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            <author>Delamain, Richard, fl. 1631.</author>
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               <date>1632</date>
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                  <title>The making, description, and vse of a small portable instrument for ye pocket (or according to any magnitude) in forme of a mixt trapezia thus called a horizontall quadrant composed and prodused soly for the benefit and vse of such which are studious of mathematicall practice Written and delivered by Delamain, student and teacher of the mathematickes.</title>
                  <author>Delamain, Richard, fl. 1631.</author>
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               <extent>[18], 104 p., [3] plates, folded table : ill.  </extent>
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                  <publisher>Printed [by Thomas Cotes] for Richard Hawkins and are to be sold at his shop in Chancery lane neere Sarjants Inne,</publisher>
                  <pubPlace>London :</pubPlace>
                  <date>1632.</date>
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      <front>
         <div type="illustration">
            <pb facs="tcp:10089:1"/>
            <pb facs="tcp:10089:2" rendition="simple:additions"/>
            <p>
               <figure>
                  <figDesc>engraving of the horizontal quadrant (mathematical instrument)</figDesc>
                  <p>Thiſ inſtrument or any other for the Mathema<g ref="char:EOLhyphen"/>ticall arts are made in ſiluer or braſſe by Elias Allen or Iohn Allen neare the Sauoy in the ſtrand</p>
               </figure>
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            <pb facs="tcp:10089:2"/>
            <p>The making, description, and vse of a small portable Instrument for y<hi rend="sup">e</hi> Pocket (or according to any Magnitude) in forme of a mixt Trapezia thus Called a Horizontall Quadrant.</p>
            <p>Composed and prodused soly for the benefit and vse of such which are studious of Mathematicall Practice Written and delivered by Delamain student and Teacher of the Mathematickes.</p>
            <p>Attribuit nullo praescripto tempore vitae vsuram nobis ingenij<expan>
                  <am>
                     <g ref="char:abque"/>
                  </am>
                  <ex>que</ex>
               </expan> Deus.</p>
            <figure>
               <figDesc>mathematical diagram</figDesc>
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            <p>
               <hi>London</hi> printed for Richard Hawkins and are to be ſold at his ſhop in Chancery lane neere Sarjants Inne 1632.</p>
         </div>
         <div type="dedication">
            <pb facs="tcp:10089:3"/>
            <pb facs="tcp:10089:3" rendition="simple:additions"/>
            <head>TO The right Honorable and his much honoured Lo. <hi>Thomas</hi> Lo. <hi>Brudenel,</hi> Baron of <hi>Stauton.</hi>
            </head>
            <opener>
               <salute>Right honourable, and my very good Lo.</salute>
            </opener>
            <p>
               <hi>
                  <seg rend="decorInit">Y</seg>Our</hi> ſingular knowledge in all excellent, and ſolid <hi>Li<g ref="char:EOLhyphen"/>terature,</hi> and your ever He<g ref="char:EOLhyphen"/>roicke, and Noble diſpoſition to the beſt kinds of <hi>Learning,</hi> are not unknowne unto the world; And amongſt
<pb facs="tcp:10089:4"/> other ſtudies in your Lo. minoritie at the <hi>Vniverſitie,</hi> you tooke no little affection, to the <hi>Mathematicall Arts,</hi> as by your Lo. owne <hi>Manu-ſcripts</hi> and ex<g ref="char:EOLhyphen"/>cellent <hi>Bookes</hi> in your Lo. great <hi>Libra<g ref="char:EOLhyphen"/>rie</hi> I have often ſeene; Beſides, not onely by mine owne ſundry conferences with your Lo. but alſo by the relation of others of more mature judgement I have bin amply informed in theſe your L. more aged yeares not onely of your continued love to theſe <hi>Arts,</hi> but alſo that your knowledge in them far exceedes many of the <hi>Nobilitie</hi> of this <hi>kingdome.</hi> Now my L. when I cau<g ref="char:EOLhyphen"/>ſed the ſubject of this <hi>Tractat</hi> to be made for your Lo. laſt <hi>Summer</hi> (I meane your Lo. <hi>Horizontall Quadrant</hi>) I had not then any intention ſo ſoone to have written publikely upon it; But, ha<g ref="char:EOLhyphen"/>ving then but declared unto your Lo. the excellent and abundant uſe of the <hi>In<g ref="char:EOLhyphen"/>ſtrument</hi>
               <pb facs="tcp:10089:4"/> by the heads of the <hi>pro<g ref="char:EOLhyphen"/>poſitions</hi> then ſlightly compiled, (farre exceeding the <hi>Inſtrumentall</hi> way in this nature, that eyther <hi>Nobili<g ref="char:EOLhyphen"/>tie, Gentrie,</hi> or others are now acquain<g ref="char:EOLhyphen"/>ted with in this <hi>kingdome,</hi> for a recreative <hi>Inſtrument,</hi> as well for the copious uſe thereof, as its great facilitie, and expedition in operation) your Lo. then incouraging me to the publiſh<g ref="char:EOLhyphen"/>ing of it for a generall end; many <hi>Moneths</hi> after I conſidered thereon: and drew it up into a <hi>Body,</hi> and thus ac<g ref="char:EOLhyphen"/>commodated it, as I here preſent it now unto your Lo. favourable cenſure, and <hi>Pa<g ref="char:EOLhyphen"/>tronage</hi> (to be ſheltred under the wings of your Lo. clemency againſt all calum<g ref="char:EOLhyphen"/>niators and malevolents) as belonging eſpecially to your Lo. ſith you were the ſole motive to this worke, and had both the uſe of the <hi>Inſtrument</hi> before it came
<pb facs="tcp:10089:5"/> thus to a publicke view, and the firſt <hi>Quadrant</hi> that ever was made common in this kind: accept therefore favourably I beſeech your Lo. this ſmall mite of my labours, as from the hands of one of your pooreſt <hi>ſervants</hi> (yet true affectionate) who ſhall alwayes acknowledge your Lo. Nobleneſſe towards him, and ever reſt</p>
            <closer>
               <signed>Your Lo. moſt humbly devoted to Honour and ſerve you De la main.</signed>
            </closer>
         </div>
         <div type="to_the_reader">
            <pb facs="tcp:10089:5"/>
            <head>To the Reader.</head>
            <p>
               <hi>
                  <seg rend="decorInit">B</seg>Efore</hi> I ſhew the <hi>Projection,</hi> deſcribe the particulars, and deliver the uſes of this <hi>Horizontall Quadrant,</hi> it will not bee impertinent, for the ſa<g ref="char:EOLhyphen"/>tisfaction of ſome, to give the <hi>Reader</hi> to under<g ref="char:EOLhyphen"/>ſtand what moved me unto it, how it exceeds other <hi>Instruments,</hi> and whence it might be drawne, and projected.</p>
            <p>
               <hi>Now</hi> the ingenious aptneſſe for <hi>Inuention,</hi> and accomodating of things in a faire and expedite courſe for <hi>Mathematicall Practices,</hi> of that late profeſſor of <hi>Aſtronomy</hi> M<hi rend="sup">r</hi>. <hi>Gunter</hi> is not un<g ref="char:EOLhyphen"/>knowne unto many about this kingdome, ſatisfying many of his friends (according to his free and noble affection) by <hi>Tranſcripts</hi> in that of more ſolid matter, but ſuch of vulgar <hi>Practices</hi> he hath publikely made manifeſt for the uſe of all ſuch as affect thoſe <hi>Studies. In</hi> which worke ma<g ref="char:EOLhyphen"/>ny yeares paſt I tooke occaſion to conſider the <hi>Scheme,</hi> or <hi>Diagramme</hi> of the fourth <hi>Projection</hi> in
<pb facs="tcp:10089:6"/> his <hi>Booke</hi> of the <hi>Sector</hi> Page the 64. &amp; 65. w<hi rend="sup">ch</hi> ac<g ref="char:EOLhyphen"/>cording as he ſaies is after the manner of the old <hi>Concaue hemiſphere</hi> (but being in truth a naturall <hi>Projection</hi> of the viſible <hi>Hemiſphere,</hi> that is, one Moytie of the <hi>Globe,</hi> projected on a <hi>Plaine</hi>) which <hi>Diagram</hi> and <hi>Projection</hi> is now chalenged by my Reverend good friend <hi>Master Oughtred,</hi> and it ſhould ſeeme that <hi>Master Gunter</hi> had the Original of it from his labours, &amp; invention, who compoſed and made the ſame ſo, for more then thirty yeares paſt, as appeares by his owne <hi>Wri<g ref="char:EOLhyphen"/>tings,</hi> &amp; <hi>Manuſcripts</hi> upon that <hi>Protection</hi> ſhew<g ref="char:EOLhyphen"/>en me in the time of the Printing of this <hi>Trac<g ref="char:EOLhyphen"/>tat</hi> upon my <hi>Horizontall Quadrant,</hi> whoſe ex<g ref="char:EOLhyphen"/>cellent knowledge in <hi>Mathematicall</hi> Learning may evidently confirme it: which <hi>Projection</hi> the ſaid <hi>Master Oughtred</hi> gave to the late <hi>Biſhop</hi> of <hi>Wincheſter, Doctor Bilſon,</hi> for more then 20. yeares paſt, and to ſome others of very good quality.</p>
            <p>And it may alſo, by a Letter from that moſt famous and admired <hi>Geometer, Master Henry Brigges</hi> unto <hi>Master Oughtred</hi> dated from <hi>Gre<g ref="char:EOLhyphen"/>ſham College Iune,</hi> the 2. <hi>Anno.</hi> 1618. be collected that the ſaid <hi>Maſter Gunter</hi> had the firſt overture of that fourth <hi>Projection,</hi> from the ſaid <hi>Maſter Oughtred,</hi> in which <hi>letter</hi> are theſe words: <hi>Master Gunter</hi> doth here ſend you the <hi>Print</hi> of an <hi>Horizontall Diall</hi> of his drawing after your <hi>Inſtrument;</hi> And afterwards the ſaid <hi>Projec<g ref="char:EOLhyphen"/>tion</hi> was alſo preſented by <hi>Master Gunter</hi> to many Noble <hi>Perſonages,</hi> and in particular to
<pb facs="tcp:10089:6"/> the <hi>Right Honourable</hi> the <hi>Earle</hi> of <hi>Bridgewater,</hi> cauſing it to be cut in <hi>Braſſe,</hi> in ſuch a forme a<gap reason="illegible" resp="#PDCC" extent="1 letter">
                  <desc>•</desc>
               </gap> I have placed at the end of this <hi>Tractat,</hi> ſome uſes of which <hi>Diall</hi> are extant, viz. the 2. 18. 21. and 34. <hi>Pro.</hi> of the <hi>Index</hi> or <hi>Table</hi> following.</p>
            <p>
               <hi>Now</hi> having conſidered diverſe <hi>Pocket Inſtru<g ref="char:EOLhyphen"/>ments</hi> (that many men are practiſed in) &amp; looked into ſundry <hi>Projections,</hi> amongſt which that of <hi>Gemmafriſius</hi> (there drawne in the <hi>Booke</hi> of the <hi>Sector</hi>) is of admirable uſe, yet making a more ſerious quaere, &amp; contemplating more intenſively upon that <hi>Diagram,</hi> drawne and ſpecified in that 64. and 65. Pages of the <hi>Sector</hi> (aforeſaid) I found it farre to exceede all others in the <hi>Multiplicity,</hi> and excellencie of performance.</p>
            <p>
               <hi>If</hi> I ſhould adde unto it a <hi>Kalender</hi> of <hi>time,</hi> and an <hi>Index</hi> graduated with an <hi>Axis,</hi> and <hi>Per<g ref="char:EOLhyphen"/>pendiculars</hi> to be erected vpon it at pleaſure: &amp; referring only the <hi>Trapeziall forme,</hi> it ſhould be fitted farre to exceede any portable <hi>Instrument</hi> for the <hi>Pocket,</hi> ever yet produced in reſpect of the general uſes of it: in reſolving ſuch ordinary <hi>Pro<g ref="char:EOLhyphen"/>poſitions</hi> which are practiced in <hi>Astronomie,</hi> up<g ref="char:EOLhyphen"/>on the <hi>Globe, Spheare, Hemiſpheare, Quadrants</hi> of all ſorts, <hi>Aſtrolabe</hi> of <hi>Friſius, Blagraue,</hi> and others for facility, expedition, or certaintie, (like <hi>Magnitudes</hi> conſidered) for in theſe <hi>Inſtruments</hi> for ſeverall times, and ſeverall <hi>Pro<g ref="char:EOLhyphen"/>poſitions,</hi> there muſt be diverſe rectifications of the parts belonging to theſe <hi>Instruments,</hi> and
<pb facs="tcp:10089:7"/> that diverſly by reaſon of their diverſity: By this <hi>Horizontall Quadrant,</hi> the former redifications are avoided, Contemplation &amp; the eye being on<g ref="char:EOLhyphen"/>ly the <hi>Index,</hi> the aptneſſe, &amp; fitneſſe of the parts, and lines ſo naturally projected, or deſcribed as they are upon the plaine of the <hi>Instrument</hi> (being a part of the <hi>Horizon</hi> the <hi>Parallels Meridians,</hi> &amp; <hi>Verticall Circles,</hi> that are contained or may be deſ<g ref="char:EOLhyphen"/>cribed in our <hi>Latitude</hi> ſufficiently neceſſary) indu<g ref="char:EOLhyphen"/>ceth any one in the underſtanding of the uſes of it that is but indifferently verſed in the linaments and principles of the <hi>Globe,</hi> what to ſpeake, and what to anſwere in a <hi>Propoſition</hi> without farther direction: And having had this <hi>Horizontall Quadrant</hi> for many yeares paſt, as a <hi>Pocket In<g ref="char:EOLhyphen"/>strument,</hi> diverſe about this <hi>Kingdome</hi> being im<g ref="char:EOLhyphen"/>portunate with me for to have it, or to pub<g ref="char:EOLhyphen"/>liſh the uſe of it, ſeeing its great facilitie, and expedition, in compariſon of ſuch <hi>Pocket Instru<g ref="char:EOLhyphen"/>ments</hi> as are now uſed, here, or in forraigne parts: I was willing at laſt after I had given order for the making of fower of theſe <hi>Instruments</hi> in <hi>Sil<g ref="char:EOLhyphen"/>ver</hi> for ſeverall <hi>Noble Perſonages,</hi> to disbur<g ref="char:EOLhyphen"/>then my ſelfe of <hi>Tranſcribing</hi> the uſes of the <hi>In<g ref="char:EOLhyphen"/>ſtrument,</hi> and <hi>Tables</hi> for the making of it, to ſatiſ<g ref="char:EOLhyphen"/>fie thoſe which were importunate, and to let o<g ref="char:EOLhyphen"/>thers that are ſtudious in <hi>Mathematicall Practices</hi> alſo participate of it.</p>
            <p>Now, what I have delivered vpon the accommodating of the <hi>Instrument</hi> thus, the making thereof, with the uſes that I
<pb facs="tcp:10089:7"/> have delivered in this <hi>Tractat</hi> upon it fol<g ref="char:EOLhyphen"/>lowing: I acknowledge due to none <hi>Inferiour aſſiſtant,</hi> but to mine owne <hi>Induſtry, ſearch</hi> and <hi>labour,</hi> and that 64. 65. and 66. <hi>Pages</hi> of the <hi>Booke:</hi> of the <hi>Sector</hi> before ſpecified in which is onely ſhewne the 2. 3. 19. 22. 25. and 30. <hi>Propo<g ref="char:EOLhyphen"/>ſitions</hi> of the <hi>Index,</hi> or <hi>Table</hi> following, as uſes of the ſaid <hi>Projection.</hi>
            </p>
            <p>
               <hi>But</hi> I have extended them to many more, and abundantly, and plentifully ſupplied the obſcuritie of that <hi>Scheme,</hi> or <hi>Diagramme</hi> there drawne (as for a generall good) in the uſe of this <hi>Horizantal Quadrant.</hi> I deliver therfore firſt the making of it, firſt by the <hi>Sector</hi> (ſomewhat different from that of <hi>Maſter Gunters</hi>) ſecondly by <hi>Geometrie,</hi> and laſtly I ſhew a third way, how it may be <hi>Proiected</hi> and made by my <hi>Mathema<g ref="char:EOLhyphen"/>ticall Ring,</hi> and by <hi>Numbers,</hi> which I have <hi>Cal<g ref="char:EOLhyphen"/>culated</hi> and accommodated to that end in <hi>Tables,</hi> for more exactneſſe. <hi>Part</hi> of the generall ſcope, and uſe of which <hi>Inſtrument</hi> I deliuer in the <hi>Index,</hi> or <hi>Table</hi> following.</p>
         </div>
         <div type="index">
            <pb facs="tcp:10089:8"/>
            <head>An Index, or Table of the vſes of the Horizontall Quadrant.</head>
            <p>Viz of the
<list>
                  <item>
                     <hi>Horizon.</hi>
                  </item>
                  <item>
                     <hi>Line of Shadowes.</hi>
                  </item>
                  <item>
                     <hi>Kalender.</hi>
                  </item>
                  <item>
                     <hi>Parallels.</hi>
                  </item>
                  <item>
                     <hi>Aequator.</hi>
                  </item>
                  <item>
                     <hi>Eclipticke.</hi>
                  </item>
                  <item>
                     <hi>Houre-lines.</hi>
                  </item>
                  <item>
                     <hi>Index.</hi>
                  </item>
               </list>
            </p>
            <list>
               <item>1 <hi>By the Hori<g ref="char:EOLhyphen"/>zon to ſhew.</hi>
                  <list>
                     <item>1. The <hi>Sunne,</hi> or <hi>Starres Altitude</hi> at any time. Pag. 53.</item>
                     <item>2. At any <hi>Day</hi> of the <hi>yeare,</hi> how farre the <hi>Sun riſeth,</hi> or <hi>ſetteth</hi> from the true <hi>Eaſt</hi> or <hi>Weſt.</hi> Pag. 28.</item>
                     <item>3. The <hi>Suns Azimuth,</hi> and <hi>Altitude,</hi> at any <hi>houre,</hi> for any <hi>day,</hi> Pag. 62.</item>
                     <item>4. The <hi>Meridian</hi> line, upon any appea<g ref="char:EOLhyphen"/>rance of the <hi>Sunne.</hi> Pag. 55.</item>
                     <item>5. The vncertaintie of <hi>time,</hi> by noting the <hi>Shadow</hi> of things, Pag. 63.</item>
                     <item>6. The <hi>Site</hi> of a <hi>Building,</hi> or Coſting of a <hi>Place.</hi> Pag. 57.</item>
                     <item>7. The <hi>Variation</hi> of the <hi>Needle.</hi> Pag. 59.</item>
                     <item>8. The <hi>Declination</hi> of a <hi>Wall,</hi> or <hi>Plaine,</hi> the <hi>Sunne</hi> ſhining thereon, Pag. 71.</item>
                     <item>9. The <hi>Inclination</hi> of a <hi>Plaine,</hi> and to place a <hi>Plaine Horizontall,</hi> Pag. 89.</item>
                  </list>
               </item>
               <pb facs="tcp:10089:8"/>
               <item>2. <hi>By the line of ſhadowes is had.</hi>
                  <list>
                     <item>10. At what <hi>houre</hi> in any <hi>Day</hi> of the <hi>yeare</hi> the <hi>ſhadow</hi> of an <hi>Altitude</hi> is equall, double, triple, &amp;c. unto it. Pag. 35.</item>
                     <item>11. Inſtantly the <hi>houre</hi> of the <hi>day,</hi> the <hi>Azimuth</hi> and <hi>Altitude</hi> of the <hi>Sun,</hi> with the <hi>Meridian line,</hi> without obſervation or ſight of the <hi>Sun,</hi> by knowing the <hi>Pro<g ref="char:EOLhyphen"/>portion</hi> betweene the length of a <hi>ſhadow</hi> upon a <hi>Horizontall Plaine</hi> &amp; that which caſts the <hi>ſhadow.</hi> Pag. 67.</item>
                     <item>12. At any <hi>houre,</hi> an <hi>Altitude</hi> of the <hi>Sun,</hi> or <hi>Azimuth,</hi> what Proportion <hi>ſhadowes</hi> have to their <hi>Bodies.</hi> Pag. 37.</item>
                     <item>13. Whether and <hi>Altitude</hi> be above, or be<g ref="char:EOLhyphen"/>low the Iewell of the <hi>eye,</hi> &amp; how much.</item>
                     <item>14. The hight of an <hi>Altitude,</hi> acceſſible, or in acceſſible. Pag. 100. 101.</item>
                     <item>15. The meaſure of any Part of <hi>Altitude</hi> not approchable. Pag. 102.</item>
                  </list>
               </item>
               <item>3. <hi>By the Ka<g ref="char:EOLhyphen"/>lender is knowne.</hi>
                  <list>
                     <item>16. The inequality of <hi>Time,</hi> in equall <hi>Months,</hi> or equall number of <hi>Dayes</hi> Pag. 44.</item>
                     <item>17. What number of <hi>dayes</hi> wil make the <hi>day</hi> and <hi>houre</hi> longer, or ſhorter at any time. Pag. 43.</item>
                     <item>18. The <hi>houre</hi> of the <hi>Sun riſing, ſetting,</hi> with the length of the <hi>day at any time,</hi> Pag. 23.</item>
                     <item>19. What <hi>dayes</hi> are alike in length, &amp; what <hi>day</hi> the <hi>Sun riſing</hi> in the one, ſhall be the <hi>Sun ſetting</hi> in the other, Pag. 24.</item>
                     <item>20. The inequality of <hi>Time</hi> between day breake, and <hi>Sun riſing.</hi> Pag. 41.</item>
                  </list>
               </item>
               <item>4. <hi>By the Pa<g ref="char:EOLhyphen"/>rallels to ſearch out.</hi>
                  <list>
                     <item>21. At any day the <hi>Suns declination. Pag.</hi> 24</item>
                     <item>22. The <hi>Latitude</hi> of a <hi>Place,</hi> or hight of the <hi>Pole</hi> above the <hi>Horizon,</hi> Pag. 60.</item>
                     <item>23. At what <hi>houre</hi> in any <hi>day,</hi> the <hi>Suns Azi<g ref="char:EOLhyphen"/>muth,</hi> and <hi>Altitude</hi> will be equall, and how much the <hi>Altitude</hi> &amp; <hi>Azimuth</hi> wil be. Pag. 42.</item>
                  </list>
               </item>
               <pb facs="tcp:10089:9"/>
               <item>5. <hi>By the Ae<g ref="char:EOLhyphen"/>quator is ſeene</hi>
                  <list>
                     <item>24. The <hi>Suns</hi> equall motion, <hi>right Aſ<g ref="char:EOLhyphen"/>cention,</hi> and <hi>obli<expan>
                              <am>
                                 <g ref="char:abque"/>
                              </am>
                              <ex>que</ex>
                           </expan> Aſcention,</hi> Pag. 26.</item>
                  </list>
               </item>
               <item>6. <hi>By the Eclipticke to give</hi>
                  <list>
                     <item>25. The <hi>Sunnes Place</hi> at any time of the yeare, Pag. 25.</item>
                     <item>26. The Degree of the <hi>Aequator</hi> in the <hi>Ho<g ref="char:EOLhyphen"/>rizon,</hi> by ſuppoſing the degree of the <hi>Ecliptick</hi> in the <hi>Horizon,</hi> Pag 46.</item>
                     <item>27. The Degree of the <hi>Eclipticke</hi> in the <hi>Horizon,</hi> by ſuppoſing the degree of the <hi>Aequator</hi> in the <hi>Horizon.</hi> Pag. 47.</item>
                     <item>28. The degree of <hi>Medium Coeli,</hi> or the degree of the <hi>Eclipticke</hi> in the <hi>Meridian,</hi> by ſuppoſing the degree of the <hi>Eclipticke</hi> in the <hi>Horizon, <g ref="char:V">Ʋ</g>el</hi> contra. Pag. 47.</item>
                     <item>29. The <hi>Horoſcope,</hi> or the degree <hi>aſcendant'</hi> or <hi>deſcendant,</hi> and the <hi>Nonageſsima</hi> de<g ref="char:EOLhyphen"/>gree at any <hi>houre.</hi> Pag. 49.</item>
                     <item>30. What Angle the <hi>Eclipticke</hi> makes with the <hi>Horizon,</hi> or the <hi>Altitude</hi> of the <hi>Nona<g ref="char:EOLhyphen"/>geſsima</hi> degree and what <hi>Azimuth</hi> it is in at any <hi>houre,</hi> Pag. 50.</item>
                  </list>
               </item>
               <item>7. <hi>By the hour lines to find</hi>
                  <list>
                     <item>31. The <hi>houre</hi> of the <hi>Day,</hi> and <hi>Azimuth</hi> of the <hi>Sunne,</hi> Pag. 54.</item>
                     <item>32. The <hi>houre</hi> of the <hi>day</hi> agreeable to any <hi>Altitude,</hi> or <hi>Azimuth,</hi> Pag. 39.</item>
                     <item>33. The <hi>Sunnes</hi> Difference of <hi>Aſcention</hi> for any <hi>day,</hi> Pag. 23.</item>
                     <item>34. The <hi>Quarter</hi> of the <hi>yeare,</hi> and <hi>day</hi> of the <hi>moneth, houre</hi> of the <hi>day, Meridi<g ref="char:EOLhyphen"/>an-line,</hi> and <hi>Azimuth</hi> of the <hi>Sunne,</hi> if it were forgotten: Pag. 64.</item>
                  </list>
               </item>
               <pb facs="tcp:10089:9"/>
               <item>8. <hi>By the In<g ref="char:EOLhyphen"/>dex adioy<g ref="char:EOLhyphen"/>ned with o<g ref="char:EOLhyphen"/>ther lines you have.</hi>
                  <list>
                     <item>35. At what <hi>houre,</hi> &amp; <hi>Altitude,</hi> the <hi>Sun</hi> wil be due <hi>Eaſt,</hi> at any <hi>day</hi> of the <hi>yeare,</hi> Pag. 27.</item>
                     <item>36. The <hi>Suns Azimuth,</hi> &amp; <hi>houre</hi> without obſervation, Pag. 58.</item>
                     <item>37. The time of <hi>day-breake,</hi> or end of <hi>Twi-light,</hi> for any <hi>day</hi> in the <hi>yeare,</hi> Pag. 30.</item>
                     <item>38. The <hi>hight</hi> or <hi>Depreſſion</hi> of the <hi>Sun</hi> in the <hi>Meridian,</hi> for any <hi>day</hi> in the <hi>yeare,</hi> here or for any <hi>Latitude,</hi> Pag. 29.</item>
                     <item>39. The <hi>Suns depreſſion</hi> &amp; <hi>Azimuth,</hi> at any <hi>houre</hi> of the <hi>Night</hi> aſſigned, Pag. 40.</item>
                     <item>40. The <hi>houre</hi> of the <hi>day</hi> to our <hi>Antipodes,</hi> by ſuppo<g ref="char:EOLhyphen"/>ſing the <hi>ſuns depreſſion</hi> under the <hi>Horizon,</hi> Pag. 42.</item>
                     <item>41. What <hi>houre,</hi> &amp; <hi>Altitude</hi> the <hi>ſunne</hi> commeth upon a <hi>declining wall,</hi> any <hi>day</hi> in the <hi>yeare,</hi> &amp; how long the <hi>ſun</hi> ſhineth thereon, Pag. 32.</item>
                     <item>42. At what <hi>houre</hi> and <hi>Altitude</hi> the <hi>Sun</hi> muſt have, to be oppoſite or Perpendicular to a <hi>Declination Plaine,</hi> Pag. 33.</item>
                     <item>43 The <hi>declinatio<g ref="char:cmbAbbrStroke">̄</g>
                        </hi> of <hi>a wall,</hi> by ſeing the <hi>ſun</hi> beginning to ſhine thereon, or going from it, Pag. 69.</item>
                     <item>44. The <hi>houre</hi> &amp; <hi>Altitude</hi> of a <hi>ſtars</hi> coming to the <hi>Me<g ref="char:EOLhyphen"/>ridian</hi> at any <hi>Night</hi> in the <hi>yeare</hi> aſſigned, Pag. 74.</item>
                     <item>45. The time of the <hi>riſing, ſetting,</hi> &amp; continuance of a ſtarre above the <hi>Horizon,</hi> &amp; in what part of the <hi>Hemi<g ref="char:EOLhyphen"/>ſphere</hi> they may be ſeene, with the <hi>Azimuth</hi> and <hi>Alti<g ref="char:EOLhyphen"/>tude</hi> thereof at any <hi>houre,</hi> Pag. 78.</item>
                     <item>46 In what part of the <hi>Horizon</hi> a <hi>ſtarre riſeth or ſet<g ref="char:EOLhyphen"/>teth,</hi> and at what <hi>houre</hi> &amp; <hi>Altitude</hi> it will be due <hi>Eaſt</hi> or <hi>Weſt,</hi> Pag. 80.</item>
                     <item>47. What <hi>Azimuth</hi> any <hi>ſtarre</hi> is in, upon any appea<g ref="char:EOLhyphen"/>rance thereof, with the <hi>houre</hi> of the <hi>night,</hi> Pag. 82.</item>
                     <item>48. How to meaſure the Quantitie of an <hi>Angle,</hi> or to finde the diſtance of two <hi>Starres,</hi> Pag. 85.</item>
                     <item>49. How to meaſure <hi>Diſtances,</hi> and <hi>Bredths,</hi> Pag. 87.</item>
                     <item>50. How to take the <hi>Circuit</hi> of a <hi>Figure,</hi> or the <hi>ſur<g ref="char:EOLhyphen"/>veigh</hi> of a <hi>Place.</hi> Pag. 93.</item>
                  </list>
               </item>
            </list>
         </div>
         <div type="authors_note">
            <pb facs="tcp:10089:10"/>
            <p>MVch more I might have laid open up<g ref="char:EOLhyphen"/>on the uſe of this <hi>Inſtrument,</hi> as the ma<g ref="char:EOLhyphen"/>king of <hi>Horizontall, direct, declining, cilindrical,</hi> &amp; <hi>Ring dyalls,</hi> the diſtance of the <hi>houres, ſub<g ref="char:EOLhyphen"/>ſtiler</hi> &amp; <hi>ſtiles</hi> hight, <hi>Stoflerius Astrolabe, Master Gunters Quadrant,</hi> with many other <hi>Inſtru<g ref="char:EOLhyphen"/>ments,</hi> now uſed, but let theſe be ſufficient for the preſent; the ingenious, may eaſily adde vnto that which I have delivered, &amp; therefore I ſhew firſt how to project the <hi>Instruments,</hi> then the <hi>Deſcription,</hi> and laſtly how theſe uſes, are compendiouſly con<g ref="char:EOLhyphen"/>tracted, and operated.</p>
         </div>
         <div type="tables_some_fragmentary">
            <pb facs="tcp:10089:11"/>
            <head>The Tables for making of the Horizon<gap reason="illegible" resp="#PDCC" extent="4 letters">
                  <desc>••••</desc>
               </gap> 
               <gap reason="illegible" resp="#PDCC" extent="1 span">
                  <desc>〈…〉</desc>
               </gap>
            </head>
            <p>
               <table>
                  <head>The Table for the deſcribing of the Parallels.</head>
                  <row>
                     <cell role="label">
                        <hi>G</hi>
                     </cell>
                     <cell role="label">
                        <hi>A</hi>
                     </cell>
                     <cell role="label">
                        <hi>B</hi>
                     </cell>
                     <cell role="label">
                        <hi>C</hi>
                     </cell>
                     <cell role="label">
                        <hi>F</hi>
                     </cell>
                     <cell role="label">
                        <hi>E</hi>
                     </cell>
                     <cell role="label">
                        <hi>D</hi>
                     </cell>
                  </row>
                  <row>
                     <cell>58 20</cell>
                     <cell>♑</cell>
                     <cell>37 30</cell>
                     <cell>76732</cell>
                     <cell>162173</cell>
                     <cell>401078</cell>
                     <cell>70 00</cell>
                  </row>
                  <row>
                     <cell>57 49</cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>3</cell>
                     <cell>37 15</cell>
                     <cell>76041</cell>
                     <cell>158854</cell>
                     <cell>393750</cell>
                     <cell>75 45</cell>
                  </row>
                  <row>
                     <cell>56 45</cell>
                     <cell>22</cell>
                     <cell>36 45</cell>
                     <cell>74673</cell>
                     <cell>152576</cell>
                     <cell>379826</cell>
                     <cell>75 15</cell>
                  </row>
                  <row>
                     <cell>55 44</cell>
                     <cell>2<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>36 15</cell>
                     <cell>73323</cell>
                     <cell>146736</cell>
                     <cell>366795</cell>
                     <cell>74 45</cell>
                  </row>
                  <row>
                     <cell>54 42</cell>
                     <cell>20</cell>
                     <cell>35 45</cell>
                     <cell>71989</cell>
                     <cell>141292</cell>
                     <cell>354573</cell>
                     <cell>74 15</cell>
                  </row>
                  <row>
                     <cell>53 43</cell>
                     <cell>19</cell>
                     <cell>35 15</cell>
                     <cell>76673</cell>
                     <cell>136205</cell>
                     <cell>343084</cell>
                     <cell>73 45</cell>
                  </row>
                  <row>
                     <cell>52 41</cell>
                     <cell>18</cell>
                     <cell>34 45</cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>9372</cell>
                     <cell>131445</cell>
                     <cell>332263</cell>
                     <cell>73 15</cell>
                  </row>
                  <row>
                     <cell>51 46</cell>
                     <cell>17</cell>
                     <cell>34 15</cell>
                     <cell>68087</cell>
                     <cell>126982</cell>
                     <cell>322052</cell>
                     <cell>72 45</cell>
                  </row>
                  <row>
                     <cell>50 50</cell>
                     <cell>16</cell>
                     <cell>33 45</cell>
                     <cell>66817</cell>
                     <cell>122791</cell>
                     <cell>312399</cell>
                     <cell>72 15</cell>
                  </row>
                  <row>
                     <cell>49 55</cell>
                     <cell>15</cell>
                     <cell>33 15</cell>
                     <cell>65562</cell>
                     <cell>118848</cell>
                     <cell>303259</cell>
                     <cell>71 45</cell>
                  </row>
                  <row>
                     <cell>49 0<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>1<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>32 45</cell>
                     <cell>64322</cell>
                     <cell>115134</cell>
                     <cell>294590</cell>
                     <cell>71 15</cell>
                  </row>
                  <row>
                     <cell>48 09</cell>
                     <cell>13</cell>
                     <cell>32 15</cell>
                     <cell>63095</cell>
                     <cell>111630</cell>
                     <cell>286356</cell>
                     <cell>70 45</cell>
                  </row>
                  <row>
                     <cell>47 17</cell>
                     <cell>12</cell>
                     <cell>31 45</cell>
                     <cell>61881</cell>
                     <cell>108321</cell>
                     <cell>278523</cell>
                     <cell>70 15</cell>
                  </row>
                  <row>
                     <cell>46 28</cell>
                     <cell>1<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>31 15</cell>
                     <cell>60681</cell>
                     <cell>105190</cell>
                     <cell>271061</cell>
                     <cell>69 45</cell>
                  </row>
                  <row>
                     <cell>45 38</cell>
                     <cell>10</cell>
                     <cell>30 45</cell>
                     <cell>59493</cell>
                     <cell>102226</cell>
                     <cell>263945</cell>
                     <cell>69 15</cell>
                  </row>
                  <row>
                     <cell>44 50</cell>
                     <cell>9</cell>
                     <cell>30 15</cell>
                     <cell>58318</cell>
                     <cell>99415</cell>
                     <cell>257149</cell>
                     <cell>68 45</cell>
                  </row>
                  <row>
                     <cell>44 03</cell>
                     <cell>8</cell>
                     <cell>29 45</cell>
                     <cell>57154</cell>
                     <cell>96748</cell>
                     <cell>250651</cell>
                     <cell>68 15</cell>
                  </row>
                  <row>
                     <cell>43 18</cell>
                     <cell>7</cell>
                     <cell>29 15</cell>
                     <cell>56002</cell>
                     <cell>94215</cell>
                     <cell>244432</cell>
                     <cell>67 45</cell>
                  </row>
                  <row>
                     <cell>42 34</cell>
                     <cell>6</cell>
                     <cell>28 45</cell>
                     <cell>54861</cell>
                     <cell>91805</cell>
                     <cell>238472</cell>
                     <cell>67 15</cell>
                  </row>
                  <row>
                     <cell>41 50</cell>
                     <cell>5</cell>
                     <cell>28 15</cell>
                     <cell>53731</cell>
                     <cell>89512</cell>
                     <cell>232756</cell>
                     <cell>66 45</cell>
                  </row>
                  <row>
                     <cell>41 08</cell>
                     <cell>4</cell>
                     <cell>27 45</cell>
                     <cell>52612</cell>
                     <cell>87327</cell>
                     <cell>227267</cell>
                     <cell>66 15</cell>
                  </row>
                  <row>
                     <cell>40 27</cell>
                     <cell>3</cell>
                     <cell>27 15</cell>
                     <cell>51503</cell>
                     <cell>85244</cell>
                     <cell>221991</cell>
                     <cell>65 45</cell>
                  </row>
                  <row>
                     <cell>39 47</cell>
                     <cell>2</cell>
                     <cell>26 45</cell>
                     <cell>50404</cell>
                     <cell>83256</cell>
                     <cell>216916</cell>
                     <cell>65 15</cell>
                  </row>
                  <row>
                     <cell>39 08</cell>
                     <cell>1</cell>
                     <cell>26 15</cell>
                     <cell>49314</cell>
                     <cell>81358</cell>
                     <cell>212030</cell>
                     <cell>64 45</cell>
                  </row>
                  <row>
                     <cell>38 29</cell>
                     <cell>0</cell>
                     <cell>25 45</cell>
                     <cell>48234</cell>
                     <cell>79498</cell>
                     <cell>207231</cell>
                     <cell>64 15</cell>
                  </row>
                  <row>
                     <cell>37 53</cell>
                     <cell>1</cell>
                     <cell>25 15</cell>
                     <cell>47163</cell>
                     <cell>77808</cell>
                     <cell>202719</cell>
                     <cell>63 45</cell>
                  </row>
                  <row>
                     <cell>37 17</cell>
                     <cell>2</cell>
                     <cell>24 45</cell>
                     <cell>46100</cell>
                     <cell>76148</cell>
                     <cell>198396</cell>
                     <cell>63 15</cell>
                  </row>
                  <row>
                     <cell>36 <gap reason="illegible" resp="#PDCC" extent="2 letters">
                           <desc>••</desc>
                        </gap>
                     </cell>
                     <cell>3</cell>
                     <cell>24 15</cell>
                     <cell>45046</cell>
                     <cell>74558</cell>
                     <cell>194162</cell>
                     <cell>62 45</cell>
                  </row>
                  <row>
                     <cell>36 08</cell>
                     <cell>4</cell>
                     <cell>23 45</cell>
                     <cell>44001</cell>
                     <cell>73033</cell>
                     <cell>190068</cell>
                     <cell>62 15</cell>
                  </row>
                  <row>
                     <cell>25 36</cell>
                     <cell>5</cell>
                     <cell>23 15</cell>
                     <cell>42963</cell>
                     <cell>71573</cell>
                     <cell>186109</cell>
                     <cell>61 45</cell>
                  </row>
                  <row>
                     <cell>35 03</cell>
                     <cell>6</cell>
                     <cell>22 45</cell>
                     <cell>41933</cell>
                     <cell>7017<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>182275</cell>
                     <cell>61 15</cell>
                  </row>
                  <row>
                     <cell>34 33</cell>
                     <cell>7</cell>
                     <cell>22 15</cell>
                     <cell>40911</cell>
                     <cell>68825</cell>
                     <cell>178562</cell>
                     <cell>60 45</cell>
                  </row>
                  <row>
                     <cell>34 02</cell>
                     <cell>8</cell>
                     <cell>21 45</cell>
                     <cell>39895</cell>
                     <cell>67538</cell>
                     <cell>174963</cell>
                     <cell>60 15</cell>
                  </row>
                  <row>
                     <cell>33 32</cell>
                     <cell>9</cell>
                     <cell>21 15</cell>
                     <cell>38887</cell>
                     <cell>66292</cell>
                     <cell>171472</cell>
                     <cell>59 4<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>33 03</cell>
                     <cell>10</cell>
                     <cell>20 45</cell>
                     <cell>37886</cell>
                     <cell>65099</cell>
                     <cell>168084</cell>
                     <cell>59 15</cell>
                  </row>
                  <row>
                     <cell>32 36</cell>
                     <cell>11</cell>
                     <cell>20 15</cell>
                     <cell>36891</cell>
                     <cell>63951</cell>
                     <cell>164994</cell>
                     <cell>58 45</cell>
                  </row>
                  <row>
                     <cell>32 08</cell>
                     <cell>12</cell>
                     <cell>19 45</cell>
                     <cell>35903</cell>
                     <cell>62847</cell>
                     <cell>161598</cell>
                     <cell>58 15</cell>
                  </row>
                  <row>
                     <cell>31 42</cell>
                     <cell>13</cell>
                     <cell>19 15</cell>
                     <cell>34921</cell>
                     <cell>61784</cell>
                     <cell>158490</cell>
                     <cell>57 54</cell>
                  </row>
                  <row>
                     <cell>31 17</cell>
                     <cell>14</cell>
                     <cell>18 45</cell>
                     <cell>33945</cell>
                     <cell>60761</cell>
                     <cell>155467</cell>
                     <cell>57 15</cell>
                  </row>
                  <row>
                     <cell>30 52</cell>
                     <cell>15</cell>
                     <cell>18 15</cell>
                     <cell>32975</cell>
                     <cell>59775</cell>
                     <cell>152525</cell>
                     <cell>56 45</cell>
                  </row>
                  <row>
                     <cell>30 28</cell>
                     <cell>16</cell>
                     <cell>17 45</cell>
                     <cell>32010</cell>
                     <cell>58825</cell>
                     <cell>149660</cell>
                     <cell>56 15</cell>
                  </row>
                  <row>
                     <cell>30 05</cell>
                     <cell>17</cell>
                     <cell>17 15</cell>
                     <cell>31050</cell>
                     <cell>57909</cell>
                     <cell>146869</cell>
                     <cell>55 45</cell>
                  </row>
                  <row>
                     <cell>29 42</cell>
                     <cell>18</cell>
                     <cell>16 45</cell>
                     <cell>30096</cell>
                     <cell>57026</cell>
                     <cell>144149</cell>
                     <cell>55 15</cell>
                  </row>
                  <row>
                     <cell>29 19</cell>
                     <cell>19</cell>
                     <cell>16 15</cell>
                     <cell>29147</cell>
                     <cell>56174</cell>
                     <cell>141496</cell>
                     <cell>54 45</cell>
                  </row>
                  <row>
                     <cell>28 5<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>20</cell>
                     <cell>15 45</cell>
                     <cell>28202</cell>
                     <cell>55353</cell>
                     <cell>138908</cell>
                     <cell>54 15</cell>
                  </row>
                  <row>
                     <cell>28 36</cell>
                     <cell>21</cell>
                     <cell>15 15</cell>
                     <cell>27263</cell>
                     <cell>54559</cell>
                     <cell>136382</cell>
                     <cell>53 45</cell>
                  </row>
                  <row>
                     <cell>28 16</cell>
                     <cell>22</cell>
                     <cell>14 45</cell>
                     <cell>26327</cell>
                     <cell>53794</cell>
                     <cell>133916</cell>
                     <cell>53 15</cell>
                  </row>
                  <row>
                     <cell>27 57</cell>
                     <cell>23</cell>
                     <cell>14 15</cell>
                     <cell>25396</cell>
                     <cell>53055</cell>
                     <cell>131506</cell>
                     <cell>52 45</cell>
                  </row>
                  <row>
                     <cell>27 47</cell>
                     <cell>69</cell>
                     <cell>14 00</cell>
                     <cell>24932</cell>
                     <cell>52695</cell>
                     <cell>130522</cell>
                     <cell>52 30</cell>
                  </row>
               </table>
            </p>
            <p>
               <table>
                  <head>The Table for drawing the houre lines</head>
                  <row>
                     <cell role="label" cols="3">T. 125717</cell>
                     <cell role="label" cols="3">P. 34921</cell>
                  </row>
                  <row>
                     <cell role="label" cols="3">
                        <hi>H</hi>
                     </cell>
                     <cell role="label" cols="3">
                        <hi>I</hi>
                     </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>1</cell>
                     <cell>1745</cell>
                     <cell>46</cell>
                     <cell>103553</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>2</cell>
                     <cell>3492</cell>
                     <cell>47</cell>
                     <cell>107236</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>3</cell>
                     <cell>5240</cell>
                     <cell>48</cell>
                     <cell>111061</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>4</cell>
                     <cell>6992</cell>
                     <cell>49</cell>
                     <cell>115063</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>5</cell>
                     <cell>8748</cell>
                     <cell>50</cell>
                     <cell>119175</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>6</cell>
                     <cell>10510</cell>
                     <cell>51</cell>
                     <cell>123489</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>7</cell>
                     <cell>12278</cell>
                     <cell>52</cell>
                     <cell>127994</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>8</cell>
                     <cell>14054</cell>
                     <cell>53</cell>
                     <cell>132704</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>9</cell>
                     <cell>15838</cell>
                     <cell>54</cell>
                     <cell>137638</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>10</cell>
                     <cell>17632</cell>
                     <cell>55</cell>
                     <cell>142814</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>11</cell>
                     <cell>19438</cell>
                     <cell>56</cell>
                     <cell>148256</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>12</cell>
                     <cell>21255</cell>
                     <cell>57</cell>
                     <cell>153986</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>13</cell>
                     <cell>23086</cell>
                     <cell>58</cell>
                     <cell>160033</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>14</cell>
                     <cell>24932</cell>
                     <cell>59</cell>
                     <cell>166427</cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell>7</cell>
                     <cell>15</cell>
                     <cell>26794</cell>
                     <cell>60</cell>
                     <cell>173205</cell>
                     <cell>10</cell>
                  </row>
                  <row>
                     <cell> </cell>
                     <cell>16</cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="3 letters">
                           <desc>•••</desc>
                        </gap>
                     </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="2 letters">
                           <desc>••</desc>
                        </gap>
                     </cell>
                     <cell> </cell>
                  </row>
               </table>
            </p>
            <p>
               <table>
                  <head>The Table fo<gap reason="illegible" resp="#PDCC" extent="1 letter">
                        <desc>•</desc>
                     </gap> 
                     <gap reason="illegible" resp="#PDCC" extent="1 span">
                        <desc>〈…〉</desc>
                     </gap>
                  </head>
                  <row>
                     <cell> </cell>
                     <cell role="label">
                        <hi>I</hi>
                     </cell>
                     <cell role="label">
                        <hi>F</hi>
                     </cell>
                     <cell role="label">
                        <hi>M</hi>
                     </cell>
                     <cell role="label">
                        <hi>A</hi>
                     </cell>
                  </row>
                  <row>
                     <cell>1</cell>
                     <cell>36 37</cell>
                     <cell>22 40</cell>
                     <cell>5 4<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>13 4</cell>
                  </row>
                  <row>
                     <cell>2</cell>
                     <cell>36 19</cell>
                     <cell>22 07</cell>
                     <cell>5 02</cell>
                     <cell>14 1<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>3</cell>
                     <cell>35 58</cell>
                     <cell>21 33</cell>
                     <cell>4 24</cell>
                     <cell>14 5</cell>
                  </row>
                  <row>
                     <cell>4</cell>
                     <cell>35 38</cell>
                     <cell>20 58</cell>
                     <cell>3 4<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>5 2</cell>
                  </row>
                  <row>
                     <cell>5</cell>
                     <cell>35 20</cell>
                     <cell>20 24</cell>
                     <cell>3 0<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>6 0</cell>
                  </row>
                  <row>
                     <cell>6</cell>
                     <cell>34 58</cell>
                     <cell>19 49</cell>
                     <cell>2 31</cell>
                     <cell>16 3<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>7</cell>
                     <cell>34 36</cell>
                     <cell>19 14</cell>
                     <cell>1 53</cell>
                     <cell>17 1</cell>
                  </row>
                  <row>
                     <cell>8</cell>
                     <cell>34 14</cell>
                     <cell>18 39</cell>
                     <cell>1 14</cell>
                     <cell>17 4<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>9</cell>
                     <cell>33 50</cell>
                     <cell>18 02</cell>
                     <cell>0 37</cell>
                     <cell>18 2</cell>
                  </row>
                  <row>
                     <cell>10</cell>
                     <cell>33 27</cell>
                     <cell>17 28</cell>
                     <cell>0 02</cell>
                     <cell>18 5<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>11</cell>
                     <cell>33 03</cell>
                     <cell>16 51</cell>
                     <cell>0 40</cell>
                     <cell>19 3</cell>
                  </row>
                  <row>
                     <cell>12</cell>
                     <cell>32 38</cell>
                     <cell>16 15</cell>
                     <cell>1 18</cell>
                     <cell>20 0<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>13</cell>
                     <cell>32 13</cell>
                     <cell>15 39</cell>
                     <cell>1 56</cell>
                     <cell>20 3<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>14</cell>
                     <cell>31 47</cell>
                     <cell>15 03</cell>
                     <cell>2 34</cell>
                     <cell>21 1<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>15</cell>
                     <cell>31 19</cell>
                     <cell>14 25</cell>
                     <cell>3 11</cell>
                     <cell>21 4<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>16</cell>
                     <cell>30 53</cell>
                     <cell>13 49</cell>
                     <cell>3 50</cell>
                     <cell>22 17</cell>
                  </row>
                  <row>
                     <cell>17</cell>
                     <cell>30 26</cell>
                     <cell>13 12</cell>
                     <cell>4 27</cell>
                     <cell>22 49</cell>
                  </row>
                  <row>
                     <cell>18</cell>
                     <cell>29 58</cell>
                     <cell>12 36</cell>
                     <cell>5 06</cell>
                     <cell>23 2<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>19</cell>
                     <cell>29 28</cell>
                     <cell>11 58</cell>
                     <cell>5 44</cell>
                     <cell>23 53</cell>
                  </row>
                  <row>
                     <cell>20</cell>
                     <cell>29 00</cell>
                     <cell>11 20</cell>
                     <cell>6 20</cell>
                     <cell>24 2<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>21</cell>
                     <cell>28 29</cell>
                     <cell>10 43</cell>
                     <cell>6 59</cell>
                     <cell>24 54</cell>
                  </row>
                  <row>
                     <cell>22</cell>
                     <cell>28 00</cell>
                     <cell>10 06</cell>
                     <cell>7 35</cell>
                     <cell>25 25</cell>
                  </row>
                  <row>
                     <cell>23</cell>
                     <cell>27 29</cell>
                     <cell>9 29</cell>
                     <cell>8 12</cell>
                     <cell>25 56</cell>
                  </row>
                  <row>
                     <cell>24</cell>
                     <cell>27 00</cell>
                     <cell>8 50</cell>
                     <cell>8 50</cell>
                     <cell>26 25</cell>
                  </row>
                  <row>
                     <cell>25</cell>
                     <cell>26 29</cell>
                     <cell>8 12</cell>
                     <cell>9 27</cell>
                     <cell>26 56</cell>
                  </row>
                  <row>
                     <cell>26</cell>
                     <cell>25 56</cell>
                     <cell>7 35</cell>
                     <cell>10 03</cell>
                     <cell>27 26</cell>
                  </row>
                  <row>
                     <cell>27</cell>
                     <cell>25 25</cell>
                     <cell>6 57</cell>
                     <cell>10 40</cell>
                     <cell>27 58</cell>
                  </row>
                  <row>
                     <cell>28</cell>
                     <cell>24 53</cell>
                     <cell>6 20</cell>
                     <cell>11 16</cell>
                     <cell>28 24</cell>
                  </row>
                  <row>
                     <cell>29</cell>
                     <cell>24 21</cell>
                     <cell> </cell>
                     <cell>11 53</cell>
                     <cell>28 50</cell>
                  </row>
                  <row>
                     <cell>30</cell>
                     <cell>23 46</cell>
                     <cell> </cell>
                     <cell>12 29</cell>
                     <cell>29 17</cell>
                  </row>
                  <row>
                     <cell>31</cell>
                     <cell>23 13</cell>
                     <cell> </cell>
                     <cell>13 07</cell>
                     <cell> </cell>
                  </row>
               </table>
            </p>
            <p>
               <table>
                  <head>The Table for the inſerti<gap reason="illegible" resp="#PDCC" extent="2 letters">
                        <desc>••</desc>
                     </gap> 
                     <gap reason="illegible" resp="#PDCC" extent="1 span">
                        <desc>〈…〉</desc>
                     </gap>
                  </head>
                  <row>
                     <cell> </cell>
                     <cell role="label">0</cell>
                     <cell role="label">1</cell>
                     <cell role="label">2</cell>
                     <cell role="label">3</cell>
                     <cell role="label">
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>1</cell>
                     <cell>45 00</cell>
                     <cell>42 00</cell>
                     <cell>39 49</cell>
                     <cell>37 34</cell>
                     <cell>3</cell>
                  </row>
                  <row>
                     <cell>2</cell>
                     <cell>26 33</cell>
                     <cell>25 28</cell>
                     <cell>24 27</cell>
                     <cell>23 30</cell>
                     <cell>2</cell>
                  </row>
                  <row>
                     <cell>3</cell>
                     <cell>18 26</cell>
                     <cell>17 53</cell>
                     <cell>17 21</cell>
                     <cell>16 51</cell>
                     <cell>1</cell>
                  </row>
                  <row>
                     <cell>4</cell>
                     <cell>14 02</cell>
                     <cell>13 43</cell>
                     <cell>13 23</cell>
                     <cell>13 06</cell>
                     <cell>8</cell>
                  </row>
                  <row>
                     <cell>5</cell>
                     <cell>11 19</cell>
                     <cell>11 06</cell>
                     <cell>10 53</cell>
                     <cell>10 41</cell>
                     <cell>1</cell>
                  </row>
                  <row>
                     <cell>6</cell>
                     <cell>9 27</cell>
                     <cell>9 19</cell>
                     <cell>9 10</cell>
                     <cell>9 01</cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                  </row>
                  <row>
                     <cell>7</cell>
                     <cell>8 07</cell>
                     <cell>8 01</cell>
                     <cell>7 54</cell>
                     <cell>7 48</cell>
                     <cell>7</cell>
                  </row>
                  <row>
                     <cell>8</cell>
                     <cell>7 07</cell>
                     <cell>7 02</cell>
                     <cell>6 58</cell>
                     <cell>6 52</cell>
                     <cell>6</cell>
                  </row>
                  <row>
                     <cell>9</cell>
                     <cell>6 20</cell>
                     <cell>6 16</cell>
                     <cell>6 12</cell>
                     <cell>6 08</cell>
                     <cell>6</cell>
                  </row>
                  <row>
                     <cell>10</cell>
                     <cell>5 43</cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell>15</cell>
                     <cell>3 49</cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell>20</cell>
                     <cell>2 51</cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                  </row>
                  <row>
                     <cell>40</cell>
                     <cell>1 26</cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                     <cell> </cell>
                  </row>
               </table>
            </p>
            <p>
               <table>
                  <head>The Table for drawing, and div<gap reason="illegible" resp="#PDCC" extent="5 letters">
                        <desc>•••••</desc>
                     </gap> 
                     <gap reason="illegible" resp="#PDCC" extent="1 span">
                        <desc>〈…〉</desc>
                     </gap>
                  </head>
                  <row>
                     <cell role="label" cols="3">♑. 26794.</cell>
                     <cell role="label">♋. 1880</cell>
                  </row>
                  <row>
                     <cell role="label">
                        <hi>K</hi>
                     </cell>
                     <cell role="label">
                        <hi>L</hi>
                     </cell>
                     <cell role="label">
                        <hi>M</hi>
                     </cell>
                     <cell role="label">
                        <hi>N</hi>
                     </cell>
                  </row>
                  <row>
                     <cell>1</cell>
                     <cell>0 55</cell>
                     <cell>2604</cell>
                     <cell>46</cell>
                  </row>
                  <row>
                     <cell>2</cell>
                     <cell>1 50</cell>
                     <cell>3200</cell>
                     <cell>47</cell>
                  </row>
                  <row>
                     <cell>3</cell>
                     <cell>2 45</cell>
                     <cell>4893</cell>
                     <cell>48</cell>
                  </row>
                  <row>
                     <cell>4</cell>
                     <cell>3 40</cell>
                     <cell>6408</cell>
                     <cell>49</cell>
                  </row>
                  <row>
                     <cell>5</cell>
                     <cell>4 35</cell>
                     <cell>8016</cell>
                     <cell>50</cell>
                  </row>
                  <row>
                     <cell>6</cell>
                     <cell>5 31</cell>
                     <cell>9658</cell>
                     <cell>51</cell>
                  </row>
                  <row>
                     <cell>7</cell>
                     <cell>6 25</cell>
                     <cell>11246</cell>
                     <cell>52</cell>
                  </row>
                  <row>
                     <cell>8</cell>
                     <cell>7 21</cell>
                     <cell>12899</cell>
                     <cell>53</cell>
                  </row>
                  <row>
                     <cell>9</cell>
                     <cell>8 10</cell>
                     <cell>14350</cell>
                     <cell>54</cell>
                  </row>
                  <row>
                     <cell>10</cell>
                     <cell>9 12</cell>
                     <cell>16196</cell>
                     <cell>55</cell>
                  </row>
                  <row>
                     <cell>11</cell>
                     <cell>10 07</cell>
                     <cell>17842</cell>
                     <cell>56</cell>
                  </row>
                  <row>
                     <cell>12</cell>
                     <cell>11 03</cell>
                     <cell>19528</cell>
                     <cell>57</cell>
                  </row>
                  <row>
                     <cell>13</cell>
                     <cell>11 57</cell>
                     <cell>21164</cell>
                     <cell>58</cell>
                  </row>
                  <row>
                     <cell>14</cell>
                     <cell>12 53</cell>
                     <cell>22872</cell>
                     <cell>59</cell>
                  </row>
                  <row>
                     <cell>15</cell>
                     <cell>13 48</cell>
                     <cell>24562</cell>
                     <cell>60</cell>
                  </row>
                  <row>
                     <cell>16</cell>
                     <cell> </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>
                     </cell>
                     <cell>
                        <gap reason="illegible" resp="#PDCC" extent="2 letters">
                           <desc>••</desc>
                        </gap>
                     </cell>
                  </row>
               </table>
            </p>
         </div>
      </front>
      <body>
         <div type="text">
            <pb facs="tcp:10089:12"/>
            <div type="part">
               <head>Of the Making of the Horizontall Quadrant by the Sector.</head>
               <div type="section">
                  <head>1. How to de<g ref="char:EOLhyphen"/>ſcribe the Parallels.</head>
                  <p>
                     <hi>
                        <seg rend="decorInit">F</seg>Irſt,</hi> according to any <hi>Semidiameter</hi> as <hi>Z N.</hi> or <hi>Z S.</hi> deſcribe a Circle repreſenting the <hi>Horizon,</hi> and draw the line <hi>S N.</hi> for the <hi>Meridian:</hi> Divide the halfe <hi>Meridian Z N.</hi> and <hi>Z S.</hi> into 90. gr. according to the <hi>Tan<g ref="char:EOLhyphen"/>gents</hi> of halfe their Arkes, by the helpe of the <hi>Sines</hi> on the edge of the <hi>Sector:</hi> or the ſemidiameters may be divi<g ref="char:EOLhyphen"/>ded into ſuch parts, or points as are required concerning the <hi>Projection,</hi> thus. Conſider what parallels you would deſcribe, and how much they are diſtant from the <hi>Zenith</hi> in their interſections, in the <hi>Meridian</hi> both towards the South and North of the <hi>Zenith</hi> (for every parallell in an oblique <hi>Spheare,</hi> in his interſection with the <hi>Meridian,</hi> is farther from the <hi>Zenith</hi> in one part, than in an other) Then if the ſemidiameter <hi>Z N.</hi> be placed over in the <hi>ſigne Complement</hi> of halfe that diſtance, from the Zenith, the parallell <hi>Sine</hi> of the former halfe taken from the <hi>Sector:</hi> ſhall from ſhew the interſection in the <hi>Meridian</hi> with that parallell.</p>
                  <p>
                     <table>
                        <row>
                           <cell> </cell>
                           <cell> </cell>
                           <cell> </cell>
                           <cell> </cell>
                           <cell> </cell>
                           <cell role="label">gr. m.</cell>
                           <cell> </cell>
                           <cell role="label">gr. m.</cell>
                        </row>
                        <row>
                           <cell rows="6">So if the paralles were the</cell>
                           <cell>
                              <hi>Tropicke</hi> of ♋</cell>
                           <cell rows="6">whoſe diſtan<g ref="char:EOLhyphen"/>ces of inter<g ref="char:EOLhyphen"/>ſections in the Meridian (ac<g ref="char:EOLhyphen"/>cording to the Lat. of 51. gr. 30. m.) from Z. towards</cell>
                           <cell>S. the South</cell>
                           <cell rows="6">is</cell>
                           <cell>28. 0.</cell>
                           <cell rows="6">The halfe of theſe Arks are</cell>
                           <cell>14.00. A</cell>
                        </row>
                        <row>
                           <cell> </cell>
                           <cell>N. the North</cell>
                           <cell>105.0,</cell>
                           <cell>52.30. B</cell>
                        </row>
                        <row>
                           <cell>
                              <hi>Aequator</hi>
                           </cell>
                           <cell>S. the South</cell>
                           <cell>51.30.</cell>
                           <cell>25.45. C</cell>
                        </row>
                        <row>
                           <cell> </cell>
                           <cell>N. the North</cell>
                           <cell>128.30</cell>
                           <cell>64.15. D</cell>
                        </row>
                        <row>
                           <cell>
                              <hi>Tropicke</hi> of ♑</cell>
                           <cell>S. the South</cell>
                           <cell>75.30.</cell>
                           <cell>37.30. E</cell>
                        </row>
                        <row>
                           <cell> </cell>
                           <cell>N the North</cell>
                           <cell>152.0.</cell>
                           <cell>76.00. F</cell>
                        </row>
                     </table>
                  </p>
                  <pb n="2" facs="tcp:10089:13"/>
                  <p>Now if the ſemidiameter <hi>Z. S.</hi> bee placed in the <hi>Sine Complement</hi> of A. viz. 76. gr. and then the parallell Sine of A taken, viz. 14. gr. it will reach from <hi>Z.</hi> to ♋. the in<g ref="char:EOLhyphen"/>terſection of the <hi>Tropicke</hi> of ♋ with the South part of the <hi>Meridian,</hi> but if the ſemidiameter <hi>Z. S.</hi> be placed over in the <hi>Sine Complement. B.</hi> viz. 37. gr. 30. m. &amp; then the pa<g ref="char:EOLhyphen"/>rallell Sine of <hi>B.</hi> viz. 52. gr. 30. m. being taken it will reach from <hi>Z</hi> to V. the other interſection of the <hi>Tropicke</hi> of 69 with the <hi>Meridian</hi> below the Pole, the Middle betweene this V. and 69. will bee at 1. which is the Center of that <hi>Tropicke:</hi> In like manner may be found the interſections, and <hi>Centers</hi> of the other parallels with the <hi>Meridians,</hi> and ſo may be deſcribed.</p>
               </div>
               <div type="section">
                  <head>2. To de<g ref="char:EOLhyphen"/>ſcribe rhe houre lines</head>
                  <p>
                     <hi>Secondly,</hi> ſeeing the Lat. is 51. gr. 30. take the Semidiame<g ref="char:EOLhyphen"/>ter <hi>Z S.</hi> and fit it over in the <hi>Sine Complement</hi> of it, viz. 38. gr. 30. then the parallell ſine of 51. gr. 30. m. will reach from <hi>Z.</hi> to <hi>T.</hi> the center of the houre of 6. <hi>E P W.</hi> but if the <hi>Radius Z S.</hi> be fitted over in the <hi>Sine Comple<g ref="char:EOLhyphen"/>ment</hi> of halfe 38. gr. 30. viz. 70. gr. 45. m. and the parallell ſine of halfe 38. gr. 30. viz. 19. gr. 15. m. be taken, it will reach from <hi>Z.</hi> to <hi>P.</hi> the <hi>Pole,</hi> then upon <hi>T.</hi> erect a perpen<g ref="char:EOLhyphen"/>dicular to the line <hi>P T.</hi> viz. 2. <hi>T.</hi> 10. which ſhall ſerve for the finding of the Centers of the <hi>Meridians,</hi> or houre Cir<g ref="char:EOLhyphen"/>cles paſſing through the <hi>Pole P.</hi> now ſeeing that <hi>T P.</hi> is the neereſt diſtance in the right line 2. 10. unto <hi>P.</hi> the right line <hi>P. T.</hi> ſhall be <hi>Radius,</hi> to a Circle, and the line 2. <hi>T.</hi> 10. ſhal be a Tangent line to that Circle. Now the <hi>Radius</hi> of a Circle being knowne, the Tangent of any Angle, or Arke, may be alſo knowne, according to the Naturall projection and congruity of lines, but becauſe in this firſt direction we would apply it ſoly to the <hi>Sector:</hi> the center of the <hi>Meridians</hi> or houres may be had by the helpe of the Sines thereon thus.</p>
                  <p>Conſider what houre, or <hi>Meridian circle</hi> from the houre of 6. viz. <hi>E, P, W.</hi> you would diſcribe, for then if the <hi>Radius P, T.</hi> be fitted over in the <hi>Sine complement</hi> of it and the parallell <hi>Sine</hi> of the houre Angle Taken, it will ſhew from <hi>T,</hi> in the line 2. 10. the center of that <hi>Meri<g ref="char:EOLhyphen"/>dian,</hi> or houre circle: ſo if the houre circle of 5. or 7. were
<pb n="3" facs="tcp:10089:13"/> to be deſcribed, whoſe houre Angle at <hi>P,</hi> the Pole is 15. gr. fit the <hi>Radius</hi> or ſemediameter <hi>T, P.</hi> over in the Sine complement of it viz. 75. gr. for then the Sine perallell of 15. gr. being taken will reach from <hi>T,</hi> to 5. and from <hi>T,</hi> to 7, the Center of the houre circles of 5 and 7. If therefore one foote of the Cumpaſſes be placed in 5. and then extended to <hi>P.</hi> the Pole, you may deſcribe the houre Circle of 5. and placed in 7. you may draw the houre Circle of 7. and ſo may be deſcribed the reſt of the <hi>Meridians.</hi> and houre Circles.</p>
               </div>
               <div type="section">
                  <head>3 To de<g ref="char:EOLhyphen"/>ſcribe and divide the Eclipticke</head>
                  <p>
                     <hi>Thirdly,</hi> to deſcribe the <hi>Eclipticke,</hi> conſider the diſtan<g ref="char:EOLhyphen"/>ces betweene the <hi>Zenith Z.</hi> and the Tropicks of ♑. and 69. according to the former Lat. of 51. gr. 30. which will be <hi>Z,</hi> ♑ 75. gr. and <hi>Z.</hi> ♋. 28. gr. then take the ſemideameter <hi>Z, S.</hi> and fit it over in the <hi>Sine</hi> of thoſe Arkes, then the par<g ref="char:EOLhyphen"/>allell <hi>Sines</hi> of the Complements of thoſe Arkes will ſhew from <hi>Z.</hi> the diſtances of the Centers of theſe Tro<g ref="char:EOLhyphen"/>picall points, ſo the Center of the Southerne ſemicircle of the <hi>Eclipticke,</hi> will be neare the Pole <hi>P,</hi> viz. at ♑. and the Center of the Northerne ſemicircle of the <hi>Eclipticke</hi> will be below the Pole at ♋. Therefore placing one foote of the Cumpaſſes in ♋. below the Pole, and extending the other foote to ♋. above the <hi>Pole</hi> you may deſcribe the ſemicircle <hi>E,</hi> ♋. <hi>W.</hi> and placing one foote in ♑. neare the <hi>Pole,</hi> you may deſcribe the ſemicircle, <hi>E,</hi> ♑, <hi>W.</hi>
                  </p>
                  <p>Now for the dividing of the <hi>Eclipticke;</hi> this Mr. <hi>Gun<g ref="char:EOLhyphen"/>ter</hi> delivers ſo obſtruſly in his 66, page of the Sector. That if a man had not more fundamentall Mathematicall Do<g ref="char:EOLhyphen"/>ctrine, then his Booke teacheth, he ſhould never attaine unto it: Conſider therefore firſt, what right Angle Triangles there are made by this <hi>Eclipticke, Equator</hi> and <hi>Meridians,</hi> viz, ♈ B ♓. or ♈ <hi>B</hi> ♉: ♈ <hi>R</hi> ♒. or ♈ <hi>R</hi> ♊, &amp;c. and get the <hi>right aſcention</hi> of theſe Arkes of the <hi>Eclipticke</hi> hat you intend to divide, ſo ♈, <hi>B.</hi> is the <hi>right aſcention</hi> of the Arkes ♈, ♉, and ♈, ♓. and ♈, <hi>R.</hi> is the Right aſention of Arkes ♈, ♊, and ♈, ♒, from which ground the Table <hi>S.</hi> is calculated according to the Arkes in the <hi>Eclipticke</hi> in the Table <hi>R.</hi> Now to finde the Centers of thoſe <hi>Me<g ref="char:EOLhyphen"/>ridians</hi> which may divide the <hi>Eclipticke</hi> according to the
<pb n="4" facs="tcp:10089:14"/> 
                     <hi>Right aſcenſion</hi> here calculated anſwerable to
<table>
                        <row>
                           <cell role="label">
                              <hi>R.</hi>
                           </cell>
                           <cell role="label">
                              <hi>S.</hi>
                           </cell>
                        </row>
                        <row>
                           <cell>5</cell>
                           <cell>4.45</cell>
                        </row>
                        <row>
                           <cell>10</cell>
                           <cell>9.11</cell>
                        </row>
                        <row>
                           <cell>15</cell>
                           <cell>13.48</cell>
                        </row>
                        <row>
                           <cell>20</cell>
                           <cell>18.27</cell>
                        </row>
                        <row>
                           <cell>25</cell>
                           <cell>23.09</cell>
                        </row>
                        <row>
                           <cell>30</cell>
                           <cell>27.54</cell>
                        </row>
                        <row>
                           <cell>35</cell>
                           <cell>32.42</cell>
                        </row>
                        <row>
                           <cell>40</cell>
                           <cell>37.35</cell>
                        </row>
                        <row>
                           <cell>45</cell>
                           <cell>42.31</cell>
                        </row>
                        <row>
                           <cell>50</cell>
                           <cell>47.33</cell>
                        </row>
                        <row>
                           <cell>55</cell>
                           <cell>52.38</cell>
                        </row>
                        <row>
                           <cell>60</cell>
                           <cell>57.48</cell>
                        </row>
                        <row>
                           <cell>65</cell>
                           <cell>63.03</cell>
                        </row>
                        <row>
                           <cell>70</cell>
                           <cell>68.21</cell>
                        </row>
                        <row>
                           <cell>75</cell>
                           <cell>73.43</cell>
                        </row>
                        <row>
                           <cell>80</cell>
                           <cell>79.07</cell>
                        </row>
                        <row>
                           <cell>85</cell>
                           <cell>84.32</cell>
                        </row>
                        <row>
                           <cell>90</cell>
                           <cell>90.00</cell>
                        </row>
                     </table> the Arkes of the <hi>Eclipticke</hi> from ♈ or ♎ it nothing differeth from the inſtruction of the deſcribing of the houre Circles, in the ſecond derection: for if I would interſect the <hi>Eclip<g ref="char:EOLhyphen"/>ticke</hi> in the beginning of ♉. ♓. ♍. or ♏. the diſtance of either of thoſe ſingcs from ♈ or ♎ is 30. gr. againſt which in the Table, <hi>S.</hi> is 27. gr. 54. m. Now if the ſemidiamiter <hi>P T.</hi> be fitted over in the <hi>ſine Complement</hi> of this 27. gr. 54. m. viz. 68. gr. 6. m. and then the parallell <hi>ſine</hi> of 27. gr. 54. m. being taken it wil reach fro<g ref="char:cmbAbbrStroke">̄</g> 
                     <hi>T.</hi> to 30. in the line 2. <hi>T.</hi> 10. if therefore one foote of the Compaſſes bee placed in 30. to<g ref="char:EOLhyphen"/>wards 10. and the other foote extended to <hi>P.</hi> you may interſect the <hi>Eclipticke</hi> in ♉. and ♓. and then the Compaſſes placed in the other 30. you may interſect the other part of the <hi>E<g ref="char:EOLhyphen"/>clipticke</hi> in ♍ and ♏. and ſo may you divide the reſt of the <hi>Eclipticke.</hi>
                  </p>
               </div>
            </div>
            <div type="part">
               <head>Of the making of the Horizontall Quadrant Geometrically.</head>
               <div n="1" type="section">
                  <p> 
                     <milestone type="tcpmilestone" unit="unspecified" n="1"/> 
                     <hi>FIrſt,</hi> having diſcribed a <hi>Cirrle</hi> at pleaſure as before, <hi>E. S. W. N.</hi> draw a line to paſſe by the center as <hi>S. N.</hi> and croſſe it at right Angles, with the line <hi>E. W.</hi> in <hi>Z.</hi> then let the <hi>ſemcircles W S E</hi> and <hi>W N E.</hi> bee divided from <hi>W.</hi> each of them into 180. gr. or rather upon <hi>E.</hi> wee may diſ<g ref="char:EOLhyphen"/>cribe a <hi>Quadrant</hi> at pleaſure, as <hi>C D.</hi> and augmenting it unto ω, divide the <hi>Quadrant D C.</hi> from <hi>D.</hi> into the uſuall diviſions of a <hi>Quadrant,</hi> and ſo from <hi>D.</hi> unto ω, inſert or protract the ſame diviſions, then having conſidered as be<g ref="char:EOLhyphen"/>fore
<pb n="5" facs="tcp:10089:14"/> the <hi>Latitude</hi> of the place, and diſtance of the parallels from <hi>Z.</hi> the <hi>Zenith,</hi> towards <hi>S.</hi> the <hi>South,</hi> and alſo towards <hi>N.</hi> the <hi>North,</hi> in the <hi>Meridian</hi> as in the former Table there is ſpecified. Account the diſtance of the parallels from the <hi>Zenith</hi> towards <hi>S.</hi> the <hi>South,</hi> in the ſemicircle <hi>W S E.</hi> but thoſe towards <hi>N</hi> the <hi>North,</hi> in the ſemicircle <hi>W N E.</hi> from <hi>W.</hi> ſo ſuppoſing the Latitude as before to bee 51. gr. 30.<note place="margin">1 To de<g ref="char:EOLhyphen"/>ſcribe the parallels.</note> m. the diſtance betweene the <hi>Zenith</hi> &amp; the Tro<g ref="char:EOLhyphen"/>picke of 69. towards the <hi>South,</hi> is 28. gr. which account from <hi>W.</hi> to <hi>F.</hi> but rather halfe of it from <hi>D.</hi> to <hi>F.</hi> then conſider the diſtance betweene the Zenith and the other part beyond the <hi>Pole,</hi> viz. 105. gr. number this from <hi>W.</hi> to <hi>G.</hi> but rather halfe uf it from <hi>D.</hi> to <hi>G.</hi> and laying a ru<g ref="char:EOLhyphen"/>ler upon <hi>E. F.</hi> and <hi>E. G.</hi> the <hi>Meridian A B.</hi> may be inter<g ref="char:EOLhyphen"/>ſected in 69. and <hi>V.</hi> the middle, betweene which will be at 1. the Center of the Tropicke: in like manner the di<g ref="char:EOLhyphen"/>ſtance of the <hi>Aequator</hi> from the Zenith towards the South is 51. gr 30. reckon it from <hi>W.</hi> to <hi>H.</hi> or halfe of it from <hi>D.</hi> to <hi>H.</hi> but the diſtance of the <hi>Aequater</hi> from the Zenith towards the <hi>North</hi> beyond the <hi>Pole</hi> is 128. gr. 30. m. which I account from <hi>W.</hi> to <hi>I.</hi> or halfe of it from <hi>D.</hi> to <hi>I,</hi> then laying a ruler upon <hi>E. H.</hi> and <hi>E. I.</hi> the <hi>Meridian A B.</hi> may be interſected in <hi>Q</hi> and <hi>Y.</hi> the halfe diſtance be<g ref="char:EOLhyphen"/>tweene <hi>Q</hi> and <hi>Y.</hi> will be at 2. the Center of the <hi>Aequater:</hi> In like manner may the <hi>Meridian A B.</hi> bee divided into any of the reſt of the diviſions, and the parallels alſo diſ<g ref="char:EOLhyphen"/>cribed: But if a ruler be faſtned to move upon <hi>E.</hi> then may you ſoftly move the ruler from <hi>D.</hi> towards ω. and as it paſſet by the degrees according to the Colume <hi>B.</hi> of the Tables following, beginnig at the bottome, ſo the edge of the ruler ſhall ſhew the interſections that the parallels of de<g ref="char:EOLhyphen"/>clination betweene the Tropickes do make, with the <hi>Me<g ref="char:EOLhyphen"/>ridian Z. S.</hi> then move the <hi>Ruler</hi> ſoftly along from <hi>D.</hi> to<g ref="char:EOLhyphen"/>wards <hi>C.</hi> as it paſſeth by the degrees in the Colume <hi>G.</hi> be<g ref="char:EOLhyphen"/>ginning at the bottome, ſo the edge of the <hi>Ruler</hi> ſhall in<g ref="char:EOLhyphen"/>terſect the <hi>Meridian A. B.</hi> in the Centers of thoſe paral<g ref="char:EOLhyphen"/>lels.</p>
               </div>
               <div n="2" type="section">
                  <p>
                     <hi>Secondly,</hi> account the <hi>Latitude</hi> from <hi>D</hi> to <hi>M.</hi> and halfe <milestone type="tcpmilestone" unit="unspecified" n="2"/> the Complement of the Lat. from <hi>D</hi> to <hi>R.</hi> and laying a
<pb n="6" facs="tcp:10089:15"/> ruler upon <hi>E M.</hi> and <hi>E R.</hi> the <hi>Meridian, S N.</hi> ſhall be in<g ref="char:EOLhyphen"/>terſected in <hi>T.</hi> and <hi>P. P.</hi> repreſenting the Pole of the world,<note place="margin">2 To de<g ref="char:EOLhyphen"/>ſcribe the houre lines</note> and <hi>T</hi> the center of the houre of 6. then unto the line <hi>T P.</hi> upon the point <hi>T.</hi> erect a <hi>perpendicular</hi> 2. 10. and according to the ſemidiameter <hi>P T.</hi> deſcribe a ſemicir<g ref="char:EOLhyphen"/>cle α <hi>T</hi> ς. divide the <hi>Quadrants T</hi> α and <hi>T</hi> ς. from <hi>T.</hi> each of them into 90. gr. then lay a ruler upon <hi>P.</hi> and the ſeve<g ref="char:EOLhyphen"/>rall houre Arkes in the <hi>Quadrants, T</hi> α. and <hi>T</hi> ς. inter<g ref="char:EOLhyphen"/>ſect the line 2. <hi>T.</hi> 10. in the houre points, 2. 3. 4. 5. 7. 8. 9. 10. &amp;c. then placing the Compaſſes in <hi>T.</hi> and extending the other foote to <hi>P.</hi> you may diſcribe the houre Circle of 6. but placing it in 5. and extended to <hi>P.</hi> you may diſcribe the houre Circle of 5. the ſame extent placed in 7. will diſ<g ref="char:EOLhyphen"/>cribe the houre Circle of 7. and ſo of the reſt: but if a ru<g ref="char:EOLhyphen"/>ler be faſtned to move on <hi>P.</hi> as it paſſeth by the degrees of the houres in the Quadrants from <hi>T.</hi> ſo the edge of the <hi>Ruler</hi> ſhall interſect the line 2. 10. in the Centers of thoſe houres from <hi>T.</hi>
                  </p>
               </div>
               <div n="3" type="section">
                  <head>3. To deſcribe and divide the Eclip<g ref="char:EOLhyphen"/>ticke.</head>
                  <p>
                     <hi>Thirdly,</hi> to deſcribe the <hi>Eclipticke,</hi> conſider the Altitude of each Tropicke above the <hi>Horizon,</hi> according to the <hi>La<g ref="char:EOLhyphen"/>titude</hi> given, which was 51. gr. 30. m. So the Altitude of ♑. is 15. gr. and that of 69. is 62. gr. In the Quadrant <hi>D C.</hi> ac<g ref="char:EOLhyphen"/>count thoſe degrees from <hi>D.</hi> viz. <hi>D y</hi> and <hi>D</hi> δ. lay a ruler upon <hi>E.</hi> and thoſe ſeverall points, ſo may the Meridian <hi>S. N.</hi> be interſected in the points ♑. and 69. which are the Centers of the ſemicircles of the Eclipticke, therefore placing one foote of the Compaſſes in 69. below the Pole, and extending the other foote to 69. above the Pole, you may diſcribe the Northeren ſemicircle <hi>E.</hi> 69. <hi>W.</hi> and pla<g ref="char:EOLhyphen"/>cing one foote of the Compaſſes in ♑. neere the Pole, and extending the other foote to ♑. neere <hi>S.</hi> you may deſcribe the <hi>Southerne ſemicircle E</hi> ♑ <hi>W.</hi> thoſe ſemicircles of the <hi>Eclipticke</hi> may bee divided <hi>Geometrically,</hi> without the helpe of the Table of <hi>right aſcenſion,</hi> but for more expe<g ref="char:EOLhyphen"/>dition we may uſe them thus. In the <hi>Quadrants T</hi> α. and <hi>T</hi> ς. account the degrees of the <hi>right aſcenſion</hi> for ſuch di<g ref="char:EOLhyphen"/>viſions of the <hi>Eclipticke</hi> as you intend to have, ſuppoſe the beginning of ♉ ♓ or ♍ ♏ the diſtances of the beginning of any of theſe ſignes, fromithe <hi>Equinoctiall</hi> points are
<pb n="7" facs="tcp:10089:15"/> equall the one unto the other. viz. 30. gr which finde in the Table under <hi>R.</hi> ſo right againſt it under <hi>S.</hi> is 27. gr. 54. m. this account from <hi>T.</hi> towards α. and ς. and laying a ruler upon <hi>P.</hi> and thoſe degrees interſect the Tangent line 2. 10. in 30. and then placing one foote of the Compaſſes in 30. towards 10. and extending the other foote to <hi>P.</hi> you may interſect the <hi>Eclipticke</hi> in the beginning of ♉. ♓. &amp; ſo in ♍ ♏. the points required: In the likemanner you may divide the other part of the <hi>Eclipticke.</hi> So the Centers of the de<g ref="char:EOLhyphen"/>grees of the Eclipticke may bee ſooner had, if a ruler bee placed upon <hi>P.</hi> and then to move thereon, Now as it paſ<g ref="char:EOLhyphen"/>ſeth by the degrees of the Columes <hi>I.O.</hi> in tha Tables fol<g ref="char:EOLhyphen"/>lowing from <hi>T.</hi> in the ſeveral <hi>Quadrants:</hi> ſo the <hi>Ruler</hi> ſhall Interſect the line 2. to in the Centers of thoſe Arkes an<g ref="char:EOLhyphen"/>ſwerable to the columes <hi>K N.</hi> the degrees of the Ecliptick.</p>
               </div>
            </div>
            <div type="part">
               <head>
                  <hi>3. By my Ring it may bee</hi> o<g ref="char:EOLhyphen"/>therwiſe projected: In which it exceeds any Inſtrument whatſoever for facility, and expedition, for where there is many proportionals required in any ſervice, there the uſe of the Ring is moſt excel<g ref="char:EOLhyphen"/>lently made manifeſt, they being inſtantly de<g ref="char:EOLhyphen"/>clared at once, which in ſome ſort I have deli<g ref="char:EOLhyphen"/>vered in the uſe of my Appendix upon plaine Triangles, or it may be drawne from that of Proportionating the Fort, to the Fort, or the Building, to the Building, Pag. the <hi>2.</hi> and <hi>3.</hi>
               </head>
               <p>LEt a Circle bee diſcribed according to any capacity, <label type="milestone">
                     <seg type="milestoneunit">Conſtructi. </seg>
                  </label> as before, and croſſed with <hi>diametrall lines</hi> at right Angles
<pb n="8" facs="tcp:10089:16"/> 
                  <hi>E Z W.</hi> and <hi>S Z N.</hi> then take the ſemidiameter <hi>E Z.</hi> and divide it into 10. parts, &amp; ſupdivide each of thoſe parts into 10. or 100. (according to the capacity of the ſcale) as <hi>A.</hi> or more accurately according to the ſame <hi>Radius</hi> make a <hi>dia<g ref="char:EOLhyphen"/>gonall</hi> ſeale, then conſider the diſtance of the <hi>parallels</hi> from the <hi>Zenith</hi> according to the <hi>Latitude</hi> you intend, as admit 51. gr. 30. m. to be the <hi>Latitude</hi> as before. Take the halfe of thoſe diſtances (according to the firſt directions) by which is made the Colume <hi>B.</hi> which are the halfe di<g ref="char:EOLhyphen"/>ſtances of every degree betweene the <hi>Tropickes</hi> and the <hi>Zenith,</hi> then move the <hi>Tangent</hi> of 45. gr. unto the parts of the <hi>Radius</hi> or ſemidiameter, viz. 10000. in the <hi>Circle</hi> of <hi>Numbers,</hi> ſo right againſt the Tangent of any one of thoſe degrees in the Colume <hi>B.</hi>
                  <note place="margin">Of the calculating of the Numbers, to deſcribe the paral<g ref="char:EOLhyphen"/>lels.</note> in the moveable is the Number of equall parts in the fixed, by which is made the Colume <hi>C.</hi> (or they may be extracted out of the Tables of naturall <hi>Tangents.</hi>) Further if we conſider the diſtance betweene the <hi>Zenith</hi> and the other interſections of thoſe parallels, with the <hi>Meridian</hi> beyond the <hi>Pole,</hi> and take halfe of thoſe diſtances wee may make the Colume <hi>D.</hi> then moving the moveable ſoftly along, as the <hi>Tangent</hi> of any degree of the Colume <hi>D.</hi> in the moveable, paſſeth by the parts of the ſcall, viz. 10000. in the fixed (on the Circle of Numbers) ſo the <hi>Tangent</hi> of 45. gr. in the moveable, ſhall point out in the Circle of <hi>Numbers,</hi> the diſtance betweene <hi>Z.</hi> and thoſe <hi>parallels</hi> beyond the <hi>Pole.</hi> From theſe directions are calcu<g ref="char:EOLhyphen"/>lated the Numbers in the Colume <hi>E.</hi> or they may bee alſo taken from the Table of naturall <hi>Tagents</hi> as before: The Numbers of the Colume <hi>C</hi> and <hi>E.</hi> ſerve to finde the diſtan<g ref="char:EOLhyphen"/>ces of the interſections of the <hi>parallels</hi> in the <hi>Meridian</hi> fro<g ref="char:cmbAbbrStroke">̄</g> 
                  <hi>Z.</hi> &amp; to diſcribe thoſe parallels, note that at the bottome of the Columes <hi>C.</hi> &amp; <hi>E.</hi> are the Numbers, 2493. &amp; 13032. take 2493. from the <hi>diagonall ſcale,</hi> and protract it from <hi>Z.</hi> towards <hi>S.</hi> viz. at ♋. then take from the ſame ſcale alſo, 13032. and protract it from <hi>Z.</hi> to ♋. below <hi>N.</hi> divide the ſpace betweene ♋. and ♋. into two equall parts which will be at 1. neere <hi>P.</hi> ſo have you the Center of the Tro<g ref="char:EOLhyphen"/>picke of ♋. extend the <hi>Compaſſes</hi> therefore from 1. to ♋. then may you deſcribe that <hi>Tropicke,</hi> viz. δ. ♋. ζ. In like
<pb n="9" facs="tcp:10089:16"/> manner may you draw the other <hi>parallels,</hi> but for more eaſe we may take halfe of the differences of the Num<g ref="char:EOLhyphen"/>bers in the Colume <hi>C</hi> and the Colume <hi>E.</hi> and ſo may we have the Colume <hi>F.</hi> and then wi h greater expedition wee may protract the Centers of theſe <hi>parallels,</hi> from <hi>Z.</hi> for if 5269. which is at the bottome of the Colume <hi>F.</hi> (&amp; betweene the former two Numbers) be taken from the ſcale, and protracted from <hi>Z.</hi> it will reach unto 1. the Cen<g ref="char:EOLhyphen"/>ter as before, and ſo any Number in the Colume <hi>F.</hi> is the diſtance of the <hi>Centers</hi> from <hi>Z.</hi> of his oppoſite Number in the Colume <hi>B.</hi> or <hi>A.</hi> by which Columes <hi>C.</hi> and <hi>F.</hi> you may deſcribe all the <hi>parallels,</hi> betweene the <hi>Tropicks</hi> from degree to degree.</p>
               <p>But for more exactneſſe it were conveni<g ref="char:EOLhyphen"/>ent
<table>
                     <row>
                        <cell role="label">
                           <hi>R.</hi>
                        </cell>
                        <cell role="label">
                           <hi>T.</hi>
                        </cell>
                     </row>
                     <row>
                        <cell>1</cell>
                        <cell>1.36</cell>
                     </row>
                     <row>
                        <cell>2</cell>
                        <cell>3.13</cell>
                     </row>
                     <row>
                        <cell>3</cell>
                        <cell>4.44</cell>
                     </row>
                     <row>
                        <cell>4</cell>
                        <cell>6.26</cell>
                     </row>
                     <row>
                        <cell>5</cell>
                        <cell>8.03</cell>
                     </row>
                     <row>
                        <cell>6</cell>
                        <cell>9.40</cell>
                     </row>
                     <row>
                        <cell>7</cell>
                        <cell>11.17</cell>
                     </row>
                     <row>
                        <cell>8</cell>
                        <cell>12.55</cell>
                     </row>
                     <row>
                        <cell>9</cell>
                        <cell>14.33</cell>
                     </row>
                     <row>
                        <cell>10</cell>
                        <cell>16.12</cell>
                     </row>
                     <row>
                        <cell>11</cell>
                        <cell>17.51</cell>
                     </row>
                     <row>
                        <cell>12</cell>
                        <cell>19.31</cell>
                     </row>
                     <row>
                        <cell>13</cell>
                        <cell>21.11</cell>
                     </row>
                     <row>
                        <cell>14</cell>
                        <cell>22.52</cell>
                     </row>
                     <row>
                        <cell>15</cell>
                        <cell>24.34</cell>
                     </row>
                     <row>
                        <cell>16</cell>
                        <cell>26.07</cell>
                     </row>
                     <row>
                        <cell>17</cell>
                        <cell>28.01</cell>
                     </row>
                     <row>
                        <cell>18</cell>
                        <cell>29.46</cell>
                     </row>
                     <row>
                        <cell>19</cell>
                        <cell>31.32</cell>
                     </row>
                     <row>
                        <cell>20</cell>
                        <cell>33.20</cell>
                     </row>
                     <row>
                        <cell>21</cell>
                        <cell>35.09</cell>
                     </row>
                     <row>
                        <cell>22</cell>
                        <cell>37.00</cell>
                     </row>
                     <row>
                        <cell>23</cell>
                        <cell>38.53</cell>
                     </row>
                     <row>
                        <cell>23.30</cell>
                        <cell>39.50</cell>
                     </row>
                  </table> to ſhew in what points of the <hi>Arke</hi> δ. <hi>E.</hi> π. the parallels of <hi>declination</hi> interſect it, if truly deſcribed, and may be found by Page 57. of the <hi>Appendix</hi> upon the <hi>Ring,</hi> where is ſhewne to finde what Amplitude belongeth to the Sunnes declination, for any <hi>Latitude</hi> by moving the <hi>Sine</hi> of the Complement of the <hi>Latitude,</hi> uiz. this of <hi>London,</hi> 38. gr. 30. m. unto the <hi>ſine</hi> of 90. in the fixed, ſo every degree of <hi>declination</hi> in the moveable, ſhall point out the <hi>Amplitude</hi> in the fixed by which is had the Numbers of the Colume <hi>T.</hi> the ſuns <hi>Amplitude</hi> belonging to the <hi>declina<g ref="char:EOLhyphen"/>tion</hi> of the Colume <hi>R.</hi> Now if the <hi>Quadrants E S. EN. WS. W N.</hi> be divided from <hi>E</hi> &amp; <hi>W.</hi> a ruler layed upon the Center <hi>Z.</hi> and to paſſe by the degrees in the ſeverall <hi>Quadrants,</hi> anſwerable to the degrees of the Colume <hi>T.</hi> the <hi>Arkes</hi> δ π. and ζ ς. ſhall be noted in ſuch points as the parallels of the <hi>declination</hi> ſhould interſect.</p>
               <p>
                  <hi>Secondly,</hi> move the <hi>Tangent</hi> of the <hi>Lati<g ref="char:EOLhyphen"/>tude</hi> in the moveable viz. 51 gr. 30. m. unto the former part of the <hi>Radius</hi> or ſcale. viz. 10000. in the <hi>Circle of Numbers</hi> in the fixed,
<pb n="10" facs="tcp:10089:17"/> ſo the Tangent of 45. gr. in the movable ſhall point out 125717. in the Circle of Numbers in the fixed, which ta<g ref="char:EOLhyphen"/>ken from the ſcale <hi>A.</hi> and protracted from <hi>Z.</hi> to <hi>T.</hi> it ſhall be the <hi>Center</hi> of the houre of 6. upon <hi>T.</hi> erect a perpendi<g ref="char:EOLhyphen"/>cular 2. <hi>T.</hi> 10. ſerving for the Centers of the other houres: then move the Tangent of 45: gr. to the parts of the ſcale, viz. 10000 in the <hi>Circle of Numbers,</hi> and conſider the di<g ref="char:EOLhyphen"/>ſtance betweene the <hi>Zenith</hi> and the Pole, viz. 38. gr. 30. m. the Tangent of halfe of it in the movable doth point out in the Circle of <hi>Numbers</hi> 34921. which taken alſo fro<g ref="char:cmbAbbrStroke">̄</g> the diagonall ſcale, and protracted from <hi>Z.</hi> will reach to <hi>P.</hi> the Pole, through which all the houres muſt be drawne, and the <hi>Centers</hi> of which houres in the line 2.10. from <hi>T.</hi> may be had thus: which two numbers 125717. &amp; 34921. I place over the Columes <hi>H.</hi> and <hi>I.</hi>
               </p>
               <p>
                  <note place="margin">Of the cal<g ref="char:EOLhyphen"/>culating of the diſtan<g ref="char:EOLhyphen"/>ces of the Centers of the houres</note>
                  <hi>According</hi> to the diſtance <hi>P.T.</hi> make a ſcale <hi>B.</hi> (or rather a <hi>diagonall ſcale</hi>) to containe 10000. parts, then move the <hi>Tangent</hi> of 45. gr. to the parts of this ſcale in the <hi>Circle of Numbers,</hi> viz. 10000. ſo every degree in the mouable a<g ref="char:EOLhyphen"/>mongſt the <hi>Tangents</hi> unto 45. gr. doth point out in the <hi>Cir<g ref="char:EOLhyphen"/>cle of Numbers,</hi> the diſtances of the Centers of thoſe de<g ref="char:EOLhyphen"/>grees from <hi>T.</hi> in the line 2. 10. by which the Colume <hi>H.</hi> is made, then moving the moveable ſoftly along as the <hi>Tan<g ref="char:EOLhyphen"/>gent</hi> of any degree in the movable above 45. gr. paſſeth by the parts of the ſcale <hi>B.</hi> viz. 10000. in the <hi>Circle of Num<g ref="char:EOLhyphen"/>bers,</hi> ſo the Tangent of 45. gr. in the moveable, paſſeth by the diſtance of the Centers of thoſe degrees from <hi>T.</hi> in the <hi>Circle of Numbers</hi> in the fixed, above 10000. by which is made up the reſt of the Colume <hi>H.</hi> viz. <hi>I.</hi> by helpe of which Colume <hi>H.</hi> and <hi>I.</hi> the houres may be thus drawne.</p>
               <p>
                  <note place="margin">Of the de<g ref="char:EOLhyphen"/>ſcribing of the houres</note>
                  <hi>Marke,</hi> what Numbers are againſt the houres in the Colume <hi>H</hi> and <hi>I.</hi> for if thoſe Numbers be taken from the ſcale <hi>B.</hi> and protracted from <hi>T.</hi> in the line 2.10. they ſhall be the Centers of thoſe houres: ſo in the Colume <hi>H.</hi> againſt the houre of 7. or 5. is 2679, which take from the ſcale <hi>B.</hi> and protract it from <hi>T.</hi> to 7. and from <hi>T.</hi> to 5. in the line 2. 10. then placing one foote of the <hi>Compaſſes</hi> in 7. and ex<g ref="char:EOLhyphen"/>tending the other foote to <hi>P.</hi> deſcribe the houre of 7. and one foote of the <hi>Compaſſes</hi> at the ſame extent being pla<g ref="char:EOLhyphen"/>ced
<pb n="11" facs="tcp:10089:17"/> in 5. ſhall alſo deſcribe the houre of 5. In like manner may be protracted from <hi>T.</hi> out of the Colume <hi>H. I.</hi> the <hi>Cen<g ref="char:EOLhyphen"/>ters</hi> of the other houres with their intermediats, and ſo al<g ref="char:EOLhyphen"/>ſo deſcribed.</p>
               <p>
                  <hi>But</hi> here note, that it were convenient to finde the In<g ref="char:EOLhyphen"/>terſections of the <hi>houre lines</hi> (and their intermediate de<g ref="char:EOLhyphen"/>grees) with the <hi>Horizon</hi> as before was delivered of the in<g ref="char:EOLhyphen"/>terſections of the parallels of <hi>Declination</hi> with the <hi>Hori<g ref="char:EOLhyphen"/>zon,</hi> and it may be drawne from my <hi>Ring</hi> thus.<note place="margin">Of the fin<g ref="char:EOLhyphen"/>ding the interſecti<g ref="char:EOLhyphen"/>on of the houre with the Hori<g ref="char:EOLhyphen"/>zon.</note> Move the Tangent of 45. gr. in the
<table>
                     <row>
                        <cell role="label">
                           <hi>A</hi>
                        </cell>
                        <cell role="label">
                           <hi>B</hi>
                        </cell>
                        <cell role="label">
                           <hi>A</hi>
                        </cell>
                        <cell role="label">
                           <hi>B</hi>
                        </cell>
                        <cell role="label">
                           <hi>A</hi>
                        </cell>
                        <cell role="label">
                           <hi>B</hi>
                        </cell>
                     </row>
                     <row>
                        <cell>1</cell>
                        <cell>1.16</cell>
                        <cell>12</cell>
                        <cell>15.12</cell>
                        <cell>23</cell>
                        <cell>28.29</cell>
                     </row>
                     <row>
                        <cell>2</cell>
                        <cell>2.33</cell>
                        <cell>13</cell>
                        <cell>16.26</cell>
                        <cell>24</cell>
                        <cell>29.38</cell>
                     </row>
                     <row>
                        <cell>3</cell>
                        <cell>3.50</cell>
                        <cell>14</cell>
                        <cell>17.40</cell>
                        <cell>25</cell>
                        <cell>30.48</cell>
                     </row>
                     <row>
                        <cell>4</cell>
                        <cell>5.16</cell>
                        <cell>15</cell>
                        <cell>18.54</cell>
                        <cell>26</cell>
                        <cell>31.56</cell>
                     </row>
                     <row>
                        <cell>5</cell>
                        <cell>6.23</cell>
                        <cell>16</cell>
                        <cell>20.7</cell>
                        <cell>27</cell>
                        <cell>33.4</cell>
                     </row>
                     <row>
                        <cell>6</cell>
                        <cell>7.39</cell>
                        <cell>17</cell>
                        <cell>21.20</cell>
                        <cell>28</cell>
                        <cell>34.12</cell>
                     </row>
                     <row>
                        <cell>7</cell>
                        <cell>8.55</cell>
                        <cell>18</cell>
                        <cell>22.33</cell>
                        <cell>29</cell>
                        <cell>35.19</cell>
                     </row>
                     <row>
                        <cell>8</cell>
                        <cell>10.11</cell>
                        <cell>19</cell>
                        <cell>23.45</cell>
                        <cell>30</cell>
                        <cell>36.25</cell>
                     </row>
                     <row>
                        <cell>19</cell>
                        <cell>11.27</cell>
                        <cell>20</cell>
                        <cell>24.57</cell>
                        <cell>31</cell>
                        <cell>37.21</cell>
                     </row>
                     <row>
                        <cell>10</cell>
                        <cell>12.42</cell>
                        <cell>21</cell>
                        <cell>26.08</cell>
                        <cell>32</cell>
                        <cell>38.36</cell>
                     </row>
                     <row>
                        <cell>11</cell>
                        <cell>13.57</cell>
                        <cell>22</cell>
                        <cell>27.18</cell>
                        <cell>33</cell>
                        <cell>39.41</cell>
                     </row>
                  </table> moveable unto the <hi>ſine</hi> of the <hi>Latitude,</hi> viz. 51. gr. 30. m. in the fixed, then right againſt the Tangent of any degree from the houre of 6. in the fixed, is the Tan<g ref="char:EOLhyphen"/>gent of the degrees of the interſection of the houres, and the intermediate de<g ref="char:EOLhyphen"/>grees with the <hi>Horizon</hi> in the moveable: from which direction is this Table drawne, and is onely for theſe degrees which interſect the <hi>Horizon</hi> in the <hi>Calender,</hi> but it might have beene extended further. The Application of which is thus: Account in the <hi>Limbe</hi> of the <hi>Inſtrument</hi> fro<g ref="char:cmbAbbrStroke">̄</g> 
                  <hi>E.</hi> (the point of <hi>Eaſt,</hi>) any degree in the <hi>Colume B.</hi> and lay a Ruler thereto, and to the <hi>Center Z.</hi> ſo the interſection thereof in the <hi>Horizon</hi> ſhall ſhew the in<g ref="char:EOLhyphen"/>terſection that the <hi>houre line,</hi> or degree oppoſite thereunto in the <hi>Colume A.</hi> maketh with the <hi>Horizon.</hi> In like man<g ref="char:EOLhyphen"/>ner I might have delivered the Tables of the interſection of the houre lines with the parallels of <hi>declination,</hi> which would ſerve of great uſe in large <hi>Inſtruments,</hi> to deſcribe theſe degrees, which are neere the houre of 12.</p>
               <p>Now to deſcribe the <hi>Ecliptick,</hi> conſider as before the hight of the <hi>Tropicks</hi> above the <hi>Horizon,</hi> in the <hi>Latitude</hi> given, viz. 51. gr, 30. m. ſo ♑ will be 15. above the <hi>Horizon,</hi> and ♋ will be 62. gr. high. Then move the <hi>Tangent</hi> of 45.
<pb n="12" facs="tcp:10089:18"/> unto the parts of the ſcale <hi>A.</hi> in the <hi>Circle of Numbers</hi> in the fixed. viz. 10000. ſo right againſt the Tangent of 15. gr. in the moveable is 2679. the diſtance of the Center of the Southerne ſemicircle of the <hi>Eclipticke</hi> from <hi>Z.</hi> which I place in the Colume over <hi>M.</hi> and againſt ♑. then move the moveable ſoftly along untill the Tangent of 62 gr. bee right againſt 10000.<note place="margin">To de<g ref="char:EOLhyphen"/>ſcribe the Eclipticke</note> in the <hi>Circle of Numbers,</hi> ſo the Tan<g ref="char:EOLhyphen"/>gent of 45. gr. in the moveable, ſhal point out 18807. on the <hi>Circle of Numbers</hi> in the fixed: The diſtance of the Cen<g ref="char:EOLhyphen"/>ter of the Northerne ſemicircle of the <hi>Eclipticke,</hi> from <hi>Z.</hi> which I place in the Colume over <hi>P.</hi> againſt ♋. if theſe numbers be taken from the ſcale <hi>A.</hi> and protracted from <hi>Z.</hi> they will reach from <hi>Z.</hi> to ♑. and from <hi>Z.</hi> to ♋, and ſo placing one foote of the <hi>Compaſſes</hi> in ♑. neere the <hi>Pole,</hi> and extending the other foote to ♑. neere <hi>S.</hi> you may de<g ref="char:EOLhyphen"/>ſcribe the Southerne ſemicircle of the <hi>Eclipticke E,</hi> ♑. <hi>W.</hi> and placing one foote of the <hi>Compaſſes</hi> in ♋. below the Pole, and extending the other foote to ♋. above the <hi>Pole:</hi> you may deſcribe the Northerne part of the <hi>Eclipticke E,</hi> ♋, <hi>W.</hi> and thoſe ſemicircles of the Eclipticke may be di<g ref="char:EOLhyphen"/>vided as followeth.</p>
               <p>
                  <hi>Move</hi> the Tangent of 45. unto the <hi>Sine</hi> of 66. and 30. ſo right againſt the Tangent of the degrees of the Sunnes Longitude in the <hi>Eclipticke</hi> in the moveable,<note place="margin">How to make the Table to divide the Eclipticke</note> are the Tan<g ref="char:EOLhyphen"/>gents of the degrees of the Sunnes <hi>right aſcention</hi> in the fixed, or they may be had by reſolving of a <hi>Triangle,</hi> in which there will be 9<gap reason="illegible" resp="#PDCC" extent="1 letter">
                     <desc>•</desc>
                  </gap>. ſeverall operations, but by this <hi>Ring</hi> they are given at one rectification, and onely by a glance of the <hi>eye:</hi> for proportionals either in <hi>Sines</hi> or <hi>Tan<g ref="char:EOLhyphen"/>gents</hi> are had by the <hi>Ring,</hi> with the ſame expedition that <hi>Numbers</hi> are had, As by the uſe of the <hi>Circles</hi> of <hi>Sines</hi> and <hi>Tangents</hi> upon the projection of this <hi>Ring,</hi> in diverſe par<g ref="char:EOLhyphen"/>ticulars is declared in the <hi>Appendix</hi> upon the uſe of the <hi>Ring;</hi> and ſo according to the former Conſtruction is made the Columes <hi>L.</hi> and <hi>O.</hi> for 45. being brought to 66. gr. 30. m. as before, right againſt 10. gr. in the moveable, is 9. gr. 11. m. in the fixed, againſt 20. gr. in the moveable, is 18. gr. 28. m. in the fixed, and ſo of the reſt. Then move the Tangent of 45. gr. to the parts of the ſcale <hi>B.</hi> viz.
<pb n="13" facs="tcp:10089:18"/> 10000. in the Circle of Numbers, ſo right againſt the Tangent of the Arkes in the Colume <hi>L.</hi> in the moveable are the diſtances of the Centers of thoſe Arks, from <hi>T.</hi> in the <hi>Circle of Numbers</hi> in the fixed, and ſo is made the Colume <hi>M.</hi> &amp; if you move the moveable ſoftly along as the Tangent of any degree in the Colume <hi>O.</hi> paſſeth by 10000 the parts of the ſcale <hi>B.</hi> ſo the Tangent of 45. in the move<g ref="char:EOLhyphen"/>able, paſſeth by the diſtances of the Centers of thoſe de<g ref="char:EOLhyphen"/>grees from <hi>T.</hi> in the Circle of Numbers in the fixed, by which is made the Colume <hi>P.</hi> or they may bee had from the Table of naturall Tangents.</p>
               <p>
                  <hi>Then by the ſcale B.</hi> protract the <hi>Numbers,</hi>
                  <note place="margin">To divide the Eclip<g ref="char:EOLhyphen"/>ticke.</note> out of the Co<g ref="char:EOLhyphen"/>lume <hi>M.</hi> and <hi>P.</hi> from <hi>T.</hi> in the line 2. 10. for they ſhall bee the <hi>Centers</hi> of thoſe degrees of the <hi>Eclipticke,</hi> which are oppoſite unto them, viz. in the Columes <hi>K.</hi> and <hi>N.</hi> ſo if I would interſect the <hi>Eclipticke,</hi> in the beginning of ♉. ♓. ♍. or ♏. each being diſtant from ♈. 30. gr. which I ſeeke in the Colume. <hi>K.</hi> and finde right againſt it in the Colume <hi>M.</hi> 5294. which I take from the ſcale B. and protract it from <hi>T.</hi> to 30. in the line 2. 10. Now placing one foote of the <hi>Compaſſes</hi> in 30. next 10. and extending the other foote to <hi>P.</hi> the <hi>Eclipticke</hi> may be interſected in the points of ♉. and ♓. and placed in 30. towards 2. the ſame extent will Interſect the <hi>Eclipticke</hi> in ♍. and ♏. In like manner may the Centers of the reſt of the degrees of the <hi>Eclipticke</hi> be protracted in the line, 2. 10. from <hi>T.</hi> out of the Columes <hi>M.</hi> and <hi>P.</hi> and ſo all the <hi>Eclipticke</hi> divided from degree, to degree: but this may be otherwiſe done.</p>
               <p>Beſides that which is delivered touching the drawing of the <hi>Parallels, Eclipticke,</hi> and <hi>Houre lines,</hi> there remaines yet how to put on the <hi>Callender,</hi> to graduate the <hi>Index,</hi> and to draw, and divide the line of <hi>Shadowes.</hi>
               </p>
               <p>This may be eaſily done from the Table <hi>R.</hi> Calculated, and accommodated to that purpoſe for the yeare 1640, and may ſufficiently ſerve for many yeares after, without any ſenſible error.</p>
               <p>Having divided the <hi>Quadrants,</hi> 
                  <label type="milestone">
                     <seg type="milestoneunit">Conſtru∣ction. </seg>
                  </label> 
                  <hi>E.S.</hi> and <hi>E.N.</hi> (as before into the uſuall degrees of a <hi>Quadrant,</hi>) lay a ruler upon
<pb n="14" facs="tcp:10089:19"/> the Center <hi>Z.</hi> and account the degrees from the point <hi>E.</hi> in the <hi>Quadrant</hi> towards <hi>N.</hi> and <hi>S.</hi> out of the Table <hi>R.</hi> according to the ſeverall Columes of the Table <hi>R.</hi> and In<g ref="char:EOLhyphen"/>terſect the <hi>Quadrants,</hi>
                  <note place="margin">How to in<g ref="char:EOLhyphen"/>ſcribe the Callender</note> with ſmall ſhort lines, ſo ſhall the Arke of the <hi>Horizon</hi> of the <hi>Inſtrument</hi> from <hi>E.</hi> be divided into the uſuall dayes of the <hi>Month,</hi> which is the <hi>Callender</hi> and the beginning of theſe diviſions, may be at the 10. of <hi>March,</hi> and ſo going on to the 11. of <hi>Iune,</hi> and then againe to begin from the 10. of <hi>March,</hi> and go on unto the 10. of <hi>December,</hi> and theſe dayes may bee noted upon the inſide of the <hi>Horizontall</hi> Arke with ſhort lines from <hi>E.</hi> as before, and at every <hi>Month</hi> may bee placed a repreſentative letter for that <hi>Month,</hi> and every 10. and 5. day of every <hi>Month,</hi> may bee noted with a ſmall ſtroke ſomewhat longer then the reſt, to helpe the memory the readier to number. In like manner may the reſt of the dayes of the <hi>Calender</hi> be interſected in the out ſide of the <hi>Horizontall</hi> Arke, to<g ref="char:EOLhyphen"/>wards the <hi>Limbe,</hi> beginning at the 13. of <hi>September,</hi> and ſo going on to the 11. of <hi>Iune,</hi> then againe from the 13. of <hi>September,</hi> and going on unto the 10. of <hi>December,</hi> and theſe <hi>Months</hi> may bee alſo noted with ſignificant letters, appropriate to each <hi>Month,</hi> and each 10. and 15. day of the <hi>Month,</hi> may be alſo denoted as before, with a ſtroke ſome<g ref="char:EOLhyphen"/>what longer than the reſt, according to the Scheme againſt Page the 1.</p>
            </div>
            <div type="part">
               <head>How to graduate the Index for the Inſtrument.</head>
               <p>Let the <hi>Index</hi> be equall to the ſemidiameter, <hi>Z. E.</hi> and then may it bee divided out of the <hi>Table Q.</hi> by the helpe of the ſcale <hi>A.</hi> beginning at the Center: the <hi>Index</hi> being diuided, and placed on the Center of the <hi>Inſtrument</hi> at <hi>Z.</hi> it ſhall helpe to put on, and divide the line of <hi>ſhadowes.</hi> as followeth.</p>
               <p>Lay the edge of the <hi>Index</hi> to <hi>A.</hi> in the <hi>Limbe</hi> which is neere the 10. of <hi>December,</hi> and move it to any degree in
<pb n="15" facs="tcp:10089:19"/> the <hi>Table S.</hi> and account the like degree in the <hi>Index,</hi> and then make a marke upon the plaine of the <hi>Inſtrument</hi> where that degree toucheth, and ſo goe on from point to point, untill the whole line bee deſcribed and divided, ac<g ref="char:EOLhyphen"/>cording to the <hi>Table S.</hi> This line might bee placed be<g ref="char:EOLhyphen"/>tweene the <hi>Calender</hi> and the <hi>Limbe,</hi> or in a <hi>Quadrant,</hi> &amp;c. But I have cauſed it to bee deſcribed as is ſeene upon the <hi>Scheme</hi> againſt Page the 1. for expedition and conveni<g ref="char:EOLhyphen"/>ency. ☞</p>
               <figure>
                  <figDesc>mathematical diagram</figDesc>
               </figure>
               <p>Let <hi>A. B. C. D.</hi> be a plaine, divide the length <hi>A. B.</hi> within halfe an Inch of the higher end, and an Inch of the lower end, in to 3. equall parts which ſuppoſe the line <hi>M.N.</hi> then di<g ref="char:EOLhyphen"/>vide each part into halfe ſo the line <hi>M. N.</hi> ſhall bee di<g ref="char:EOLhyphen"/>vided into 6. equall parts, the middle of which will bee at <hi>Z.</hi> Then take 4. of theſe parts for <hi>Radius,</hi> and on <hi>Z.</hi> de<g ref="char:EOLhyphen"/>ſcribe the obſcure <hi>Arke, A. E. B.</hi> and upon <hi>Z.</hi> erect a per<g ref="char:EOLhyphen"/>pendicular to the line <hi>M. N.</hi> to cut the Arke <hi>A. B.</hi> in <hi>E.</hi> now from <hi>E.</hi> to <hi>A.</hi> protract 40. gr. and
<pb n="16" facs="tcp:10089:20"/> from <hi>E.</hi> to <hi>B.</hi> protract 50. gr. ſo the Angle <hi>E. Z. M.</hi> ſhall be 90. and alſo <hi>A.Z.B.</hi> ſhall be 90. Now having made a ſcale of <hi>Z.E.</hi> like to the ſcale <hi>A.</hi> according to the former directions) then out of the Colume <hi>C.</hi> and by helpe of the ſaid ſcale <hi>A.</hi> from <hi>Z.</hi> you may protract <hi>Z.</hi> ♋. 2493. <hi>Z.Q.</hi> 4823. and <hi>Z.</hi> ♑ 7673. and from the Colume <hi>F.</hi> y u may protract the diſtances of the <hi>Centers</hi> of thoſe inter<g ref="char:EOLhyphen"/>ſections from <hi>Z.</hi> viz. Z. 1.5269. <hi>Z.</hi> 2.7949. and Z. 3.16217. and ſo placing the Compaſſe in theſe <hi>Centers,</hi> you may deſcribe the <hi>Equator,</hi> and both <hi>Tropicks.</hi> But if <hi>Z. M,</hi> and Z. <hi>N.</hi> be divided according to the ſcale <hi>A.</hi> then from <hi>Z.</hi> you may account the interſections of the parallels, and diſtan<g ref="char:EOLhyphen"/>ces of the Centers, and ſo deſcribe the parallels with grea<g ref="char:EOLhyphen"/>ter expedition, and ſo ſhall you have the <hi>Scheme</hi> or <hi>Tra<g ref="char:EOLhyphen"/>peziall</hi> forme of the <hi>Inſtrument, B. A.</hi> ♑. ♋. and may bee finiſhed according to that againſt Page the 1. by the <hi>Ta<g ref="char:EOLhyphen"/>bles</hi> and directions here calculated, and delivered to that end.</p>
               <p>Now to augment the <hi>Inſtrument</hi> to any proportion aſ<g ref="char:EOLhyphen"/>ſigned, as if betweene the <hi>Tropickes</hi> were ſuppoſed to bee 10. <hi>Inches,</hi> the <hi>Radius</hi> might be found out, or if the <hi>Radius</hi> were 4. foote, (which is according to mine owne <hi>Inſtru<g ref="char:EOLhyphen"/>ment:</hi>) what diſtance might there bee betweene the <hi>Tro<g ref="char:EOLhyphen"/>pickes:</hi> the proportion would be as 516. to 1000. ſo the breadth to the ſcale, or as 1000. to 516. ſo the ſcale to the breadth: therefore by the <hi>Ring,</hi> bring 516. in the move<g ref="char:EOLhyphen"/>able, to 1000. in the fixed, ſo right againſt any <hi>Radius</hi> in the fixed, is the diſtance betweene the <hi>Tropickes</hi> in the <hi>Moveable,</hi> or againſt the diſtance aſſigned for the <hi>Tro<g ref="char:EOLhyphen"/>pickes</hi> in the <hi>Moveable,</hi> is the meaſure of the <hi>Radius</hi> or <hi>Scale,</hi> in the <hi>fixed:</hi> So if ♑. ♋. be allotted to be 10. <hi>Inches,</hi> for the diſtance betweene the <hi>Tropickes,</hi> the <hi>Scale,</hi> or <hi>Ra<g ref="char:EOLhyphen"/>dius,</hi> of the <hi>Inſtrument</hi> ſhould be 19 4/10. fere: but if the ſcale or <hi>Radius</hi> were 4. foote, or 48. <hi>Inches,</hi> then the di<g ref="char:EOLhyphen"/>ſtance betweene the <hi>Tropickes</hi> of ♑, and ♋. will be neere 24 77/100. <hi>Inches.</hi> Thus for the making of the <hi>Inſtrument,</hi> the deſcription of which followeth.</p>
               <pb facs="tcp:10089:20"/>
               <figure>
                  <figDesc>mathematical diagram</figDesc>
               </figure>
               <pb facs="tcp:10089:21"/>
            </div>
            <div type="part">
               <pb n="17" facs="tcp:10089:21"/>
               <head>The Deſcription of the Hori<g ref="char:EOLhyphen"/>zontall Quadrant.</head>
               <p>THe forme of this <hi>Inſtrument</hi> is like a mixt <hi>Trapezia,</hi> as appeares againſt Page. 1. where of two ſides are right, and the other two ſides are <hi>Circular,</hi> which falleth out to bee ſo from the nature of the <hi>Projection,</hi> and that part which I have thought moſt convenient for uſe, and is fully ſufficient for that which I have deliuered upon it; and may be made of any plaine <hi>Materiall,</hi> but fitteſt in <hi>Braſſe,</hi> or <hi>Silver:</hi> the ſeverall parts of which <hi>Inſtrument</hi> are five, viz. the <hi>Backe,</hi> the <hi>Face,</hi> the <hi>Sights,</hi> the <hi>Index,</hi> and the di<g ref="char:EOLhyphen"/>viſions, and lines projected on the <hi>Face.</hi>
               </p>
               <p>
                  <hi>Firſt, the Backe of the Inſtrument,</hi> is a part of <hi>Gemma <milestone type="tcpmilestone" unit="unspecified" n="1"/> Friſius</hi> projection, whoſe particular deſcription and admi<g ref="char:EOLhyphen"/>rable uſe I intend here after as God ſhall give life and A<g ref="char:EOLhyphen"/>bility to make manifeſt.</p>
               <p>
                  <hi>Secondly, the face of the Inſtrument,</hi> is that upon which <milestone type="tcpmilestone" unit="unspecified" n="2"/> the <hi>Index,</hi> and ſights are placed on.</p>
               <p>
                  <hi>Thirdly, the Sights are</hi> the ſmall peeces of <hi>Braſſe</hi> in <milestone type="tcpmilestone" unit="unspecified" n="3"/> which there is in each a little hole to looke through, or the ſunne beames to paſſe through, and are faſtned upon the <hi>Face</hi> of the <hi>Inſtrument;</hi> one of which Sights is neere the <hi>Center</hi> of the <hi>Inſtrument,</hi> and the other is neere the <hi>Circumference</hi> thereof.</p>
               <p>
                  <hi>Fourthly, the Index,</hi> is the movable peece of braſſe, <milestone type="tcpmilestone" unit="unspecified" n="4"/> faſtned at the <hi>Center,</hi> upon which alſo two other ſights may be placed, the edge of this <hi>Index</hi> is divided and noted thus. 10. 20. 30. 40. 50. 60. 70. 80. 90. which are called the degrees of the <hi>Index,</hi> and there is adjoyned unto it three ſmall plates to be rectified as occaſion requires, one of which is called the <hi>Axis,</hi> and the other two are perpendicu<g ref="char:EOLunhyphen"/>lars.</p>
               <pb n="18" facs="tcp:10089:22"/>
               <p> 
                  <milestone type="tcpmilestone" unit="unspecified" n="5"/> 
                  <hi>Fiftly,</hi> the lines deſcribed on the <hi>Face</hi> of the <hi>Qua<g ref="char:EOLhyphen"/>drant</hi> are ſixfold.</p>
               <p>Viz.
<list>
                     <item>
                        <hi>The Limbe and its Parallels.</hi>
                     </item>
                     <item>
                        <hi>The Kalender and its diviſions.</hi>
                     </item>
                     <item>
                        <hi>The Aequator and its Parallels.</hi>
                     </item>
                     <item>
                        <hi>The Eclipticke and its diviſions.</hi>
                     </item>
                     <item>
                        <hi>The Houre lines and their intermediates.</hi>
                     </item>
                     <item>
                        <hi>The line of Shadowes and its diviſions.</hi>
                     </item>
                  </list>
               </p>
               <p> 
                  <milestone type="tcpmilestone" unit="unspecified" n="1"/> 
                  <hi>Firſt, the Limbe</hi> is the outmoſt <hi>Circle,</hi> which is divided into 140. gr. and noted at every 10. degree thus, 10. 20. 30. 40. 50. 60. 70. 80. 90. and each of theſe degrees is divided into parts according to the Capacity of a degree in the <hi>Inſtrument.</hi>
               </p>
               <p> 
                  <milestone type="tcpmilestone" unit="unspecified" n="2"/> 
                  <hi>Secondly,</hi> the next parallell line to the Limbe is the <hi>Ho<g ref="char:EOLhyphen"/>rizon</hi> or <hi>Kalender,</hi> which is noted with letters thus, <hi>I.A. S.O. N.D. I.F. M.A. M.I.</hi> of which <hi>I.</hi> in the firſt place ſtands for <hi>Iuly, A.</hi> for <hi>Auguſt, S.</hi> for <hi>September, O.</hi> for <hi>Octo<g ref="char:EOLhyphen"/>ber.</hi> &amp;c. then againe on the inſide, <hi>I.</hi> ſtands for <hi>Ianuary, F.</hi> for <hi>February,</hi> &amp;c. each letter repreſenting its <hi>Month,</hi> and each of thoſe <hi>Months</hi> is divided into dayes by ſmall ſhort lines, whereof the 10. and 15. day of every <hi>Month</hi> is ſignified by <hi>Numbers,</hi> or elſe by a line ſomewhat longer then any of the others, to helpe the <hi>memory</hi> the readier to <hi>Number,</hi> and for more promptneſſe of finding the day of the <hi>Month,</hi> in the <hi>Kalender</hi> as occaſion requireth.</p>
               <p> 
                  <milestone type="tcpmilestone" unit="unspecified" n="3"/> 
                  <hi>Thirdly, The Equater</hi> is that line that meeteth with the tenth of <hi>March,</hi> and the thirteenth of <hi>September</hi> in the <hi>Kalender,</hi> and is divided into degrees, and numbred thus, 10. 20. 30. 40. 50. 60. 70. 80. 90. and the parallels to the <hi>Equator</hi> are theſe lines which are on each ſide of it, every 5. degree of which being noted thus, 5. 10. 15. 20. the outmoſt of thoſe <hi>Parallels</hi> on each ſide of the <hi>Equator</hi> are the two <hi>Tropickes</hi> that which is neareſt the <hi>Center,</hi> is cal<g ref="char:EOLhyphen"/>led the <hi>Tropicke</hi> of ♋, and that which is fartheſt of, is called the <hi>Tropicke</hi> of ♑, thoſe two <hi>Tropicks,</hi> the <hi>Kalen<g ref="char:EOLhyphen"/>der,</hi> and the houre of 12. comprehend the whole <hi>Projecti<g ref="char:EOLhyphen"/>n:</hi> and here note farther that theſe parallels are called
<pb n="19" facs="tcp:10089:22"/> parallels of the day of the <hi>Moneth,</hi> as well as the parallels of the Sunnes <hi>Declination,</hi> according as they ſhall be vſed, and farther below the <hi>Tropicke</hi> of <hi>Cancer</hi> is a graduation of the common houres of a <hi>Horizontall</hi> Dyall: ſome vſe of whſch is ſhowne, by pro. 36.</p>
               <p>
                  <hi>Fourthly, the Eclipticke</hi> on the inſtrument is repreſen<g ref="char:EOLhyphen"/>ted <milestone type="tcpmilestone" unit="unspecified" n="4"/> by two quarters of the <hi>Eclipticke</hi> which croſſeth the former parallels, and meeteth with the <hi>Equator,</hi> in the <hi>Horizon</hi> or <hi>Kalender,</hi> in the former 10. of <hi>March,</hi> and 13. of <hi>September:</hi> that <hi>Quarter</hi> which is towards the <hi>Cen<g ref="char:EOLhyphen"/>ter</hi> of the <hi>inſtrument,</hi> ſerves for the <hi>Northerne ſemicircle</hi> of the <hi>Eclipticke,</hi> and that which is farther from the <hi>Cen<g ref="char:EOLhyphen"/>ter</hi> ſerves for the <hi>Southerne ſemicircle</hi> of the <hi>Eclipticke;</hi> &amp; each of theſe <hi>ſemicircles</hi> is divided into the <hi>Signes</hi> of the <hi>Zodiacke,</hi> &amp; charactered accordingly thus, ♈. ♉. ♊. ♋. ♌. ♍. ♎. ♏. ♐. ♑. ♒. ♓. Of which the firſt 6. <hi>Signes</hi> are called <hi>Northerne ſignes</hi> and are in the <hi>Northerne ſemicircle,</hi> &amp; the other 6. <hi>Southerne ſignes</hi> &amp; are in the <hi>Southerne Semicircle.</hi> And each of thoſe <hi>ſignes</hi> is divided into 30. gr. and if the <hi>Inſtrument</hi> be large, each of theſe degrees may be divided into 6. or 12. diviſions more, So every diviſion ſhall ac<g ref="char:EOLhyphen"/>cordingly containe 10. or 5. Minuts.</p>
               <p>
                  <hi>Fiftly, the houre lines</hi> are thoſe that croſſe the <hi>Aequator</hi> 
                  <milestone type="tcpmilestone" unit="unspecified" n="5"/> and his parallels, and are noted, or numbred in the <hi>Tro<g ref="char:EOLhyphen"/>picke</hi> of ♋ with <hi>numerall Characters</hi> thus IIII. V. VI. VII. VIII. IX. X. XI. XII. And are the forenoone houre notes: thoſe hourelines ſerve alſo for the after<g ref="char:EOLhyphen"/>noone houres, and are noted likewiſe with <hi>Arithmeticall</hi> figures, for the houres in the afternoone thus, 1. 2. 3. 4. 5. 6. 7. 8. each of thoſe houres is divided into 3. parts, each part being 20. minuts: and each of thoſe parts is ſubdi<g ref="char:EOLhyphen"/>vided againe into 5. parts, ſo that each part containeth 4. minutes, and ſo the whole houre is diveded into 15. parts or degrees, each part or degree being 4. minuts as afore, and ſo the whole houre ſhall containe 60. minuts or parts: and here note that theſe <hi>Houre circles</hi> with their intermediates are alſo called <hi>Meridians</hi> or degrees of meaſure, and are <hi>Numbred</hi> by tens in the <hi>Aequator,</hi> from the meeting of the <hi>Aequator</hi> with the <hi>Eclipticke,</hi> as before
<pb n="20" facs="tcp:10089:23"/> thus, 10. 20. 30. 40. 50. 60. 70. 80. 90.</p>
               <p>
                  <hi>Sixtly, the line of ſhadowes</hi> is that which makes a <hi>ſphae<g ref="char:EOLhyphen"/>ricall Equilaterall Triangle</hi> upon the plaine of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment,</hi> the baſis of which is the <hi>Horizon,</hi> or <hi>Kalender</hi> and one of whoſe legges is below the <hi>Tropicke</hi> of ♋ and the other croſſeth the <hi>Tropicke</hi> and parallels, and meeteth with the <hi>Kalender</hi> neere in the 10. of <hi>December:</hi> both of thoſe equall ſides are called the line of <hi>ſhadowes,</hi> and are divided alike into 10. vnequall diviſions, and each of thoſe diviſions againe is divided into 10. other diviſions, and againe each of them into other 10. (if the <hi>Inſtrument</hi> be large.) The firſt Capitall 10. diviſions are noted with <hi>Arithmeticall figures</hi> thus, 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. of which 1. is at the very meeting of the two lines, not farre from the <hi>Center,</hi> which ſignifieth <hi>Equall:</hi> the figure of 2. <hi>Double:</hi> the figure of 3. <hi>Triple,</hi> the figure of 4. <hi>Quadruple:</hi> the fi<g ref="char:EOLhyphen"/>gure of 5. <hi>Quintuple, &amp;c, Thus for the making, and deſcrip<g ref="char:EOLhyphen"/>tion of the Inſtrument, the uſe of it now followeth.</hi>
               </p>
            </div>
            <div type="uses">
               <pb n="21" facs="tcp:10089:23"/>
               <head>Of the Vſes of the Horizontall Quadrant, ſpeci<g ref="char:EOLhyphen"/>fied in the <hi>Index</hi> or <hi>Table,</hi> formerly delivered.</head>
               <p>OF which ſome have relation to the obſer<g ref="char:EOLhyphen"/>vation or appearance of the <hi>Sunne,</hi> others without obſervation, or ſight of the <hi>Sunne.</hi>
               </p>
               <div type="section">
                  <p>The Vſes of theſe which are knowne without ſeeing the <hi>Sunne,</hi> are 30. of the ſaid <hi>Index</hi> or <hi>Table,</hi> as followeth, viz. the 2. 9. 10. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 23. 24. 25. 26. 27. 28. 29. 30. 32. 33. 35. 37. 38. 39. 40. 41. and 42. of which 13. of them will be ſhowne onely by knowing the day of the <hi>Month,</hi> viz. the 18. 33. 21. 19. 25. 24. 35. 2. 38. 37. 20. 41. and 42. as followeth.</p>
                  <list>
                     <pb n="22" facs="tcp:10089:24"/>
                     <head>The day of the Month knowne to finde.</head>
                     <item>1. <hi>The houre of Sunne riſing, ſetting, and length of the day.</hi>
                     </item>
                     <item>2. <hi>The Sunnes difference of Aſcention.</hi>
                     </item>
                     <item>3. <hi>The Sunnes Declination.</hi>
                     </item>
                     <item>4. <hi>What dayes are alike in length, and what day the Sunne riſing in the one, ſhall be the Sunne ſetting in the other.</hi>
                     </item>
                     <item>5. <hi>The Sunnes place, or degree in the Eclip<g ref="char:EOLhyphen"/>ticke.</hi>
                     </item>
                     <item>6. <hi>The Sunnes right Aſcention, and ob<g ref="char:EOLhyphen"/>lique Aſcention.</hi>
                     </item>
                     <item>7. <hi>The houre, and Altitude of the Sunnes comming Eaſt, or Weſt.</hi>
                     </item>
                     <item>8. <hi>The diſtance of the Sunnes riſing, or ſet<g ref="char:EOLhyphen"/>ting, from the Eaſt, or Weſt.</hi>
                     </item>
                     <item>9. <hi>The height, or depreſsion of the Sunne in the Meridian here, or for any Latitude.</hi>
                     </item>
                     <item>10. <hi>The time of day breake, and end of twy<g ref="char:EOLhyphen"/>light.</hi>
                     </item>
                     <item>11. <hi>The inequality of time, betweene day breake, and Sunne riſing.</hi>
                     </item>
                     <item>12. <hi>The houre, and Altitude of the Sunnes comming upon any declining wall.</hi>
                     </item>
                     <item>13. <hi>At what houre, and Altitude, the Sun muſt have to be oppoſite or perpendicular, to a declining wall.</hi>
                     </item>
                  </list>
                  <div n="1" type="application">
                     <pb n="23" facs="tcp:10089:24"/>
                     <head>Firſt, to finde the time of Sunne <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>1</label> riſing, or ſetting, and length of the day, for any day of the yeere.</head>
                     <p>
                        <hi>Seeke</hi> the day of the <hi>Month</hi> in the <hi>Kalender,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>1</label> and the <hi>houre line</hi> that meeteth therewith, ſheweth the time of <hi>Sunne riſing, or ſetting.</hi>
                     </p>
                     <p>So if the day of the <hi>Month</hi> were the 13. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> of <hi>Octo<g ref="char:EOLhyphen"/>ber,</hi> the parallell that meeteth therewith is the <hi>houre,</hi> viz. 7. of the clocke, at which time the Sun riſeth: the ſame <hi>houre</hi> is noted alſo with 5. which is y<hi rend="sup">e</hi> time of <hi>Sun ſetting</hi> that day, this dou<g ref="char:EOLhyphen"/>bled makes 10. the length of the day required.</p>
                  </div>
                  <div n="2" type="application">
                     <head>Secondly, to finde the difference <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>2</label> of Aſcention, for any day of the yeere.</head>
                     <p>
                        <hi>Marke</hi> what <hi>Meridian</hi> meeteth with the day <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>2</label> of the <hi>Month</hi> in the <hi>Kalender:</hi> as ſuppoſe the day to be the former 13. of <hi>October,</hi> which is the <hi>houre line</hi> of 7. and 5. (as before) and account the Numbers of <hi>Meridians</hi> to the <hi>houre</hi> of 6. ſo have you 15. gr. or an <hi>houre,</hi> which is the difference of <hi>Aſcention</hi> for the 13. day of <hi>October</hi> re<g ref="char:EOLhyphen"/>quired.</p>
                  </div>
                  <div n="3" type="application">
                     <pb n="24" facs="tcp:10089:25"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>3</label> Thirdly, to finde the Sunnes de<g ref="char:EOLhyphen"/>clination for any day.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>3</label> 
                        <hi>Marke</hi> what parallell of <hi>Declination</hi> meeteth with the day of the <hi>Month</hi> in the <hi>Kalender,</hi> and account how many degrees it is from the <hi>Equi<g ref="char:EOLhyphen"/>noctiall,</hi> ſo have you the <hi>Sunnes Declination</hi> for that day.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> So if the day were the laſt of <hi>Auguſt,</hi> the pa<g ref="char:EOLhyphen"/>rallell that meeteth therewith is the 5<hi rend="sup">th</hi>. from the <hi>Equator,</hi> and ſomuch is the <hi>Sunnes declination,</hi> that day, viz. 5. gr. <hi>North declination.</hi>
                     </p>
                  </div>
                  <div n="4" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>4</label> Fourthly, to finde what dayes in the yeare are alike in length, and what day the Sunne riſing in the one, ſhall be the Sunne ſetting in the other.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>4</label> 
                        <hi>For the firſt,</hi> note that the dayes betweene the 10<hi rend="sup">th</hi> of <hi>December</hi> and the 11<hi rend="sup">th</hi>. of <hi>Iune,</hi> are dayes of Increaſe, and the reſt are dayes of De<g ref="char:EOLhyphen"/>creaſe. Now right againſt any day of decreaſe in the <hi>Kalender,</hi> is the day of increaſe, which dayes are equall one to the other. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> So the 19. day of <hi>May,</hi> is againſt the 4. of <hi>Iuly,</hi> at which time the <hi>Sunne</hi> riſeth and ſetteth alike without ſenſible
<pb n="25" facs="tcp:10089:25"/> error, viz. 4. of the clocke, and therefore thoſe dayes are of equall length, and ſo of others.</p>
                     <div type="subsection">
                        <head>For the ſecond, to finde what day the ſunne riſing in the one, ſhall be the ſunne ſetting in the other.</head>
                        <p>
                           <hi>Admit</hi> the day to be the 18<hi rend="sup">th</hi>. of <hi>February</hi> and according to the firſt pro. finde the time of <hi>Sunne riſing,</hi> which is at 40. m. after 6. <label type="milestone">
                              <seg type="milestoneunit">Exam. </seg>
                           </label> of the clocke <label type="milestone">
                              <seg type="milestoneunit">Conſtru¦ctio. </seg>5</label> for that day, and the ſetting 20. m, after 5. then marke what day of the <hi>Month</hi> the <hi>houre</hi> line of 20 m, after 5. in the forenoone, meeteth with the <hi>Kalender,</hi> which will be the 23. of <hi>Auguſt,</hi> ſo the 18<hi rend="sup">th</hi>. day of <hi>February</hi> the Sun did ſet at the ſame houre that it did riſe, the 23. day of <hi>Auguſt.</hi>
                        </p>
                     </div>
                  </div>
                  <div n="5" type="application">
                     <head>Fiftly, to finde the ſunnes place, or <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>5</label> degree, for any day of the yeere.</head>
                     <p>
                        <hi>Note</hi> where the parallel of the day of the <hi>Month</hi> croſſeth the <hi>Eclipticke,</hi> that is the <hi>Sunnes</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>6</label> place. So the former parallell of the 13<hi rend="sup">th</hi>. of <hi>Octo<g ref="char:EOLhyphen"/>ber</hi> meeteth with the <hi>Eclipticke</hi> in the beginning of ♏, and ♓, but which of theſe is the <hi>Sunnes</hi> place, the quarter of the yeare may eaſily tell you, viz. ♏ which is the <hi>Sunnes</hi> place or the degree in the <hi>Eclipticke</hi> for that day.</p>
                  </div>
                  <div n="6" type="application">
                     <pb n="26" facs="tcp:10089:26"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>6</label> Sixtly, to finde the Sunnes right aſcention, and oblique aſcention at any time.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>7</label> 
                        <hi>Conſider</hi> what <hi>Meridean</hi> meeteth with the Sunnes place in the <hi>Eclipticke</hi> for the day given, and marke the number of <hi>Meridians</hi> in the <hi>Equa<g ref="char:EOLhyphen"/>tor</hi> (for the <hi>Meridians</hi> are numbred in the <hi>Equator,</hi> as is ſayd before in the deſcription) ſo have you the Sunnes right <hi>Aſcention:</hi> but here note that the degrees in the <hi>Eclipticke</hi> are numbred forward and backeward in the <hi>Eclipticke</hi> unto 360. gr. upon this <hi>Inſtrument:</hi> ſo are the right <hi>Aſcentions</hi> of thoſe degrees alſo numbred forward and backward in the <hi>Aequator:</hi> for the right aſcen<g ref="char:EOLhyphen"/>tion of any degree in the <hi>Eclipticke,</hi> is that degree of the <hi>Aequator</hi> which is oppoſite unto it, (the ſucceſſion of the <hi>ſignes</hi> conſidered) ſo if the <hi>Sun</hi> were in the beginning of ♏, the right <hi>Aſcention</hi> is neere 208. degrees, for the <hi>Meridian</hi> that paſ<g ref="char:EOLhyphen"/>ſeth by the beginning of ♏, is accounted in the <hi>Equator</hi> from ♈, and is within 6. m, of 28. gr. <hi>Now</hi> the right <hi>Aſcention</hi> of ♋, is 90. gr. and the beginning the of ♎, is 180. gr. and from the beginning of ♎, to the beginning ♏, is within 6. m, of 28. gr. as before, all is which put toge<g ref="char:EOLhyphen"/>ther makes neere 208. gr. the right <hi>Aſcention</hi> of the <hi>Sun</hi> the 13th. day of <hi>October.</hi>
                     </p>
                     <div type="subsection">
                        <pb n="27" facs="tcp:10089:26"/>
                        <head>To find the Sunnes Oblique Aſcention at any time.</head>
                        <p>
                           <hi>Note</hi> that the difference of <hi>Aſcention,</hi> is the <label type="milestone">
                              <seg type="milestoneunit">Conſtru¦ctio. </seg>8</label> difference alwayes betweene the right <hi>Aſcention</hi> of the <hi>Sun,</hi> and the oblique <hi>Aſcention</hi> thereof: ther<g ref="char:EOLhyphen"/>fore the right <hi>Aſcention</hi> known by the laſt di<g ref="char:EOLhyphen"/>rectio<g ref="char:cmbAbbrStroke">̄</g>, &amp; the difference of <hi>Aſcention</hi> by the ſecond direction, the oblique <hi>Aſcention</hi> is eaſily had, by <hi>Addition,</hi> or <hi>ſubſtraction</hi> thus. If the <hi>Sun</hi> be in a <hi>Southerne ſigne</hi> then the <hi>oblique Aſcention,</hi> is grea<g ref="char:EOLhyphen"/>ter then the right <hi>Aſcention,</hi> by ſo much as the difference of <hi>Aſcention</hi> comes to: but if the <hi>Sun</hi> be in a <hi>Northerne ſigne, the oblique Aſcention</hi> is ſo much leſſe: which difference of <hi>Aſcention</hi> as be<g ref="char:EOLhyphen"/>fore by the 2 <hi>Pro:</hi> for the ſaid 13<hi rend="sup">th</hi>. of <hi>October</hi> was 15. gr. this ad unto the right <hi>Aſcention</hi> of the be<g ref="char:EOLhyphen"/>ginning of ♏, viz. 208. gr. makes 223. gr. the <hi>Suns oblique Aſcention</hi> for the beginning of ♏, on the 13<hi rend="sup">th</hi>. day of <hi>October;</hi> but if the <hi>Sun</hi> had beene in the beginning of ♉, the <hi>oblique aſcention</hi> would have beene onely neere 13. gr. viz. 12. gr. 54. m.</p>
                     </div>
                  </div>
                  <div n="7" type="application">
                     <head>Seventhly, to find the ſuns Alti<g ref="char:EOLhyphen"/>tude, <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>7</label> and houre of the ſuns com<g ref="char:EOLhyphen"/>ming Eaſt, or Weſt, any day of the yeare above the Horizon.</head>
                     <p>
                        <hi>Here</hi> note that this <hi>Propoſition</hi> holds in uſe <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>9</label>
                        <pb n="28" facs="tcp:10089:27"/> onely for that time of the <hi>Suns</hi> being in the <hi>Nor<g ref="char:EOLhyphen"/>therne ſignes</hi> that is from the 10<hi rend="sup">th</hi>. of <hi>March</hi> to the 13<hi rend="sup">th</hi>. of <hi>September:</hi> therefore lay the <hi>Index</hi> to the <hi>Eaſt,</hi> or <hi>Aequinoctiall point</hi> noted with <hi>E.</hi> or 40. &amp; 50. in the <hi>Limbe:</hi> ſo have you inſtantly at once without farther rectification both the <hi>Altitude and houre</hi> of the <hi>Suns</hi> comming <hi>East</hi> or <hi>Weſt,</hi> a<g ref="char:EOLhyphen"/>bove the <hi>Horizon</hi> for all or any of the dayes a<g ref="char:EOLhyphen"/>bove ſpecified: ſo the parallel of any day of the <hi>Moneth</hi> meeting with the edge of the <hi>Index</hi> gives the Suns <hi>Altitude</hi> in the <hi>Index,</hi> and the <hi>Meridian</hi> meeting therewith ſhewes the <hi>houre.</hi>
                     </p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> 
                        <hi>So</hi> if it were the ſecond of <hi>May,</hi> or the 22. of <hi>Iuly,</hi> the parallel belonging to thoſe daies meetes with the <hi>Index</hi> neere about, 23. gr. 17. m, and there alſo meetes with that point, the <hi>houre line</hi> of 7, and 5. which ſheweth that when the <hi>Sun</hi> is 23. gr. 17. m, high either upon the ſecond of <hi>May</hi> or the 22. of <hi>Iuly;</hi> then the <hi>Sun</hi> will be due <hi>Eaſt</hi> or <hi>Weſt,</hi> and that will happen to be at 7 of the clocke in the forenoone, and 5. of the clocke in the af<g ref="char:EOLhyphen"/>ternoone.</p>
                  </div>
                  <div n="8" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>8</label> Eightly, to find the diſtance of the ſuns riſing, or ſetting, any day of the yeare, from the Eaſt, or Weſt, called the ſuns Amplitude.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>12</label> 
                        <hi>Lay</hi> the <hi>Index</hi> to the day of the <hi>Moneth,</hi> for the
<pb n="29" facs="tcp:10089:27"/> time given, &amp; the edge of it in the <hi>Limbe</hi> of the <hi>In<g ref="char:EOLhyphen"/>strument</hi> ſhall ſhew the <hi>Amplitude</hi> required.</p>
                     <p>
                        <hi>So</hi> if the day were the 13<hi rend="sup">th</hi>. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> of <hi>October</hi> the num<g ref="char:EOLhyphen"/>ber of degrees from the points of <hi>Eaſt,</hi> noted with 40. 50. unto the <hi>Index</hi> is 18. gr. 40. m. which is the <hi>Suns Amplitude</hi> for the given day, viz. the 13<hi rend="sup">th</hi>. day of <hi>October.</hi>
                     </p>
                  </div>
                  <div n="9" type="application">
                     <head>Ninthly, to know the ſuns Me<g ref="char:EOLhyphen"/>ridionall <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>9</label> Altitude, or the ſuns depreſsion under the Horizon, at Midnight here, or in any Lati<g ref="char:EOLhyphen"/>tude, for any day in the yeare.</head>
                     <p>
                        <hi>Lay the Index</hi> unto the <hi>houre</hi> of 12, and where <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>11</label> the parallel of the day of the <hi>Moneth</hi> meeteth y<hi rend="sup">t</hi> therewith ſhal be the <hi>Suns Meridionall Altitude.</hi>
                     </p>
                     <p>
                        <hi>So</hi> if it were the 13<hi rend="sup">th</hi>. day of <hi>October,</hi> as before, <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> the parallell, for that day is 11. gr. and a halfe from the <hi>Equator South:</hi> this croſſeth the <hi>Index</hi> in 27. gr. which is the Sunnes <hi>Meridionall Alti<g ref="char:EOLhyphen"/>tude</hi> that day. Now for the Sunnes depreſſion at midnight, here is to be noted, that any degree of the <hi>Eclipticke</hi> is at any time ſo much below the <hi>Horizon,</hi> as his oppoſite degree in the <hi>Eclipticke,</hi> is above the <hi>Horizon</hi> at the ſame time. <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>12</label> 
                     </p>
                     <p>
                        <hi>Therefore</hi> where the contrary parallell of the <hi>Sunne</hi> viz. 11. gr. and a halfe <hi>North,</hi> meeteth with
<pb n="30" facs="tcp:10089:28"/> the <hi>Index</hi> in the houre of 12. that ſhall bee the <hi>Sunnes Meridionall depreſſion</hi> at midnight, the ſaid 13th. day of <hi>October.</hi>
                     </p>
                  </div>
                  <div n="10" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>10</label> Tenthly, to finde the time of day<g ref="char:EOLhyphen"/>breake, and end of twy-light, with the Poſition of the ſunne under the Horizon for any time.</head>
                     <p>
                        <hi>This propoſition,</hi> hath reference to the Sunnes depreſſion under the <hi>Horizon,</hi> for it is ſaid to bee day breake or twi-light to end, when the <hi>Sun</hi> is, 18. gr. under the <hi>Horizon:</hi> therefore the Con<g ref="char:EOLhyphen"/>ſtruction in this will be thus.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>13</label> Account 18. gr. on the <hi>Index</hi> then move the <hi>In<g ref="char:EOLhyphen"/>dex</hi> untill that degree meete with the Contrarie parallel of <hi>Declination</hi> for the day given, ſo the <hi>Meridian</hi> or <hi>Houre-line</hi> that meeteth therewith ſhall bee the <hi>houre</hi> of day breake required.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> So if the day were the 10. of <hi>Aprill,</hi> the paral<g ref="char:EOLhyphen"/>lel of <hi>Declination</hi> for that day is <hi>North</hi> II. gr. and a halfe which I ſeeke out one the other ſide of the <hi>Aequator</hi> viz. II. gr. and a halfe <hi>South Declination,</hi> and Marke where the 18th. gr. of the <hi>Index</hi> meeteth therewith, for there alſo is the <hi>houre</hi> of day breake <hi>viz.</hi> with in 20. m. of 3. in the Morning, and 20. m. paſt 9. for the end of <hi>twi-light</hi> the ſayd 10<hi rend="sup">th</hi>. of <hi>Aprill,</hi> alſo the <hi>Index</hi> in the <hi>Horizon</hi> at that Inſtant
<pb n="31" facs="tcp:10089:28"/> ſheweth the poſition of the <hi>Sun</hi> under the <hi>Hori<g ref="char:EOLhyphen"/>zon</hi> viz. neere 48 gr. 10. m. to the <hi>North</hi> of the <hi>Eaſt:</hi> but if the day had beene the 13<hi rend="sup">th</hi> of <hi>October</hi> the houre of <hi>daybreake</hi> had beene 2 minuts before 5. and <hi>twi-light</hi> would have ended 2. m. af<g ref="char:EOLhyphen"/>ter 7.</p>
                  </div>
                  <div n="11" type="application">
                     <head>Eleventhly, to finde the inequal<g ref="char:EOLhyphen"/>litie <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>11</label> of time, betweene day breake and Sun riſing, for any day of the yeare aſsigned.</head>
                     <p>By the firſt <hi>Conſtruction,</hi> for the dayes given <label type="milestone">
                           <seg type="milestoneunit">Conſtructio. </seg>14</label> finde the time of <hi>Sun riſing,</hi> and by the former 13<hi rend="sup">th</hi> Conſtruction the <hi>houre</hi> and time of <hi>day breake</hi> belonging to thoſe dayes: then compare the time betweene the <hi>Sun riſing, and day breake</hi> of the one, with that of the other, ſo the difference of thoſe two, ſhall bee the difference of time re<g ref="char:EOLhyphen"/>quired. <label type="milestone">
                           <seg type="milestoneunit">Example. </seg>
                        </label> 
                     </p>
                     <p>
                        <table>
                           <row>
                              <cell> </cell>
                              <cell> </cell>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>H. M.</hi>
                              </cell>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>H. M.</hi>
                              </cell>
                              <cell> </cell>
                           </row>
                           <row>
                              <cell rows="6">So on the tenth of</cell>
                              <cell rows="2">
                                 <hi>March</hi> the</cell>
                              <cell>
                                 <hi>Sun riſing is at</hi>
                              </cell>
                              <cell>6. 00</cell>
                              <cell rows="6">
                                 <hi>The time betweene day breake and Sun riſing is.</hi>
                              </cell>
                              <cell rows="2">2. 0</cell>
                              <cell rows="3">the dif<g ref="char:EOLhyphen"/>ference is, 12. m.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>day breake is at</hi>
                              </cell>
                              <cell>4. 00</cell>
                           </row>
                           <row>
                              <cell rows="2">
                                 <hi>Docemb.</hi> the</cell>
                              <cell>
                                 <hi>Sun riſing it at</hi>
                              </cell>
                              <cell>8. 12</cell>
                              <cell rows="2">2. 12</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>day breake, is at</hi>
                              </cell>
                              <cell>6. 00</cell>
                              <cell rows="3">the dif<g ref="char:EOLhyphen"/>ference is. 1. ho. 22. m.</cell>
                           </row>
                           <row>
                              <cell rows="2">
                                 <hi>May the</hi>
                              </cell>
                              <cell>
                                 <hi>Sun riſing is at</hi>
                              </cell>
                              <cell>4. 11</cell>
                              <cell rows="2">3. 34</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>day breake, at</hi>
                              </cell>
                              <cell>12, 37</cell>
                           </row>
                        </table>
                     </p>
                     <p>So the difference of time betweene <hi>day breake and Sunne riſing</hi> the 10<hi rend="sup">th</hi> of <hi>December</hi> is neere a
<pb n="32" facs="tcp:10089:29"/> quarter of an <hi>houre</hi> longer then that of the 10<hi rend="sup">th</hi> of <hi>March;</hi> but more then an <hi>houre</hi> and halfe longer betweene <hi>day breake, and Sun riſing</hi> the 10<hi rend="sup">th</hi> of <hi>May,</hi> then the 10<hi rend="sup">th</hi> of <hi>March.</hi>
                     </p>
                  </div>
                  <div n="12" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>12</label> Twelfely to finde the houre, and Altitude of the ſunnes comming upon a Declining wall any day of the yeare.</head>
                     <p>
                        <note place="margin">☞</note>
                        <hi>Seeing the declinations of Plaines, or Walls,</hi> are ac<g ref="char:EOLhyphen"/>counted from the points of <hi>Eaſt</hi> or <hi>Weſt</hi> in the <hi>Horizon,</hi> as the <hi>ſunnes Amplitude</hi> is the num<g ref="char:EOLhyphen"/>bering of them therefore ſhall bee alike, in the <hi>Limbe</hi> of the <hi>Inſtrument.</hi> Now admit the <hi>Decli<g ref="char:EOLhyphen"/>nation</hi> of a <hi>Plaine</hi> or <hi>Wall,</hi> to be 22. gr. the oppe<g ref="char:EOLhyphen"/>ration <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>15</label> would be thus. The <hi>Index</hi> being ſet there<g ref="char:EOLhyphen"/>to, you may inſtantly ſee at what <hi>houre</hi> the <hi>Sunne</hi> will come upon the <hi>Plaine,</hi> for any day in the yeare; for where the parallell of the day of the <hi>Moneth</hi> croſſeth the <hi>Index</hi> amongſt the <hi>houre<g ref="char:EOLhyphen"/>lines,</hi> (which <hi>Index</hi> repreſents the <hi>Plaine</hi>) that is the <hi>houre</hi> of the <hi>Suns</hi> comming upon the <hi>Plaine</hi> and the degrees in the <hi>Index</hi> gives the <hi>Sunnes Altitude.</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Examp. </seg>
                        </label> So if the Sunne were in the <hi>Tropicke</hi> of ♋ the <hi>Tropicke</hi> meeteth with the <hi>Index</hi> almoſt within 5 m. of 9 in the Morning, and at that time the <hi>Sunne</hi> commeth upon the <hi>Plaine,</hi> and there the <hi>Tropicke</hi> cuts alſo the <hi>Index</hi> in 45. gr.
<pb n="33" facs="tcp:10089:29"/> 40. m. which is the <hi>ſuns Altitude</hi> at that time that y<hi rend="sup">e</hi> 
                        <hi>Sun</hi> wil glance or begin to ſhine upo<g ref="char:cmbAbbrStroke">̄</g> the <hi>Plaine.</hi>
                     </p>
                     <p>As for the time of the <hi>ſuns</hi> continuance on the <hi>Plaine</hi> (as is ſpecified in the <hi>Index</hi> or <hi>Table</hi>) ac<g ref="char:EOLhyphen"/>count the <hi>Declination,</hi> on the other ſide of the <hi>Eaſt</hi> point, and lay the <hi>Index</hi> thereto, ſo the edge of it in the <hi>Tropicke</hi> of ♋, will point out at what houre the <hi>Sun</hi> goes of the <hi>Plaine</hi> viz. at 6. of the clock &amp; 38. m, neere, if the <hi>declination</hi> were <hi>Weſt,</hi> (as here it is ſuppoſed) which added to the time of the <hi>ſuns</hi> co<g ref="char:cmbAbbrStroke">̄</g>ming on the <hi>Plaine,</hi> makes 9. <hi>houres</hi> 33. m, &amp; ſo long the <hi>ſun</hi> ſhines on the <hi>Plaine.</hi>
                     </p>
                  </div>
                  <div n="13" type="application">
                     <head>Thirteenthly, to finde at what <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>13</label> houre, and Altitude the ſun muſt have to be oppoſite, or perpendicu<g ref="char:EOLhyphen"/>lar to a declining Plaine, any day in the yeere.</head>
                     <p>
                        <hi>Let a Plaine decline</hi> from the <hi>Eaſt</hi> point to<g ref="char:EOLhyphen"/>wards the <hi>South</hi> 22. <label type="milestone">
                           <seg type="milestoneunit">Example. </seg>
                        </label> gr. account this in the <hi>Limbe</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>16</label> from the <hi>houre</hi> of 12. and lay the <hi>Index</hi> thereto, ſo the parallell that croſſeth the <hi>Index,</hi> doth ſhew the <hi>Sunnes Altitude,</hi> and the <hi>Meridian</hi> meeting therewith, gives the <hi>houre,</hi> at which time the <hi>Sun</hi> will be oppoſite to the <hi>Plaine;</hi> ſo have you at one inſtant for every day in the yeare, at what <hi>houre</hi> and <hi>Altitude,</hi> the <hi>Sunne</hi> will bee oppoſite to the <hi>Plaine.</hi>
                     </p>
                     <pb n="34" facs="tcp:10089:30"/>
                     <p>
                        <table>
                           <row>
                              <cell cols="7"> </cell>
                              <cell role="label">gr. m. </cell>
                           </row>
                           <row>
                              <cell rows="3">As admit the dayes were theſe.</cell>
                              <cell>
                                 <hi>Decem.</hi>
                              </cell>
                              <cell rows="3">the tenth, the Suns place at which time is in</cell>
                              <cell>♑</cell>
                              <cell rows="3">and the houre of the Suns be<g ref="char:EOLhyphen"/>ing oppoſite to the plaine, that day would be at</cell>
                              <cell>40-m paſt. 1</cell>
                              <cell rows="3">and the Suns Altitude at that time would be,</cell>
                              <cell>12.12</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>March.</hi>
                              </cell>
                              <cell>♈</cell>
                              <cell>14 m. paſt. 1.</cell>
                              <cell>36.25</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Iune</hi>
                              </cell>
                              <cell>♋</cell>
                              <cell>48 m. paſt 12</cell>
                              <cell>60.45</cell>
                           </row>
                        </table>
                     </p>
                  </div>
               </div>
               <div type="section">
                  <p>Thus touching the reſolution of the former 13 uſes of the aforeſaid <hi>Table,</hi> or <hi>Index</hi> which had re<g ref="char:EOLunhyphen"/>ference only to the knowledge of the day of the <hi>Month,</hi> there are 13. other <hi>uſes</hi> of the foreſaid <hi>In<g ref="char:EOLhyphen"/>dex,</hi> or <hi>Table</hi> viz. the 10. 12. 32. 39. 40. 23. 17. 16. 26. 27. 28. 29. 30. Which have no dependance upon the ſight of the <hi>Sun,</hi> of which the 6 firſt are reſolued, only by knowing the day of the <hi>Month,</hi> and the other 7. are as followeth.</p>
                  <list>
                     <head>viz by knowing the day of the Month to finde.</head>
                     <item>1. <hi>At what houre the ſhadow of an Alti<g ref="char:EOLhyphen"/>tude is equall, double, triple, &amp;c. unto it.</hi>
                     </item>
                     <item>2. <hi>At any houre and Altitude of the Sun, or Azimuth, what proportion ſhadowes have to their bodies.</hi>
                     </item>
                     <item>3. <hi>The houre of the day agreeable to any Al<g ref="char:EOLhyphen"/>titude, or Azimuth.</hi>
                     </item>
                     <item>4. <hi>The Suns depreſſion and Azimuth at any houre of the night Aſſigned.</hi>
                     </item>
                     <item>5. <hi>The houre of the day to our Antipodes, by ſupoſing the Suns Depreſsion under the Horizon.</hi>
                     </item>
                     <item>6. <hi>At what houre in any day the Suns Azimuth and Altitude will be equall, and how much the Altitude and Azimuth will be.</hi>
                     </item>
                  </list>
                  <list>
                     <pb n="35" facs="tcp:10089:30"/>
                     <head>To finde.</head>
                     <item>7. <hi>What number of dayes will make the day an houre longer, or ſhorter at any time.</hi>
                     </item>
                     <item>8. <hi>Th<gap reason="illegible" resp="#PDCC" extent="1 letter">
                              <desc>•</desc>
                           </gap> inequallitie of time in equall moneths, or equall number of dayes.</hi>
                     </item>
                     <item>9. <hi>The degree of the Aequator in the Hori<g ref="char:EOLhyphen"/>zon, by ſuppoſing any degree of the Eclip<g ref="char:EOLhyphen"/>ticke in the Horizon.</hi>
                     </item>
                     <item>10. <hi>The degree of the Eclipticke in the Hori<g ref="char:EOLhyphen"/>zon by ſuppoſing the degree of the Equator in the Horizon.</hi>
                     </item>
                     <item>11. <hi>The degree of Medium Coeli, or the de<g ref="char:EOLhyphen"/>gree of the Eclipticke in the Meridian, by ſuppoſing the degree of the Eclipticke in the Horizon, vel contra.</hi>
                     </item>
                     <item>12. <hi>The Horoſcope, or the degree aſcendant, or deſcend<gap reason="illegible" resp="#PDCC" extent="1 letter">
                              <desc>•</desc>
                           </gap>nt, and the Nonageſſima de<g ref="char:EOLhyphen"/>gree at any houre.</hi>
                     </item>
                     <item>13. <hi>What Angle the Eclipticke makes with the Horizon, or the Altitude of the Nona<g ref="char:EOLhyphen"/>geſſima degree, &amp; what Azimuth it is in at any houre.</hi>
                     </item>
                  </list>
                  <div n="1" type="application">
                     <head>Firſt, to finde the Proportion of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>14</label> ſhadowes to their Altitudes at any time.</head>
                     <p>
                        <hi>As</hi> if it were required the 20 of <hi>Aprill,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Declara∣tio. </seg>
                        </label> at what houre of the day, and how high the <hi>Sun</hi> muſt be either in the <hi>forenoone</hi> or <hi>afternoone,</hi> that the ſha<g ref="char:EOLhyphen"/>dow
<pb n="36" facs="tcp:10089:31"/> of a <hi>man</hi> or any <hi>Altitude,</hi> ſhall be equall unto his height <hi>double, triple, quadruple Quintuple</hi> &amp;c.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>17</label> 
                        <hi>Lay</hi> the <hi>Index</hi> unto the numbers in the line of <hi>ſhadowes</hi> viz. to 1. 2. 3. 4. 5. &amp;c. and whereſoever any of thoſe diviſions in the line of <hi>ſhadowes</hi> meete with the <hi>Index</hi> amongſt the degrees; there it ſheweth what height the <hi>Sun</hi> muſt have, to make the <hi>ſhadowes equall, double, triple</hi> &amp;c. to the <hi>Altitude.</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> So laying the <hi>Index</hi> upon 1 in the line of <hi>ſhadowes,</hi> it meeteth with 45. gr. in the <hi>Index:</hi> &amp; ſo high the <hi>Sun</hi> muſt be to make the <hi>ſhadow of a man</hi> or any thing equall to his height upon an <hi>Hori<g ref="char:EOLhyphen"/>zontall plaine:</hi> then move the <hi>Index</hi> to and fro, un<g ref="char:EOLhyphen"/>till the ſaid 45. gr. in the <hi>Index</hi> meete with the pa<g ref="char:EOLhyphen"/>rallel of the day <hi>Month,</hi> viz the 20. of <hi>April,</hi> ſo the <hi>houre line</hi> that meeteth therewith, is the <hi>houre</hi> of the day that the <hi>ſhadow</hi> of a <hi>Man:</hi> or other <hi>Alti<g ref="char:EOLhyphen"/>tudes,</hi> will be <hi>equall</hi> to his heigth or <hi>Altitude,</hi> viz neere 10. of the Clocke in the <hi>forenoone,</hi> or 2. of the Clocke, in the <hi>afternoone.</hi>
                     </p>
                     <p>
                        <table>
                           <row>
                              <cell> </cell>
                              <cell> </cell>
                              <cell> </cell>
                              <cell> </cell>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>fore<g ref="char:EOLhyphen"/>noone.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>after<g ref="char:EOLhyphen"/>noone.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell> </cell>
                              <cell> </cell>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>gr. m.</hi>
                              </cell>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>ho. m.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>ho. m.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell rows="10">And according to the ſame directions when ſhadows are</cell>
                              <cell>
                                 <hi>Double.</hi>
                              </cell>
                              <cell rows="10">The <hi>Altitude</hi> would be.</cell>
                              <cell>26. 33</cell>
                              <cell rows="10">and the <hi>houre</hi> the ſaid 20. of <hi>Aprill</hi> would be,</cell>
                              <cell>7. 37</cell>
                              <cell>4. 23</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Triple.</hi>
                              </cell>
                              <cell>18. 26</cell>
                              <cell>6. 43</cell>
                              <cell>5. 17</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Quadruple.</hi>
                              </cell>
                              <cell>14. 2</cell>
                              <cell>6. 16</cell>
                              <cell>5. 44</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Quintuple.</hi>
                              </cell>
                              <cell>11. 19</cell>
                              <cell>5. 58</cell>
                              <cell>6. 02</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Sextuple.</hi>
                              </cell>
                              <cell>9. 27</cell>
                              <cell>5. 46</cell>
                              <cell>6. 14</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Septuple.</hi>
                              </cell>
                              <cell>8. 7</cell>
                              <cell>5. 37</cell>
                              <cell>6. 23</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Octuple.</hi>
                              </cell>
                              <cell>7. 7</cell>
                              <cell>5. 31</cell>
                              <cell>6. 29</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>N<gap reason="illegible" resp="#PDCC" extent="1 letter">
                                       <desc>•</desc>
                                    </gap>nocuple.</hi>
                              </cell>
                              <cell>6. 20</cell>
                              <cell>5. 25</cell>
                              <cell>6. 35</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Decuple.</hi>
                              </cell>
                              <cell>5. 43</cell>
                              <cell>5. 21</cell>
                              <cell>6. 39</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Vigecuple.</hi>
                              </cell>
                              <cell>2. 51</cell>
                              <cell>5. 2</cell>
                              <cell>6. 58</cell>
                           </row>
                        </table>
                     </p>
                  </div>
                  <div n="2" type="application">
                     <pb n="37" facs="tcp:10089:31"/>
                     <head>Secondly, to finde what proporti<g ref="char:EOLhyphen"/>on <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>15</label> ſhadowes have to their bodies at any houre in the day, Azimuth, or Altitude of the Sun aſigned.</head>
                     <p>If the <hi>houre</hi> be knowne, or ſuppoſed, move the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>18</label> 
                        <hi>Index</hi> until it meete with the houre in the parallel of the day of the <hi>Month,</hi> ſo the interſection of that parallel with the <hi>Index</hi> is the <hi>ſuns Altitude,</hi> and the edge of the <hi>Index,</hi> in the <hi>Limbe,</hi> wil ſhew the <hi>Suns Azimuth,</hi> then move the <hi>Index</hi> until the degree of <hi>Altitude</hi> interſect the <hi>line of ſhadowes,</hi> ſo ſhall you have the proportion of <hi>ſhadowes,</hi> to their bodies required.</p>
                     <p>So if on the 11<hi rend="sup">th</hi>. of <hi>Aprill</hi> at, 7. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> of the <hi>Clocke</hi> in the <hi>forenoone,</hi> (if the <hi>Sun</hi> ſhine,) it were required what proportion the <hi>ſhadow</hi> of a <hi>man</hi> ſhall beare to his height, or the <hi>ſhadow</hi> of an <hi>Altitude</hi> to the <hi>Altitude,</hi> the parallel that belongeth to the given day is neere 12. gr. <hi>Marke</hi> where this parallel meeteth with the given <hi>houre</hi> of 7. and bring the <hi>Index</hi> to it; ſo have you the <hi>Suns height</hi> at that <hi>houre</hi> viz 18. gr. 26. m, and the edge of the <hi>Index</hi> in the <hi>Limbe</hi> of the <hi>Inſtrument,</hi> ſhall give the <hi>Azimuth</hi> viz 4. gr. from the <hi>Eaſt:</hi> then move the <hi>Index,</hi> untill the degree of the <hi>Suns Altitude</hi>
                        <pb n="38" facs="tcp:10089:32"/> viz 18. gr. 26. m, meete with the line of <hi>ſhadowes</hi> which will be in 3, which ſheweth that at 7. of the Clock in the <hi>forenone</hi> the ſaid 11<hi rend="sup">th</hi>. of <hi>Aprill,</hi> the <hi>ſhadow</hi> of a <hi>man,</hi> or the <hi>ſhadow</hi> of an <hi>Altitude,</hi> ſhall be <hi>Triple</hi> to his <hi>height:</hi> the like will be at 5. of the <hi>Clocke</hi> in the <hi>afternoone,</hi> for equall diſtances of the <hi>Sun</hi> from the <hi>Meridian</hi> the ſame day, with<g ref="char:EOLhyphen"/>out ſenſible error, will give equall <hi>Altitudes</hi> of the <hi>ſun,</hi> and equall <hi>Altitude</hi> of the <hi>ſun</hi> doth pro<g ref="char:EOLhyphen"/>duce equall <hi>ſhadowes</hi> upon <hi>Horizontall Plaines</hi>
                     </p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>19</label> 
                        <hi>Secondly,</hi> if the <hi>Poſition</hi> or <hi>Azimuth</hi> of the <hi>Sun</hi> be knowne or ſuppoſed, which admit 4 gr. from the <hi>Eaſt</hi> towards the <hi>South.</hi>
                     </p>
                     <p>
                        <hi>Lay</hi> the <hi>Index</hi> unto it in the <hi>limbe,</hi> &amp; marke what degree in the <hi>Index</hi> the parallel meeteth with, which is with 18. gr. 26. m, ſo have you the <hi>ſuns Altitude</hi> in the <hi>Index:</hi> then move the <hi>Index</hi> until y<hi rend="sup">e</hi> degree meete with the <hi>Line</hi> of <hi>ſhadowes;</hi> ſo have you the proportion of <hi>ſhadowes</hi> required at that inſtant, viz <hi>Triple</hi> as before.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>20</label> 
                        <hi>Thirdly,</hi> if the <hi>Suns</hi> height be knowne or ſup<g ref="char:EOLhyphen"/>poſed, which admit 18. gr. 26. m, account it in the <hi>Index,</hi> and moove the <hi>Index</hi> until that degree meete with the <hi>line of ſhadowes;</hi> ſo where it inter<g ref="char:EOLhyphen"/>ſecteth the <hi>line of the ſhadowes,</hi> there you have the proportion of <hi>ſhadowes</hi> to their <hi>bodies</hi> at that in<g ref="char:EOLhyphen"/>ſtant of time required, which will be <hi>triple</hi> as be<g ref="char:EOLhyphen"/>fore; ſo the 10<hi rend="sup">th</hi>. of <hi>Aprill</hi> if the <hi>houre</hi> be 7. or the <hi>Altitude</hi> 18. g. 26. m, or the <hi>Azimuth</hi> 4. gr. from the <hi>Eaſt</hi> toward the <hi>South,</hi> the proportion of <hi>ſhadowes</hi> to their bodies will be <hi>Triple.</hi>
                     </p>
                  </div>
                  <div n="3" type="application">
                     <pb n="39" facs="tcp:10089:32"/>
                     <head>Thirdly to finde the houre of the <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>16</label> day agreeable to any Altitude or Azimuth, for any day of the yeare Propoſed.</head>
                     <p>
                        <hi>For the firſt</hi> account the <hi>Suns Altitude</hi> in the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>21</label> 
                        <hi>Index,</hi> and move it to and fro untill that degree meete with the parallel of the day of the <hi>Month:</hi> ſo the <hi>Meridian</hi> that paſſeth by that point, ſhal be the houre required.</p>
                     <p>Thus if the day were the tenth of <hi>March,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> the <hi>Sun</hi> being that day in the <hi>Aequinoctial,</hi> &amp; the <hi>Altitude</hi> ſuppoſed to be 32. gr. 37. m, this I ſeeke out upon the <hi>Index</hi> and move the <hi>Index</hi> till that degree meete with the <hi>Aequator;</hi> ſo the <hi>Meridian</hi> or <hi>houre Circle</hi> that paſſeth thereby is the <hi>houre</hi> viz. 10. of the <hi>Clocke</hi> in the <hi>forenoone</hi> or 2. of the <hi>Clocke</hi> in the <hi>afternoone,</hi> and if you move the <hi>Index</hi> ſoftly along as the degrees of the <hi>Suns Altitude</hi> in the <hi>Index</hi> interſect the <hi>Aequator</hi> (and ſo of any parallel:) ſo the <hi>Meridian</hi> that meeteth there<g ref="char:EOLhyphen"/>with is the <hi>houre</hi> of the day agreeable to that <hi>Altitude.</hi>
                     </p>
                     <div type="subsection">
                        <head>For the ſecond, to finde the houre <label type="milestone">
                              <seg type="milestoneunit">Conſtru¦ctio. </seg>22</label> of the day agreeable to any Azimuth.</head>
                        <p>
                           <hi>As</hi> ſuppoſe it were 36. gr. 35. m, <label type="milestone">
                              <seg type="milestoneunit">Exam. </seg>
                           </label> from the
<pb n="40" facs="tcp:10089:33"/> 
                           <hi>South.</hi> Move the <hi>Index</hi> in the <hi>Limbe</hi> unto this <hi>Azimuth</hi> known or ſuppoſed; ſo where the <hi>Index</hi> croſſeth the parallel for the day given, there the <hi>Meridian</hi> that meeteth therewith, ſhewes the <hi>houre</hi> of the <hi>day</hi> viz 10. of the <hi>Clocke</hi> in the <hi>fore<g ref="char:EOLhyphen"/>noone</hi> or 2 in the <hi>afternoone</hi> as before. And if you move the <hi>Index</hi> ſoftly along, as the <hi>Index</hi> paſ<g ref="char:EOLhyphen"/>ſeth by any <hi>Azimuth</hi> in the <hi>Limbe:</hi> ſo the edge of the <hi>Index</hi> ſhall interſect the parallel of <hi>declination</hi> for the day of the <hi>Month,</hi> in the <hi>houre</hi> of the day agreeable to that <hi>Azimuth:</hi> by which <hi>propoſition</hi> and the laſt, <hi>Glaſſes</hi> may be eaſily placed to burne according to the <hi>Suns Azimuth,</hi> or <hi>houre aſſigned.</hi>
                        </p>
                     </div>
                  </div>
                  <div n="4" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>17</label> Fourthly, to finde the ſuns depreſ<g ref="char:EOLhyphen"/>ſion, &amp; poſition under the Hori<g ref="char:EOLhyphen"/>zon, at any houre of the night, with the houre of the day to our Antipo<g ref="char:EOLhyphen"/>des, by ſuppoſing the ſun any num<g ref="char:EOLhyphen"/>ber of degrees under the Horizon.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>23</label> 
                        <hi>By</hi> the 11<hi rend="sup">th</hi> Conſtruction it is ſaid that any de<g ref="char:EOLhyphen"/>gree of the <hi>Eclipticke,</hi> is aſmuch belowe the <hi>Hori<g ref="char:EOLhyphen"/>zon</hi> at any time, as his oppoſite degree is above the <hi>Horizon</hi> at the ſame time: therefore if the <hi>Index</hi> be layed to the like parallel, on the contrary ſide of the <hi>Aequator,</hi> that meeteth with the given
<pb n="41" facs="tcp:10089:33"/> 
                        <hi>houre</hi> the interſection in the <hi>Index</hi> ſhall ſhew you the degree of the <hi>Suns depreſsion</hi> under the <hi>Hori<g ref="char:EOLhyphen"/>zon</hi> at that <hi>houre.</hi>
                     </p>
                     <p>
                        <hi>So</hi> if at 10 of the <hi>Clocke</hi> at night the ſaid 13<hi rend="sup">th</hi> of <hi>October</hi> it were required to finde the <hi>Suns</hi> de<g ref="char:EOLhyphen"/>preſſion under the <hi>Horizon,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> conſider the <hi>declinati<g ref="char:EOLhyphen"/>on,</hi> or the <hi>ſuns</hi> parallel for that day, which is 11. gr. and a halfe <hi>South,</hi> which <hi>declination</hi> I ſeeke in the other ſide of the <hi>Aequator,</hi> and marke where it meeteth with the <hi>houre</hi> of 10. unto which I lay the <hi>Index,</hi> ſo the edge thereof in the <hi>Limbe</hi> ſheweth the <hi>ſuns Azimuth</hi> to be nere 42 gr. 30. m, from the <hi>South,</hi> and the parallels interſection that meeteth with the <hi>Index,</hi> gives the <hi>Suns</hi> depreſſion, viz. neere 43. gr. and ſo much is the <hi>Sun</hi> below the <hi>Horizon,</hi> and in that poſition the 13<hi rend="sup">th</hi> of <hi>Octo<g ref="char:EOLhyphen"/>ber</hi> at 10. of the <hi>Clocke</hi> at night.</p>
                     <p>But if it were required at what <hi>houre</hi> of the <hi>Night</hi> the <hi>Sun</hi> would touch the verticall Circle of <hi>Eaſt</hi> and <hi>Weſt</hi> under the <hi>Horizon.</hi>
                     </p>
                     <p>
                        <hi>Lay</hi> the <hi>Index</hi> to the point of <hi>Eaſt</hi> and marke <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>24</label> where about the Contrary palle<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap> meeteth with the <hi>Index,</hi> for there you have both the <hi>houre</hi> and the degree of the <hi>ſuns depreſſion.</hi>
                     </p>
                     <p>
                        <hi>So</hi> the day being as before the 13<hi rend="sup">th</hi> of <hi>October,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> &amp; the <hi>declination ſouth</hi> 11. gr. and a halfe, this ac<g ref="char:EOLhyphen"/>count among<gap reason="illegible" resp="#PDCC" extent="2 letters">
                           <desc>••</desc>
                        </gap> the <hi>North declinations</hi> &amp; it meeteth with the <hi>Index</hi> in 38 m, paſt 6. the <hi>houre</hi> of the Suns being <hi>Weſt,</hi> and with all the <hi>ſuns depreſſion,</hi> at the ſame time is neere 14. gr. and 50. m.</p>
                  </div>
                  <div n="5" type="application">
                     <pb n="42" facs="tcp:10089:34"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>18</label> Fiftly, to finde the houre of the day to our Antipodes, by ſup<g ref="char:EOLhyphen"/>poſing the ſuns depreſſion under the Horizon.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>25</label> 
                        <hi>Conſider</hi> the <hi>declination</hi> for the day, and move the <hi>Index</hi> to and fro untill the degree of the <hi>ſuns depreſſion</hi> in the <hi>Index,</hi> meeteth with the like pa<g ref="char:EOLhyphen"/>rallel or the other ſide of the <hi>Aequator,</hi> ſo the <hi>houre</hi> that meeteth therwith is the <hi>houre</hi> of the day to our <hi>Antipodes.</hi>
                     </p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> 
                        <hi>So</hi> if on the 20<hi rend="sup">th</hi>. of <hi>Aprill,</hi> we ſhould ſuppoſe the <hi>ſun</hi> to be 13. gr. under the <hi>Horizon,</hi> &amp; deſire to know the <hi>houre</hi> to our <hi>Antipodes,</hi> the parallel of <hi>declention</hi> for that day is 15. gr. <hi>North,</hi> Now in the <hi>Index</hi> account 13. degrees and move it to and fro untill the ſaid thirteenth degree in the <hi>Index</hi> meete with the 15<hi rend="sup">th</hi>. parallel of <hi>South declination,</hi> ſo the <hi>Meridian</hi> that meeteth therewith is the <hi>houre</hi> of the day to our <hi>Antipodes,</hi> within 2 m, of 9. at night.</p>
                  </div>
                  <div n="6" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>19</label> Sixtly, to finde at what houre in any day, the ſuns Azimuch and Altitude will be equall, and how much the Altitude and Azimuth will be.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru∣ction. </seg>
                        </label> 
                        <hi>Move</hi> the <hi>Index,</hi> to &amp; fro untill the edge of the
<pb n="43" facs="tcp:10089:34"/> 
                        <hi>Index</hi> meete with the parallel belonging to that day, in the ſame Number of degrees that the end of the <hi>Index</hi> in the <hi>Limbe</hi> from the point of <hi>Eaſt</hi> doth; ſo have you the degree of the <hi>Suns Azimuth,</hi> and <hi>Altitude</hi> equall the one to the other, and the <hi>Meridian</hi> meeting with the <hi>Index</hi> in the parallel of the given day, ſheweth at what <hi>houre</hi> that <hi>Azimuth,</hi> and <hi>Altitude</hi> will be equall.</p>
                     <p>
                        <hi>So</hi> admit the <hi>ſun</hi> to be in the <hi>Tropicke</hi> of ♋, <label type="milestone">
                           <seg type="milestoneunit">Exam </seg>
                        </label> the <hi>Index</hi> being moved to and fro untill there be like degrees in the <hi>Index,</hi> and in the <hi>Limbe,</hi> which will be neere 16. gr. 45. m, and there the <hi>houre</hi> that meeteth therewith is 12. m, after 6. in the <hi>forenoon,</hi> at which <hi>houre</hi> the eleventh of <hi>Iune,</hi> the <hi>Suns Azimuth,</hi> and <hi>Altitude,</hi> will be <hi>equall</hi> viz. neere 16. <hi>gr.</hi> 45. m, as before.</p>
                  </div>
                  <div n="7" type="application">
                     <head>Seventhly, to finde what number <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>20</label> of dayes any time of the yeare, will make the day an houre longer or ſhorter.</head>
                     <p>
                        <hi>Account</hi> 7. gr. and a halfe amongſt the <hi>Meridi<g ref="char:EOLhyphen"/>ans</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtruc¦tio. </seg>27</label> from the given day in the <hi>Kallender,</hi> and note the day of the <hi>Month</hi> againſt it, then number the dayes betweene that day and the given day, and you haue the anſwer.</p>
                     <p>
                        <hi>So</hi> if the day were the laſt of <hi>February,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> or the firſt of <hi>March,</hi> conſider the <hi>Suns ſetting</hi> that day by the Inſtrument, which is 40. m, paſt 5. this <hi>doubled</hi>
                        <pb n="44" facs="tcp:10089:35"/> makes the length of the day, 11. <hi>houres</hi> 20. m, then from the laſt of <hi>February</hi> account 7. gr. and a halfe and it will point out the fifteenth of <hi>March</hi> at which time the Sun ſeteth at 10. m, paſt 6 which <hi>doubled</hi> makes 12 <hi>houres</hi> 20. m, ſo the fifteenth of <hi>March,</hi> the length of the day is an <hi>houre</hi> longer then it was the firſt of <hi>March;</hi> and the difference of time only but 15. dayes, but if the number of daies were accounted to or from the <hi>Suns</hi> entring into the <hi>Tropicall points,</hi> it will be more then 35. dayes before the day will be an <hi>houre</hi> longer or ſhorter.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> 
                        <hi>So</hi> if from the tenth of <hi>Iune</hi> we ſhould account 7. gr. and a halfe amongſt the <hi>Meridians</hi> from that <hi>Meridian</hi> that meeteth with the tenth of <hi>Iune,</hi> it would fall out at the 16<hi rend="sup">th</hi>. day of <hi>Iuly,</hi> at which time the day will be an <hi>houre</hi> ſhorter then it was the tenth of <hi>Iune,</hi> and the intervall of <hi>time</hi> more then twiſe as much as the former viz. 39. dayes.</p>
                  </div>
                  <div n="8" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>21</label> Eightly, to finde the inequalitie of time, in equall Mounthes or equall number of dayes.</head>
                     <p>
                        <hi>This propoſition</hi> at the firſt ſeemes as a <hi>Paradox,</hi> yet by this <hi>Inſtrument</hi> may eaſily be reſolued, and ſo conſequently from <hi>Mathematicall</hi> principles demonſtrated, not onely the inequalitie of equall <hi>Months,</hi> but alſo the inequalitie of <hi>Naturall dayes.</hi>
                     </p>
                     <pb n="45" facs="tcp:10089:35"/>
                     <p>
                        <hi>Now</hi> a day naturall according to the generall definition is one revolution of the <hi>Aequator</hi> or <hi>primum mobile,</hi> that is from <hi>ſun riſing</hi> to <hi>ſun riſing:</hi> or it is the time wherein the <hi>ſun</hi> paſſeth by the <hi>Meridian,</hi> and commeth to the <hi>Meridian</hi> againe, commonly taken for 24. <hi>houres:</hi> but be cauſe that in that intervale of <hi>time</hi> the ſun paſſing from the <hi>Meridian</hi> and commeth to the <hi>Meridian</hi> againe, the <hi>Sun</hi> moves according to his <hi>Naturall motion (ſecundum antiquiorum traditionem)</hi> neere a degree more or leſſe; therefore the <hi>Na<g ref="char:EOLhyphen"/>turall day</hi> ſhall be ſome what longer or ſhorter then 24. <hi>houres,</hi> viz. by ſo much as the difference of <hi>right aſcention</hi> of that degree of the <hi>Eclipticke</hi> comes to that the <hi>ſun</hi> is in, and ſeeing the degrees of the <hi>Eclipticke</hi> amongſt themſelues have not the ſame <hi>difference</hi> of <hi>right Aſcention</hi> that the other degrees have, (notwithſtanding the degrees of the <hi>Eclipticke</hi> amongſt themſelves being equall the one to the other) the <hi>ſuns motion</hi> ender thoſe de<g ref="char:EOLhyphen"/>grees being ſometimes quicker, and ſometimes ſlower, it will neceſſarily follow that the <hi>ſun</hi> will move more or leſſe untill the <hi>ſun</hi> can touch the <hi>Meridian,</hi> which is the limit or tearme of the <hi>ſuns diurnall revolution</hi> as before: this difference and inequalitie of time in <hi>naturall dayes</hi> may by calculation be given from day to day, but be<g ref="char:EOLhyphen"/>cauſe it is ſo inſenſible little in a day, hardly by an <hi>Inſtrument</hi> of this nature can be ſeene, but by a number of dayes, compared with another number of dayes it will evidently appeare.</p>
                     <p>
                        <hi>So,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> if it were required how much the <hi>Month
<pb n="46" facs="tcp:10089:36"/> of December</hi> is longer then the Month of <hi>March,</hi> in the firſt of which months the <hi>ſuns motion</hi> is quicker, being about the <hi>Perigeum</hi> then at other <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>28</label> times, now both of which <hi>months</hi> have equal num<g ref="char:EOLhyphen"/>ber of dayes, viz. 31.</p>
                     <p>
                        <table>
                           <row>
                              <cell rows="4">Finde the right aſcention for the</cell>
                              <cell rows="2">beginning and ending</cell>
                              <cell rows="2">of <hi>Mar.</hi> viz.</cell>
                              <cell>350.0.</cell>
                              <cell rows="2">the difer. of right aſcention for the Month of <hi>Mar.</hi> is</cell>
                              <cell rows="2">29.30.</cell>
                              <cell rows="4">the difference be<g ref="char:EOLhyphen"/>tweene theſe is 5. gr.</cell>
                           </row>
                           <row>
                              <cell>19. 30.</cell>
                           </row>
                           <row>
                              <cell rows="2">beginning and ending</cell>
                              <cell rows="2">of <hi>Dece.</hi> viz.</cell>
                              <cell>257. ¾</cell>
                              <cell rows="2">the difer. of right aſcention for the Month of <hi>Dece.</hi> is</cell>
                              <cell rows="2">34. 30.</cell>
                           </row>
                           <row>
                              <cell>292. ¼.</cell>
                           </row>
                        </table> which 5. gr. being conuerted into time by allowing 4 minits to a degree makes about 20. m, and ſo much is the <hi>Month</hi> of <hi>December</hi> longer then the <hi>Month</hi> of <hi>March,</hi> notwithſtanding both of theſe <hi>Months</hi> containing equall number of dayes.</p>
                  </div>
                  <div n="9" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>22</label> Ninthly, to finde the degree of the Aequator in the Horizon, by ſuppoſſing the degree of the Eclipticke in the Horizon.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Notatio. </seg>
                        </label> 
                        <hi>If</hi> the degree given be in the <hi>Northerne</hi> part of the <hi>Ecliptike,</hi> the oblique <hi>Aſcention</hi> is leſſe then the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>29</label> right <hi>Aſcention</hi> vel contra. Get therefore firſt the right <hi>Aſcention</hi> of the point given by the ſixt Pro. and the difference of <hi>Aſcention</hi> by the 2. Pro. for
<pb n="47" facs="tcp:10089:36"/> that taken from the right <hi>Aſcention</hi> gives the de<g ref="char:EOLhyphen"/>gree of the <hi>Aequinoctiall</hi> in the <hi>Horizon,</hi> but if the given degree had beene in a <hi>Southren</hi> ſigne, the difference of <hi>Aſcention</hi> muſt be added to the right <hi>Aſcention,</hi> ſo have you the degree of the <hi>Aequator</hi> in the <hi>Horizon.</hi>
                     </p>
                  </div>
                  <div n="10" type="application">
                     <head>Tenthly, to finde the degree of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>23</label> the Eclipticke in the Horizon by ſuppoſing the degree of the Aequator in the Horizon.</head>
                     <p>
                        <hi>This</hi> is but the Conuerſe of the former, onely <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>30</label> conſider the correſpondent quarters of the <hi>Ae<g ref="char:EOLhyphen"/>quinoctiall</hi> to theſe of the <hi>Eclipticke.</hi>
                     </p>
                  </div>
                  <div n="11" type="application">
                     <head>Eleventhly, to finde the degree of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>24</label> Medium Coeli, or the degree of the Eclipticke in the Meridian, by ſupp ſing any degree of the Eclipticke in the Horizon.</head>
                     <p>Seeke the degree of the <hi>Aequator</hi> in the <hi>Ho<g ref="char:EOLhyphen"/>rizon,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>31</label>
                        <pb n="48" facs="tcp:10089:37"/> by the 22. Pro. ſubtract, 90. from it (if the Number be too little adde a whole <hi>Circle</hi> to it) then the degree of the <hi>Eclipticke</hi> oppoſite to the remainder, is the Anſwer, but note that if the re<g ref="char:EOLhyphen"/>mainder be betweene 270. and 360. the oppoſite point belongs to the laſt <hi>Quarter</hi> of the <hi>Ecliptike,</hi> if the remainder be betweene 180. and 270. then it reſpects the 3 quarter of the <hi>Eclipticke,</hi> if the remainder be betweene 90. and 180. it hath refe<g ref="char:EOLhyphen"/>rence to the ſecond Quarter. &amp;c.</p>
                     <div type="subsection">
                        <head>But if the degree of the Eclipticke in the Horizon were required by knowing the degree of the in Eclipticke the Meridian.</head>
                        <p>
                           <hi>This,</hi> is onely but the converſe of the former, &amp; <label type="milestone">
                              <seg type="milestoneunit">Conſtru¦ctio. </seg>23</label> is thus performed firſt, ſeek the right <hi>Aſcentio<g ref="char:cmbAbbrStroke">̄</g>
                           </hi> of the given degree of <hi>Medium Coeli,</hi> &amp; adde there<g ref="char:EOLhyphen"/>to 90. gr. by accounting it from the former right <hi>Aſcention,</hi> &amp; note the <hi>ſuns</hi> place oppoſit therto for the difference of <hi>Aſcention</hi> of this laſt degree being ſubtracted from the former <hi>degree</hi> of the <hi>Aequator</hi> in the <hi>Horizon,</hi> if it be a degree of the <hi>Southren ſignes</hi> (otherwiſe Adde) gives the degree of the <hi>Eclipticke</hi> in the <hi>Horizon</hi> demanded.</p>
                     </div>
                  </div>
                  <div n="12" type="application">
                     <pb n="49" facs="tcp:10089:37"/>
                     <head>Twelfthly, to finde the Horoſcope <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>25</label> or the degree Aſcendant, or de<g ref="char:EOLhyphen"/>ſcendant and the Nona<g ref="char:EOLhyphen"/>geſſima degree at any houre.</head>
                     <p>
                        <hi>Firſt,</hi> note the <hi>right Aſcention</hi> for the day gi<g ref="char:EOLhyphen"/>ven <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio, </seg>33</label> according to the 6. Pro. which is the degree of the <hi>Aequator</hi> in the <hi>Meridian,</hi> at 12. of the <hi>Clocke,</hi> unto which degree adde 90. ſo have you the degree of the <hi>Aequator</hi> in the <hi>Horizon</hi> at 12. of the Clocke. Then conſider how many <hi>houres</hi> the given <hi>houres</hi> wants of 12. or is paſt 12. which conuerted into meaſure and accounted <hi>Eaſtward,</hi> or <hi>Weſtward,</hi> according to the <hi>houre</hi> given from the former points of the <hi>Aequator</hi> in the <hi>Hori<g ref="char:EOLhyphen"/>zon</hi> at 12. will give the degree of the <hi>Aequator</hi> in the <hi>Horizon</hi> at the <hi>houre</hi> propoſed, then by the 23. Pro. I ſeeke out the degree of the <hi>Eclipticke</hi> in the <hi>Horizo<g ref="char:cmbAbbrStroke">̄</g>
                        </hi> anſwerable to the degree of the <hi>Aequa<g ref="char:EOLhyphen"/>tor</hi> ſo have you the degree <hi>Aſcendant,</hi> from which account 90. gr. or 3 <hi>ſignes,</hi> ſo have you the degree of the <hi>Nonageſſima point</hi> in the <hi>Horizon,</hi> but if you reckon 6. ſignes from the <hi>Aſcendant,</hi> you have the <hi>deſendant</hi> degree of the <hi>Eclipticke</hi> in the <hi>Weſt</hi> of the <hi>Horizon.</hi>
                     </p>
                  </div>
                  <div n="13" type="application">
                     <pb n="50" facs="tcp:10089:38"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>26</label> Thirteenthly, to finde what Angle the Eclipticke makes with the Horizon, or the Altitude of the Nonageſſima degree of the Eclipticke, above the Horizon, and what Azi<g ref="char:EOLhyphen"/>muth it is in at any houre.</head>
                     <p>According to the laſt Pro. ſinde the degree <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>34</label> 
                        <hi>Aſcendant,</hi> and <hi>the Nonageſſima</hi> degree, then by the 24. Pro. finde what degree of the <hi>Eclipticke</hi> is in the <hi>Meridian,</hi> Anſwerable to the degree of the <hi>Eclipticke</hi> in the <hi>Horizon,</hi> ſo ſhall you know on which ſide of the <hi>Meridian</hi> the <hi>Nonageſſima</hi> degree is, &amp; how far from the <hi>Meridian,</hi> then if y<hi rend="sup">t</hi> 
                        <hi>Index</hi> be layed upon the <hi>houre</hi> of 12, where the parallel of the <hi>Nonageſſima</hi> degree croſſeth it, that ſhould be the height of it, if it were in the <hi>Meridi<g ref="char:EOLhyphen"/>an;</hi> account therfore from the <hi>Meridian</hi> or houre of 12. in the <hi>Aequator,</hi> the number of degrees betweene the <hi>Nonageſſima</hi> degree, and the degree of the <hi>Eclipticke</hi> in the <hi>Meridian,</hi> &amp; marke where that <hi>Meridian</hi> meeteth with the parallel of the of the <hi>Nonageſſima</hi> degree, lay the <hi>Index</hi> thereto,
<pb n="51" facs="tcp:10089:38"/> ſo have you the <hi>Altitude</hi> of the <hi>Nonageſſima</hi> degree in the <hi>Index,</hi> and the <hi>Azimuth</hi> in the <hi>Horizon,</hi> or <hi>Limbe</hi> of the <hi>Inſtrument.</hi>
                     </p>
                  </div>
               </div>
               <div type="section">
                  <p>There are yet the 48. 49. 50. 9. 13. 14. and 15<hi rend="sup">th</hi>. uſes of the ſaid <hi>Index</hi> or <hi>Table,</hi> which haue no relation to the <hi>ſuns</hi> ſight or obſer<g ref="char:EOLhyphen"/>vation in there operation, and reſolutions, and ſhould have followed theſe 26. uſes that have beene delivered: but I referre them to the end of this <hi>Tractat;</hi> as for theſe uſes of the <hi>Inſtrument</hi> which depend upon the <hi>Suns</hi> ſight, or obſervati<g ref="char:EOLhyphen"/>on they are theſe 13. following viz. the 1. 31. 4. 6. 36. 7. 22. 3. 5. 34. 11. 43. and 8<hi rend="sup">th</hi>.</p>
                  <list>
                     <pb n="52" facs="tcp:10089:39"/>
                     <head>viz. to ſhew</head>
                     <item>1. <hi>The Sun, or ſtarres Altitude above the Horizon at any time.</hi>
                     </item>
                     <item>2. <hi>The houre of the day, and Azimuth of the ſun.</hi>
                     </item>
                     <item>3. <hi>The Meridian Line upon any appearance of the Sun.</hi>
                     </item>
                     <item>4. <hi>The ſit of a building, or coſting of a place.</hi>
                     </item>
                     <item>5. <hi>The Suns Azimuth, and houre without Obſervation.</hi>
                     </item>
                     <item>6. <hi>The variation of the Needle.</hi>
                     </item>
                     <item>7. <hi>The Latitude of a place, or height of the Pole above the Horizon.</hi>
                     </item>
                     <item>8. <hi>The Suns Azimuth, and Altitude at any houre.</hi>
                     </item>
                     <item>9. <hi>The vncertainetie of time, by noting the ſhadow of things.</hi>
                     </item>
                     <item>10. <hi>The Quarter of the yeare and day of the Month, with the houre, Azimuth, and the Meridian line.</hi>
                     </item>
                     <item>11. <hi>Inſtantly the houre of the day, the Azimuth, and Altitude of the Sun: with the Meridionall line, without obſervation or ſight of the Sun, by knowing the Pro<g ref="char:EOLhyphen"/>portion betweene the length of a ſhadow upon a Horizontal Plaine, and that which did caſt the ſhadow.</hi>
                     </item>
                     <item>12. <hi>The Declination of a Wall, by ſeeing the Sun beginning to ſhine thereon or going from it.</hi>
                     </item>
                     <item>13. <hi>The Declination of a Wall, the Sun ſhining thereon.</hi>
                     </item>
                  </list>
                  <div n="1" type="application">
                     <pb n="53" facs="tcp:10089:39"/>
                     <head>Firſt, how to obſerue the Sun, or <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>27</label> ſtarres Altitude above the Horizon at any time.</head>
                     <p>
                        <hi>Lift</hi> up the edge of the <hi>Inſtrument</hi> to the eye, <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>35</label> ſo that the ſight which is at the <hi>Limbe</hi> or <hi>Cir<g ref="char:EOLhyphen"/>cumference</hi> of the <hi>Quadrant</hi> be next the eye, and the <hi>Index</hi> to hang perpendicular and to play eaſi<g ref="char:EOLhyphen"/>ly by the ſide therof: then move the <hi>Quadrant</hi> up and downe untill you may through both ſights ſee the <hi>Center</hi> or midle of the <hi>Sun,</hi> or <hi>ſtarre:</hi> ſo the <hi>Index</hi> in the <hi>Limbe</hi> ſhall fall upon the degrees of the <hi>Sun</hi> or <hi>ſtarres Altitude</hi> above the <hi>Horizon</hi> at that time. Or without looking at the <hi>ſun,</hi> the <hi>Al<g ref="char:EOLhyphen"/>titude</hi> thereof may be thus found: hould the <hi>Qua<g ref="char:EOLhyphen"/>drant</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>36</label> that the <hi>Index</hi> may hang perpe<g ref="char:cmbAbbrStroke">̄</g>dicular, or be <hi>verticall</hi> as before, then move about the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> untill the edge of it be oppoſite to the body of the <hi>Sun.</hi> Now ſuppoſing the <hi>Inſtrument</hi> to hang thus upon his <hi>Center,</hi> ſoftly lift up the edge thereof which is towards the <hi>Sun,</hi> untill you ſee the beames of the <hi>ſun</hi> paſſe through both <hi>ſights,</hi> then the <hi>Index</hi> in the <hi>Limbe</hi> ſhall give the <hi>ſuns Altitude</hi> as before.</p>
                  </div>
                  <div n="2" type="application">
                     <pb n="54" facs="tcp:10089:40"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>28</label> Secondly, how to finde the houre of the day, and Azimuth of the Sun, upon any appea<g ref="char:EOLhyphen"/>rance of the Sunne.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>37</label> 
                        <hi>By</hi> the laſt <hi>Pro.</hi> obſerue or take the <hi>ſuns Altitude</hi> and account it on the <hi>Index,</hi> then ſeeke for the parallel of the day of the <hi>Month</hi> for the day pre<g ref="char:EOLhyphen"/>ſent, &amp; move the <hi>Index</hi> untill that degree of <hi>Alti<g ref="char:EOLhyphen"/>tude</hi> in the edge of the <hi>Index</hi> meete with the parallel of the day, ſo the <hi>Meridian</hi> that meeteth with that degree of <hi>Altitude</hi> in the <hi>Index,</hi> ſhall be the houre of the day required, &amp; the edge of y<hi rend="sup">e</hi> 
                        <hi>In<g ref="char:EOLhyphen"/>dex</hi> in the <hi>Limbe</hi> of the <hi>Inſtrument,</hi> ſhall likewiſe ſhew the Suns <hi>Azimuth</hi> belonging to that houre.</p>
                     <p>
                        <hi>So</hi> if upon the laſt of <hi>August</hi> the <hi>Suns Altitude</hi> in the forenoone ſhould be obſerued and found to be 30. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> gr. &amp; a halfe, ſeeke this <hi>Altitude</hi> out upon the <hi>Index</hi> &amp; move the <hi>Index</hi> untill the degree of <hi>Alti<g ref="char:EOLhyphen"/>tude</hi> meete with the parallel for the day of the <hi>Month</hi> given, viz. the fift parallel from the <hi>Aequa<g ref="char:EOLhyphen"/>tor Northward</hi> ſo the <hi>houreline</hi> that meeteth alſo with the 30. gr. &amp; a halfe in the <hi>Index,</hi> is the <hi>houre</hi> viz. neere 9. &amp; that ſhall be the <hi>houre</hi> of the day at that inſtant, &amp; the edge of the <hi>Index</hi> in the <hi>Limbe</hi> cutteth neere 35. gr. and 30. m, from the point of <hi>Eaſt,</hi> towards the South, and ſo much is the <hi>Suns Azimuth</hi> at that time.</p>
                  </div>
                  <div n="3" type="application">
                     <pb n="55" facs="tcp:10089:40"/>
                     <head>Thirdly, how to finde the Meridi<g ref="char:EOLhyphen"/>an <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>29</label> line, and the true points of North, &amp; South, Eaſt, and Weſt upon any appearance of the Sunne.</head>
                     <p>According to the 27. <hi>Pro.</hi> firſt obſerue the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>38</label> 
                        <hi>Suns Altitude</hi> above the <hi>Horizon,</hi> and by the laſt Conſtruction finde the <hi>Suns Azimuth</hi> agreeable to that <hi>Altitude:</hi> let the <hi>Index</hi> and reſt at that de<g ref="char:EOLhyphen"/>gree, and erect the prependicular at the end of the <hi>Index,</hi> then houlding the plaine or <hi>face</hi> of the <hi>Quadrant</hi> parallel to the <hi>Horizon,</hi> move the <hi>In<g ref="char:EOLhyphen"/>ſtrument Circular,</hi> untill the ſhadow of the ſaid perpendicular fall by the ſide of the <hi>Index,</hi> and ſo the <hi>houerline</hi> of 12, or the edge of the <hi>Inſtrument</hi> which is parallel unto it (which is the <hi>North</hi> and <hi>ſouth</hi> edge of the <hi>Inſtrument</hi>) ſhall repreſent the <hi>Meridian line,</hi> and pointeth out the <hi>North</hi> and <hi>South</hi> in the <hi>Horizon</hi> of the world by the termes thereof, and the other ſtraight edge of the <hi>Inſtrument</hi> which is perpendicular unto that edge is the (<hi>Eaſt</hi> and <hi>Weſt</hi> edge of the <hi>Inſtrument</hi>) and denoteth or ſheweth the line of <hi>Eaſt,</hi> and <hi>Weſt</hi> in the <hi>Horizon,</hi> of the world. But this may be more accurately done if you place the backe
<pb n="56" facs="tcp:10089:41"/> of the <hi>Inſtrument</hi> downe upon an <hi>Horizontall</hi> plaine, and the edge of the <hi>Index</hi> being at the de<g ref="char:EOLhyphen"/>gree of the <hi>ſuns Azimuth</hi> obſerved, and the per<g ref="char:EOLhyphen"/>pendicular erected at the end of the <hi>Index</hi> as be<g ref="char:EOLhyphen"/>fore: then moving the <hi>Inſtrument</hi> as it ſo lyeth untill the ſhadow of the perpendicular fall by the ſide of the <hi>Index,</hi> ſo the <hi>Meridian</hi> of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment,</hi> ſhall be in the <hi>Meridian</hi> of the World, and every point and degree in the <hi>Limbe</hi> of the <hi>In<g ref="char:EOLhyphen"/>ſtrument</hi> ſhall point out, and be oppoſite, and re<g ref="char:EOLhyphen"/>preſent his like degree in the <hi>Horizon</hi> of the world.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>39</label> But here note that this <hi>Conſtruction</hi> ſerves on<g ref="char:EOLhyphen"/>ly but for the forenoone obſervation; for if the practice be in the afternone, the way to finde the <hi>Meridian</hi> line may be thus. Having found the <hi>ſuns Azimuth</hi> as before, lay the <hi>Index</hi> upon the houre line of 12. and erect the perpendicular at the end thereof, and move the <hi>Inſtrument</hi> a<g ref="char:EOLhyphen"/>bout <hi>Circular,</hi> untill the ſhadow of the ſaid per<g ref="char:EOLhyphen"/>pendicular fall by the ſide of the <hi>Index:</hi> for then if the edge of the <hi>Index</hi> be moved unto the <hi>ſuns Azimuth</hi> before known, the edge of the <hi>Index</hi> ſhall repreſent the <hi>Meridian</hi> line, &amp; 90. gr. farther ſhall be the point of <hi>Eaſt,</hi> and the <hi>Center</hi> of the <hi>Inſtrument</hi> the point of <hi>Weſt,</hi> therefore if upon the plaine that the <hi>Inſtrument lies</hi> upon, you make a marke at the edge of the <hi>Index</hi> which is in the <hi>Meridian</hi> as before, and another marke right un<g ref="char:EOLhyphen"/>der the <hi>Center</hi> and ſo place the <hi>North</hi> and <hi>South</hi> edge of the <hi>Inſtrument</hi> unto theſe two points: then
<pb n="57" facs="tcp:10089:41"/> every degree in the <hi>Horizon.</hi> or <hi>Limbe</hi> of the <hi>In<g ref="char:EOLhyphen"/>ſtrument,</hi> ſhall point out as before his oppoſite or <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>ike degree in the <hi>Horizon</hi> of the world.</p>
                  </div>
                  <div n="4" type="application">
                     <head>Fourthly, how to finde the ſit <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>30</label> of a Building, or Coſting of a place.</head>
                     <p>
                        <hi>By</hi> the laſt <hi>Pro.</hi> finde out or draw the <hi>Meridian <label type="milestone">
                              <seg type="milestoneunit">Conſtru¦ctio. </seg>40</label> line,</hi> and place the <hi>North</hi> and <hi>South</hi> edge of the <hi>Inſtrument</hi> unto it: if the <hi>Building</hi> or <hi>Place</hi> ly in the <hi>Eaſterne ſemicircle</hi> of the world (but if it ly in the <hi>Weſterne ſemicircle,</hi> then let the <hi>Eaſt</hi> &amp; <hi>Weſt</hi> edge of the <hi>Inſtrument</hi> be placed upon the <hi>Meri<g ref="char:EOLhyphen"/>dian</hi> line) ſo the eye being over the <hi>Center</hi> of the <hi>Inſtrument,</hi> and behoulding the place, let the <hi>Index</hi> be moved untill it be alſo with the viſual line ob<g ref="char:EOLhyphen"/>ſerved by the eye, that is oppoſite to the place, ſo the edge of the <hi>Index,</hi> from the <hi>Cardinall</hi> points of the <hi>Inſtrument</hi> in the <hi>Limbe,</hi> viz. from the <hi>Eaſt</hi> or <hi>Weſt, North</hi> or <hi>South,</hi> ſhall ſhew the bearing of that place from you, in reſpect of the <hi>Cardinall</hi> points of the world in the <hi>Horizon:</hi> but if two ſights be placed at the <hi>Index</hi> (which is according to the deſcription thereof) then may you ob<g ref="char:EOLhyphen"/>ſerve the place through the ſights of the <hi>Index</hi> by leting the <hi>Inſtrument</hi> reſt, and moving the <hi>Index</hi> to and fro untill you ſee the obiect, ſo the edge of the <hi>Index</hi> in the <hi>limbe,</hi> ſhall point out the
<pb n="58" facs="tcp:10089:42"/> bearing or <hi>Poſition</hi> of the place from you in de<g ref="char:EOLhyphen"/>grees from the <hi>Eaſt, Weſt, North,</hi> or <hi>South,</hi> &amp; ac<g ref="char:EOLhyphen"/>counting 11. gr. and ¼ as often as you can in thoſe degrees, obſerved: you have the point of the <hi>Compaſſe</hi> which the place, or obiect beares from you.</p>
                  </div>
                  <div n="5" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>31</label> Fiftly, to finde the ſuns Azimuth, and houre without obſervation.</head>
                     <p>The <hi>Meridian line</hi> being drawne firſt upon a <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>41</label> plaine according to the former directions, con<g ref="char:EOLhyphen"/>ſider if it be in the forenoone or afternoone; if in the forenoone, then let the <hi>North,</hi> and <hi>South</hi> edge of the <hi>Inſtrument</hi> be placed unto the <hi>Meridian line,</hi> but if it be in the afternoone, then ſet the edge of <hi>Eaſt,</hi> &amp; <hi>Weſt</hi> of the <hi>Inſtrument,</hi> unto the <hi>Meridian line,</hi> and let the <hi>Inſtrument</hi> reſt there, then erect the perpendicular at the end of the <hi>Index,</hi> &amp; move the <hi>Index</hi> about untill the ſhadow of the perpen<g ref="char:EOLhyphen"/>dicular fall by the ſide of the <hi>Index,</hi> ſo the edge of the <hi>Index</hi> will amongſt the degrees in the <hi>Limbe</hi> ſhew the <hi>Suns Azimuth</hi> at that time, and where the edge of the <hi>Index</hi> meeteth with the parallel of the day of the <hi>Month,</hi> that is the <hi>houre</hi> of the day at that time. <hi>But</hi> if the <hi>Axis</hi> be rectified then there is no neede of a <hi>Meridian line</hi> to be drawne, for this <hi>Inſtrument</hi> will with great facilitie finde out his owne <hi>Meridian,</hi> by moving it to and fro untill
<pb n="59" facs="tcp:10089:42"/> the ſhadow of the perpendicular which is ouer the <hi>Center</hi> of the <hi>Inſtrument,</hi> interſect the ſame <hi>houre</hi> in the <hi>Parallel</hi> of the day of the <hi>Moneth,</hi> that the <hi>Axis</hi> doth amongſt the Common <hi>houres<g ref="char:punc">▪</g>
                        </hi> ſo that <hi>houre</hi> ſhall be the <hi>houre</hi> of the day for that inſtant, and the ſhadow of the ſaid perpendicular, cutting the <hi>Limbe,</hi> or extended unto it, doth there ſhew the Suns <hi>Azimuth,</hi> and ſo the <hi>Meridi<g ref="char:EOLhyphen"/>an</hi> of the <hi>Inſtrument</hi> at that poſition, ſhal be in the <hi>Meridian</hi> of the world required.</p>
                  </div>
                  <div n="6" type="application">
                     <head>Sixtly, to finde the variation <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>32</label> of the needle.</head>
                     <p>
                        <hi>By</hi> the twentie nineth <hi>Pro.</hi> vpon an even <hi>Plaine</hi> parallel to the <hi>Horizon</hi> draw the <hi>Meridian line,</hi> &amp; <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>42</label> place the <hi>North</hi> &amp; <hi>South</hi> line of the <hi>Card</hi> directly over the ſaid <hi>Meridian line,</hi> ſo the Number of de<g ref="char:EOLhyphen"/>grees that the <hi>Needle</hi> cutteth in the <hi>Card</hi> from the <hi>North</hi> and <hi>South</hi> line of the <hi>Card,</hi> that ſhall be the variation of the <hi>Needle</hi> required; otherwiſe it may be found thus: Neere unto the <hi>Center</hi> of the <hi>Index,</hi> upon the <hi>Index</hi> may a ſmall <hi>Broſse pinne</hi> be ſo placed that it may be erected perpendicular to the <hi>Center</hi> of the <hi>Inſtrument</hi> and halfe an inch a<g ref="char:EOLhyphen"/>bove it. Let a <hi>Needle</hi> by placed upon this pinne, then lay the <hi>Eaſt,</hi> and <hi>Weſt</hi> edge of the <hi>Inſtrument</hi> to the <hi>Meridian line,</hi> &amp; when the <hi>Needle</hi> reſteth, move the <hi>Index,</hi> untill the edge of it be di<g ref="char:EOLhyphen"/>rectly under the <hi>Needle</hi> ſo the edge of the <hi>Index;</hi> in the <hi>Limbe</hi> of the <hi>Inſtrument,</hi> ſhall
<pb n="60" facs="tcp:10089:43"/> point out or ſhew the <hi>Needles variation</hi> required.</p>
                  </div>
                  <div n="7" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>33</label> Seventhly, to finde the Latitude of a place, or the Poles hight above the Horizon.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>43</label> 
                        <hi>First,</hi> draw the <hi>Meridian line</hi> upon ſome plaine by helpe of the 38. <hi>Construction,</hi> then erect the prependicular at the end of the <hi>Index,</hi> and place the <hi>North</hi> and <hi>South</hi> edge of the <hi>Inſtrument,</hi> to the <hi>Meridian line</hi> ſo drawne upon the plaine, and move alſo the <hi>Index</hi> untill the edge thereof touch the houre of 12. let the <hi>Inſtrument</hi> reſt at this poſition, then marke diligently about noone or 12. of the Clocke when the ſhadow of the perpendicular doth fall by the edge of the <hi>Index,</hi> for then the <hi>ſun</hi> is in the <hi>Meridian,</hi> at which time according to the 27. Pro. obſerue or take the <hi>ſuns</hi> height (which is his <hi>Meridian Altitude,</hi> for that day) and by the 3. <hi>Pro.</hi> finde the Suns <hi>declination</hi> agreeable to that day, and adde it to the <hi>Suns Meridionall Altitude</hi> obſerve (if it be <hi>South de<g ref="char:EOLhyphen"/>clination,</hi> otherwiſe ſubtract it from the former <hi>Meridionall Altitude,</hi>) ſo have you the height of the <hi>Aequinoctial</hi> above the <hi>Horizon,</hi> that taken from 90. gives the depreſſion of the South <hi>Pole</hi> under the <hi>Horizon,</hi> which is alwayes equall to the elevation of the <hi>North Pole</hi> above the <hi>Horizon.</hi>
                     </p>
                     <pb n="61" facs="tcp:10089:43"/>
                     <p>
                        <hi>So</hi> if upon the tenth of <hi>Aprill,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> the <hi>Meridian Altitude</hi> ſhould be found to be 50. gr. the <hi>Decli<g ref="char:EOLhyphen"/>nation</hi> belonging to that day by the 3. Pro. is 11. gr. and a halfe <hi>North,</hi> which being ſubtracted (ac<g ref="char:EOLhyphen"/>cording to the former directions) leaves 38. gr. 30. m, the height of the <hi>Aequinoctiall</hi> above the <hi>Horizon:</hi> &amp; that taken from 90. leaves 51. gr. 30. m the depreſſion of the South <hi>Pole</hi> under the <hi>Hori<g ref="char:EOLhyphen"/>zon:</hi> or the elevation of the <hi>North Pole</hi> above the <hi>Horizon,</hi> for the height of the <hi>Aequinoctiall</hi> knowne, the Complement thereof is alwayes the <hi>Latitude</hi> of the place, or height of the <hi>Pole:</hi> and here note generally that the height of the <hi>Pole</hi> and <hi>Aequinoctiall</hi> together, doe alwayes make a <hi>Quadrant</hi> or 90. gr. therefore the height of one of them being knowne, the height of the other is alſo knowne, and further here note that if the <hi>ſun</hi> have <hi>North Declination,</hi> the <hi>ſun</hi> is ſo much higher then the <hi>Aequinoctiall</hi> at none that day, by ſo much as his <hi>Declination,</hi> cometh to, but if the <hi>Sun</hi> have South <hi>Declination,</hi> then the <hi>Sun</hi> is lower then the <hi>Aequinoctiall</hi> that day at noone, by ſo much as his <hi>Declination</hi> cometh to, by which you may eaſily gether when to adde, or ſubtract the <hi>ſuns Declination to,</hi> or from the <hi>ſuns Meridianall Altitude</hi> to get the height of <hi>Aequator,</hi> which knowne the <hi>Poles</hi> height cannot be unknowne.</p>
                  </div>
                  <div n="8" type="application">
                     <pb n="62" facs="tcp:10089:44"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>34</label> Eightly, to finde the ſuns Azimuth and Altitude for any houre.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>44</label> 
                        <hi>Marke</hi> where the parallel for the day of the <hi>Month</hi> meeteth with the given <hi>houre,</hi> and bring the edge of the <hi>Index</hi> thereto, ſo the degree that the edge of the <hi>Index</hi> cutteth in the <hi>Limbe</hi> of the <hi>Inſtrument</hi> that ſhal be the <hi>Suns Azimuth,</hi> and the degree that the <hi>houre</hi> cutteth in the <hi>Index,</hi> that ſhall be the <hi>Suns Altitude</hi> required.</p>
                     <p>
                        <hi>So,</hi> if upon the tenth of <hi>December</hi> at nine of the Clocke in the Morning, <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> the <hi>Suns Azimuth</hi> and <hi>Altitude</hi> were required, marke firſt where the <hi>Tropick</hi> of <hi>Capricorne</hi> (which is the parallel, for that day given) meeteth with the given <hi>houre</hi> of nine, and bring the <hi>Index</hi> thereto, ſo the edge of it in the <hi>Limbe</hi> pointeth out neere 40. gr. and a halfe, &amp; ſo much is the <hi>Suns Azimuth,</hi> from the <hi>South,</hi> at nine of the <hi>Clocke</hi> in the forenoone, the ſaid tenth of <hi>December,</hi> and the <hi>houre line</hi> meeting with the <hi>Index,</hi> ſheweth neere 5. gr. 25. m. ſo much is the <hi>ſuns Altitude</hi> at that time; now if you move the <hi>Index</hi> ſoftly along, as the edge of it paſſeth by any <hi>houre</hi> for any day of the yeare, ſo the edge of the <hi>Index</hi> in the <hi>Limbe</hi> of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> ſheweth the <hi>ſuns Azimuth,</hi> and the inter<g ref="char:EOLhyphen"/>ſection of the parallel with the <hi>Index</hi> ſhall ſhew the <hi>Suns Altitude</hi> belonging to that <hi>houre.</hi>
                     </p>
                  </div>
                  <div n="9" type="application">
                     <pb n="63" facs="tcp:10089:44"/>
                     <head>Ninthly, to ſhew the uncertain<g ref="char:EOLhyphen"/>tie <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>35</label> of time, by noting the ſhadow of things.</head>
                     <p>
                        <hi>It</hi> is uſually noted by ſome, that when the ſha<g ref="char:EOLhyphen"/>dow of the edge of a Window, Dore, Wall, or ſuch like, ſhall touch ſuch or ſuch markes, that it ſhall be then ſuch, or ſuch an houre of the day, and ſo conſtantly to hould for all the yeare, this obſeruation is farre from truth, and the princi<g ref="char:EOLhyphen"/>palls of <hi>Aſtronomie</hi> (and may be eaſily contra<g ref="char:EOLhyphen"/>dicted by ſuch which have but indifferent judge<g ref="char:EOLhyphen"/>ment in the Nature of ſhadowes, and the <hi>Suns</hi> paſſages by the <hi>Meridians</hi> and verticall <hi>Circles</hi> of the Heavens, for by how much greater the pro<g ref="char:EOLhyphen"/>pinquitie of the <hi>Suns</hi> approchment is unto the <hi>Zenith,</hi> or verticall point, by ſo much the more ſhall the houre or time be various in one and the ſame <hi>Azimuth.</hi>
                     </p>
                     <p>
                        <hi>So</hi> in the laſt <hi>Pro.</hi> the <hi>Azimuth</hi> of the <hi>Sun</hi> the tenth of <hi>December,</hi> at nine of the <hi>Clocke</hi> in the forenoone, was found to be 40. gr. and a halfe, <label type="milestone">
                           <seg type="milestoneunit">Exam </seg>
                        </label> and the <hi>Suns</hi> diſtance from the <hi>Zenith,</hi> at that time was neere 84. gr. 35. m, Now admitte the <hi>Suns</hi> diſtance from the <hi>Zenith</hi> the tenth of <hi>Iune</hi> were but 32. gr. 35. m, the Sunne being in the ſame <hi>Azimuth,</hi> the houre would be halfe an houre paſt 10. For the <hi>Index</hi> being layed to the <hi>houre</hi> of 9. in the <hi>Tropicke</hi> of ♑. (which is the <hi>Suns</hi> parallel, for the ſaid tenth of <hi>December,</hi>) and it cutteth the
<pb n="64" facs="tcp:10089:45"/>
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>45</label> parallels of the <hi>Suns Motion</hi> in the inequalitie of time, and ſo the complement of the former 32. gr 35. m, in the <hi>Index,</hi> meeteth with the <hi>Tropicke</hi> of ♋, (which is the <hi>Suns</hi> parallel for the tenth of <hi>Iune</hi>) in halfe an houre paſt 10. ſo that it evident<g ref="char:EOLhyphen"/>ly appeares, that the ſhadow of a perpendicular thing on the tenth of <hi>December,</hi> denoting the <hi>houre</hi> of the day to be 9. of the <hi>Clocke,</hi> the ſame ſhadow the tenth of <hi>Iune,</hi> ſhall repreſent halfe an houre paſt 10. ſo the error ſhall be an houre and a halfe: but if you move the <hi>Index</hi> unto the houre of 9. belonging to the tenth of <hi>Iune,</hi> the <hi>Index</hi> ſhall point you out in the <hi>Limbe</hi> neere 68. gr. of <hi>Azimuth</hi> for that <hi>houre,</hi> which at 9. of the Clocke the tenth of <hi>December,</hi> was but 40. gr. &amp; an halfe, ſo the difference of <hi>Azimuth</hi> in one and the ſame <hi>houre,</hi> ſhall be 27. gr. and a halfe, &amp; the time as be<g ref="char:EOLhyphen"/>fore, an houre and a halfe: which differences are ſufficient to confirme the point.</p>
                  </div>
                  <div n="10" type="application">
                     <head>Tenthly, to finde the Quarter of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>36</label> the yeare, and day of the month, if it were forgotten.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>46</label> 
                        <hi>At</hi> any appearance of the <hi>Sun</hi> by the 27. <hi>Pro.</hi> take the <hi>Suns Altitude,</hi> then place the <hi>North</hi> and <hi>South</hi> edge of the <hi>Inſtrument</hi> unto the <hi>Meridian line</hi> formerly, drawne (if in the fore<g ref="char:EOLhyphen"/>noone) otherwiſe place the <hi>East,</hi> and <hi>West,</hi> edge of <hi>Instrument</hi> to the <hi>Meridian-line,</hi>
                        <pb n="65" facs="tcp:10089:45"/> and erect the prependicular at the end of the <hi>Index,</hi> then moove the <hi>Index</hi> to and fro untill the <hi>ſhadow</hi> of the prependicular fall by the ſide of the <hi>Index,</hi> ſo the parallel that meeteth with the degree of the <hi>Suns</hi> obſerued <hi>Altitude,</hi> in the edge of the <hi>Index,</hi> parallel in the <hi>Kalender</hi> that ſhall ſhew the day of the <hi>Month</hi> required.</p>
                     <p>
                        <hi>So</hi> if, <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> upon a certaine day in the yeare the <hi>ſuns Altitude</hi> were obſerved and found to be 36. gr. having placed the edge of the <hi>Inſtrument</hi> to the <hi>Meridian</hi> line, and rectified the <hi>Index,</hi> then move the <hi>Index,</hi> untill the ſhadow of the prependicular fall by the edge of the <hi>Inſtrument,</hi> let the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> reſt at this poſition, and account the former 36. gr. upon the <hi>Index,</hi> which degree meeteth with the houre in the <hi>Aequator,</hi> and alſo that in<g ref="char:EOLhyphen"/>terſecteth the <hi>Kalender,</hi> in the tenth of <hi>March,</hi> &amp; the thirteenth of <hi>September,</hi> but which of theſe dayes is the day of the <hi>Month,</hi> the next dayes obſeruation of the <hi>Sun</hi> upon the ſame houre will helpe you, for if the <hi>ſuns Altitude</hi> beſound to be greater then the day of the month inquired after it was the tenth of (<hi>March,</hi> becauſe the <hi>ſun</hi> from the tenth of <hi>December</hi> unto the eleventh of <hi>Iune,</hi> doth every day at one &amp; the ſame houre, aſcend,) but if the <hi>Suns Altitude</hi> be found to be leſſe then the former dayes obſervation ſpecified was, then the day required, was the thirteenth of <hi>September,</hi> becauſe that from the eleventh of <hi>Iune,</hi> unto the tenth of <hi>December,</hi> the ſuns <hi>Altitude</hi> every day doth ſenſibly diminiſh at one and the ſame houre.</p>
                     <pb n="66" facs="tcp:10089:46"/>
                     <p>
                        <note place="margin">☞</note>
                        <hi>But</hi> here is to be noted that if there be no <hi>Meridionall line,</hi> then the prependicular over the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>47</label> Center and the <hi>Axis</hi> of the <hi>Index</hi> being erected, place downe the backe of the <hi>Inſtrument</hi> upon an <hi>Horizontall</hi> plaine, and move the <hi>Inſtrument</hi> to and fro, untill the ſhadow of the <hi>Axis</hi> meete with the ſame houre below the <hi>Tropicke,</hi> amongſt the com<g ref="char:EOLhyphen"/>mon houres, that the ſhadow of the prependicular over the Center of the <hi>Inſtrument</hi> meeteth with on the face of the <hi>Inſtrument,</hi> for then the parallel that croſſeth or meeteth with the <hi>ſhadow</hi> of the prependicular, and the <hi>houre,</hi> will in the <hi>Kalender</hi> ſhew the day of the <hi>Month</hi> required, and ſo then the <hi>Meridian</hi> of the <hi>Inſtrument</hi> ſhall be in the <hi>Meridian</hi> of the world, and every point or degree in the <hi>Horizon</hi> of the <hi>Inſtrument,</hi> it ſhall point out his like, or oppoſite degree in the <hi>Ho<g ref="char:EOLhyphen"/>rizon</hi> of the world.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio, </seg>48</label> Or otherwiſe it may be done thus, take the Suns <hi>Altitude,</hi> then immediatly by ſome Watch, clock, or Sun-dyall, learne the <hi>houre</hi> of the day, and move the <hi>Index</hi> to and fro, untill the <hi>Suns Altitude</hi> in the <hi>Index,</hi> meete with the former houre, ſo the parallel that meeteth therewith, ſhall ſhew the day of the <hi>Month</hi> in the <hi>Kalender</hi> required, then having the day of the <hi>Month,</hi> you have the <hi>Quar<g ref="char:EOLhyphen"/>ter of the yeare,</hi> for from the tenth of <hi>March</hi> unto the eleventh of <hi>Iune,</hi> is the <hi>Spring quarter,</hi> from the eleventh of <hi>Iune,</hi> to the thirteenth of <hi>Septem<g ref="char:EOLhyphen"/>ber,</hi> is the <hi>Summer quarter,</hi> from the thirteenth of <hi>September,</hi> to the tenth of <hi>December</hi> is the <hi>Autum<g ref="char:EOLhyphen"/>muall
<pb n="67" facs="tcp:10089:46"/> quarter,</hi> and from the tenth of <hi>December,</hi> unto the tenth of <hi>March,</hi> is the <hi>Winter Quarter.</hi>
                     </p>
                  </div>
                  <div n="11" type="application">
                     <head>Eleuenthly, to finde the houre of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>37</label> the day, the Azimuth and Alti<g ref="char:EOLhyphen"/>tude of the Sun, with the Meridi<g ref="char:EOLhyphen"/>onall line without obſeruation, or ſight of the ſun, by knowing the proportion betweene the length of a ſhadow upon a Horizontal Plaine, and that which caſt the ſhadow.</head>
                     <p>
                        <hi>Firſt,</hi> let the thing that caſteth the <hi>ſhadow,</hi> or <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>59</label> ſomething equall in length unto it, be divided into ten equall parts, and each of thoſe parts ſub<g ref="char:EOLhyphen"/>dived into ten other equall parts, (which thing ſo divided ſhal repreſent a common <hi>ſcale,</hi>) then mea<g ref="char:EOLhyphen"/>ſure the ſhadow with the <hi>ſcale,</hi> and marke how often the <hi>ſhadow</hi> is longer then the <hi>ſcale,</hi> and the <hi>Decimall</hi> part if there be any, ſo have you the proportion betweene the <hi>ſhadow,</hi> and that which
<pb n="68" facs="tcp:10089:47"/> did caſt the <hi>ſhadow,</hi> and then is it reſolved accor- to the conuerſe of the fifteenth Pro.,</p>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> Admit ſome one: upon the 12. of <hi>February,</hi> or on the ninth of <hi>October,</hi> houlding <hi>a ſtaffe</hi> prepen<g ref="char:EOLhyphen"/>dicular as <hi>A B,</hi> or ſuppoſing it to be part of the Coyne of a <hi>Houſe,</hi> or edge of a <hi>Window</hi> or ſuch like ſhould caſt a <hi>ſhadow,</hi> as <hi>B, C,</hi> which being noted, or drawne and having divided the <hi>ſtaffe,</hi> or thing as before, and ſhould then meaſure the <hi>ſha<g ref="char:EOLhyphen"/>dow,</hi> as <hi>B, C,</hi> by the ſaid <hi>ſtaffe</hi> or <hi>ſcale,</hi> and finde it to be contained therein three times, and 6, parts or 6, decimals, the porportion of the <hi>Gnomon,</hi> or <hi>ſcale, A B,</hi> to the <hi>ſhadow B C,</hi> would be as 1 to 3. and 6/10.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtruc¦tio. </seg>50</label> Move therefore the <hi>Index</hi> to and fro, untill the edge of it meere with 3. and 6/10, in the line of <hi>ſhadowes;</hi> ſo have you the degree of the <hi>Suns Alti<g ref="char:EOLhyphen"/>tude</hi> at that inſtant in the <hi>Index,</hi> viz. 15. gr. and ½ then ſeeke out the parallel for the 12. of <hi>Fe<g ref="char:EOLhyphen"/>bruary,</hi> or the ninth of <hi>October</hi> (the day given) which is neere the tenth degree from the <hi>Aequa<g ref="char:EOLhyphen"/>tor South,</hi> move the <hi>Index,</hi> until the former 15. gr.
<pb n="69" facs="tcp:10089:47"/> and ½ in the <hi>Index,</hi> meeteth with the ſaid parallel for the day, ſo have you the <hi>houre</hi> belonging to that time, which will be neere 42 m, paſt 8. in the Morning, or 18. m, paſt 3 in the after noone, and the edge of the <hi>Index</hi> in the <hi>Limbe</hi> of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> ſheweth the <hi>ſuns Azimuth</hi> alſo at that in<g ref="char:EOLhyphen"/>ſtant, viz, neere 39. gr. 12. m, from the <hi>Eaſt</hi> to<g ref="char:EOLhyphen"/>ward the <hi>South.</hi>
                     </p>
                     <p>
                        <hi>Now for the Meridionall line,</hi> this may be done <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>51</label> at any time after, if the <hi>Azimuth</hi> be not forgotten: for if the Center of the <hi>Inſtrument</hi> be layed downe upon any part of the <hi>ſhadow B C,</hi> and ſo the <hi>In<g ref="char:EOLhyphen"/>ſtrument</hi> to be mooved upon his Center untill the ſaid <hi>ſhadow B C,</hi> formerly drawne, cut the edge of the <hi>Limbe,</hi> in the aforeſaid <hi>Azimuth</hi> of 39. gr. 30. m, then the <hi>Meridian</hi> of the <hi>Inſtrument</hi> ſhall be in the <hi>Meridian</hi> of the world, and if that <hi>ſhadow</hi> were from a <hi>Window,</hi> or <hi>Building,</hi> the poſi<g ref="char:EOLhyphen"/>tion of the <hi>Inſtrument,</hi> ſhall denote the <hi>poſition</hi> of the <hi>Window</hi> or <hi>Building.</hi>
                     </p>
                  </div>
                  <div n="12" type="application">
                     <head>Twelfthly, to finde the Declinati<g ref="char:EOLhyphen"/>on <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>38</label> of a Wall; by ſeeing the ſun beginning to ſhine thereon, or going from it.</head>
                     <p>
                        <hi>By</hi> the 27. <hi>Pro.</hi> take the height of the <hi>Sun,</hi> and <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>52</label> by the 28. <hi>Pro.</hi> finde the <hi>Suns Azimuth</hi> for the
<pb n="70" facs="tcp:10089:48"/> 
                        <hi>Altitude,</hi> ſo the <hi>Azimuth</hi> thus found ſhall be the declination of the <hi>Plaine</hi> required: for the decli<g ref="char:EOLhyphen"/>nation of any perpendicular <hi>Plaine,</hi> is accounted from the points of <hi>Eaſt, Weſt, North</hi> or <hi>South,</hi> in the <hi>Horizon,</hi> as the <hi>Suns Azimuth</hi> is: therefore whatſoever <hi>Plaine</hi> is in the plaine of any <hi>virticall Circle,</hi> that Plaine is as far from any of the Cardinal points of the <hi>Horizon,</hi> as the <hi>ſun</hi> is at that time, &amp; ſo the <hi>Sun,</hi> being in that <hi>virticall Circle,</hi> ſhall ne<g ref="char:EOLhyphen"/>ceſſarily glance upon the <hi>Plaine:</hi> and therefore looke what the <hi>Suns Azimuth</hi> is at that inſtant, ſuch ſhall be the <hi>Declination</hi> of the <hi>Plaine</hi> re<g ref="char:EOLhyphen"/>quired.</p>
                  </div>
                  <div n="13" type="application">
                     <pb n="71" facs="tcp:10089:48"/>
                     <head>Thirteenthly, to finde the Decli<g ref="char:EOLhyphen"/>nation <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>39</label> of a Plaine, upon any appearance of the Sunne.</head>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                     <p>Thus for the Conſtruction of the aforeſaid 13. uſes which did depend upon the <hi>ſuns obſervation,</hi> the 48. 49. 50. 9. 13. 14. and 15<hi rend="sup">th</hi>. uſes of the <hi>Index</hi> or <hi>Table</hi> againſt Page the firſt, ſhould have follow<g ref="char:EOLhyphen"/>ed; but before I ſpeake of them it will not be in<g ref="char:EOLhyphen"/>convenient
<pb n="73" facs="tcp:10089:49"/> that I apply the <hi>Inſtrument</hi> unto the re<g ref="char:EOLhyphen"/>ſolution of the 44. 45. 46. &amp; 47. uſes of the afore<g ref="char:EOLhyphen"/>ſaid <hi>Index</hi> or <hi>Table,</hi> which have reference to night obſervation, upon ſuch <hi>Starres</hi> which are, or may be placed on the face of the <hi>Instrument,</hi> betweene the two <hi>Tropickes,</hi> or under the <hi>Tropicke of Cancer,</hi> according to there <hi>Declinations,</hi> and <hi>right Aſcenti<g ref="char:EOLhyphen"/>ons:</hi> which are theſe following.</p>
                     <p>
                        <table>
                           <row>
                              <cell role="label" rows="2">
                                 <hi>The names of the Stars</hi>
                              </cell>
                              <cell role="label">
                                 <hi>Decli.</hi>
                              </cell>
                              <cell role="label" cols="2">
                                 <hi>Rec:</hi>
                              </cell>
                              <cell role="label" rows="2">
                                 <hi>The names of the ſtars</hi>
                              </cell>
                              <cell role="label">
                                 <hi>Decli.</hi>
                              </cell>
                              <cell role="label" cols="2">
                                 <hi>Rec.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell role="label">
                                 <hi>G. M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>H. M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>G.M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>G.M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>H.M</hi>
                              </cell>
                              <cell role="label">
                                 <hi>G. M.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Ex. Alae Pegaſi</hi>
                              </cell>
                              <cell>13.9. <hi>N.</hi>
                              </cell>
                              <cell>23.54.</cell>
                              <cell>1. 30.</cell>
                              <cell>
                                 <hi>Co<gap reason="illegible" resp="#PDCC" extent="1 letter">
                                       <desc>•</desc>
                                    </gap> Hydrae.</hi>
                              </cell>
                              <cell>7.5. <hi>A</hi>
                              </cell>
                              <cell>9. 10.</cell>
                              <cell>42.45.</cell>
                           </row>
                           <row>
                              <cell>pri. ♈.</cell>
                              <cell>
                                 <gap reason="illegible" resp="#PDCC" extent="1 letter">
                                    <desc>•</desc>
                                 </gap>1.40. <hi>N.</hi>
                              </cell>
                              <cell>1.46.</cell>
                              <cell>26. 30.</cell>
                              <cell>
                                 <hi>Cor Leonis.</hi>
                              </cell>
                              <cell>13.45. <hi>B.</hi>
                              </cell>
                              <cell>9. 48.</cell>
                              <cell>33.00.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Oculus.</hi> ♉.</cell>
                              <cell>15.42. <hi>N.</hi>
                              </cell>
                              <cell>4.15.</cell>
                              <cell>63.45.</cell>
                              <cell>
                                 <hi>Cauda</hi> ♌.</cell>
                              <cell>16.38. <hi>B</hi>
                              </cell>
                              <cell>11.30</cell>
                              <cell>7.26.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>pri ſinguli. Ori.</hi>
                              </cell>
                              <cell>0. 17. <hi>S.</hi>
                              </cell>
                              <cell>5. 13.</cell>
                              <cell>78.15.</cell>
                              <cell>
                                 <hi>Spica.</hi> ♍.</cell>
                              <cell>9. <gap reason="illegible" resp="#PDCC" extent="1 letter">
                                    <desc>•</desc>
                                 </gap>0. <hi>M.</hi>
                              </cell>
                              <cell>13. 5.</cell>
                              <cell>16.15.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Canis maior.</hi>
                              </cell>
                              <cell>16.1<gap reason="illegible" resp="#PDCC" extent="1 letter">
                                    <desc>•</desc>
                                 </gap> 
                                 <hi>S.</hi>
                              </cell>
                              <cell>6. 30.</cell>
                              <cell>82.15.</cell>
                              <cell>
                                 <hi>Arcturus.</hi>
                              </cell>
                              <cell>21.10. <hi>B.</hi>
                              </cell>
                              <cell>14. 0.</cell>
                              <cell>29. 30.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Canis minor.</hi>
                              </cell>
                              <cell>6. 9. <hi>N.</hi>
                              </cell>
                              <cell>7.20.</cell>
                              <cell>70.00.</cell>
                              <cell>
                                 <hi>Aquila.</hi>
                              </cell>
                              <cell>8. 00. <hi>S.</hi>
                              </cell>
                              <cell>19.32</cell>
                              <cell>66.45.</cell>
                           </row>
                        </table>
                     </p>
                  </div>
               </div>
               <div type="section">
                  <p>Much may be ſaid upon the uſes of theſe <hi>starres,</hi> but for brevitie I onely delivere theſe foure ex<g ref="char:EOLhyphen"/>amples following.</p>
                  <p n="1">1. <hi>First,</hi> for any night of the <hi>yeare,</hi> to find at what <hi>houre,</hi> and <hi>Altitude</hi> any of the ſaid <hi>starres</hi> will be in the <hi>Meridian,</hi> (that ſo they may be known.)</p>
                  <p n="2">2. <hi>To know</hi> at any day, at what <hi>houre</hi> any of theſe <hi>starres</hi> riſeth, or ſetteth, with their time of continuance above the <hi>Horizon,</hi> and in what part of the <hi>Hemiſpheare,</hi> they may be ſeene with their <hi>Azimuth,</hi> and <hi>Altitude</hi> at any houre.</p>
                  <p n="3">
                     <pb n="74" facs="tcp:10089:50"/>3. <hi>Thirdly,</hi> to finde in any night at what part of the <hi>Horizon,</hi> any of the aforeſaid <hi>starres</hi> riſeth, or ſetteth, and at what <hi>houre,</hi> and <hi>Altitude</hi> they will be due <hi>East,</hi> or <hi>Weſt.</hi>
                  </p>
                  <p n="4">4. <hi>Fourthly,</hi> upon the ſight or apparance of any of the ſaid <hi>Starres,</hi> to finde the <hi>Azimuth</hi> thereof: and the <hi>houre of the night.</hi>
                  </p>
                  <div n="1" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>40</label> Firſt in any night, to finde at what houre and Altitude, any of the aforeſaid ſtarres will be in the Meridian.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>54</label> 
                        <hi>By</hi> the ſixth <hi>Pro:</hi> finde the <hi>Suns</hi> rigth <hi>Aſcention</hi> for the day given, which conuerted into time by allowing for every 15. degrees an <hi>houre,</hi> and for every <hi>degree</hi> 4. m, then ſubſtract this <hi>right Aſcen<g ref="char:EOLhyphen"/>tion</hi> of the <hi>Sun,</hi> from the <hi>starres right Aſcention,</hi> ſo the remainder or difference of time, ſhall ſhew how many <hi>houres</hi> the <hi>ſtarres</hi> ſhall come later to the <hi>Meridian</hi> then the <hi>Sun:</hi> but if the ſubtracti<g ref="char:EOLhyphen"/>on cannot be made, then adde 24. houres to it &amp; you have the <hi>Anſwere,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> 
                        <hi>ſo,</hi> if upon the ſixth of <hi>Fe<g ref="char:EOLhyphen"/>bruary,</hi> it were required to find at what <hi>houre</hi> any of the aforeſaid <hi>starres</hi> will be in the <hi>Meridian,</hi> or due <hi>South,</hi> firſt therefore by the ſaid ſixth <hi>Pro.</hi> I find the <hi>ſuns right Aſcention</hi> for the day given viz, 330. gr. which containes three nineties or
<pb n="75" facs="tcp:10089:50"/> 270. each 90. gr. being ſix <hi>houres,</hi> and ſo the whole 270. gr. makes 18. <hi>houres,</hi> and the other 60. gr. at 15. gr. to an <hi>houre</hi> makes 4. <hi>houres</hi> more all which put together makes 22. <hi>houres:</hi> ſo the <hi>right Aſcention</hi> of the <hi>Sun</hi> the ſixth of <hi>February,</hi> is neere 330. gr. as before, or 22. <hi>houres</hi>
                     </p>
                     <p>
                        <table>
                           <row>
                              <cell> </cell>
                              <cell> </cell>
                              <cell role="label">H. M.</cell>
                              <cell> </cell>
                              <cell role="label">H. M.</cell>
                              <cell> </cell>
                           </row>
                           <row>
                              <cell rows="12">Which 22. houres ta<g ref="char:EOLhyphen"/>ken from the right aſ<g ref="char:EOLhyphen"/>cention of the afore<g ref="char:EOLhyphen"/>ſaid Stars, viz. from.</cell>
                              <cell>
                                 <hi>Ex. Ala Pegaſi.</hi>
                              </cell>
                              <cell>23.54.</cell>
                              <cell rows="12">there re<g ref="char:EOLhyphen"/>maines.</cell>
                              <cell>1. 54. P.</cell>
                              <cell rows="12">the time of the ſtarres being in the <hi>Meridian.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Pri.</hi> ♈.</cell>
                              <cell>1. 46.</cell>
                              <cell>3. 46. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Oculus.</hi> ♉.</cell>
                              <cell>4. 15.</cell>
                              <cell>6. 15. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Orion ſingu.</hi> 1.</cell>
                              <cell>5. 13.</cell>
                              <cell>7. 13. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Canis Maior</hi>
                              </cell>
                              <cell>6. 30.</cell>
                              <cell>8. 30. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Canis Minor.</hi>
                              </cell>
                              <cell>7. 20.</cell>
                              <cell>9. 20. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cor Hidra.</hi>
                              </cell>
                              <cell>9. 10.</cell>
                              <cell>11. 10. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cor Leonis.</hi>
                              </cell>
                              <cell>9. 48.</cell>
                              <cell>11. 48. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cauda.</hi> ♌.</cell>
                              <cell>11.40.</cell>
                              <cell>1. 40. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Spica verginis.</hi>
                              </cell>
                              <cell>13.05.</cell>
                              <cell>2. 05. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Arcturus</hi>
                              </cell>
                              <cell>14.00.</cell>
                              <cell>4. 00. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Aquila.</hi>
                              </cell>
                              <cell>19.32.</cell>
                              <cell>9. 32. A.</cell>
                           </row>
                        </table>
                     </p>
                     <p>
                        <hi>For</hi> ſeeing that 22. <hi>houres</hi> the <hi>Sunnes right Aſcention,</hi> is greater then the <hi>right Aſcention</hi> of any of the <hi>starres</hi> afore ſpecified, ſubſtract this 22, <hi>houres</hi> from 24. <hi>houres,</hi> reſt 2. <hi>houres,</hi> which added to the <hi>right Aſcention</hi> of each <hi>Starre</hi> before delivered, you have the <hi>houre</hi> of the <hi>Stars</hi> coming to the <hi>Meridian:</hi> hence you may gather which of thoſe <hi>starres,</hi> are out of obſervation for that time, viz. <hi>Alae Pegaſi, Pri.</hi> ♈, and <hi>Aquila,</hi> which come to the <hi>Meridian</hi> in the day time: but if the day given had been the 26<hi rend="sup">th</hi> of <hi>Iuly,</hi> the <hi>right Aſ<g ref="char:EOLhyphen"/>cention</hi> of the <hi>Sunne,</hi> that day is neere 135. gr. or 9. <hi>houres.</hi>
                     </p>
                     <pb n="76" facs="tcp:10089:51"/>
                     <p>
                        <table>
                           <row>
                              <cell> </cell>
                              <cell> </cell>
                              <cell role="label">H.M.</cell>
                              <cell> </cell>
                              <cell role="label">H.M.</cell>
                              <cell> </cell>
                           </row>
                           <row>
                              <cell rows="12">which 9. houres ta<g ref="char:EOLhyphen"/>ken from the right Aſcention of the a<g ref="char:EOLhyphen"/>foreſaid ſtarrs viz, from.</cell>
                              <cell>
                                 <hi>Ex. Alae Pegaſi.</hi>
                              </cell>
                              <cell>23. 54.</cell>
                              <cell rows="12">leaves.</cell>
                              <cell>2. 54. A.</cell>
                              <cell rows="12">the time of the ſtars co<g ref="char:cmbAbbrStroke">̄</g>
                                 <g ref="char:EOLhyphen"/>ming to the <hi>Meridian.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Pri.</hi> ♈.</cell>
                              <cell>1. 46.</cell>
                              <cell>04.46. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Oculus</hi> ♉.</cell>
                              <cell>4. 15.</cell>
                              <cell>07. 15. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Orion Singu.</hi>
                              </cell>
                              <cell>1. 5. 31.</cell>
                              <cell>08. 13. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Caenis Maior.</hi>
                              </cell>
                              <cell>6. 30.</cell>
                              <cell>09.30. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Canis Minor.</hi>
                              </cell>
                              <cell>7. 20.</cell>
                              <cell>10. 20. A.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cor hidra.</hi>
                              </cell>
                              <cell>9. 10.</cell>
                              <cell>00.10. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cor Leonis.</hi>
                              </cell>
                              <cell>9. 48.</cell>
                              <cell>00.48. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Cauda.</hi> ♌.</cell>
                              <cell>11. 40.</cell>
                              <cell>02.40. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Spica vergenis.</hi>
                              </cell>
                              <cell>13.5.</cell>
                              <cell>04. 05. P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Acturus.</hi>
                              </cell>
                              <cell>14. 00.</cell>
                              <cell>05.<gap reason="illegible" resp="#PDCC" extent="1 letter">
                                    <desc>•</desc>
                                 </gap>0 P.</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Aquila.</hi>
                              </cell>
                              <cell>19.32.</cell>
                              <cell>10.32. P</cell>
                           </row>
                        </table>
                     </p>
                     <p>
                        <hi>For the right Aſcention</hi> of the <hi>Sun</hi> being but 9. <hi>houres</hi> take it from the <hi>right aſcention</hi> of <hi>Cor. hidra</hi> which is 9. <hi>houres</hi> 10. m, reſt 10. m, which ſhew<g ref="char:EOLhyphen"/>eth that <hi>Cor. Hydra</hi> comes to the <hi>Meridian</hi> 10. m, later then the <hi>Sun</hi> that day, that is, 10. m, after 12 and ſo the reſt, whoſe <hi>rightaſcention</hi> is greater then the <hi>Suns.</hi> But for theſe <hi>ſtarres,</hi> whoſe <hi>right Aſcention</hi> is leſſe then the ſaid 9. <hi>houres,</hi> ſubtract this 9 <hi>houre</hi> from 24. <hi>houres,</hi> reſt 15. <hi>houre</hi> (or ra<g ref="char:EOLhyphen"/>ther ſubtract it from 12. reſt 3. <hi>houres</hi>) this adde unto the <hi>right aſcention</hi> of any of the aforeſaid ſtarres, as ſuppoſe <hi>Canis Minor</hi> makes 22. <hi>houres</hi> 20. m, which ſheweth that <hi>Canis minor,</hi> wil come to the <hi>Meridian.</hi> 22. <hi>houres</hi> 20, m, later that day then the <hi>ſun:</hi> therefore this, 22. <hi>houres</hi> and 20. m, being conſidered according to an hour<g ref="char:EOLhyphen"/>ly account ſheweth, that <hi>Canis Minor</hi> will come to the <hi>Meridian</hi> at 10. of the <hi>clocke</hi> and 20. m: of the next day (the <hi>right aſcention</hi> of the Internall of
<pb n="77" facs="tcp:10089:51"/> time being neglected) or for brevitie adde the aforeſaid 3. <hi>houres</hi> unto the <hi>right aſcention</hi> of theſe <hi>Starres,</hi> whoſe <hi>right aſcentions</hi> are leſſer then the <hi>Suns,</hi> ſo have you the <hi>Meridionall houre</hi> re<g ref="char:EOLhyphen"/>quired.</p>
                     <p>Hence may be gathered that <hi>Alae Pegaſi, Pri.</hi> ♈ and <hi>Aquila,</hi> are onely for obſervation that night, the other <hi>ſtarres</hi> are out of obſervation, and will come to the <hi>Meridian,</hi> in the day time.</p>
                     <p>
                        <hi>Laſtly, to finde the Meridionall Altitude of any of theſe starres,</hi> lay the edge of the <hi>Index</hi> unto the <hi>houre line,</hi> of 12, ſo the parallel of the <hi>starres de<g ref="char:EOLhyphen"/>clination</hi> that croſſeth the edge of the <hi>Index,</hi> ſhall there ſhew you in the <hi>Index,</hi> the <hi>Meridionall Al<g ref="char:EOLhyphen"/>titude</hi> of the <hi>starre</hi> required.</p>
                  </div>
                  <div n="2" type="application">
                     <pb n="78" facs="tcp:10089:52"/>
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>41</label> Secondly, to know at any day, at what houre any of the ſtarres (in<g ref="char:EOLhyphen"/>ſcribed on the Inſtrument) ri<g ref="char:EOLhyphen"/>ſeth or ſetteth, with their time of continuance above the Horizon, &amp; in what part of the hemiſpheare, they may be ſeene, with their Azimuth, and Alti<g ref="char:EOLhyphen"/>tude at any houre.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>55</label> 
                        <hi>By</hi> the laſt direction finde the <hi>houre</hi> of the <hi>stars</hi> being in the <hi>Meridian,</hi> then marke what houre the parallel of the <hi>declination</hi> of any <hi>starre</hi> inter<g ref="char:EOLhyphen"/>ſecteth the <hi>Horizon</hi> or <hi>Kalender,</hi> ſo have you the <hi>houre</hi> or time of the <hi>starres riſing</hi> or <hi>ſetting,</hi> and the number of <hi>houres,</hi> from that point of the <hi>stars riſing</hi> in the <hi>Horizon,</hi> unto the <hi>Meridian</hi> being doubled, gives the countinuance of the <hi>starres</hi> a<g ref="char:EOLhyphen"/>bove the <hi>Horizon,</hi> required.</p>
                     <p>
                        <hi>So</hi> if upon the 6<hi rend="sup">th</hi>. of <hi>February,</hi> it were de<g ref="char:EOLhyphen"/>manded at what <hi>houre Oculus</hi> ♉. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> would aſcend, &amp; how long it would continue above the <hi>Horizon.
<pb n="79" facs="tcp:10089:52"/> By</hi> the laſt propoſition, get the <hi>houre</hi> of the <hi>starres</hi> being in the <hi>Meridian,</hi> which is at 6. of the Clocke and 15. minuts at night, and marke the Number of <hi>houres</hi> betweene the <hi>Meridian,</hi> and that point where the parallel of <hi>Oculus</hi> ♉, meeteth with the <hi>Kalender,</hi> which is 7. <hi>houres</hi> 24, minuts, this doubled makes 14. <hi>houres</hi> 48. m, and ſo long will <hi>Oculus</hi> ♉, be above the <hi>Horizon.</hi>
                     </p>
                     <p>
                        <hi>But</hi> if from the ſaid 7, houres and 24. m, the ſaid 6, houres 15. m, be taken, there will reſt 1. houre 9. m, and ſo much before 12. of the clocke at noone, doth <hi>Oculus</hi> ♉ riſe, that is 51. m, after 10, of the Clocke, and ſo conſequently if the ſaid 7. <hi>houres</hi> and 24. m, be added unto the houre of the <hi>starres</hi> being in the <hi>Meridian,</hi> viz. 6. of the Clocke and 15. m, as before, the ſaid <hi>starre</hi> will ſet at 39. m, paſt 1, in the <hi>Morning.</hi>
                     </p>
                     <p>Laſtly, if at any <hi>houre</hi> betweene the <hi>riſing</hi> of the <hi>starre,</hi> and the <hi>ſetting</hi> thereof, it be required at what <hi>Poſition</hi> and <hi>Altitude</hi> the <hi>ſtarre</hi> is in. It is thus done.</p>
                     <p>
                        <hi>Account</hi> to the given <hi>houre,</hi> from the <hi>houre</hi> of the <hi>ſtarre riſing, ſetting,</hi> or being in the <hi>Meridian,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>56</label> (in the parallel of the ſtarres declination) and lay the <hi>Index</hi> thereto, ſo the edge of it in the <hi>Limbe</hi> of the <hi>Inſtrument,</hi> ſhall ſhew the <hi>ſtarres Azimuth</hi> or <hi>Poſition,</hi> and where the parallel of the ſtarres <hi>Declination</hi> croſſeth the edge of the <hi>Index,</hi> that ſhall be the <hi>ſtarres Altitude,</hi> at that <hi>houre.</hi>
                     </p>
                     <p>
                        <hi>So</hi> if on the ſaid 6<hi rend="sup">th</hi>. of <hi>February,</hi> at 11. <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> of the <hi>Clocke</hi> at night, it were required in what <hi>Poſiti<g ref="char:EOLhyphen"/>on,</hi>
                        <pb n="80" facs="tcp:10089:53"/> or <hi>Azimuth Oculus</hi> ♉, was in, and alſo how high above the <hi>Horizon:</hi> I make, or ſuppoſe the <hi>houre</hi> of 12. to be the aforeſaid 6. of the Clocke and 15. m, (for at that <hi>houre</hi> as before <hi>Oculus</hi> ♉ was in the <hi>Mridian</hi>) and from thence in the <hi>ſtars</hi> parallel of <hi>Declination,</hi> I account untill I come unto 11. of the <hi>Clocke,</hi> viz. that is 4. <hi>houres,</hi> and 45. m, from 12. and lay the <hi>Index</hi> thereto, ſo the edge of the <hi>Index</hi> in the <hi>Limbe,</hi> pointeth out 4. gr: 24. m, and ſo farre <hi>Oculus</hi> ♉, is diſtant from the <hi>Weſt</hi> at 11. of the <hi>Clocke</hi> at night, and the parallel of the <hi>starres Declination</hi> meeteth with the <hi>Index</hi> in 24. gr, neere, which is the ſtarres <hi>Altitude,</hi> at that <hi>houre</hi> required.</p>
                  </div>
                  <div n="3" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>42</label> Thirdly, to find in any night of the yeare, in what part of the Horizon any of the ſtarres on the inſtru<g ref="char:EOLhyphen"/>ment riſeth or ſetteth, and at what houre, and Alti<g ref="char:EOLhyphen"/>tude a ſtarre will be due Eaſt, or Weſt.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>57</label> 
                        <hi>For the firſt, Marke</hi> where the parallel of the <hi>ſtarres declination</hi> croſſeth the <hi>Horizon,</hi> or <hi>Kalen<g ref="char:EOLhyphen"/>der,</hi> Lay the edge of the <hi>Index</hi> hereto, ſo the
<pb n="81" facs="tcp:10089:53"/> number of degrees betweene the edge of the <hi>In<g ref="char:EOLhyphen"/>dex,</hi> and the point of <hi>Eaſt</hi> or <hi>Weſt,</hi> upon the <hi>limbe</hi> of the <hi>Inſtrument,</hi> ſheweth the diſtance of the <hi>ſtarres riſing</hi> from the <hi>East</hi> or <hi>Weſt.</hi>
                     </p>
                     <p>
                        <hi>So</hi> if it were required in what part of the <hi>Ho<g ref="char:EOLhyphen"/>rizon Oculus</hi> ♉ riſeth, <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> marke where the parallel of the <hi>ſtars Declination</hi> croſſeth the <hi>Horizon,</hi> and lay the edge of the <hi>Index</hi> thereto, ſo it cutteth the <hi>Limbe</hi> of the <hi>Inſtrument</hi> from the <hi>Eaſt</hi> neere 26. gr. and ſo farre <hi>Oculus</hi> ♉, riſeth from the <hi>East</hi> towards the <hi>North.</hi>
                     </p>
                     <p>
                        <hi>For the ſecond to finde the time of a starres coming Eaſt, or weſt.</hi>
                     </p>
                     <p>
                        <hi>By</hi> the 40<hi rend="sup">th</hi>. <hi>Pro.</hi> conſider at what houre the <hi>star</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>58</label> is in the <hi>Meridian,</hi> then lay the edge of the <hi>Index</hi> to the point of <hi>Eaſt</hi> and <hi>West,</hi> and account in the parallel of the <hi>ſtars Declination</hi> the number of <hi>houres</hi> betweene the edge of the <hi>Index,</hi> and the <hi>houre</hi> of 12. which being taken from the <hi>houre</hi> of the <hi>stars</hi> being in the <hi>Meridian,</hi> gives the <hi>houre</hi> of the <hi>ſtars</hi> coming <hi>East,</hi> but added unto the <hi>houre</hi> of the <hi>ſtars</hi> being in the <hi>Meridian,</hi> ſhewes the <hi>houre</hi> of the <hi>ſtars</hi> being <hi>West.</hi>
                     </p>
                     <p>
                        <hi>So</hi> if it were demaunded at what <hi>houre,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> upon the 6<hi rend="sup">th</hi>. of <hi>February,</hi> Cor ♌, would be due <hi>Eaſt</hi> or <hi>Weſt,</hi> and what <hi>Altitude</hi> the ſtarre ſhould then have. Firſt, lay the edge of the <hi>Index,</hi> to the point of <hi>Eaſt</hi> and <hi>West,</hi> &amp; whereſoever the parallel of the ſtarres <hi>declination</hi> croſſeth the edge of the <hi>Index</hi> that ſhall be the ſtarres <hi>Altitude,</hi> viz. neere 17. gr 45. m, then account the number of <hi>houres</hi>
                        <pb n="82" facs="tcp:10089:54"/> in the parallel of the ſtarres <hi>Declination</hi> betweene the edge of the <hi>Index,</hi> and the <hi>houre</hi> of 12. which is neere 5. <hi>houres</hi> and 12. m, which taken from the <hi>houre</hi> of the ſtarres being in the <hi>Meridian,</hi>) which by the 40<hi rend="sup">th</hi>. Pro. was at 11. of the <hi>clocke</hi> &amp; 48. m, at night) reſts 6 <hi>houres,</hi> and 36. m: but if the ſaid 5. <hi>houres</hi> and 12. m, be added unto the ſaid 11. <hi>houres</hi> and 48. m, it makes 17. <hi>houres,</hi> from which 12. being taken leaves 5, <hi>houres.</hi> So upon the 6<hi rend="sup">th</hi>. of <hi>February,</hi> Cor ♌ ſhall be due <hi>Eaſt,</hi> at 36. m, paſt 6, at night, and due <hi>Weſt,</hi> at 5, of the Clocke in the Morning, and the <hi>Stars Altitude,</hi> being either <hi>Eaſt</hi> or <hi>West,</hi> is neere 17. gr. 45. m, as was re<g ref="char:EOLhyphen"/>quired.</p>
                  </div>
                  <div n="4" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>43</label> Fourthly, upon the ſight or appea<g ref="char:EOLhyphen"/>rance of any of the aforeſaid ſtars, to finde the Azimuth there<g ref="char:EOLhyphen"/>of, and the houre of the night.</head>
                     <p>
                        <hi>By</hi> the 40<hi rend="sup">th</hi>. Pro. for the day given finde the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>59</label> 
                        <hi>houre</hi> of the <hi>starres</hi> coming to the <hi>Merid<gap reason="illegible" resp="#PDCC" extent="2 letters">
                              <desc>••</desc>
                           </gap>
                        </hi> then by the 27. Pro. take the <hi>starres</hi> heigh<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap> 
                        <gap reason="illegible" resp="#PDCC" extent="1 word">
                           <desc>〈◊〉</desc>
                        </gap> account that height in the <hi>Index,</hi> the<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap> 
                        <gap reason="illegible" resp="#PDCC" extent="1 span">
                           <desc>〈…〉</desc>
                        </gap> 
                        <hi>Index</hi> untill the degree of the <hi>ſtarre<gap reason="illegible" resp="#PDCC" extent="1 letter">
                              <desc>•</desc>
                           </gap>
                        </hi> 
                        <gap reason="illegible" resp="#PDCC" extent="1 span">
                           <desc>〈…〉</desc>
                        </gap> the <hi>Index,</hi> meete with the parall<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap> 
                        <gap reason="illegible" resp="#PDCC" extent="1 span">
                           <desc>〈…〉</desc>
                        </gap> 
                        <hi>Declination,</hi> ſo the edge of the <gap reason="illegible" resp="#PDCC" extent="1 span">
                           <desc>〈…〉</desc>
                        </gap>
                        <pb n="83" facs="tcp:10089:54"/> ſheweth the ſtarres <hi>Azimuth,</hi> and the <hi>Meridian</hi> that meeteth with the degree of the <hi>Altitude,</hi> in the <hi>Index</hi> ſhall ſhew you the <hi>houre</hi> that the <hi>ſtarre</hi> wants to be in the <hi>Meridian,</hi> or is paſt the <hi>Meri<g ref="char:EOLhyphen"/>dian,</hi> which added, or ſubtracted from the <hi>houre</hi> of the <hi>ſtarres</hi> being in the <hi>Meridian,</hi> gives the <hi>houre</hi> of the night required.</p>
                     <p>
                        <hi>So</hi> if the day were the 26<hi rend="sup">th</hi>. of <hi>Iuly,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> and if <hi>Aquila,</hi> ſhould be obſerved to be on the <hi>Weſt</hi> of the <hi>Meridian,</hi> 29. gr. 20. m, high above the <hi>Hori<g ref="char:EOLhyphen"/>zon,</hi> this I ſeeke out upon the <hi>Index,</hi> and move the <hi>Index</hi> to and fro untill the ſaid, 29. gr. 20. m, meete with the parallel of <hi>Declination,</hi> of <hi>Aquila,</hi> ſo the edge of the <hi>Index,</hi> in the <hi>Limbe</hi> doth point out the <hi>ſtarres Azimuth</hi> from the <hi>South,</hi> viz. 63. gr. 12. m, and the <hi>Meridian</hi> that meeteth with the aforeſaid degree of <hi>Altitude,</hi> is the time of the <hi>ſtarres</hi> diſtance from the <hi>Meridian,</hi> viz. neere 3. <hi>houres</hi> and 28. m, this added unto the <hi>houre</hi> of <hi>Aquilas</hi> being in the <hi>Meridian,</hi> which by the 40<hi rend="sup">th</hi>. Pro. was at 10. of the Clocke &amp; 32. m, at night, makes 14. <hi>houres,</hi> or 2 of the <hi>Clocke,</hi> in the <hi>Morning,</hi> ſo if <hi>Aquila</hi> were obſerved the 26<hi rend="sup">th</hi>. of <hi>Iuly,</hi> to be 29. gr. 20. m, <hi>high</hi> to the <hi>Weſt</hi> of the <hi>Meridian,</hi> then the <hi>Poſition</hi> or <hi>Azimuth</hi> of that <hi>ſtarre</hi> from the <hi>Meridian,</hi> was 63. gr. 12. m, and the <hi>houre</hi> at that inſtant, was at 2. of the Clocke in the Morning.</p>
                  </div>
               </div>
               <div type="section">
                  <pb n="84" facs="tcp:10089:55"/>
                  <p>
                     <hi>Thus</hi> touching the reſolution of the aforeſaid 44. 45. 46. and 47<hi rend="sup">th</hi>. <hi>Pro.</hi> of the aforeſaid <hi>Index</hi> or <hi>Table,</hi> which did belong to <hi>Aſtronomicall</hi> ob<g ref="char:EOLhyphen"/>ſeruations, the laſt uſes now follow, viz. 48. 49. 50. 9. 13. 14. and 15<hi rend="sup">th</hi>. uſes of the <hi>Index</hi> or <hi>Table,</hi> which are onely proper to <hi>Geometricall Practices,</hi> viz.
<list>
                        <head>to ſhew</head>
                        <item>1. <hi>How to meaſure the Quantitie of an Angle, or to take the diſtance of two Starres.</hi>
                        </item>
                        <item>2. <hi>How to meaſure diſtances and bredthes.</hi>
                        </item>
                        <item>3. <hi>How to take the Circuit of a figure, or the ſurueigh of a Place.</hi>
                        </item>
                        <item>4. <hi>The inclination of a Plaine, or to Place a Plaine Horizontall.</hi>
                        </item>
                        <item>5. <hi>Whether an Altitude be in the Point of libration, or above, or below the levell of the eye, and how much.</hi>
                        </item>
                        <item>6. <hi>How much the hight of an Altitude is above the eye, which is acceſſable, or in acceſſable.</hi>
                        </item>
                        <item>7. <hi>How to meaſure any Part of an Altitude, which is not approachable.</hi>
                        </item>
                     </list>
                  </p>
                  <div n="1" type="application">
                     <pb n="85" facs="tcp:10089:55"/>
                     <head>Firſt, how to obſerue or finde the <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>44</label> meaſure of an Angle, or take the diſtance of two ſtarres by the Inſtrument.</head>
                     <p>
                        <hi>Let</hi> the <hi>Iſtrument</hi> be placed upon ſome <hi>Rest,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>60</label> which may be ſo accommodated that the <hi>Inſtru<g ref="char:EOLhyphen"/>ment,</hi> may be elevated, depreſſed, or be placed <hi>Horizontall,</hi> as occaſion requires, then erect the ſights of the <hi>Index,</hi> &amp; place the edge of the <hi>Index</hi> upon the houre line of 12. the <hi>Index</hi> ſo placed looke through the <hi>ſights</hi> thereof and moving the <hi>Inſtrument</hi> upon his <hi>Reſt</hi> to and fro, untill you ſee the marke or <hi>Starre,</hi> that makes the Angle or diſtance required. Then ſcrew faſt the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> to the ſocket, and move about the <hi>Index,</hi> untill through the <hi>ſights</hi> thereof you ſee the other marke or <hi>ſtar,</hi> ſo the number of degrees betweene the edge of the <hi>Index</hi> and the <hi>houre</hi> of 12. in the <hi>Limbe</hi> of the <hi>Inſtrument</hi> ſhall be the meaſure of y<hi rend="sup">e</hi> Angle, or diſtance of the <hi>two Stars</hi> ſought for.</p>
                     <p>
                        <hi>Let E</hi> and <hi>D</hi> be two markes or <hi>Starres,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> and let the Angle <hi>E A D,</hi> or diſtance <hi>E D,</hi> be required. The <hi>Inſtrument, A B M,</hi> being placed upon his <hi>Reſt G H I K,</hi> obſerue one of the markes or <hi>ſtarres</hi> as <hi>D,</hi> through the <hi>ſights</hi> (admit <hi>A B,</hi>) ſo the viſuall line ſhall be <hi>A B D,</hi> then having made faſt the
<pb n="86" facs="tcp:10089:56"/> 
                        <hi>Inſtrument,</hi> move the <hi>Index A B,</hi> untill through the <hi>ſights</hi> of it you ſee the other marke or <hi>ſtarre, E,</hi> which ſuppoſe to be in the viſuall line, <hi>A C E,</hi> ſo the Arke of the <hi>Limbe</hi> of the <hi>Inſtrument B C,</hi> ſhall be the diſtance betweene the two <hi>Stars, ED,</hi> or the meaſure of the Angle <hi>E A D,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Corolla∣rie. </seg>
                        </label> required. Now Infinit are the uſes of knowing the Quantitie of <hi>Angles,</hi> in the Copious and vaſt Body of <hi>Mathematicall</hi> Practices, therefore from the multitude of <hi>Examples</hi> that might be raiſed upon them, or extracted from them, I will onely inſtance for brevitie, upon theſe two plaine, and ordinary ones following.</p>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                  </div>
                  <div n="2" type="application">
                     <pb n="87" facs="tcp:10089:56"/>
                     <head>Secondly, how to meaſure diſtan<g ref="char:EOLhyphen"/>ces, <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>45</label> and Breadths.</head>
                     <p>
                        <hi>Let G F L H,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> repreſent part of the <hi>Perimeter</hi> of a <hi>Fort,</hi> and let it be required, that ſtanding at ſome convenient place without <hi>Musket</hi> ſhot, as admit at <hi>Y,</hi> the diſtance betweene the points of the <hi>Bulwarke</hi> viz. <hi>F</hi> &amp; <hi>L,</hi> as alſo the meaſure of the <hi>face</hi> of either of the <hi>Bulwarks</hi> viz. <hi>F E,</hi> or <hi>M L,</hi> with the length of the <hi>Cortaine D N,</hi> and all the diſtances from <hi>Y,</hi> viz. <hi>Y F, Y E, Y M,</hi> and <hi>Y L,</hi> were required.</p>
                     <p>
                        <hi>Or ſuppoſe O P Q R,</hi> were 4 places, whoſe ſe<g ref="char:EOLhyphen"/>verall <gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>iſtances the one from the other as from <hi>O</hi> to <hi>P,</hi> then from <hi>P</hi> to <hi>Q,</hi> and from <hi>Q</hi> to <hi>R,</hi> &amp; al<g ref="char:EOLhyphen"/>ſo the ſeveral diſtances from <hi>Y</hi> viz. <hi>Y O, Y P, Y Q</hi> and <hi>Y R,</hi> were demanded. The <hi>Conſtruction</hi> and reſolution upon either of theſe is alike, therefore <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>61</label> we will inſtance upon the latter.</p>
                     <p>
                        <hi>Place</hi> the <hi>Inſtrument</hi> upon his <hi>Reſt,</hi> at <hi>Y,</hi> and the edge of the <hi>Index,</hi> upon the <hi>houre</hi> of 12. then loo<g ref="char:EOLhyphen"/>king through the <hi>ſights</hi> of the <hi>Index,</hi> upon ſome marke taken at pleaſure in the field, which, admit to be <hi>S,</hi> then obſerve the firſt marke <hi>R,</hi> ſo have you the Angle <hi>S Y R,</hi> which ſuppoſe 52. gr. 30. m, then looke to <hi>Q,</hi> ſo have you the Angle <hi>SYQ,</hi> which let be 63. gr. 15. m. then looke to <hi>P,</hi> ſo ha<gap reason="illegible" resp="#PDCC" extent="1 letter">
                           <desc>•</desc>
                        </gap>e you the Angle <hi>SYP,</hi> admit to be 74. gr. 15. m, and laſtly looke to <hi>O,</hi> ſo have you the Angle
<pb n="88" facs="tcp:10089:57"/> 
                        <hi>S Y O,</hi> 123. gr. 15. m: for theſe Angles are taken with great facillitie, when once the <hi>Inſtrument</hi> is rectified as in the firſt direction is ſpecified, for you neede not but move the <hi>Index, Circular</hi> from obiect to obiect, ſo the Arkes of the <hi>Limbe</hi> of the <hi>Inſtrument</hi> as before, from the <hi>houre</hi> of 12, unto the edge of the <hi>Index,</hi> ſhall ſhew the meaſure of the ſeuerall Angles obſerved.</p>
                     <p>Thus at <hi>Y,</hi> place up a Marke, and in the viſuall line, <hi>Y S,</hi> and meaſure a certaine diſtance at pleaſure, as admit to <hi>S,</hi> and ſuppoſe it were found to be 900. foote (or 300. yardes) then placing the <hi>Inſtrument</hi> at <hi>S,</hi> upon his <hi>Reſt,</hi> and laying the edge of the <hi>Index</hi> to the <hi>houre</hi> of 12. I move the <hi>Inſtrument</hi> about, untill through the <hi>ſights</hi> of the <hi>Index</hi> I may ſee the marke which was ſet up at my, laſt <hi>station,</hi> then make faſt the <hi>Inſtrument,</hi> and obſerve <hi>O,</hi> ſo have you the Angle <hi>Y S O,</hi> which ſuppoſe to be 26. gr. 50. m, then looke to <hi>P,</hi> ſo have you the Angle <hi>Y S P,</hi> which let be 55. gr. 50. m, then looke to <hi>Q,</hi> ſo have you the Angle <hi>Y S Q,</hi> which admit to be 60. gr. 15. m, laſtly obſerve <hi>R,</hi> ſo have you the Angle <hi>Y S R,</hi> 87. gr. In like maner may you obſerve the Angles at the <hi>Fort</hi> from the ſtations <hi>Y,</hi> and <hi>S,</hi> formerly ſpecified all which <hi>obſervations</hi> may be placed downe in <hi>Tables,</hi> as here under appeares, which may be called the <hi>Tables</hi> of obſerved Angles.</p>
                     <pb facs="tcp:10089:57"/>
                     <figure>
                        <figDesc>mathematical diagrams</figDesc>
                     </figure>
                     <pb n="90" facs="tcp:10089:58"/>
                     <p>
                        <table>
                           <row>
                              <cell> </cell>
                              <cell role="label">
                                 <hi>Ang: G. M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>Diſtances</hi>
                              </cell>
                              <cell role="label">
                                 <hi>Ang: G.M.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>Diſtances.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell rows="8">
                                 <hi>Y. S.</hi> 900.</cell>
                              <cell>
                                 <hi>R Y S.</hi> 52. 30</cell>
                              <cell>
                                 <hi>S R.</hi> 1099. 5</cell>
                              <cell>
                                 <hi>S Y L.</hi> 55. 45.</cell>
                              <cell>
                                 <hi>S L.</hi> 1071. 0</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Q Y S.</hi> 63. 15</cell>
                              <cell>
                                 <hi>S Q.</hi> 963. 6</cell>
                              <cell>
                                 <hi>S Y M.</hi> 68. 15</cell>
                              <cell>
                                 <hi>S M.</hi> 1182. 2</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>P Y S.</hi> 74. 15</cell>
                              <cell>
                                 <hi>S P.</hi> 1132. 2</cell>
                              <cell>
                                 <hi>S Y E.</hi> 89. 10.</cell>
                              <cell>
                                 <hi>S E.</hi> 1364. 4</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>O Y S.</hi> 123. 50</cell>
                              <cell>
                                 <hi>S O.</hi> 1526. 1</cell>
                              <cell>
                                 <hi>S Y F.</hi> 104.00</cell>
                              <cell>
                                 <hi>S F.</hi> 1459. 5</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Y S O.</hi> 26. 50.</cell>
                              <cell>
                                 <hi>Y O.</hi> 829. 2</cell>
                              <cell>
                                 <hi>Y S F.</hi> 39. 15.</cell>
                              <cell>
                                 <hi>Y F.</hi> 971. 6</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Y S P.</hi> 55. 50.</cell>
                              <cell>
                                 <hi>Y P.</hi> 973. 2</cell>
                              <cell>
                                 <hi>Y S E.</hi> 49. 35.</cell>
                              <cell>
                                 <hi>Y E.</hi> 1039. 2</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Y S Q.</hi> 60. 15.</cell>
                              <cell>
                                 <hi>Y Q.</hi> 937. 0</cell>
                              <cell>
                                 <hi>Y S M.</hi> 66. 45.</cell>
                              <cell>
                                 <hi>Y M.</hi> 1169. 4</cell>
                           </row>
                           <row>
                              <cell>
                                 <hi>Y S R.</hi> 87. 00.</cell>
                              <cell>
                                 <hi>Y R.</hi> 1384.</cell>
                              <cell>
                                 <hi>Y S L.</hi> 79. 30.</cell>
                              <cell>
                                 <hi>Y L.</hi> 1268. 2</cell>
                           </row>
                        </table>
                     </p>
                     <p>
                        <hi>Now</hi> touching the reſolution of the point, there is a triple way of operation, viz. either <hi>Arithmeticall, Inſtrumentall,</hi> or <hi>Geometricall,</hi> each of which being ſufficiently facill, to ſuch which are verſed in the documents of <hi>Mathematicall Practices,</hi> but the later becauſe it is more vulgar, and eaſieſt to be apprehended, I will inſtance here upon: which is that part of <hi>Geometrie,</hi> common<g ref="char:EOLhyphen"/>ly called <hi>Pretraction,</hi> a thing ſo common that al<g ref="char:EOLhyphen"/>moſt every one that hath any entrance in <hi>Geome<g ref="char:EOLhyphen"/>trie,</hi> can performe it according to the ordinary way they are inſtructed in. But to facilitate that kind of practice, I aduiſe ſuch as affect this kinde of Practice to uſe the <hi>Protracter,</hi> which I uſe, which is a plaine then <hi>ſector,</hi> having a ſmal hole at the <hi>Center,</hi> whoſe two legges from the <hi>Center</hi> are made with a ſharpe edge, but ſo that they lie flat upon the <hi>Paper,</hi> &amp; each of them to be divided into 100 or 1000 diuiſions with a <hi>Quadrantall Arke</hi> or more divided and faſtned alſo at the end of one of the leggs, but ſo that the <hi>Quadrantall,
<pb n="91" facs="tcp:10089:58"/> Arke</hi> have alſo an edge to lie flat upon the <hi>Paper,</hi> and to ſlide in at the other leg, ſo ſhall it be ac<g ref="char:EOLhyphen"/>commodated and made a fit, &amp; apt <hi>Inſtrument</hi> to finde the <hi>Quantitie of Angles,</hi> in a <hi>Plot,</hi> or to pro<g ref="char:EOLhyphen"/>tract <hi>Angles,</hi> for ſervice, as followeth.</p>
                     <p>
                        <hi>So</hi> to ſearch out the diſtance of <hi>O P Q R,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> the one from the other, or all the diſtances from <hi>Y</hi> as was required: by the helpe of the former Angles of obſervations and <hi>Protracter,</hi> it may be done thus.</p>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                  </div>
                  <div n="3" type="application">
                     <head>Thirdly, how to take the Circuite <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>46</label> of a figure, or the ſurueigh of a Place.</head>
                     <p>
                        <hi>Let ABCD,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> be a plaine to be raiſed as <hi>Fortifiers</hi> have it, or a <hi>field</hi> to be ploted as <hi>ſurveyers</hi> account it, or a <hi>Figure</hi> whoſe <hi>Perimeter</hi> is required, as <hi>Geo<g ref="char:EOLhyphen"/>metritia<g ref="char:cmbAbbrStroke">̄</g>s</hi> treate of it. The <hi>Plaine Table,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Notatio. </seg>
                        </label> may be held beſt for this ſervice, as ſuch would have it, whoſe learning is altogether verſed therein. But any <hi>In<g ref="char:EOLhyphen"/>strument</hi> ſhall be able to doe this <hi>Service,</hi> that can but accuratly take or meaſure any Angle, (not
<pb n="94" facs="tcp:10089:60"/> that we reject that, but make uſe of this for the preſent) and therefore in this action, it were no loſſe of time to make a preambulation about the field, to view the ſeverall windings and turnings thereof, and what <hi>Angles</hi> with greateſt Conve<g ref="char:EOLhyphen"/>niency, and expedition are to be obſerved, and what might be omitted, and at the <hi>Angles</hi> of con<g ref="char:EOLhyphen"/>ſequence there to ſet up ſome marke, and upon thoſe <hi>Angles</hi> to fabricate the whole worke: for here eſpecially is to be noted, that the more <hi>Angles</hi> that are obſerued in any practiſe, by way of Circumſcribing a <hi>Field,</hi> or <hi>Campaigne,</hi> the greater, and more evident ſhall the error be in the Concluſion.</p>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                     <pb n="95" facs="tcp:10089:60"/>
                     <p>
                        <hi>So</hi> in the <hi>Figure A B C D,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Exam. </seg>
                        </label> there is eleven <hi>Angles</hi> and as many ſides, now if at every <hi>Angle,</hi> an obſervation ſhould be made, it would be more. ſubiect to error (as before) then if leſſe <hi>Angles</hi> were obſerved, therfore in this <hi>Diagramme</hi> fewer <hi>Angles</hi> of obſervation may be fully ſufficient to raiſe that <hi>Plaine,</hi> Take the <hi>Plot</hi> of the <hi>Field,</hi> or give the <hi>Perimeter</hi> of that <hi>Figure,</hi> Therefore ſup<g ref="char:EOLhyphen"/>poſe the noted <hi>Angles</hi> of Conſequence to be, <hi>A, B, C, D, Q,</hi> the worke may be then thus.</p>
                     <p>
                        <hi>Place</hi> the <hi>Inſtrument,</hi> upon his reſt at <hi>A,</hi> and obſerue the <hi>Angle Q AB,</hi> which ſuppoſe 32. gr. 10 m, then meaſure <hi>Q A,</hi> with a <hi>Decimall</hi> Chaine (or ſuch like,) which ſuppoſe to be 5. Chaines, note this in a peece of paper, then take the <hi>Inſtrument</hi> up, and meaſure the line, <hi>A B,</hi> but firſt onely <hi>A E,</hi> which ſuppoſe to be 11. Chaines and 60 Linkes, which is written down thus. 11. 60. Then meaſure the diſtance from <hi>E</hi> to the Angle <hi>F,</hi> which admit to be 2. 20, Laſtly, go one with the meaſure <hi>A B,</hi> which ſuppoſe to be 15. 00, the Angle of obſeruation, and meaſures thus taken may be noted downe one againſt another, as in the <hi>Table</hi> following, then place the <hi>Inſtrument</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>63</label> upon his reſt at <hi>B,</hi> and obſerue the Angle: <hi>ABC,</hi> which note downe alſo and meaſure the diſtance, <hi>B G,</hi> and <hi>G H,</hi> and then going on with <hi>G B,</hi> to <hi>G I,</hi> and marke and meaſure <hi>B I,</hi> and then meaſure alſo <hi>I K,</hi> and ſo goe on with <hi>B C,</hi> which <hi>meaſures</hi> are all placed down as appeares in the <hi>Table</hi> of <hi>Angles</hi>
                        <pb n="96" facs="tcp:10089:61"/> and meaſures following: In like matter performe the reſt of the worke untill you come to <hi>Q,</hi> and ſo all the <hi>Angles</hi> and <hi>meaſures</hi> will be according to the <hi>Table</hi> here under ſpecified.</p>
                     <p>
                        <table>
                           <row>
                              <cell role="label">
                                 <hi>The Table of Angles.</hi>
                              </cell>
                              <cell role="label">
                                 <hi>The Table of meaſures.</hi>
                              </cell>
                           </row>
                           <row>
                              <cell role="label">G.M.</cell>
                              <cell>5. 00.</cell>
                           </row>
                           <row>
                              <cell>32.10.</cell>
                              <cell>11. 60.</cell>
                           </row>
                           <row>
                              <cell> </cell>
                              <cell>2.20.</cell>
                           </row>
                           <row>
                              <cell> </cell>
                              <cell>15. 00.</cell>
                           </row>
                           <row>
                              <cell rows="5">80.10.</cell>
                              <cell>6. 00.</cell>
                           </row>
                           <row>
                              <cell>1.00.</cell>
                           </row>
                           <row>
                              <cell>9. 20.</cell>
                           </row>
                           <row>
                              <cell>2.00.</cell>
                           </row>
                           <row>
                              <cell>16. 40.</cell>
                           </row>
                           <row>
                              <cell rows="3">79.30.</cell>
                              <cell>6. 90.</cell>
                           </row>
                           <row>
                              <cell>1. 29.</cell>
                           </row>
                           <row>
                              <cell>8. 00.</cell>
                           </row>
                           <row>
                              <cell rows="3">74. 45.</cell>
                              <cell>3. 70.</cell>
                           </row>
                           <row>
                              <cell>1. 15.</cell>
                           </row>
                           <row>
                              <cell>5. 40.</cell>
                           </row>
                        </table>
                     </p>
                     <pb facs="tcp:10089:61"/>
                     <figure>
                        <figDesc>mathematical diagram</figDesc>
                     </figure>
                     <p>But it had beene fully ſufficient (by helpe of this <hi>Protractor</hi>) to have plotted the aforeſaid <hi>Plaine,</hi> by knowing the former <hi>Meaſures,</hi> and two Angles of obſeruation only.</p>
                  </div>
                  <div n="4" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>47</label> Fourthly, how to finde the Incli<g ref="char:EOLhyphen"/>nation of a Plaine, or to Elevate a Plaine unto an Angle aſſigned, and to Place a Plaine Horizon<g ref="char:EOLhyphen"/>tall.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>65</label> 
                        <hi>For the first,</hi> Set the <hi>Eaſt</hi> and <hi>West,</hi> edge of the
<pb n="99" facs="tcp:10089:62"/> 
                        <hi>Instrument</hi> unto the <hi>Plaine,</hi> then if the edge of the <hi>Index</hi> in the <hi>Limbe</hi> of the <hi>Instrument,</hi> cut the point of <hi>Eaſt</hi> or <hi>West,</hi> the <hi>Plaine</hi> is <hi>verticall,</hi> and doth not <hi>Incline,</hi> but if the <hi>Index</hi> fall from the points, looke how many degrees it is from the points of <hi>East</hi> or <hi>West</hi> in the <hi>Limbe</hi> of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment</hi> ſo much is that <hi>Inclination</hi> of the <hi>Plaine.</hi>
                     </p>
                     <p>
                        <hi>For the Second, to Elevate a Plaine, to an Angle aſſigned.</hi>
                     </p>
                     <p>
                        <hi>This</hi> is onely the ſame with the former, but may be applyed to ſeverall uſes, as to trie the mount, or to mount a <hi>Peece</hi> of <hi>Ordinance</hi> at any <hi>Randon:</hi> or to place <hi>Burning glaſſes</hi> (or others) at ſeverall Angles, to receive each others <hi>Reflex<g ref="char:EOLhyphen"/>on,</hi> and that the point of concurſe, or <hi>inflammation</hi> in ſuch <hi>Glaſſes</hi> may be in the <hi>Radius</hi> or beame of the <hi>Sunne,</hi> or that the point of <hi>inflamation,</hi> the re<g ref="char:EOLhyphen"/>preſentative <hi>Image,</hi> or the extenſive <hi>Elumin<g ref="char:EOLhyphen"/>ation</hi> may be proiected to a point aſſigned.</p>
                     <p>
                        <hi>For the Third, to rectifie a Plaine Horizontall.</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>66</label> 
                     </p>
                     <p>
                        <hi>Place</hi> the <hi>North</hi> and <hi>South</hi> edge of the <hi>Instru<g ref="char:EOLhyphen"/>ment,</hi> unto the under face of the <hi>Plaine,</hi> and then marke if the edge of the <hi>Index,</hi> cut the points of <hi>Eaſt</hi> or <hi>West</hi> in the <hi>Limbe</hi> of the <hi>Instrument,</hi> for then the <hi>Plaine</hi> is <hi>Horizontall,</hi> but if it ſwarne from that point, then it is not <hi>Horizontal,</hi> but the <hi>Plaine</hi> is to be raiſed, or depreſſed, untill by ſeverall tryalls in ſundry parts of the <hi>Plaine,</hi> you ſee the edge of the <hi>Index</hi> fall upon the points of <hi>Eaſt</hi> or <hi>West,</hi> for then ſhall it be truly <hi>Horizontall:</hi> Other<g ref="char:EOLhyphen"/>wiſe you may rectifie the <hi>Plaine Horizontall,</hi> by operating upon the upper face of it, if you ſet a
<pb n="100" facs="tcp:10089:63"/> 
                        <hi>Cube</hi> upon the plaine, and then placing the <hi>East</hi> and <hi>West</hi> edge of the <hi>Instrument</hi> unto the ſide of the <hi>Cube,</hi> for then the obſeruation will be as the former, and therefore, accommodated &amp; conclu<g ref="char:EOLhyphen"/>ded accordingly.</p>
                  </div>
                  <div n="5" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>48</label> Fiftly, to finde whether an Alti<g ref="char:EOLhyphen"/>tude be in the Point of libration, or above, or below the levell of the eye, and how much.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Declara∣tion. </seg>
                        </label> 
                        <hi>Let C B</hi> and <hi>X,</hi> be three ſeverall obiects, and let their ſeverall ſituations be required.</p>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>67</label> 
                        <hi>Firſt,</hi> let the <hi>Instrument</hi> hang upon a reſt per<g ref="char:EOLhyphen"/>pendicular, and let it be held ſtedfaſt that the <hi>Index</hi> may be verticall, and play eaſily by the ſide of the <hi>Inſtrument,</hi> then looking through the <hi>ſights</hi> of it, lift the <hi>Instrument</hi> up and downe, untill you ſee your marke, which ſuppoſe firſt <hi>C,</hi> and admit the <hi>Index</hi> ſhould cut 5. in the line of <hi>ſhadowes,</hi> which ſheweth that <hi>C,</hi> is higher then the eye by the 5<hi rend="sup">th</hi>. part of the diſtance of the baſſis of the obiect, from the eye, ſuppoſed at <hi>A.</hi>
                     </p>
                     <p>
                        <hi>Secondly,</hi> if through the <hi>ſights</hi> of the <hi>Instrument</hi> you ſee the ſecond obiect, <hi>B</hi> and the <hi>Index</hi> falling upon no part in the line of <hi>ſhadowes,</hi> then it ſhew<g ref="char:EOLhyphen"/>eth that the point <hi>B,</hi> is levell with the eye, for if in any obſervation the <hi>Index</hi> fall betweene the beginning of the line of <hi>ſhadowes,</hi> (which is neere the begining of <hi>December</hi>) and the ſight next
<pb n="101" facs="tcp:10089:63"/> the eye, it argueth that the obiect is higher then the eye, but if the <hi>Index</hi> fall beyond the beginning of the line of ſhadowes, then the obiect is lower then the eye.</p>
                     <p>
                        <hi>Thirdly,</hi> if you obſerve the obiect <hi>X,</hi> (the <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>68</label> eye being at <hi>A,</hi>) then if in obſerving the <hi>Marke X,</hi> through the <hi>ſights</hi> of the <hi>Instrument,</hi> the <hi>Index</hi> ſhall fall beyond the beginning of the line of <hi>ſhadowes,</hi> that is from the <hi>Kalender</hi> number the degrees, in the <hi>Limbe</hi> from the edge of the <hi>Index</hi> unto that point, and account the ſame back<g ref="char:EOLhyphen"/>ward from the point in the <hi>Limbe</hi> that is oppoſit to the beginning of the line of <hi>ſhadowes,</hi> and lay the edge of the <hi>Index</hi> unto it, then ſuppoſe the <hi>Index,</hi> in the line of <hi>ſhadowes</hi> interſect 8. which ſheweth that the point <hi>X</hi> is lower then the levell of the eye, by the eight part of the diſtance from you to the marke. Now if the diſtance ſhould be 100. foote, then the point <hi>X,</hi> ſhall be below the <hi>Horizontall</hi> line, or line of levell <hi>A B,</hi> 12. foote and ½ which is the ⅛ part of 100. the diſtance be<g ref="char:EOLhyphen"/>fore ſpecified.</p>
                  </div>
                  <div n="6" type="application">
                     <head>Sixtly, how to finde the height of <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>49</label> an Altitude above the levell of of the eye, either Acceſsible, or inacceſsible.</head>
                     <p>
                        <hi>Let, B C</hi> be an <hi>Altitude</hi> and the eye at, <label type="milestone">
                           <seg type="milestoneunit">Declara∣tio. </seg>
                        </label> 
                        <hi>A</hi> di<g ref="char:EOLhyphen"/>ſtant from the <hi>Baſis</hi> of <hi>B,</hi> 100. foote.</p>
                     <pb n="102" facs="tcp:10089:64"/>
                     <p>
                        <hi>If</hi> through the <hi>ſights</hi> of the <hi>Inſtrument</hi> the ſummet of the <hi>Altitude B C,</hi> viz. <hi>C,</hi> be ſeene, and the <hi>Index</hi> falling upon 5, in the line of <hi>ſhadowes,</hi> 
                        <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>69</label> it argueth the <hi>Altitude B C,</hi> to be the 5<hi rend="sup">th</hi>. part of the diſtance, viz. of <hi>A. B.</hi> which is 20. foot. <hi>Or</hi> let the <hi>Altitude</hi> of <hi>G,</hi> be ſought out, whoſe <hi>Baſis</hi> cannot be ſeene Admit, the firſt ſtation be made at <hi>A</hi> and ſeing the ſummet of the <hi>Altitude G,</hi> the <hi>Index</hi> ſhould cut 3 in the line of <hi>ſhadowes,</hi> it Argu<g ref="char:EOLhyphen"/>eth that the diſtance to the <hi>Baſis</hi> of the <hi>Altitude,</hi> is triple to the <hi>Altitude,</hi> then if I ſhould go neerer to the <hi>Altitude,</hi> viz. at <hi>D,</hi> and ſhould obſerue the ſummet or top of the <hi>Altitude G,</hi> and that the <hi>Index</hi> ſhould fall upon 1. in the line of <hi>ſhadowes,</hi> then it ſheweth that the diſtance from <hi>D,</hi> to the <hi>Baſis</hi> of the <hi>Altitude</hi> is equall to the <hi>Al<g ref="char:EOLhyphen"/>titude.</hi> Now ſuppoſe that betweene <hi>D</hi> and <hi>A</hi> were 80. foote it ſhould ſeeme that the <hi>Altitude</hi> obſerued ſhould be 40. foote, for if at <hi>D.</hi> the diſtance to the <hi>Altitude</hi> be equall to the <hi>Altitude,</hi> &amp; the diſtance from <hi>A,</hi> to the <hi>Altitude,</hi> be <hi>Triple</hi> to the <hi>Altitude,</hi> then the diſtance from <hi>D</hi> to the <hi>Altitude</hi> is the ⅓ of the diſtance <hi>AR,</hi> &amp; ſo <hi>AD,</hi> ſhall be double to <hi>DR,</hi> therefore halfe the di<g ref="char:EOLhyphen"/>ſtance <hi>AD,</hi> viz. 40. foot is the <hi>Altitude</hi> required.</p>
                  </div>
                  <div n="7" type="application">
                     <head> 
                        <label type="milestone">
                           <seg type="milestoneunit">Pro. </seg>50</label> Seventhly, to meaſure any part of an Altitude which is not approachable.</head>
                     <p> 
                        <label type="milestone">
                           <seg type="milestoneunit">Decla∣ratio. </seg>
                        </label> 
                        <hi>Let G H,</hi> a part of an <hi>Altitude</hi> be required to be meaſured.</p>
                     <pb n="103" facs="tcp:10089:64"/>
                     <p>
                        <hi>Firſt,</hi> ſearch out the height <hi>G R,</hi> as before 40. <label type="milestone">
                           <seg type="milestoneunit">Conſtru¦ctio. </seg>70</label> foote, then admit ſtanding at <hi>A</hi> and looking to <hi>H,</hi> through the ſights, the <hi>Index</hi> ſhould cut 4, which ſhewes the diſtance from <hi>A,</hi> to be Qua<g ref="char:EOLhyphen"/>druple to the <hi>Altitude</hi> of <hi>H R,</hi> and if comming neerer the <hi>Altitude</hi> 80. foote, viz. at <hi>D, I</hi> ſhould obſerve <hi>H</hi> againe, through the <hi>ſights</hi> of the <hi>Inſtru<g ref="char:EOLhyphen"/>ment,</hi> and finde the <hi>Index</hi> to cut 1, and ⅓, in the line of the <hi>ſhadowes,</hi> then the diſtance from <hi>D,</hi> to the <hi>Altitude H R,</hi> viz. <hi>D R,</hi> ſhould containe the <hi>Altitude H R,</hi> once, and a third part of the <hi>Alti<g ref="char:EOLhyphen"/>tude,</hi> now ſeeing that <hi>D R,</hi> is 1 and ⅓, therefore <hi>H R,</hi> ſhall be 1, but the obſervation at <hi>A</hi> ſhewed the diſtance from <hi>A,</hi> to the <hi>Altitude H R,</hi> to be <hi>Quadruple,</hi> and ſeeing that <hi>D R,</hi> is 1, and 1 part of 3, therefore <hi>A D,</hi> muſt be 2, and 2 parts of 3, which makes <hi>A R,</hi> the whole diſtance to be 4, or <hi>Quadruple</hi> to <hi>H R,</hi> but if <hi>A B,</hi> 2, and 2 parts be 80. foote then <hi>D R,</hi> being 1, and 1, part ſhall be 40 foote, and if <hi>D R,</hi> 1, and ⅓, be 40. foote, then <hi>H R,</hi> (which was 1 ſhould be but 30. foote, &amp; ſo con<g ref="char:EOLhyphen"/>ſequently <hi>H R,</hi>) taken from <hi>G R,</hi> there ſhall re<g ref="char:EOLhyphen"/>maine <hi>G H,</hi> 10. foote, the meaſure of the part of the <hi>Altitude</hi> required. In like manner might we applie the <hi>Inſtrument</hi> to the meaſuring of Bredths and diſtances: but that which is delivered may ſerue for the preſent, and as fully ſufficient for the Ingenious.</p>
                  </div>
               </div>
            </div>
            <div type="conclusion">
               <pb n="104" facs="tcp:10089:65"/>
               <head>Concluſion.</head>
               <p>I might have Annexed unto this <hi>Tractat</hi> the demonſtra<g ref="char:EOLhyphen"/>tion of this <hi>Proiection,</hi> which might have ſatisfied thoſe which are more learned, but to ſhew them it would be impertinent, ſeeing the thing lies ſo obuious: for others, it would not be reſpected or regarded, ſeeing the making, and practicall uſe of the <hi>Inſtrument,</hi> principally &amp; Totally they looke after, which I have plentifully delivered. Now by way of Compariſon it is ſaid in the deſcription of <hi>Maſter Gunters Quadrant,</hi> that if a <hi>Quadrant</hi> were made (as he there relateth) unto a foote ſemidiameter, it ſhould ſhew the <hi>Azimuth</hi> unto a degree, &amp; the houre unto a minute. It is moſt probable that if this <hi>Horlzontal Quadrant</hi> have the ſame <hi>ſemidiameter,</hi> it ſhal ſhew the <hi>houre</hi> unto half a minut, and the <hi>Azimuth</hi> unto 3 m. And if in this <hi>Tractat</hi> I have beene too obſcure (which I have avoyded as much as poſ<g ref="char:EOLhyphen"/>ſible I could,) I intreat the <hi>Reader</hi> to excuſe me. I confeſſe I might more Methodically have digeſted it, and more a<g ref="char:EOLhyphen"/>boundantly Amplified it, howſoever the affectionate I perſwade my ſelfe will not ſpurne at that which I have de<g ref="char:EOLhyphen"/>livered; as for the Malevolent I way not: my few houres would not permit me to make a long premeditation of ſo great a facilitie. But if any one deſire to ſay more upon this <hi>Horizontall Quadrant,</hi> then I have done: I have made way for him, and vnuailed the ſubject, to helpe his ſight.</p>
               <closer>
                  <dateline>
                     <hi>From my houſe in Chancery-Lane,</hi>
                     <date>Ianuary, <hi>Anno.</hi> 1631.</date>
                  </dateline> 
                  <hi>Deus donat &amp; digerit.</hi>
               </closer>
            </div>
            <trailer>FINIS.</trailer>
         </div>
      </body>
      <back>
         <div type="illustration">
            <pb facs="tcp:10089:65"/>
            <p>
               <figure>
                  <figDesc>mathematical diagram</figDesc>
                  <p>Motus Perpetuus Solis Diſtinguit Tempora</p>
                  <p>VIGILATE</p>
                  <q>
                     <l>Cuncta sciaterists solaria ducta figuris,</l>
                     <l>Cernitur Hoc varijs exuperare modis:</l>
                     <l>Solis, et ascendens, occaſus, et ortus, et auſter,</l>
                     <l>Azimuth Hinc, menſis, longa videnda dies;</l>
                     <l>Hora<expan>
                           <am>
                              <g ref="char:abque"/>
                           </am>
                           <ex>que</ex>
                        </expan> Solaris via, Sol quodcun<expan>
                           <am>
                              <g ref="char:abque"/>
                           </am>
                           <ex>que</ex>
                        </expan> per vmbras</l>
                     <l>Praestitit, Horologî mobilis orbis habet.</l>
                  </q>
                  <p>QVAERE VT IVENIa<gap reason="illegible" resp="#PDCC" extent="1 letter">
                        <desc>•</desc>
                     </gap>
                  </p>
               </figure>
            </p>
            <pb facs="tcp:10089:66"/>
            <pb facs="tcp:10089:66"/>
            <p>
               <figure>
                  <figDesc>mathematical diagram</figDesc>
               </figure>
            </p>
         </div>
      </back>
   </text>
</TEI>
