HYDROSTATICKS: OR, INSTRUCTIONS CONCERNING WATER WORKS. COLLECT [...]D Out of the Papers OF Sir SAMƲEL MORLAND. CONTAINING The Method which he made use of in this Curious Art.

LONDON: Printed for John Lawrence at the Angel in the Poultrey, over [...]gainst the Compter. 1697.

TO THE READER.

THE following Ta­bles I Received from Sir Samuel Mor­land, amongst the rest of his Mathematical Papers, all of which Kind he was pleased to bestow on me not long before his Death. As for these which I now Pub­lish, he told me particu­larly, [Page]that they contained the Mystery of that Art and nimble Dispatch, which he was Master of, in the Making and Managing of (more especially) such Me­chanical Engines as re­late to the Water; in the Improvement of which sort he was so much happier than the rest of Man­kind. He thought that it might be an acceptable and useful piece of Ser­vice to the World, to range [Page]these Materials in good Order; and where there should be occasion, to add so much light as might make them easily Intelligi­ble to a Common Reader.

How I should do this, he gave me large Directions from his own Mouth, and I have punctually observed them, in the Compleating of this Piece; so that here are plain and easy Rules and Di­rections delivered in a perspi­cuous manner, that guide the [Page]Practitioner into the Con­cisest way of Calculation in these Matters; and almost infallibly secure him from Mistakes and Errors, which are so vexatious and expensive. And I think it is not necessary to give any larger Account of this Treatise. What other of his Papers may hereafter be made Publick, must be left to further Enqui­ry and Consideration.

Joseph Morland.

THE FIRST TABLE. A Table of Square Roots of all Numbers from 1 to 100.

Squ. Num­berSqua. Roots.Diffe­rence
11.000.41
21.410.32
31.730.27
42.000.24
52.240.21
62.450.20
72.650.18
82.830.17
93.000.16
103.160.16
113.320.14
123.460.15
133.610.13
143.740.13
153.870.13
164.000.12
174.120.12
184.240.12
194.360.11
204.470.11
214.580.11
224.690.11
234.800.10
244.900.10
255.000.10
265.100.10
275.200.09
285.290.10
295.390.09
305.480.09
315.570.09
325.660.08
335.740.09
345.830.09
355.920.08
366.000.08
376.080.08
386.160.08
396.240.08
406.320.08
416.400.08
426.480.08
436.560.07
446.630.08
456.710.07
466.780.08
476.860.07
486.930.07
497.000.07
507.070.07
517.140.07
527.210.07
537.280.07
547.350.07
557.420.06
567.480.07
577.550.07
587.620.06
597.680.07
607.750.06
617.810.06
627.870.07
637.940.06
648.000.06
658.060.06
668.120.07
678.190.06
688.250.06
698.310.06
708.370.06
718.430.06
728.490.05
738.540.06
748.600.06
758.660.06
768.720.05
778.770.06
788.830.06
798.870.05
808.940.06
819.000.06
829.060.05
839.110.06
849.170.05
859.220.05
869.270.06
879.330.05
889.380.05
899.430.06
909.490.05
919.540.05
929.590.05
939.640.06
949.700.05
959.750.05
969.800.05
979.850.05
989.900.05
999.950.05
10010.00 

The Ʋse of the foregoing TABLE. To find the Square Root of any given Number as far as Three Figures.

DIstinguish the given Number by Points, as is usual in the Extracting of Square Roots, and observe how many Figures belong to the first Point, which will be either one or two: If only one, then seek that Figure in the fore­going Table of Square Roots, in the first Column from one to nine inclusive, and write out the Root [Page 6]standing directly over-against it in the second Column; and take al­so the next lower difference out of the third Column, which you Multiply by the two next Figures of your given Number, and from the Product cut off two Figures, and add the remainder to the Root first written out. The Sum is the desired Root. But if there be two Figures belonging to the first Point, then seek them in the first Column from 10 to 99 inclusive, and pro­ceed as before.

Example. Extract the Square Root out of 276438. the Num­ber distinguished by the Points standeth thus; 27̣64̣38̣. and the Figures belonging to the first Point are 27. which being look'd in the first Column, you find o­ver against it in the second Co­lumn 520. and in the third Co­lumn [Page 7]the next lower difference 10, which Multiplied by 64 (the two next following Figures in the given Number) the Pro­duct is 640. and cutting off two Figures, the remainder is 6. to be added to 520. and the desired Root is 526.

THE SECOND TABLE. A TABLE of Cube Roots, from 1 to 10, and then continued for every Tenth Number from 10 to 100.

Num­berCube RootsDiffe­rence
11.000.26
21.260.18
31.440.15
41.590.12
51.710.11
61.820.09
71.910.09
82.000.08
92.080.07
102.150.56
202.710.40
303.110.31
403.420.26
503.680.23
603.910.21
704.120.19
804.310.17
904.480.16
1004.640.15
1104.790.14
1204.930.14
1305.070.12
1405.190.12
1505.310.12
1605.430.11
1705.540.11
1805.650.10
1905.750.10
2005.850.09
2105.940.09
2206.040.09
2306.130.08
2406.210.09
2506.300.08
2606.380.08
2706.460.08
2806.540.08
2906.620.07
3006.690.07
3106.770.07
3206.840.07
3306.910.07
3406.980.07
3507.050.06
3607.110.07
3707.180.06
3807.240.07
3907.310.06
4007.370.06
4107.430.06
4207.490.06
4307.550.06
4407.610.05
4507.660.06
4607.720.05
4707.770.06
4807.830.05
4907.880.06
5007.940.05
5107.990.05
5208.040.05
5308.090.05
5408.140.05
5508.190.05
5608.240.05
5708.290.05
5808.340.05
5908.390.04
6008.430.05
6108.480.05
6208.530.04
6308.570.05
6408.620.04
6508.660.05
6608.710.04
6708.750.04
6808.790.05
6908.840.05
7008.890.03
7108.920.04
7208.960.04
7309.000.04
7409.040.05
7509.090.04
7609.130.04
7709.170.04
7809.210.03
7909.240.04
8009.280.05
8109.330.03
8209.360.04
8309.400.04
8409.440.03
8509.470.04
8609.510.04
8709.550.03
8809.580.04
8909.620.03
9009.650.04
9109.690.04
9209.730.03
9309.760.04
9409.800.03
9509.830.03
9609.860.04
9709.900.03
9809.930.04
9909.970.03
100010.00 

The Ʋse of the Second TABLE. To find the Cubick Root of any given Number as far as Three Figures.

DIstinguish the given Number by Points, as is usual in Extracting Cubick Roots. Then to the first Point towards the left Hand, there will belong either one Figure, or two, or three Fi­gures. If it be one, then look the same in the Table of Cubick Roots, from 1 to 9 inclusive, if there be two Figures belonging to the first Point, then look the first of them from 10 to 90 in­clusive, [Page 13]if there be three, look the two first from 100 to 990 inclusive, and write out the Root standing directly over-against it in the Second Column, and the next lower Difference out of the third Column, which you Multiply by the two next Figures of your given Number, and from the Pro­duct cut off two Figures, and add the remainder to the Root first written out: The Sum is the desired Root.

Example. Extract the Cubick Root out of 34̣167̣942̣. The Number distinguished by Points standeth thus: 34167942. and the Figures belonging to the first Point are 34, whereof the first, viz. 3. is to be look'd between 10 and 90. inclusive; and you find 30. and the Root of this in the Second Column 311. to be written out, [Page 14]and the next lesser Difference in the third Column is 31. which Multiplied by 41. (the two next fol­lowing Figures in the given Num­ber) the Product is 1271. and cutting off two Figures, the re­mainder is 12 or 13. (because the Figures cut off, viz. 71. are more than the half of 100.) which ad­ded to 311. (the Root first writ­ten out) the Sum is 324. the de­sired Cubick Root.

THE THIRD TABLE. A TABLE of Cube-Root-Inches, from a Pint to a Gallon, from a Gallon to a Barrel, from a Barrel to a Tun, from One Tun to Se­venty, and from thence by Decimal Steps to 10000.

PintsCube Root Inch.
13.27
24.16
34.72
45.20
55.60
65.95
76.27

[Page 16]

FirkinsGallonsCube Root Inch.
 16.55
 28.26
 39.45
 410.40
 511.21
 611.91
 712.54
 813.11
1)913.63
 1014.12
 1114.58
 1215.01
 1315.41
 1415.80
 1516.17
 1616.52
 1716.86
2)1817.18
 1917.49
 2017.80
 2118.09
 2218.37
 2318.64
 2418.91
 2519.17
 2619.42
3)2719.67
 2819.91
 2920.14
 3020.37
 3120.60
 3220.81
 3321.03
 3421.24
 3521.45
 3621.65
Cube-Root-Inches of Barrels and Tuns.
TunsBarrelsCube Root Inch.
 121.65
 227.28
 331.22
 434.37
 537.02
1) 639.34
 741.42
 843.31
 945.03
 1046.65
 1148.15
2) 1249.57
 1350.91
 1452.18
 1553.40
 1654.56
 1755.67
3) 1856.74
 1957.77
 2058.77
 2159.73
 2260.67
 2361.57
4) 2462.45
 2563.31
 2664.14
 2765.75
 2865.95
 2966.52
5) 3067.28
 3168.01
 3268.74
 3369.45
 3470.14
 3570.82
6) 3671.49
 3772.15
 3872.79
 3973.42
 4074.05
 4174.66
7) 4275.26
 4375.86
 4476.44
 4577.01
 4677.58
 4778.14
8) 4878.69
Cube-Root-Inches of Tuns.
TunsCube Root Inch.
981.84
1084.76
1187.50
1290.07
1392.51
1494.82
1597.03
1699.14
17101.16
18103.11
19104.95
20106.80
21108.55
22110.24
23111.89
24113.49
25115.04
26116.56
27118.03
28119.47
29120.88
30122.25
31123.60
32124.91
33126.20
34127.46
35128.70
36129.91
37131.10
38132.28
39133.40
40134.56
41135.67
42136.76
43137.84
44138.90
45139.94
46140.97
47141.99
48142.99
49143.97
50144.95
51145.91
52146.86
53147.80
54148.71
55149.63
56150.53
57151.42
58152.30
59153.17
60154.03
61154.88
62155.73
63156.56
64157.38
65158.20
66159.01
67159.80
68160.60
69161.38
70162.15
80169.53
90176.32
100182.62
200230.09
300263.39
400289.90
500312.28
600331.85
700349.35
800365.25
900379.88
1000393.46
2000495.73
3000567.47
4000624.58
5000672.81
6000714.96
7000752.66
8000768.92
9000818.43
10000847.68
200001068.06
300001222.57
400001345.61
500001449.52
600001540.34
700001621.56
800001695.37
900001763.25
CM.1826.28

THE Use of this third Table is so Obvious to every Mans Capacity, that it needs no Expla­nation; for if there be occasion to make any Vessel in a Cubical Form, of which the Content ought to be a Pint, a Quart, a Gallon, &c. This Table gives the Cubick Roots of their Re­spective Dimensions.

THE FOURTH TABLE. A TABLE shewing the true Content of Cubick Feet, (from 1 to 5) in Gallons and Cubick Inches, and (from 5 to 1000) in Barrels, Gallons, and Cubick In­ches.

Cubick FeetBarrelsGallonsCubick Inches
10636
201272
3018108
4024144
5030180
6100216
716252
81136
911942
1012578
11131114
1221150
1327186
14213222
15219258
1622612
1723248
183284
1938120
20314156
3053234
4062930
50818108
60107186
701132264
80132260
901511138
1001700216
200341150
30051284
40068318
500853234
6001024168
7001195102
800136636
9001536252
10001707186

The several Ʋses of the Fourth TABLE.

First Use.

ONE Use of this Table is this, viz. either by having given the Dimensions of any Rect­angular Vessel, whose sides are Plain, to find the true Content in Gallons, Barrels, &c. or else, the Content of any such Vessel being given with one of its three Dimensions, to determine the two remaining Dimensions.

First, Let it be required to know the true Content of a Rectan­gular [Page 27]Vessel, of which the length is seven, the breadth three, and the height five Feet.

The Answer is this: 7 into 3 into 5, make 105 Cubick Feet: Now by this Table I find that 100 Cubick Feet contain 17 Barr. 216. Cub. In. and by the same 5 Cubick Feet, contain 30 Gall. 180 Cub. In. which two Sums being added together make 17 Bar. 31 Gall. 114 Cub. In. which is the Content of the aforesaid Vessel.

Again, The Content of a Ves­sel being given (viz. four Bar­rels) and the length of that Vessel (six Feet) let it be re­quired [Page 28]to find the Breadth and Depth.

Answer, By this Table I find that six Cubick Feet contain one Barrel, and 216 Cubick Inches. By this I know the Content of a Vessel, whose Length is six Feet, its Breadth one, and its Height one; therefore two such Ves­sels joined together upon a Plane, or (which is all one) a Vessel six Feet long, two Feet wide, and one Foot deep, contains two Barrels, one Gallon, and one Hundred and fifty Cubick Inches, and by Consequence a Vessel six Feet long, two Feet wide, and two Feet deep, contains four Bar­rels, three Gallons, and eighteen Cubick Inches, which is some­thing over the given Content, but near enough for common use. And by this Method may any [Page 29]Cistern be designed near enough the Truth, with great Ease and Expedition.

But if it be required to per­form these or the like Operati­ons more exactly, the follow­ing Method will guide the Practi­tioner, several Precognita being first laid down.

1. The Original of all long Measures is an Inch, whereof twelve make a Standard English Foot, 36 Inches make a Yard; 72 make a Fathom, 198 make a Perch, 7920 make a Furlong, 65360 make a Mile.

2. The Original of all Square Measures is a Square Inch, where­of 144 make a Square Foot, 1296 make a Square Yard, 39204 [Page 30]make a Square Rod, 6272640 make a Square Acre.

3. Of all Solid Measures the Original is a Cubick Inch, where­of 1728 make a Cubick Foot, 15,552, make a Cubick Yard.

Again 35⌊25 make a Pint, 70⌊5 make a Quart, 282 make a Gallon, 10,152 make a Barrel, or Thirty six Gallons; 60,912 make a Tun or Six Barrels.

4. Any one Number being Multiplied either by it self, or a­ny other Number, and that Pro­duct Multiplied by any third Number make a Solid, or the Content of a Rectangular Cistern, whose sides are plain.

These Precognita being laid [Page 31]down the Operations will be as follow:

For Example, The Content of a Cistern being given, viz. Four Barrels, and the length of that Cistern six Feet: Let it be re­quired to find out two Num­bers, which being Multiplied one into another, and that Product into the given Length, make a Con­tent equal to Four Barrels.

Having first Reduced the given Terms to their least Denomina­tions, the General Rule is this:

The Content of any Rectan­gular Vessel being given toge­ther, with either the length, or breadth, or Depth of that Ci­stern: Divide the given Con­tent by the given Dimension, and the Quotient by any Num­ber [Page 32]less than it self: The last Di­visor and Quotient are the two Terms sought.

Thus having reduced the Four Barrels to 40,608 Inches, and the given 6 Feet to to 72 Inches, I divide the said 40,608 by the said 72. And again I divide the Quotient 564 Inches by a­ny Number less than it self, sup­pose 40, the last Divisor 40, and its Quotient 14⌊1 are the two sides required. And after this Method may infinite Answers be given to this Question; so that the Operator in the second Di­vision may from the given length chuse either what Depth or Breadth he pleases, or from a given given Depth may chuse what [Page 33]Length or Breadth he plea­ses.

The Second Ʋse of the Fourth TABLE.

To Explain this Use it is ne­cessary to premise this following Theorem:

Like Solids are in proportion one to another, as the Cubes of their He­mologous sides.

Upon which Theorem depends this Problem:

Having the Content of a Ci­stern, together with the Ratio of the Length, Breadth and Height given to find the sides.

I. Example, Let it be demand­ed to frame a Cistern contain­ing 1000 Cubick Feet, and the Ratio of the sides or three Di­mensions, let be one two and four.

First, I imagine, or frame in my mind, a Cistern, whose

Length4
Breadth2
Height1

The Content of it is 4×2×1=(8)

Therefore I say,

1. As the Content 8, is to the Content 1000, so is the Cube of the side 4. viz. the Cube 64. to the Cube 8000, whose Cube-Root is=20.

2. As the said 8 to the said 1000. so is the Cube of the side 2. viz. the Cube 8. to the Cube 1000. whose Cube Root is=10.

3. As the said 8 to the said 1000. so is the Cube of the side 1. viz. Cube 1. to the Cube 125. whose Cube Root is=5.

So then of the Cistern demand­ed to be framed, the

Length20
Breadth10
Height5

For 20×10×5=1000; and

  • 1. As 1 to 2, so 5 to 10.
  • 2. As 2 to 4, so 10 to 20.
  • 3. As 1 to 4, so 5 to 20.

II. Example, Let a Cistern be demanded, containing 600 Cu­bick Feet, and the Ratio of the sides, as 3, 4, 5.

First, I frame in my mind a Cistern of 3 4 5, 3×4×5=60. wherefore.

1. As to the Content 60. to the Content 600. so is the Cube of the side 3. viz. the Cube 27 to the Cube 270. whose Cube Root is=6. 463.

2. As the said 60 to the said 600. so is the Cube of the side 4. viz. the Cube 64, to the Cube 640, whose Cube Root is=8. 617.

3. As the said 60 to the said 600. so is the Cube of the side 5. viz. the Cube 125. to the [Page 37]Cube 1250, whose Cube Root is=10. 77 2.

So then

 ContentLengthBreadthheight
Of the gi­ven Cistern60543.
Of the Ci­stern demanded60010.7728.61766⌊4632

For 6.4632 into 8.6176 into 10.7720 is=599. 978.

And

  • 1. As 3 to 4, so is 6.4632 to 8.6176
  • 2. As 4 to 5, so is 8.6176. to 10.7720
  • 3. As 3 to 5, so is 6.4362 to 10.7720.

This Problem being clearly An­swered by the two foregoing Ex­amples; [Page 38]in the first of which the Length, Breadth and Depth of the Cistern, that is required to be designed, are 20, 10 and 5; and its Content 1000 Cubick Feet; and in the second the Length, Breadth and Depth of the Ci­stern that is required to be design­ed are 10,7720, 8.6176 and 6.4632. and its Content 600 Cubcik Feet. The next thing to be done is to Convert their Con­tents into Gallons, Barrels, &c. which is to be done with much ease by this Fourth Table: For by that Table 1000 Cubick Feet (which is the Content of the first Cistern required to be de­signed) contain 170 Bar.—7 Gall.—186. Cub. Inch.

And in the second Example the Content of the Cistern re­quired to be designed, being 600 Cubick Feet; I find by the said Table, that 600 Cubick Feet contain 102 Bar.—4 Gall.—168 Cub. Inch.

The Third Ʋse.

The third Use of this Table relates to Cylindrical Elliptical Vessels; for the better Expla­nation of which there are again several Precognita to be pre­mised.

I. Diam of any CirclePeripherie
13. 14159265
26. 28318530
39. 42477795
412. 56637060
515. 70796325
618. 84955590
721. 99118455
825. 13274120
9.28. 27433385

[Page 41]

II. Diam of any CircleSquare Root of the Area
10. 88622692
21. 77245385.
32. 65868077
43. 54490770
54. 43114362
65. 31736155
76. 20358847
97. 97604231

If the Diam be (1) the Area is 0. 785398163.

4. Square any given Diame­ter, and then Multiply that Square by 0. 7853, &c. and [Page 42]the last Produce is the Area of the Circle.

5. The Length of an Ellip­sis drawn into the Breadth, and that Product Multiplied by 0. 7853981, &c. gives the A­rea of an Ellipsis.

6. Circles in proportion to one another, as the Squares of their Diameters.

First Problem.

The Diameter of any Cilin­drical Vessel being given, toge­ther with its Height, to find the true Content thereof in Gal­lons, Barrels, &c.

For Example, Suppose in a No­blemans or Gentlemans Garden [Page 43]there be found a Bason, whose Di­ameter is 45 Feet, and its Depth 4 Feet, and it be required to know the true Content thereof in Gallons, Barrels and Tuns.

Answer. By the Fourth Prae­cognitum, I square the given Di­ameter 45. and that Square I Multiply by the Fraction 0.7853, &c. and the Product 1590.232 is the Area of the Circle, which Multiply by 4, the Height of the Cylindrical Vessel, and the Product, viz. 6360.9— Cubick Feet, is the Content of the Ba­son.

This being done, the next thing is to convert the said Cu­bick Feet into Gallons, Barrels and Tuns; which, by the help of the Fourth Table, is easily done.

For by the said Table, 1000 Cubick Feet is equal to 170 Barr. — 7 Gall. — 186, Cub. In. which being Multiplied by Six gives 1020, Barr. — 42 Gall. — 1116, Cub. In. which is being reduced to its right Denomi­nation, 1021 Barr. — 9 Gall. — 270 Cub. In. the Content of 6000 Cubick Inches.

Again. 300 Cubick Feet is e­qual to 51 B. — 2 G. — 84. C. In. this be­ing added to the foregoing Sum, viz.

B.G.C. In.
10219270
51284
makes 107211354

the Content of 6300 Cubick Feet.

Lastly, 60 Cubick Feet contain 10 B. — 7 G. — 186 C. In. which be­ing added to the Content of 6300 Cubick Feet, viz.

B.G.C. In.
107211354
107186
makes 108218540

which Reduced to its right Deno­mination is 1082 B. — 19 G. — 258 C. In. the Content of the Bason which was required.

Second Problem.

The long and short Diameters of an Elliptical Vessel being gi­ven, together with the Height, [Page 46]to find the true Content thereof in Gallons, Barrels, &c.

Suppose in a Gentlemans or No­blemans Garden there be an El­liptical Bason, whose Length is 45 Feet, whose Breadth is 35 Feet, and whose Depth is 4 Feet; and it be required to know the true Content thereof in Gallons, Bar­rels and Tuns.

Answer. By the Fifth Precog­nitum, I Multiply 45 the Length into 35, the Breadth of the Ba­son; the Product which is 1575, I Multiply by the Fraction 0.7853, and the Product of these two Numbers Multiplied, will be 1236. 847. which I then Multiply by 4 the Depth, and thence arises 4947.3... Cubick Feet which is the Content of the Bason. Now I, as before, Convert the said [Page 47]Cubick Feet into Gallons, Bar­rels and Tuns, by the help of the Fourth Table. Thus, 1000 Cubick Feet is there equal to 170 Barr. — 7 Gall. — 186 Cub. In. which being Multiplied by 4 gives 680 Barr. — 28 Gall. — 744 Cub. In. which (being reduced to its right Denomination) is 680 Barr. — 30 Gall. — 180 Cub. In. Again, 900 Cubick Feet is equal to 153 Barr. — 6 Gall. — 252 Cub. In. this being added to the forego­ing Sum, viz.

Barr.Gall.Cub. In.
68030180
1536252
makes 83336432

[Page 48]which is (being reduced) 833 Barr. — 37 Gall. — 150 Cub. In.

Lastly, 40 Cubick Feet contain 6 Barr. — 29 Gall. — 30 Cub. In.

And 7 Cubick Feet contain 1 Barr. — 6 Gall. — 252 Cub. In. therefore 47 Cubick Feet contain 7 Barr. — 35 Gall. — 282 Cub. In. which being added to the Con­tent of 4900 Cubick Feet, viz.

Barr.Gall.Cub. In.
83337150
735282
makes 84073150

which (being reduced to its right Denomination) is 842 Barr. — 1 Gall. — 150 Cub. In. the Content of the Bason, in Bar­rels, [Page 49]Gallons and Cubick Inches, which was required.

But forasmuch as in the Practi­cal part of Hydrostaticks, and the designing of Engines to raise Water to great Heights, by the means of Forcers; it will be often requisite to know the Con­tents and the Weight of less Cy­linders, that is to say, whose Di­ameters are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 Inches, and the Length Indefinite (suppose from 1 to 100, or more). And because such Calculations are ve­ry tedious, I have here inserted the following Table.

THE FIFTH TABLE Giving the true Content in Cu­bick Inches of Cylinders of different Diameters, from 1 to 12 Inclusive, and each of these Cylinders of a Foot or Twelve Inches in Height.

Diam of BasesSolid Content in Cubick Inches.
19⌊424777961
237⌊699111843
384⌊823001647
4150⌊79644736
5235⌊61944900
6339⌊29200656
7461⌊81412004
8603⌊18578044
9763⌊40701476
10942⌊47779600
111140⌊39813316
121357⌊16802624

As for the weight of Water, it is not to be determined abso­lutely, because almost all Wells, Springs and Rivers, are of a dif­ferent weight, and therefore my advice is to all Engineers and Practitioners, to find out the ex­act [Page 52]weight of a Cubick Foot of that particular Water, which they have occasion to make use of; by which means they will easily discover the weight of a­ny Cylinder of Water with these following Cautions.

First Caution. When an Engi­neer desires to force up Water 50, or 100 Feet in Perpendicu­lar Height, and designs to do this by a Forcer of 4, 5, or 6 Inches Diameter; but intends the Water shall be carried up the said 50, or 100 Feet in Perpendicu­lar Height, through a Pipe of of 1 Inch and ½, 1 Inch and ¾, or 2 Inches and ¼ Diameter, the Wa­ter standing in any such perpen­dicular Pipe, is equivalent in weight to a Pipe of the same Perpendicular Height, whose Di­ameter is 4, 5, or 6 Inches, [Page 53] viz. the Diameter of the said For­cer; and indeed the less one of those Pipes is, the greater is the weight against the Forcer to raise up the Water in the same Mo­ment or Interval of Time; that is to say, there is required more Weight to be laid upon that Forcer, to raise the Water through a Pipe of one Inch Di­ameter, than through a Pipe of four Inches Diameter. And what­soever is here said of the weight of Water against a Foreer, in a Forcing Engine, is also true in Suction, by a Drawing Pump.

For Example. A Pump whose Barrel or Pipe of Suction is four Inches Diameter; and the Pipe which reaches from the Barrel to the Water, through which it is drawn up but two Inches Dia­meter, requires more force or [Page 54]strength, than if it were drawn up through a Pipe of four In­ches Diameter. For want of the Knowledge of this, many igno­norant Plummers and Pump-ma­kers, covet to draw their Water through less Pipes, which makes the Work more difficult: And though this seems to be a Para­dox, yet 'tis a real truth; and the want of the right under­standing thereof has occasioned very many great Mistakes by ig­norant Practitioners.

Second Caution. The true weight of Water in all Pipes, is to be determined by the Perpendi­cular Height of those Pipes.

For Example. The weight of Water in Perpendicular Pipes of three Feet (in Height) and three Inches Diameter, is equal to the [Page 55]weight of Water contained in a Pipe of any Length whate­ver (be it a Rod, a Furlong, or more) which rises not more than three Feet above the Horri­zontal Line; which seems like­wise to be a Mystery, but is a real truth, as it lyes in the Pipes; although if it be ta­ken out and laid in a Ballance, it will weigh one Hundred times as much or more, than the Wa­ter in the said Perpendicular Pipe.

I must confess, that the Au­thor had very small Encourage­ment to help our Engineers in things of this Nature, many of them having dealt very disinge­nuously with him; when he had, by near Forty Years Stu­dy and Practise, and the Ex­pence of many a thousand Pounds, [Page 56]produced new and better ways of raising Water, than for ought I know, were ever known to former Ages, viz. by the means of

1. A Forcer moving up and down in a Chamber of Water, through a small Collar or Neck of Leather fastned in a Groove.

2. The Circular Motion of a Crank, reduced to a Perpen­dicular.

3. The Ʋnequal Motion of a Crank exchanged for an Elliptical Equal Motion.

Divers Persons have borrow­ed, some one part, some ano­ther, and making some small Alterations, call it their own Invention. This I am willing [Page 57]to let pass; and after all, to give them the following Items, to prevent their attempting Per­petual Motions, which most of them are apt to do by their Ig­norance in Hydrostaticks; and not a few Gentlemen, in all A­ges, have, by such vain ima­ginations of deceiving Nature, deceived themselves, and Rui­ned their Families.

1. As in Staticks a Pound weight suspended Perpendicular­ly, has a greater force than a Pound weight suspended on a ri­sing Line in Proportion, as the Hypotenuse of a Rectangled Tri­angle, is longer than its Per­pendicular; so in Hydrostaticks, if the two ends of a Syphon turned angular-wise, and a part of it filled with Water, or a­ny other Liquor, be immer­ged [Page 58]in a Vessel of the same Li­quor; that part which hangs Perpendicularly, shall be heavi­er than that which declines in proportion, as one side of that Syphon is longer than the other opposite side.

1. Fig:

For Example. Let the two Triangles in Fig. 1. be Isosceles, and the two sides of the Tri­angle ABC (viz. AC and AB) equal. And so likewise the two sides of the Triangle DEF [Page 59](viz. DE and EF) equal. In this case a Pound weight (P) and another (Q) are equally Ponderous; and so is the Wa­ter contained in the Syphon (FN) from the Superfices (GR) to (N) of an equal weight with the Water in the Syphon (DM) between the Super­fices of the Water (GR) and (M)

2. Fig:

But now in Fig. 2. because the side (AB) of the Trian­gle (ABC) has double the length of (BC) therefore a [Page 60]Pound weight (D) suspended Perpendicularly from (B) is E­quiponderant to two Pounds (E and F) on the side (AB) according to the Doctrine of Sta­tinks. And therefore an Horse drawing a weight of four Hun­dred Pound, upon an Ascent of thirty Deg. heaves at two Hundred Pound, which is one half, and the Ground bears the rest.

3. Fig.

And so in Fig. 3. because the side (DE) of the Triangle (DEF) has twice the Length of (EF) therefore the Water (HF) which hangs Perpendi­cularly, is equal in weight to [...]he Water (DG) which has twice its Quantity and Length, [Page 62]according to the Doctrine of Hy­drostaticks.

2. As in Staticks, a Pound weight on the one side of the Perpendicular Line makes an E­quilibrium, with another Pound Equidistant from the Perpendi­cular Line on the other side: so in Hydrostaticks, one Tube of Water standing at any Height above the Horizontal Line, E­quiponderates any other Tube o [...] Water that stands at the same Height, and is of the same Di­ameter.

3. As in Staticks if a les [...] weight raise a greater, it mus [...] be proportionably at a greate [...] distance from the Perpendicu­lar Line, and have a greater Mo­tion. So in Hydrostaticks, i [...] a less Tube of Water raise a [Page 63]greater Tube, it must be pro­portionably of a greater Length above the Horizontal Line than the other; and consequently the Descent of the Water in a lesser Tube, must have a greater Length than the Ascent of the Water in a greater Tube in proportion, as the Square of the Diameter of the greater Tube, exceeds the Square of the Diameter of the lesser Tube.

And this length of Ascent and Descent of the lesser Tube of Water above the Horizontal Line, compared with the Ascent and Descent of the greater Tube, together with the proportion that the Square of the Diameter of the lesser Tube, bears to the Square of the Diameter of the [Page 64]greater Tube; answers exactly to the force and Motion of a Lea­ver, or rather of a lesser weight placed on a Ballance at a grea­ter distance from the Perpendi­cular to Counterpoise or raise a greater weight placed on the o­ther side at a lesser distance according to the Doctrine of Sta­ticks.

Fig. 1.

As in Fig. 1. A pound weight (A) is equiponderant to ano­ther (B) because equidistant from the Perpendicular (CD) So that part of the Tube (EL) [Page 65]whose Height above the Horizon­al Line (FE) is of an equal weight with that part of the Tube (GM) which is of an equal leight above (FH) viz. (GH.)

Fig. 2.

In Fig. 2. as a pound weight A equiponderating three Pound (B, C, D,) must have thrice the Distance from the Perpendicu­cular (EF) and for every Foot or Inch (B, C, D,) ascends or descends A must ascend or descend three Feet, or 3 Inches, viz. from (G) to (H.)

So the Tube (RM) being less than the Tube (NQ) in Proportion as (1) is less than three. The Water must descend from (G) to (H) to raise the Wa­ter in the Tube (NQ) from (O) to (P) which is ½ of the Height.

And which is admirable, if the Liquor from (O) to (N) be Wine by turning the Cock (S) gently the Water shall carry up the Wine in an entire Body.

And this is a pretty Experi­ment in Hydrostaticks; and these Cautionary Reflections will, I presume, if throughly under­stood, discourage young Practi­tioners from ever attempting to deceive the Order of Nature, and confound the Equilibrium of Weights (whether liquid or dry) by imaginary Perpetual Motions.

[...]
[...]

THE LAST TABLE. A most Excellent TABLE of POLIGONES from 3 to 80, Calculated to a Radus of 10,000,000, by that incomparable Master of Num­bers, LUDOLPHUS A CULEN, Published Anno Dom. 1619.

Pol. 
317,320,508
414,242,135
511,755,705
610,000,000
78,677,674
87,653,668
96,840,402
106,180,339
115,634,651
125,176,380
134,786,313
144,450,418
154,158,233
163,901,806
173,674,990
183,472,993
193,291,891
203,128,689
212,980,845
222,846,296
232,723,332
242,610,523
252,506,660
262,410,733
272,321,858
282,239,289
292,162,380
302,090,569
312,023,366
321,960,342
331,901,120
341,845,362
351,792,786
361,743,114
371,696,118
381,651,586
391,609,331
401,561,181
411,530,985
421,494,601
431,459,906
441,426,783
451,395,129
461,364,848
471,335,852
481,308,062
491,281,404
501,255,810
511,231,218
521,207,569
531,184,812
541,162,896
551,141,776
561,121,408
571,101,755
581,082,778
591,074,453
601,046,719
611,029,575
621,012,983
630,996,912
640,981,353
650,966,275
660,951,638
670,937,445
680,923,669
690,910,291
700,897,296
710,884,666
720,872,387
730,860,444
740,848,824
750,837,513
760,826,499
770,815,771
780,805,318
790,795,130
800,785,196

The Ʋse of the TABLE of Polygones.

SUppose you had a Wheel, in which you intend there should be Forty Coggs or Teeth, standing at equal Distances, and the Diameter of this Wheel be Thirty Three. By this Table you must proceed thus; First having taken half 33. which is 16.5 for the Radius of your Circle, look out the side of the Polygon of 40, standing over against that Num­ber in the Table, which is 1,561.

Then say,

As 10.000. 1.561. so 16. 5. 2.575. this taken off a Line of equal parts, by which you mea­sure your Radius, will rightly [Page 72]divide your Circle; and each of these Points of Division so found, will be Centers for your Teeth or Coggs.

There are other Operations re­lating to the Division of Wheels, or Circles, which may be nicely performed by the Assistance of this Table; but the Nature of it being understood, 'tis ea­sie to apply it to those other Uses.

Note, To shorten the Work, I thought it convenient to take a lesser Radius, as 10.000. and 1.561, which stands over a­gainst 40 in the Table, will consist of the first Figure an Integer, and the rest Deci­mals; and as you take a grea­ter [Page 73]or a less Radius, you must make use of more or fewer Figures, throughout the whole Table.

FINIS.

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