change of the Epact, must be more fully considered.

CHAP. V.

Of the Moons mean Motion, and how the Antici­pation of the New Moons may be discovered by the Epacts.

THe Moon according to her middle motion doth finish her course in the Zodiack in 29 days, 12 hours 44 minutes, three seconds or there­about, and therefore a common Lunar year doth consist of 354 days, 8 hours, 48 minutes, 38 seconds and some few thirds, but an Embolismi­cal year doth consist of 383 days, 21 hours, 32 minutes, 41 seconds and somewhat more; and therefore in 19 years it doth exceed the motion of the Sun 1 hour, 27 minutes, 33 seconds feré.

2. Hence it cometh to pass, that although the New Moons do after 19 years return to the same days; yet is there an Anticipation of 1 hour, 27 minutes, 33 seconds. And in twice 19 years, that is, in 38 years, there is an Anticipation of 2 hours, 55 minutes, 6 seconds, and after 312 years and a half, there is an Anticipation of one whole day and some few Minutes. And therefore after 312 years no new Moon can happen upon the same day it did 19 years before, but a day sooner. Hence it comes to pass that in the Julian Calen­dar, in which no regard is had to this Anticipa­tion, the New Moons found out by the Golden Number must needs be erroneous, and from the time of the Nicene Council 4 days after the New Moons by a regular Computation.

3. And hence it follows also, that if the Gol­den Number, after 312 were upon due conside­ration [Page 338] removed a day forwarder or nearer the be­ginning of the Months, they would shew the New Moons for 312 years to come. And being again removed after those years, a day more would by the like reason do the same again. But it was thought more convenient so to dispose 30 Epacts, that they keeping their constant places, 19 of them should perform the work of the Gol­den Number, until by this means there should be an Anticipation of one day. And when such an Anticipation should happen, those 19 Epacts be­ing let alone, other 19 should be used, which do belong to the preceding day, without making any alteration in the Calendar.

4. And if this Anticipation would do the whole work, nothing were more plain, then to make that commutation of the 19 Epact once in 312 years: but because the detraction of the Bissex­tile days doth variously interpose and cause the 19 Epacts sometimes to be changed into these that do precede, sometimes into these that follow, sometimes into neither, but to continue still the same; therefore some Tables are to be made, by which we may know, when the commutation was to be made and into what Epacts.

4. First therefore there was made a Table cal­led Tabula Epactarum Expansa, in this manner.

First on the top were placed the 19 Golden Numbers in order, beginning with the Number 3, which in the old Calendar is placed against the Calends of Ianuary, and under every one of these Golden Numbers there are placed 30 Epacts all constituted from the lowest number in the first rank in which the Epact is 1, and in that first rank the Golden Number is 3, the rest from [Page 339] thence towards the right Hand are made by the constant addition of it, and the casting away of 30, as often as they shall exceed that number, only when you come to the 27, the Epact under the Golden Number 19, there must be added 12 instead of 11, that so the Epact following may be 9 not 8, for the Reasons already given in this Discourse concerning the Golden Number and Embolismical years. And this rank being thus made, the other Epacts are disposed in their na­tural order ascending upwards, and the number once again resumed after the Epact 30 or rather this Asterisk * set in the place thereof: only ob­serve that under the Golden Number 12. 13. 14. 15. 16. 17. 18. 19. in the place of XX there is yet 25 in the common Character. And to the Epacts under the Golden Number 19, 12 must still be added to make that Epact under the Golden Number 1. As was said before concern­ing the lowest Rank.

5. And on the left hand of these Epacts before those under the Golden Number 3. are set 30 Letters of the Alphabet, 19 in a small Character, and 11 in a great, in which some are passed by, for no other reason save only this, that their simili­tude with some of the small Letters, should not occasion any mistake in their use, which shall be shewed in its place.

6. Besides this Table there was another Table made which is called Tabula AEquationis Epacta­rum, in which there is a series of years, in which the Moon, by reason of her mentioned anticipa­tion doth need AEquation, and in which the num­ber of Epacts signed with the letters of the Al­phabet, are to be changed; being otherwise AE­quated [Page 340] where it needeth, by the suppression of the Bissextile days.

7. But it supposeth, that it was convenient to suppress the Bissextiles once only in 100 years; and the Moon to be aequated, or as far as concerns her self, the rank of Epacts to be changed, once only in 300 years, and the 12 years and a half more, to be referred till after the years 2400, they do amount unto 100 years, and then an ae­quation to be made: but then it must be made by reason of the interposing this hundred not in the three hundredth but the hundredth year. Moreover this aequation is to be made as in refe­rece to the Moon only, because as the suppression of the Bissextiles intervene, the order of chang­ing the ranks of Epacts is varied, as shall be shewed hereafter.

8. Again this Table supposeth, that seeing the New Moon at the time of the Nicene Council was upon the Calends of Ianuary, the golden Number 3 being there placed, that it would have been the same if the Epact * had been set to the same Calends, that is if the Epacts had been then in use. And therefore at that time the highest or last rank of Epacts was to be used, whose Index is P, and then after 300 years, the lowest or first rank should succeed, whose Index is a, (for the letters return in a Circle) and af­ter 300 years more, the following rank whose Index is b and so forward; but that it is concei­ved, that the New Moon in the Calends of Ia­nuary, is more agreeable to the year of Christ 500, than the time of the Nicene Councel; and therefore as if the rank of Epacts under the let­ter l were sutable to the year 500, it seemed [Page 341] good to make use of that rank under the letter a in the year of Christ 800, and those under the let­ter b, in the year 1100, and those under the let­ter e in the year 1400.

9. Which being granted, because in the year 1582, ten days were cut off from the Calendar, we must run backward, or in an inverted order count 10 series, designed, suppose, by the letters b. a. P. N. M. H. G. F. E. D. so that from the year 1582 the series of Epacts whose literal Index is D, is to be used, and this is that rank of Epacts which is now used in the Church of Rome.

10. And therefore as if this Table had its be­ginning from that year; the first number in the second column is 1582, and then in order un­der it. 1600. 1700. 1800. 1900. 2000. &c. And in the third Column every fourth hundred year is marked for a Bissextile, that is, 1600. 2400. 2800, &c. and in the fourth Column to eve­ry three hundreth▪ Year is set this Character C, to shew in what year the Moon by her Anticipati­on of one day, doth need aequation; but in the year 1800 the double character is set CC, to sig­nify that then another hundred years are got­ten by the 12 years and a half reserved, besides and above the other 300 years; and this charact­er is also set to the years 4300. 6800, and for the same reason.

But in the first Column, or on the left hand of these years are placed the Letters or Indices of those ranks of Epacts in the former Table, which are to be used in those years and when the Let­ters are charged. Thus against the year 1600 the Letter D is continued, to shew that from that [Page 342] year, to the year 1700 the rank of Epacts is still to be used, which do belong to that Letter. And for as much as the Letter C is set to the year 1700, it sheweth that that rank of Epacts is then to be used, which do belong thereto, and so of the rest.

11. The reason why these Letters in the first Column are sometimes changed in 100 years, sometimes in 200, sometimes not in less then 300 Years, and that they are some­times taken forward, sometimes backward, according to the order of the Alphabet, is because the suppression of the Bissextiles do intervene with the lunar aequation: for if the Bissextile were only to be suppressed, in these 300 or sometimes 400 years, in which the Moon needeth aequation, the rank of Epacts in that case would need no commutation, but would continue the same for ever; and the gol­den Number would have been sufficient, if the suppression of the Bissextile, and anticipation of the Moon, did by a perpetual compensati­on cause the new Moons still to return to the same days: but because the Bissextile is ofttimes suppressed, when the Moon hath no aequation, the Moon hath sometimes an aequation when the Bis­sextile is not suppressed, sometimes also both are to be done and sometimes neither; all which varieties may yet be reduced to these three Rules.

1. As often as the Bissextile is suppressed without any aequation of the Moon, then the let­ter which served to that time shall be changed to the next below it contrary to the order of the Alphabet. And the new Moons shall be removed [Page 343] one day towards the end of the Year.

2. As often as the Moon needeth aequation, without suppression of the Bissextile, then the Letter which was in use to that time shall be chan­ged to the next above it according to the order of the Alphabet, that the New Moons may a­gain return one day towards the beginning of the year.

3. As often as there is a Suppression and an aequation both, or when there is neither, the Letter is not changed at all but that which ser­ved for the former Centenary, shall also conti­nue in the succeeding; because the compensation so made, the New Moons do neither go for­ward nor backward, but happen in the compass of the same days.

1. And this is enough to shew for what rea­son the letters are so placed in the Table, as there you see them: for in the year 1600 the Bissextile being neither suppressed, nor the Moon aequated, the letter D used in the former Cen­tenary or in the latter part thereof from the year 1582, is still the same.

In the year 1700, because there is a suppressi­on, but no aequation, the commutation is made to the Letter C descending.

In the Year 1800, because there is both a sup­pression and an aequation, the same letter C doth still continue.

In the Year 2400, because there is an aequation and no suppression, there is an ascension to the Letter A.

And thus you see not only the construction of this Table, but how it may be continued to any other Year, as long as the World shall last.

[Page 344] 12. And by these two Tables we may easily know which rank of the 30 Epacts doth belong to, or is proper for any particular age: for as in our age, that is, from the Year 1600 to the Year 1700 exclusively, that series is proper whose Index is D. Namely, 23, 4, 15, 26, &c. so in the two Ages following, that is, from the Year 1700 to the Year 1900 exclusively, that series is proper whose In­dex is C, namely these, 22, 3, 14, 25. and in the three ages following thence, that is from the Year 1900 to the Year 2100 exclusively, that series is proper whose Index is B, namely these, 21, 2, 13, 24, &c. And so for any other.

Hence also it may be known, which of the 19 doth belong to any particular Year, for which no more is necessary, than only to know the Gol­den Number for the year given, which being sought in the head of the Table, and the Index of that Age in the side, the common Angle, or meeting of these two, will shew you the Epact desired: As in the year 1674 the Golden Number is 3 and the Index D; therefore in the common Angle I find 23 for the Epact that year, and shew­eth the New Moons in every Month thereof.

And here it will not be unseasonable to give the reason, for which the Epact 25 not XXV is writ­ten under the Golden Numbers 12, 13, 14, 15, 16, 17, 18, 19. namely, because the ranks of E­pacts, which under these greater Numbers hath this Epact 25, hath also XXIV, it would follow that in these Ages in which any of these Ranks were in use, the New Moon in 19 years will hap­pen twice upon the same days; in those six Months in which the Epacts XXV and XXIV are set to the same day: Whereas the New Moons do not hap­pen [Page 245] on the same day till 19 years be gone about. To avoid this inconvenience, the Epact 25 not XXV is set under these great numbers, and the Epact 25 is in the Calendar, in these Months set with the Epact XXVI, but in the other Months with the Epact XXV.

14. Hence it cometh to pass, 1. That in these Years the Epacts 25 and XXIV do never meet on the same day. 2. That there is no danger that the Epacts 25 and XXVI should in these 6 Months cause the same inconvenience, seeing that the E­pacts 25 and XXVI are never both found in the same Rank. 3. That the Epact 25 may in other Months without inconvenience be set to the same day with the Epact XXVI, because in these there is no danger of their meeting with the Epact XXIV on the same days. 4. That there is no fear that the Epacts XXV and XXIV being set on the same days, should in future Ages cause the same inconvenience, because the Epacts XXV and XXIV are not found together in any of the other Ranks. But that either one or both of them are wanting. Besides, when one of these Epacts is in use, the o­ther is not, and that only which is in use is pro­per to the day. As in this our Age until the Year 1700 the Epacts in use are those in the rank whose Index is D. In which these two XXIV and XXV are not both found. And in the two following Ages, because the rank of Epacts in use is that whose Index is C, in which there is the Epact XXV, not XXIV, the New Moons are shewed by the Epact XXV not by XXIV. But because in three following Ages, the rank of Epacts in use is that whose Index is B, in which 25 and XXIV are both found, the New [Page 346] Moons are shewed by the Epact XXIV when the golden Number is 6. And by the Epact 25 when the golden Number is 17, and not by the Epact XXV.

15. And if it be asked why the Epact 19 in the common Character is set with the Epact XX against the last day of December; know that for the reasons before declared, the last Embo­lismical Month within the space of 19 years, ought to be but 29 days and not 30, as the rest are; and therefore when the Epact 19 doth concur with the golden Number 19, the last Month or last Lunation beginning the second of December, shall end upon the 30 and not up­on the 31 of that Month, and the New Moon should be supposed to happen upon the 31 un­der the same Epact 19, that 12 being added to 19 and not 11, you may have one for the Epact of the year following, which may be found up­on the 30 of Ianuary, as if the Lunation of 30 days had been accomplished the Day be­fore.

CHAP. VI.

How to find the Dominical Letter and Feast of Easter according to the Gregorian account.

HAving shewed for what reason, and in what manner the Epacts are substituted in the place of the golden Number, and how the New Moons may be by them found in the Calendar for ever; I shall now shew you how to find the Feast of Easter and the other moveable [Page 347] Feasts according to the Gregorian or new ac­count; and to this purpose I must first shew you how to find the Dominical Letter, for that the Cycle of 28 years will not serve the turn, be­cause of the suppression of the Bissextile once in a hundred years, but doth require 7 Cycles of 28 years apeice. The first whereof begins with CB, and endeth in D. The second begins with DC, and endeth in E. The third begins with ED, and endeth in F &c. The first of these Cycles began to be in use 1582, in which year the dominical Letter according to the Julian ac­count was G, but upon the fifteenth day of October, that Year was changed to C: for the fifth of October being Friday and then called the fifteenth, the Letter A became Friday, B Satur­day, and C Sunday, the remaining part of the year, in which the Cycle of the Sun was 23, and the second after the Bissextile or leap Year, and so making C, which answereth to the fifteenth year of that Circle, to be 23, the Circle will end at D; and consequently CB, which in the old account doth belong to the 21 year of the Circle, hath ever since been called the first, and so shall continue until the year 1700, in which the Bissextile being suppressed, the next Cycle will begin with DC as hath been said already. Under the first rank or order of Dominical Letters are written the years 1582 and 1600, under the se­cond 1700, under the third 1800, under the fourth 1900 and 2000, under the fifth 2100, un­der the sixth 2200 and under the seventh 2300 and 2400. And again under the first Order, 2500, under the second 2600, under the third 2700 and 2800, and so forward as far as you [Page 348] please, always observing the same order, that the 100 Bissextile years may still be joyned with the not Bissextile immediately preceding.

1. And hence it appears, that the seven or­ders of Dominical Letters, are so many Tables, successively serving all future Generations. For as the first Order serveth from the year 1582 and 1600 to the year 1700 exclusively, and the second Order from thence to the year 1800 ex­clusively, so shall all the rest in like manner which here are set down, and to be set down at plea­sure. And hence the Dominical Letter or Let­ters may be found for any year propounded, as if it were required to find the dominical Letter for the year 1674, because the year given is contained in the centenary 1600. I find the Cycle of the Sun by the Rule already given to be 3. In the first order against the number 3, I find G for the Sunday Letter of that year, in like manner because the year 1750 is contained under the Centenary 1700, the Cycle of the Sun being 27, I find in the second rank the Let­ter D answering to that Number, and that is the Dominical Letter for that year, and so of the rest.

3. Again for as much as the fifth Order is the same with that Table, which serves for the old account, therefore that order will serve the turn for ever where that Calendar is in use, and so this last will be of perpetual use to both the Calendars.

4. Now then to find the time in which the Feast of Easter is to be observed, there is but little to be added to that which hath been already said concerning the Julian Calendar. For the Pas­chal [Page 349] Limits are the same in both, the difference is only in the Epacts, which here are used in­stead of the golden Number.

5. For the terms of the Paschal New Moons are always the eighth of March and the fifth of April: but whereas there are 11 days within these Limits to which no golden Number is affixed, there is now one day to which an Epact is not appointed, because there is no day within those Limits, on which in process of time a New Moon may not happen. And the reason for which the two Epacts XXV and XXIV are both set to the fifth of April, is first general, which was shew­ed before, namly that by doing the same in 5 other Months, the 12 time 30 Epacts might be contracted to the Limits of the lunar Year which consists of 354 days: but there is a particular rea­son also for it, that the Antients having appointed that all the Paschal lunations should consist of 29 days, it was necessary that some two of the E­pacts should be set to one of these days in which the Paschal lunation might happen, the Epacts being 30 in number. And it was thought con­venient to choose the last day, to which the E­pact XXV belonging, the Epact XXIV should also be set; and hence by imitation it comes to pass, that these and not other Epacts are set to that day in other Months, in which two Epacts are to be set to the same days.

6. The use of these Epacts in finding the Feast of Easter, is the same with that which hath been shewed concerning the golden Numbers. For the Epact and the Sunday Letter for that year propounded being given, the Feast of Easter may be found in the Calendar after the same [Page 350] manner. Thus in the year 1674, the Epact is 23 and the Sunday Letter G, and therefore reck­oning fourteen days from the eighth of March to which the Epact is set, the Sunday following is March 25, which is the day on which the Feast of Easter is observed.

7. And hence as hath been shewed in the third Chapter concerning the Julian Calendar, a brief table may be made to shew the feast of Easter and the other moveable Feasts for ever, in which there is no other difference, save only that the Epacts as they are in this new Calendar, are to be used as the golden Numbers are, which stand in the old Calendar. And a Table having the golden Numbers of the old Calendar set in one Column, and the Epacts as they are in the new Calendar set in another, will indifferently shew the movable Feasts in both accounts, as in the Year 1674, the golden Number is 3 and the Sunday Letter according to the Julian ac­count is D, according to the Gregorian G, and the Epact 23, and therefore according to this Table our Easter is April 19, and the other, to wit, the Gregorian, is March 25. The like may be done for any other year past or to come.

CHAP. VII.

How to reduce Sexagenary numbers into Decimal, and the Contrary.

EVery Circle hath antiently, and is yet ge­nerally supposed to be divided into 300 de­grees, each degree into 60 Minutes, each Mi­nute into 60 Seconds, and so forward as far as need shall require. But this partition is some­what troublesom in Addition and Subtraction, much more in Multiplication and Division; and the Tables hitherto contrived to ease that man­ner of computation, do scarce sufficiently per­form the work, for which they are intended. And although the Canon published by the lear­ned H. Gellibrand, in which the Division of the Circle into 360 degrees is retained, but every degree is divided into 100 parts, is much bet­ter than the old Sexagenary Canon, yet some are of opinion, that if the Antients had divided the whole circle into 100 or 1000 parts, it would have proved much better then either; only they think Custome such a Tyrant, that the alteration of it now will not be perhaps so advantagious; leaving them therefore to injoy their own opinions, they will not I hope be of­fended if others be of another mind: for their sakes therefore, that do rather like the Deci­mal way of calculation▪ Having made a Canon of artificial Signs and Tangents for the degrees and parts of a Circle divided into 100 parts, I shall here also shew you, how to reduce sexa­genary Numbers into Decimal, and the contra­ry, [Page 352] as well in time as motion.

2. The parts of a Circle consisting of 360 degrees, may be reduced into the parts of a cir­cle divided into 100 degrees or parts, by the rule of Three in this manner.

As 360 is to 100, so is any other Number of degrees, in the one, to the correspondent de­grees and parts in the other.

But if the sexagenary degrees have Minutes and Seconds joyned with them, you must reduce the whole Circle as well as the parts propoun­ded into the least Denomination, and so proceed according to the rule given.

Example. Let it be required to convert 125 degrees of the Sexagenary Circle, into their correspondent parts in the Decimal. I say, as 360 is to 100, so is 125 to 34, 722222, &c. that is, 34 degrees and 722222 Parts.

2. Example. Let the Decimal of 238 de­grees 47 Minutes be required. In a whole Cir­cle there are 21600 Minutes, and in 238 de­grees, there are 14280 Minutes, to which 47 being added the sum is 14327. Now then I say if 21600 give 100, what shall 14327. The Answ. is 66, 3287 &c. In like manner if it were required to convert the Hours and Minutes of a Day into decimal Parts, say thus, if 24 Hours give 100, what shall any other number of Hours give. Thus if the Decimal of 18 hours were required, the answer would be 75, and the De­cimal answering to 16 Hours 30 Minutes is 68, 75.

But if it be required to convert the Decimal Parts of a Circle into its correspondent Parts in Sexagenary. The proportion is; as 100 is [Page 353] to the Decimal given, so is 360 to the Sexage­nary degrees and parts required.

Example. Let the Decimal given be 349 722222, if you multiply this Number given by 360, the Product will be 1249999992, that is cutting off 7 Figures, 124 degrees and 9999992 parts of a degree. If Minutes be required, mul­tiply the Decimal parts by 60, and from the product cut off as many Figures, as were in the Decimal parts given, the rest shall be the Mi­nutes desired.

But to avoid this trouble, I have here exhi­bited two Tables, the one for converting sex­agenary degrees and Minutes into Decimals, and the contrary. The other for converting Hours and Minutes into Decimals, and the con­trary. The use of which Tables I will explain by example.

Let it be required to convert 258 degrees 34′. 47″, into the parts of a Circle decimally divi­ded.

The Table for this purpose doth consist of two Leaves, the first Leaf is divided into 21 Columns, of which the 1. 3. 5. 7. 9. 11. 13. 15. 17. 19 doth contain the degrees in a sexagenary Circle, the 2. 4. 6. 8. 10. 12. 14. 16. 18 and 20 doth contain the degrees of a Circle Decimally divided, answering to the for­mer, and the last Column doth contain the De­cimal parts, to be annexed to the Decimal de­grees. Thus the Decimal degrees answering to 26 Sexagenary are 7, and the parts in the last Column are 22222222 and therefore the de­grees and parts answering to 26 Sexagenary de­grees are 7. 22222222.

[Page 354] In like manner the Decimal of 62 degrees, 17. 22222222. And the Decimal of 258 de­grees, 34′. 47″, is thus found.

The Decimal of 258 degrees is
71.66666666
The Decimal of 34 Minutes is
.15747040
The Decimal of 47 seconds is
.00362652
Their Sum
71.82776358

is the Decimal of 258 degrees, 34′. 47″ as was required.

In like mauner the Decimal of any Hours and Minutes may be found by the Table for that purpose.

Example. Let the Decimal of 7 Hours 28′ be required.

The Decimal answering to 7h. is
29.16666667
The Decimal of 28 Minutes is
1.94444444
The Sum
31.11111111

is the Decimal Sought.

To find the degrees and Minutes in a sexage­nary Circle, answering to the degrees and parts of a Circle Decimally divided, is but the contra­ry work.

As if it were required to find the Degrees and minutes answering to this decimal 71. 02776359, the Degrees or Integers being sought in the 2. 4. 6 or 8 Columns &c. of the first Leaf of that Table, right against 71. I find 256 and in the last Column these parts 11111111, which being less than the Decimal given, I proceed [Page 355] till I come to 6666667, which being the nea­rest to my number given, I find against these parts under 71. Degrees 258, so then 258 are the de­grees answering to the Decimal given and,

To find the Minutes and Seconds from
71.82776359
I Substract the num­ber in the Table
71.66666667
The remainer is
16109692
which being Sought in the next Leaf under the title Minutes, the next leaf is
11747640
And the Minutes 34, and this number being Subtracted the remainer is
00362652

Which is the Decimal of 47 seconds, and so the degrees and Minutes answering to the De­cimal given are 258 degrees 34′ and 47″, the like may be done for any other.

CHAP. VIII.

Of the difference of Meridiens.

HAving in the first part shewed how the pla­ces of the Planets in the Zodiack may be found by observation, and how to reduce the time of an observation made in one Country, to the correspondent time in another, as to the day of the Month, by considering the several [Page 356] measures of the year in several Nations, there is yet onething wanting, which is, by an obser­vation made of a Planets place in one Country to find when the Planet is in that place in refe­rence to another; as suppose the ☉ by observa­tion was found at Vraniburg to be in ♈. 3d. 13′. 14″. March the fourteenth 1583 at what time was the Sun in the same place at London? To re­solve this and the like questions, the Longitude of places from some certain Meridian must be known; to which purpose I have here exhibi­ted a Table shewing the difference of Meridians in Hours and Minutes, of most of the eminent places in England from the City of London, and of some places beyond the Seas also. The use whereof is either to reduce the time given under the Meridian of London to some other Meridi­an, or the time given in some other Meridian to the Meridian of London.

1. If it be required to reduce the time given under the Meridian of London to some other Meridian, seek the place desired in the Catalogue, and the difference of time there found, either add to or subtract from the times given at Lon­don, according as the Titles of Addition or Sub­traction shew, so will the time be reduced to the Meridian of the other place as was required. Example. The same place at London was in the first Point of ♉, 6 Hours P. M. and it is required to reduce the same to the Meridian of Vraniburg I therefore seek in Vraniburg in the Catalogue of places, against which I find 50′ with the Letter A annexed, therefore I conclude, that the Sun was that day at Vraniburg in the first point of ♉, 6 Hours 50′. P. M.

[Page 357] 2. If the time given be under some other Me­ridian, and it be required to reduce the same to the Meridian of London, you must seek the place given in the Catalogue, and the difference of time there found, contrary to the Title is to be added or subtracted from the time there gi­ven.

Example. Suppose the place of the Sun had been at Vraniburg, at 6 Hours 50′. P. M. and I would reduce the same to the Meridian of Lon­don; against Vraniburg as before I find 50′ A. therefore contrary to the Title I Subtract 50′ and the remainder 6 Hours is the time of the Suns place in the Meridian of London.

CHAP. IX.

Of the Theory of the Sun's or Earth's Motion.

IN the first part of this Treatise we have spok­en of the primary Motion of the Planets and Stars, as they are wheeled about in their di­urnal motion from East to West, but here we are to shew their own proper motions in their several Orbs from West to East, which we call their second motions.

1. And these Orbs are supposed to be Ellip­tical, as the ingenious Repler, by the help of Tycho's accurate observations, hath demonstra­ted in the Motions of Mars and Mercury, and may therefore be conceived to be the Figure in which the rest do move.

2. Here then we are to consider what an El­lipsis is, how it may be drawn, and by what Me­thod [Page 358] the motions of the Planets according to that Figure may be computed.

3. What an Ellipsis is Apollonius Pergaeus in Conicis, Claudius Mydorgius and others have well defined and explained, but here I think it suffici­ent to tell the Reader, that it is a long Circle, or a circular Line drawn within or without a long Square; or a circular Line drawn between two Circles of different Diameters.

4. The usual and Mechanical way of drawing this Ellipsis is thus; first draw a line to that length which you would have the greatest Diameter to be, as the Line AP in Figure 8, and from the middle of this Line at X, set off with your com­passes the Equal distance XM and XH.

5. Then take a piece of thred of the same length with the Diameter AP and fasten one end thereof in the point M and the other in the point H, and with your Pen extend the thred thus fastened to the point A, and from thence towards P keeping the thread stiff upon your Pen, draw a line from A by B to P, the line so drawn shall be half an Ellipsis, and in like manner you may draw the other half from P by D to A. In which because the whole thred is equal to the Diameter AP. therefore the two Lines made by thred in drawing of the Ellipsis, must in every point of the said Ellipsis be also e­qual to the same Diameter AP. They that de­sire a demonstration thereof geometrically, may consult Apollonius Pergaeus, Claudius Mydorgius or others, in their treatises of Conical Sections, this is sufficient for our present purpose, and from the equality of these two Lines with the Diameter, a brief Method of calculation of the [Page 359] Planets place in an Ellipsis, is thus Demonstra­ted by Dr. Ward now Bishop of Salisbury.

6. In this Ellipsis H denotes the place of the Suns Center, to which the true motion of the Planet is referred, M the other Focus whereun­to the equal or middle motion is numbred, A the Aphelion where the Planet is farthest distant from the Sun and slowest in motion, P the Pe­rihelion where the Planet is nearest the Sun and slowest in motion. In the points A and P the Line of the mean and true motion do convene, and therefore in either of these places the Pla­net is from P in aequality, but in all other points the mean and true motion differ, and in D and C is the greatest elliptick AEquation.

8. Now suppose the Planet in B, the line of the middle motion according to this Figure is MB, the line of the true motion HB. The mean Anomaly AMB. The Eliptick aequati­on or Prosthaphaeresis MBH, which in this Exam­ple subtracted from AMB, the remainer AHB is the true Anomaly. And here note that in the right lined Triangle MBH, the side MH is al­ways the same, being the distance of the Foci, the other two sides MB and HB are together equal to AP. Now then if you continue the side MB till BE be equal to BH and draw the line HE, in the right lined Triangle MEH, we have given ME=AD and MH with the Angle EMH, to find the Angles MEH and MHE which in this case are equal, because EB=BH by Contraction, and therefore the double of BEH or BHE=MBH, which is the Angle required.

And that which yet remaineth to be done, is [Page 360] the finding the place of the Aphelion, the true Excentricity or distance of the umbilique points, and the stating of the Planets middle motion.

CHAP. X.

Of the finding of the Suns Apogeon, quantity of Excentricity aend middle motion.

THe place of the Suns Apogaeon and quantity of Excentricity may from the observati­ons of our countrey man Mr. Edward Wright be obtained in this manner, in the years 1596, and 1497, the Suns entrance into ♈ and ♎ and into the midst of ♉. ♌. ♍. and ♒ were as in the Table following expressed.

 15961597 
 D. H. M.D. H. M. 
Ianuary.25. 00.0724. 05.54♒. 15
March.9. 18.4310. 00.37♈. 0
April.24. 21.4725. 03.54♉. 15
Iuly.28. 01.4328. 09.56♌. 15
September.12. 13.4812. 19.15♎. 0
October.27. 15.2327. 21.50♍. 15

And hence the Suns continuance in the Nor­thern Semicircle from ♈ to ♎ in the year 1596 being Leap year, was thus found.

 
d. h.
From the 1. of Ianuary to ☉ Entrance ♎.
256. 13. 48.
From the 1. of Iun to ☉ Entrance ♈
69. 18.43
Their difference.
186. 19.05

In the year 1597 from the 1 of Ianuary to the time of the ☉ Entrance into ♎.
255. 19.15
To the ☉ entrance into ♈.
69. 09.37
Their difference is
186. 18.38

And the difference of the Suns continuance in these Arks in the year 1596 and 1597 is 27′. and therefore the mean time of his continuance in those Arks is days 186. hours 18. minutes 51. se­conds 30. And by consequence his continuance in the Southern Semicircle that is from ♎ to ♈ is 178 days. 11 hours, 8 minutes and 30 se­conds.

In like manner in the year 1596 between his entrance into ♉ 15. and ♍ 15, there are days
185. 17.36
And in the year 1597 there are days
185. 17.56

And to find the middle motion answering to days 186. hours 18. Minutes 51. seconds 30 I say.

As 365 days, 6 hours, the length of the Julian, year is to 360, the degrees in a Circle.

So is 186 days, 18 hours, 51′. 30″ to 184 degrees. 03′. 56″.

In like manner the mean motion answering [Page 362] to 185 days, 17h. 46′ is 183 degrees, 02′.09.

Apparent motion from ♈ to ♎
180. 00.00
Middle motion
184. 03.56
Their Sum
364. 03.56
Half Sum is the Arch. SME
182. 01.58

In 1596 from 15 ♒ to 15 ♌ there are days 185, hours 01, minutes 36. In 1597. days 135. hours 4. 02′.

And the mean motion answering thereunto is. 182d. 30′. 36″.

Apparent motion from
15 ♉ to 15 ♍. 180.
Middle motion
185. 17. 56. 181. 04.53
Half Sum is
183. 32. 26

From 15 ♒ to 15 ♌ Days. 185. 04h. 02′

Apparent motion
180.
Middle motion
182. 30. 36
Half Sum
181. 15. 18

Now then in Fig. from PGC. 181. 32. 26 deduct NKD 180, the Remainer is DC+NP. 1. 32. 26. Therefore DC or NP. 46. 13, whose Sine is HA.

And from XPG. 181. 15. 18 deduct TNK 180, the Remainer is KG+TX 1. 15. 18. Therefore KG or TX 37. 39, whose Sine is HR.

[Page 363]

Now then to find the Apogaeon.
As HA 46′.13″
5.12851105
To Rad. So HR 37′.39″
15.03948202
To Tang. HAR. 39d.10′.04″
9.91097097
GAM.
45
Apogaeon
95. 49. 56.

Hence to find the excentricity AR.
As the Sine HAR. 39. 10.04
9.80043756
To Rad. So HR. 37.39
15.03948202
To RA. 1733.99
5.23904446
Or thus,

In the Triangle [...] we have given [...]. and [...].

As [...]. 37.39
5.03948202
To Rad. So [...]. 46. 13.
15.12851105
To Tang. R [...]. 50. 49.56
10.08902903
PAS.
45.

Apogaeon 95 deg. 49′. 56″. as before.

Then for the Excentricity RA.
As the Sine of R [...]. 50. 49. 56
9.88945938
Is to [...]. 46′.13″
5.12851105
So is Radius. To RA.1734.01
5.23905167

And this agreeth with the excentricity, used [Page 364] by Mr. Street in his Astron. Carolina, Pag. 23. But Mr. Wing as well by observation in former ages, as our own, in his Astron. Instaur. Pag. 39. doth find it to be 1788 or 1791. The work by both observations as followeth.

2. And first in the time of Ptolemy, Anno Christi 139 by comparing many observations to­gether, he sets down for the measure nearest truth, the interval between the vernal Equinox and the Tropick of Cancer to be days 93. hours 23. and minutes 03. And from the Vernal to the Autumnal Equinox, days 186. hours 13. and minutes 5.

 
D.
The apparent motion from ♈ to ♎
90. 36.00
Middle motion for 93d. 23h. 3′. is
92. 36.42
The half Sum is GP
91. 18.21

Apparent motion from ♈ to ♎
180. 00.00
Middle motion for 186d. 13h. 5′. is
183. 52.03
The half Sum is GEK
181. 56.02

The half of GEK is GE.
90. 58.01
And GP less GE is
00. 20.20
Whose Sum is AC 59146.
 

Again from GEK 181. 56. 02. deduct the Semicircle FED 180. the remainer is the summ DK and FG. 1. 56. 2. and therefore DK=FG. 58′. 01″. whose sign is BC. 168755. L is the place of the Aphelion, and AB the Excentricity.

Now then in the Triangle ABC. in the Fig. 6 we have given the two sides AC and BC. To find the Angle BAC and the Hypotenuse AB. [Page 365] For which the proportions are.

As the side AC. 59146
4.77192538
Is to the Radius.
10.00000000
So is the side BC▪ 168755
5.22725665
To Tang. BAC. 70. 41. 10.
10.45533127

Secondly for AB.
As the Sine of BAC. 70. 41. 10.
9.97484352
Is to the side AB. 168755.
5.22725665
So is the Radius.
10.00000000
To the Hypot. AB. 1788. 10.
5.25241313

Therefore the Aphelion at that time was in II 10. 41. 10. And the excentricity. 1788.

3. Again Anno Christi 1652 the Suns place by observation was found to be as followeth.

April. 24.hours. 10.♉. 15
October. 27.hours. 7. 10′♍. 15
Ianuary. 24.hours. 11.20′♒. 15
Iuly. 27.hours. 16.30,♌. 15

Hence it appeareth that the Sun is running through one Semicircle of the Ecliptick, that is from ♉ 15 to ♍ 15. 185 days 21 hours and 10′. And through the other Semicircle from ♒ 15 to ♌ 15, days 184. hours 5. therefore the Suns mean motion, according to the practice in the last example, from ♉ 15 to ♍ 15 is 181. 30. 26. and from ♒ 15 to ♌ 15. 181. 16. 30.

Now then in Fig. 7. if we subtract the semi­circle of the Orb KMH. 180. from WPV 181. 36. 26. the remainer is the sum of KW and HV [Page 366] 1. 36. 26. the Sine of half thereof 48′. 13″ is e­qual to AC. 140252.

Again the mean motion of the Sun in his Orb from ♒ 15 to ♉ 15 is the Arch SKP. 181. 16. 30. whose excess above the Semicircle being bi­sected is 38. 15. whose Sine CB. 111345. now then in the Triangle ABC to find the Angle BAC, the proportion is.

As the side AC. 140252
5.14690906
Is to the Radius.
10.00000000
So is the Side CB 111345
5.04667072
To Tang. BAC. 38. 36. 21,
9.89966166

Which being deducted out of the Angle. 69 A ♌. 45 it leaveth the Angle 69 AL 6. 33. 39. the place of the ☉ Aphelion sought, and this is the quantity which we retain.

And for the excentricity BC.
As the Sum of BAC. 38. 26. 21
9.79356702
Is to the Radius.
10.00000000
So is the side BC 111345
5.04667072
To the Hypot. AB. 179103
5.25310370

So then Anno Christi. 1652. Aphel.
96. 33.39
Anno Christi. 139. the Aphelion
70. 41.10
Their difference is
25. 52.29

And the difference of time is 1513 Julian years.

Hence to find the motion of the Aphelion for 2. years, say I, if 1513 years give 25. 52.29, what shall one year give, and the answer is 00d. 01′ [Page 367] 01″. 33‴. 56iv. 44v. that is in Decimal num­bers. 0. 00475. 04447. 0555.

And the motion for. 1651 years. 7. 84298. 4208862, which being deducted from the place of the Aphelion Anno Christi. 1652—26. 82245. 3703703. The remainer, viz. 18. 97946. 9494841 is the place thereof in the beginning of the Christian AEra, which being reduced is, 68 deg. 19. min. 33. sec. 56. thirds.

4. The Earths middle motion, Aphelion and Excentricity being thus found, we will now shew how the same may be stated to any particular time desired, and this must be done by help of the Sun or Earths place taken by observation. In the 178 year then from the death of Alexan­der, Mechir the 27 at 11 hours P. M. Hippar­cus found in the Meridian of Alexand. that the Sun entered ♈ 0. the which Vernal Equinox happened in the Meridian of London according to Mr. Wings computation at 9 hours 14′, and the Suns Aphelion then may thus be found.

The motion of the Aphelion for one year, was before found to be. 0. 00475. 04447. 0555. there­fore the motion thereof for one day is 0. 00001. 501491722. The Christian AEra began in the 4713 year compleat of the Julian Period, in which there are days 1721423. The AEra A­lexandri began November the twelfth, in the year 4390 of the Julian Period, in which there are 1603397 days. And from the death of A­lexander to the 27 of Mechir 178, there are days 64781, therefore from the beginning of the Julian Period, to the 178 year of the AEra A­lexandri, there are days 1668178 which being deducted from the days in the Christian AEra, [Page 368] 1721423, the remainer is 53245, the number of days between the 178 year after the death of Alexander, Mechir 27, and the beginning of the Christian AEra.

Or thus. From the AEra Alexandri to the AEra Christi there are 323 Julian years, and 51 days, that is 118026 days. And from the AEra Alexandri to the time of the observation, there are 64781 days, which being deducted from the former, the remainer is 53245 as before. Now then if you multiply the motion of the A­phelion for one day, viz. 0. 00001. 3014917 by 53245, the product is 0. 69297. 9255665, which being deducted from the place of the Aphelion in the beginning of the Christian AEra, before found. 18. 97946. 9494841. the remainer 18. 28649. 0239176 is the place of the Aphelion at the time of the observation, that is in Sexage­nary numbers. deg. 65. 49′. 53″.

5. The place of the Aphelion at the time of the observation being thus found to be deg. 65. 49′. 53″. The Suns mean Longitude at that time, may be thus computed.

In Fig. 8. In the Triangle EMH we have gi­ven the side ME 200000, the side MH 3576, the double excentricity before found, and the An­gle EMH 114. 10′. 07″. the complement of the Aphelion to a Semicircle, to find the Angle MEH, for which the proportion is,

As the Summ of the sides, is to the difference of the sides, so is the Tangent of the half Summ of the opposite Angles, to the Tangent of half their difference.

The side ME. 200000.
 
The side MH 3576.
 
Z. Of the sides. 203576. Co. ar.
4.69127343
X. Of the sides. 196424.
5.29321855
Tang. ½ Z Angles. 32′. 54′. 56.
9.91111512
Tang. ½ X Angles. 31. 59. 21.
 
Angle MEH. 0. 55. 35.
9.79560710

The double whereof is the Angle MBH 1. 51. 10. which being Subtracted from 360 the re­mainer 358. 08. 50. is the estimate middle mo­tion of the Sun, from which subtracting the A­phelion before found, 65. 49. 53. the remain­er 292. 18. 57. is the mean Anomaly by which the absolute AEquation may be found according to the former operation.

Z. ME+MH. 203576. Co. ar.
4.69127343
X. ME-MH. 196424
5.29321855
Tang. ½ Anom. 56. 09. 28.
10.17359517
Tang. ½ X. 55. 12. 18.
10.15808715
Differ. 00. 57. 10.
 

Doubled 1. 54. 20, which added to the mid­dle motion before found gives the ☉ true place ♈. 00. 3′. 10″, which exceeds the observation 3′. 10″. therefore I deduct the same from the middle motion before found, and the remainer 358. 05. 50. is the middle motion at the time of the observation of Hipparchus, to which if you add the middle motion of the Sun for 53245 days, or for 323 AEgyptian years 131 days, 280. 46. 08′ the Summ, rejecting the whole Circles, is 278. 51. 48 the Suns mean Longitude in the beginning of the Christian AEra.

6. But one observation is not sufficient, where­by [Page 370] to state the middle motion for any desired Epocha, we will therefore examine the same by another observation made by Albategnius at A­racta in the year of Christ 882, March: 15. hours 22. 21. but in the Meridian of London at 18 hours. 58′.

The motion of the Aphelion for 881 years, 74 days is 3. 806068653737, which being ad­ded to the place thereof in the beginning of the Christian AEra, the place at the time of the obser­vation will be found to be 22. 785538148578, that is reduced, Deg. 82. 01′. 40″. And hence the AEquation according to the former operati­ons is Deg. 2. 01′. 16″ which being deducted from a whole Circle, the remainer 357d. 58′. 44″ is the estimate middle motion at that time, from which deducting the Aphelion deg. 82. 01. 40. the remainer 275. 57. 04 is the mean ano­maly, and the AEquation answering thereto is deg. 2. 02′. 18″ which being added to the middle motion before found, gives the ☉ place ♈. 00. 01′. 02″ which exceeds the observation 01′. 02″. therefore deduct the same from the middle motion before found, the remainer 357. 57′. 22″ is the middle motion of the ☉ at the time of the observation, from which deducting the middle motion for 881 years, 74 days, 18 hours, 58 minutes, viz. 80d. 06′. 10″. the re­mainer 277 deg. 51′. 12″. is the ☉ mean Lon­gitude in the beginning of the Christian AEra.

By the first observation it is deg.
278. 51′. 48″
By the second
277. 51. 12
Their difference is
1. 00. 36

[Page 371] He that desires the same to this or any other Epocha, to more exactness, must take the pains to compare the Collection thereof from sun­dry Observations, with one another, this is sufficient to shew how it is to be found. Here therefore I will only add the measures set down by some of our own Nation, and leave it to the Readers choice to make use of that which pleaseth him best.

The ☉ mean Longitude in the beginning of the Christian AEra according to.
Vincent Wing is
9. 8d. 00′. 31″
Tho. Street is
9. 7. 55. 56
Iohn Flamsted is
9. 7. 54. 39
By our first Computation
9. 8. 51. 48
By our second
9. 7. 51. 12

In the Ensuing Tables of the ☉ mean Lon­gitude, we have made use of that measure gi­ven by Mr. Flamsted, a little pains will fit the Tables to any other measure.

CHAP. XI.

Of the quantity of the Tropical and Sydereal Year.

THe year Natural or Tropical (so called from the Greek word [...], (which sig­nifies to turn) because the year doth still turn or return into it self) is that part of time in which the ☉ doth finish his course in the Zodiack [Page 372] by coming to the same point from whence it began.

2. That we may determine the true quanti­ty thereof, we must first find the time of the ☉ Ingress into the AEquinoctial Points, about which there is no small difference amongst Astrono­mers, and therefore an absolute exactness is not to be expected, it is well that we are arrived so near the Truth as we are. Leaving it therefore to the scrutiny of after Ages, to make and com­pare sundry Observations of the ☉ entrance in­to the AEquinoctial Points, it shall suffice to shew here how the quantity of the Tropical year may be determined, from these following obser­vations.

3. Albategnius, Anno Christi 882 observed the ☉ entrance into the Autumnal AEquinox at Aracta in Syria to be Sept. 19. 1 hour 15′ in the Morning. But according to Mr. Wings cor­rection in his Astron. Instaur. Page 44, it was at 1 hour 43′ in the Morning, and therefore ac­cording to the ☉ middle motion, the mean time of this Autumnal AEquinox was Sept. 16. 12h. 14′. 25″. that is at London at 8h. 54′. 25″.

4. Again by sundry observations made in the year 1650. the second from Bissextile as that of Albategnius was, the true time of the ☉ in­gress into ♎ was found to be Sept. 12. 14h. 40′. and therefore his ingress according to his mid­dle motion was Sept. 10. 13h. 02.

5. Now the interval of these two observa­tions is the time of 768 years, in which space by subtracting the lesser from the greater, I find an anticipation of 5 days, 9 hours, 52′. 25″. which divided by 768 giveth in the quotient [Page 373] 10′. 55″. 39 which being subtracted for 365 days, 6 hours, the quantity of the Julian year, the true quantity of the Tropical year will be 365 days, 5 hours, 49′. 04″. 21‴. Others from other observations have found it some­what less, our worthy countryman Mr. Edward Wright takes it to be 365d. 5 hours. 48′.

Mr. Iohn Flamsted, 5h. 29′. Mr. Tho. Street 5h. 49′. 01″. taking therefore the Tropical year to consist of 365 days, 5 hours, 49 Minutes, the Suns mean motion for one day is 0 deg. 59′. 8″. 19‴. 43iv. 47v. 21vi. 29vii. 23viii. or in de­cimal Numbers, the whole Circle being divi­ded into 100 degrees, the ☉ daily motion is 0. 27379. 08048. 11873.

6. The Sydereal or Starry year is found from the Solar by adding the Annual Motion of the eighth Orb or praecession of the AEquinoctial Points thereunto, that praecession being first converted into time.

7. Now the motion of the fixed Stars is found to be about 50″. in a years time, as Mr. Wing hath collected from the several observations of Timocharis, Hipparchus, Tycho and others; and to shew the manner of this Collection, I will mention onely two, one in the time of Timo­charis, and another in the time of Tycho.

8. Timocharis then as Ptolemy hath it in his Almagist, sets down the Virgins Spike more northwardly than the AEquinoctial, 1 deg. 24′. the time of this observation is supposed to be about 291 years before Christ, the Latitude 1 deg. 59′ South, and therefore the place of the Star was in ♍. 21d. 59′. And by the ob­servation of Tycho 1601 current, it was in ♎ [Page 374] 18. 16′. and therefore the motion in one year 50″, which being divided by 365 days, 6 hours, the quotient is the motion thereof in a days time. 00′. 8‴. 12iv. 48v. 47vi. 18vii. 30viii. 13ix. and in decimal Numbers, the motion for a year is 00385. 80246. 91358. The motion for a day. 00001. 05626. 95938.

9. Now the time in which the Sun moveth 50″, is 20′. 17″. 28‴, therefore the length of the sydereal year is 365 days, 6 hours, 9′. 17″. 28‴. And the Suns mean motion for a day 59′. 8″. 19‴. 43iv. 47v. 21vi. 29vii. 23viii. converted into time is 00. 03′. 56″. 33‴. 18iv. 55v. 9vi. 23vii. 57viii. which being added to the AEquinocti­al day, 24 hours, giveth the mean solar day, 24 hours. 3.′ 56″. 33‴. 18iv. 55. 9. 23. 57.

10. And the daily motion of the fixed Stars, being converted into time is 32iv. 51v. 15vi. 9vii. 14viii. 24ix. and therefore the AEquinoctial day being 24 hours, the sydereal day is 24 hours, 00′. 00″. 00‴. 32iv. 51. 15. 9. 14 24.

11. Hence to find the praecession of the AEqui­noctial Points, or Longitude of any fixed Star, you must add or subtract the motion thereof, from the time of the observation, to the time given, to or from the place given by observation, and you have your desire.

Example. The place of the first Star in A­ries found by Tycho in the year 1601 current, was in ♈. 27d. 37′. 00. and I would know the place thereof in the beginning of the Christian AEra.

[Page 375]

The motion of the fixed Stars for 1600 years,
22d. 13′. 20″
Which being deducted from the place found by observ.
27. 37. 00
The remainer.
5. 231. 40

is the place thereof in the beginning of the Christian AEra.

12. Having thus found the ☉ middle moti­on, the motion of the Aphelion and fixed Stars, with their places, in the beginning of the Chri­stian AEra; we will now set down the num­bers here exhibited AEra Christi. Mr. Wing from the like observations, takes the ☉ motion to be as followeth.

The ☉ mean Longitude
9. 8. 00. 31
Place of Aphelion
2. 8. 20. 03
The Anomaly
06. 29. 40. 28

The which in decimal Numbers are
The ☉ mean Longitude
77. 22460. 86419
Place of the Aphelion
18. 98171. 29629
The Anomaly
58. 24289. 56790

The mean motions for one year.
The ☉ mean Longitude
99. 93364. 37563. 34
The Aphelion
00. 00475. 04447. 05
The ☉ mean Anomaly
99. 92889. 33116. 29

The ☉ mean motions for one day.
The ☉ mean Longitude
00. 27379. 08048. 11
The Aphelion
00. 00001. 30149. 17
The mean Anomaly
00. 27377. 77898. 94

And according to these measures are the Ta­bles made shewing the ☉ mean Longitude and Anomaly, for Years, Months, Days and Hours.

CHAP. XII.

The Suns mean motions otherwise stated.

SOme there are in our present age, that will not allow the Aphelion to have any motion, or alteration, but what proceeds from the mo­tion of the fixed Stars, the which as hath been shewed, do move 50 seconds in a year, and hence the place of the first Star in Aries, in the begin­ning of the Christian AEra was found to be ♈. 5. 23d. 40.

Now then, if from the place of the Aphelion Anno Christi. 1652 as was shewed in the tenth Chapter, deg. 96. 33′. 39. we deduct the mo­tion of the fixed Stars for that time. 28. 19. 12. the remainer 68. 14. 27 is the constant place of the Aphelion; but Mr. Street in his Astrono­mia Carolina Page 23, makes the constant place of the Aphelion to be 68d. 20. 00, and the ☉ ex­centricity 1732.

And from the observation of Tycho 1590 March the eleventh. in the Meridian of V­raniburg, but reduced to the Meridian of London. March the tenth, hour 23. 2′. He [Page 376]

[figure]

[Page] [Page]

[figure]

[Page] [Page 377] determines the Earths mean Anomaly thus.

The place of the Sun observed
♈. 0. 33. 19
The praecession of AEquinox
0. 27. 27. 22
The Earths Sydereal Longitude
5. 03. 05. 57
The place of the Aphelion Subtract
8. 08. 20. 00
The Earths true Anomaly
8. 24. 45. 57
AEquation Subtract
1. 58. 47
The remainer is the Estimate M. Anom.
8. 22. 47. 10
AEquation answering thereto add.
1. 58. 27
The Earths true Anomaly
8. 24. 45. 37
The place of the Aphelion
8. 08. 20. 00
Praecession of the AEquinox
0. 27. 27. 22
Place of the Sun
♈. 00. 32. 59
But the place by observation
♈. 00. 33. 19
The difference is
001. 001. 20
Which being added to the mean Anom.
8. 22. 47. 10
The mean Anomaly is
8. 22. 47. 30
The absolute AEquation
1. 58. 27
The true Anomaly
8. 24. 45. 57
Agreeing with observation.
 

And so the mean Anomaly AEra Christi is 6. 23. 19. 56. But Mr. Flamsted according to whose measure the ensuing Tables are compo­sed, takes the mean Anomaly AEra Christi. to be 6. 24. 07. 091. The place of the Aphelion to be 8, 08. 23. 50. And so the Praecession of the AEquinox and Aphelion in the beginning of [Page 378] the Christian AEra. 8, 13. 47. 30. in decimal Numbers.

AEra Christi.
The Suns mean Anomaly
56. 69976. 85185
The Suns Apogaeon and Praec. AEq.
20. 49768. 51851
The ☉ mean motions for one Year.
The ☉ mean Longitude
99. 93364. 37563. 34
The Praecession of AEquin.
00385. 80246. 91
The ☉ mean Anomal.
99. 92978. 57316. 43
The ☉ mean Motions for one Day.
The ☉ mean Longitude
00. 27379. 08048. 11
The Praecession of AEqui.
00. 00001. 05699. 30
The ☉ mean Anom.
00. 27378. 02348. 81

CHAP. XIII.

How to Calculate the Suns true place by either of the Tables of middle motion.

VVRite out the Epocha next before the given time, and severally under that set the motions belonging to the years, months and days compleat, to the hours, scruples, cur­rent every one under his like (only remember that in the Bissextile years after the end of Fre­bruary the days must be increased by an unite) then adding all together, the sum shall be the ☉ mean motion for the time given.

[Page 379] Example.

Let the given time be Anno Christi 1672. Fe­bruary 23. hours 11. 34′. 54″. by the Tables of the ☉ mean Longitude and Anomaly, the num­bers are as followeth.

  M. Longitud.M. Anomal.
The Epocha166080. 67440.53.79815
Years1199. 81766.99.76526
Ianuary 08. 48751.08.48711
Day.2306. 29718.06.29688
Hours1100. 12548.00.12548
 3400. 00646.00.00646
 5400. 00017.00.00017
  95. 40886.68.47951

By the Tables of the Suns mean Anomaly and praecession of the AEquinox, the numbers are these.

  Anomaly.Praece. AEqui.
The Epocha166053. 76721.26.90200
Years1199. 77520.00.04243
Ianuary 8. 48718.00032
Days236. 29694.00024
Hours110. 12548.26.94499
 34′.00646.68.45882
 54″.00035.95.40381
☉ mean Anomaly 68.45882 

[Page 380] There is no great difference between the ☉ mean Longitude and Anomaly found by the Ta­bles of mean Longitude and Anomaly, and that found by the Tables of mean Anomaly and Pre­cession of the AEquinox. The method of finding the Elliptical AEquation is the same in both, we will instance in the latter only, in which the ☉ mean Anomaly is Degrees 68. 45882. And the precession of AEquin. deg. 26. 94499.

But because there is no Canon of Sines and Tan­gents as yet published, suitable to this division of the Circle into an 100 deg. or parts: We must first convert the ☉ mean Anomaly, and prec. of of the AEquin, given, into the degrees and parts of the common Circle: And this may be done either into degrees and decimal parts of a degree, or into deg. and minutes: if it were required to be done into degrees and minutes, the Table here exhibited for that purpose will serve the turn, but if it be required to be done into degrees and de­cimal parts, I judge the following method to be more convenient.

Multiply the degrees and parts given by 36, the Product, if you cut off one figure more towards the right hand than there are parts in the num­ber given, shall be the degrees and parts of the common Circle.

Anomaly. 68. 45882Praec. AEquinox. 26. 94499
36 36
41075292 16166994
20537646 8983497
Anom. 246. 451752 Prae. AEq. 97. 001964

[Page 38] And if you multiply the parts of these Pro­ducts, you will convert them into minutes.

Otherwise thus. Multiply the degrees and parts given by 6 continually, the second Product, if you cut off one figure more towards the right hand than are parts in the number given, shall be the degrees and parts of the common Circle. The third Product of the parts only shall give minutes, the fourth seconds, and so forward as far as you please. Example.

☉ Mean Anom. 68. 45882
Praec. AEq. 26. 94499
6
6
41075292
16166994
246.451752
97.001964
6
6
27.10512
0.11784
6
6
6.3072
7.0704

And thus the mean Anom. is deg. 246. 451742 or 27′. 06. The Prec. AEq. 97. 001964. or 00′. 07″.

Hence to find the Elliptical AEquation in degrees and decimal parts: In Fig. 8. we have given in the right lined plain Triangle EMH, the sides ME, and MH, and the Angle EMH, 66. 451742. the excess of the mean Anomaly above a Semicircle, to find the Angle MEH.

The side ME
200000
The side MH
3468
Zcru.203468Co. ar.4.69150389
Xcru.196532 5.29343327
t frac12 Zangle.56.774129 10.18374097
t frac12 Xangle.55.857087 10.16867813

MEH. 0. 917042 the double whereof is the Angle MBH. 1. 834084 or Elliptick AEqua­tion sought, which being added to the mean A­nomaly and praecession of the AEquinox, because the Anomaly is more than a Semicircle, the same is the Suns true place.

The ☉ mean Anomaly
246.451742
The Praecession of the AEquinox
97.001964
Elliptick AEquation
1.834084
The Suns true place.
345.287790

But because the Elliptick AEquation thus found doth not so exactly agree to observation as is de­sired, Bullialdus in Chap. 3. of his Book entituled Astronomiae Philolaicae fundamenta clarius explicata, Printed at Paris, 1657. shews how to correct the same by an Angle applied to the Focus of middle motion, subtended by the part of the ordinate line, intercepted between the Ellipsis and the Cir­cle circumscribing it. This Mr. Street maketh use of in his Astronomia Carolina, and this I thought not amiss to add here.

In Fig. 9. let ABCPDF be supposed an El­lipsis, and the Circle AGPK described upon the extremes of the transverse Diameter, and the Or­dinates KN and OB extended to G and M in [Page]

[figure]

[Page] [Page 383] the Periphery of the Circle: then by the 21 of the first of Apollonius.

XN. GX∷OB tang. OEB. OM tang. OEM.

And the Angle OEM-OEB=BEM=ETY, the variation to be deducted from the Elliptick AEquation ETH, the Remainer is the absolute AEquation YTS in the first Quadrant.

In the second and third Quadrants, the variati­on or difference between the mean and corrected Anomaly, must be added to the Elliptick AEqua­tion, to find the true and absolute AEquation.

For XN. XG. QV. tang. QEV. the comp. m. Anom. QR. t. QER. and the Angle VER=ECO is the va­riation, and ECO+ECH=OCH is the absolute AEquation sought in the second Quadrant.

Again, XN. SG∷a D, tang. a ED. a b, tang. aEB. And aEB—aED=DEf the variation=EFO and EfO+EfH=OfH the absolute AEquation sought in the third Quadrant.

Lastly, in the fourth Quadrant of mean Ano­maly it is.

XN. XG∷ch. tang. eEH. eg. tang. eFg. and hEg is the variation: And EFH— [...]= [...] the absolute AEquation sought in the fourth Quadrant.

And to find XN the conjugate Semi-diameter, in the right angled Triangle ENX, we have gi­ven, EN=AX and EX the semi-distance of the umbilick points. And Mr. Briggs in Chap. 19. of his Arithm. Logar. hath shewed, that the half Sum of the Logarith. of the sum and difference of the Hypotenuse, and the given leg. shall be the Loga­rith. of the other leg.

[Page 384] Now then EN=AX. 100000  
The Leg EX.1734 
Their Sum1017345.00745001
Their difference982664.99240328
 The Z of the Logarithms,9.99985329
 frac12; Z. Logarith. XN. 999834.99992664

Now then in the former Example the mean Anomaly is 246 deg. 451741. and the excess a­bove a semicircle is the ang. aED. 66. 451742. Therefore.

As XN. 99983
4.99992664
Is to XG. 100000
5.00000000
So is the tang. aED 66.451742
10.36069857
To the tang. aEB 66.455296
10.36077193

aEB—aED=DEf .003544 the variation, which being added to the Elliptick AEquation be­fore found, the absolute AEquation is 1. 837628. and therefore the ☉ true place 345. 291334. that is X. 15. 17. 28.

CHAP. XIV.

To find the place of the fixed Stars.

THe annual motion of the fixed Stars is, as hath been shewed, 50 Seconds, hence to find their places at any time assigned, we have exhibited a Table of the Longitude and Latitude of some of the most fixed Stars, from the Cata­logue [Page]

[figure]

[Page] [Page 385] of noble Tycho for the year of our Lord 1600 compleat. Now then the motion of the fixed Stars according to our Tables being com­puted, for the difference of time between 1600 and the time propounded, and subtracted from the place in the Table, when the time given is before 1600, or added to it, when the time gi­ven is after; the Summ or difference shall be the place desired. The Latitude and Magnitude are still the same.

Example. Let the given time be 1500, the difference of time is 100 years, and the moti­on of the fixed Stars for 100 years is 0. 38580.

The place of the 1 * in ♈, 1600
7.67129
Motion for 100 years subtract
0.38580
Place required in the year 1500
7.28549

2. Example.

Let the time given be
1674.
The place of the first Star in ♈ 1600 was
7.67129
Motion for 60 years is
0.23148
Motion for 14 years is
0.05401
Place required in the year 1674 compl.
7.95678

CHAP. XV.

Of the Theory of the Moon, and the finding the place of her Apogaeon, quantity of excentricity and middle motion.

THe Moon is a secondary Planet, moving a­bout the Earth, as the Earth and other [Page 386] Planets do about the Sun, and so not only the Earth but the whole System of the Moon, is also carried about the Sun in a year. And hence, ac­cording to Hipparchus, there arises a twofold, but according to Tycho a three-fold Inequality in the Moons Motion. The first is Periodical and is to be obtained after the same manner, as was the excentrick AEquation of the Sun or Earth: in order whereunto, we will first shew how the place of her Apogaeon and excentricity may be found.

At Bononia in Italy, whose Longitude is 13 degrees Eastward from the Meridian of London, Ricciolus and others observed the apparent times of the middle of three lunar Eclipses to be as fol­loweth.

  • The first 1642. April the 4. at 14 hours and 4 Minutes.
  • The second 1642, September 27 at 16 hours and 46 minutes.
  • The third 1643. September 17 at 7 hours and 31 Minutes.

The equal times reduced to the Meridian of London, with the places of the Sun in these three observations, according to Mr. Street in the 25 Page of his Astronomia Carolina, are thus.

Anno Mens. D. h.
d.
1642. April 4. 13. 37.
♈. 25. 6. 54
1642. Septemb. 27. 15. 57
♎. 14. 50. 09
1643. Sehtemb. 17. 6. 46
♎ 4. 20. 20

Hence the place of the Moon in the first obser­vation [Page 387] is in ♎ 25. 6′. 54. in the second ♈ 14. 50. 9. in the third ♓ 4. 20. 20. Now then in Fig. 10. let the Circle BHDGFE denote the Moons AEquant T the Center of the Earth, the Semidiameters TD, TE and TF the apparent places of the Moon, in the first, second and third observations, C the Center of the Excentrick, CD, CE and CF the Lines of middle motion.

From the first observation to the second there are
176d. 2h. 20′
The true motion of the Moon is deg.
169. 43. 15″
The motion of the Apogaeon subtract
19. 37. 07
The motion of the true Anomaly is the arch DE
150. 06. 08
The motion of the mean Anomaly DCE
140. 42. 28
From the first observation to the third, there are
530d. 17h. 9.
The true motion of the Moon is degrees
159. 13. 26
The motion of the Apogaeon subtract
159. 07. 32
The motion of the true Ano­maly is the Arch DF
100. 05. 54
The motion of the mean Anomaly DCF
93. 46. 45
And deducting the Arch DGF from the Arch DFE, the re­mainer is the Arch FE
50. 00. 14
And deducting the Angle DCF from the Angle DCE, the re­mainer is the Angle FCE
46. 55. 43

Suppose 10.00000000 the Logarithm of DC, continue FC to H, and with the other right Lines compleat the Diagram.

1. In the Triangle DCH we have given the Angle DCH 86. 13. 15. the complement of DCF 93. 46. 45 to a Semicircle. The Angle DHC 50. 02. 57. The half of the Arch DF and the side CD 1000000. To find CH.

As the Sine of DHC 50. 02. 57
9.88456640
To the Side DC, so the Sine of HDC 43. 43. 48.
19.83964197
To the Side CA
9.95507557

2 In the Triangle HCE we have given CH as before, the Angle CHE 25. 00. 07. The half of the Arch FE, the Angle HCE 133. 04. 17 the complement of FCE, and by consequence the Angle CEH 21. 55. 36 To find the Side CE.

As the Sine of CEH 21. 55. 36
9.57219707
To the Side CH
19.95507557
So is the Sine of CHE 25. 00. 07
9.62597986
To the Sine CE
  • 19.58105543
  • 10.00885836

3. In the Triangle DCE, we have given DC. CE and the Angle DCE 140. 42. 28. whose complement 39. 17. 32 is the Summ of the An­gles, to find the Angle CED and DE,

As the greater Side CE
10.00885836
Is to the lesser Side DC
10.00000000
So is the Radius
10.00000000
To the tang. of 44. 24. 54
19.99114164
Which subtracted from 45. 2
the remainer is the half.
Difference of the acute angles 35. 16.
 
As the Radius.
To the tang. of the com. 35. 16
8.01109962
Is to the tang. of the frac12; Z. 19. 38. 46
9.55265735
To the tang. of frac12; X. 00. 12. 35
7.56375697
Their Sum 19. 51. 21. is the angle—CDE.
 
Their difference 19. 26. 11. is the angle CED.
 
As the Sine of CED. 19. 26. 11.
9.52216126
Is to the Sine of DCE. 140. 42. 28.
9.80159290
So is the Side EC.
10.00000000
To the Side DE.
10.27943164

4. In the Isosceles Triangle DTE we have gi­ven the Side DE, the angle DTE 150. 06. 08 whose complement 29. 53. 52 is the Summ of the other two angles, the half whereof is the angle TDE 14. 56. 56 which being subtracted from the angle CDE. 19. 51. 21 the remainer is the angle CDT. 4. 54. 25.

As the Sine of DTE 150. 06. 08 Co. ar.
0.30237482
Is to the Sine of DET. 14. 56. 56
9.41154778
So is the Side DE
10.27943164
To the Side DT
9.99335424

5. In the Triangle CDT we have given DC. DT and the angle CDT, to find CTD and CT.

As the Side DT
9.99335424
Is to the Side DC
10.00000000
So is the Rad.
10.00000000
To the tang. of 26. 18
10.00664576
  • Deduct 45.
  • As the Radius.
Is to the Sine of the remainer 0. 26. 18.
7.88368672
So is the tang. of the frac12; Z angle 87. 32. 57
11.36854996
To the tang. frac12; X angle 10. 08. 04
9.25223668
Their Summ 97. 41. 01
is the angle CTD
As the Sine of CTD. 97. 41. 01. Co. ar.
0.00391693
Is to the Side DC
10.00000000
So is the Sine of CDT 4. 54. 25
8.93215746
To the Side CT
8.93607439
 
s. d.
The place of the Moon in the first Observation
6. 25. 06. 54
The true Anomaly CTD sub.
3. 07. 41. 01
The place of the Apogaeon
3. 17. 25. 53
☽ place in the first Observation
6. 25. 06. 54
The AEquation CDT Add.
04. 54. 25
The ☽ mean Longitude
7. 00. 01. 19
From which subtract the place of the Apogeon
3. 27. 25. 53
There rests the mean Anomaly BCD
3. 12. 35. 26

And for the excentricity in such parts, as the Radius of the AEquant is 100000 the Proporti­on is.

DT
9.99335424
CT
8.93607439
100000
5.00000000
8764
3.94272015

And this is the Method for finding the place of the Moons Apogaeon and excentricity. And from these and many other Eclipses as well Solar as Lunar, Mr. Street limits the place of the ☽ Apogaeon to be at the time of the first observation 21′. 04″ more, and the mean Anomaly 20. 41″ less, and the excentricity 8765 such parts as the Radius of the AEquant is 100000.

And by comparing sundry observations both antient and modern, he collects the middle mo­tion of the Moon, from her Apogaeon, to be in the space of four Julian years or 146 days, 53 revolutions, 0 Signes, 7 degrees, 56 minutes, 45 Seconds. And the Apogaeon from the AEqui­nox 5 Signes, 12 degrees, 46 minutes. And hence the daily motion of her mean Anomaly will be found to be 13d. 03′. 53″. 57‴. 09iv. 58v. 46vi. Of her Apogaeon 0. 06. 41. 04. 03. 25. 33.

And according to these Measures, if you de­duct the motion of the ☽ mean Anomaly for 1641 years April

4. hours 13. 37′, viz.
8. 22. 02. 00.
from
3. 121. 35. 26
The remainer is
6. 201. 33. 26
from which abating 20′. 41″ the ☽ mean Anom. AEra Chr. 6. 20. 12. 45.
 

[Page]

[figure]
In like manner the motion of her Apogaeon for the same time is
6. 05. 311. 57
which being deducted from
3. 17. 25. 57
The remainer is
9. 11. 55. 56
To which if you add
21.04
The Sum
91. 121. 15200
is the place of the ☽ Apogaeon in the beginning of the Christian AEra.
 

CHAP. XVI.

Of the finding of the place and motion of the Moons Nodes.

ANno Christi 1652, March 28, hour. 22. 16′, the Sun and Moon being in conjunction, Mr. Street in Page 33, computes the ☽ true place in the Meridian of London to be in ♈. 19. 14. 18 with latitude North 46′. 15″.

And Anno Christi 1654 August 1. hour. 21. 19′. 30″ was the middle of a Solar Eclipse at London. at which time the Moons true place was found to be in ♌ 18. 58′. 12″ with North La­titude 32′. 01″.

  • 1654 August 1. 21. 19′. 30″ ☽ place ♌ 18. 58. 12
  • 1652 March 28. 22. 16. 00 ☽ place ♈ 19. 14. 18

From the first observation to the second there are 27 years, 4 months, 5 days, 23 hours 03′. 30″.

Mean motion of the Nodes in that time, deg.
45. 19. 41
The true motion of the ☽
119. 43. 54
Their Summ is in Fig. 11. The angle DPB
165. 03. 35

Therefore in the oblique angled Spherical Triangle DPB we have given BP. 89. 13. 45 the complement of the Moons Latitude in the first Observation 2. PD 89. 27. 50 the comple­ment of the Moons Latitude in the second obser­vation, and the angle DPB 165. 03. 35, whose complement to a Semicircle is DPF 14. 56. 25. The angle PBD is required.

1. Proportion.

As the Cotangent of PD 89. 27. 50
9.97114485
Is to the Radius
10.00000000
So is the Cosine of DPF 14. 56. 25
9.98506483
To the tang. of PF 89. 26. 42
12.01191998
BP 89. 13. 45
 

Their Z is FPB 178. 40. 27. whose complement Is the Arch FG 1. 19. 33.

2. Proportion.

As the Sine of FP 89. 26. 42. Co. ar.
0.00002037
Is to the Cotang. of DPF 14. 56. 25
10.57376158
So is the Sine of FG 1. 19. 33
8.36418419
To the Cotang. of FGD 85. 02. 56
8.93796614
FGD=PBD inquired.
 

[Page 395] And in the right angled Spherical Triangle BA☊ right angled at A we have given AB 046′. 15″ the Latitude in the first observation, and the Angle AB☊=PBD 85. 02. 56. to find A☊ the Longitude of the Moon from the ascending Node.

As the Cot. of AB☊ 85. 02. 56
8.93796614
Is to the Radius
10.00000000
So is the Sine of AB 0.46′. 15″
8.12882290
To the tang. of A☊ 8. 49. 17
9.19085676

2. To find the Angle A☊B.

As the tang. of AB 0. 46. 15
8.12886212
Is to the Radius
10.00000000
So is the Sine of A☊ 8. 49. 17
9.18569718
To the Cotang. of A☊B 5. 0. 41
11.05682506
The angle of the ☽ orbite with the Ecliptick
 
The first observed place of the ☽
♈. 19. 14. 18
A☊ Subtract
8. 49. 17
There rests the true place of the ☊
♈. 10. 25. 01

The retrograde motion whereof in 4 Julian years or 2461 days, is by other observations found to be Sign 2. deg. 17. 22′. 06″. and there­fore the daily motion deg. 0. 03′. 10″. 38‴. 11iv. 35v.

And the motion thereof for 1651 years, March 28. h. 22. 16′, viz. Sign 8. deg. 18. 26′. 58″ being added to the place of the Node before found Sig. 0. 10. 25: 01. Their Sum is the place thereof in the beginning of the Christian AEra Sign 8. deg. 28. 51′. 59″.

[Page 396] But the Rudolphin Tables as they are corrected by Mr. Horron and reduced to the Meridian of London, do differ a little from these measures, for according to these Tables, the Moons mean mo­tions are.

AEra Christi.
The Moons mean Lon­gitude is
Sign. 04. deg. 02. 25. 55
The Moons Apogaeon
Sign. 09. deg. 13. 46. 59
The Moons mean Anomaly
Sign. 06. deg. 18. 38. 56
The Moons Node Re­trograde
Sign. 08. deg. 28. 33. 16

And according to these measures, the Moons mean motions in decimal Numbers are.

AEra Christi.
The Moons mean Longi­tude, deg.
34. 00887.345677
The Moons Apogaeon, deg.
78. 82862.654320
The Moons mean Anomaly, deg.
55. 18024.691357
The Moons Node Retro­grade, deg.
74. 69845.679010

[Page]

[figure]
The ☽ mean motion for one year.
The Moons mean Longi­tude, deg.
35. 94001. 44893. 1
The Moons Apogeaon, deg.
11. 29551. 126365
The Moons mean Anoma­ly, deg.
24. 64450. 322566
The Moons Node Retro­grade, deg.
05. 36900. 781604
The ☽ mean motion for one day.
The Moons mean Longi­tude, deg
03. 66010. 962873
The Moons Apogaeon, deg.
00. 03094. 660620
The Moons mean Anoma­ly, deg.
03. 62916. 302253
The Moons Node Retro­grade, deg.
00. 01470. 961045

And according to these measures are the Ta­bles made shewing the Moons mean Longitude, Apogaeon, Anomaly, and Node retrograde for Years, Months, Days and Hours.

And hence to compute the Moons true place in her Orbit, I shall make use of the Method, which Mr. Horron in his Posthumas works lastly pub­lished by Mr. Flamsted, in which from the Ru­dolphin Tables he sets down these Dimensi­ons.

The Moons mean Semidiameter deg.
00. 15′. 30″
Her mean distance in Semid. of the Earth Deg.
11. 47. 22
The half whereof deg. 5. 53. 41. he adds 45 the whole is
deg. 50. 53. 41
Whose Artificial cotangent is
9.91000022
And the double thereof makes this standing Numb.
9.82000044
 Greatest 6685. 44 
The MoonsMean 5523. 69Excentricity
 Least 4361. 94 
And her greatest variation 00. 36′. 27″.

These things premised his directions for com­puting the Moons place, are as followeth.

CHAP. XVII.

How to Calculate the Moons true place in her Orbit.

TO the given time find the true place of the Sun, or his Longitude from the Vernal AEquinox, as hath been already shewed.

2. From the Tables of the Moons mean moti­ons, write out the Epocha next before the gi­ven time, and severally under that set the moti­ons, belonging to the years, months and days compleat, and to the hours and scruples cur­rent, every one under his like (only remember that in the Bissextile years, after the end of Fe­bruary, the days must be increased by one Unite) then adding them all together, the Summ shall be [Page 399] the Moons mean motions for the time given: But in her Node Retragrade you must leave out the Radix or first number, and the Summ of the remainer being deducted from the Radix, shall be the mean place of her Node required.

3. Deduct the Moons Apogaeon from the ☉ true place, the rest is the annual Augment, the tan­gent of whose Complement 180 or 360, being ad­ded to the artificial Number given 9. 82000044. the Summ shall be the tangent of an Arch, which being deducted from the said Complement, gi­veth the Apogaeon AEquation to be added to the mean Apogaeon, in the first and third quadrants of the annual Augment, and Subtracted in the second and fourth, their Summ or difference is the true Apogaeon.

4. The true Apogaeon being Deducted from the ☽ mean Longitude gives the Moons mean Anomaly.

5. Double the annual Augment, and to the Cosine thereof add the Logarithm of 1161. 75. the difference between the Moons mean and ex­tream Excentricity, viz. 3. 06511268, the Summ shall be the Logarithm of a number which being added to the mean Excentricity, if the double annual Augment be in the first or fourth quadrants; or Subtracted from it, if in the second or third quadrants; the Summ or difference shall be the Moons true Excentricity.

6. The Moons true Excentricity being taken for a natural Sine, the Arch answering thereto shall be the ☽ greatest Physical AEquation.

7. To the half of the Moons greatest Physical AEquation add 45 deg. the cotagent of the Summ is the artificial Logarithm of the Excentrick. [Page 400] To the double whereof if you add the tang. of half the mean Anomaly, the Summ shall be the tangent of an Arch, which being added to half the mean Anomaly, shall give the Excentrick A­nomaly.

8. To the Logarithm of the Excentrick, add the tangent of half the Excentrick Anomaly, the Summ shall be the tangent of an Arch, whose double shall be the Coequated Anomaly, and the difference between this and the mean Anomaly is the terrestrial Equation, which being added to the Moons mean Longitude, if the mean Anoma­ly be in the first Semicircle, or Subtracted from it, if in the latter, the Summ or difference shall be the place of the Moon first Equated.

9. From the place of the Moon first Equated, Deduct the true place of the Sun, and double the remainer, and to the Sine of the double add the Sine of the greatest variation 0. 36. 27, viz. 8. 02541571, the Summ shall be the Sine of the true variation, at that time, which being added to the Moons place first Equated, when her single distance from the Sun is in the first or third qua­drants, or Subtracted when in the second or fourth, the Summ or difference shall be the Moons true place in her Orbit.

Example.

Let the given time be Anno Christi 1672. Feb. 23. h. 11. 34′. 54″ at which time the Suns true place is in ♓ 15. 29133 and the Moons middle motions are as followeth.

[Page 401]

 ☽ Longitude☽ Apogaeon☊ Retrograde 
166013. 36650.41. 78372.55.85177 
11.02. 66032.24. 31246.59.08943 
Ianuary.13. 46339.00.95934.45599 
D. 2384. 18252..71177.33832 
H. 111. 67755..01418.00674 
34′.08641..00072.00054 
54.00228..00012.00001 
Longitude15. 43897.67.7822959.89082 
    95.96094
These Numbers reduced to the Degrees and Parts of the common Circle are for the ☽ mean Longitude.
55.580292
The ☽ Apogaeon.
244.015956
The ☉ true place is
345.29133
The ☽ Apogaeon subtract.
244.01595
The Annual Augment.
101.27538
The Complement whereof is
78.72462
The Tang. of deg. 78. 72462
10.70033391
The standing Number.
9.82000044
The Tang. of deg. 73. 20288
10.52033435
Their difference. 5. 52174 the Apogaeon Equation
 
Mean Apogaeon 244. 01595
 
Their difference 238. 49421 is the true Apogaeon.
 

[Page 402] Secondly.

The ☽ mean Longitude.
55.58029
The true Apogaeon subtract.
238.49421
Rests the ☽ mean Anom. correct.
177.08608

Or thus.

The ☽ mean Anomaly in the Tables for the time propounded, will be found to be 67. 78221, which converted into the deg. and parts of the common Circle is
171.56434
To which the Apogaeon Equation being added
5.52174
Their Sum is the mean Anom. correct.
177.08608

And hence it appears that working by the mean Anomaly instead of the mean Longitude, the true Apogaeon Equation must be added to the mean Anomaly, in the second and fourth Qua­drants of the ☽ Annual Augment, and sub­tracted from it in the first and third.

Thirdly.

The Annual Augment. 101. 27538 being dou­bled is deg. 202. 55076, the Cosine of whose excess above 180, that is the Cosine of 22. 54076 is
9.96545577
The Logarithm of 1161. 75
3.06511268
The Logarithm of 1072. 92
3.03056845
The ☽ mean Excentr. 5523. 69
 
Their difference 4450. 77 is the ☽ true Ex­centricity. [Page 403] Which taken as a natural Sine, the Arch answering thereunto Deg. 2. 55094 is the ☽ greatest Physical Equation.
 

Fourthly.

To the half of the Physical Equation. deg. 01. 27547 add 45 degrees, the Sum is deg. 46. 27547, the Cotangent whereof; viz. 9. 98080957 is the Logarithm of the Excen­trick, the double of which Logarithm is
9.96161914
Tangent frac12 Anomaly corrected 88. 54304
11.59455229
Tang. of deg. 88. 40849
11.55620143
Their Sum deg. 176. 95153 is the excentrick A­nomaly.
 

Fifthly.

The Logarithm of the Excen­trick is
9.98080957
Tang. frac12 excent. Anom. 88. 475765
11.57505878
Tangent of deg. 88. 407268
11.55586835
The double whereof 176. 814536
is the coequa­ted Anomaly.
M. Anomaly correct.
177.086080
Their difference 0. 271544
is the Equati­on sought to
be subst. from ☽ mean Long.
55.580292
The Remainer 55. 308748
is the ☽ place first Equated.

[Page 404] Sixthly,

From the place of the ☽ first E­quated.
55.308748
Deduct the true place of the Sun
345.291330
The Remainer is the Distance of the ☽ à
70.017418
The double whereof is 140. 034836. The Sine of whose Complement to a Semi-circle, 39. 965164 is
9.80775260
The Sine of the greatest variation
8.02541571
The Sine of the true var. 0. 390206
7.83316831
The ☽ place first Equa. 55. 308748
 
The ☽ place in Orbit 55. 698954 that is in Sex­agenary Numbers. 8. 25. 41. 54.
 

CHAP. XVIII.

To compute the true Latitude of the Moon, and to reduce her place, from her Orbit to the Ecliptick.

THe greatest Obliquity of the Moon's Orb with the Ecliptick or Angle A ☊ B Fig. 11. is by many Observations confirmed to be 5 De­grees just, at the time of the Conjunction or Op­position of the Sun and Moon, but in her Quar­ters deg. 5. 18′. Now then then find her Latitude at all times, the said Mr. Horrox refers us to pag. 87. in the Rudolphin Tables, to find from thence the Equation of the Nodes, and Inclination limi­tis menstrui, in this manner.

1. From the mean place of the Node, deduct [Page 405] the ☉ true place, the Remainer is the distance of the ☉ from the ☊. with which entring the said Table, he finds the Equation of the Node and Inclination limitis menstrui, which being added to or subtracted from the Nodes mean place ac­cording to the title, the Sum or difference is the true place of the Node, which being deducted from the place of the Moon in her Orb, the Re­mainer shall be the Augment of Latitude or Di­stance of the Moon from the Node, or Leg A ☊.

2. With the Augment of Latitude, enter the Table of the Moon's Latitude, and take thence her Simple and Latitude and Increase answering to it. Then say, as the whole excess of Latitude 18′, or in Decimals 30. is to the Inclination of the Monethly limit: So is the increase of Latitude to the Part Proportional; which being added to the sim­ple Latitude, will give you the true Latitude of the Moon.

3. With the same Augment of Latitude, en­ter the Table of Reduction, and take thence the Reduction and Inclination answering thereto: Then say again, as 18′. 00″. or 0. 30. is to the In­clination of the Monethly limit: So is the increase of Reduction, to the Part Proportional; which being added to the simple Reduction, shall give the true, to be added to, or subtracted from the place of the Moon in the Ecliptick.

Example. By the former Chapter, we found the mean motion of the Node to be 95. 96094, which reduced to the Degrees and Parts of the common Circle is
345.459384
And the Suns true place to be
345.291334
Their difference is the distance ☉ à
. 168050

[Page 406] with which entring the Table, Entituled Ta­bula AEquationis Nodorum Lunae. I find the Node to need no Equation, and the Inclinati­on limitis menstrui to be deg. 00. 30.

The place of the ☽ in her Orbit
55.698954
The Nodes true place, subtract.
345.459384
The Augment of Latitude
70.239570
2. With this Augment of Latitude I enter the Table shewing the Moons simple Latitude, and thereby find her simple Latitude to be De­grees. 04. 70476. North; And the in­crease
00.28234
And therefore the Moons true Lati­tude is deg.
4.98610
3. With the same Augment of Latitude, I en­ter the Table of Reduction, and thereby find the Reduction to be
00.06955
And the increase of Reduction to be deg.
00.00855
And therefore the whole Reduction to be sub.
00.07810
From the ☽ place in her Orbit
55.69895
The ☽ true place in the Ecliptick
55.62085
That is in Sexagenary Numbers.
8. 25. 37′. 15″.

CHAP. XIX.

To find the Mean Conjunction and Opposition of the Sun and Moon.

TO this purpose we have here exhibited a Ta­ble shewing the Moons mean motion from the Sun, the construction whereof is this: By the Tables of the Moons mean motions, her mean

Longitude AEra Christi is
34.0088734567
The ☉ mean Anomaly.
56.6997085185
Praecession of the AEquinox.
20.4976851851
Their Sum is the ☉ mean lon­git. AEra a Christi.
77.4973937036
Which being deducted from the ☽ mean longitude, the remainer is the Moons mean
56.8114797531
distance from the Sun, in the beginning of the Christian AEra.
 

In like manner the Moons mean distance from the Sun in a year or a day is thus found.

☉ Anomaly for a year.
99.9297857316
Praecession of the AEquinox.
0038580246
Their Sum subtract.
99.9336437562
From the ☽ mean Longitude.
35.9400144893
Moons distance from the ☉.
36.0063707331

[Page 408] Moons distance from the Sun in a days time.

☉ mean Anomaly.
27378.02348
Praecession of the AEquinox.
1.05699
Their Sum subtract.
27379.08047
From the ☽ mean Longitude.
03. 66010.96287
☽ Daily motion from the ☉.
03. 38631.88240

And according to these measures are the Ta­bles made, shewing the Moons mean motion from the Sun, by which the mean conjunction of the ☽ and Moon may be thus computed.

To the given year and Month gather the mid­dle motions of the Moon from the Sun, and take the complement thereof to a whole Circle, from which subtracting continually the nearest lesser middle motions, the day, hour, and minute en­fuing thereto is the mean time of the Conjun­ction.

Example, Anno Christi 1676. I would know the time of the mean Conjunction or New Moon in October.

Epocha 1660
32.697283
Years Compl. 15.
50.254463
Septemb. Compl.
24.465038
1. day for Leap-year.
03.386318
Their Sum is the Moons motion from the ☉.
10.803102
Complement to a whole Circle.
89.196898
Days 26 Subtract.
88.044289
Hours 8. substract.
  • 1.152609
  • 1.128772
[Page 409] Minutes 10 Subtract.
  • 0.023837
  • 0.023516
The Remainer giveth 8″.
.00321

Therefore the mean Conjunction in October, 1676. was the 26 day, 10 min. 8 seconds after 8 at night.

And to find the mean opposition. To the com­plement of the middle motion, add a semicircle, and then subtract the nearest lesser middle moti­ons as before, the day, hour, and minute ensuing thereto, shall be the mean opposition required.

Example, Anno Christi, 1676. I desire to know the mean opposition in November.

Epocha 1660
32.697283
Years Compl. 15
50.254463
October Compl.
29.440922
1 day for Leap-year.
03.386318
The ☽ mean motion from the ☉
15.778986
Complement to a whole Circle.
84.221014
To which add a Semicircle.
50.
The Sum is
34.221014
Day 10 subtract.
33.863188
Hours 2.
  • .357826
  • .282193
Minutes 32.
  • .075633
  • .075251
The Remainer giveth 9 seconds.
.000382

[Page 410] Therefore the Full Moon or mean Opposition of the Sun and Moon was November the 10th, Hours 2, 32′ 09″. The like may be done for a­ny other.

And here I should proceed to shew the manner of finding the true Conjunction or Opposition of the Sun and Moon, but there being no decimal Canon yet extant, suitable to the Tables of mid­dle motions here exhibited, I chuse rather to re­fer my Reader to Mr. Street's Astronomia Carolina, for instructions in that particular, and what else shall be found wanting in this Subject.

AN INTRODUCTION TO Geography, OR, The Fourth Part of COSMOGRAPHY.

CHAP. I.

Of the Nature and Division of Geography.

GEOGRAPHY is a Science concern­ing the measure and distinction of the Earthly Globe, as it is a Spheri­cal Body composed of Earth and Wa­ter, for that both these do together make but one Globe.

[Page 412] 2. And hence the parts of Geography are two, the one concerns the Earthy part, and the other the Water.

3. The Earthy part of this Globe is common­ly divided into Continents and Islands.

4. A Continent is a great quantity of Land not separated by any Sea from the rest of the World, as the whole Continent of Europe, Asia, and Africa, or the Continents of France, Spain, and Germany.

5. An Island is a part of Earth environed round about with some Sea or other; as the Isle of Bri­tain with the Ocean, the Isle of Sicily with the Me­diterranean, and therefore in Latine it is called Insula, because it is scituate in Salo, in the Sea.

6. Both these are subdivided into Peninsula, Isthmus, Promontorium.

7. Peninsula, quasi pene insula, is a tract of land which being almost encompassed round by water, is joyned to the main land by some little part of Earth.

8. Isthmus is that narrow neck of Land which joyneth the Peninsula to the Continent.

9. Promontorium is a high mountain which shooteth it self into the Sea, the outmost end whereof is called a Cape or Foreland, as the Cape of Good Hope in Africk.

10. The Watry part of this Globe may be also distinguished by diverse Names, as Seas, Rivers, Ponds, Lakes, and such like.

11. And this Terrestrial Globe may be measu­red either in whole, or in any particular part.

12. The measure of this Earthly Globe in whole, is either in respect of its circumference, [...]o its bulk and thickness.

[Page 413] 13. For the measuring of the Earths circumfe­rence, it is supposed to be compassed with a great Circle, and this Circle in imitation of Astrono­mers, is divided into 360 degrees or parts, and each degree is supposed to be equal to 15 com­mon German miles, or 60 miles with us in England, and hence the circumference of the Earth is found, by multiplying 360 by 15, to be 5400 German miles, or multiplying 360 by 60, the circumfe­rence is 21600 English miles.

14. The circumference of the Earth being thus obtained, the Diameter may be found by the common proportion between the Circumference and the Diameter of a Circle, the which accord­ing to Archimedes is as 22 to 7, or according to Van Culen as 1 to 3. 14159. and to bring an U­nite in the first place.

As the circumference 3. 14159. is to 1 the Di­ameter, so is 1 the circumference to 318308 the Diameter, which being multiplied by 5400, the Earths Diameter will be found to be 1718 Ger­man miles and 8632 parts, but being multiplied by 21600, the Diameter will be 6875 English miles, and parts 4528.

15. The measure of the Earth being thus found in respect of its whole circumference and Diame­ter, that which is next to be considered, is the distinction of it into convenient spaces.

16. And this is either Primary or Secon­dary.

17. The Primary distinction of the Earthly Globe into convenient spaces, is by Circles con­sidered absolutely in themselves, dividing the Globe into several parts without any reference to one another.

[Page 416] Dutch Geographer inclines much to the bring­ing back the great Meridian to the Fortunate Islands, more particularly to the Peak a Moun­tain so called from the sharpness in the top, in the Isle Teneriff, which is believed to be the high­est Mountain in the World; therefore the same Iohnson in his greatest Globe of the year 1616, hath drawn the great Meridian in that place, and it were to be wished, that this might be made the common and unchangeable practice.

25. The Horizon is a great Circle, designing so great a Part of the Earth, as a quick sight can discern in an open field; it is twofold Rational and Sensible.

26. The Rational Horizon is that which is supposed to pass through the Center of the Earth, and is represented by the wooden Circle in the Frame, as well of the Celestial, as the Ter­restrial Globe, this Rational Horizon belongeth more to Astronomy than Geography.

27. The Sensible Horizon is that before de­fined, the use of it is to discern the divers risings and settings of the Stars, in divers places of the Earth, and why the days are sometimes longer, and sometimes shorter.

28. The great but less principal Circle upon the Terrestrial Globe is the Zodiack, in which the Sun doth always move. This Circle is de­scribed upon Globes and Maps for ornament sake, and to discover under what part of the Zo­diack the several Nations lie.

29. The lesser Circles are those which do not divide the Terrestial Globe into two equal, but into two unequal Parts, and these by a general name are called Parallels, or Circles aequidistant [Page 417] from the Equinoctial; of which as many may be drawn, as there can Meridians, namely 180 if but to each degree, but they are usually drawn to every ten Degrees in each Quadrant from the AEquator to the Poles.

30. These Parallels are not of the same Magni­tude, but are less and less as they are nearer and nearer to each Pole: and their use is to distin­guish the Zones, Climates and Latitudes of all Countries, with the length of the Day and Night▪ in any Part of the World.

31. Again, a Parallel is either named or un­named.

32. An unnamed Parallel is that which is drawn with small black Circular Lines.

33. A named Parallel is that which is drawn upon the Globe with a more full ruddy and circu­lar Line: such as are the Tropicks of Cancer and Capricorn, with the Arctick and Antarctick Cir­cles, of which having spoken before in the general description of the Globe, there is no need of adding more concerning them now.

CHAP. II.

Of the Distinction or Dimension of the Earthly Globe by Zones and Climates.

HAving shewed the primary distinction of the Globe into convenient spaces by Cir­cles considered absolutely in themselves, we come now to consider the secondary Dimension or di­stinction of convenient spaces in the Globe, by the same Circles compared with one another, [Page 418] and by the spaces contained between those Cir­cles.

2. This secundary Dimension or Distinction of the terrestial Globe into Parts, is either a Zone or a Clime.

3. A Zone is a space of the Terrestial Globe included either between two of the lesser nomi­nated Circles, or between one and either Pole. They are in Number five, one over hot, two over cold, and two temperate.

4. The over hot or Torrid Zone, is between the two Tropicks, continually scorched with the presence of the Sun.

5. The two over cold or Frigid Zones, are scituated between the two polar Circles and the very Poles, continually wanting the neighbour hood of the Sun.

6. The two temperate Zones, are one of them between the Tropick of Cancer and the Ar­ctick Circles and the other between the Tropick of Capricorn and the Antarctick Circle, enjoy­ning an indifferency between Heat and Cold; so that the parts next the Torrid Zone are the hotter, and the parts next the Frigid Zone are the Colder.

7. The Inhabitants of these Zones, in respect of the diversity of their noon Shadows are divi­ded into three kinds, Amphiscii, Heteroscii and Periscii. Those that inhabit between the two Tropicks are called Amphiscii, because that their noon Shadows are diversly cast, sometimes towards the South as when the Sun is more North­ward than their vertical point, and sometimes towards the North, as when the Sun declines Southward from the Zenith.

[Page 419] Those that live between the Tropick of Can­cer and the Arctick Circle or between the Tro­pick of Capricorn and the Antarctick Circle are [...]alled Heteroscii, because the Shadows at noon are cast one only way, and that either North or South. They that inhabit Northward of the Tropick of Cancer have their Shadows always towards the North, and they that inhabit South­ward of the Tropick of Capricorn, have their noon Shadows always towards the South.

Those that inhabit between the Poles and the Arctick or Antarctick Circles are called Periscii, because that their Gnomons do cast their Sha­dows circulary, and the reason hereof is, for that the Sun is carried round about above their Hori­zon in his whole diurnal revolution.

8. The next secundary Dimension or distincti­on of the earthy Globe into convenient parts or spaces, is by Climes.

9. And a Clime or Climate is a space of Earth conteined between three Paralells, the middle­mo [...] whereof divideth it into two equal parts, serving for the setting out the length and short­ness of the days in every Country.

10. These Climates and the Parallels by which they are conteined are none of them of equal quantity, for the first Clime as also the Pa­rallel beginning at the AEquator is larger than the second, and the second is likewise greater than the third.

11. The Antients reckoned but seven Cli­mates at the first, to which Number there were afterward added two more, so that in the first of these Numbers were comprehended fourteen parallels, but in the latter eighteen.

[Page 420] 12. Ptolemy accounted the Paralells 38 each way from the Equator, that is 38 towards the North, and as many towards the South, 24 of which he reckoned by the difference of one quar­ter of an hour, 4 by the difference of half an hour, 4 by an whole hours difference, and 6 by a Months difference, but now the parallels being reckoned by the difference of a quarter of an hour, the Climates are 24 in Number till you come to the Latitude of 66 degrees 31 Minutes, to which are afterwards added 6 Climates more unto the Pole it self, where the Artificial day is 6 Months in length.

13. The distances of all both Climates and Parallels, together with their Latitudes from the AEquator, and difference of the quantity of the longest days, are here fully exprest in the Table following.

[Page 421]

A Table of the Climates belonging to the three sorts of Inhabitants.
Inhabitants be­longing to the several ClimesClimesParalellsLength of the DayPoles Ele­vationBea of the Clime
  012.00.0 
 0   4.18
  112.154.18 
  212.308.34 
 1   8.25
Amphiscii 312.4512.43 
  413.016.43 
 2   7.50
  513.1520.33 
  613.3023.10 
 3   7.3
  713.4527.36 
  814.030.47 
 4   6.9
  914.1533.45 
  1014.3036.30 
 5   5.17
  1114.4539.02 
  1215.041.22 
 6   4.30
  1315.1543.32 
  1415.3045.29 
 7   3.48
  1515.4547.20 
  1616.049.21 
 8   3.13
  1716.1550.13 
  1816.3051.58 
 9   2.44
  1915.4553.17 

 ClimesParalellsLength of the DaysPoles Ele­vationBreadth of the Clime
  2017.0054.29 
 10   2.17
Heteroscii 2117.1555.34 
  2217.3056.37 
 11   2.0
  2317.4557.34 
  2418.0058.26 
 12   1.40
  2518.1559.14 
  2618.3059.59 
 13   1.26
  2718.4560.40 
  2819.0061.18 
 14   1.13
  2919.1561.53 
  3019.3062.25 
 15   1.0
  3119.4562.54 
  3220.0063.22 
 16   0.52
  3320.1563.46 
  3420.3064.06 
 17   0.44
  3520.4564.30 
  3621.0064.49 
 18   0.36
  3721.1565.06 
  3821.3065.21 
 19   0.29
  3921.4565.35 
  4022.0065.47 
 20   0.22
  4122.1565.57 
  4222.3066.00 
 21   0.17
  4322.4566.14 

[Page 423]ClimeParalellsLength of the DayPoles Ele­vationBreadth of the Clime
  4423.0066.20 
 22   0.11
  4523.1566.25 
  4623.3066.28 
 23   0.5
  4723.4566.30 
 244824.0066.310.0

PerisciiHere the Cli­mates begin to be accounted by Months, from 66. 31 where the day is 24 hours long; unto the Pole it self, where it is 6 Months in length.167.15
269.30
373.20
478.20
584.0
690.0

[Page 424] 14. Hitherto we have considered the inhabi­tants of the Earth in respect of the several Zones and Climes into which the whole Globe is divi­ded; there is yet another distinction behind in­to which the inhabitants of the Earth are divi­ded in respect of their site and position in refe­rence to one another, and thus the inhabitants of the Earth are divided into the Perioeci, Antoec [...] and Antipodes.

15. The Perioeci are such as dwell in the same Parallel on the same side of the AEquator, how far distant soever they be East and West, the sea­son of the year and the length of the days being to both alike, only the midnight of the one is the moon to the other.

16. The Antoeci are such as dwell under the same Meridian and in the same Latitude, or Pa­rallel distance from the AEquator, the one North­ward and the other Southward, the days in both places being of the same length, but differ in the Seasons of the year, for when it is Summer in the one it is Winter in the other.

17. The Antipodes are such as dwell Feet to Feet, so as a right Line drawn from the one unto the other, passeth from North to South through the Center of the World. These are distant 180 degrees or half the compass of the Earth, they differ in all things, as Seasons of the year, length of days, rising and setting of the Sun and such like. A matter reckoned so ridi­culous and impossible in former times, that Bo­niface Arch-Bishop of Mentz seeing a Treatise concerning these Antipodes written by Virgilius Bishop of Salisburg, and not knowing what dam­nable Doctrine might be couched under that [Page 425] strange Name, made complaint first to the Duke of Bohemia, and after to Pope Zachary Anno 745 by whom the poor Bishop (unfortunate only in being learned in such a time of Ignorance) was condemned of Heresie, but God hath blest this latter age of the World with more understand­ing, whereby we clearly see those things, which either were unknown, or but blindly guessed at by the Antients.

18. The second part of the Terrestial Globe is the Water which is commonly divided into these parts, or distinguished by these Names, Oceanus, Mare, Fretum, Sinus, Lacus and Flu­men.

19. And first Oceanus or the Ocean is that general Collection of all Waters, which encom­passeth the Earth on every side.

20. Mare the Sea, is a part of the main Ocean, to which we cannot come but through some Fre­tum or Strait, as Mare Mediterraneum. And it takes it name first either from the adjacent Shore, as Mare Adriaticum, from the City of Adria; or secondly from the first discoverer, as Mare Magellanicum, from Magellanus who first found it, or thirdly from some remarkable acci­dent, as Mare Icarium from the drowning of Icarus the Son of Daedalus.

21. Fretum, a Strait is a part of the Ocean penned within some narrow Bounds, and ope­ning a way into some Sea, or out of some Sea in­to the Ocean, as the Strait of Hellespont, Gi­bralter, &c.

22. Lacus, a Lake is a great body or collecti­on of Water, which hath no visible Intercourse with the Sea, or influx into it; as the Lake of [Page 426] Thrasymene in Italy, and Lacus Asphaltites, or the dead Sea in the Land of C [...]naan.

23. Flumen or Fluvius is a water-course con­tinually running, (whereby it differs frum Stag­num a standing Pool) issuing from some Spring or Lake, and emptying it self into some part of the Sea, or some other great River, the mouth or outlet of which is called Ostium.

And thus we have gon over those particulars both of Earth and Water, which appertain to this Science of Geography in the general; We will now proceed to a more particular Conside­ration of the several parts into which the Ter­restial Globe is commonly divided.

CHAP. III.

Of Europe.

THe Terrestial Globe is divided into two parts, known or unknown.

2. The unknown or the parts of the World not fully discovered, are distinguished into North and South, the unknown parts of the World towards the North, are those which lie between the North part of Europe or America and the North Pole; and the unknown parts of the World toward the South, are those which ly between the South part of America and the South Pole.

3. The known parts of the World were antiently these three, Europe, Asia and Africk, to which in latter ages a fourth hath been ad­ded which is called America.

[Page 427] 4. Europe is bounded on the North with the Northern Ocean, and on the South with the Me­diterranean Sea, on the East with the River Ta­nais, and on the West with the Western Ocean, and is contained between the Tropick of Cancer, and the Pole Arctick, or 44 degrees as most do say, taking its beginning Southward from Sicily where the Pole is elevated 36 degrees, and is thence continued to 80 degrees of North Lati­tude, and so the whole Latitude of Europe is in English miles 2640, but some allow to Europe 45 degrees of Latitude, that is in English miles 2700.

5. The Longitude of Europe is reckoned from the furthest part of Spain and the Atlantick Oce­an, to the River Tanais, which some reckon to be 60 Degrees, to one of which Degrees passing through the middle of Europe, they allow fifteen German miles almost, or sixty English, and so the Longitude in German miles is 900, in English 3600.

6. Europe though the least of all the four Quarters of the World, is yet of most renown amongst us: First, because of the temperature of the Air, and fertility of the Soil: Secondly, from the study of Arts, both ingenuous and me­chanical: Thirdly, of the Roman and Greek Monarchies: Fourthly, from the purity and sin­cerity of the Christian Faith: Fifthly, because we dwell in it, and so give it the first place.

7. Europe may be considered as it stands di­vided into the Continent and the Islands: the Continent lying all together, containeth these Countries. 1. Spain. 2. France. 3. Germa­ny. 4. Italy, and the Alpes. 5. Belgium. 6. Den­mark▪ [Page 428] 7. Swethland. 8. Russia. 9. Poland. 10. Hungary. 11. Sclavonia, 12. Dacia, and 13. Greece. Of each of which I will give some short account; as also of the chief Islands as they are dispersed, in the Greek, AEgaean, Cretan and Io [...]ian Seas, with those in the Adriatick, Me­diterranean, and in the British and Northern O­cean.

8. Amongst these I give Spain the first place, as being the most Western Part of all the Conti­nent of Europe environed on all sides with the Sea, except towards France; from which it is separated by the Pyrenaean Hills: but more parti­cularly, it is bounded upon the North with the Cantabrian, on the West with the Atlantick Oce­an, on the South with the Straits of Gibralter, on the East with the Mediterranean, and on the North East with the said Pyren [...]ean Hills. The Figure of it is compared by Strabo to an Oxes hide spread upon the Ground; the Neck whereof being that Isthmus which unites it to France.

9. The greatest length hereof, it reckoned at 800 miles, the breadth where it is broadest at 500, the whole Circumforence 2480 Italian miles: but Mariana measuring the compass of it by the bendings of the Pyrenaean Hills, and the creeks and windings of the Sea, makes the full circuit of it to be 2816 miles of Italian mea­sure.

10. It is situate in the more Southerly Part of the Northern temperate Zone, and almost in the midst of the fourth and sixth Climates; the longest day being 15 hours and a quarter in length in the most Northern Parts hereof: but in the extream South near to Gibralter not above [Page 429] fourteen, which Situation of this Country, ren­dreth the Air here very clear and calm, seldom obscured with mists and vapours, and not so much subject to Diseases as the more Northern Regi­ons are.

11. This Continent is subdivided into the Kingdoms of Navarr. 2. Biscay. 3. Guipusco [...]. 4. Lean and Oviodo. 5. Gallicia. 6. Corduba. 7. Granada. 8. Murcia. 9. Toledo. 10. Castile. 11. Portugal. 12. Valentia. 13. Catalonia. 14. Majorca. And 15. Aragon; but all of them are now united in the Monarchy of Spain.

12. France according to the present dimensi­ons of it, is bounded on the East with a Branch of the Alpes which divide Dauphine and Piemont, as also with the Countries of Savoy, Switzerland, and some Parts of Germany and the Netherlands. On the West with the Aquitanick Ocean, and a Branch of the Pyrenaean Mountains which divide it from Spain. On the North with the English Ocean, and some Parts of Belgium, and on the South with the rest of the Pyrenaean Mountains, and the Mideterranean.

13. The Figure of it is almost square, each side of the Quadrature being reckoned 600 miles in length, but they that go more exactly to work upon it, make the length thereof to be 660 Ita­lian miles, the breadth 570, the whole Circum­ference 2040. It is seated in the Northern tem­perate Zone, between the middle Parallel of the first Clime, where the longest day is 15 hours, and the middle Parallel of the eighth Clime, where the longest day is 16 hours and a half.

14. The Principal Provinces in this flourish­ing [Page 430] Country, are. 1. France specially so called. 2. Champagne. 3. Picardy. 4. Normandy. 5. Bretagne. 6. The Estates of Angiou. 7. La Be­ausio. 8. Nivernois. 9. The Dukedom of Bour­bon. 10. Berry. 11. Poictou. 12. Limosin. 13. Piregort. 14. Quercu. 15. Aquitain. 16. Lan­guedoc. 17. Provence. 18. Daulphine. 19. La Bresse. 20. Lionnois. 21. The Dutchy. 22. The County of Burgundy. 23. The Islands in the Aquitanick and Gallick Ocean: Those of most note are these six. 1. Oleron. 2. Re [...]. 3. Iarsey. 4. Gernsey. 5. Sarke. 6. Aldernay on the shores of Normandy, of which the four last are under the Kings of England.

15. Italy once the Empress of the greatest part of the then known World, is compassed with the Adriatick, Ionian and Tyrrhenian Seas, except it be towards France and Germany, from which it is parted by the Alpes; so that it is in a manner, a Peninsula, or a Demi-Island. But more particularly it hath on the East the lower part of the Adriatick, and the Ionian Sea, by which it is divided from Greece; on the West the River Varus, and some part of the Alpes, by which it is parted from France, on the North in some part the Alpes which divide it from Germany; and on the other, part of the Adria­tick, which divides it from Dalmaria; and on the South the Tyrrhenian and Tuscan Seas, by which it is separated from the main Land of Africa.

16. It containeth in length from Augusta Prae­toria, now called Aost, at the foot of the Alpes, unto Otranto in the most Eastern Point of the Kingdom of Naples 1020 miles; in breadth from [Page 431] the River Varo, which parts it from Provence, to the mouth of the River Arsia in Friuli, where it is broadest, 410 miles; about Otranto, where it is narrowest not above 25 miles; and in the middle parts from the mouth of Peseara in the Adriatick or upper Sea to the mouth of Tiber in the Tuscan or lower Sea, 126 miles. The whole compass by Sea reckoning in the windings and turnings of the shore, comes to 3038 miles; which added to the 410 which it hath by Land, make up in all 3448 miles: but if the Coasts on each side be reckoned by a straight Line, then as Castaldo computes it, it comes to no more than 2550 miles.

17. The whole Country lieth under the first and sixth Climates of the Northern temperate Zone, which it wholly taketh up: so that the longest day in the most Northern Parts is 15 hours and three first parts of an hour; the long­est in the Southern Parts, falling short a full hour of that length.

18. Italy as it stands now is divided into the Kingdoms of Naples, Sicily and Sardinia. 2. The Land or Patrimony of the Church. 3. The great Dukedom of Tuscany. 4. The Common­wealths of Venice, Genoa and Luca. 5. The E­states of Lombardy, that is the Dukedoms of 1. M [...]llain. 2. Mantua. 3. Modena. 4. Parma. 5. Montferrat, and the Principality of Piedmont.

19. To the Peninsula of Italy belong the Alpes, aridge of Hills, wherewith as with a strong and defensible Rampart Italy is assured against France and Germany. They are said to be five days Journey high, covered continually with Snow, [Page 432] from the whiteness whereof they took this name, it doth contain the Dukedom of Savoy; the Seigniory of Geneva; the Country of Wallisland, Switzerland and the Grisons.

20. Belgium, or the Netherlands, is bounded on the East with Westphalin, Gulick, Cleve, and the Land of Triers, Provinces of the higher Ger­many; on the West with the main Ocean, which divides it from Britain; on the North with the River Ems, which parts it from East-Friezeland; on the South with Picardie and Campagne two French Provinces; upon the South-East with the Dukedom of Lorrain.

21. It is in compass 1000 Italian or 280 Ger­man miles, and is situated in the Northern tem­perate Zone, under the seventh, eighth and ninth Climates: the longest day in the midst of the seventh Climate where it doth begin, being 16 hours, iu the beginning of the ninth Climate in­creased to 16 hours 3 quarters, or near 17 hours.

22. It containeth those Provinces which in these later Ages were possessed by the House of Burgundy, that is the Lordship of West-Friezeland, given to the Earls of Holland by Charles the Bald; the Earldom of Zutphen united unto that of Gel­der by Earl Otho of Nassau, and finally the Estate of Groening, Over-Yssel, and some part of Vtrecht, by Charles the Fifth. As it stands now divided between the Spaniards and the States it containeth the Provinces of 1. Flanders. 2. Artois. 3. Hai­nault. 4. The Bishoprick of Cambray. 5. Na­mur. 6. Luxemburg. 7. Limbourg. 8. Luyck­land, or the Bishoprick of Leige. 9. Brabant. 10. Marquisate. 11. Meohlin. The rest of the Ne­therlands [Page 433] which have now for sometime with­drawn their obedience from the Kings of Spain, are 1. Holland. 2. Zeland. 3. West-Friezeland. 4. Vtrecht. 5. Over-Yssel. 6. Gelderland. 7. Zutphen. 8. Groening.

23. Germany is bounded on the East with Prus­sia, Poland, and Hungary; on the West with France, Switzerland and Belgium; on the North with the Baltick Seas, the Ocean, and some part of Denmark; on the South with the Alps which part it from Italy.

24. The length from East to West, that is from the Vistula or Weissel to the Rhine, is estima­ted at 840 Italian miles, the breadth from North to South, that is from the Ocean to the Town of Brixen in Tyrol, 740 of the same miles. So that the Figure of it being near a Square, it may take up 3160 miles in compass, or thereabouts. Si­tuate in the Northern temperate Zone, between the middle Parallels of the sixth and tenth Cli­mates; the longest day in the most Southern Parts being 15 hours and an half, and in the most Northern 17 hours and a quarter.

25. The Principal Parts of this great Conti­nent, are 1. Cleveland. 2. The Estates of the three spiritual Electors, Colen, [...]ntz, and Triers. 3. The Palatinate of the Rhine. 4. Alsatia. 5. Lorrain. 6. Suevia or Schwaben. 7. Bavaria. 8. Austria and its Appendices. 9. The Confedera­tion of Waderaw. 10. Franconia. 11. Wirten­berg. 12. Baden. 13. The Palatinate of North­goia, or the Upper Palatinate. 14. Bohemia and the Incorporate Provinces. 15. Pomerania. 16. Mecklenburg. 17. The Marquisate of Branden­burg. [Page 434] 18. Saxony, and the Members of it. 19. The Dukedom of Brunswick and Lunenburg. 20. The Lantgravedom of Hassia. 21. Westphalen. 22. East-Friezeland.

26. Denmark or Danemark, reckoning in the Additions of the Dukedom of Holstein, and the great Continent of Norway, with the Isles there­of, now all united and incorporated into one E­state is bounded on the East with the Baltick Sea and some part of Sweden; on the West with the main Western Ocean; on the North-East with a part of Sweden; full North with the main fro­zen Seas; and on the South with Germany, from which it is divided on the South-West by the River Albis, and on the South-East by the Trave; a little Isthmus or neck of Land uniting it to the Continent.

27. It lieth partly in the Northern temperate Zone, and partly within the Arctick Circle; ex­tending from the middle Parallel of the tenth Clime, or 55 degree of Latitude where it joyn­eth with Germany, as far as the 71 degree where it hath no other bound but the frozen O­cean; by which account the longest day in the most Southern Parts is 17 hours and a quarter, but in the Parts extreamly North, they have no Night for two whole Moneths, three Weeks, one Day, and about seven hours; as on the other side no day for the like quantity of time, when the Sun is most remote from them, in the other Tro­pick.

28. The whole Body of the Estate consisteth chiefly of three Members. viz. 1. The Duke­dom [Page 435] of Holstein; containing Waggerland, Dil­marsh, Starmaria, and Holstein, especially so call­ed. 2. The Kingdom of Denmark; compre­hending both Iuitlands, part of Scandia, and the Hemodes, or Baltick Islands. 3. The Kingdom of Norway consisting of Norway it self, and the Islands of the Northern Ocean.

29. Swethland is bounded on the East with Muscovy, on the West with the Doferine Hills, which divide it from Norway; on the North with the great frozen Ocean spoken of before; on the South with Denmark, Liefland, and the Baltick Sea.

30. It is situate under the same Parallels and Degrees with Norway, that is, from the first Parallel of the 12 Clime, where the Pole is ele­vated 58 degrees 26 minutes, as far as to the 71 degree of Latitude, by which account the long­est day in the Southern Point is but 18 hours, whereas on the farthest North of all the Coun­trey, they have no Night for almost three whole Moneths together.

31. The whole Kingdom is divided into two Parts, the one lying on the East, the other on the West of the Bay or Gulf of Bodener, being a large and spacious branch of the Baltick Sea, extending from the most Southerly Point of Gothland, as far as to Lapland on the North. According to which Division we have the Provinces of 1. Goth­land. 2. Sweden lying on the West side of the Gulph. 3. Lapland shutting it up upon the North. 4. Bodia or Bodden. 5. Finland on the East side thereof. 6. The Sweedish Islands, where it mingleth with the rest of the Baltick Seas.

32. Russia is bounded on the East by Tartary, [Page 436] on the West with Livonia and Finland, from which it is divided by great mountains and the River Poln, on the North by the frozen Ocean, and some part of Lapland, and on the South by Li­tuania a Province of the Kingdom of Poland, and the Crim Tartar inhabiting on the Banks of Palus Maeotis, and the Euxine Sea. It standeth partly in Europe and partly in Asia, the River Tanais or Don running through it, the common boundary of those great and noted parts of the world.

33. It is scituate North within the Artick Cir­cle so far, that the longest day in Summer will be full six months, whereas the longest day in the southern parts is but 16 hours and an half.

34. It is divided into the Provinces of 1. Mos­covy specially so called. 2. Snol [...]usio, 3. Masaisky, 4. Plesco, 5. Novagrod the great, 6. Corelia, 7. Blarmia, 8. Petzora, 9. Condora, 10 Obdora, 11. Iugria, 12. Severia, 13. Permia, 14. Rozan, 15. Wiathka, 16. Casau, 17. Astracan, 18. Novo­gordia inferiour, 10. The Morduits or Mordua, 20. Worotime, 21. Tuba, 22. Wolodomir, 23. Duina, 24. the Russian Islands.

35. Poland is bounded on the East with Russia, and the Crim-Tartar, from whom it is parted by the River Borysthenes; on the West with Germa­ny, on the North with the Baltick Sea and some part of Russia, on the South with the Carpathian Mountains, which divide it from Hungary, Tran­silvania, and Moldavia. It is of figure round in compass 2600 miles, scituate under the 8 and 12 Climates, so that the longest day in the southern parts is but 16 hours, and about 18 [Page 437] hours in the parts most North.

36. The several Provinces of which this King­dom doth consist, are 1. Livonia, 2. Samogitia, 3. Lituania, 4. Volkinia, 5. Podolia, 6. Russia nigra, 7. Massovia, 8. Podlassia, 9. Prussia, 10. Pomerel­lia, 11. Poland specially so called.

37. Hungary is bounded on the East with Tran­silvania and Walachia, on the West with Sterria, Austria and Moravia, on the North with the Car­pathian mountains which divide it from Poland, and on the South with Sclavonia, and some part of Dacia: it extendeth in length from Presburg a­long the Danow to the borders of Transilvania, for the space of 300 English miles, and 190 of the same miles in breadth.

38. It lieth in the Northern temperate Zone, betwixt the middle parallels of the 7 and 9 Cli­mates, so that the longest Summers day in the Southern parts is but 15 hours and an half, and not above 16 hours in the parts most North.

40. This Country is commonly divided into the upper Hungary and the lower, the upper ly­ing on the North of the River Danow, the lower lying on the South of that River, comprehend­ing all Pannonia inferior and part of Superior, and is now possessed by the King of Hungary and the Great Turk, who is Lord of the most part by Arms and Conquest.

04. Sclavonia is bounded on the East with Servia, Macedonia and Epirus, from which it is parted by the River Drinus, and a line drawn from thence unto the Adriatick, on the West with Carniola in Germany, and Istria in the Seig­niory [Page 438] of Venice, from which last it is divided by the River Arsia; on the North with Hungary, on the South with the Adriatick Sea.

41. It is scituate in the Northern temperate Zone, between the middle Parallels of the sixth and seventh Climates, so that the longest day in Summer is about 15 hours and an half.

42. This Country as it came at last to be di­vided, between the Kings of Hungary and the State of Venice; is distinguished into 1. Windisch­land, 2. Croatia, 3. Bosnia, 4. Dalmatia, 5. Libur­nia or Cantado di Zara, and 6. The Sclavonian I­slands.

43. Dacia is bounded on the East with the Euxine Sea and some part of Thrace; on the West with Hungary and Sclavonia; on the North with Podolia, and some other members of the Realm of Poland, on the South with the rest of Thrace and Macedonia.

44. It lieth on both sides of the Danow front­ing all along the upper and the lower Hungary, and some part of Sclavonia; extended from the 7 Climate to the 10; so that the longest Summers day in the most northern parts thereof, is near 17 hours, and in the most southern 15 hours 3 quarters.

45. The several Provinces comprehended un­der the name of Dacia, are 1. Transilvania, 2. Mol­davia, 3. Walachia, 7. Rascia, 5. Servia, 6. Bulga­ria, the first four in old Dacia, on the North side of the Danow; the two last in new Dacia, on the South thereof.

45. Greece in the present Latitude and ex­tent thereof, is bounded on the East with the [Page 439] Propontick, Hellespont, and AEgean Seas, on the West with the Adriatick; on the North with Mount Haemus which parteth it from Bulgaria, Servia and some part of Illyricum; and on the South with the Sea-Ionian; so that it is in a man­ner a Peninsula or Demi-Island, environed on three sides by the Sea, on the fourth only united to the rest of Europe.

46. It is scituate in the northern temperate Zone, under the fifth and sixth Climates, the longest day being 15 hours.

47. In this Country formerly so famous for learning and government, the several Provin­ces are 1. Peloponnesus, 2. Achaia, 3. Epirus, 4. Al­bania, 5. Macedon, 6. Thrace, 7. The Islands of the Propontick; 8. AEgean, and 9. The Ionian Seas, and 10. finally the Isle of Crete.

And thus I have given you a brief description of those Countries which are comprehended in the Continent of Europe; the Islands in this part of the world are many; I will mention only some few. These two in the British and Northern O­cean, known by the names of Great Britain and Ireland are the most famous, to which may be ad­ded Greenland. In the Mediterranaen Sea you have the Islands of Sicilia, Sardinia, Corsica and Crete, which is now called Candia the greater and the less: As for the other Islands belonging to this part of the world, the Reader may expect a more particular description from them who have or shall write more largely of this subject: This we deem sufficient for our present purpose. Let this then suffice for the description of the first part of the World called Europe.

CHAP. IV.

Of Asia.

ASia is bound on the West with the Medite­ranean and AEgaean Seas, the Hellespont, Propontis, Thracian Bosphorus and the Euxine Sea, the Palus Maeotis, the Rivers Tanais and Du­ina, a Line being drawn from the first of the two said Rivers unto the other, by all which it is parted from Europe; on the North it hath the main Scythick Ocean; but on the East the Indi­an Ocean, and Mare del Eur by which it is sepa­rated from America; on the South the Mediter­ranean, or that part of it, which is called the Carpathian Sea, washing the shoars of Anatolia, and the main Southern Ocean, passing along the Indian, Persian and Arabian Coasts: and finally on the south-west, the red Sea or Bay of Ara­bia, by which it is parted from Affrick. Envi­roned on all sides with the Sea, or some Sea like Rivers, except a narrow Isthmus in the south-west, which joyns it to Africk, and the space of ground (whatsoever it be) between Duina and Tanais, on the North-west which unites it to Europe.

2. It is situated East and West, from the 52 to the 169 degree of Longitude; and North and South from the 82 degree of Latitude to the very AEquator; some of the Islands only ly­ing on the South of that Circle: so that the longest summers day in the southern parts, is but twelve hours, but in the most northern parts hereof almost four whole Months together.

[Page 441] 3. This Country hath heretofore been had in special honour; 1. For the creation of Man, who had his first making in this part of the World. 2. Because in this part of it stood the Garden of Eden, which he had for the first place of his habitation. 3. Because here flou­rished the four first great Monarchies of the As­syrians, Babylonians, Medes and Persians. 4. Because it was the Scene of almost all the memo­rable Actions which are recorded by the pen­men of the Scriptures. 5. Because our Saviour Christ was borne here, and here wrought his most divine Miracles, and accomplished the great work of our Redemption. 6. And final­ly, because from hence all Nations of the World had their first beginning, on the dispersion which was made by the Sons of Noah after their vain attempt at Babel.

4. This part of the World for the better un­derstanding of the Greek and the Roman Stories and the estate of the Assyrian, Babylonian and the Persian Monarchies, to which the holy Scrip­tures do so much relate, we shall consider as di­vided into the Regions of 1. Anatolia or Asia minor. 2. Cyprus. 3. Syria. 4. Arabia. 5. Chal­dea. 6. Assyria. 7. Mesopotamia. 8. Turcoma­nia. 9. Media. 10. Persia. 11. Tartaria. 12. China. 13. India. and 14. the Oriental Islands.

Anatolia or Asia minor.

Anatolia or Asia minor, is bounded on the East with the River Euphrates, by which it is par­ted from the greater Asia; on the West with the Thracian Bosphorus, Propontis, Hellespont, and [Page 442] the AEgean Sea, by which it is parted from Eu­rope; on the North with Pontus Euxinus, called also the black Sea, and Mare Maggiore, and on the South by the Rhodian, Lydian and Pam­philian Seas, several parts of the Mediterranean. So that it is a Demi-Island or Peninsula environed on all sides with water, excepting a small Isthmus or Neck of Land extending from the head of Euphrates to the Euxine Sea, by which it is joy­ned to the rest of Asia.

It reacheth from the 51 to the 72 degree of Longitude, and from the 36 to the 45 degree of Latitude, and lyeth almost in the same posi­tion with Italy, extending from the middle Pa­rallel of the fourth Clime, to the middle Parallel of the sixth, so that the longest summers day in the Southern Parts, is about 14 hours and a half; and one hour longer in those parts which lie most towards the North.

The Provinces into which it was divided be­fore the Roman Conquest were 1. Bithynia. 2. Pontus. 3. Paphlagonia. 4. Galatia. 5. Cappadocia. 6. Armenia Major & Minor. 7. Phrygia minor. 8. Phrygia major. 9. Mysia the greater and the less. 10. Asia specially so called, comprehending AEolis and Ionia. 11. Lydia. 12. Caria. 13. Ly­cia. 14. Lycaonia. 15. Pisidia. 16. Pamphylia. 17. Isauria. 18. Cilicia. 19. The Province of the Asian Isles, whereof the most principal are 1. Tenedos. 2. Chios. 3. Samos. 4. Choos. 5. Ica­ria. 6. Lesbos. 7. Patmos. 8. Claros. 9 Carpa­thos. 10. Rhodes.

Cyprus.

Cyprus is situated in the Syrian and Cilician Seas, extended in length from East to West 200 miles, in breadth 60 the whole compass reck­oned 550, distant about 60 miles from the rocky Shores of Cilicia in Asia minor, and about one hundred from the main Land of Syria.

It is situated under the fourth Climate, so that the longest day in Summer is no more than 14 hours and a half.

Divided by Ptolemy into the 4 provinces of 1. Paphia. 2. Amathasia. 3. Lepathia. 4. Sala­mine.

Syria.

Syria is bounded on the East with the River Euphrates by which it is parted from Mesopota­mia; on the West with the Mediterranean Sea; on the North with Cilicia and Armenia minor, parted from the last by mount Taurus; and on the South with Palestine, and some parts of A­rabia. The length hereof from Mount Taurus to the Edge of Arabia, is said to be 525 Miles; the breadth from the Mediterranean to the Ri­ver Euphrates 470 Miles, drawing somewhat near unto a Square.

The whole Country was antiently divided in­to these six parts. 1. Phoenicia. 2. Palestine. 3. Sy­ria specially so called. 4. Comagena. 5. Palmyrene. and Caelosyria, or Syria Cava.

Arabia.

Arabia hath on the East Chaldaea and the Bay or Gulf of Persia; on the West Palestine, some part of Egypt, and the whole course of the red Sea, on the North the River Euphrates with some parts of Syria and Palestine, and on the South the main southern Ocean. It is in circuit about 4000 Miles, but of so unequal and hete­regeneous Composition, that no general Cha­racter can be given of it, and therefore we must look upon it as it stands divided into Arabia De­serta, 2. Arabia Petraea. 3. Arabia Felix and 4. The Arabick Islands.

Chaldea.

Chaldea is bounded on the East with Susiana a Province of Persia; on the West with Arabia deserta; on the North with Mesopotamia; and on the South with the Persian Bay and the rest of Deserta.

Assyria.

Assyria is bounded on the East with Media, from which it is parted by the Mountain called Coathras; on the West with Mesopotamia, from which it is divided by the River Tygris; on the South with Susiana; and on the North with some part of Turcomania; it was antiently divided into six parts. 1. Arraphachitis. 2. Adiabene. 3. Calacine. 4. Aobelites. 5. Apolloniates.

Mesopotamia.

Mesopotamia is bounded on the East with the River Tygris by which it is parted from Assyria; on the West with Euphrates which divides it from Comagena a Province of Syria; on the North with Mount Taurus; by which it is separated from Armenia major; and on the South with Chal­dea and Arabia deserta from which last it is par­ted by the bendings of Euphrates also. It was antiently divided into, 1. Anthemasia. 2. Chal­citis. 3. Caulanitis. 4. Acchabene. 5. Anco­rabitis and 6. Ingine.

Turcomania.

Turcomania is bounded on the East with Media and the Caspian Sea; on the West with the Eux­ine Sea, Cappadocia and Armenia minor; on the North with Tartary, and on the South with Me­sopotamia and Assyria. A Countrey which con­sisteth of four Provinces. 1. Armenia major or Turcomania properly and specially so called. 2. Colchis. 3. Iberia. 4. Albania.

Media.

Media is bounded on the East with Parthia, and some part of Otyrcania, Provinces of the Persian Empire; on the West with Armenia ma­jor, and some part of Assyria; on the North with the Caspian Sea and those parts of Armenia major, which now pass in the account of Iberia, Georgia; and on the South with Persia. It is now [Page 446] divided into two Provinces. 1. Atropatia. 2. Me­dia major.

Persia.

Persia is bounded on the East with India; on the West with Media, Assyria, and Chaldea; on the North with Tartary, on the South with the main Ocean.

It is divided into the particular Provinces of 1. Susiana. 2. Persis. 3. Ormur. 4. Carma­nia. 5. Gedrosia. 6. Drangiana. 7. Aracho­sia. 8. Paropamisus. 9. Aria. 10. Parthia. 11. Hyrcania. 12. Margiana and 13. Bactria.

Tartaria.

Tartaria is bounded on the East with China, the Oriental Ocean, and the Straits of Ani­an, by which it is parted from America, on the West with Russia and Podolia, a Province of the Realm of Poland; on the North with the main Scythick or frozen Ocean; and on the South with part of China, from which it is separated by a mighty Wall, some part of India, the Ri­ver Oxus parting it from Bactria and Margiana, two Persian Provinces; the Caspian Sea which separates it from Media and Hyrcania; the Cau­casian Mountains interposing between it and Turcomania; and the Euxine Sea which divideth it from Anatolia and Thrace.

It reacheth from the 50 degree of Longitude to the 195 which is 145 degrees from West to East; and from the 40 degree of Northern La­titude, unto the 80, which is within 10 de­grees [Page 447] of the Pole it self, By which accompt it lieth from the beginning of the sixth Clime, where the longest day in Summer is 15 hours, till they cease measuring the Climates, the longest day in the most Northen parts hereof being full six Months, and in the winter half of the Year, the night as long.

It is now divided into these five parts. 1. Tar­taria Precopensis. 2. Asiatica. 3. Antiqua. 4. Zagathay. 5. Cathay.

China.

China is bounded on the North with Altay and the Eastern Tartars, from which it is separated by a continued Chain of Hills, part of those of Ararat, and where that chain is broken off or interrupted, with a great wall extended 400 Leagues in length; on the South partly with Cauchin China a Province of India, partly with the Ocean; on the East with the oriental Ocean, and on the West with part of India and Cathay.

It reacheth from the 130 to the 160 degree of Longitude, and from the Tropick of Cancer to the 53 degree of Latitude; so that it lieth under all the Climes from the third to the ninth inclusively. The longest summers day in the southern parts being 13 hours and 40 Minutes increased in the most northern parts to 16 hours and 3 quarters.

It containeth no fewer than 15 Provinces. 1. Canton. 2. Foquien. 3. Olam. 4. Sisnam 5. Tolenchia. 6. Causay. 7. Minchian. 8. Ochi­an. 9. Honan. 10. Pagnia. 11. Taitan. 12. Quinchen. 13. Chagnian 14. Susnan. 15. Cu­nisay. [Page 448] Besides the provinces of Suehuen, the Island of Chorea and the Island of Cheaxan.

India.

India is bounded on the East with the Orien­tal Ocean and some part of China; on the West with the Persian Empire; on the North with some Branches of Mount Taurus, which divide it from Tartary; on the South with the In­dian Ocean.

Extended from 106 to 159 degrees of Lon­gitude, and from the AEquator to the 44th de­gree of Northern Latitude, by which account it lieth from the beginning of the first to the end of the sixth Clime, the longest Summers day in the southern Parts being 12 hours onely, and in the parts most North 15 hours and a half.

The whole Country is divided into two main parts, India intra Gangem, and India extra Gan­gem.

The Oriental Islands.

The Oriental Islands are 1. Iapan. 2. The Philippine and Isles adjoyning. 3. The Islands of Bantam. 4. The Moluccoes. 5. Those cal­led Sinda or the Celebes. 6. Iava. 7. Borneo. 8. Sumatra. 9. Ceilan. and 10. others of less note.

CHAP. V.

Of Africk.

AFrick is bounded on the East by the Red Sea, and Bay of Arabia, by which it is parted from Asia; on the West by the main At­lantick Oceans interposing between it and Ame­rica; on the North by the Mediterranean Sea, which divides it from Europe and Anatolia; and on the South with the AEthiopick Ocean, se­parating it from Terra Australis incognita or the southern continent, parted from all the rest of the World except Asia only, to which it is joy­ned by a narrow Isthmus not above 60 miles in length.

It is situate for the most part under the Tor­rid Zones, the AEquator crossing it almost in the midst. It is now commonly divided into these seven parts. 1. AEgypt. 2. Barbary or the Roman Africk. 3. Numidia. 4. Lybia. 5. Ter­ra Nigritarum. 6. AEthiopia superior. and 7. AE­thiopia rinferior.

AEgypt.

AEgypt is bounded on the East with Idumea, and the Bay of Arabia; on the West with Bar­bary, Numidia, and part of Lybia; on the North with the Mediterranean Sea; on the South with AEthiopia superior, or the Abyssyn Emperor; it is situate under the second and fifth Climates, so that the longest day in Summer is but thirteen hours and a half.

Barbary.

Barbary is bounded on the East with Cyrenai­ca; on the West with the Atlantick Ocean; on the North with the Mediterranean Sea, the Straits of Gibralter and some part of the Atlan­tick also; on the South with Mount Atlas, by which it is separated from Lybia inferior or the Desarts of Lybia.

It is situated under the third and fourth Cli­mates: so that the longest Summers day in the parts most South, amounteth to 13 hours and 3 quarters, and in the most northern parts it is 14 hours and a quarter. This country is now re­duced to the Kingdoms of 1. Tunis. 2. Tremesch or Algiers. 3. Fesse and 4. Morocco.

Numidia.

Numidia is bounded on the East with Egypt, on the West with the Atlantick Ocean; on the North with Mount Atlas, which parteth it from Barbary and Cyrene; on the South with Lybia Deserta.

Lybia.

Lybia is either Interior or Deserta, Libia inte­rior is bounded on the North with Mount Atlas by which it is parted from Barbary and Cyrenai­ca; on the East with Lybia Marmarica interpo­sed between it and Egypt, and part of AEthiopia superior, or the Habassine Empire; on the South with AEthiopia inferior, and the Land of the Ne­groes; [Page 451] and on the West with the main Atlan­tick Ocean.

Lybia deserta is bounded on the North with Numidia or Biledulgerid; on the South with the Land of the Negroes; and on the West with Gu­lata another Province of the Negroes interposed between it and the Atlantick.

Terra Nigritarum.

Terra Nigritarum or the Land of the Negroes is bounded on the East with AEthiopia Superior; on the West with the Atlantick Ocean; on the North with Lybia deserta and on the South with the Ethiopick Ocean, and part of AEthiopia Inferior.

AEthiopia Superior.

AEthiopia Superior is bounded on the East with the Red Sea and the Sinus Barbaricus; on the West with Lybia Interior, the Realm of Nubia in the Land of the Negroes and part of the Kingdoms of Congo in the other AEthiopia; on the North with Egypt and Lybia Marmarica, and on the South with the Mountains of the Moon, by which it is parted from the main Body of AEthiopia Inferior.

It is situate on both sides of the AEquinoctial, extending from the South Parallel of seven de­grees, where it meeteth with some part of the other AEthiopia to the Northern end of the Isle of Meroz situated under the fifth Parallel on the North of that Circle.

AEthiopia Inferior.

AEthiopia inferior is bounded on the East with the Red Sea; on the West with the Ethiopick Ocean; on the North with Terra Nigritarum, and the higher AEthiopia; and on the South where it endeth, is a point of a Conus, with the main Ocean parting it from the Southern undis­covered Continent. This in Ptolemyes time went under the name of Terra incognita.

CHAP. IV.

Of America.

AMerica the fourth and last part of the World is bounded on the East with the Atlantick Ocean and the Vergivian Seas, by which it is par­ted from Europe and Africa; on the West with the Pacifick Ocean, which divides it from Asia; on the South with some part of Terra Australis incognita, from which it is separated by a long, but narrow Strait, called the Straits of Ma­gellan; the North bounds of it hither to not so well discovered, as that we can certainly af­firm it to be Island or Continent.

It is called by some and that most aptly, The new World; New for the late discovery, and World for the vast greatness of it. The whole is naturally divided into two great Peninsules, whereof that towards the North is called Mexi­cana. That towards the South hath the name of Peruana: the Isthmus which joyneth these two [Page 453] together is very long, but narrow in some pla­ces not above 120 miles from Sea to Sea, in many not above seventeen.

The Northern Peninsula called Mexicana, may be most properly divided into the Continent and Islands: The Continent again into the several Provinces of 1. Estotiland, 2. Nova Francia, 3. Virginia, 4. Florida, 5. California, 6. Nova Gallicia, 7. Nova Hispania, 8. Guntimala. The Southern Peninsula called Peruana, taking in some part of the Isthmus, hath on the Continent the Provinces of 1. Castella Aurea, 2. Nova Granada, 3. Peru, 4. Chile, 5. Paraguay, 6. Brasil, 7. Guiana, and 8. Paria. The Islands which belong to both, are dispersed either in the South­ern Ocean called Mare del Zur, where there is not any one of Note but those called Los Ladro­nes and the Islands of Solomon. Or in the North­ern Ocean called Mare del Noords, reduced unto the Caribes, Porto-Rico, Hispaniola, Cuba and Iamaica. And thus much concerning the real and known parts of the Terrestrial Globe.

CHAP. XV.

Of the Description of the Terrestrial Globe by Maps Vniversal and Particular.

HItherto we have spoken of the true and real Terrestrial Globe, and of the measure thereof by Circles, Zones, and Climates, as it is usually represented by a Sphere or Globe; which must be confessed to be the nearest and the most▪ commensurable to nature: Yet it may also be [Page 454] described upon a plain, in whole or in part many several ways: But those which are most useful and artificial are these two, by Parallelogram and by Planisphere.

2. The description thereof by Parallelogram is thus, the Parallelogram is divided in the midst by a line drawn from North to South, passing by the Azores or Canaries for the great Meridian. Cross to this and at eight Angles, another line is drawn from East to West for the AEquator; then two parallels to each to comprehend the figure, in the squares whereof there are set down four parts of the world rather than the whole: And this way of description though not exact or near to the natural, hath yet been followed by such as ought still to be accounted excellent, and is the form of our plain Charts, and in places near the AEquinoctial may be used without com­mitting any great error; because the Meridians about the AEquinoctial are equi-distant, but as they draw up towards the Pole, they do upon the Globe come nearer and nearer together, to shew that their distance is proportionably dimi­nished till it come to a concurrence, and answe­rably the Parallels as they are deeper in latitude, so they grow less and less with the Sphere; so that at 60 degrees, the Equinoctial is double to the parallel of Latitude, and so proportionably of the rest.

3. Hence it followeth, that if the picture of the earth be drawn upon a Parallelogram, so that the Meridians be equally distant throughout, and the Parallels equally extended, the Parellel of 60 degrees shall be as great as the line of the AEqua­tor it self is, and he that coasteth about the world [Page 455] in the latitude of 60 degrees, shall have as far to go by this Map, as he that doth it in the AEqua­tor, though the way be but half as long. For the longitude of the Earth in the AEquator it self, is 21600; but in the Parallel of 60 but 10800 miles. So two Cities under the same parallel of 60, shall be of equal Longitude to other two un­der the Line, and yet the first two shall be but 50, the other two an hundred miles distant. So two Ships departing from the AEquator at 60 miles distance, and coming up to the Parallel of 60, shall be thirty miles nearer, and yet each of them keep the same Meridians and sail by this Card upon the very points of the Compass at which they set forth. This was complained of by Martin Cortez and others, and the learned Mercator considering well of it, caused the de­grees of the Parallel to increase by a proportion towards the Pole. The Mathematical Genera­tion whereof, Mr. Wright in the second Chapter of his Correction of Errors in Navigation, hath sought by the inscription of a Planisphere into a Concave Cylinder. And this description of the Earth upon a Parallelogram, may indeed be so ordered by Art, as to give a true account of the scituation and distance of the parts, but can­not be fitted to represent the figure of the whole.

4. The description therefore of the whole by Planisphere is much better, because it represents the face of the Earth upon a plain, in its own proper Spherical Figure as upon the Globe it self. This description cannot well be contrived upon so few as one Circle or more than two.

Suppose then the Globe to be divided into [Page 456] two equal parts or Hemispheres, which cannot be done but by a great Circle: And therefore it must be done by the AEquator or Meridian (for the Colure is all one with the Meridian) the Ho­rizon cannot fix, and the Zodiack hath nothing to do here.

5. Suppose then the Globe to be flatted upon the plain of the AEquator, and you have the first way of projection dividing the Globe into the North and South Hemispheres.

In this projection the Pole is the Centre, the AEquator is the Circumference divided into 360 degrees of Longitude, the Paralles are whole Circles, the Meridians are streight lines, the Parallels are Parallels indeed, and the Meridians equi-distantly concur, and therefore all the de­grees are equal. After this way of projection, Ptolemy describes that part of the habitable world which was discovered to his time.

6. Suppose the Globe to be flatted upon the plain of the Meridian, and you have the other way of projection; the AEquator here is a streight line, the great Meridian a whole Circle, in this Section the Meridians do not equi-distantly con­cur, the Parallels are not Parallels indeed, and therefore the degrees are all un­equal.

However, this latter way is that which is now most and indeed altogether in use.

7. Particular Maps are but limbs of the Globe, and therefore though they are drawn asunder, yet are they still to be done with that proportion, as a remembring eye may suddenly acknowledge, and joyn them to the whole Body.

[Page 457] The Projection is most commonly upon a Paral­lelogram, in which the Latitude is to be expres­sed by Paralles from North to South, and the Longtitude by Meridians from West to East at 10 or 15 degrees distance, as you please, and may be drawn either by circle or right Lines; but if they be right Lines, the Meridians are not to be drawn parallel, but inclining and concur­ring, to shew the nature of the whole, whereof they are such parts. For the Graduation; the degrees of Longitude are most commonly divi­ded upon the North and South sides of the Pa­rallelogram; the degrees of Latitude upon the East and West sides, or otherwise upon the most Eastern or Western Meridian of the Map, within the square. But it hath seemed good to some in these particular descriptions to make no graduation or projection at all; but to put the matter off to a scale of Miles, and leave the rest to be believed.

The difference of Miles in several Countries is great, but it will be enough to know that the Italian and English, are reckoned for all one, and four of these do make a German Mile; two a French League. The Swedish or Danish Mile consisteth of 5 Miles English and somewhat more. Sixty common English and Italian Miles answer to a degree of a great Circle.

Now as the Miles of several Countries do ve­ry much differ, so those of the same do not ve­ry much agree: and therefore the scales are com­monly written upon with Magna, Mediocria and Parva, to shew the difference. In some Maps you shall find the Miles thus hiddenly set down, and the meaning is, that you should measure the [Page 458] Milliaria magna upon the lowermost Line, the Parva upon the uppermost, and the Mediocria upon the middlemost.

Scala Milliarium.

[figure]

The use of the Scale is for the measuring the distances of places in the Map, by setting one foot of your Compasses in the little circle repre­senting one place, and the other foot in the like little circle representing another, the Compasses kept at that distance being applied to the Scale, will shew the number of great or middle Miles according as the inhabitants of those places are known to reckon.

Soli Deo Gloria.

[Page 459]

A View of the more Notable Epochae
Epochae.Years of the Julian Period.Months
The Julian Period1Ian. 1
Creation of the World765Ian. 1
AEra of the Olympiades3938Iuly 8
The building of Rome4961Ap. 21
Epochae of Nabonasser3667Feb. 26
The beginning of Metons Cyrcle.4281Iune 26
The beginning of the periods of Calippus4384Iune 28
The Death of Alexander the great4390No. 12
AEra of the Caldees4403Oct. 15
The AEra of Dionysrus4429Mar. 25

The beginning of the Christian AEra falls in the 4713 year of the Julian Period.Years of ChristMonth
The Dioclesian AEra284Aug. 29
The Turkish AEra or Hegyra622Iuly 16
The Persian AEra from Iesdagird632Iune 16
The AEra from the Persian Sultan1079Mar. 14

Days in the Year of
Julian AccomptAEgypt and Persian Accompt
1000 365250 1000 365000
2000 730500 2000 730000
3000 1095750 3000 1095000
4000 1461000 4000 1460000
5000 1826250 5000 1825000
6000 2191500 6000 2190000
7000 2556750 7000 2555000
8000 2922000 8000 2920000
9000 3287250 9000 3285000
10000 3652500 10000 3650000

Days in Julian MonthsDays in AEgyptian MonthsDays in Persian Months
ComonBissexThoth 30Pharvadin 30
Ianuary 3130Paophi 60Aripehast 60
February 5960Athyr 90Chortat 90
March 9091Chaeae 120Tirma 120
April 120121Tybi 150Mertat 150
May 151152Michir 180Sachriur 180
Iune 181182Phamenoth 210Macherma 210
Iuly 212213Pharmuthi; 240Apenina Wahak 245
August 243244Pachon 270
September 273274Payny 300Aderma 275
October 304305Ephephi 330Dima 305
November 334335Mesori 330Pechmam 335
December 365366Epagomena 365Aphander 365

Days in Turkish or Arabical YearsDays in Turkish Months
1354 Muharran 30
2709 Sapher 59
3.1063 Rabie 1. 89
4.1417 Rabie 2. 118
5.1772 Giumadi 1. 148
6.2126 Giumadi 2. 177
7.2480 Regeb 207
8.2835 Sahahen 236
9.3189 Ramaddan 266
10.3543 Scheval 295
11.3898 Dulkadati 325
12.4252 Dulhajati Dsilhitts­che true 354
13.4607 
14.4961 
15.5315 In anno A­bundanti 355
16.5670 
17.6024  
18.6378  
19.6733  
20.7087  
21 7442   
22 7796   
23 8150   
24 8505   
25 8859   
26 9213   
27 9568   
28 9922   
29 10276   
300106310  
600212620  
900318930  
1200425240  
1500531550  
1800637860  
2100744170  
2400050480  
2700956790  
30001063100  

 IanuaryFebruaryMarch
13ACircumcis. DPurificat3D 
2 B 11E  E 
311C 19F 11F 
4 D 8G  G 
519E  A 19A 
68FEpiphany16B 8B 
7 G 5C  C 
816A  D 16D 
95B 13E 5E 
10 C 2F  F 
1113D  G 13G 
122E 10A 2A 
13 F  B  B 
1410G 18C 10C 
15 A 7D  D 
1618B  E 18E 
177C 15F 7F 
18 D 4G  G 
1915E  A 15A 
204F 12B 4B 
21 G 1C  C 
2212A  D 12D 
231B 9E 1E 
24 C  F  F 
259DConv. S. Paul17GS. Matthias9GAnunc.
26 E 6A  A 
2717F  B 17B 
286G 14C 6C 
29 A     D 
3014B    14E 
313C    3F 

 AprilMayIune
1 G 11BPhil. & Jac. E 
211A  C 19F 
3 B 19D 8G 
419C 8E 16A 
58D  F 5B 
616E 16G  C 
75F 5A 13D 
8 G  B 2E 
913A 14C  F 
102B 2D 10G 
11 C  E  AS. Barnaby
1210D 10F 18B 
13 E  G 7C 
1418F 18A  D 
157G 7B 15E 
16 A  C 4F 
1715B 15D  G 
184C 4E 12A 
19 D  F 1B 
2012E 12G  C 
211F 1A 9D 
22 G  B  E 
239A 9C 17F 
24 B  D 6GS. John B.
2517CMark Evang.17E  A 
266D 6F 14B 
27 E  G 3C 
2814F 14A  D 
295G 3B 11EPet. Ap.
30 A  C  F 
31   11D    

 IulyAugustSeptember
119G 8C 16F 
28A 16D 5G 
3 B 5E  A 
416C  F 13B 
55D 13G 2C 
6 E 2A  D 
713F  B 10E 
82G 10C  F 
9 A  D 18G 
1010B 18E 7A 
11 C 7F  B 
1218D  G 15C 
137E 15A 4D 
14 F 4B  E 
1515G  C 12F 
164A 12D 1G 
17 B 1E  A 
1812C  F 9B 
191D 9G  C 
20 EMargaret A 17D 
219F 17B 6ES. Matth
22 G 6C  F 
2317A  D 14G 
246B 14EBarthol.3A 
25 C 3F  B 
2614D 11G 11C 
273E 19A 19D 
28 F  B 8E 
2911G 8C  FS. Mich.
309A  D  G 
31 B  E    

 OctoberNovemberDecember
116A  DAll Saints13F 
25B 13EAll Souls2G 
313C 2F  A 
42D  G 10B 
5 E 10AP. Conspir. C 
610F  B 18D 
7 G 18C 7E 
818A 7D  F 
97B  E 15G 
10 C 15F 4A 
1115D 4G  B 
124E  A 12C 
13 F 12B 1D 
1412G 1C  E 
1513A  D 9F 
16 B 9E  G 
179C  F 17A 
18 DLuke Evang.17G 6B 
1917E 6A  C 
206F  B 14D 
21 G 14C 3ES. Thomas
2214A 3D  F 
233B  E 11G 
24 C 11F 19A 
2511D 19G  BChri. Nat.
2619E  A 8CS. Steph.
27 F 8B  DS. John
288GSim. & Jude C 16EInnocents
29 A 16D 5F 
3016B 5ES. Andrew G 
315C    13ASylvester

[Page 465]

 IanuaryFebruaryMarch
1*AXXIXD*D
2XXIXBXXVIIIEXXIXE
3XXVIIICXXVIIFXXVIIIF
4XXVIID25. XXVIGXXVIIG
5XXVIEXXV. XXIVAXXVIA
625. XXVFXXIIIB25. XXVB
7XXIVGXXIICXXIVC
8XXIIIAXXIDXXIIID
9XXIIBXXEXXIIE
10XXICXIXFXXIF
11XXDXVIIIGXXG
12XIXEXVIIAXIXA
13XVIIIFXVIBXVIIIB
14XVIIGXVCXVIIC
15XVIAXIVDXVID
16XVBXIIIEXVE
17XIVCXIIFXIVF
18XIIIDXIGXIIIG
19XIIEXAXIIA
20XIFIXBXIB
21XGVIIICXC
22IXAVIIDIXD
23VIIIBVIEVIIIE
24VIICVFVIIF
25VIDIVGVIG
26VEIIIAVA
27IVFIIBIVB
28IIIGICIIIC
29IIA  IID
30IB  IE
31*C  *F

 AprilMayIune
1XXIXGXXVIIIBXXVIIE
2XXVIIIAXXVIIC25. XXVIF
3XXVIIBXXVIDXXV. XXIVG
425. XXVIC25. XXVEXXIIIA
5XXV. XXIVDXXIVFXXIIB
6XXIIIEXXIIIGXXIC
7XXIIFXXIIAXXD
8XXIGXXIBXIXE
9XXAXXCXVIIIF
10XIXBXIXDXVIIG
11XVIIICXVIIIEXVIA
12XVIIDXVIIFXVB
13XVIEXVIGXIVC
14XVFXVAXIIID
15XIVGXIVBXIIE
16XIIIAXIIICXIF
17XIIBXIIDXG
18XICXIEIXA
19XDXFVIIIB
20IXEIXGVIIC
21VIIIFVIIIAVID
22VIIGVIIBVE
23VIAVICIVF
24VBVDIIIG
25IVCIVEIIA
26IIIDIIIFIB
27IIEIIG*C
28IFIAXXIXD
29*G*BXXVIIIE
30XXIXAXXIXCXXVIIF
31  XXVIIID  

 IulyAugustSeptember
1XXVIGXXV. XXIVCXXIIIF
225. XXVAXXIIIDXXIIG
3XXIVBXXIIEXXIA
4XXIIICXXIFXXB
5XXIIDXXGXIXC
6XXIEXIXAXVIIID
7XXFXVIIIBXVIIE
8XIXGXVIICXVIF
9XVIIIAXVIDXVG
10XVIIBXVEXIVA
11XVICXIVFXIIIB
12XVDXIIIGXIIC
13XIVEXIIAXID
14XIIIFXIBXE
15XIIGXCIXF
16XIAIXDVIIIG
17XBVIIIEVIIA
18IXCVIIFVIB
19VIIIDVIGVC
20VIIEVAIVD
21VIFIVBIIIE
22VGIIICIIF
23IVAIIDIG
24IIIBIE*A
25IIC*FXXIXB
26IDXXIXGXXVIIIC
27*EXXVIIIAXXVIID
28XXIXFXXVIIB25. XXVIE
29XXVIIIGXXVICXXV. XXIVF
30XXVIIA25. XXVDXXIIIG
3125. XXVIBXXIVE  

 October November December 
1XXIIAXXIDXXF
2XXIBXXEXIXG
3XXCXIXFXVIIIA
4XIXDXVIIIGXVIIB
5XVIIIEXVIIAXVIC
6XVIIFXVIBXVD
7XVIGXVCXIVE
8XVAXIVDXIIIF
9XIVBXIIIEXIIG
10XIIICXIIFXIA
11XIIDXIGXB
12XIEXAIXC
13XFIXBVIIID
14IXGVIIICVIIE
15VIIIAVIIDVIF
16VIIBVIEVG
17VICVFIVA
18VDIVGIIIB
19IVEIIIAIIC
20IIIFIIBID
21IIGIC*E
22IA*DXXIXF
23*BXXIXEXXVIIIG
24XXIXCXXVIIIFXXVIIA
25XXVIIIDXXVIIGXXVIB
26XXVIIE25. XXVIA25. XXVC
27XXVIFXXV. XXIVBXXIVD
2825. XXVGXXIIICXXIIIE
29XXIVAXXIIDXXIIF
30XXIIIBXXIEXXIG
31XXIIC  XXA

A Table shewing the Dominical Letter, Gol­den Number and Epact, according to the Ju­lian account for ever, and in the Gregorian, till the Year 1700.
    
16721GFCB
16732EA
16743DG
16754CF
16765BAED
16776GC
16787FB
16798EA
16809DCGF
168110BE
168211AD
168312GC
168413FEBA
168514DG
168615CF
168716BE
168817AGDC
168918FB
169019EA
169120DG
169221CBFE
169322AD
169423GC
169524FB
169625EDAG
169726CF
169827BE
169928AD

YearGJulianGregor.
 NEpactEpact
16721111
167322212
16743323
16754144
167652515
16776626
16787177
167982818
16809929
1681102010
168211121
168312122
1684132313
168514424
168615155
1687162616
168817717
168918188
1690192919
The anticipation of the Gregorian Calender.
  • From 5 October 1582 D. 10
  • From 24 Feb. 1700 D. 11
  • From 24 Feb. 1800 D. 12
  • From 24 Feb. 1900 D. 13
  • From 24 Feb. 2100 D. 14
  • From 24 Feb. 2200 D. 15
  • From 24 Feb. 2320 D. 16
[...]
[...]

[Page 470]

  IIIIVVVIVIIVIII
1P*XIXXIIIIIXIVXXV
2NXXIXXXXIIIXIIIXXIV
3MXXVIIIIXXXIXIIXXIII
4HXXVIIVIIIXIX*XIXXII
5GXXVIVIIXVIIIXXIXXXXI
6FXXVVIXVIIXXVIIIIXXX
7EXXIVVXVIXXVIIVIIIXIX
8DXXIIIIVXVXXVIVIIXVIII
9CXXIIIIIXIVXXVVIXVII
10BXXIIIXIIIXXIVVXVI
11AXXIXIIXXIIIIVXV
12uXIX*XIXXIIIIIXIV
13tXVIIIXXIXXXXIIIXIII
14sXVIIXXVIIIIXXXIXII
15rXVIXXVIIVIIIXIX*XI
16qXVXXVIVIIXVIIIXXIXX
17pXIVXXVVIXVIIXXVIIIIX
18nXIIIXXIVVXVIXXVIIVIII
19mXIIXXIIIIVXVXXVIVII
20lXIXXIIIIIXIVXXVVI
21kXXXIIIXIIIXXIVV
22iIXXXIXIIXXIIIIV
23hVIIIXIX*XIXXIIIII
24gVIIXVIIIXXIXXXXIII
25fVIXVIIXXVIIIIXXXI
26eVXVIXXVIIVIIIXIX*
27dIVXVXXVIVIIXVIIIXXIX
28cIIIXIVXXVVIXVIIXXVIII
29bIIXIIIXXIVVXVIXXVII
30aIXIIXXIIIIVXVXXVI

IXXXIXIIXIIIXIVXV
VIXVIIXXVIIIIXXXIXII
VXVIXXVIIVIIIXIX*XI
IVXVXXVIVIIXVIIIXXIX 
IIIXIVXXVVIXVIIXXVIIIIX
IIXIIIXXIVVXVIXXVIIVIII
IXIIXXIIIIVXVXXVIVII
*XIXXIIIIIXIV25VI
XXIXXXXIIIXIIIXXIVV
XXVIIIIXXXIXIIXXIIIIV
XXVIIVIIIXIX*XIXXIIIII
XXVIVIIXVIIIXXIXXXXIII
XXVVIXVIIXXVIIIIXXXI
XXIVVXVIXXVIIVIIIXIX*
XXIIIIVXVXXVIVIIXVIIIXXIX
XXIIIIIXIVXXVVIXVIIXXVIII
XXIIIXIIIXXIVVXVIXXVI
XXIXIIXXIIIIVXVXXVII
XIX*XIXXIIIIIXIV25
XVIIIXXIXXXXIIIXIIIXXIV
XVIIXXVIIIIXXXIXIIXXIII
XVIXXVIIVIIIXIX*XIXXII
XVXXVIVIIXVIIIXXIXXXXI
XIVXVVIXVIIXXVIIIIXXX
XIIIXXIVVXVIXXVIIVIIIXIX
XIIXXIIIIVXVXXVIVIIXVIII
XIXXIIIIIXIV25VIXVII
XXXIIIXIIIXXIVVXVI
IXXXIXIIXXIIIIVXV
VIIIXIX*XIXXIIIIIXIV
VIIXVIIIXIXXXXIIIXIII

 XVIXVIIXVIIIXIXIII
PXXIIIIVXVXXVIVIIIXIX
NXXIIIIIXIV25VIIXVIII
MXXIIIXIIIXXIVVIXVII
HXXIXIIXXIIIVXVI
GXIX*XIXXIIIVXV
FXVIIIXXIXXXXIIIIXIV
EXVIIXXVIIIIXXXIIXIII
DXVIXXVIIVIIIXIXIXII
CXVXXVIVIIXVIII*XI
BXIV25VIXVIIXXIXX
AXIIIXXIVVXVIXXVIIIIX
uXIIXXIIIIVXVXXVIIVIII
tXIXXIIIIIXIVXXVIVII
tXXXIIIXIII25VI
rIXXXIXIIXXIVV
qVIIIXIX*XIXXIIIIV
pVIIXVIIIXXIXXXXIIIII
nVIXVIIXXVIIIIXXXIII
mVXVIXXVIIVIIIXXI
lIVXVXXVIVIIXIX*
kIIIXIV25VIXVIIIXXIX
iIIXXIIIXXIVVXVIIXXVIII
hIXIIXXIIIIVXVIXXVII
g*XIXXIIIIIXVXXVI
fXXIXXXXIIIXIV25
eXXVIIIIXXXIXIIIXXIV
dXXVIIVIIIXIX*XIIXXIII
cXXVIVIIXVIIIXXIXXIXXII
b25VIXVIIXXVIIIXXXI
aXXIVVXVIXXVIIIXXX

Anni Christi.
NI  
P320  
P580Biss. 
a800Biss.C
b1100Biss.C
c1400Biss.C

Detract is decem di­ebus.
D1484  
D1600Biss. 
C1700  
C1800 CC
B1900  
B2000Biss. 
B2100 C
A2200  
u2300  
A2409Biss.C
u2500  
t2600  
t2700 C
t2800Biss. 
s2900  
s3000 C
r3100  
r3200Biss. 
r3300 C
q3400  
p3500  

Anni Christi.
q3600Biss.C
p3700  
n3800  
n3900  
n4000Biss.C
m4100  
l4200  
l4300 CC
l4400Biss. 
k4500  
k4600 C
i4700  
i4800Biss. 
i4900 C
h5000  
g5100  
h5200Biss.C
g5300  
f5400  
f5500 C
f5600Biss. 
e5700  
e5800 C
d5900  
d6000Biss. 
d6100 C
c6200  
b6300  
c6400Biss.C
b6500  

A Table shewing the Dominical Letter both in the Julian and the Gregorian account for ever.
Cy. ☉1234567
1C BD CE DF EG FA GB A
2ABCDEFG
3GABCDEF
4FGABCDE
5E DF EG FA GB AC BD C
6CDEFGAB
7BCDEFGA
8ABCDEFG
9G FA GB AC BD CE DF E
10EFGABCD
11DEFGABC
12CDEFGAB
13B AC BD CE DF EG FA G
14GABCDEF
15FGABCDE
16EFGABCD
17D CE DF EG FA GB AC B
18BCDEFGA
19ABCDEFG
20GABCDEF
21F EG FA GB AC BD CE D
22DEFGABC
23CDEFGAB
24BCDEFGA
25A GB AC BD CE DF EG F
26FGABCDE
27EFGABCD
28DEFGABC
Anni1582  1900  2300
 1600170018002000210022002400
   2700  3100 
Chr.25002600 29003000  
   2800  32003300

   LXXAsh.East.Asci.Pent.Corp. Chri­sti.Adv.
16XXIII Ian.Feb.Mar.Apr.May.May.Nov.
5XXIId1842230102129
 XXIe19523Ma. 1112230
13XXf2062421223De. 1
2XIXg21725313242
 XVIIIa22826414253
10XVIIb2392751526No. 27
 XVIc2410286162728
18XVd2511297172829
7XIVe2612308182930
 XIIIf27133191930Dec. 1
15XIIg2814Ap. 11020312
4XIa291521121Iun. 13
 Xb3016312222No. 27
12IXc311741323328
1VIIIdFeb. 11851424429
 VIIe21961525530
 VIf320716266Dec. 1
9Vg4218172772
17IVa5229182883
6IIIb6231019299No. 27
 IIc7241120301028
14Id8251221311129
3*e9261322Iun. 11230
 XXIXf10271423213Dec. 1
11XXVIIIg112815243142
 XXVIIa12Ma. 116254153
1925. XXVIb1321726516No. 27
8XXV. XXIVc143182761728
  d154192871829
  e165202981930
  f1762130920Dec. 1
  g187223110212
  a19823Iun. 111223
  b2092421223No. 27
  c2110253132428

A Table to convert Sexagenary Degrees and Minutes into Decimals and the contrary.
10037107320109301454018150
2 38 74 110 146 182 
3 39 75 111 147 183 
40140117621112311484118451
5 41 77 113 149 185 
6 42 78 114 150 186 
7 43 79 115 151 187 
80244128022116321524218852
9 45 81 117 153 189 
10 46 82 118 154 190 
110347138323119331554319153
12 48 84 120 156 192 
13 49 85 121 157 193 
14 50 86 122 158 194 
150451148724123351594419554
16 52 88 124 160 196 
17 53 89 125 161 197 
180554159025126351624519855
19 55 91 127 163 199 
20 56 92 128 164 200 
21 57 93 129 165 201 
220658169426130361664620256
23 59 95 131 167 203 
24 60 96 132 168 204 
25 61 97 133 169 205 
260762179827134371704720657
27 63 99 135 171 207 
28 64 100 136 172 208 
2908651810128137381734820958
30 66 102 138 174 210 
31 67 103 139 175 211 
32 68 104 140 176 212 
3309691910529141391774921359
34 70 106 142 178 214 
35 71 107 143 179 215 
3610722010830144401805021660
[Page 477] 21760253702898032590277777778
218 254 290 326 555555555
219 255 291 327 833333333
22061256712928132891111111111
221 257 293 329 388888889
222 258 294 330 666666667
223 259 295 331 944444444
22462260722968233292222222222
225 261 297 333 500000000
226 262 298 334 777777778
22763263732998333593055555555
228 264 300 336 333333333
229 265 301 337 511111111
230 266 302 338 888888889
23164267743038433994166666667
232 268 304 340 444444444
233 269 305 341 722222222
23465270753068534295000000000
235 271 307 343 277777778
236 272 308 344 555555555
237 273 309 345 833333333
23866274763108634696111111111
239 275 311 347 388888889
240 276 312 348 666666667
241 277 313 349 944444444
24267278773148735097222222222
243 279 315 351 500000000
244 280 316 352 777777778
24568281783178835398055555555
246 282 318 354 333333333
247 283 319 355 611111111
248 284 320 356 888888889
24969285793218935799166666667
250 286 322 358 444444444
251 287 323 359 722222222
252702888032490360100000000000

A Table to Convert Sexagenary Minutes into Decimals and the contrary.
 MinutesSecondsThirds
1004629620000771600000128
20092592515432257
30138888923148385
40185185130864515
5023148140003858000000643
60277777846296771
70324074054012900
803703703617281028
904166667694441157
10046296290007716000001286
11050925920848761414
12055555550925921543
13060185181003081671
14064814801080241800
1506944444001157401929
16074094071234502057
17078703701311722186
18083333331388892314
19087962961466042443
2009259259001543202572
21007222221620362700
22101851851697522829
23106481481774682957
24111111111851843086
2511574074001929003215
26120370372006163343
27125000002083323472
28129629622160483600
29134259262237643729
30138888890023148100003858
[Page 479] 31143518520023967000003986
32148148142469134115
33152777772546294243
34157470402623454372
35162037032700614581
36166666660027777700004629
37171296292854934758
38175925922932094886
39180555553009255015
40185185183086405144
41189814810031635600005272
42194444443240725401
43199074073317885529
44203703703395045658
45208333333472205787
46212962960035493600005915
47217592593626526044
4822222222370 [...]706172
49226851853780846301
50231481483858026430
51236111110039351800006558
52240740744012346687
53245370374089506815
54250000004166666944
55254629634243827073
56259259260043209800007201
57263888884398147330
58268518524475307458
59273148144552567587
60277777770046296200007716

A Table Converting Hours and Minutes into De­grees and Minutes of the AEquator, and into
 Hours.
104.16666667
208.33333333
312.5
416.16666667
520.83333333
625.0
729.16666667
833.33333333
937.5
1041.66666667
1145.83333333
1250.
1354.16666667
1458.33333333
1562.5
1666.66606667
1770.83333333
1875.00
1979.16660667
2083.33333333
2187.5
2291.66666667
2395.83333333
24100.00000000

 Minutes
10.06944444
20.13888888
30.20833333
40.27777777
50.34722222
60.41666666
70.48611111
80.55555555
90.625
100.69444444
110.76388888
120.83333333
130.90277777
140.97222222
151.04166666
161.11111111
171.18055555
181.25
191.31944444
201.38888888
211.45833333
221.52777777
231.59722222
241.66666666
251.73611111
261.80555555
271.875
281.94444444
292.01388888
302.08333333

The Decimal parts of a Day and the contrary.
Seconds MinutesSeconds
.00115740312.15277777.03587963
.00231481322.22222222.03703704
.00347222332.29166666.03819444
.00462962342.36111111.03935185
.00578703352.43055555.04050926
.00694444362.5.04166666
.00810184372.56944444.04282407
.00925925382.63888888.04398148
.01041660392.70833333.04513888
.01157405402.77777777.04629629
.01273148412.84722222.04745370
.01388888422.91666666.04861111
.01504630432.98611111.0497685 [...]
.01620371443.05555555.05092592
.01736111453.125.05208333
.01851853463.19444444.05324074
.01967593473.26388888.05439814
.02083333483.33333333.05555555
.02199074493.40277777.05671296
.02314810503.47222222.05787037
.02430555513.54166666.05902777
.02546295523.61111111.06018518
.02662037533.68055555.06134 [...]59
.02777777543.75.0625
.02893518553.81944444.06365741
.03009259563.88888888.06481481
.03125000573.95833333.06597222
.03240741584.02777777.06712963
.03356482594.09722222.06828704
.03472222604.16666666.06944444

A Catalogue of some of the most eminent Cit­tes and Towns in England and Ireland where­in is shewed the difference of their Meridian from London, with the hight of the Pole.
Names of CittiesDiffer. Merid.Hight Pole
St. Albons0 1 s55.55
Barwick0 6 s55.49
Bedford0 2 s52.18
Bristol0 11 s51.32
Boston0 053.2
Cambridge0 1 a52.17
Canterbury0 5 a51.27
Carlile0 10 s54.57
Chester0 11 s53.20
Coventry0 4 s52.30
Carmarthen0 17 s52.2
Chichester0 3 s50.56
Colchester0 5 a52.4
Darby0 5 s53.6
Dublin in Ireland0 26 s53.11
Duresm [...]0 5 s54.45
Dartmouth0 15 s50.32
Eely0 1 a52.20
Grantha [...]0 2 s52.58
Glocester0 9 s52.00
Halefax0 6 s52.49
Hartford0 1 s52.50
Hereford0 11 s52.14
Huntington0 1 s52.19
Hull0 1 s53.58
Lancaster0 11 s54.08
Leicester0 4 s52.40
[Page 483] Lincoln0 1 s53.12
Middle of the Isle of Man0 17 s54.22
Nottingham0 4 s53.03
Newark0 3 s53.02
Newcastle0 6 s54.58
N. Luffingham0 3 s52.41
Norwich0 4 a52.44
Northampton0 4 s52.18
Oxford0 5 s51.54
Okenham0 3 s52.44
Peterborough0 2 s52.35
Richmond0 6 s54.26
Rochester0 3 a51.28
Ross0 10 s52.07
St. Michaels Mount in Cornwal0 23 s50.38
Stafford0 8 s52.55
Stamford0 2 s52.41
Shrewsbury0 11 s52.48
Tredah in Ireland0 27 s53.28
uppingham in Rutland0 3 s52.40
Warwick0 6 s52.25
Winchester0 5 s50.10
Waterford in Ireland0 27 s52.22
Worcester0 9 s52.20
Yarmouth in Suffolk0 6 a52.45
York0 4 s54.00
London0 0051.32

The Suns mean Longitude and mean Anomaly in AEgyptian Years.
 ☉ Mean Longitude☉ Mean Anomaly
199.933643756399.9288933116
299.867287512699.8577866232
399.800931269099.7866799348
499.734575025399.7155732465
599.668218781699.6444665581
699.601862538099.5733598697
799.535506294399.5022531814
899.469150050699.4211464930
999.402793807099.3600398046
1099.336437563399.2889331162
10093.364375633492.8893311628
100033.643756334128.8933116289

The Suns Mean Anomaly and Praecession of the AEquinox 8 in. 1 AEgyptian Years.
Year.☉ Mean AnomalyPraecession AEquinox.
199.929785731600.0038580246
299.859571463200.0077160493
399.789357194900.0115740740
499.719142926500.0154320987
599.648928658200.0192901234
699.578714389800.0231481481
766.508500111400.0270061728
899.297857316400.0308641975
999.368071584700.0347222221
1099.297857316400.0385802469
10092.978573164200.3858024691
100099.785731642703.8580246913

The Suns mean Longitude and mean Anomaly in Julian Years.
 ☉ Mean Longitude☉ Mean Anomaly
199.933643756399.9288933116
299.867287512699.8577866232
399.800931268999.7866799348
B 400.00836583099.9892901234
599.942009586499.9181834350
699.87563342799.8470767466
799.809297099099.7759700583
B 800.016731660299.9785802468
999.950375416599.9074735584
1099.884019172899.8363668700
1199.817662929199.7652591816
B 1200.025097490399.9678703702
1399.958741246699.8967636818
1499.892385002999.8256569934
1599.826028759299.7545503050
B 1600.033463320599.9571604936
1799.967107076899.8860548052
1899.900750833199.8149481168
1999.834394589499.7438414284
B 2000.041829150699.9164506171
4000.083658301299.8929012342
6000.125487451899.8393518513
8000.167316602499.7858024684
10000.209145753099. 73225308 [...]5
20000.418201506099.4645061710
30000.627437259099.1967592565
40000.836583012098.9290123420
50001.045728765098.6612654275
60001.254874518098.3935185130
70001. 4640 [...]0271098.1257715985

The ☉ mean Longitude and Anomaly
AEra☉ mean Longitude☉ mean Anomaly
Chr.77. 22400.8641958. 24289.56790
160080. 54891.9752953. 95880.62961
162080. 59074.8903553. 90525.69132
164080. 63257.8054153. 85170.75303
166080. 67440.7204753. 79815.81474
168080. 71623.6355353. 74460.87645
170080. 75806.5505953. 69105.93816
172080. 79989.4666553. 63750.99987
174080. 84172.3817153. 58396.06158
176080. 88265.2967753. 53041.12329
 ☉ mean Lon. in Mon.☉ mean Ano. in Mo.
Ianu.08. 48751.4948808. 48711.14867
Febr.16. 15365.7483216. 15288.96037
Mar.24. 64117.2432024. 64000.10904
April32. 85489.6576032. 85333.47872
May41. 34241.1524841. 34044.62739
Iune49. 55613.5668849. 55377.99708
Iuly58. 04365.0617658. 04089.14575
Aug.66. 53116.5566466. 52800.29442
Sept.74. 74488.9710474. 74133.66410
Octo.83. 23240.4659285. 22844.81277
Nov.91. 44612.8803291. 44178.18245
Dec.99. 93364.3756399. 92889.33116

In Anno [...]issentili; post Februarium adde unum diem & unius dies motum.

[Page 487]

The Suns mean Longitude and mean Anomaly in Days.
 ☉ mean Longitude☉ mean Anomaly
10.27379080480.2737777898
20.54758160960.5475555796
30.82137241440.8213333694
41.09516321921.0951111592
51.3 [...]895402401.3688889490
61.64274482881.6426667388
71.91653563361.9164445286
82.19032643842.1902223184
92.46411724322.4640001082
102.73790804802.7377778980
113.01169885283.0115556878
123.28548965763.2853334776
133.55928046243.5591112674
143.83307126723.8328890572
154.10686207204.1066668470
164.38064287684.3804446368
174.65444368164.6542224266
184.92823448644.9280002164
195.20202529125.2077780062
205.47581609605.4755557960
215.74960690085.7493335858
226.02339770566.0231113756
236.29718851046.2968891654
246.57097931526.5706669552
256.84477012006.8444447450
267.11856092487.1182225348
277.39235172967.3920003246
287.66614253447.6957781144
297.93993333927.9395559042
308.21372414408.2133336940
318.48751494888.4871114838

[Page 488]

The Suns mean Longitude and mean Anomaly in Days
 ☉ Mean Longitude☉ Mean Anomaly.
10.01140795020.0114074079
20.02281590040.0228148158
30.03422385060.0342222237
40.04563180080.0456296316
50.05703975100.0570370395
60.06844770120.0684444474
70.07985565140.0798518553
80.09126360160.0912592632
90.10267155180.1026666711
100.11407950200.1140740790
110.12548745220.1254814869
120.13689540240.1368888948
130.14830335260.1482963027
140.15971130280.1597037106
150.17111925300.1711111185
160.18252720320.1825185264
170.19393515340.1939259343
180.20534310360.2053333422
190.21675105380.2167407501
200.22815900400.2281481580
210.23956695420.2395555659
220.25097490440.2509629738
230.26238285460.2623703817
240.27377770480.2737777896

[Page 489]

The Suns mean Anomaly and Praecession of the AEquinox.
AEra☉ Anomaly.Praecess. AEquinox
Chr.56. 69976.8518520. 49768.51851
160053. 87323.1075126. 67052.46907
162053. 83789.1568726. 74768.51845
164053. 80255.2062326. 82484.56783
166053. 76721.2555926. 90200.61721
168053. 73187.3049526. 97916.66659
170053.69653▪3543127. 05632.71597
172053. 66119.4036727. 13348.76535
174053. 65585.4530327. 21064.81473
176053. 59051.5023027. 28780.86411
 ☉ Anomaly in MonthsPraecess. AEqui­nox in Months
Ianu08. 48718.728130. 00032.76678
Febr.16. 15303.385790. 00062.36258
Mar.24. 64022.113920. 00095.12937
April32. 85362.818570. 00126.83916
May41. 34081.546700. 00159.60594
Iune49. 55422.251340. 00191.31573
Iuly58. 04140.979470. 00224.08251
Aug.66. 52859.707600. 00256.84929
Sept.74. 74200.412250. 00288.55908
Octo.83. 22919.140380. 00321.32587
Nov.91. 44259.845020. 00353.03566
Dec.99. 92978.573150. 00385.80244

[Page 470]

The ☉ mean Anomaly, and Praecession of the AEquinox in Julian Years.
 ☉ mean AnomalyPraecess. AEquinox
199.929785731600.0038580246
299.859571461200.0077160493
399.789357194900.0115740740
B 499.992923168600.0154320987
599.922708900200.0192901233
699.852494631800.0231481479
799.782280363400.0270061725
B 899.985846337200.0308641974
999.915632068800.0347222220
1099.845417800400.0385802466
1199.775203532100.0424382714
B 1299.978769505800.0462962961
1399.908555237400.0501543207
1499.838340969000.0540123453
1599.768126606600.0578703699
B 1699.971692674400.0617283948
1799.901478406000.0655864194
1899.831264737600.0694444440
1999.761049869200.0733024686
B 2099.964615843400.0771604938
4099.929230686800.1543209876
6099.893846530200.2314814814
8099.858462373600.3086419752
10099.827078217000.3858024690
20099.646156434000.7716049380
30099.469234651001.1574074070
40099.292312868001.5432098760
50099.115391085001.9290123450
60098.938469302002.3148148140
70098.761547519002.7006172830

[Page 491]

The Suns mean Anomaly and Praec. of the AEqui. in Days.
D☉ AnomalyPraecess. AEquinox
10.27378023480.0000105699
20.54756046970.0000211398
30.82134070460.0000317097
41.09512093950.0000422797
51.36890117440.0000528496
61.64268140920.0000634195
71.91646164410.0000739894
82.19024187900.0000845593
92.46402211390.0000951292
102.73780234880.0001056993
113.01158258360.0001162692
123.28536281840.0001268391
133.55914305320.0001374090
143.83292328800.0001479789
154.10670352280.0001585488
164.38048375760.0001691187
174.65426399240.0001796886
184.92804422720.0001902585
194.20182446200.0002008284
205.47560469760.0002113986
215.74938493240.0002219685
226.02316516720.0002325384
236.29694540200.0002431083
246.57072563680.0002536782
256.84450587160.0002642481
267.11828610640.0002748180
277.39206634120.0002853879
287.66584557660.0002959580
297.93962581150.0003065279
308.21340704640.0003170979
318.48718728130.0003276678

[Page 492]

The Suns mean Anomaly and Praec. of the AEqui. in Hours
D☉ mean AnomalyPraecess. AEquinox
10.01140750970.0000004404
20.022815019508808
30.034222529313212
40.045630039117616
50.057037548922020
60.06844505870.0000026424
70.079852568430828
80.091260078235232
90.102667588139636
100.114075097844041
110.12548260750.0000048445
120.13689011740.0000052849
130.148297627157253
140.159705136861657
150.171112646566061
160.182520156270465
170.193927665974869
180.20533517610.0000079272
190.216742685883677
200.228150195588081
210.239557705292485
220.250965214996889
230.2623727246101293
240.27378023480.0000105698

THE TABLES OF THE MOONS MEAN MOTIONS.

[Page 494]

The Moons mean Longitude and Apogeon
AEra☽ Mean Longitude☽ Apogaeon
Chr.34.008873456778.8286265432
160002.064429012263.5892746911
162039.165113456689.6540895059
164076.265807901015.7189033207
166013.366502345441.7837191355
168050.467196789867.6485339503
170087.567591234293.9133487651
162029.668580123019.9781635799
174061.769280123046.0429783947
176098.869974567472.1077932095
 ☽ Mean Long. in Mon.☽ Apogaeon in Mont.
Ianu.13.463398489700.9593447922
Febr.15.946467093301.8258497658
Mar.29.409866583002.7851945580
April39.213155444003.7135927440
May.52.676553933704.6729375362
Iune62.479842794705.6013357222
Iuly75.943241284406.5606805144
Aug.89.406639774107.5200253066
Sept.99.209928645108.4484234926
Octo.12.673327134809.4077682848
Nov.22.476615995810.3361664708
Dec.35.940014489311.2955112636

[Page 495]

The Moons mean Anomaly and Node Retrograde
AEra☽ Mean Anomaly☽ Node Retrograde
Chr.55.180246913574.6984567901
160038.475154321178.2198302468
162049.511023950770.7638117283
164060.546903580363.3077932098
166071.582783209955.8517746913
168082.618662839548.3957561728
170093.654542469140.9397376543
172004.690422098733.4837191358
174015.726301728326.0277006173
176026.762181357918.5716820988
 ☽ Mean Ano. in Mon.Node Ret. in Mont.
Ianu.12.504053697500.4559979224
Febr.14.720618327500.8678670136
Mar.27.224672025001.3238649360
April35.499562700001.7651532480
May.48.003616397502.2211511704
Iune56.878507072502.6624394824
Iuly69.382560770003.1184374048
Aug.81.886614467503.5744353272
Sept.90.761505142504.0157236392
Octo.03.265558840004.4717215616
Nov.12.140449515004.9130098736
Dec.24.644503225605.3690078260

The Moons mean Motions in Julian Years.
 ☽ Mean Longitude☽ Apogaeon
135.940014489311.2955112636
271.880028978622.5910225272
307.820043467933.8865337908
B 447.420138888845.2129629629
583.360153378156.5084742265
619.300167867467.8039854901
755.240182356779.0994967537
B 894.840277777790.4259259258
930.780292267001 [...]7214371894
1066.720306756313.0169484530
1102.660321245624.3124597166
B 1242.260416666635.6388888888
1378. [...]00431155946.9344001524
1414.140445665258.2299114 [...]60
1550.080460154569. [...]2 [...]4226706
B 1689.680555555580.8518518518
1725.620570044891.1473631154
1861.560584534102.4428743790
1997.500599023413.7383856426
B 2037.100694440426.0648 [...]48148
4074.201388888852.1296296296
6011.302083333378.1944444444
8048.402777777704.2592592592
10085.503472222230.3240740740
20071.006944444460.648 [...]81 [...]81
30056.510416666690.9722222222
40042.013888888821.2962962962
50027.517361111 [...]51.6003703700
60013.020833333391.9444444442
70098.524305555512.2685185182

[Page 497]

The Moons mean Motions in Julian Years
 ☽ Mean Anomaly☽ Nodes Retrograde
124.644503225605.3690078260
249.289006451210.7380156520
373.933509676816.1070234780
B 402.207175925921.4912037037
526.851679151526.7602115297
65 [...].495182377132.1292193557
776.139685602737.4982271817
B 804.414351851842.9824074074
929.058855077448.3514152334
1053.703358303053.7204230594
1178.347861528659.0894308854
B 1206.621527777764.4736111111
1337.266031003369.8426189371
1455.910534228974.2116267631
1580.555037454579.5806345891
B 1608.828703703785.9648148148
1733.473206929391.3338226408
1858.117710154996.7028304668
1982. [...]62213380502.0718382928
B 2011.0 [...]58796 [...]9707.4560185185
4022.071759259414.9120370370
6033.107638889122.3680555555
8044.143518518829.8040740740
10055.179398148737.2800925925
20010.358706207474.5601851850
30065.538194446111.8402777775
40020.717592594849.1203703700
50075.896990743586.4004629629
60031.076388892223.6805555555
70086.255787040960.9606481480

[Page 498]

The Moons mean Motions in Days.
Days☽ Mean Longitude☽ Apogaeon
103.660109628700.0309466062
207.320219257400.0618932124
310.980328886100.0928398186
414.640438514800.1237864248
518.300548143500.1547330310
621.960657772200.1856796372
725.620767400900.2166262434
829.280877029600.2475728496
932.940986658300.2785194558
1036.601096287000.3094660620
1140.261205915700.3404126682
1243.921315544400.3713592744
1347.581425173100.4023058806
1451.241534801800.4332524868
1554.901644430500.4641990930
1658.561754059200.4951456992
1762.221863687900.5260923054
1865.881973316600.5570389116
1969.542082945300.5879855178
2073.202192574000.6189321240
2176.862302203700.6498787302
2280.522411831400.6808233364
2384.182521460100.7117719426
2487.842631089800.7427185488
2591.502740717500.7736651550
2695.162850346200.8046117612
2798.822959974900.8355583674
2802.483069603600.8665049736
2906.143179232300.8974515798
3009.803288861000.9283981860
3113.463398489700.9593447922

[Page 499]

The Moons mean Motions in Days.
Days☽ Mean Anomaly☽ Node Retrograde
103.629163022500.0147096104
207.258326045000.0294192208
310.887489067500.0441288312
414.516652090000.0588384416
518.145815112500.0735480520
621.774978135000.0882576624
725.404141157500.1029672728
829.033304180000.1176768832
932.662467202500.1323864936
1036.291630225000.1470961040
1139.920793247500.1618057144
1243.549956270000.1765153248
1347.179119292500.1912249352
1450.808282315000.20 [...]9345456
1554.437445337500.2206441560
1658.066608360000.2353537664
1761.695771382500.2500633768
1865.324934405000.2647729872
1968.954097427500.2794825976
2072.583260450000.2941922080
2176.212423472500.3089018184
2279.841586495000.3236114288
2383.470749517500.3383210392
2487.099912540000.3530306496
2590.729075562500.3677402600
2694.358238585000.3824498704
2797.987401607500.3971594808
2801.616564630000.4118690912
2905.245727652500.4265787016
3008.874890675000.4412883120
3112.504053697500.4559979224

[Page 500]

The Moons mean Motions in Hours.
Hours☽ Mean Longitude☽ Apogaeon
100.152504567800.0012894419
200.305009135700.0025788838
300.457513703500.0038683257
400.610018271300.0041577676
500. [...]62522839100.0064172095
600.915027407100.0077366515
701.067531974900.0090260934
801.220036542700.0103155353
901.372541110500.0116049772
1001.525045678600.0128044192
1101.677550246400.0141838611
1201.830054814300.0154733031
1301.982559382100.0167627450
1402.135063949900.0180521869
1502.287568517700.0193416288
1602.440073085500.0206310707
1702.592577653300.0219205126
1802.745082221100.0232099545
1902.897586789100.0244993964
2003.0500 [...]1356000.0257888384
2103.202595925000.0270782803
2203.355100492800.0283677222
2303.507605060700.0296571642
2403.660109628500.0309466061

[Page 501]

The Moons mean Motions in Hours.
Hours☽ Mean Anomaly☽ Node Retrograde
100.151215125900.0006129004
200.302430251800.0012258008
300.453645377800.0018387013
400.604860503700.0024516017
500.756075629600.0030645021
600.907290755600.0036774026
701.058505881500.0042903030
801.209721007400.0049032034
901.360936133300.0055161038
1001.512151259300.0061290043
1101.663366385200.0067419047
1201.814581511200.0073548052
1301.965706637100.0079677056
1401.117011763000.0085806060
1502.268206888900.0091935064
1602.419442014800.009 [...]064068
1702.570657140700.0 [...]04193072
1802.721872266600.0110722076
1902.873087392600.0116451081
2003.9243025 [...]8500.0122580085
2103.175517644500.0128709090
2203.326732770400.0134838004
2303.477947896400.0140967099
2403.629163022300.0147096103

[Page 502]

The Moons mean Motions in Minutes of an Hour
M.☽ M. Long.☽ Apog.☽ M. Au. [...] Retrog.
1.0025414.0000214.0025202.0000102
2.0050828.0000429.0050405.0000204
3.0076242.0000643.0075607.0000306
4.0101656.0000859.0100810.0000408
5.0127070.0001074.0126012.0000510
6.0152484.0001288.0151214.0000612
7.0177898.0001502.0176416.0000714
8.0203312.0001716.0201618.0000816
9.0228726.0001930.0226820.0000918
10.0254141.0002149.0252025.0001021
11.0279555.0002363.0277227.0001123
12.0304969.0002577.0302429.0001225
13.0330383.0002791.0327631.0001327
14.0355797.0003004.0352833.0001429
15.0381211.0003218.0378035.0001531
16.0406624.0003432.0403237.0001633
17.0432038.0003646.0428439.0001735
18.0457452.0003860.0453641.0001837
19.0482867.0004079.0478843.0001939
20.0508284.0004298.0504045.0002041
21.0533696.0004512.0529247.0002143
22.0559110.0004726.0554449.0002245
23.0584524.0004940.0579651.0002347
24.0609938.0005154.0604853.0002442
25.0635352.0005368.0630055.0002544
26.0660766.0005582.0655257.0002642
27.0686180.0005795.0680459.0002744
28.0711594.0006008.0705661.0002846
29.0737008.0006222.0730863.0092948
30.0762422.0006437.0756075.0003064

[Page 503]

The Moons mean Motions in Seconds.
 ☽ M. Long.☽ Apog.☽ M. Au.☊ Retrog.
10000423000000300004200000002
20000847000000700008400000003
30001270000001000012600000005
40001693000001300016800000006
50002116000001600021000000009
60002539000001900025200000010
70002969000002200029400000012
80003392000002500033600000013
90003815000002800037800000015
100004275000003500042000000017
110004658000003800046200000019
120005078000004100050400000020
130005504000004400054600000022
140005930000004700058800000023
150006357000005000063000000025
160006784000005300067200000027
170007207000005600071400000028
180007630000005900075600000029
190008050000006200079800000031
200008470000006500084000000033
210008893000006800088200000035
220009316000007100092400000036
230009736000007400096600000038
240010156000007700100800000039
250010582000008000105000000041
260011008000008300109200000043
270011434000008600113400000044
280011860000008900117600000047
290012287000009200121800000049
300012714000009500126000000051

[Page 504]

Sig. o. &. 61 & 72 & 8
aAEqu. ☊Inclin.AEqu. ☊Inclin.AEqu. ☊Inclin.a
AddilimetisAddilimitisAddilimitis
00.00000300001.06500200001.085001500030
10.00000300001.12888257221.018881452729
20.00055300001.19277254720.953051405528
30.00194299721.25222251660.886661358327
40.0041 [...]299441.30833248880.820551313826
50.00888298881.36166245830.553331266625
60.01472298331.41055242770.686941219424
70.02305297771.45666239720.6241611 [...]2223
80.02416297221.49916236380.564441125022
90.04805296381.53666233050.505551075021
100.06500295551.58000229720.446661025020
110.08555294441.60027226380.388880975019
120.10944293611.62527222770.340000925018
130.13666292501.64472219 [...]60.289720875017
140.16833291111.6577121 [...]550.250830825016
150.20250289721.66277212220.209720775015
160.2411 [...]288331.65805208330.173880725014
170.27472286671.64527204440.141380675013
180. [...]2944285671.62638200550.113050625012
190.37916283611.60194196660.088050572211
200.43277281941.58222192790.067220522210
210.48888180271.53972188610.04916046949
220.54833278331.50333184440.03416041668
230.60694276111.46222180270.02333036387
240.66833274161.41799176140.01500031386
250.73555271041.37027171940.00888026115
260.79805269721.3186 [...]147500.00416020834
270.8641 [...]267221.26527163330.001 [...]4015553
280.93083265001.20833158880.00055010272
290.99611262501.14750154440.00000 [...]05271
301.06500266001.08500140000.00000000000
 Sntract Subtract. Subtract.  
 Sig. 5. & 114 & 103 & 9 

[Page 505]

Aug.Sig. o. N.Incr.1. NorthIncr.2. NorthI ncr. 
 Sig. 6. S. 7. South 8. South  
Lat. or Exc. or Exc. or Exc. 
 Latit. Latit. Latit.  
00.00000000002.49750150004.328882600030
10.08722005272.57277154444.371662625029
20.17444010272.64722158884.413612650028
30.26166015552.72083163334.453882672227
40.34861020832.79361164164.492772697226
50.43555026112.86555171944.530552719425
60.52222031382.93638176114.566662741624
70.60888036383.00666180274.601662761123
80.69527041663. [...]7583184444.635002783322
90.78138046943.14416188614.667222802721
100.86722052223.21166192774.697772819420
110.95277057223.27805196664.726942836119
121.03833062503.34333200554.754722852718
131.12333067503.41055204444.781112866617
141.10805072503.47111208334.805832883316
151.29250077503.53333212224.829162897215
161.37666082503.59444215554.851112911114
171.46027087503.65472219164.871662925013
181.54333092503.71361222774.890552936112
191.62611097503.77138226384.907772944411
201.70805102503.82833229724.923882955510
211.78972107503.88388233054.93833296389
221.87111112503.93805236384.95111297228
231.95166117223.99138239724.96250297777
242.03166121944.04333242774.97250298336
252.11083126664.29416245834.98083298885
262.18972131384.14361248884.98777299444
272.26777135834.19166251664.99301299723
282.34500140554.23861254724.99694299722
292.42166145274.28444257224.99916180001
302.49750150004.32888260005.00000180000
 Sig. 11. S. Sig. 19. S. 9. South  
 Sig. 5. N. 4 N. 3. North  

A Table of the Moons Red. to the El. Subt
As Lat.Sig.0.6 S.1.7 S.2.8 As. Lat.
  Incr. Incr. Incr. 
 Red. Red. Red.  
0.00000000000944401166094720116630
1.00388000550963801194092770113829
2.00750001110980501222090550111128
3.01138001660997201250088330108327
4.01527002221011101277086110105526
5.01888002501025001277083880102725
6.02277003051038801277081380100024
7.02638003331050001305078610097223
8.03000003611058301305076110094422
9.03361004161066601305073050091621
10.03722004721075001333070270086120
11.04083005271080501333067220083319
12.04444005551086101333064160080518
13.04777006111088801333061110077717
14.05111006381091601361058050072216
15.05444006661091601361054720066615
16.05777007221091601361051380063814
17.06111007771086201361048050061113
18.06416008051086101361044440055512
19.0672200833108050133 [...]041110052711
20.07000008611075001333037500047210
21.0730500916106940130503388004169
22.0758300944106110130503027003618
23.0788800972105000130502092003337
24.0811101000103880127702611003056
25.0836101027102770127702222002505
26.0858301055101380127701527002224
27.088230108310000012500113800166 [...]3
28.0905501111098330122200750001112
29.0925001138096380119400388000551
30.0944401166094720116600000000060
 11.5 10.4 9.3  

[Page 507]

A Table shewing the mean Motion of the Moon from the Sun in Years and Months.
AEra☽ à ☉ in Years ☽ à ☉ in Years
Chr.56.8114797531136.0063707331
160021.5206732464272.012741466 [...]
162058.5795367034308.0191121993
164095.6384101604447.4117836215
166032.6972836174583.4181543546
168069.7561560744619.4245250877
170006.8150305314755.4308958208
172043.8739039884894.8235672430
174080.9027774454940.8298379761
176017.99165090241076.8362087092
  1102.8426794423
 Motion of the1242.2353508645
 Moon from the1378.2417215976
 Sun in Months.1414.2480923307
  1550.2544630638
  1689.6471344860
Ian.04.97588354401725.6535052191
Feb.99.79281061601861.6598759522
Mar.04.76869416001997.6662466853
April06.35825888002037.0589181075
  4074.1178362150
May11.33414242406011.1767543225
Iune12.92370714408048.2356724300
Iuly17.899590688010085.2945905375
Aug.22.875474232020070.5891810750
  30055.8837716125
Sept.24.465038952040041.1783621500
Octo.29.440922496050026.4729526875
Nov.31.030487216060011.7675432250
Dec.36.006370733170097.0621337625

[Page 508]

A Table shewing the mean Motion of the Moon from the Sun in Days and Hours.
 ☽ à ☉ in Days. ☽ à ☉ in Hours.
103.3863188240100.1410966176
206.7726376480200.2821932352
310.1589564720300.4232898530
413.5452752960400.5643864706
516.9315941200500.7054830882
620.3179129440600.8465797060
723.7042317680700. [...]876763236
827.0905505920801.1287729412
930.4768694160901.2698695588
1033.86318824001001.4109661766
1137.24950706401101.5520627942
1247.63582588801201.6931594120
1344.02214477201301.8342560296
1447.40846353601401.9753526472
1550. [...]947823600150 [...].1164492648
1654.18110118401602.2575458824
1757.56742000801702.3986425000
1860.95373883201802.5397391176
1964.34005765601902.6808357354
2067.72637648002002.8219323520
2171.11269530402102.9630289708
2274.49901412802203.1041255884
2377.88533295202303.2452222062
2481.27165177602403.3863188240
2584.6579706000  
2688.0442804240  
2791 4306082480  
2894.8169270720  
2998.2032458960  
3001.5895647200  
3104.9758835440  

[Page 509]

A Table shewing the mean Motion of the Moon from the Sun in Minutes.
 ☽ à ☉ in Minutes.
100.0023516102
200.0047032205
300.0070548308
400.00 [...]4064411
500.0117580513
600.0141096617
700.0164612719
800.0188128822
900.0211644924
1000.0235161029
1100.0258677131
1200.0262193233
1300.0305709335
1400.0329225437
1500.0352741539
1600.0376257644
1700.0399773746
1800.0423289848
1900.044680 [...]950
2000.0170322052
2100.0493838154
2200.0517354256
2300.0540870 [...]58
2400.0564386460
2500.0587902562
2600.0611418664
2700.0634934766
2800.0658450868
2900.0681966970
3000.0705483080
 ☽ à ☉ in Minutes.
3100.0728999183
3200.0752515088
3300.0776031390
3400.0799547492
3500.0823063594
3600.0846579696
3700.0870095798
3800.0893611900
3900.0917128002
4000.0940644104
4100.0964160206
4200.0997676308
4300.1011192410
4400.1034708512
4500.1058224614
4600.1081740716
4700.1105256818
4800.1128772920
4900.1152289022
5000.1175805124
5100.1199321226
5200.1222837328
5300.1246353430
5400.1269869532
5500.1293385634
5600.1316901736
5700.1340417838
5800.1363933940
5900.1387450050
6000.1410966152

[Page 510]

A Table shewing the mean Motion of the Moon from the Sun in Seconds.
 ☽ à ☉ in Seconds
100.0000391935
200.0000783870
300.0001175805
400.0001567740
500.0001959675
600.0002351610
700.0002743545
800.0003135480
900.0003527415
1060.0003919350
1100.0004811285
1200.0004703220
1300.0005995155
1400.0005487090
1500.0005879025
1600.00 [...]6270960
1700.0006662895
1800.0007954830
1900.0007446765
2000.0007838700
2100.0008230635
2200.0008622570
2300.0009014505
2400.0009406440
2500.0009798 [...]75
2600.0010190310
2700.0010582245
2800.0010974180
2900.0011366115
3000.0011758050
 ☽ à ☉ in Seconds
3100.0012149985
3200.0012541920
3300.0012933855
3400.0013325790
3500.0013717725
3600.0014109660
3700.0014501595
3800.0014893530
3900.0015285465
4000.0015677400
4100.0016069335
4200.0016461270
4300.0016853205
4400.0017245140
4500.0917637075
4600.0018029010
4700.0018420945
4800.0018812880
4900.0019204815
5000.0019596750
5100 0019988685
5200.0020380620
5300.0020772555
5400.0021164490
5500.0021556425
5600.0021948360
5700.0022340295
5800.0022732230
5900.0023124165
6000.0023516100

[Page]

A Catalogue of some of the most notable fixed Stars according to the observations of Tycho Brahe, and by him rectified to the beginning of the Year of Mans Re­demption, 1601.
The Names of the StarsLongit.Latit.
The first Star of Aries.07.671 ♈7. 8. N 4
The bright Star in the top of the head of Aries.00.583 ♉9. 57. N 3
The South Eye of Taurus.01.169 [...]5. 31. S 1
The North Eye of Taurus.00.801 [...]5. 31. S 1
The bright Star of the Pleiades.06.620 ♉2. 6. S 3
The higher head of Gemini.04.078 [...]4. 11. N 5
The lower head of Gemini.04.921 ♋10. 2. N 2
The bright foot of Gemini.01.069 ♋6. 38. N 2
In the South Arm of Cancer.02.238 ♌6. 48. S 2
The bright Star in the neck of Leo.06.662 ♌5. 8. S 3
The heart of Leo.06.745 ♌ [...].47. N 2
In the extream of the tail of Leo.04.458 ♍0. 26. N 1
In Virgo's Wing; Vindemiatrix.01.217 ♎12. 18. N 1
Virgins Spike.05.074 ♎16. 15. N 3
South Ballance.02.643 ♏1. 59. S 1
North Ballance.03.833 ♏0. 26. N 2
The highest in the Forehead of Scorpio.07.388 ♏8. 35. N 2
The Scorpions heart.01.171 [...]1. 05. N 3
Former of the 3 in the head of Sagittarius.02.203 [...]4. 27. S 1
Northern in the former horn of Capricorn.07.861 [...]1. 24. N 4
The left Shoulder of Aquarius.04.949 ♒7. 22. N 3
In the mouth of the South Fish.03.620 ♓8. 42. N 3
The Polar Star or last Star in the [...]ail of the lesser Bear. 9. 4. N 5
 06.400 [...]66. 02. N 2
[Page] The last Star in the tail of the great Bear,05.888 ♍54. 25. N 2
The Tongu [...] of the Dragon.05.259 ♍76. 17. N 4
Arcturus in the skirt of his Garment.05.181 ♎31. 2. N 1
The bright Star of the North Crown.01.845 ♏44. 23. N 2
The Head of Hercules▪02.921 [...]37. 23. N [...]
The bright S [...]r of the H [...]rp.0 [...].699 [...]61. 47. N [...]
The Head of Medusa.05.727 ♉22. 22. N 3
The bright Star in the Goa [...]s left Shoulder.04.518 ♊22. 50. N 1
The middle of the Serp [...]nts Neck.04.583 ♍25. 35. N 2
The bright Star in the [...]agles Shoulder.07.264 ♑29. 21. N 2
The bright Star in the [...] Tail.02.370 ♒29. 8. N 3
The mouth of Pegas [...]s.07.3 [...]4 ♒22. 7. N 3
The head of And [...]omeda.0 [...].4 [...]0 ♈ [...]5. 42. N 2
In the top of the Triangle.00.366 ♉16. 49. N 4
In the Snout of the Whale.02.643 ♉7. 50. S
The bright Star in the Whales Tail.07.481 ♓20. 47. S 2
Bright Shoulder of Orion.06.444 ♊16.06 S 2
Middlemost in the belt of Orion.04.972 ♊24. 33. S 2
The last in the tail of the Har [...].0 [...].324 ♊38. 26. S 4
The great Dogs mouth Sirius.02.386 [...]38. 30. S 1
The lesser Dog Procyon.05.641 [...]1 [...].57. S 2
In the top of the Ships Stern.01.636 ♌43. 18. S 3
Brightest in Hydra's Heart.06.044 ♌22. 24. S 1
FINIS

THE CONTENTS OF THE First Part, CONTAINING The Practical Geometry or the Art of Surveying.

  • CHapter 1. Of the Definition and Division of Geometry.
  • Chap. 2. Of Figures in the General, more particularly of a Circle and the Affections thereof.
  • Chap. 3. Of Triangles.
  • Chap. 4. Of Quadrangular and Multangular Figures.
  • Chap. 5. Solid Bodies.
  • [Page] Chap. 6. Of the measuring of Lines both Right and Circular
  • Chap. 7. Of the measuring of a Cir­cle.
  • Chap. 8. Of the measuring of plain Triangles.
  • Chap. 9. Of the measuring of Heights and Distances.
  • Chap. 10. Of the taking of Distan­ces.
  • Chap. 11. How to take the Plot of a Field at one Station, &c.
  • Chap. 12. How to take the Plot of a Wood, Park, or other Champian Plane, &c.
  • Chap. 13. The Plot of a Field being taken by an Instrument, how to compute the Content thereof in A­cres, Roods, and Perches.
  • Chap. 14. How to take the Plot of mountainous and uneven Ground, &c.
  • Chap. 15. To reduce Statute measure [Page] into Customary, and the contrary.
  • Chap. 16▪ Of the measuring of solid Bodies.
Tables.
  • A Table of Squares. Page. 99
  • A Table for the Gauging of Wine Ves­sels. 114
  • A Table for the Gauging of Beer and Ale Vessels. 120
  • A Table shewing the third part of the Areas of Circles, in Foot measure and Deoimal parts of a Foot. 132
  • A Table shewing the third part of the Area of any Circle in Foot measure, not exceeding 10 f. circumf. 136
  • A Table for the speedy finding of the length or Circumference answering to any Arch in Degrees and Deci­mal parts. 151
  • A Common Divisor for the speedy [Page] converting of the Table, shewing the Areas of the Segments of a Cir­cle whose Diameter is 2 &c. 154
  • A Table shewing the Ordinates, Arch­es, and A rea [...] of the Segments of a Circle, whose Diameter is [...] &c. 156

The Contents of the Second Part of this Treatise, of the Doctrine of the PRIMUM MOBILE.

  • CHap. 1. Of the General Subject of Astronomy.
  • Chap. 2. Of the Distinctions and Af­fections of Spherical Lines and Arches.
  • Chap. 3. Of the kind and parts of Spherical Triangles, and how to project the same upon the Plane of the Meridian.
  • Chap. 4. Of the solution of Spherical Triangles.
  • Chap. 5. Of such Spherical Problems as are of most general Vse in the Doctrine of the Primum Mobile, &c.

The Contents of the Third Part of this Treatise being an Account of the Civil Year with the reason of the diffe­rence between the Julian and Gregorian Calendars, and the manner of Computing the Places of the Sun and Moon.

  • CHap. 1. Of the Year Civil and Astronomical.
  • Chap. 2. Of the Cycle of the Moon, what it is, how placed in the Ca­lendar, and to what purpose.
  • Chap. 3. Of the use of the Golden Number in finding the Feast of Easter.
  • Chap. 4. Of the Reformation of the [Page] Calendar by Pope Gregory the Thirteenth, &c.
  • Chap. 5. Of the Moons mean Motion and how the Anticipation of the New Moons may be discovered by the Ep [...]ts.
  • Chap. 6. To find the Dominical Let­ter and Feast of Easter according to the Gregorian Account.
  • Chap. 7. How to reduce Sexagenary Numbers into Decimals, and the contrary.
  • Chap. 8. Of the difference of Meri­dians.
  • Chap. 9. Of the Theory of the Suns or Earths motion.
  • Chap▪ 10. Of the finding of the Suns Apogaeon, quantity of Excentricity and middle Motion.
  • Chap. 11. Of the quantity of the tro­pical and sydereal Year.
  • Chap. 12. Of the Suns mean Motion otherwise stated.
  • [Page] Chap. 13. How to calculate the Suns true place by either of the Tables of [...] middle Motion. I [...]
  • Chap. 14. To find the place of the fixed Stars.
  • Chap. 15. Of the Theory of the Moon and the finding the place of her A­pogaeon, quantity of Excentricity, and middle motion.
  • Chap. 16. Of the finding of the place and motion of the Moons Nodes.
  • Chap. 17. How to calculate the Moons true place in her Orbs.
  • Chap. 18. To compute the true Lati­tude of the Moon, and to reduce her place from her Orbit to the Ecli­ptick.
  • Chap. 19. To find the mean Conjun­ctions and Opposition of the Sun and Moon▪

The Fourth Part, or an Intro­duction to Geography.

  • CHap. 1. Of the Nature and Di­vision of Geography.
  • Chap. 2. Of the Distinction or Di­mension of the Earthly Globe by Zones and Climates.
  • Chap. 3. Of Europe.
  • Chap. 4. Of Asia.
  • Chap. 5. Of Africk.
  • Chap. 6. Of America.
  • Chap. 7. Of the description of the Terrestrial Globe, by Maps Vni­versal and Particular.

A Table of the view of the most no­table Epochas.

  • The Iulian Calendar. Page. 461
  • The Gregorian Calendar. 466
  • [Page] A Table to convert Sexagenary De­grees and Minutes into Decimals and the contrary. 476
  • A Table converting hours and mi­nutes into degrees and minutes of the AEquator. 480
  • A Table of the Longitudes and Lati­tudes of some of the most eminent Cities and Towns in England and Ireland. 482
  • A Table of the Suns mean Longitude and Anomaly in both AEgyptian and Iulian Years, Months, Days, Hours and Minutes. 484
  • Tables of the Moons mean motion. 493
  • A Catalogue of some of the most nota­ble fixed Stars, according to the observation of Tycho Brahe, re­ctified to the year 1601. 511

Books Printed for and sold by Thomas Pas­singer at the Three Bibles on the middle of London-Bridge.

THe Elements of the Mathematical Art, commonly called Algebra, expounded in four Books by Iohn Kersey, in two Vol. fol. A mirror or Looking-glass for Saints and Sin­ners, shewing the Justice of God on the one, and his Mercy towards the other, set forth in some thousands of Examples by Sam. Clark, in two Vol. fol.

The Mariners Magazine by Capt. Sam. Sturmy, fol.

Military and Maritime Discipline in three Books, by Capt. Tho. Kent, fol.

Dr. Cudworth's universal Systeme.

The Triumphs of Gods Revenge against the Crying and Execrable sin of wilful and premedi­tated Murther, by Iohn Reynolds, fol.

Royal and Practical Chymistry by Oswaldus Crollius and Iohn Hartman, faithfully rendred into English, fol.

Practical Navigation by Iohn Seller. Quarto.

The History of the Church of Great Britain from the Birth of our Saviour until the Year of our Lord 1667. quarto.

The Ecclesiastical History of France from the first plantation of Christianity there unto this time, quarto.

The book of Architecture by Andrea Palladio, quarto.

[Page] The mirror of Architecture or the ground Rules of the Art of Building, by Vincent Scammozi quarto.

Trigonometry, on the Doctrine of Triangles, by Rich. Norwood, quarto.

Markham's Master-piece Revived, containing all knowledge belonging to the Smith, Farrier, or Horse-Leach, touching the curing of all Disea­ses in Horses, quarto.

Collins Sector on a Quadrant, quarto.

The famous History of the destruction of Troy, in three books, quarto.

Safeguard of Sailers, quarto.

Norwood's Seamans Companion, quarto.

Geometrical Seaman, quarto.

A plain and familiar Exposition of the Ten Commandments, by Iohn Dod, quarto.

The Mariners new Calendar, quarto.

The Seamans Calendar, quarto.

The Seamans Practice, quarto.

The honour of Chivalry do the famous and de­lectable History of Don Belianus of Greece, quarto.

The History of Amadis de Gaul, the fifth part, quarto.

The Seamans Dictionary, quarto.

The complete Canonier, quarto.

Seamans Glass, quarto.

Complete Shipwright, quarto.

The History of Valentine and Orson, quarto.

The Complete Modellist, quarto.

The Boat-swains Art, quarto.

Pilots Sea-mirror, quarto.

The famous History of Montelion Knight of the Oracle, quarto.

The History of Palladine of England, quarto.

[Page] The History of Cleocretron and Clori [...]ma, quarto.

The Arralgnment of lower, idle, froward and unconstant Women, quarto.

The pleasant History of Iack of Newb [...]y, quarto

Philips Mathematical Manual, Octavo.

A prospect of Heaven, or a Treatise of the hap­piness of the Saints in Glory, oct.

Etymologicunt parvum, oct.

Thesaurus Astrologiae, or an Astrological Trea­sury by Iohn Gadbury, oct.

Gellibrand's Epitome, oct.

The English Academy or a brief Introduction to the seven Liberal Arts, by Iohn Newton, D. D. oct.

The best exercise for Christians in the worst times, by I. H. oct.

A seasonable discourse of the right use and a­buse of Reason in matters of Religion, oct.

The Mariners Compass rectified, oct.

Norwood's Epitome, oct.

Chymical Essays by Iohn Beguinus, oct.

A spiritual Antidote against sinful Contagions, by Tho. Doolittle, oct.

Monastieon Fevershamiense; or a description of the Abby of Feversham, oct.

Scarborough's Spaw, oct.

French Schoolmaster, oct.

The Poems of Ben. Iohnson, junior, oct.

A book of Knowledge in three parts, oct.

The Book of Palmestry, oct.

Farnaby's Epigramms, oct.

The Huswifes Companion, and the Husband­mans Guide, oct.

Jovial Garland, oct.

Cocker's Arithmetick, twelves.

The Path Way to Health, twelves.

Hall's Soliloquies, twelves.

[Page] The Complete Servant Maid, or the young Maidens Tu­tor, twelves.

Newton's Introduction to the Art of Logick, twelves.

Newton's Introduction to the Art of Rhetorick, twelves.

The Anatomy of Popery, or a Catalogue of Popish er­rors in Doctrine and corruptions in Worship, twelves.

The famous History of the five wise Philosophers, con­taining the Life of Iehosophat the Hermit. twelves,

The exact Constable with his Original and Power in all cases belonging to his Office, twelves.

The Complete Academy or a Nursery of Complements, twelves.

Heart salve for a wounded Soul, and Eye salve for a blind World, by Tho. Calvert. twelves.

Pilgrims Port, or the weary mans rest in the Grave, twelves.

Christian Devotion or a manual of Prayers, twelves.

The Mariners divine Mate, twelves.

At Cherry Garden Stairs on Rotherhith Wall, are taught these Mathematical Sciences, viz. Arithmetick, Algebra, Geometry, Trigonometry, Surveying, Navigation, Dyalling, Astronomy, Gauging, Gunnery and Fortification: The use of the Globes, and other Mathematical Instruments, the projection of the Sphere on any circle, &c. He maketh and selleth all sorts of Mathematical Instruments in Wood and Brass, for Sea and Land, with Books to shew the use of them: Where you may have all sorts of Maps, Plats, Sea-Charts, in Plain and Mercator, on reasonable Terms.

By Iames Atkinson.
FINIS.

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